A rock is kicked horizontally off a dock into the bay 3
times with a higher initial velocity each time as shown to the right. Which of the following statements is true regarding
these scenarios? AND WHY?
(a) The rock takes the longest time to hit the water in
case 3
(b) The rock takes about the same time to hit the water
in each case
(c) The rock hits the water below with the highest speed
in case 1
(d) The rock hits the water with the same speed in each|
case
Student Answer(s):
Student Reasoning:
Answers
Answer:
The true statement is;
(b) The rock takes about the same time to hit the water in each case
Explanation:
The given information are;
The direction in which the rock is kicked = Horizontally
The number of different initial horizontal with which the rock as kicked = different horizontal velocity
The time taken for the rock to hit the water is given by the following equation for projectile motion;
y = y₀ + v₀× sin(θ₀)×t - 1/2×g×t²
Where;
θ = The angle the rock makes with the horizontal when it was kicked = 0
y = The height through which the rock drops
y₀ = The initial height of the rock
t = The time taken for the ball to hit the water
g = The acceleration due to gravity ≈ 9.81 m/s²
For the different speeds, v₁, v₂, and v₃, we have;
y = y₀ + v₁× sin(0)×t - 1/2×g×t² = y₀ - 1/2×g×t²
y = y₀ + v₂× sin(0)×t - 1/2×g×t² = y₀ - 1/2×g×t²
y = y₀ + v₃× sin(0)×t - 1/2×g×t² = y₀ - 1/2×g×t²
Therefore, the time it takes for the ball to hit the water is given as follows;
\(t = \sqrt{\dfrac{(y_0 - y) \times 2}{g} }\)
Which is the same for each case
However, the speed, v, with which the rock hits the water is given by the following equation;
\(v = \sqrt{v_x^2 + v_y^2}\)
\(v_y\) = The vertical velocity = v₀ × sin(θ₀) - g×t = v₀ × sin(0) - g×t = -g×t
\(v_y\) = -g×t
Therefore, \(v_y\), is the same for all three times
While vₓ = v₁, v₂, and v₃, for each of the three times.
Therefore, \(v = \sqrt{v_x^2 + v_y^2}\) the speed with which the rock hits the water is different for all three times.
Related Questions
what interferences can be subtracted out of an ir spectrum due to the usage of a double beam spectrometer with a reference cell?
Answers
Explanation: In a double beam spectrometer with a reference cell, interferences due to the light source, the environment, and the sample holder can be subtracted out of an air spectrum.
The reference cell is filled with a gas that is transparent and has no absorption bands in the spectral range of interest. The reference cell and the sample cell are alternatively placed in the path of the light source. The detector records the intensity of the light passing through both cells, which is then compared to the intensity of the light passing through the sample cell only.
By using the reference cell as a baseline, any interferences due to the light source or the environment (e.g., variations in temperature, pressure, or humidity) can be subtracted out, as these will affect the intensity of the light passing through both cells equally. Similarly, any interferences due to the sample holder or any contaminants in the sample can be subtracted out, as these will affect the intensity of the light passing through the sample cell only.
The result is a spectrum that reflects only the absorption or transmission of the sample itself, without interference from other sources.
When using a double beam spectrometer with a reference cell, several interferences can be subtracted out of an IR spectrum which are: Background absorption, Stray light, Sample cell absorption and Instrumental noise.
What is a double beam spectrometer?A spectrometer is an instrument that measures the light intensity and the wavelength of light. The double beam spectrometer works on the principle of the single beam spectrometer but with two beams of light. The use of a double beam spectrometer with a reference cell enables you to measure the absorption of infrared radiation at different wavelengths due to a specific chemical compound.
Interferences that can be subtracted out of an IR spectrum due to the usage of a double beam spectrometer with a reference cell:
1. Background absorption: Background absorption occurs when an IR beam from the source is absorbed by the atmosphere or by the instrument components. This absorption can be reduced by subtracting the IR spectrum of the reference material from the spectrum of the sample.
2. Stray light: Stray light is a problem that occurs when the IR beam from the source is not completely focused on the sample. This leads to a low intensity of the IR beam reaching the detector. It can be reduced by the use of appropriate filters.
