A reaction must be spontaneous if its occurrence is exothermic with an increase in entropy.
For a reaction to be spontaneous, two factors are considered: enthalpy change (ΔH) and entropy change (ΔS). A spontaneous reaction usually has a negative ΔH, indicating that it is exothermic (releases heat).
Additionally, a spontaneous reaction has a positive ΔS, meaning there is an increase in entropy (disorder) in the system. The combination of these two factors, along with temperature (T), determines the Gibbs free energy change (ΔG), where ΔG = ΔH - TΔS.
A negative ΔG value signifies that the reaction is spontaneous. Therefore, a reaction with an exothermic occurrence and an increase in entropy is more likely to be spontaneous.
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Someone Please HELP Me
2C4H10(g) + 13O2(g) → 8CO2(g) + 10 H2O(g)
How many liters of O2 are required to produce 3.15g of carbon dioxide?
magnesium has two naturally occurring isotopes: magnesium-24 and magnesium-25. if the average atomic mass of magnesium is 24.305 amu, what are the percent abundance's of each isotope?
a. 69.5% and 30.5%
b. 50% and 50%
c. 62% and 38%
d. 0.7% and 0.3%
e. .62% and .38%
Answer:
a. 69.5% and 30.5%
Explanation:
we know there are two naturally occurring isotopes of Mg, Mg-24 and Mg-25.
First of all we will set the fraction for both isotopes
X for the isotopes having mass 25
1-x for isotopes having mass 24
The average atomic mass of Mg is 24.305 amu.
we will use the following equation,
25x + 24 (1-x) = 24.305
25x + 24 - 24x = 24.305
25x- 24x = 24.305 - 24
1x = 0.305
x= 0.305 /1
x= 0.305
0.305 × 100 = 30.5 %
30.5 % is abundance of Mg-25 because we solve the fraction x.
now we will calculate the abundance of Mg-24.
(1-x)
1-0.305 =0.695
0.695 × 100 = 69.5%
69.5% for Mg-24.
Give one example of each of the following, that happens to us in our everyday life: Explain a bit about the science behind it, so for example, for melting you can say ice cream melting in your hand, which turns from a solid to a liquid, which is melting. If you are unsure please do not answer, though if you are confident please be free to do so! Have a wonderful day or night!
a) Melting:
b) Freezing:
c) Condensation:
d) Evaporation:
e) Sublimation.
a) Melting: An example of melting that occurs in our everyday life is when we heat butter on a stovetop.
b) Freezing: Freezing is the process in which a liquid transforms into a solid upon cooling.
c) Condensation: One example of condensation that we encounter regularly is when water droplets form on the surface of a cold drink on a hot day.
d) Evaporation: Evaporation is the process by which a liquid transforms into a gas or vapor.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state.
a) Melting: Butter is a solid at room temperature, but when heat is applied, it melts into a liquid. This change is a result of the increase in temperature, which provides enough energy to overcome the intermolecular forces holding the butter molecules together.
b) Freezing:Eventually, the temperature reaches the freezing point of water (0°C or 32°F), at which the water molecules slow down and arrange themselves into a regular, crystalline structure. This transformation from a liquid to a solid state is accompanied by the release of heat energy.
c) Condensation: As the temperature decreases, the air's capacity to hold moisture decreases, causing the water vapor in the air to condense into liquid water droplets. This process occurs due to the transfer of heat energy from the warm air to the cold surface, leading to the saturation of the air and the conversion of water vapor into liquid form.
d) Evaporation: As the sun's heat energy is absorbed by the water molecules on the clothes' surface, their kinetic energy increases, causing them to break free from the liquid phase and escape into the surrounding air as water vapor. This process occurs because the molecules at the liquid surface with sufficient energy can overcome the attractive forces within the liquid and enter the gas phase.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state. An example of sublimation is the process of dry ice (solid carbon dioxide) converting into carbon dioxide gas.
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Which describes why governmental funding for scientific research is important?
Governmental funding for scientific research is essential in advancing our understanding of the world and improving our way of life.
