A rigid uniform rod of length 90.0 cm and mass 35.0 kg laying on a horizontal frictionless surface is free to rotate on that surface about an axle through its center. A small puck slides into it at an angle of 90 degrees to its surface at a distance of 30.0 cm from the pivot point at a speed of 20.0 m/s. It rebounds with a speed of 16.0 m/s along the same line. If the angular speed of the rod immediately after the collision is 1.14 rad/s, what was the mass of the puck

Answer:

Thanks!!!!! adding this so it doesn’t get deleted.

Explanation:

1. Electrostatic forces are trillions of times stronger than gravitational forces. 2. normal force and friction 3. contact forces 4. The electrostatic forces from the contact of the hands with the paper causes the paper molecules to separate. 5. The electrostatic forces between the molecules of the board prevent the force of gravity from breaking the board apart.

The correct statement over here is that electrostatic forces are trillions of times stronger than gravitational forces. Hence, option C is correct.

One of the basic forces in the cosmos is electrostatic force. In the universe, there are four basic forces. These include gravitational force, electromagnetic force, weak nuclear force, and strong nuclear force. Under the umbrella of electromagnetic force is electrostatic force. Two charges placed apart are subject to the electrostatic force. The size of each charged and the separation between them determines how much electrostatic force there will be.

When two charges of the same type are brought together, whether positive or negative, they repel one another. It is known as the electrostatic force of repelling when it operates among two charges that are similar.

Therefore, the electrostatic forces are trillions of times stronger than the gravitational forces.

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Answer: 4.97 years

Explanation: I got the answers right

By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D

We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.

By the application of the Keplers third law;

T^2 = r^3

The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.

We then know that;

T = period

r = distance

Hence;

T = r^3/2

T = (3.01 )^3/2

T = 5.22 years

The period of the object is seen to be 5.22 years from the calculation above.

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It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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Explanation:

The net force along the horizontal direction is

\(\sum{F_x} = F_{applied} - f\)

where f is the frictional force. We can find the frictional force by looking at the vertical forces acting on the couch:

\(\sum{F_y} = N - mg = 0 \Rightarrow N = mg\)

From the definition of frictional force,

\(f = \mu{N} = \mu{mg} = (0.65)(42\:\text{kg})(9.8\:\text{m/s}^2)\)

\(\:\:\:\:= 267.5\:\text{N}\)

Therefore, the net force on the couch is

\(\sum{F_x} = 600\:\text{N} - 267.5\:\text{kN} = 332.5\:\text{N}\)

Answer:332 N

Explanation:

The displacement of a 1.5 kg mass is then determined using the formula x = F/k.  stretching a spring 2 cm from its equilibrium position need twice as much effort as stretching it a distance of x

W = 1/2kx2 = 1.96 Joules.

Actually, it requires more than twice as much labour since, as the spring extends, more power is needed to do so.

The shear strength and shear modulus of a compression spring formed of music wire with a 2mm diameter are 800 MPa and 80 GPa, respectively.

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Answer:

C: World War I resulted from a chain reaction involving many nations.

Explanation:

Just did the questions and got it right

Answer:

C

Explanation:

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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(a) Work done by the cord's force on the block \((WF) = Mg/4\times d\)

(b) Work done by the weight of the block \((Wg) = Mg/4 \times d\)

(c) Kinetic energy of the block \((K) = Mg/2\times d\)

(d) Speed of the block \((v) = sqrt(gd/2)\) where g is the acceleration due to gravity and d is the distance the block has fallen.

Kinetic energy is the energy that an object possesses due to its motion. In other words, if an object is moving, it has kinetic energy. The amount of kinetic energy an object has depends on its mass and velocity. The formula for calculating kinetic energy, K, is:

K = 1/2 mv^2

where m is the mass of the object and v is its velocity. The factor of 1/2 in the formula is due to the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. If a force is applied to an object to put it in motion, work is done on the object, and its kinetic energy increases.

The units of kinetic energy are joules (J). One joule is defined as the amount of work done when a force of one newton (N) is applied over a distance of one meter (m). Since work and energy are measured in the same units, the unit of kinetic energy is the same as the unit of work, which is the joule.

Kinetic energy is a scalar quantity, which means it has magnitude but no direction. The kinetic energy of an object increases as its mass and velocity increase.

(a) The work done by the cord's force on the block can be found using the formula:

\(WF = force\times distance\)

The force applied by the cord is equal to the tension in the cord, which is equal in magnitude to the weight of the block. Therefore, the force applied by the cord is:

\(F = Mg\)

where M is the mass of the block, and g is the acceleration due to gravity.

The distance over which the force is applied is d, the distance the block has fallen. Therefore, the work done by the cord's force on the block is:

\(WF = Fd = Mg \times d\)

Substituting g/4 for g

\(WF = M(g/4) \times d = Mg/4 \times d\)

Hence, the work done by the cord's force on the block is Mg/4 × d.

(b) The work done by the weight of the block can be found using the formula:

\(Wg = force \times distance\)

The weight of the block is equal to its mass times the acceleration due to gravity, which is:

\(W = Mg\)

The distance over which the weight is applied is again d. Therefore, the work done by the weight of the block is:

\(Wg = Wd = Mg\times d\)

Substituting g/4 for g:

\(Wg = M(g/4) \times d = Mg/4 \times d\)

Hence, the work done by the weight of the block is also \(Mg/4 \times d.\)

(c) The change in the kinetic energy of the block can be found using the work-energy principle:

Wnet = ΔK

where Wnet is the net work done on the block, and ΔK is the change in the kinetic energy of the block.

The net work done on the block is equal to the sum of the work done by the cord's force and the work done by the weight of the block:

\(Wnet = WF + Wg = Mg/4 \times d + Mg/4 \times d = Mg/2 \times d\)

The change in the kinetic energy of the block is equal to the net work done on the block:

ΔK = Mg/2 × d

Since the block starts from rest, its initial kinetic energy is zero. Therefore, the final kinetic energy of the block is equal to the change in kinetic energy:

\(K = Mg/2\times d\)

(d) The final speed of the block can be found using the equation for the final kinetic energy:

\(K = 1/2 mv^2\)

where m is the mass of the block, and v is its final speed.

Substituting Mg/2 × d for K and M for m

\(Mg/2\times d = 1/2 Mv^2\)

Simplifying and solving for v, we get:

\(v = sqrt(gd/2)\)

Therefore, the speed of the block is\(sqrt(gd/2)\), where g is the acceleration due to gravity and d is the distance the block has fallen.

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Answer:

I=VRS=9V90Ω=0.1A

Explanation:

The equivalent resistance is the algebraic sum of the resistances (Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω. The current through the circuit is the same for each resistor in a series circuit and is equal to the applied voltage divided by the equivalent resistance

The seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.

Some other risk factors for heart attack are:

To prevent heart attack, one must,

Therefore, the seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.

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Answer:

Study More You will get it :L

Answer:

more pressure towards one side

Explanation:

if Carol pulls very hard and molly pulls even harder molly will win because she is putting more pull force than Carol

the angle between vectors is 1

let,  vector A,B and |A| =5 , |B| =12

According to dot product,

A.B = |A| |B| cos∝

-6 = 5x12cos∝

cos∝ = 0.99

nearly equal to 1

hence the angle between A and B is 1

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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(a) The linear momentum of the system is conserved due to the absence of external forces. (b) The kinetic energy of the system is generally not conserved in an explosion due to energy transfers and losses associated with the process.

(a)  According to the principle of conservation of momentum, the total momentum of an isolated system remains constant if no external forces act upon it. In the given scenario, the bomb is initially at rest, which means the total momentum of the system is zero before the explosion. After the explosion, the bomb fragments move in different directions, but their individual momenta add up to zero. Thus, the total momentum of the system remains conserved.

(b) In an explosion, a significant amount of potential energy stored in the bomb is rapidly converted into kinetic energy of the fragments. As the bomb explodes, the fragments gain kinetic energy, resulting in an increase in the total kinetic energy of the system. Additionally, the explosion may cause the fragments to collide with other objects or experience air resistance, leading to energy losses in the form of heat, sound, or work done against external forces. These energy losses further prevent the conservation of kinetic energy.

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Scattering is the process of deflection of radiation due to interaction with the particle.

Thus option C: scattering is correct.

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.

Acceleration - constant; velocity - increasing.

What is Acceleration?

Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.

What is velocity?

Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.

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The function of the power supply is to provide electrical energy to the device or system that needs it. The power supply converts the incoming voltage from the power source into a form that is usable by the device, such as DC voltage.

