A projectile is launched in the horizontal direction. It travels 2.050 m horizontally while it falls 0.450 m vertically, and it then strikes the floor. How long is the projectile in the air

Answer:

try S or Q

Explanation:

To model the discovery of electromagnetic induction, Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Electromagnetic induction refers to the phenomenon of generating an electric current in a conductor by varying the magnetic field passing through it. This concept was discovered by Michael Faraday in the early 19th century. To model this discovery, Tonya needs to recreate the conditions that led to this breakthrough.

In Faraday's experiment, he observed that when a magnet is moved into or out of a coil of wire, it induces an electric current in the wire. This occurs when the magnetic field passing through the coil changes. Therefore, Tonya should use a similar setup to replicate this process.

Out of the given options, the most appropriate procedure for Tonya would be to move a magnet into a coil of wire in a closed circuit. By having a closed circuit, it means that the ends of the wire are connected to form a complete loop. When the magnet is moved into the coil, the changing magnetic field induces an electric current to flow through the wire.

This procedure demonstrates the principle of electromagnetic induction and shows how a changing magnetic field can produce an electric current. It allows Tonya to visually observe the effects of the induced current, which is essential in modeling the discovery of electromagnetic induction.

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Answer:

F = 172 N

Explanation:

Newton's second law of motion gives the amount of force acting on an object. Mathematically, it is given by :

F=ma

Put m =86 kg and a = 2 m/s²

So,

\(F=(86\times 2)\ N\\\\F=172\ N\)

Hence, the net force is 172 N.

Answer:

C

Explanation:

Check for coordinates of the VT graph in C part. The information matches with the table.

Answer:

p waves travel faster than s waves and surface waves

Answer:

p waves travel faster than s waves and surface waves

Explanation:

I took a quiz and got this right.

Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

To successfully answer the question given above, we must know the meaning of zero acceleration and negative acceleration respectively.

Zero acceleration simply means the object is not accelerating. This implies that velocity of the object is constant (i.e unchanged) with time.

Negative acceleration simply means the object is decelerating i.e coming to rest.

Now, let us answer the question given above.

From the question given above, the following data were obtained:

1. AB indicates that the particle is accelerating because the velocity increased from A to B with time.

2. BC indicates zero acceleration because the velocity of the Particle is constant (i.e unchanged) with time.

3. CD indicates that the object is coming to rest i.e decelerating (negative acceleration) because the velocity of the object decreased from C to D with time.

From the above illustrations, we can see that only option C gives the correct answer to the question.

Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

Answer:

Static equilibrium.

Explanation:

Answer:

100

Explanation:

F = m * a

Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):

F = 0.02 kg * 5 m/s^2 = 0.1 N

So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.

Answer:

We apply an electric field in the negative y direction

Explanation:

Since A uniform magnetic field is in the positive z direction and A positively charged particle is moving in the positive x direction through the field, the magnetic force acting on the positively charged particle is in the positive y direction according to Fleming's right-hand rule.

For the net force on the particle to be zero, we apply an electric field in the negative y direction to create an electric force on the positively charged particle, so as to cancel out the magnetic force.

Answer:

Increase the amplitude

Explanation:

The energy conveyed by a wave is directly proportional to the square of its amplitude. Thus; E ∝ A²

This means that increasing the amplitude will lead to an increase in the energy.

Now, the amplitude of a wave is the height of a wave from it's highest point known as the peak, to the lowest point on the wave known as the trough whereas wavelength refers to the length of a wave from one peak to the next.

This means that increasing the amplitude has no effect on the wavelength.

Since you wanted to use some brain-mapping techniques to identify anatomical functioning, the method that would be the best choice is option A. MRI.

In PET scans, the breakdown of option B:  radioactive materials in the body and the release of gamma rays produce a functional view of the brain.

FDG, which stands for "fluorodeoxyglucose," is a simple sugar (like glucose) that is frequently employed in PET scanning. It is injected into the bloodstream and builds up inside the body, where it emits gamma rays as energy.

Note that without injecting any kind of dye or tracer, brain mapping techniques like magnetoencephalography (MEG) and functional magnetic resonance imaging (fMRI) scans can be used to detect the anatomical functioning of the brain. The diagnosis and treatment of neurodegenerative illnesses can both benefit greatly from these techniques.

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D. Kinetic energy is converted to potential energy.

At point C, the pendulum is at its highest point, and the kinetic energy it has accumulated from the initial release at point A has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

At point A, potential energy is converted to kinetic energy. At point C, the pendulum is at its highest point, and the kinetic energy has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

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The spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

The angular speed of the ball is calculated as follows;

ω = 2π/T

ω = (2π) / (0.13)

ω = 48.33 rad/s

The spring constant is calculated as follows;

ω = √(k/m)

ω² = k/m

ω²m = k

(48.33² x 0.232) = k

542 N/m

v = ωL

v = 48.33 x 0.56 m

v = 27.1 m/s

h = v²/2g

h = (27.1²) / (2 x 9.8)

h = 37.5 m

Thus, the spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

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Answer:

B. The "Learner" was working with Milgram.

Explanation:

just took the test

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Answer:

\(\huge\boxed{T = 0.025\ seconds}\)

Explanation:

Given:

Frequency = f = 40 Hz

Required:

Time period = T = ?

Formula:

\(\sf T = 1 / f\)

Solution:

T = 1 / 40

T = 0.025 seconds

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

The object appears larger

Explanation:

B

If the same motor is to be driven from a 440-V, 60 Hz power supply, The slip at pullout torque is 0.0455.