3. Sample cell absorption: This is the absorption of the sample cell material that contributes to the IR spectrum. This can be corrected by subtracting the spectrum of the empty reference cell from the spectrum of the sample.
4. Instrumental noise: This is the background noise in the IR spectrum that is due to the instrument. It can be reduced by using appropriate signal processing techniques.
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_____________(kinetic energy released in matter) specifies the intensity of x-rays at a given point in air at a known distance from the focal spot or source of x-rays, and the cumulative or total ___________(same word) will be monitored during the fluoroscopic procedure
Answers
Answer:
Air kerma
Explanation:
The acronym for the word 'kerma' is \($\text{"kinetic energy released per unit mass"}$\). It is the sum or the total of the kinetic energies of the \($\text{charged particles}$\) that is liberated by the uncharged ionizing radiation in the small sample of a matter, and is divided by the mass of that sample.
It is sometimes used for expressing the radiation concentration that is delivered to a point.
It is used to specify the intensity of the x-rays for any given point in the air at some known distance form the local spot. The total air kerma can be monitored in the fluoroscopic procedure.
What are the four phases of movement (in proper order) that make up a backflip?
Answers
Acrobatic flips are a series of bodily motions in which the performer leaps into the air before rotating once or more while in the air.
What is a backflip?A person who performs an acrobatic flip will first leap into the air before rotating once or more while in the air. Acrobatic flips are performed in a variety of sports and activities, including tricking, goal celebrations, cheering, free running, gymnastics, and acro dance.
The four steps to do a backflip are given below:-
1. Before you jump, stretch your muscles to avoid harm.
2. Find a cushioned area, like a foam pit or a gymnastics mat.
3. For the most protection, use a spotter.
4. Make a high squat by bending at the knees. Ring your arms forward and above your head as you leap upwards, pausing when they are just behind your back.
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A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
Answer Quick plz!
Answers
Answer:
Explanation:
14
Help me pleaseee, it’s due today: Two people push on a large gate as shown on the view from above in the diagram. If the moment of inertia of the gate is 90 kgm2, what is the resulting angular acceleration of the gate?
Answers
Answer:
the angular acceleration of the gate is approximately 1.61 \(\frac{rad}{s^2}\)
Explanation:
Recall the formula that connects the net torque with the moment of inertia of a rotating object about its axis of rotation, and the angular acceleration (similar to Newton's second law with net force, mass, and linear acceleration):
\(\sum \tau_1=I\,\alpha\)
In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:
\(\tau_{net}=(20*2+30*3.5) \,N\,m=145\,\,N\,m\)
Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:
\(\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}\)
How are electromagnetic waves used in a bar-code scanner?
O A. An image is produced when a silicon chip releases electrons by the photoelectric effect. OB. Red light shines on a bar code, and light is reflected according to the black-and-white pattern.
C. Visible light is reflected off an object and then captured by a charge-coupled device.
O D. X-rays shine on objects, and the rays either pass through or are absorbed by the objects.
Answers
The electromagnetic waves used in a bar-code scanner by an image is produced when a silicon chip releases electrons by the photoelectric effect and Visible light is reflected off an object and then captured by a charge-coupled device.
What is electromagnetic wave?The electromagnetic wave is the white light or Sunlight coming directly from the Sun. This light ray is the form of wave. This light when falls on any object segregates into the range of all types of EM radiation.
Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves and visible light waves, ultraviolet rays and microwaves.
Bar code scanner uses the photoelectric effect and visible light reflection phenomenon.
Thus, the correct options are A and C.
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What is the positive contribution that a philosopher makes to the question/problem of ethics
Answers
Answer:
There are many well-known figures in the history of ethics, including the Greek philosophers Plato and Aristotle. Since the mid-20th century, Aristotle's ethics has inspired the field of virtue theory, an approach to ethics that emphasizes human well-being and the development of character.
Explanation:
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unfortunately, you sat on a fire ant pile while you ate your lunch at the park and now your ankle has a few red, swollen marks. what defense mechanism do fire ants use to avoid becoming prey?
