ANSWER
\(\text{ b. None of the above}\)EXPLANATION
The buoyant force of the rock is the difference between the weights of the rock out of water and in water.
Hence, the buoyant force on the rock is:
\(\begin{gathered} F_B=5-3 \\ F_B=2N \end{gathered}\)Hence, the correct option is option b (None of the above).
Please help! Will give a lot of points
If a 100 N block is resting on a steel table with a coefficient of
static friction μs = 0.68, then what minimum force is required to
move the block?
Answer:
6800
Explanation:
100 x 0.68=6800
Answer: 68
Explanation:
What is the rms speed of oxygen molecule at a pressure of 3.9x104
Pa if it has a
density of 1.3kg/m3
The root-mean-square speed of an oxygen molecule at a pressure of 3.9 x 10^4 Pa and a density of 1.3 kg/m^3 is approximately 6.13 x 10^-9 m/s.
What is the rms speed?The root-mean-square (rms) speed of an oxygen molecule can be calculated using the ideal gas law and the definition of density.
The ideal gas law states:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Rearranging the ideal gas law to solve for the rms speed (v) gives:
v = sqrt(3 * P / (density * N))
where P is the pressure, density is the density of the gas, and N is Avogadro's number (6.022 x 10^23 molecules/mol).
Given:
Pressure (P) = 3.9 x 10^4 Pa
Density = 1.3 kg/m^3
We can substitute these values into the formula to calculate the rms speed of an oxygen molecule.
v = sqrt(3 * (3.9 x 10^4) / (1.3 * (6.022 x 10^23)))
v = sqrt(3.77 x 10^-18 m^2/s^2)
v ≈ 6.13 x 10^-9 m/s
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State any five (5) clinical uses of heat enery .
The therapeutic effects of heat include increasing the extensibility of collagen tissues; decreasing joint stiffness; reducing pain; relieving muscle spasms; reducing inflammation, edema, and aids in the post acute phase of healing; and increasing blood flow.
What is the role of heat energy in the body?In the process of ATP production by cells throughout the body, approximately 60 percent of the energy produced is in the form of heat used to maintain body temperature. Thermoregulation is an example of negative feedback.
Why is heat used as a treatment during health care?
Heat treatments should be used for chronic conditions to help relax and loosen tissues, and to stimulate blood flow to the area. Heat is a great treatment option for chronic conditions caused from old injuries or even arthritis. Heat can be applied before participating in activities to help limber up.
So we can conclude that heat is one of the most important form of energy for our daily life.
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Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.
High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.
High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.
Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.
Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.
Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.
Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.
Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."
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1. Fenway Park's small dimensions and the Green Monster have what overall effect on baseball statistics?
Suppose that you drop a 10 Kg object from a table and gains a kineticenergy of 100 J right before it hits that ground. How high was the table?Use g = 10 m/s2
KE when it hits the ground = PE before it's dropped
PE = mgh
KE = mv^2/2 = 100J
100 J = mgh
100 = 10*10*h
h = 100/100
h = 1 m
What invisible force will cause you to fall to the earth if you fall off your bed?
Answer:
The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.
Explanation:
your welcome
The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 188 kg, while the mass of the other sphere was 0.93 kg.
What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
The gravitational force between the spheres is
\(F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N\)
where G = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
\(F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N\)
where g = 9.80 m/s².
The ratio between the two forces is then
\(\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}\)
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy … (use g = 10 m/s 2)
A) at the moment of impact.
B) 2 seconds after the stone is released.
C) after the stone has fallen 40 m.
D) when the stone is moving at 20 m/s.
At the moment of impact both Kinetic Energy and Potential Energy should be 0, right? So it can't be A), right? Or is this wrong? Is it indeed A)? Please show work and explain it well.
Answer: c. 40m
Explanation:
See picture
Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.
The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.
To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.
The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.
The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.
By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:
The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.
The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.
The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.
Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.
Hence, the correct statement is: The graph shifts 2 units right and 7 units down.