The slip at pullout torque, pullout torque, and rotor speed at the pullout torque of the motor are given by Slip

\(s = Pmech/ (Xm\times 1.5\times V^2/1000)\)

Pullout torque is given by \((0.5 \times V^2 / X2) \times (R2 / (R1^2 + (X1 + X2)^2))\)

Rotor speed at pullout torque is given by Ns = (120f/p)(1 - s)

The given parameters of the motor are R1 = 0.075 Ohms, R2 = 0.065 Ohms, Xm = 7.2 Ohms, X1 = 0.17 Ohms, X2 = 0.17 Ohms, Pmech = 1.0 KW W, Pstray = 150 W, Pcore = 1.1 KW.

The motor is rated at 75 KW with a power factor of 0.85.Assuming the motor is running at unity power factor.

The output power of the motor is Pout = 75 KW and the input power to the motor is Pin = 75 KW / 0.85 = 88.24 KW

The input current to the motor is \(Iin = 88.24 KW / (3 \times 440 V \times sqrt(3)) = 89.5 A\)

Therefore, the torque developed by the motor is \(T = 1000 \times Pout / (2 \times pi \times N)\)

The slip at the pullout torque is given by \(s = sqrt((Pcore + Pstray) / Pout) = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

The pullout torque is given by \((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) = 411.7 Nm.\)

The rotor speed at pullout torque is \(Ns = (120 \times 50 / 2) \times (1 - 0.0455) = 2846 rpm.\)

The pullout torque of the motor if driven from a 440 V, 60 Hz power supply is given by

\((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) \times (60 / 50) = 548.4 Nm.\)

The slip at pullout torque is given by \(s = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

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Answer:

Power

Explanation:

It only has one force. An un-scalar quantity has more than one factor. For example friction not only has weight but also speed. The faster something is traveling the more friction, the more weight the more friction.

Answer:

hi what is your question?? say in English please

Answer:

He has a hangover.

Explanation:

Just something I know.

Answer:

Explanation:

amplitude of oscillation A = .06 m .

maximum velocity = ω A where ω is angular frequency .

ω A = 3.2 m/s ( Given )

ω x .06  = 3.2

ω = 53.33 rad /s .

velocity when the displacement is x can be given by the expression

v² = ω²( A² - x² )

x = .04 m

v² = 53.33²( .06² - .04² )

=  2844.1( .0036 - .0016 )

= 5.688

kinetic energy = 1/2 m v²

= .5 x .050 x 5.688

= .1422 J .

=

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer:

In this problem, the harp string is fixed at both ends, so it is a standing wave with nodes at both ends and an antinode in the center. The frequency of the wave is given as 440 Hz, and the length of the string is 30.5 cm.

(a) To find the wavelength of the wave, we can use the formula:

λ = 2L/n

where λ is the wavelength, L is the length of the string, and n is the number of nodes. In this case, n = 2 (since there are nodes at both ends) and L = 30.5 cm, so we have:

λ = 2(30.5 cm)/2 = 30.5 cm

Therefore, the wavelength of the wave is 30.5 cm.

(b) To find the speed of the wave on the string, we can use the formula:

v = fλ

where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength. In this case, f = 440 Hz and λ = 30.5 cm, so we have:

v = (440 Hz)(30.5 cm) = 13420 cm/s

Therefore, the speed of the wave on the string is 13420 cm/s

Explanation:

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Answer:

groups

Explanation:

Answer: Groups

Explanation: They are in the same group! Like the Alkaline Metals are all the group. They all lose an electron. :)

The term which describes the increased soil erosion in the regions where sheep and cattle eat the grasses and reggianvorz is called overgrazing.

Overgrazing happens when livestock and other grazers (such as wildlife) consume more plant biomass than the vegetation can replenish in a reasonable amount of time, exposing the soil and lowering the vegetation's potential for production.

The exposure of the soil might hasten the potential for processes of water and wind erosion, which can result in soil losses. Less water infiltration into the soil might result in slower plant growth due to accelerated erosion processes and soil compaction caused by grazing animals.

Because less plant biomass is accessible as litter due to ongoing overgrazing, less soil organic matter, nutrients, and biotic activity are added to the soil. This causes the soil structure to deteriorate, which lowers the soil's capacity to store water and raises the risk of erosion.

Therefore, the term describing the given action is overgrazing.

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The work done by \(\vec F\) along the given path C from A to B is given by the line integral,

\(\displaystyle \int_C \mathbf F\cdot\mathrm d\mathbf r\)

I assume the path itself is a line segment, which can be parameterized by

\(\vec r(t) = (1-t)(-2\,\vec\imath + 5\,\vec\jmath) + t(4\,\vec\imath+7\,\vec\jmath) \\\\ \vec r(t) = (6t-2)\,\vec\imath+(2t+5)\,\vec\jmath \\\\ \vec r(t) = x(t)\,\vec\imath + y(t)\,\vec\jmath\)

with 0 ≤ t ≤ 1. Then the work performed by F along C is

\(\displaystyle \int_0^1 \left(6x(t)^3\,\vec\imath-4y(t)\,\vec\jmath\right)\cdot\frac{\mathrm d}{\mathrm dt}\left[x(t)\,\vec\imath + y(t)\,\vec\jmath\right]\,\mathrm dt \\\\ = \int_0^1 (288(3t-1)^3-8(2t+5)) \,\mathrm dt = \boxed{312}\)

Answer:

Obviously the answer is Sun...