Answers
Unfortunately, fire ants are known for their aggressive behavior and powerful defense mechanisms. Defense mechanism employed by fire ants are:
1) Their ability to release pheromones to alert their colony members of danger
2) Fire ant's strong mandibles, which can deliver painful bites and even sever limbs of larger predators
3) Fire ants have adapted to their environment by building complex underground nests with multiple entrances and exits
When threatened or disturbed, they will attack in large numbers and deliver painful stings with their venomous bites. To avoid becoming prey themselves, fire ants have evolved several strategies to protect their colonies and deter potential predators.
One defense mechanism employed by fire ants is their ability to release pheromones to alert their colony members of danger. When one ant detects a threat, it will release a chemical signal that prompts other ants to swarm and attack the perceived threat. This coordinated response makes it difficult for predators to single out and capture individual ants.
Another defense mechanism is the fire ant's strong mandibles, which can deliver painful bites and even sever limbs of larger predators. Fire ants can also sting repeatedly, injecting venom that causes pain and swelling in their prey.
Finally, fire ants have adapted to their environment by building complex underground nests with multiple entrances and exits. This allows them to quickly escape potential threats and retreat to safety.
Overall, fire ants have evolved a range of effective defense mechanisms to protect themselves and their colonies from predators. Unfortunately, these mechanisms can also pose a threat to humans who inadvertently disturb their nests, resulting in painful stings and swollen marks like the ones you experienced on your ankle.
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What does the phrase "1 meter per second per second" means? A. The velocity of an object can increase by 1 meter per second, for every minute of time measured. B. The velocity of an object can increase by 1 meter per second, for every second of time measured. C. The velocity of an object can increase by 1 meter per second.
Answers
Explanation:
"1 meter per second per second" means acceleration of an object. It is equal to the rate of change of velocity. Its SI unit is \(m/s^2\).
It is simply given by :
\(a=\dfrac{dv}{dt}\)
dv is change in velocity
dt is small interval of time
"1 meter per second per second" means that the velocity of an object can increase by 1 meter per second.
A magnetic field is oriented at an angle of 37° the normal of arectangular area 6.2 cm 7.5cm. If the magnetic flux through this surface has a magnitude of 4.7×10^−5Tm^2, what is the strength of the magnetic field?Express your answer using two significant figures.B=____ mT
Answers
The strength of the magnetic field is approximately 2.8 mT.
The equation is:
Φ = B × A × cos(θ)
You are given the magnetic flux (Φ = 4.7 × \(10^-^5\) \(Tm^2\), the angle (θ = 37°), and the dimensions of the rectangular area (6.2 cm x 7.5 cm). First, we need to calculate the area (A):
A = length × width = 6.2 cm × 7.5 cm = 46.5 \(cm^2\)
= 0.00465 \(m^2\)
Next, rearrange the magnetic flux equation to solve for the magnetic field (B):
B = Φ / (A × cos(θ))
Now, plug in the given values and calculate the magnetic field:
B = (4.7 ×\(10^-^5\) \(Tm^2\)) / (0.00465\(m^2\)× cos(37°)) ≈ 0.00283 T
Finally, convert the magnetic field strength to milli tesla (mT) and express it using two significant figures:
B = 0.00283 T × 1000 mT/T ≈ 2.8 mT
So, the strength of the magnetic field is approximately 2.8 mT.
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how many collisions occur when a vehicle hits a solid object?
Answers
The perpendicular distance (closest distance) between the axis of rotation and the line of action of the force is called ....
Answers
Answer:
sorry
Explanation:
thank you please i'm sorry i can't make this question a problem for someone else
A mosquito's wings create a buzzing noise with a frequency of 1050 Hz. If you hear a mosquito buzzing with a frequency of 1034 Hz, at what velocity is the mosquito travelling with respect to you (in m/s)?
NO LINKS
Answers
Answer:
5.26 m/s
Explanation:
Given that,
The frequency of mosquito's wings, f = 1050 Hz
The observed frequency = 1034 Hz
We need to find the velocity of the mosquito travelling with respect to you. We have a formula to find it such that,
\(v=\dfrac{v}{\dfrac{f'}{f}}-v\)
Where
v is the speed of sound
So,
\(v=\dfrac{340}{\dfrac{1034}{1050}}-340\\\\v=5.26\ m/s\)
So, the required velocity is equal to 5.26 m/s/
Which wave measure is changing by the greatest amount in the image?