The readout is a device or component that displays data or information to the user. The readout could be a simple LED display or a complex graphical display.

A peripheral is a device or component that connects to a computer or other electronic device to provide additional functionality. Examples of peripherals include printers, scanners, and external hard drives.

A microcomputer is a type of computer that is designed to fit on a single microchip. Microcomputers are found in a wide range of devices, including smart phones, tablets, and embedded systems.

A transducer is a device that converts one form of energy to another. In electronics, transducers are commonly used to convert electrical energy into mechanical energy, or vice versa.

The processor is the central component of a computer or electronic device. The processor is responsible for executing instructions and controlling the other components of the system. The performance and capabilities of a device are largely determined by the speed and power of the processor.

ANSWER: About 9.832 m/s raised to a power 2

Explanation:

In combination , the equational bulge and the effects of the surface centrifugal force due to rotation that means sea level gravity increases from about 9.780 m/s raised to a power 2 at the equator to about 9.832m/s raised to a power 2 at the poles , so an object will weigh approximately 0.5% more at the poles than the equator

Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

A procedure known as magnetic separation can be used to extract magnetic elements from coal.

This method makes use of the magnetic characteristics of some materials to distinguish them from non-magnetic materials like coal. A description of how magnetic separation can be used to remove magnetic components from coal is given below:

Putting a magnetic field around the coal and magnetic material mixture is the first step in the magnetization process. This can be achieved by creating an electromagnetic field or by putting the mixture close to a powerful magnet.

Magnetism: Magnetic materials, such as iron atoms or magnetite that are frequently found in coal, will be drawn to the magnetic field and become magnetized. They line up their magnetic moments with the magnetic field's direction.

Separation: The magnetic coal components can be physically separated from the non-magnetic coal once they have been magnetized. To create this separation, there are numerous techniques:

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A. The ball's (vertical) velocity \(v\) at time \(t\) is

\(v(t) = 30\dfrac{\rm m}{\rm s} - gt\)

so that after 4 seconds, the ball's speed is

\(|v(4\,\mathrm s)| = \left|30\dfrac{\rm m}{\rm s} - \left(10\dfrac{\rm m}{\mathrm s^2}\right) (4\,\mathrm s)\right| = \boxed{10\frac{\rm m}{\rm s}}\)

(The velocity is -10 m/s, so the ball is falling back down at this point.)

B. At maximum height, the ball has zero velocity, so it takes

\(30\dfrac{\rm m}{\rm s} - gt = 0 \implies t = \dfrac{30\frac{\rm m}{\rm s}}g = \boxed{3\,\mathrm s}\)

for the ball to reach this height.

C. The height of the ball \(y\) at time \(t\) is

\(y(t) = \left(30\dfrac{\rm m}{\rm s}\right) t - \dfrac g2 t^2\)

The maximum height is attained by the ball at 3 seconds after it's thrown, so

\(y_{\rm max} = \left(30\dfrac{\rm m}{\rm s}\right) (3\,\mathrm s) - \dfrac{10\frac{\rm m}{\mathrm s^2}}2 (3\,\mathrm s)^2 = \boxed{45\,\mathrm m}\)

D. The time it takes for the ball to reach its maximum height is half the time it spends in the air. So the total airtime is \(\boxed{6\,\mathrm s}\).

Put another way: When the ball returns to the height from which it was thrown, its final velocity has the same magnitude as its initial velocity but points in the opposite direction. This is to say, after the total time the ball is in the air, it's final velocity will be -30 m/s. Then the total airtime is

\(30\dfrac{\rm m}{\rm s} - gt = -30\dfrac{\rm m}{\rm s} \implies t = \dfrac{60\frac{\rm m}{\rm s}}g = \boxed{6\,\mathrm s}\)

Put yet another way: Solve \(y(t) = 0\) for \(t\). I don't see a need to elaborate...

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

What are your options? also i believe the answer may be ecosystem.

Explanation:

There are both biotic and abiotic factors in an ecosystem. Be cause living organisms Are Biotic. While water and rocks are abiotic which are needed to form an ecosystem.

Answer:

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

Explanation:

The force required to accelerate an object can be calculated using the formula:

force = mass x acceleration

where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.

In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:

force = mass x acceleration

force = 500 kg x 10 m/s^2

force = 5000 N

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).