Known :
z1 = 380 ft
z2 = 210 ft
D1 = 8 in
D2 = 4 in
hL = 36 ft
Solution :
Continuity Equation
Q1 = Q2
A1 • V1 = A2 • V2
(πD1²/4) • V1 = (πD2²/4) • V2
D1² • V1 = D2² • V2
8² • V1 = 4² • V2
V2 = 4V1 ... (i)
Energy Equation :
P1/γ + V1²/2g + z1 = P2/γ + V2²/2g + z2 + hL
Since P1 = P2, then
V1²/2g + z1 = V2²/2g + z2 + hL
V1²/2(32.2) + 380 = V2²/2(32.2) + 210 + 36
V2² - V1² = 8.63 × 10³ ... (ii)
Subtitute (i) into (ii)
(4V1)² - V1² = 8.63 × 10³
15V1² = 8.63 × 10³
V1 = 24 ft/s
Q = A1 • V1
Q = [π(8/12)² / 4] • 24
Q = 8.377 cfs
a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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What causes perfume particles to move from an area of many perfume particles, to your nose where there is fewer perfume particles?
Please ans me this question
Answer:
Diffusion
Explanation:
Diffusion is a phenomenon whereby particles move from an area of higher concentration to an area of lower concentration.
Now, when the chemical substances of the perfume are sprayed in a room, their particles will now mix with the particles of the surrounding air.
Furthermore, the particles of the perfume which is like gas will be free to move in a very fast manner in all directions. Thus, they will eventually spread throughout the whole area where you are and thus move from the area where it is sprayed which is the area of higher concentration to the area where you are which includes your nose which is the area of lower concentration.
A 50 kg mass is placed 2 meters from the fulcrum. To balance the lever, a second object is placed 4 meters
from the fulcrum. What is the mass of the second object?
Answer:
mass =25 kg
using clockwise moment = anticlockwise moment
a 3.6kg cat is laying on a tree branch, 3 meters above the ground what is the cat's potential energy
Answer:
105.84 JoulesExplanation:
potential energy = mgh
Given
Mass m = 3.6kg
g = 9.8m/s²
Height = 3m
Substitute
potential energy = 3.6*9.8 * 3
potential energy= 105.84 Joules
Hence the cat's potential energy is 105.84 Joules
Question 10 of 10 Which image shows an example of the strong nuclear force in action?
A worker drags a rubbish bin with an effective constant horizontal force of 100N on a horizontal surface. If the bin starts from rest and moves distance of 100m in 10s with the constant horizontal force exerted to overcome a constant Kinetic friction of 20N, what is the mass of the bin?
We can use the kinematic equation for constant acceleration to solve this problem .The mass of the bin is 40 kg.
Kinematics: What is it?Kinematics is the study of how points, objects, and groups of objects move without considering the factors that generate those motions. The part of classical mechanics known as kinematics addresses the motion of points, objects, and systems made up of collections of items.
\(x = 1/2 * a * t^2 + v0 * t\)
\(a = 2(x - v0 * t) / t^2\)
In this case, x = 100 m, t = 10 s, v0 = 0, and the net force acting on the bin is:
F_net = F_applied - F_friction
F_net = 0
Therefore, we can solve for the mass of the bin:
F_applied - F_friction = ma
100 N - 20 N = m * a
Simplifying, we get:
80 N = m * a
\(a = 2(x - v0 * t) / t^2\)
\(= 2(100 m - 0) / (10 s)^2\)
\(= 2 m/s^2\)
Substituting this value into the previous equation, we get:
\(80 N = m * 2 m/s^2\)
Simplifying, we get:
m = 40 kg
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A 770-kg two-stage rocket is traveling at a speed of 6.90×103 m/s away from Earth when a predesigned explosion separates the rocket into two sections of equal mass that then move with a speed of 2.60×103 m/s relative to each other along the original line of motion.What is the speed of each section (relative to Earth) after the explosion?How much energy was supplied by the explosion?
Answer:
Explanation:
Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.
Each half will have a mass of 770/2 = 385 kg
Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s
Now add back the reference frame velocity to get velocity relative to earth.
Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s
Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s
In the moving reference frame, each half will have kinetic energy which could only come from the explosion
KE = ½(385)(1.3 x 10³)² = 325,325,000 J
2(325,325,000) = 650,650,000 J released in the explosion.