A. amplitude
B. wavelength
C. speed
D. frequency
Answers
Answer: frequency
Explanation:
amplitude is the max height at which the wave reaches
wavelength distance b/w two waves
the speed at which the wave is oscillating
frequency is no. of oscillations of a wave per unit length
what are the main component of network
Answers
Answer:
A network has 5 basic components viz. clients, servers, channels, interface devices and operating systems.
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A 5kg block is pushed 3m at a constant velocity up a vertical wall by a constant force applied at an angle of 37 degree with the horizontal, if the coefficient of kinetic friction between the block and the wall is 0.3. what is the work done by the force on the block?
Answers
The work done by the force on the block is:
\(W=135.41*3=406.23 \: J\)
The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.
Using trigonometric functions:
\(F_{y}=Fsin(37)\)
This component is in the positive y-direction.
Now, there is a friction force between the block and the wall, so we need to find the friction force.
\(F_{f}=\mu N\)
Where:
μ is the coefficient of kinetic frictionN is the normal force (Here N = Fcos(37))Let's use the first Newton's Law to get F.
F(y) is upward (+) and F(f) and the weight is downward (-).
\(F_{y}-F_{f}-W=0\)
\(F_{y}-F_{f}=mg\)
Factoring F in the left side:
\(F(sin(37)-\mu cos(37))=mg\)
\(F=\frac{mg}{sin(37)-\mu cos(37)}\)
\(F=\frac{5*9.81g}{sin(37)-(0.3*cos(37))}\)
\(F=135.41\: N\)
Therefore, the work done will be:
\(W=Fd\)
\(W=135.41*3=406.23 \: J\)
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When you have more than one battery in a circuit you __________ (add, subtract, multiply, divide) the values of the individual batteries to get the overall voltage of the circuit.
Answers
Answer: When you have more than one battery in a circuit, you add the values of the individual batteries to get the overall voltage of the circuit.
Explanation:
23. In an experiment to determine the density of a lead using a density bottle, the following readings were obtained (a) Mass of empty density bottle = 13.2g (b) Mass of density bottle filled with water = 53.2g (c) Mass of a partially filled density bottle with lead shots only = 126.1g (d) Mass of density bottle with lead shots filled up with water = 166.lg Calculate iii) iv) v) Volume of water that fills the density bottle 40g Capacity of the density bottle Mass of lead shots 112.99 Volume of lead shots Density of lead (2 marks) (1 mark) (1 mark) (1 mark) (2 marks)
Answers
Answer:To calculate the required values, we can use the formula for density: density = mass/volume.
i) Volume of water that fills the density bottle = mass of water/density of water
Mass of water = Mass of density bottle filled with water - Mass of empty density bottle = 53.2g - 13.2g = 40g
Density of water = 1g/cm³ (at room temperature and pressure)
Volume of water = 40g/1g/cm³ = 40cm³
ii) Capacity of the density bottle = Volume of water + Volume of lead shots
Volume of water = 40cm³ (calculated above)
Volume of lead shots = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of density bottle filled up with lead shots and water = Mass of density bottle with lead shots filled up with water - Mass of empty density bottle
= 166.1g - 13.2g = 152.9g
Volume of lead shots and water = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of lead shots and water = 152.9cm³ - 40cm³ = 112.9cm³
Assuming that the volume of water in the partially filled density bottle is negligible, we can take the volume of lead shots to be equal to the volume of the partially filled density bottle.
Capacity of the density bottle = Volume of water + Volume of lead shots = 40cm³ + 112.9cm³ = 152.9cm³
iii) Mass of lead shots = Mass of density bottle with lead shots filled up with water - Mass of density bottle filled with water
= 166.1g - 53.2g = 112.9g
iv) Volume of lead shots = Mass of lead shots/density of lead
Density of lead = 11.34 g/cm³ (at room temperature and pressure)
Volume of lead shots = 112.9g/11.34 g/cm³ = 9.96 cm³ (approximately)
v) Density of lead = Mass of lead shots/Volume of lead shots
Density of lead = 112.9g/9.96cm³ = 11.32 g/cm³ (approximately)
Therefore, the required values are:
iii) Mass of lead shots = 112.9g
iv) Volume of lead shots = 9.96cm³ (approximately)
v) Density of lead = 11.32 g/cm³ (approximately)
Explanation:
If a vehicle is moving at a constant speed of 60 miles per hour, how many miles will it travel in 1 hour and 20 minutes?.
Answers
The vehicle will travel a total of 80 miles in 1 hour and 20 minutes.
The vehicle is moving at a constant speed of 60 miles per hour.
It means that in one hour, the vehicle travels 60 miles.
So, we can write,
Miles travelled in hour = 60
Miles travelled in one minute = 60/60
Miles travelled in one minute = 1 mile
Total time given is 1 hours and 20 minutes.
1 hours = 60 minutes,
Hence, total time = 60+20
Total time = 80 minutes.
So, the distance travelled in 80 minutes = 80 x 80 miles,
Miles travelled in 80 minutes = 80 miles/
So, the vehicle travelled 80 miles in 1 hour and 20 minutes.
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A wave travels with speed 200 m/s. Its wave number is 1.5 rad/m. What are its (a) wavelength and (b) frequency
Answers
Answer:
(a)
Explanation:
The wavelength and the frequency will be 0.66 m and 303.3 Hz respectively. All the given terms are related to the wave.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
Wavenumber is the inverse of the wavelength.It is denoted by N.
\(\rm \lambda =\frac{1}{N} \\\\ \rm \lambda =\frac{1}{1.5} \\\\ \lambda=0.66 m\)
The relationship between the wave's wavelength, frequency, and speed is given as
\(\rm \lambda=\frac{v}{f} \\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{200}{0.66} \\\\ f= 303.3 \ Hz\)
Hence the wavelength and the frequency will be 0.66 m and 303.3 Hz respectively.
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An iron ball hangs from a ceiling by an insulating thread. The ball is attracted to a negatively charged rod held near the ball. The charge of the ball must be
Answers
An iron ball hangs from a ceiling by an insulating thread. The ball is attracted to a negatively charged rod held near the ball: The charge of the ball must be positive.
The iron ball, being attracted to a negatively charged rod, indicates that the ball and the rod have opposite charges. According to the principles of electrostatics, opposite charges attract each other. Since the negatively charged rod attracts the iron ball, the ball must possess a positive charge.
When a negatively charged object is brought near the neutral iron ball, the electrons in the iron ball are attracted towards the rod, causing a redistribution of charges. Electrons move away from the side of the ball facing the rod, leaving behind a net positive charge. As a result, the ball acquires a positive charge, enabling it to be attracted to the negatively charged rod.
Therefore, the charge of the ball must be positive to experience an attractive force towards the negatively charged rod.
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17)
A positively charged ion will bond with
A)
a negatively charged ion.
Elin
B)
a neutral atom.
C)
another positively charged ion.
D)
nothing else.
Answers
Answer:
Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... the complete transfer of valence electron(s) between atoms. It is ... The compound is neutral overall, but consists of positively charged ions called cations and negatively ... an ion with net negative charge, having more electrons than protons.
Explanation:
Light travels slower in oil than in air. If a light wave moves through the oil at a speed of 2 x 108 m/s and the wavelength of this light wave is 2 x 10-3 m, what is the frequency of this wave?
1 x 105 Hz
4 x 10-24 Hz
4 x 105 Hz
1 x 1011 Hz
Answers
The frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct. Frequency is the inverse of the time period.
What is the frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
The given data in the problem is;
v is the speed of light = 2 x 10⁸ m/s
\(\lambda\) is the wavelength = 2 x 10⁻³ m,
f is the frequency of the wave is to be found;
Frequency is given by the formula as,
\(\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{2 \times 10^8}{2 \times 10^-3} \\\\ \rm f = 1 \times 10^{11} \ Hz\)
Hence the frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct.
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Whats a support force
Answers
According to the given information A support force that completely balances the weight of an object at rest.
What is an example of support force?The normal force is another name for a support force. With the same amount of power as the book's downward weight, the table pushes up on the book. A support force—the upward force that balances an object's weight on a surface—holds the book steady on the table.
What sources does support force have?Pull force attributed to another item, such as "Pull attributed to Steve." The force here is identical to the push force, but it is directed at the thing that is pulling. Support force resulting from the ground (or from the object's surface): When two solid surfaces come in contact with one another, support force arises.
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The complete question is -
What is a support force ?
What are brown bears doing as a result of panting?
maintaining internal water levels by releasing moisture
maintaining internal water levels by taking in moisture
maintaining body temperature by warming up
maintaining body temperature by cooling down
Answers
They are maintaining their body temperature by cooling down, like dogs do, as they don't have enough sweat glands to keep them cool without panting.
Brown bears maintain body temperature by cooling as a result of panting. So, the correct option is D.
What is Body temperature?Normal human body-temperature is defined as the typical temperature range found in humans which is commonly referred to as 36.5–37.5 °C. The human body temperature varies. Temperature is known as the degree of hotness or coldness of an area or object.
When we are very hot, the blood vessels of the skin dilate to carry the excess heat to the surface of the skin. Brown bear panting ensures that cool air circulates over the moist surfaces in the mouth which helps maintain body temperature by cooling the body.
Therefore, the correct option is D.
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Psertica track detectors are ised to measure the speed of particles in the lifetime of the particie is known. Particie-X has a lifetime of 256.2. an experment inside the detector by a given reaction. The partides leave 10.6 cm long tracks on average before they decay into other particies not abservable by the detectori What is the aunage speed of the particles in terms of the speed of light? Tries 0/12
Answers
The average speed of the particles in terms of the speed of light is 0.976c. Given that, The particle-X has a lifetime of 256.2.A particle track detector is used to measure the speed of particles. On average, the particles leave 10.6 cm long tracks before they decay into other particles that are not observable by the detector.
The formula to calculate the average speed of the particles is given as;v = d / t Where,v = velocity of the particles, d = distance traveled by the particles, and t = time taken by the particles. The distance traveled by the particles before they decay is 10.6 cm = 0.106 m. The lifetime of the particle is given as 256.2 s. Therefore, time taken by the particle to decay, t = 256.2 s.
The speed of the particles can be calculated as follows; v = d / tv = 0.106 / 256.2v = 4.135 × 10^-4 m/s The speed of the particles in terms of the speed of light can be calculated as follows; Speed of light = 3 × 10^8 m/s Average speed of the particles in terms of the speed of light, v/c= (4.135 × 10^-4) / (3 × 10^8)= 0.976 × 10^-8= 0.976cTherefore, the average speed of the particles in terms of the speed of light is 0.976c.
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A bat hasa mads of 2kg at the velocity of 45 m/s what is the kinectic energy could he give to a ball
Answers
Answer:
the kinetic energy the bat can give to a ball is 2,025 J.
Explanation:
Given;
mass of the bat, m = 2kg
velocity of the bat, v = 45 m/s
The kinetic energy the bat can give to a ball is calculated as;
\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 2 \ \times \ 45^2\\\\K.E = 2,025 \ J\)
Therefore, the kinetic energy the bat can give to a ball is 2,025 J.
which shows valid accesses for an array a and vector v, each with 10 elements?
Answers
The possible valid accesses for an array a and vector v, each with 10 elements is given below:Array: a[0], a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], a[9]Vector: v[0], v[1], v[2], v[3], v[4], v[5], v[6], v[7], v[8], v[9]
The term array is used to define a set of similar data types that are stored in contiguous memory blocks. The index of an array starts at 0, which means the first element of the array is stored at index 0. In the case of arrays, the elements must be of the same data type.The term vector is defined as a dynamic array, which means that the size of the vector can be changed during runtime. Vectors are defined in the same way as arrays, except that they have a dynamic size limit and can be easily resized.
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What two things does the sun send to the Earth that allows life to flourish here?
Answers
Answer:
Nothing is more important to us on Earth than the Sun. Without the Sun's heat and light, the Earth would be a lifeless ball of ice-coated rock. The Sun warms our seas, stirs our atmosphere, generates our weather patterns, and gives energy to the growing green plants that provide the food and oxygen for life on Earth.Because of Earth's ideal distance from the Sun, it receives the perfect amount of heat and light to allow life to be created and to support it.Explanation:
Answer:
Earth receives the perfect amount of heat and light that allow life to flourish
Help me!
l want the correct answers :)
Answers
A. State of motion
B. Sachin
C. State of rest