Every wave has the same wave pattern is the statement is true for this tuning fork sound wave, Option A is correct.
What is a sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
The correct statement is
"A pure sound wave, generated by a tuning fork, is considered a periodic wave. Which statement is true for this tuning fork sound wave?
A. The wave pattern repeats itself after every two waves.
B. Every wave has the same wave pattern.
C. The amplitude of the waves increases after every subsequent wave.
D. No two waves have the same wave pattern."
A tuning fork's pure sound wave is seen as a periodic wave. For this tuning fork sound wave,
Hence statement A is accurate.
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What causes friction between two solids?
Answer:
Friction is when 2 solids move against each other. The cause of friction is adhesion, and surface roughness. Surface roughness is when a surface is rough enough that is causes friction against another surface. Adhesion is when 2 surfaces collide because of thier molecular force.
(20%) Problem 5: Two identical springs, A and B, each with spring constant k=54.5 N/M, support an object with a weight W=11.6N. Each spring makes an angle of θ=20.6 degrees to vertical, as shown in the diagram.
50% Part (a) Write an expression for the tension in spring A (which is equal to the tension in spring B) in terms of W and θ.
T= W cos (θ) -sin (θ)
The expression for the tension in the spring A is T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]
What is the tension in spring A?
The tension in spring A can be determined by resolving the forces into x and y components as shown below.
The angle spring A makes with horizontal is calculated as;
A = 90⁰ - θ
The horizontal component of the tension on spring A;
T(Aₓ) = -W cos(A)
T(Aₓ) = -W cos(90 - θ)
The vertical component of the tension of spring A is calculated as;
T(Ay) = W sin(A)
T(Ay) = W sin(90 - θ)
The expression for the tension in spring A is calculated as;
T(A) = √[(T(Aₓ)² + T(Ay)²]
T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]
Thus, the expression for the tension in the spring A is determined through resolution of vector components.
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Shopper leaves home and drives to a store located 7km away in direction 30° north of east.Leaving the store,the shopper drives 5km in a direction 50° west of north to a restaurant.Find the distance and direction from shopper's home to the restaurant?
As a result, from the homes of the shoppers to the restaurant, the distance is 12 km, and the direction is 80° north.
What is distance and direction?As the name implies, questions based on direction and/or distance are also known as Direction and Distance questions. Candidates must calculate the distance traveled between the starting location and the final / end point based on the provided starting point and direction. The position of one point and person with regard to another point and person and the distance among them must be determined for the Direction & Distance reasoning part.
How do you teach directions?Declare the terms "right" and "left." Ask the kids to tell you what these terms imply or mean when they are translated, then write their answers on the board with arrows pointing in the appropriate directions. Show the class how to pronounce the words once their meanings are obvious. Relative terminology, such as up, down, in, out, left, right, forward, backward, or sideways, can be used to define direction. You can also depict direction using the four cardinal directions: north, south, east, & west.
7km = 30 Degree of NE
5km = 50 degree of N
Therefore distance = 7km+5km
=12km
thus, direction = 50+30
=80° N
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A double slit produces a diffraction pattern that is a combination of single and double slit interference. Find the ratio of the width of the slits (D) to the separation between them (d), if the third minimum of the single slit pattern falls on the fourth-order maximum of the double slit pattern. (This will greatly reduce the intensity of the fourth-order maximum. Assume the central maxima of the single slit and double slit interference patterns are located at the same place on the screen.)
Answer:
D / d = 3 / 4
Explanation:
Let the wavelength and distance of screen be λ and L . Let the distance at which both the fringes fall be at x distance from central point .
For double slit experiment , location of fourth order maxima
x = 4 x λ L / d
For single slit experiment , location of third order minima
x = 3 x λ L / D
As they overlap
3 x λ L / D = 4 x λ L / d
D / d = 3 / 4
Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.
Answer:
what's the question
........
What is the difference between chronic and acute stress?
Acute stress is long-term, while chronic stress is short in duration.
Acute stress is short-term, while chronic stress endures over time.
Chronic stress varies by geographic location, while acute stress is universal.
Chronic stress is not harmful, while acute stress has negative consequences.