There are several reasons why governmental funding for scientific research is important:1. Scientific research has been a critical component of advancing society. It has helped us to develop new technologies, find cures for diseases, and understand complex systems.2. Governmental funding helps to ensure that scientific research is unbiased and can be conducted without conflicts of interest. This is particularly important when research is being conducted on topics that have the potential to impact public policy.3. Governmental funding is often necessary for scientific research to be conducted at all. This is especially true for basic research, which is research that is conducted to increase our understanding of a topic without a specific goal in mind. Basic research is often not profitable for private industry, so governmental funding is necessary to ensure that it is conducted.4. Scientific research often requires expensive equipment and resources, which can be difficult for individual researchers or small organizations to afford. Governmental funding can help to provide these resources, allowing researchers to conduct more in-depth studies.Governmental funding for scientific research has been instrumental in advancing our understanding of the world and improving our way of life. Without it, many of the technological and medical advancements that we take for granted today would not exist.
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The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by the equation PV = 8.31T . Find the rate at which the volume is changing when the temperature is 290 K and increasing at a rate of 0.15 K/s and the pressure is 14 and increasing at a rate of 0.05 kPa/s.
Please show your answers to at least 4 decimal places.
(dV)/(dt) = Box LI
The rate at which the volume is changing when the temperature is 290 K and increasing at a rate of 0.15 K/s and the pressure is 14 kPa and increasing at a rate of 0.05 kPa/s is approximately -0.9474 L/s.
The rate at which the volume is changing when the temperature is 290 K and increasing at a rate of 0.15 K/s, and the pressure is 14 kPa and increasing at a rate of 0.05 kPa/s can be found using implicit differentiation.
Given: PV = 8.31T
To find dV/dt, we need to differentiate both sides of the equation with respect to time (t) while considering the chain rule:
P(dV/dt) + V(dP/dt) = 8.31(dT/dt)
Substituting the given values:
14(dV/dt) + 290(0.05) = 8.31(0.15)
Rearranging the equation to solve for dV/dt:
14(dV/dt) = 1.2465 - 14.5
14(dV/dt) = -13.2535
(dV/dt) = -13.2535/14
(dV/dt) ≈ -0.9474
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Why polymer melting point transitions are broader than low molecular compounds?
Polymer melting point transitions are broader than low molecular compounds primarily due to their molecular structure and size. Polymers consist of long, repeating chains of monomers, which creates a more complex and varied molecular arrangement.
This leads to a broader distribution of melting points because the polymer chains have varying degrees of entanglement and intermolecular forces. In contrast, low molecular compounds have smaller and simpler structures, which results in a more uniform distribution of melting points. This uniformity is due to the more consistent intermolecular forces and the absence of entanglements, allowing these compounds to have a sharper melting point transition. Furthermore, the presence of impurities or additives in polymers can also contribute to the broadening of the melting point transition. These impurities can disrupt the regularity of the polymer structure, resulting in a wider range of melting points.
In summary, the broader melting point transitions of polymers compared to low molecular compounds are a result of their complex molecular structure, varying degrees of entanglement, intermolecular forces, and the potential presence of impurities or additives.
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Which term represent a phase change ?
Burning
Melting
Expanding
Cutting
What impact does CO2 (g) dissolving into an aqueous solution of NaOH have on the molarity of the solution
The formation of sodium carbonate (Na2CO3) from the reaction between CO2 and NaOH increases the number of moles of solute particles, leading to an increase in the molarity of the solution.
The impact of CO2 (g) dissolving into an aqueous solution of NaOH is that it increases the molarity of the solution. This is because CO2 reacts with NaOH to form sodium bicarbonate (NaHCO3), which increases the number of moles of solute particles in the solution, thus increasing the molarity. The reaction is as follows:
CO2 (g) + 2NaOH (aq) -> Na2CO3 (aq) + H2O (l)
An aqueous solution of NaOH have on the molarity of the solution. The formation of sodium carbonate (Na2CO3) from the reaction between CO2 and NaOH increases the number of moles of solute particles, leading to an increase in the molarity of the solution.
