a proton is located at x = 1.0 nm, y = 0.0 nm and an electron is located at x = 0.0 nm, y = 4.0 nm. find the attractive coulomb force between them. (the value of k is 9.0 × 109 n·m2/c2.)

Answer:

A molecule is defined as two or more atom of same element or different element grouped together

according to question the correct option is b) lii < bas < mgo.

To determine the order of increasing magnitude of lattice energy for the given compounds (MgO, LiI, and BaS), we need to consider the relative strengths of the ionic bonds formed between the cations and anions in each compound.

Lattice energy is a measure of the energy released when 1 mole of a solid ionic compound is formed from its constituent ions in the gas phase. Higher lattice energy corresponds to stronger ionic bonds.

The factors affecting lattice energy include the charge of the ions and the size of the ions. Generally, the higher the charges and the smaller the ions, the stronger the ionic bonds and the higher the lattice energy.

Let's analyze the given compounds:

MgO:

Magnesium (Mg) has a 2+ charge, and oxygen (O) has a 2- charge.

The charges on the ions are the same magnitude as those in LiI and BaS, but the ionic radii of Mg^2+ and O^2- are smaller than those of Li^+ and Ba^2+, respectively.

Therefore, MgO is expected to have a higher lattice energy than LiI and BaS.

LiI:

Lithium (Li) has a 1+ charge, and iodine (I) has a 1- charge.

The charges on the ions are smaller in magnitude than those in MgO and BaS.

LiI is expected to have a lower lattice energy compared to MgO and BaS.

BaS:

Barium (Ba) has a 2+ charge, and sulfur (S) has a 2- charge.

The charges on the ions have the same magnitude as those in MgO, but the ionic radii of Ba^2+ and S^2- are larger than those of Mg^2+ and O^2+, respectively.

Therefore, BaS is expected to have a lower lattice energy compared to MgO but higher than LiI.

Based on the analysis above, the correct order of increasing magnitude of lattice energy is:

b) LiI < BaS < MgO

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Answer:

x = 3.6 10⁷ m

Explanation:

The speed of an electromagnetic wave is constant, in a vacuum its value is    c = 3 10⁸ m / s, this speed decreases when entering a material medium,

         v = c / n

where n is the refractive index, but in this case the refractive index of air is n = 1.00002. The refractive index of a vacuum is n = 1, so we can assume that the change in velocity is negligible.

For the calculation we can use the relations of the uniform motion

        v = x / t

        x = v t

let's calculate

        x = 3 10⁸ 0.12

        x = 3.6 10⁷ m

Answer:

2.5 km because displacement is xf -xi

xf = 2.5

xi= 0

2.5 - 0 =2.5 km

I hate to leave you without an answer, but there isn't enough information to be able to answer your problem.

The acceleration of the proton is approximately 3.43 x 10^15 m/s^2.

A proton that moves at right angles to a magnetic field experiences a magnetic force that causes it to follow a circular path. This is due to the fact that the magnetic force acting on a charged particle moving at right angles to a magnetic field is proportional to the product of the magnetic field, the charge, and the velocity. As a result, the acceleration of the proton can be calculated using the following formula:

a = (qvB) / m

where q is the charge of the proton, v is its velocity, B is the magnetic field strength, and m is the mass of the proton.

Given that a proton moves with a speed of 9.5 m/s at right angles to a magnetic field of 1.5 T, the acceleration can be calculated as follows:

a = (qvB) / m = (1.602 x 10^-19 C x 9.5 m/s x 1.5 T) / (1.673 x 10^-27 kg)≈ 3.43 x 10^15 m/s^2

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The child's radial/centripetal acceleration at the lowest point of the swing is

a = (3.00 m/s)² / (7.00 m) = 1.29 m/s²

By Newton's second law, the tension in the rope is

T = (3.5 kg) (1.29 m/s²) = 4.5 N

(Does the question really say the child's mass is 3.5 kg? That's little more than the average mass of a newborn, about 3.3 kg. Not exactly a good idea to put a newborn on a swinging rope...)

Answer:

I think C? I'm not sure totally though...

Explanation:

In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.

As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.

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Hope you could understand.

If you have any query, feel free to ask.

Answer:

Decreases the friction between the mallet and the pick.

Answer:

the wavelength is 9.8 meters

Explanation:

We can use the relationship:

Velocity = wavelenght*frequency.