Answer:
The correct difference between chronic and acute stress is:
Acute stress is short-term, while chronic stress endures over time.
Explanation:
Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.
On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.
Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.
Engine 1 has an efficiency of 0.18 and requires 5500 J ofinput heat to perform a certain amount of work. Engine 2 hasan efficiency of 0.26 and performs the same amount of work. How much input heat does the second engine require?
Answer:
The input energy to engine 2 is \(E_2 = 3807.7\ J\)
Explanation:
From the question we are told that
The efficiency of engine one is \(\eta_1 = 0.18\)
The input energy required is \(E = 5500 \ J\)
The efficiency of engine 2 is \(\eta_2 = 0.26\)
Generally the workdone by the engine 1 is mathematically represented as
\(W_1 = E * \eta_1\)
=> \(W_1 = 5500 * 0.18\)
=> \(W _ 1= 990 \ J\)
Generally the workdone by engine 2 is mathematically represented as
\(W _2= E_1 * \eta_2\)
=> \(W _2 = E_1 * 0.26\)
=> \(W_2 =0.26E_1\)
From the question we are told that \(W_1 = W_2\)
So
\(990 =W_2 =0.26E_1\)
=> \(E_2 = 3807.7\ J\)
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Explain how a tube can be used as a filter to reduce the amplitude of sounds in various frequency ranges?
Using a tube as a filter to reduce the amplitude of sounds in various frequency ranges relies on manipulating resonance and destructive interference to achieve the desired attenuation.
A tube can be used as a filter to reduce the amplitude of sounds in various frequency ranges through a phenomenon called resonance. When a sound wave travels through a tube, it encounters resonant frequencies at which the tube's length corresponds to an integer multiple of the sound's wavelength. At these resonant frequencies, constructive interference occurs, resulting in an amplification of the sound. To use a tube as a filter, it is necessary to exploit the destructive interference that occurs at certain frequencies. This can be achieved by designing the tube's length and shape to create resonant frequencies that coincide with the frequencies to be attenuated. When the sound wave encounters these resonant frequencies, destructive interference takes place, causing a reduction in the sound's amplitude. By carefully selecting the dimensions of the tube, it is possible to create a series of resonant frequencies that correspond to specific frequency ranges. This allows the tube to act as a filter, attenuating the amplitudes of sounds within those ranges while having less impact on sounds outside the targeted frequencies.
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Help my brain ain’t braining
The arrows are drawn in the figure which shows gravitational forces on each person on earth.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
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Here is Mr. Legare, skateboarding, again ...
He’s riding his skateboard down a ramp. Assume that his acceleration is 1.0 m/s2 how much force does it take for him to accelerate at this rate? He has a mass of 85 kg.
A. 0.011 N
B. 85 N
C. 7225 N
D. 85 kg
Answer:
B. 85 N
Explanation:
Newton's second law:
F = ma
F = (85 kg) (1.0 m/s²)
F = 85 N
When moving a couch, you exert a force of 400N and push it 4.0m. How much work have you done on the couch?
Answer:
Explanation: work equals force times distance so 400x4=1600 joules
Two ice skaters with masses of 40 kg and 60 kg stand together on frictionless ice. The first skater pushes against the second. When the first skater has moved a distance of 12 m, how far has the second skater moved? A12 mB 10 mC 8 mD Cannot determine without knowing the force of the push. E 0 m
Answer:
c.8
Explanation:
Two mirrors are touching so they have an angle of 35.4 degrees with one another. A light ray is incident on the first at an angle of 55.7 degrees with respect to the normal to the surface. What is the angle of reflection from the second surface
Answer:
54.6°
Explanation:
From law of reflection i=r.
So, construct the reflected ray at 55.7°degrees from the normal and let it fall on the other mirror.
Now draw the second normal at the point of incidence and again measure the angle of incidence, and draw the angle of reflection.
If you consider triangle AOB, one angle is ∠AOB=90°
and ∠OAB is 54.6°
From angle sum property third angle ie ∠ABO=180°-90°-54.6°=35.4°
So, the second incident angle will be 54.6°
Hence, the second reflected angle will be 54.6 degrees.
A missile is moving 1810 m/s ata 20.0° angle. It needs to hit atarget 19,500 m away in a 32.0°direction in 9.20 s. What is themagnitude of the accelerationthat the engine must produce?
First let's calculate the vertical and horizontal components of the distance:
\(\begin{gathered} dh=19500\cdot\cos (32\degree) \\ dh=16536.94 \\ \\ dy=19500\cdot\sin (32\degree) \\ dy=10333.43 \end{gathered}\)Then, since we have the time required, let's find the speed in each direction:
\(\begin{gathered} vh=\frac{dh}{t} \\ vh=\frac{16536.94}{9.2} \\ vh=1797.49 \\ \\ vy=\frac{dy}{t} \\ vy=\frac{10333.43}{9.2} \\ vy=1123.2 \end{gathered}\)Now, let's decompose the given speed in its components:
\(\begin{gathered} Vh=1810\cdot\cos (20\degree) \\ Vh=1700.84 \\ \\ Vy=1810\cdot\sin (20\degree) \\ Vy=619.06 \end{gathered}\)which model best represents a pattern
Answer:
A
Explanation:
2. You are traveling along a highway at night at a speed of 100 km/h when you spot an object directly in front of you in the road at the limit of your headlights. (10 Marks)
a) If the maximum braking deceleration that your car can provide is 7 m/s2, and if your headlights extend out to a range of 30 m, will you hit the object before coming to a stop?
b) How long will it take to stop?
a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:
d = (v^2) / (2a)
where:
d = distance required to stop
v = initial velocity
a = acceleration/deceleration
In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)
a = -7 m/s^2 (negative sign indicates deceleration)
We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.
Plugging in the values to the formula, we get:
d = (27.78^2) / (2 x -7) = 108.61 m
Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.
b) To calculate the time required to stop, we can use the following formula:
t = v / a
where:
t = time required to stop
v = initial velocity
a = acceleration/deceleration
Plugging in the values, we get:
t = 27.78 / 7 = 3.97 s
Therefore, it will take 3.97 seconds to stop the car.
Air is matter which backs best support the statement
Answer: A. Balloons can be filled with air.
C. Air has mass.
Explanation:
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Balloons are able to be filled with air and air has mass.
What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?
a) 3.8 kg • m/s
b) 4.2 kg • m/s
c) 6.0 kg • m/s
d) 6.2 kg • m/s
Explanation:
answer is 6.0Kg •m/s because
momentum= mass • velocity
that is 5 • 1.2 = 6
Two blocks are attached by a string as shown. The blocks are released from rest and
allowed to move freely. The sloped ramp angle is θ = 30⁰. Find the coefficient of friction
on the blocks (assume they have the same coefficient), assuming the blocks have the
same mass, and given that the blocks travel a distance of 0.50 m in a time of 0.935 s.
The coefficient of friction between the two blocks is 0.194.
The problem involves finding the coefficient of friction between two blocks of equal mass attached by a string that moves over a sloped ramp with an angle of 30 degrees. The blocks start from rest and are allowed to move freely. The distance traveled by the blocks is 0.50 m, and the time taken to travel this distance is 0.935 s. To solve the problem, we need to consider the forces acting on the system of blocks. The forces acting on the blocks are the gravitational force, the tension in the string, and the frictional force. As the blocks are moving up the ramp, the force of gravity is pulling them down. The tension in the string is pulling the blocks up the ramp. The frictional force is opposing the motion of the blocks and is acting in the opposite direction to the tension in the string.
To determine the coefficient of friction, we can use the equations of motion to find the acceleration of the blocks. Once we have the acceleration, we can use Newton's Second Law to find the net force acting on the blocks. We can then use the force of friction to find the coefficient of friction. Using the equations of motion, we can find the acceleration of the blocks:
a = 2d/t^2
where d is the distance traveled by the blocks and t is the time taken to travel the distance. Plugging in the given values, we get:
a = 2(0.50 m)/(0.935 s)^2 = 1.15 m/s^2
Next, we can use Newton's Second Law to find the net force acting on the blocks:
ΣF = ma
where ΣF is the sum of the forces acting on the blocks. Plugging in the known forces, we get:
T - mg sin θ - μmg cos θ = ma
where T is the tension in the string, m is the mass of the blocks, g is the acceleration due to gravity, θ is the angle of the ramp, and μ is the coefficient of friction.