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5+64
this is TOTALLY SOOOO hard so help me
^thats what she said
Answer:
69
Explanation:
I thought that I answer is correct
Answer:
The answer is 69
Explanation:
Because if you add one its 66, and so on, hope this helps! but if you add five it will be 69, if you need help with easy equations let me know
Express the dosage using the ratio format you prefer. (Use mg for milligrams and mL for an injectable solution that contains 250mg in each 0.6 mL 3. [-/3 Points] CURRENMEDMATH11 12.3.002. EP. Consider the following. A 40mg in 2.5 mL solution will be used to prepare a 26mg dosage. Calculate the dosage using ratio and proportion. Express your final answer in mL to the
40mg
mL
=
X mL
26mg
40x
X
=
=
mL
[-/1 Points] CURRENMEDMATH11 12.3.004. Calculate the dosage (in milliliters). Express your answer to the nearest tenth. Assess y A 36mg per 2 mL strength solution is used to prepare 22mg. mL
The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.
The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.
To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.
40mg in 2.5 mL solution will be used to prepare a 26mg dosage.
Let X represent the mL of the solution needed to prepare the 26mg dosage.
We can set up the proportion as follows:
40mg/2.5mL = 26mg/X mL
Cross-multiplying and solving for X, we have:
40mg * X mL = 2.5mL * 26mg
40X = 65
X = 65/40
X ≈ 1.625 mL
For the second question:
36mg per 2 mL strength solution is used to prepare 22mg.
Let Y represent the mL of the solution needed to prepare the 22mg dosage.
We can set up the proportion as follows:
36mg/2mL = 22mg/Y mL
Cross-multiplying and solving for Y, we have:
36mg * Y mL = 2mL * 22mg
36Y = 44
Y = 44/36
Y ≈ 1.222 mL
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BRAINLIEST !!! HELP PLZ
Answer:
Hcl Answer
Explanation:
may be this helpful!
The number is (400). Type the number of significant figures.
55.00 ml of perchloric acid is titrated with 0.2000 m barium hydroxide. the buret reads 0.43 ml at the start and 22.67 ml at the end point. what is the molar concentration of the original perchloric acid solution?
Answer: The molar concentration of the original perchloric acid is 0.1407 M.
The molar concentration of the original perchloric acid can be calculated using the following equation:
Molarity (M) = moles of solute (n) / volume of solution (V).
In this case, the moles of solute can be found by subtracting the volume of the base (0.43 mL) from the volume of the acid (55.00 mL) giving 54.57 mL of perchloric acid. We can then calculate the moles of solute by multiplying the volume of the acid by its molarity, which is 0.2000 M. Therefore, n = 54.57 mL x 0.2000 M = 10.914 mol.
We can now calculate the molarity of the perchloric acid using the equation M = n/V. V is the total volume of the solution, which is the volume of the acid (55.00 mL) plus the volume of the base (22.67 mL) giving 77.67 mL. Therefore, M = 10.914 mol/ 77.67 mL = 0.1407 M.
In conclusion, the molar concentration of the original perchloric acid is 0.1407 M.
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What is the difference between an electric force and an electric field?
Answer:
Electric field is how much electric force is being but out per unit charge
Explanation:
Answer:
the field strength or electric field intensity at any point in the field is defined as the force on unit positive charge placed at that point.... The electric force on the charge at any point is in the direction of tangent to the field line at that point.Why is 15 m acetic acid an appropriate solvent in which to perform rate studies of electrophilic bromintations?.
Acetic acid activates the bromine and makes it a better electrophile.
What is bromination?
When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction. After bromination, the result will have different properties from the initial reactant.
Why is 15M acetic acid used as a solvent for bromination?DCM (dichloromethane) requires more time. Acetic acid has protons that can give one of the Br (bromine) a positive charge and activate it. There is a brief loss of aromaticity that calls for high energy activation.
Refer to the attached image for bromination reaction.
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The bromine is activated by acetic acid, which improves its electrophilic properties.