Initially we have:

wavelenght = 4.9m

velocity = 9.8m/s

then:

9.8m/s =  4.9m*f

f = 9.8m/s/4.9m =  2*1/s

now, if the velocity is doubled and the frequency remains the same, we have:

2*9.8m/s = wavelenght*2*1/s

wavelenght = (2*9.8m/s)*(1/2)s = 9.8 m

Answer:

9.8

Explanation:

Answer:

y = m λ L / d

must use lasers of greater wavelength

Explanation:

The expression for the constructive interference of a double slit is

           d sin θ = m λ

let's use trigonometry to find the angle

          tan θ = y / L

in interference phenomena the angles are small

         tan θ= sin θ/ cos θ = sin θ

         sin θ = y / L

we subjugate

         d y / L = m λ

         y = m λ L / d

In this expression we see that the separation of the lines (and) increases linearly with the wavelength, therefore we must use lasers of greater wavelength

Typical copyright and ownership statements can be embedded in footer tags of an html page.

Typical copyright and ownership statements can be embedded in the "footer" tags of an HTML page. The footer tag is used to define a footer for an HTML document or section and is typically placed at the bottom of the page. It is commonly used to include copyright notices, contact information, and other important information that applies to the entire page or website. The footer tag is part of the HTML5 standard and is supported by all major web browsers.In general, a footer is an area at the bottom of a document page containing data common to other pages. The information in footers may include page numbers, creation dates, copyrights, or references that appears on a single page, or on all pages.

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Answer:

7.5 m/s2

Explanation:

F = ma

300 = 40 kg (a)

divide both sides by 40 to single out the variable a (acceleration)

300/40 = 7.5 m/s2

The direct interaction between two magnetic dipoles is referred to as magnetic dipole-dipole interaction, or dipolar coupling.

There are north and south poles on every magnet. The same poles repel one another whereas opposite poles are drawn to one another. The north-seeking poles of the iron's atoms line up in the same direction when it is rubbed against a magnet.

The laws of electromagnetism cause magnets to exert forces and torques on one another. Microcurrents of electrically charged electrons orbiting nuclei and the intrinsic magnetism of the basic constituent particles (such as electrons) that make up the material are what cause the magnetic fields that attract objects.

Today's technologically significant groups of materials, such as magnetic recording materials, magnetic carriers, and magnaflux sensors used to detect cracks, all depend on magnetic interactions.

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Answer:

Answer: hydraulic press and hydraulic brakes. ... This law is useful in designing instruments like Bramah press ,Hydraulic press , Hydraulic jack etc. It is the principle in the development of hydraulic brakes , that are used in automobiles. It is also known as law of transmission of fluid pressure

Answer:

If all these three charges are positive with a magnitude of \(1.8 \times 10^{-8}\; \rm C\) each, the electric potential at the midpoint of segment \(\rm AB\) would be approximately \(8.3 \times 10^{3}\; \rm V\).

Explanation:

Convert the unit of the length of each side of this triangle to meters: \(10\; \rm cm = 0.10\; \rm m\).

Distance between the midpoint of \(\rm AB\) and each of the three charges:

Let \(k\) denote Coulomb's constant (\(k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}\).)

Electric potential due to the charge at \(\rm A\): \(\displaystyle \frac{k\, q}{d({\rm A})}\).

Electric potential due to the charge at \(\rm B\): \(\displaystyle \frac{k\, q}{d({\rm B})}\).

Electric potential due to the charge at \(\rm A\): \(\displaystyle \frac{k\, q}{d({\rm C})}\).

While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.

Hence, the electric field at the midpoint of \(\rm AB\) due to all these three charges  would be:

\(\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}\).

Answer:

The mechanical advantage (M.A) of a real machine is always less than its velocity ratio(V.R) because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant.

Answer:

Full moon

Explanation:

Increasing or decreasing the initial temperature of copper will have an impact on the final temperature based on the laws of thermodynamics. The specific effect will depend on the context and the surrounding conditions.

If we consider a scenario where a piece of copper is brought into contact with a cooler object or environment, increasing the initial temperature of the copper will result in a larger temperature difference between the copper and its surroundings. As a consequence, the copper will lose more heat energy to the surroundings, leading to a higher rate of heat transfer. This will cause the final temperature of the copper to decrease more rapidly, approaching the temperature of the surroundings.

Conversely, if the initial temperature of the copper is decreased, the temperature difference between the copper and its surroundings will be smaller. As a result, the rate of heat transfer from the copper to the surroundings will be lower. This will slow down the cooling process, and the final temperature of the copper will be higher than it would be with a higher initial temperature.

It's important to note that these observations assume that the copper is in thermal equilibrium with its surroundings and that no other factors significantly affect the heat transfer process, such as insulation or additional heat sources. The specific conditions and variables involved will ultimately determine the exact impact of changing the initial temperature of the copper on the final temperature.

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The value of the Fermi-Dirac distribution for energies less than the Fermi energy at absolute zero temperature (T=0K) is 1.00.

The Fermi-Dirac distribution function describes the probability of finding an electron in a specific energy state in a Fermi gas. It is given by the equation:

f(E) = 1 / (1 + exp((E - EF) / (kT)))

Where f(E) is the Fermi-Dirac distribution function, E is the energy, EF is the Fermi energy, k is Boltzmann's constant, and T is the temperature.

At absolute zero temperature (T=0K), the exponential term in the equation becomes infinite for energies less than EF, and the distribution function simplifies to:

f(E) = 1 / (1 + ∞) = 1 / ∞ = 0

Therefore, for energies less than the Fermi energy at absolute zero temperature, the value of the Fermi-Dirac distribution function is 0. However, it's important to note that this result assumes ideal conditions and a non-degenerate Fermi gas.

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The type of electromagnetic wave from the Sun that supplies the energy to keep the surface of the Earth warm is visible light.

The region of the electromagnetic spectrum that is visible to the human eye is known as visible light.It is made up of different wavelengths of light, from red to violet, and is responsible for the illumination of the Earth's surface.Visible light is a form of electromagnetic radiation that is visible to the human eye. It is made up of different wavelengths of energy, ranging from about 380 to 700 nanometers, and is the only form of electromagnetic radiation that the human eye can detect. Visible light is most commonly observed as the colors of the rainbow, including red, orange, yellow, green, blue, indigo, and violet. Visible light is the main source of energy for photosynthesis in plants and warms the surface of the Earth.

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Answer:

Part A would be 80 Joules and Part B would be 20 meters.

Explanation:

For Part A:

The first step is to convert the mass to SI units.

400 g = 0.4 kg

Next, we need to know that the law of conservation of energy states that the total energy of an isolated system is conserved. In this case, it means that the total energy at the bottom, where kinetic energy is greatest, will be equal to the total energy at the top, where gravitational potential energy is greatest.

Max Gravitational Potential Energy = Max Kinetic Energy

Max Gravitational Potential Energy = \(\frac{1}{2} mv^{2}\)

Max Gravitational Potential Energy = \((\frac{1}{2} )(.4kg)(20m/s)^2\) = 80\(J\)

For Part B:

We need to once again set gravitational potential energy to kinetic energy, only this time we use the GPE equation and solve for height. We already solved for the kinetic energy so we just plug everything in and solve.

\(mgh = \frac{1}{2} mv^{2}\)

\((.4kg)(10m/s^{2} )h = 80J\\h = 20m\)

The final momentum of bumper car 2 is -241.0 kgm/s.

The magnitude of the final momentum of bumper car 2 can be found using the conservation of momentum principle, which states that the total momentum of a closed system remains constant before and after a collision.

To calculate the final momentum of bumper car 2, we can use the following equation:

initial momentum of system = final momentum of system

250.0 + (-320.0) = (-311.0) + final momentum of bumper car 2

-70.0 = (-311.0) + final momentum of bumper car 2

final momentum of bumper car 2 = -241.0 kgm/s

The final momentum of bumper car 2 is -241.0 kgm/s.

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Answer:

C

Explanation:

Alpha decay

Answer:

left side

Explanation:

It's smaller in length but still has a pretty close slope to the right side.

Explanation:

Force is push or pull on a body.

Contact force is a force that requires contact. It acts between two body that touches on another.

Examples are pushing a car, ringing a bell, kicking a ball.

Non contact forces are forces applied to another object without contact. The action of this force is usually through a targeted force field.

Examples are magnetic force, gravitational force

The necessary radius of the central sheave to make the fall time exactly 4 s, using the same pendulum with weights at R=175 mm, is 19.685 mm.

The fall time of a pendulum depends on its length. The formula for the period of a simple pendulum is given by:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

In this case, the pendulum length is the sum of the radius of the central sheave (let's call it R') and twice the radius of the weights (175 mm). Therefore, we have:

L = R' + 2R

Given that the fall time is 4 s, we can substitute the values into the period formula and solve for R':

4 = 2π√((R' + 2R)/g)

Squaring both sides of the equation and rearranging, we get:

16 = 4π²(R' + 2R)/g

Simplifying further:

R' + 2R = 16g/(4π²)

Substituting the value of R (175 mm) and g (acceleration due to gravity), we can calculate the radius of the central sheave:

R' = 16(9.8)/(4π²) - 2(175) ≈ 19.685 mm

The radius of the central sheave necessary to achieve a fall time of exactly 4 s, using the same pendulum with weights at R=175 mm, is approximately 19.685 mm.

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