We can simplify this equation by substituting mg sin θ for the component of the weight of the blocks that is acting down the ramp and mg cos θ for the component of the weight that is acting perpendicular to the ramp:
T - mg sin θ - μmg cos θ = ma
T - mg(1/2) - μmg(√3/2) = ma
We can also use the equation for the tension in the string:
T = 2mg sin θ
Substituting this into the equation for net force, we get:
2mg sin θ - mg(1/2) - μmg(√3/2) = ma
Simplifying and solving for μ, we get:
μ = (2gsinθ - a)/(2gcosθ)
Substituting the given values, we get:
μ = (2(9.81 m/s^2)sin 30° - 1.15 m/s^2)/(2(9.81 m/s^2)cos 30°) = 0.194
Therefore, the coefficient of friction between the two blocks is 0.194.
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.
The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.
This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point in the sunlight is equal to the pressure at any other point not in the sunlight.
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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Maslow's hierarchy of needs assumes
Answer:
That people are motivated by a series of five universal needs.
Explanation:
You will create your own circuit , discuss how electricity flows and describe how circuits are made in
Answer:
An electric current flows in a loop,powering bulbs or other electric COMPONENTS. The loop is an electric circuit. A circuit is made up of various components linked together by wires. The current is driven around the circuit by a power source, such as a BATTERY.
Voltage: is the energy given to each unit of charge that flows in a circuit
Current: is the amount of electric charge flowing past a point in a circuit each second
Wattage: is the amount of electrical energy a circuit uses each second
When you jump,you push the earth downward.Why can’t you tell that the earth has moved?
The movement of the earth is so small, especially compared to you, that you don't realize it. This is because the earth's mass is so much greater than your mass.
Describe 2 ways in which a giant boulder by the ocean may change over time.
Answer:
I'm not sure if they're right but...
1. It would erode because of the water
2. It would probably become a home for the ocean creatures
The two (2) ways in which a giant boulder by the ocean may change over time are:
1. The ocean water would change the boulder's appearance and texture.
2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.
A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.
Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.
The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.
This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.
However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:
Ocean water would change the boulder's appearance and texture. The giant boulder would be transformed into sediments due to the actions of erosion and weathering through dissolution.
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In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. What acceleration does this force produce? What is the magnitude of the force?
Answer:
a
=
F
M
a
=
137
30.8
x
=
1
2
a
t
2
x
=
1
2
⋅
137
30.8
⋅
13
2
x
=
375.86
Explanation: Hope this helps ;)
A 0.16 k/g hockey puck is moving on an icy Horizontal service with the speed of 5MSA player strikes the Puck by hockey stick after the impact the Puck moves in opposite direction with the speed of 9MS of the Puck was the in contact with the stick for 0 points 005S what is the average force of the Puck by the stick
According to Newton's second law of motion, 12.8 N is the average force of the Puck
Newton's Second Law of MotionIt states that, the rate of change of momentum is directly to the force applied. That is,
F = m(v - u)/t
Given that a 0.16 k/g hockey puck is moving on an icy Horizontal service with the speed of 5 m/s player strikes the Puck by hockey stick after the impact the Puck moves in opposite direction with the speed of 9 m/s of the Puck was the in contact with the stick for 0 points 0.05 s
The average force of the Puck by the stick can be calculated by using the formula above.
Where
m = 0.16 kgu = 5 m/sv = 9 m/st = 0.05 sSubstitute all the parameters
F = 0.16(9 - 5)/0.05
F = 0.16(4)/0.05
F = 0.64/0.05
F = 12.8 N
Therefore, the average force of the Puck by the stick is 12.8 N
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a 214kg boat is sinking in the ocean.its acceleration towards the sea floor is 6.12 m/s^2. the force of gravity that draws the boat down is partially offset by the buoyant force of the water, so what is the force pulling on the boat as it sinks?