in endothermic reaction heat is added
Classify each of the following as acombination, decomposition, singlereplacement, double replacement, orcombustion reaction:a. 2 Fe2O3(s) + 3 C(s) → 3 CO2(g) + 4 Fe(s)b. 2 KClO3(s) → 2 KCl(s) + 3 O2(g)c. 2 C3H6(g) + 9 O2(g) → 6 CO2(g) + 6 H2O(g) + energy
a) As we can see, on of the reactant has atoms Fe and O, while the other has only C. On the products side, it is the opposite, Fe is alone and C is with O, so the O atoms went from Fe to C, which means this is a single displancemente reaction, since one of the atoms was diplaces from one compound to tthe other.
b) This reaction starts with only one compound and ends with more than one product. This is characteristics of a decomposition reaction, where one compound is decomposed into two of more others.
c) In this reaction, we can see that we have a compound reacting with O₂ and forming only CO₂ and H₂O, and there are energy being released.
This is characteristics of a combustion reaction, which is a reaction where a given compound reacts with O₂ and releases energy, forming CO₂ and H₂O.
An electrolytic cell is prepared by connecting Ni(syNi2+ (aq) to Sn(s)/sn2(aq). Which of the following statements is/are true? (Select all that apply.) Refer to the table of reduction potentials on the last page of the note packet. O The Nics)/Ni2+ (aq) serves as the cathode. O At standard conditions, a minimum of 0.10V is required from a power supply for electrons to flow in the electrolytic cell. O The electrons flow from the Ni(s) to the Sn(s), O The electrons flow from cathode to anode. O Electrolytic cells do not require a salt bridge, O In an electrolytic cell, oxidation occurs at the anode.
The statements that are true are:
The Ni(s)/Ni2+ (aq) serves as the cathode.
The electrons flow from the Ni(s) to the Sn(s).
The electrons flow from the cathode to the anode.
In an electrolytic cell, oxidation occurs at the anode.
In an electrolytic cell, the electrode with the lower reduction potential, or the cathode, is the one from which electrons flow. Since Ni(s)/Ni2+ (aq) has a reduction potential of -0.25V, it is the cathode of the cell. The electrons flow from the cathode to the anode, which has a higher reduction potential. In this case, the anode is Sn(s)/Sn2+ (aq), which has a reduction potential of -0.14V. The electrons flow from the Ni(s) to the Sn(s) so that oxidation occurs at the anode, as electrons are removed from the system. A salt bridge is required to complete the circuit, as it allows for the flow of ions between the two solutions. A power supply is also required, but the voltage is not specified in the question. Thus, the statement that a minimum of 0.10V is required from a power supply for electrons to flow in the electrolytic cell is false.
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What mass is contributed by Br-79?
Answer:
Calculate the mass of BR -79? Bromine has 2 naturally occurring isotopes (Br-79 and Br-81) and has an atomic mass of 79.904 amu
Explanation:
if i get this wrong srry
I need help calculating the error % in molar mass
Aqueous solution of two salts Na2CO3 and Na2SO4 is given. How to prove the simultaneous occurrence of both carbonate and sulphate anions?
Answer:
See the answer below.
Explanation:
If an aqueous solution of two salts contains both Na2CO3 and Na2SO4, the following steps will prove the occurrence of both carbonate and sulphate ions:
1. Add a dilute acid (such as HCl) to the solution. The presence of carbonate ion will result in the release of carbon dioxide gas which will be shown by formation of effervescent bubbles. The gas can be proven to be carbon dioxide by channeling it into a lime water which usually turns milky with the presence of the gas.
\(CO^{2-}_3(aq) + 2H^+(aq) ==> H_2O(l) + CO_2(g)\)
2. Add barium chloride to an acidified portion of the aqueous solution. The presence of sulphate ion will be indicated by the formation of white barium sulphate precipitate. Initial acidification is done to disperse off any carbonate ion that might be present in the solution and give a false-positive white precipitate result.
\(Ba^{2+}(aq) + SO^{2-}_4(aq) --> BaSO_4(s)\)
Read the chemical equation.
N2 + 3H2 - 2NH3
Using the volume ratio, determine how many liters of NH3 is produced if 4.2 liters of H2 reacts with an excess of N2
if all measurements are taken at the same temperature and pressure?
A 2.8 liters
B 3.2 liters
C 5.4 liters
D 6.3 liters
Answer:
A 2.8 liters
Explanation:
Step 1: Write the balanced equation
N₂ + 3 H₂ ⇄ 2 NH₃
Step 2: Establish the appropriate volume ratio
At the same temperature and pressure, the volume ratio of H₂ to NH₃ is 3:2.