What is meant by bromination?When a material gets brominated, the chemical reaction causes bromine to be added to the compound. The outcome will differ from the initial reactant in terms of its properties after bromination.Why is 15M acetic acid employed as a bromination solvent?DCM (dichloromethane) takes longer to process. One of the Br (bromine) atoms can be activated by the protons in acetic acid, which can give it a positive charge. Short-lived loss of aromaticity necessitates high-energy activation.For the reaction of bromination, refer to the attached file.To learn more about electrophilic bromination visit:
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Please help me with this chemistry problem
Answer:
below
Explanation:
Zn mole wt =65.38 145 / 65.38 =2.2 moles
S mole wt = 32 36/32 = 1.1 mole
From the balanced equation you need 8 moles of Zn for each mole of S
so you are very short of Zn <=====limiting reactant
there is a 1:1 ratio of the moles of Zn to ZnS produced....so you will get 2.2 moles of ZnS (but you will only use .275 mole of the sulfur)
Which characteristic describes the troposphere?
PLS HELP
Answer:
hope it helps..
Explanation:
The troposphere forms the lowest level of the Earth's atmosphere, extending down to the surface of the Earth. This layer also features the heaviest weight of all Earth atmosphere layers, comprising approximately 75 percent of the total atmospheric weight. The troposphere varies in thickness and height around the world.
"The pH of an aqueous solution at 25 °C was found to be 9.60.
The pOH of this solution is ____.
The hydronium ion concentration is ____ M.
The hydroxide ion concentration is ____ M.
The pOH of this solution is 4.40.
The hydronium ion concentration is 2.51 x 10⁻¹⁰ M.
The hydroxide ion concentration is 3.98 x 10⁻⁵ M.
How to find pOH of solution?To find the pOH of this solution, we can use the relationship:
pH + pOH = 14
So,
pOH = 14 - pHpOH = 14 - 9.60pOH = 4.40Therefore, the pOH of this solution is 4.40.
How to find concentration of hydronium ion?To find the hydronium ion concentration, we can use the relationship:
pH = -log[[H₃O⁺]
So,
[H₃O⁺] =\(10^-^p^H\)[[H₃O⁺] = \(10^-^9^.^6^0\)[[H₃O⁺] = 2.51 x 10⁻¹⁰ MTherefore, the hydronium ion concentration is 2.51 x 10⁻¹⁰ M.
How to find concentration of hydroxide ion?To find the hydroxide ion concentration, we can use the relationship:
pH + pOH = 14[[H₃O⁺][OH-] = 1.0 x \(10^-^1^4\)So,
[OH-] = \(10^-^p^O^H\)[OH-] = \(10^-^4^.^4^0\)[OH-] = 3.98 x 10⁻⁵ MTherefore, the hydroxide ion concentration is 3.98 x 10⁻⁵ M.
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a side reaction occurs when acid is added to the system. which species reacts with the acid?
A side reaction occurs when acid is added to the system, so the species reacts with the acid is base.
What are acids?Acids are those species which have a pH range in between 0 to 7, generally acids are present with hydrogen atom in their molecular formula.
If in any reaction after adding the acid, side reaction wiull occur then in this condition base will reacts with the acid as it has the opposite behavior as of acid and formation of salt & water molecules takes plavce.
Hence the needed species is base.
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ΔS is positive for the reaction __________. a. CaO(s) + CO2(g) -> CaCO3(s) b. N2(g) + 3H2(g) ->2NH3(g) c. 2SO3(g) -> 2SO2(g)+ O2(g) d. Ag+(aq) + Cl-(aq)-> AgCl(s) e. H2O(l) ->H2O(s)
ΔS is positive for the reaction b. N2(g) + 3H2(g) ->2NH3(g) since there is an increase in the number of moles of gas from reactants to products.
which results in a positive ΔS. The other reactions either have no change or a decrease in the number of moles of gas, resulting in a negative ΔS. Additionally, the production of CO2 in option a. and the conversion of liquid water to solid water in option e. do not directly affect the entropy of the system.
The formation of solid AgCl in option d. could result in a slight decrease in entropy due to the decreased mobility of the ions in the solid state. The decomposition of SO3 in option c. could result in a decrease in entropy due to the formation of fewer molecules from more molecules.
ΔS is positive for the reaction c. 2SO3(g) -> 2SO2(g) + O2(g). A positive ΔS indicates an increase in disorder or entropy, which occurs in this reaction as more gaseous molecules are produced from fewer reactant molecules.
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ΔS is positive for the reaction __________.
ΔS is the change in entropy, which measures the randomness or disorder of a system. A positive ΔS value indicates an increase in disorder.
a. CaO(s) + CO2(g) -> CaCO3(s)
b. N2(g) + 3H2(g) -> 2NH3(g)
c. 2SO3(g) -> 2SO2(g) + O2(g)
d. Ag+(aq) + Cl-(aq) -> AgCl(s)
e. H2O(l) -> H2O(s)
Out of the given reactions, ΔS is positive for the reaction:
c. 2SO3(g) -> 2SO2(g) + O2(g)
In this reaction, the total number of gas molecules increases from 2 to 3, resulting in an increase in randomness and disorder, leading to a positive ΔS value.
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The molar mass of a compound is 148 g/mol and its empirical formula is C4H10O. What is the molecular formula of this compound? Provide your answer below
The result is approximately 2, we'll multiply the empirical formula by this factor to obtain the molecular formula: C4H10O × 2 = C8H20O2, So, the molecular formula of the compound is C8H20O2.
To find the molecular formula of the compound, we need to determine the ratio of the molar mass to the empirical formula mass.
The empirical formula mass of C4H10O is:
4(12.01) + 10(1.01) + 1(16.00) = 74.12 g/mol
The ratio of the molar mass to the empirical formula mass is:
148 g/mol ÷ 74.12 g/mol = 1.998
This ratio is very close to 2, which means that the molecular formula must be twice the empirical formula.
Therefore, the molecular formula of the compound is: C8H20O2
Hi! To find the molecular formula of the compound, we'll first calculate the molar mass of the empirical formula C4H10O.
C4: 4 × 12.01 g/mol = 48.04 g/mol
H10: 10 × 1.01 g/mol = 10.1 g/mol
O: 16.00 g/mol
The total molar mass of the empirical formula is 48.04 + 10.1 + 16.00 = 74.14 g/mol.
Now, we'll divide the molar mass of the compound by the molar mass of the empirical formula:
148 g/mol ÷ 74.14 g/mol = 1.997 ≈ 2
Since the result is approximately 2, we'll multiply the empirical formula by this factor to obtain the molecular formula:
C4H10O × 2 = C8H20O2
So, the molecular formula of the compound is C8H20O2.
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To find the molecular formula of the compound, we need to know the molecular mass of the compound. We can calculate the molecular mass by using the molar mass and the empirical formula. the molecular formula of the compound is \(C_{8} H_{20} O\).
The empirical formula tells us the simplest whole number ratio of atoms in the compound, but it does not give us the actual number of atoms in the molecule. To determine the actual number of atoms, we need to calculate the ratio between the molar mass and the empirical formula mass.
The empirical formula mass of \(C_{4} H_{10} O\) is:
4(12.01 g/mol for carbon) + 10(1.01 g/mol for hydrogen) + 1(16.00 g/mol for oxygen) = 74.12 g/mol
The ratio of the molar mass to the empirical formula mass is:
148 g/mol ÷ 74.12 g/mol = 1.997
This value is close to 2, so we can multiply the empirical formula by 2 to get the molecular formula:
\(C_{4} H_{10} O\) x 2 = \(C_{8} H_{20} O\)
Therefore, the molecular formula of the compound is \(C_{8} H_{20} O\).
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A sample of neon gas has a volume of 7.2 mL at a pressure of 1.5atm. What is the pressure exerted by the gas if the volume is increased to 28.8 mL at constant tempature
The pressure exerted by the neon gas, when the volume is increased from 7.2 mL to 28.8 mL at constant temperature, can be calculated using Boyle's Law. The pressure exerted by the neon gas, when the volume is increased to 28.8 mL at constant temperature, is 0.375 atm.
Boyle's Law states that at constant temperature, the product of the pressure and volume of a gas remains constant. Mathematically, it can be expressed as P₁V₁ = P₂V₂. This law allows us to calculate the change in pressure when the volume changes.
In this case, the initial volume (V₁) is given as 7.2 mL, and the initial pressure (P₁) is 1.5 atm. The final volume (V₂) is 28.8 mL. By substituting these values into Boyle's Law equation, we can solve for the final pressure (P₂).
When we perform the calculations, we find that the pressure exerted by the neon gas, when the volume is increased to 28.8 mL, is 0.375 atm. As the volume increases, the pressure decreases due to the inverse relationship between pressure and volume.
Using Boyle's Law: P₁V₁ = P₂V₂
Given:
Initial volume (V₁) = 7.2 mL
Initial pressure (P₁) = 1.5 atm
Final volume (V₂) = 28.8 mL
To find the final pressure (P₂):
P₂ = (P₁ * V₁) / V₂
= (1.5 atm * 7.2 mL) / 28.8 mL
= 0.375 atm
Therefore, the pressure exerted by the neon gas, when the volume is increased to 28.8 mL at constant temperature, is 0.375 atm.
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A sample of air at room temperature in a 4.00 L container holds approximately 0.562 moles of O2and 2.11 moles of N2 along with other trace elements to total 2.67 moles. What is the mole fraction of N2 in the mixture
Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.
Molar fractionThe molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.
The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:
x=number of moles of the solute÷ total number of moles
Mole fraction of N₂ in the mixtureIn this case, you know that:
number of moles of N₂: 2.11 molestotal number of moles: 2.67 molesReplacing in the definition of mole fraction:
x=2.11 moles÷ 2.67 moles
Solving:
x= 0.79
Finally, the mole fraction of N₂ in the mixture is 0.79.
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3. Which of the following is not a compound?
water
potassium iodide
B
sodium chloride
D hydrogen
How many moles of Magnesium are present in 0.478 g of the element?
(Atomic mass: Mg-24 u)
Answer:
0.0199moles
Explanation:
The number of miles of a substance can be calculated using the formula:
Number of moles (n) = Mass (M) / Molar mass (MM)
In this question, the mass of Magnesium element (Mg) = 0.478 g while the atomic mass is 24
Therefore, number of moles of Magnesium is:
Moles = 0.478/24
Moles = 0.01992
Hence, 0.0199 moles of Magnesium are contained in 0.478 g of the element.
hi can you pls help :)
Answer:i think it is c, it explodes in water because that’s a chemical reaction
Explanation:
1. Pollutants are very unstable molecules. Do you think N, and O2 are
pollutants? Use what you know about stable and unstable molecules
to support your answer.
Answer:
A molecule is stable when there is no energetically-accessible mechanism available that allows it to reacts and form a more stable molecule or molecules whiles Are configuration of unknown atomic nuclei and electrons discovered by Reed Richard
what 3 classes of compounds are elecrolytes
Answer:
i believe it is strong acids, strong bases, and salts.
Explanation:
Hope this helps : )
what is the pH of a 9.55 x 10^-3 M solution of sodium hydroxide
Sodium hydroxide (NaOH) is a strong base that dissociates completely in water, meaning that it breaks down into its constituent ions Na+ and OH-. The concentration of OH- ions in the solution can be found using the equation:
[OH-] = Kw/[H+]
where Kw is the ion product constant for water (1.0 x 10^-14 at 25°C).
Since NaOH is a strong base, it does not contribute any H+ ions to the solution. Therefore, the [H+] can be assumed to be very small and can be ignored in the calculation. Thus:
[OH-] = Kw/[H+] = 1.0 x 10^-14/ [H+]
At 25°C, the value of Kw is 1.0 x 10^-14. Therefore:
[OH-] = 1.0 x 10^-14/ [H+] = [OH-] = 1.0 x 10^-14/9.55 x 10^-3
[OH-] = 1.05 x 10^-12 M
The pH of the solution can be calculated as:
pH = -log[H+]
Since NaOH is a strong base, the [H+] can be assumed to be very small and can be ignored. Therefore:
pH = 14 - pOH = 14 - (-log[OH-]) = 14 - (-log(1.05 x 10^-12))
pH = 14 + 11.98 = 25.98
Therefore, the pH of a 9.55 x 10^-3 M solution of sodium hydroxide is approximately 14.02.
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what is a substance that doesn't dissole in water
Answer:
insoluble substances
Explanation: