A resin tube and a PVC rod are both rubbed against styrofoam. Do
the resin and PVC attract or repel after? Why?

Answer:

table??

Explanation:

Answer: 44.57°C

Explanation:

The following can be deduced from the question:

Specific heat of water = 4.186 J/kg

From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.

We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:

= 7.96 × 10⁴ /(625 × 4.186)

= 79600/(625 x 4.186)

= 79600/2616.25

= 30.43°C

The final temperature will then be:

= 75.0°C - 30.43°C

= 44.57°C

If a rose with the genotype Yy is pale yellow in color, then there is not complete dominance for neither allele and it is a case of incomplete dominance. Nonetheless, since allele Y is for pale yellow and the hybrid has this phenotype, then it is partially dominant (pale yellow, Y, option 3).

Incomplete dominance is a genetic phenomenon in which one of the two alleles present for a given gene locus is expressed more strongly when compared to the other allele, which is called partially dominant and partially recessive alleles, respectively.

Conversely, complete dominance is due to the presence of an allele that completely masks the expression of the recessive allele in heterozygous hybrid individuals.

Therefore, with this data, we can see that incomplete dominance is associated with the expression of both alleles in the heterozygous hybrid individuals.

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Answer:

Yes

Explanation:

Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second. ... For example: if a newborn baby's heart beats at a frequency of 120 times a minute (2 hertz), its period, T, — the time interval between beats—is half a second (60 seconds divided by 120 beats).

Since Two stars M1 and M2 of equal mass make up a binary star system.  their orbital speed is  2.69E4 m/s.

The orbital period of a binary star system is given by the equation:

T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))

where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.

Substituting the given values into this equation, we get:

3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))

Solving for the semi-major axis, we find that a = 2.11E11 m.

The speed of each star in the orbit can be found using the equation:

v = sqrt(G * (M1 + M2) / a)

Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.

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The spring stiffness constant of the spring is 1276.44 N/m.

We know that Hooke’s Law is given by, F = -kx, where F is the force applied to an object, x is the displacement caused by the force, and k is the spring constant.

Therefore, the spring stiffness constant of the spring is given by k = -F / x.Let us first determine the potential energy of the ball, which will be equal to the kinetic energy of the ball when it strikes the spring. We can use the formula, PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the vertical distance fallen by the ball.

Therefore, the potential energy of the ball is given by,PE = mgh= 2.60 kg × 9.81 m/s² × 0.55 m= 14.38 JNow, the ball will transfer all its potential energy to the spring, which will store it as potential energy in the form of elastic potential energy. Therefore, the elastic potential energy stored in the spring is given by, PE = (1/2)kx², where x is the compression of the spring.

Therefore, we have,PE = (1/2)kx²

= (1/2)k (0.15 m)²

= 0.01125 k J

Setting the two expressions for PE equal to each other, we get,1

4.38 J = 0.01125 k JK

= (14.38 J) / (0.01125 J/k)

= 1276.44 N/m

Therefore, the spring stiffness constant of the spring is 1276.44 N/m.

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Pressure is defined as the force per unit area exerted on an object by the fluid surrounding it. the force pushing on the top face of the tube is 1,146,786 N.

In this problem, the air inside the pressurized tube exerts a pressure of 750,000 Pa on the top face of the tube, which has an area of 15 cm². We need to calculate the force that is pushing on the top face of the tube.To do this, we can use the formula:

F = P *

Awhere F is the force, P is the pressure, and A is the area. Substituting the given values, we get:

F = 750,000 Pa * 15 cm² = 11,250,000 N

To convert this answer to a more convenient unit, we can use the following conversion factor:

1 N = 1 kg m/s²Therefore, the force pushing on the top face of the tube is approximately 11,250,000/9.81 = 1,146,786 kg m/s² or 1,146,786 N.

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Answer:

70 m/s

Explanation:

v=u+at

V = 0 + (5 × 14)

WHERE:

v is final velocity

u is initial velocity

a acceleration

t time

v = 70m/s

Answer:

energy

Explanation:

I am not sure but I think it's electric energy

The ratio of the velocity of light in a vacuum to its velocity in a specified medium.

also known as Snell's law defines the refractive index of a medium with respect to the other medium. First law of refraction states that, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant.

The object's final velocity, given the data is 10.5 rad/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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Answer:

Explanation:

For a person suffering from nearsightedness, far point is 3.5 m . That means , an object beyond 3.5 m will not be clearly visible by the person . Ray of light coming from 3.5 m will be focussed on retina . For an object to be visible from infinity , ray of light coming from infinity should appear to be coming from 3.5 m . In other words , the object placed at infinity should form a virtual  image at 3.5 m . This can be done by concave lens.

u = ∝ ;  v  = 3.5

Using lens formula

\(\frac{1}{v} -\frac{1}{u} = \frac{1}{f}\)

\(\frac{1}{-3.5} -0 = \frac{1}{f}\)

f = - 3.5 m .

A concave mirror is an example of curved mirrors. So that the appropriate answer to the given question is option D. The rays will cross at the focal point.

A concave mirror is a type of mirror in which its inner part is the reflecting surface, while its outer part is the back of the mirror.  This mirror reflects all parallel rays close to the principal axis to a point of convergence. It can also be referred to as the converging mirror.

In this type of mirror, all rays of light parallel to the principal axis of the mirror after reflection will cross at the focal point.

Therefore, the required answer to the given question is option D. i.e The rays will cross at the focal point.

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yes

Explanation:

because hindi ko tlaga ala

Answer:

the answer is repel

Explanation:

Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground

Explanation: Supposing that where not counting air resistance in the equation, the equation \(D = ut+\frac{1}{2} at^{2}\) states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.

Answer:

1.26

Explanation:

change 45 grams to kilograms which is 0.045 then just multiply it by 28 m/s

0.045x28=1.260

The momentum change of the ball from rest is the product of its mass and velocity. Hence, the change in momentum is 1.26 kg m/s.

Momentum of a moving body is its ability to bring a force effective to make maximum displacement. Thus, it is the product of its mass and velocity.

i.e. p = mv

As per this relation, mass or velocity or both increases momentum also increases. The change in momentum of a body is called impulse. Impulse has the same unit as that of momentum. i.e. Kg m/s

Given that, m = 45 g = 0.045 kg

velocity v = 28 m/s

The initial momentum of the body is zero since it was rest.

Then , change in momentum = 0.045 kg × 28 m/s = 1.26 kg m/s

Therefore, the change in momentum of the ball is 1.26 kg m/s.

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The arrows point away from a positive charge and towards a negative charge.

The electric field is a vector field, which means that it has both a magnitude and a direction. The magnitude of the electric field is a measure of how strong the field is, and the direction of the electric field is a measure of the direction in which the force would be exerted on a positive charge.

The brightness of the arrow in an electric field simulation is a representation of the magnitude of the electric field. The brighter the arrow, the stronger the electric field. When you check the "Direction only" box, the arrows will only show the direction of the electric field. This is because the "Direction only" box only shows the direction of the vector field, not the magnitude.

When you uncheck the box, the arrows will show both the direction and the strength of the electric field. This is because the "Direction only" box is unchecked, so the arrows will show the full vector field. The arrows point away from a positive charge and towards a negative charge because positive charges repel each other and negative charges attract each other.

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The luminosity of this star in units of the solar luminosity would be: 483.7L.

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

The distance traveled by the object during the time of acceleration is 211.75 m.

Distance can be defined as the total lenght between two points.

T o calculate the distance traveled by the object during the time of acceleration, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the distance traveled by the object is 211.75 m.

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The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Answer:

You increase the acceleration of the car.

Explanation:

To find the position function x(t), we need to integrate the acceleration function twice with respect to time.

Since the acceleration is constant, we can use the kinematic equation:

v(t) = v0 + a*t

where v0 is the initial velocity.

At t = 0.13 s, we have:

v(0.13) = -0.185 m/s

a = 0.899 m/s^2

So,

v(t) = -0.185 + 0.899t

Integrating v(t) with respect to time gives:

x(t) = x0 + ∫v(t) dt

where x0 is the initial position. Since we don't know the initial position, we can set x0 = 0 without loss of generality.

Integrating v(t) gives:

x(t) = ∫(-0.185 + 0.899t) dt = -0.185t + 0.4495t^2 + C1

where C1 is the constant of integration.

To find C1, we use the initial condition x(0.13) = 0:

0 = -0.185(0.13) + 0.4495(0.13)^2 + C1

C1 = 0.00922

So, the position function is:

x(t) = -0.185t + 0.4495t^2 + 0.00922

Answer:

The time is 1.4 sec

The initial velocity is 10.7 m/s.

Explanation:

Given that,

Height = 10 m

Distance = 15 m

We need to calculate the time

Using equation of motion

\(s=ut-\dfrac{1}{2}gt^2\)

Put the value into the formula

\(10=0+\dfrac{1}{2}\times9.8\times t^2\)

\(t^2=\dfrac{2\times10}{9.8}\)

\(t=\sqrt{\dfrac{2\times10}{9.8}}\)

\(t=1.4\ sec\)

We need to calculate the initial velocity

Using formula of velocity

\(v=\dfrac{d}{t}\)

Put the value into the formula

\(v=\dfrac{15}{1.4}\)

\(v=10.7\ m/s\)

Hence, The time is 1.4 sec

The initial velocity is 10.7 m/s.

The intrepid hero has done 2.332 x Joules of work in pushing the crate.

To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:

Force = mass x speed increase = 220 kg x 2  = 440 N

Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.

At long last, we can compute the work done by the pioneer utilizing the equation:

Work = force x distance = 440 N x 5,300 m = 2.332 x 10^6 Joules

Thusly, the valiant legend has done 2.332 x  Joules of work in pushing the case.

The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x  J.

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If the dart detaches from the spring when the spring reaches its natural length, then the speed acquired by the dart would be 3 m /s.

The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.

As given in the problem , a dart of mass 0.100 kg is pressed against the spring of a toy dart gun. The spring (with spring stiffness constant k = 250 N/m and ignorable mass) is compressed 6.0 cm and released. if the dart detaches from the spring when the spring reaches its natural length (x=0),

1/2 mv² = 1/2 kx²

0.1v²   = 250 × 0.06²

v = 3 m /s

Thus,  the speed acquired by the dart would be 3 m /s.

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