Rounding to the three significant figures of the problem numerals
E = 6.50 x 10⁸ J or 650 MJ released
A man stranded on a planet that has no magnetic field has two bars of iron in his possession. One is magnetized, and the other is not. How can he tell the difference between the two irons
There are a few ways that a man stranded on a planet with no magnetic field could tell the difference between a magnetized iron bar and a non-magnetized iron bar and they are as follows:
Attraction to a magnetic object,Magnetic field detection,Compass needle deflection,Induced magnetism, andPhysical propertiesWhat is a magnetic field?A magnetic field refers to a vector field that explains the magnetic effects on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field. Different ways of detecting a magnetic field are listed and explained below:
Attraction to a magnetic object: The magnetized iron bar will be attracted to a magnetic object (such as a magnet), while the non-magnetized iron bar will not be attracted.
Magnetic field detection: The magnetized iron bar will produce a magnetic field that can be detected using a device such as a magnetometer. The non-magnetized iron bar will not produce a detectable magnetic field.
Compass needle deflection: The magnetized iron bar will deflect the needle of a compass, while the non-magnetized iron bar will not.
Induced magnetism: The magnetized iron bar can be used to magnetize another iron bar through the process of induced magnetism. This can be tested by attempting to use the magnetized iron bar to magnetize the other iron bar. If the other iron bar becomes magnetized, it was originally non-magnetized. If the other iron bar does not become magnetized, it was already magnetized.
Physical properties: The magnetized iron bar may have different physical properties (such as density or color) compared to the non-magnetized iron bar, depending on the process used to magnetize it. These differences can be observed and used to distinguish between the two bars.
Therefore, the correct answer is as given above
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Could you help me with this question please
Charge =
(current in Amperes) x (time in seconds)
1 Ampere means 1 Coulomb per second
240 Coulombs
90 Coulombs
150 Coulombs
The shaded area of the figure may be found by subtracting the area of the unshaded portion from the total area of the figure. Use this approach to find the area of the shaded region. Use 3.14 as an approximation for . for a (a circle within a square) 14m
Given,
diameter of the circle=side of the square, d=14 m
Therefore the radius of the circle, r=7 m
Area of the circle is given by,
\(A=\pi r^2\)On substituting th known values,
\(A=3.14\times7^2=153.86m^2\)The area of the square is given by,
\(A_S=d^2\)On substituting the known values,
\(A_S=14^2=196m^2\)The area of the shaded region is given by,
\(A_R=A_S-A=196-153.86=42.14m^2\)Therefore, the area of the shaded region is 42.14 m²
Sodium has a density of 1.95 g/cm3. What is the volume of 56.2 g of sodium?
Answer: couldn't type in that little 3 haha
Explanation:
Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. The spring constant k is
N
200
m
What is the elastic potential energy stored from the spring's compression?
Khan aced my?
Answer:
6.25J
Explanation:
bc that’s the answer on khan
Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. If the spring constant k is 200 N/m, then the elastic potential energy stored from the spring's compression would be 6.25 J.
What is the spring constant?The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.
The mathematical relation for calculating the spring constant is as follows
F = - Kx
as given in the problem Two carts connected by a 0.50 m spring hit a wall, compressing the spring to 0.25 m. If the spring constant k is 200 N/m,
The elastic potential energy stored is given by
E = 1/2 kx²
=0.5×200×0.25²
=6.25 J
Thus, the elastic potential energy stored from the spring's compression would be 6.25 J.
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which one of the following statements best describes the objective of a heat engine? multiple choice question. transform heat into work transform one form of work into another transform work into heat transform one form of heat into another
The objective of a heat engine is to transform heat into work. So, correct option is A.
What do you mean by heat engine?A heat engine is a device that converts thermal energy (heat) into mechanical work. It operates by absorbing heat from a hot source, such as a furnace, and converting it into useful mechanical energy, such as rotating a shaft or driving a machine. The efficiency of a heat engine is determined by the difference between the temperature of the hot source and the temperature of the cooled working fluid (usually air or water). Examples of heat engines include internal combustion engines in cars, steam turbines in power plants, and Stirling engines in heat pumps and refrigeration systems.
The objective of a heat engine is to transform heat into work. A heat engine is a device that uses heat energy from a high-temperature source to perform mechanical work by using a thermodynamic cycle. The basic idea behind a heat engine is to extract thermal energy from a high-temperature source, convert some of this energy into useful mechanical work, and then reject the remaining heat to a lower-temperature sink. The efficiency of a heat engine is determined by the amount of thermal energy that is converted into useful work and the amount of heat that is rejected to the lower-temperature sink.
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hi i need help withMaria has already written Two-fifths of her 1,000 word essay. If she continues writing at the same pace of 6One-half words per minute, which expression shows the amount of time it will take her to write the rest of the essay?
ANSWER:
STEP-BY-STEP EXPLANATION:
Given:
\(undefined\)Can someone please check my review answers before I take my exam (sorry I’m advance for poor quality)
Answer:
Explanation: #1 is A #2 is C #3 is correct #4 is correct #5 is correct
Race: Blythe and Geoff compete in a 1-km race. Blythe’s strategy is to run the first 600 m of the race at a constant speed of 4 mm/ss, and then accelerate with constant acceleration to her maximum speed of 7.5 mm/ss, which takes her 1 min, and finish the race at that speed. Geoff decides to accelerate with constant acceleration to his maximum speed of 8 m/s at the start of the race and to maintain that speed throughout the rest of the race. It takes Geoff 3 min to reach his maximum speed. Who wins the race?
Answer:
From the value of each person's time to finish the race, it can be concluded that Geoff will win the race.
Explanation:
Given;
total distance to be covered, d = 1000 m
first distance covered by Blythe, \(d_b_1\) = 600 m
constant speed of Blythe at the first stage, \(v_b_1\) = 4 m/s
final speed of Blythe, \(v_b_f\) = 7.5 m/s
time of Blythe's constant acceleration, \(t\) = 1 min = 60 s
initial speed of Geoff, \(v_g_1\) = 0
final speed of Geoff, \(v_g_f\) = 8 m/s
time of Blythe's constant acceleration, \(t\) = 3 min = 180 s
The acceleration of Blythe is given as;
\(a_b = \frac{dv}{dt} = \frac{7.5 - 4}{60} = 0.0583 \ m/s^2\)
distance covered by Blythe during this acceleration is given as;
\(d_{a_b} = v_b_1t + \frac{1}{2} a_b t^2\\\\d_{a_b} = 4*60 + \frac{1}{2}(0.0583) (60)^2\\\\d_{a_b} = 344.94 \ m\)
The remaining distance covered by 7.5 m/s is given as;
\(d_f = d - (600 + 344.94)\\\\d_f = 1000- (944.94)\\\\d_f = 55.06 \ m\)
The total time for Blythe to covere the entire distance = time taken to cover 600 m + time taken to cover 344.94 m + time taken to cover 55.06 m
\(t_b = \frac{600 \ m}{4 \ m/s}\ +\ 60 s \ + \ \frac{55.06 \ m}{7.5 \ m/s} \\\\t_b = 150 s \ + \ 60s \ + \ 7.34 s\\\\t_b = 217.34 s\)
The acceleration of Geoff is given as;
\(a_g = \frac{dv}{dt} = \frac{8 -0}{180} = 0.044 \ m/s^2\)
distance covered by Geoff during this acceleration is given as;
\(d_{a_g} = v_g_1 + \frac{1}{2}a_gt^2\\\\ d_{a_g} =0 + \frac{1}{2}(0.044)(180)^2\\\\ d_{a_g} = 712.8 \ m\)
The remaining distance covered by 8 m/s is given a;
\(d_f = 1000 \ m - 712.8 \ m\\\\d_f = 287.2 \ m\)
The total time for Geoff to covere the entire distance = time taken to cover 712.8 m + time taken to cover 287.2 m
\(t_g = 180s + \frac{287.2 \ m}{8 \ m/s} \\\\t_g = 180s + 35.9 s\\\\t_g = 215.9 s\)
Therefore, from the value of each person's time to finish the race, it can be concluded that Geoff will win the race
the two forces acting on a boat or some other floating object _______are and gravity
Answer:
The two forces acting on a boat or some other floating object are buoyancy and gravity
Answer: buoyant forceExplanation:two forces acting on a boat or some other floating object are buoyant force and gravityhi friend your answerI hope it will be helpful for you
mark as brainest answer
thank you
A person hears sounds with a frequency in the range of about 16 Hz to 20000 Hz. What is the wavelength of sound in air and water corresponding to these frequencies?
Please let me know the answer and how you got the answer (what formula you used)
Answer:
v=f×λ
Explanation:
v=f×λ
v is the speed of sound
f is the frequency of sound
λ is the wavelength
The speed of sound in air and water is different, but the frequency can be calculated from the given range above.
HAVE FUN LEARNING!!!( sorry im just to lazy to get the number so...)
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Consider the boundary-value problem introduced in the construction of the mathematical model for the shape of a rotating string: T d2y dx2 + rhoω2y = 0, y(0) = 0, y(L) = 0. For constants T and rho, define the critical speeds of angular rotation ωn as the values of ω for which the boundary-value problem has nontrivial solutions. Find the critical speeds ωn and the corresponding deflections yn(x). (Give your answers in terms of n, making sure that each value of n corresponds to a unique critical speed.)
Answer:
\(y_n(x) =C_n \sin \sqrt{\frac{\rho}{T} } w_nx=C_n \sin \sqrt{\frac{\rho}{T} } \sqrt{\frac{T}{\rho} } \frac{n \pi}{L} x\)
\(y_n(x) = C_n \sin \frac{n \pi x}{L}\)
Explanation:
The given differential equation is
\(T\frac{d^2y}{dx^2} + \rho w ^2y=0\) and y(0) = 0, y(L) =0
where T and ρ are constants
The given rewrite as
\(\frac{d^2y}{dx^2} + \frac{\rho w^2}{T} y=0\)
auxiliary equation is
\(m^2+ \frac{\rho w^2}{T} =0\\\\m= \pm\sqrt{\frac{\rho}{T} } wi\)
Solution of this de is
\(y(x)=C_1 \cos \sqrt{\frac{\rho}{t} } wx + C_2 \sin \sqrt{\frac{\rho}{T} } wx\)
y(0)=0 ⇒ C₁ = 0
\(y(x) = C_2 \sin \sqrt{\frac{\rho}{T} } wx\)
y(L) = 0 ⇒
\(C_2 \sin \sqrt{\frac{\rho}{T} } wL=0\)
we need non zero solution
⇒ C₂ ≠ 0 and
\(\sin \sqrt{\frac{\rho}{T} } wL=0\)
\(\sin \sqrt{\frac{\rho}{T} } wL=0 \rightarrow \sqrt{\frac{\rho}{T} } wL=n \pi\)
\(w_n = \sqrt{\frac{T}{\rho} } \frac{n \pi}{L}\)
solution corresponding these \(w_n\) values
\(y_n(x) =C_n \sin \sqrt{\frac{\rho}{T} } w_nx=C_n \sin \sqrt{\frac{\rho}{T} } \sqrt{\frac{T}{\rho} } \frac{n \pi}{L} x\)
\(y_n(x) = C_n \sin \frac{n \pi x}{L}\)
Which of the following is NOT a scientific hypothesis?
A. Neon atoms emit red light.
B. There is an attractive force between the earth and moon.
C. Halle Berry is attractive.
D. Summer days are hottest
E. The sky is blue.
The following statement is not a scientific hypothesis:
C. Halle Berry is attractive.
A scientific hypothesis is a proposed explanation for an observation or pattern in nature that can be tested through further investigation and experimentation. It should be testable, falsifiable, and based on evidence.
Neon atoms emit red light. This is a scientific hypothesis that can be tested and confirmed by looking at the spectrum of light emitted by neon atoms.
B. There is an attractive force between the earth and moon. This is a scientific hypothesis that can be tested and confirmed by measuring the force of gravity between the earth and moon.
D. Summer days are the hottest of the year. This is a scientific hypothesis that can be tested and confirmed by collecting temperature data during the summer months.
E. The sky is blue. This is a scientific hypothesis that can be tested and confirmed by observing the sky under different atmospheric conditions.
The statement "Halle Berry is attractive" is a subjective opinion that cannot be tested or confirmed through scientific investigation, hence it is not a scientific hypothesis. Attractiveness, as a concept, can vary widely based on personal, cultural, and social factors.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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please read the question and answer. it is quite complicated so someone clever please reply. many thanks :)
Answer:
If he's 500 kg and 1 kg = 10 N then it would be 5,000 N
Explanation:
The surface area is unimportant and they'll use it to trick you.
Does a convex lens always form a real image? Explain
Answer:
no
Explanation:
can form either real or virtual images. Convex lens converge parallel rays coming from object at infinity and highly diminished point sized, real and inverted image is formed.
Answer:
no it does not forms a real image
PLEASE HELP I WROTE THIS LIKE 200 TIMES
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.
Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.
Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.
Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.
To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.
For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.
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30 POINTS - the cone moves with simple harmonic motion and it emits
The cone emits a single-frequency sound of 100 Hz and moves in a straightforward harmonic manner. The cone moves a maximum of 2.0 millimetres when it is making a loud sound.
What moves with simple harmonic motion?Simple harmonic motion is a particular type of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the acceleration of the body away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position.
In mechanics and physics, SHM is sometimes used to refer to this motion. If friction or any other energy dissipation is not present, it leads to an oscillation that is represented by a sinusoid and that lasts indefinitely.
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in an equation f = l^2-d^2/4l the intercept is
Answer:
the intercept is the orgin (0,0)
Waves are ?
that can travel through matter.
Answer:
A wave can be thought of as a disturbance or oscillation that travels through space-time, accompanied by a transfer of energy. The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.