Step 3: Calculate the volume of ammonia produced from 4.2 L of hydrogen
4.2 L H₂ × 2 L NH₃/3 L H₂ = 2.8 L
Students want to gather evidence for the claim that the number of atoms present before a chemical reaction is equal to the number of atoms present after the chemical reaction. They decide to react vinegar and baking soda in a sealed plastic bag. Which of the following will provide the evidence the students need?
A. The mass of the plastic bag, baking soda, and vinegar before the reaction was equal to the mass after the reaction.
B. Bubbles were produced during the reaction, which meant that a gas was being produced.
C. The plastic bag did not change in any way, indicating that it was not involved in the reaction.
D. The mass of the baking soda was exactly equal to the mass of the vinegar used to create the chemical reaction. THIS IS DUE IN AN HOUR HELPPP!!!
The mass of the plastic bag, baking soda, and vinegar before the reaction was equal to the mass after the reaction. Option A.
Law of conservation of atomsAtoms, mass, and energy are conserved during chemical reactions. Even though their forms may change after reactions.
For a reaction involving vinegar and baking soda, the equation can be expressed as:
vinegar + baking soda ---> carbon dioxide + sodium acetate + water
or
\(CH_3COOH (aq) + NaHCO_3 (aq) --- > CH_3COONa (aq) + H_2O (l) + CO_2 (g)\)
In other words, sodium acetate, water, and carbon dioxide gas are produced in the reaction. Assuming that the reaction vessel is not sealed, the gas would escape away from the vessel.
Since the vessel was sealed, the mass of the plastic bag, baking soda, and vinegar before the reaction will be equal to the sum of the masses of the plastic bag and the products after the reaction.
This will show that the number of atoms present before the reaction is the same as the number of atoms present after the reaction.
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Your first post will be about one of the following topics: how stoichiometry is used
in formulating airbags, producing contrails, or formulating rocket engines .It must
be a minimum of 1 paragraph (at least 6-8 complete sentences), use lesson
specific vocabulary, and be classroom appropriate.
Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
How stoichiometry is used in formulating airbags?
The quick chemical decomposition of solid sodium azide (NaN3) that allows the air bag to inflate fast at any time when the car hit anything. The decomposition reaction is initiated in a car by a small ignition that occurs due to collision sensing mechanism. The nitrogen gas produced during the reaction inflates the air bag which protect the person in the car.
So we can conclude that Stoichiometry is used in formulating airbags that shows relationship between product and reactants.
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Stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines so as to ensure the required amount of products are formed.
What is stoichiometry?Stoichiometry is the molar relationship between the reactants and products of a reaction.
It is the ratio in which moles of reactants of a reaction combine to form moles of products.
Stoichiometry is important in determining the amount of reactants required to produce a given amount of products.
For example, stoichiometry is important in formulating airbags, producing contrails, or formulating rocket engines in order to ensure the mass of reactants used is enough to produce the required products.
In conclusion, stoichiometry of a reaction provides the knowledge about the amount of reactants required to form products.
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Which of the following statements about valence electrons is true?
A) They are the most tightly held electrons.
B) They do not participate in chemical reactions.
C) They are the outermost electrons.
D) They reveal the period number of a second-row element
The statement that is true regarding valence electrons is that they are the outermost electrons (option C).
What are valence electrons?Valence electrons in chemistry are any of the electrons in the outermost shell of an atom. They are capable of forming bonds with other atoms.
In chemistry and physics, a valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed.
For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons.
Therefore, options A, B and D are incorrect making option C the correct option regarding valence electrons.
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What are 5 things that change so slow they are almost unnoticeable
Answer:
people ,shape ,behavior, grades ,friends
3. In your experiment, you will weigh out between 0.25 g and 0.50 g of sodium hydrogen
carbonate. If you start with 0.45 g of sodium hydrogen carbonate, how much 3.0 M
HCI should you add to get the most NaCl?
you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.
StepsTo determine how much 3.0 M HCl is needed to react with 0.45 g of sodium hydrogen carbonate (NaHCO3) and get the most NaCl, you need to first calculate the number of moles of NaHCO3 that you have:
molar mass of NaHCO3 = 84.01 g/mol
moles of NaHCO3 = mass / molar mass = 0.45 g / 84.01 g/mol = 0.00536 mol
Next, you need to determine the stoichiometry of the reaction between NaHCO3 and HCl. The balanced chemical equation for this reaction is:
NaHCO3 + HCl → NaCl + H2O + CO2
From this equation, you can see that one mole of NaHCO3 reacts with one mole of HCl to produce one mole of NaCl. Therefore, you need 0.00536 moles of HCl to react with 0.00536 moles of NaHCO3.