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Part 3: Energy Conversions 7. Record your data in the chart and include at least 5 potential-kinetic energy conversions shown in your device's construction. Example Item Description of potential-kinetic energy conversion Example Book The book had gravitational potential energy when it was on the table. Then as the book fell off the table, it was in motion and had kinetic energy. 1 2 3 4 5
Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.
Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.
As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.
Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.
As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.
Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.
Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.
Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.
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A lab cart with a mass of 530 grams has an initial speed of 1.30 meters per second. While the cart rolls through a distance of 34.0 centimeters, a constant force of 4.29 newtons pushes the cart in the direction it's moving. At the same time, friction does -0.237 joules of work. What is the cart's final speed? Include units in your answer. Answer must be in 3 significant digits.
The net work done on the cart can be given as,
\(W=Fd+W_f\)The change in kinetic energy of the cart is,
\(\Delta K=\frac{1}{2}m(v^2-u^2_{})\)According to work energy theorem,
\(W=\Delta K\)Substitute the known expression,
\(\begin{gathered} Fd+W_f=\frac{1}{2}m(v^2-u^2) \\ v^2-u^2=\frac{2(Fd+W_f)}{m} \\ v^2=\frac{2(Fd+W_f)}{m}+u^2 \end{gathered}\)Substitute the known values,
\(\begin{gathered} v^2=\frac{2((4.29\text{ N)(34.0 cm)(}\frac{1\text{ m}}{100\text{ cm}})\text{-0.237 J)}}{(530\text{ g)(}\frac{1\text{ kg}}{1000\text{ g}})}+(1.30m/s)^2 \\ =4.610m^2s^{-2}+1.69m^2s^{-2} \\ v=\sqrt[]{6.300m^2s^{-2}} \\ \approx2.51\text{ m/s} \end{gathered}\)Thus, the final speed of cart is 2.51 m/s.
Newton's Third Law of Motion
Answer:
Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts
Explanation:
Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.
We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.
A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."
Hope this helps ^_^ and have a great day
please help science .
Answer:
I think it's shape the shape of the samples
Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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find the magnitude of the vecter c that satisfies the equation 2A-6B+3C=2j
Answer:
We can solve for the magnitude of vector C by first isolating it on one side of the equation:
2A - 6B + 3C = 2j
3C = 2j - 2A + 6B
C = (2/3)j - (2/3)A + 2B
Now that we have an expression for vector C, we can find its magnitude using the formula:
|C| = sqrt(Cx^2 + Cy^2 + Cz^2)
where Cx, Cy, and Cz are the x, y, and z components of vector C, respectively.
Since the equation only gives us information about the y-component of vector C, we can assume that the x and z components are zero. Therefore,
Cx = 0
Cy = 2/3
Cz = 0
|C| = sqrt((0)^2 + (2/3)^2 + (0)^2)
|C| = sqrt(4/9)
|C| = 2/3
Therefore, the magnitude of vector C is 2/3.
A truck slows from a velocity of 34 m/s to a stop in 50 m. What was the
truck's acceleration? *
The acceleration/deceleration of the truck is 11.56 m/s^2
Velocity and acceleration Velocity is the rate of change of displacement of a body.Velocity = change in displacement/ time
Acceleration is the rate of change of velocity with time.Acceleration = change in velocity/ time.
The acceleration, velocity and distance travelled of a body is related by the equation below:
v^2 = u^2 + 2aswhere v is the initial velocity
u is the final velocity
a is the acceleration, and
s is the distance travelled
From the data provided:
v = 0
u = 34 m/s
s = 50 m
a = ?
making a subject of the formula
a = -u^2/2s
a = - 34^2 / 2 × 50
a = -11.56 m/s^2
Therefore, the acceleration/deceleration of the truck is 11.56 m/s^2
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Formulating an Investigative Question
In this lab, you will use a magnet and a simple circuit to
examine the concepts of electricity and magnetism. Think
about how these ideas can be shown experimentally.
In the space below, write a scientific question to address
by doing this experiment.
A magnet can be used to show electromagnetic forces by showing how negative charges can move a particular piece of metal.
What is a scientific question?A scientific question is a given question derived from observation of the real world and can be answered by applying the scientific method.
In this case, a plausible scientific question might be how electromagnetic forces can move a piece of metal and we need to develop an explanation (hypothesis) to understand it.
In conclusion, a magnet can be used to show electromagnetic forces by showing how negative charges can move a metal.
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Answer:
How can magnetic and electric fields be demonstrated?
Explanation:
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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Complete this concept map about types of waves.
Answer:
The answer is within the picture.
Explanation:
Objects with greater inertia will have a A. Easier time moving B. Decrease in inertia C. Increase in the accelerationD. Decrease in the acceleration
To find:
The effect of inertia on the object.
Explanation:
The inertia of a body is the tendency of the body to resist the applied force. That is inertia opposes the change in the motion of the body.
Thus if the inertia of a body is higher, then the change in the velocity, i.e., the acceleration of the body will be lesser. And if a body has less inertia, when a force is applied to the body, it will have a higher value of acceleration.
Final answer:
Thus the correct answer is option D.
A radioactive substance of mass 800g has half life of 4 years, how many years those it have with only 8g undecayed
It will take approximately 8 years for a radioactive substance of mass 800g to have 8g undecayed.
What is the half-life of the radioactive substance in question?The half-life of the radioactive substance in question is 4 years. The half-life of a radioactive substance is the amount of time it takes for half of the original amount of the substance to decay. In this case, after 4 years, half of the initial 800g of the radioactive substance will have decayed, leaving 400g remaining. This means that the decay rate of the radioactive substance is 50% per 4 years. The half-life is a constant for a specific radioactive substance and it does not change, this means that if we wait another 4 years, half of the remaining 400g will decay leaving only 200g, and so on.
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A horizontally launched projectile lands 75.72 m below the launch point and a horizontal distance of 104.42 m/s from the launch point. How long did it take to hit the ground?
With an initial horizontal velocity of 32.31 m/s and a time of 3.23 seconds to impact the earth, the projectile was launched.
Is the projectile's velocity in the y direction zero when it is fired horizontally?When an object is hurled horizontally in projectile motion, it has zero initial vertical velocity and only a horizontal initial velocity. Through the projectile's entire motion, the original horizontal velocity is maintained.
\(y = 1/2 * a_y * t^2\)
\(t^2 = 2y / a_y\)
\(t = sqrt(2y / a_y)t = sqrt(2*75.72 m / 9.81 m/s^2)\)
t = 3.23 s (rounded to two decimal places)
\(x = vi_x * t\)
\(vi_x = x / t\)
\(vi_x = 104.42 m / 3.23 s\)
\(vi_x = 32.31 m/s\)(rounded to two decimal places)
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A proposed high-speed train between Houston and Dallas will travel a distance
of 386 kilometers in 5.40 103 seconds. What is the average speed of this train
in meters per second?
o 1.40 x 10-2 m/s
o 7.50 x 10-2 m/s
0 71.5 m/s
O 140 m/s
Explanation:
the third answer is correct
71.5m/s
The average speed of the train is equal to 71.5 m/s. Therefore, option (C) is correct.
What is the average speed?The average speed can be described as the total distance traveled by the object in a definite time interval. The average speed is a scalar quantity as it carries only the magnitude and does not have direction.
The average speed can be calculated from the ratio of the total distance traveled by the object to the time taken to cover that distance.
The average speed equation can be written as follows:
Average speed = Total distance /Total time taken
Given, distance covered by the train from Houston to Dallas = 386Km
As we know that 1 Km = 1000 m
The total distance traveled by train = 386000 m
The total time taken = 5.40 × 10³ sec
The average speed of the train = 386000/5400 = 71.5 m/s
Therefore, the average speed of the given train is 71.5m/s.
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the 50-mm-diameter a992 steel shaft is subjected to the torques shown. determine the angle of twist of the end a.
The angle of twist of end A is 0.0150 radians or 0.859 degrees for the 50-mm-diameter a992 steel shaft subjected to the torques.
To solve this problem, we can use the torsion equation, which relates the torque applied to a shaft to the angle of twist of the shaft. The equation is:
T/J = Gθ/L
where T is the torque applied to the shaft, J is the polar moment of inertia of the shaft, G is the shear modulus of elasticity of the material, θ is the angle of twist of the shaft, and L is the length of the shaft between the points where the torque is applied.
For the first section of the shaft between points B and C, we can calculate the polar moment of inertia using the formula for a solid circular shaft:
J = (π/32) × (\(d^4\))
where d is the diameter of the shaft. Plugging in the values given, we get:
J = (π/32) × \((50 mm)^4\) = 6.34×\(10^6\) \(mm^4\)
The length of this section is given as 300 mm, and the torque applied is 40 Nm. Therefore, we can calculate the angle of twist using the torsion equation:
θ = TL/JG
= (40 Nm)(300 mm)/(6.34 × \(10^6\) \(mm^4\))(77 GPa)
= 0.000293 rad or 0.0168 degrees
For the second section of the shaft between points C and D, we can use the same formula to calculate the polar moment of inertia, but the length and torque are different:
J = (π/32) × \((50 mm)^4\) = 6.34×\(10^6\) \(mm^4\)
L = 600 mm, T = 200 Nm
θ = TL/JG
= (200 Nm)(600 mm)/(6.34 × \(10^6\) \(mm^4\))(77 GPa)
= 0.00294 rad or 0.168 degrees
For the final section of the shaft between points D and A, we again use the same formula, but with different length and torque values:
J = (π/32) × \((50 mm)^4\) = 6.34×\(10^6\) \(mm^4\)
L = 600 mm, T = 800 Nm
θ = TL/JG
= (800 Nm)(600 mm)/(6.34×\(10^6\) \(mm^4\))(77 GPa)
= 0.0118 rad or 0.677 degrees
The total angle of twist of the shaft from end A to end B is simply the sum of the angle of twists for each section:
θ_total = θ_BC + θ_CD + θ_DA
= 0.000293 rad + 0.00294 rad + 0.0118 rad
= 0.0150 rad or 0.859 degrees
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The question is -
The 50-mm-diameter a992 steel shaft is subjected to the torques shown. determine the angle of twist of the end a.
Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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a box of mass 8.0 kg rests on a horizontal rough surface. a string attached to the box passes over a smooth pulley and supports a 2.0 kg mass at its other end, when the box is released, a frictional force of 6.0 n acts on it. (a) draw free-body diagrams of the 8.0 kg box and the 2.0 kg mass. (b) determine the (i) acceleration of the system, (in) tension in the string.
a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.
bi) the acceleration of the system is 0.4 m/s^2
bii) the tension in the string is 0.8 N.
How do we calculate?Net force = ma
Net force = T - F_friction
where T is the tension force and F_friction is the frictional force.
Substituting the given values, we have:
T - F_friction = ma
T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)
T - 6.0 N = 10.0 kg a
(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:
Net force = ma
where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:
Net force = T
Substituting the given values, we get:
T = ma
T = 2.0 kg x a
To solve for T, we need to find the acceleration of the system.
To find both a and T, we can use the equations we derived above and solve them simultaneously:
T - 6.0 N = 10.0 kg a (equation 1)
T = 2.0 kg x a (equation 2)
Substituting equation 2 into equation 1, we get:
2.0 kg x a - 6.0 N = 10.0 kg a
Solving for a, we get:
a = 0.4 m/s^2
Substituting a into equation 2, we get:
T = 2.0 kg x 0.4 m/s^2 = 0.8 N
Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.
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Which of the following describes the role of C6H12O6 in the Calvin cycle?
Answer:
C6H12O6 is the final product of Calvin cycle light independent reactions
Explanation:
* steps in Calvin cycle
: carbon fixation
: reduction
: regeneration
for C6H12O6 it requires 2 molecules of PGAL or G3P
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Which statement does NOT correctly describe the particles in a liquid?
A. The particles are closer together than they would be in most solids.
B. The particles are moving much more rapidly than they would in a solid.
C. The particles can slide past each other.
D. The particles can vibrate.
Answer:
A
Explanation:
I may not be right but, in my view it is correct
Answer:
A. The particles are closer together than they would be in most solids.