To calculate the volume of 3.0 M HCl needed to provide 0.00536 moles of HCl, you can use the following equation:
moles of solute = concentration x volume of solution (in liters)
Rearranging this equation to solve for the volume of solution gives:
the volume of solution = moles of solute/concentration
Plugging in the values gives:
volume of solution = 0.00536 mol / 3.0 mol/L = 0.00179 L or 1.79 mL
Therefore, you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.
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what challenges do the three industries have in making better batteries
Answer:
1. Materials: One of the biggest challenges in making better batteries is finding the right materials that can store more energy and last longer. The materials need to be efficient in terms of energy density, cost, and environmental impact.
2. Manufacturing: The production of batteries is a complex and expensive process that requires specialized knowledge and equipment. Scaling up production can be a challenge, and the cost of manufacturing high-quality batteries is still relatively high.
3. Safety: The safety of batteries is a major concern. The risk of fire or explosion is always present, particularly with lithium-ion batteries. Improvements in battery safety are needed to reduce the risk of accidents and increase confidence in battery technology.
4. Environmental impact: The production and disposal of batteries can have a significant environmental impact. The mining of metals and other materials used in batteries can have negative environmental consequences, and the disposal of used batteries can lead to pollution.
5. Performance: The performance of batteries can be affected by temperature, humidity, and other environmental factors. Improving battery performance in extreme conditions and increasing their durability is a priority for the industry.
How many grams are 5.83 moles of C2H2
in the photosynthesis the energy starts as ___ energy and ends up as___energy
light heat
chemical: chemical
heat light
light chemical
Answer: Light, Chemical
Explanation: This is the answer because "photosynthesis takes place in two stages: the light-dependent reactions and the Calvin cycle. In the light-dependent reactions, which take place at the thylakoid membrane, chlorophyll absorbs energy from sunlight and then converts it into chemical energy with the use of water." - source https://opentextbc.ca/
In the photosynthesis the energy starts as Light energy and ends up as Chemical Energy. Hence option (D) is correct
What is Photosynthesis ?The process by that inexperienced plants and a few different organisms use daylight to synthesize nutrients from carbonic acid gas and water. chemical action in plants usually involves the inexperienced pigment and generates element as a by-product.
Photosynthesis may be a method employed by plants and different organisms to convert lightweight energy into energy that, through internal respiration, will later be discharged to fuel the organism's activities.
photosynthesis takes place in 2 stages: the light-dependent reactions and also the Calvin cycle. within the light-dependent reactions, that manifest itself at the thylakoid membrane, pigment absorbs energy from daylight and so converts it into energy with the employment of water.
Therefore, In the photosynthesis the energy starts as Light energy and ends up as Chemical Energy. Hence option (D) is correct
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If a radioactive isotope of thorium (atomic number 90, mass number 232) emits 6 alpha particles and 4 beta particles during the course of radioactive decay, what is the mass number of the stable daughter product?
Answer:
The mass number of the stable daughter product is 208
Explanation:
First thing's first, we have to write out the equation of the reaction. This is given as;
²³²₉₀Th → 6 ⁴₂α + 4 ⁰₋₁ β + X
In order to obtain the identity of X, we have to obtain it's mass numbers and atomic number.
There is conservation of matter so we expect the mass number to remain the same in both the reactant and products.
Mass Number
Reactant = 232
Product = (6* 4 = 24) + (4 * 0 = 0) + x = 24 + x
since reactant = product
232 = 24 + x
x = 232 - 24 = 208
Atomic Number
Reactant = 90
Product = (6* 2 = 12) + (4 * -1 = -4) + x = 8 + x
since reactant = product
90 = 8 + x
x = 90 - 8 = 82
Which is NOT a chemical property of a matter sample?
A. Texture
B. Oxidation
C. Rusting
D. Producing a gas
Answer:
A. Texture
Explanation:
Everything else is a chemical reaction
Based on the following equation, how many moles of hydrochloric acid (HCl)are needed to react with 0.44 moles of potassium
permanganate (KMnO4)?
2KMnO4 + 8HCI - 3Cl2 + 2MnO2 + 4H2O + 2KCI
Answer:
1.76 moles of HCl.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl
From the balanced equation above,
2 moles of KMnO₄ reacted with 8 moles of HCl.
Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:
From the balanced equation above,
2 moles of KMnO₄ reacted with 8 moles of HCl.
Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.
Thus, 1.76 moles of HCl is needed for the reaction.
The mass of the evaporating dish was 22.45 g. The evaporating dish and mixture was 33.62 g. The mass of the evaporating dish and sand was 25.46 g. The mass of 2nd evaporating dish was 23.46. The mass of the 2nd evaporating dish and dry salt was 25.83g. What are the mass percentages of the components? Show work.
is a pH an atom, ion, molecule, macromolecule, or a cell?
Although there is some variation amongst tissues, the physiologically typical intracellular pH ranges from 7.0 to 7.4. Skeletal muscle in mammals typically has a pHi of 6.8 to 7.1.
A cell is it an atom?A cell is the basic membrane-bound living thing and can either have one or more cells. All the molecules required for an organism to function are found in cells. An atomic is 10-10m in size. In contrast, a cellular is 10-6 metres in size. Because all cells are composed of atoms, they are therefore bigger than atoms.
What keeps a cell's pH stable?Acid excretion, efflux through plasma membranes, and buffering mechanisms all work together to precisely preserve the pH of body fluids. Protons are extruded from the cytosol into the extracellular space through the organic cation transporter (MCT) and the Na+/H+ exchanger (NHE).
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What would you do during a zombie apocalypse
A. run and hide
B. fight back
C. save some people
D. raid survivor's homes
E. keep your family alive
Answer:
C
Explanation:
because then you'd be able to make a group to raid, run with you, and save more people.
If a snail crawls 55 inches per day, how many centimeters will he crawl in 23 days?
Group of answer choices
5.0X102 cm
1.06 cm
3.2X103 cm
6.1 cm
2.0X10-3 cm
If a snail crawls 55 inches per day ,the snail will crawl approximately \(3.2 * 10^3 centimeters.\)
To convert inches to centimeters, we need to use the conversion factor: 1 inch = 2.54 centimeters.
First, let's calculate the distance the snail crawls in inches in 23 days. We can multiply the daily distance by the number of days:
Distance in inches = 55 inches/day × 23 days = 1265 inches.
Now, to convert the distance from inches to centimeters, we multiply the distance in inches by the conversion factor:
Distance in centimeters = 1265 inches × 2.54 cm/inch = 3215.1 cm.
Rounding to the appropriate number of significant figures, the snail will crawl approximately 3215 cm or \(3.2 * 10^3 centimeters.\) in 23 days.
Therefore, the answer is Option 3:\(3.2 * 10^3 centimeters.\)
This means that in 23 days, the snail will crawl approximately\(3.2 * 10^3 centimeters.\)
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5.86 ■ Liquid oxygen for use as a rocket fuel can be produced by cooling dry air to −183°C, where the O2 condenses. How many liters of dry air at 25°C and 750 torr would need to be processed to produce 150 L of liquid O2 at −183°C? (The mole fraction of oxygen in dry air is 0.21, and the density of liquid oxygen is 1.14 g/mL.)
Approximately 631.5 liters of dry air at 25°C and 750 torr would need to be processed to produce 150 liters of liquid \(O_2\) -183°C.
To solve this problem, we need to consider the ideal gas law and the molar volume of gases.
First, we can calculate the number of moles of oxygen in 150 L of liquid \(O_2\) at -183°C. To do this, we divide the mass of liquid oxygen by its molar mass:
Mass of liquid oxygen = volume of liquid oxygen * density of liquid oxygen = 150 L * 1.14 g/mL = 171 g
Molar mass of oxygen (O2) = 32 g/mol
Number of moles of oxygen = mass of oxygen / molar mass of oxygen = 171 g / 32 g/mol ≈ 5.34 mol
Since the mole fraction of oxygen in dry air is given as 0.21, we can calculate the total moles of dry air needed to produce 5.34 mol of oxygen:
Moles of dry air = moles of oxygen / mole fraction of oxygen = 5.34 mol / 0.21 ≈ 25.43 mol
Now, we can use the ideal gas law to calculate the volume of dry air at 25°C and 750 torr (convert to atm) that corresponds to 25.43 mol:
PV = nRT
P = 750 torr * (1 atm / 760 torr) ≈ 0.987 atm
V = volume of dry air (unknown)
n = 25.43 mol
R = 0.0821 L·atm/(mol·K)
T = 25°C + 273.15 = 298.15 K
Solving for V:
V = nRT / P = (25.43 mol)(0.0821 L·atm/(mol·K))(298.15 K) / 0.987 atm ≈ 631.5 L
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If the pressure on a gas decreases from 1480 mm Hg at 478 K to 555 mm Hg, what is the final temperature?
V1 = _____ P1 = _____ T1 = _____
V2 = _____
Law:
P2 = _____
T2 = _____
Answer:
179 K
Explanation:
From the question given above, the following data were:
Initial pressure (P₁) = 1480 mm Hg
Initial temperature (T₁) = 478 K
Final pressure (P₂) = 555 mm Hg
Final temperature (T₂) =?
The final temperature of the gas can be obtained as follow:
P₁/T₁ = P₂/T₂
1480 / 478 = 555 / T₂
Cross multiply
1480 × T₂ = 478 × 555
1480 × T₂ = 265290
Divide both side by 1480
T₂ = 265290 / 1480
T₂ ≈ 179 K
Therefore, the final temperature of the gas is 179 K
Using Boyle's Law solve the following: An unknown gas has a volume of 200.0 mL and a pressure of 350.0 torr, pressure were increased to 700.0 torr, what is the resulting volume?
Answer:
400 mL
Explanation:
Boyle's Law: \(P_1*V_1 = P_2*V_2\)
Let x = the resulting volume
350 (200) = 700 (x)
x = 400 mL
How many grams of barium hydroxide are required to react with 12.2 grams of caesium phosphate?
Taking into account the reaction stoichiometry, a mass of 6.24 grams of Ba(OH)₂ are required to react with 12.2 grams of caesium phosphate.
Reaction stoichiometryIn first place, the balanced reaction is:
3 Ba(OH)₂ + 2 Cs₃PO₄ → Ba₃(PO₄)₂ + 6 CsOH
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Ba(OH)₂: 3 molesCs₃PO₄: 2 molesBa₃(PO₄)₂: 1 moleCsOH: 6 molesThe molar mass of the compounds is:
Ba(OH)₂: 168.3 g/moleCs₃PO₄: 493.7 g/moleBa₃(PO₄)₂: 592.9 g/moleCsOH: 149.9 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Ba(OH)₂: 3 moles ×168.3 g/mole= 504.9 gramsCs₃PO₄: 2 moles ×493.7 g/mole= 987.4 gramsBa₃(PO₄)₂: 1 mole ×592.9 g/mole= 592.9 gramsCsOH: 6 moles ×149.9 g/mole= 899.4 gramsMass of Ba(OH)₂ requiredThe following rule of three can be applied: If by reaction stoichiometry 987.4 grams of Cs₃PO₄ react with 504.9 grams of Ba(OH)₂, 12.2 grams of Cs₃PO₄ react with how much mass of Ba(OH)₂?
mass of Ba(OH)₂= (12.2 grams of Cs₃PO₄× 504.9 grams of Ba(OH)₂)÷ 987.4 grams of Cs₃PO₄
mass of Ba(OH)₂= 6.24 grams
Finally, a mass of 6.24 grams of Ba(OH)₂ are required.
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When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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It is difficult to break the ionic bonds in a compound because of the
NaOH(aq) is transferred into a test tube. CaCl2(aq) is added to the tube. What is the formula for the precipitate (if any) that forms
Answer:
2NaOH (aq) + CaCl2 (aq) -> 2NaCl(aq) + Ca(OH)2(s)
Formula of precipitate: Ca(OH)2 (s)
Explanation:
First, we do the double replacement reaction to determine our chemical equation between the reactants and products. Once we have our products, with a solubility chart (I added one below) we can determine which of the products is soluble or insoluble.
In this case NaCl is soluble or aqueous (meaning it can dissolve in water) and Ca(OH)2 is insoluble (meaning that when the reactions takes place, these two will form a solid/precipitate)
When potassium chloride is heated it decomposes into potassium chloride and oxygen gas.
a. Write a balanced chemical equation for this decomposition reaction.
b. Determine how many liters of oxygen gas at STP could be produced from 500.0 g of potassium chlorate.
134.3 liters of oxygen gas at STP could be produced from 500.0 g of potassium chlorate.
We can use the ideal gas law to find the volume of hydrogen at STP (standard temperature and pressure, 0°C and 1 atm) that would contain 58.7 moles: PV = nRT
(1 atm) V = (58.7 mol) (0.08206 L atm/mol K) (273.15 K), V = 1,275 L
Finally, we can use the ideal gas law to calculate the volume of O2 produced at STP (standard temperature and pressure, which is 0°C and 1 atm):
PV = nRT
V = nRT / P
V = (6.12 mol)(0.0821 L•atm/mol•K)(273 K) / 1 atm
V = 134.3 L
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This is for science! I really need help.
Answer
Solid
liquid
Gas
Explanation: