A roller coaster car travels along the track shown in the diagram above At which position on the track are the kinetic and potnetial energy of the roller coaster car almost equal to each other

Let's name some variables:

n1: order of yellow-orange light; n1 = 3

λ1: wavelength of yellow-orange light; λ1 = 541.08 nm

n2: order of unknown light; n2 = 4

λ2: wavelength of unknown light; we will solve for this

Given these known and unknown variables, we can use the following equation to solve for λ2:

n1*λ1 = n2*λ2

Now all we have to do is plug in the variables we know and solve for λ2.

3*541.08 = 4*λ2

λ2 = 3*541.08/4

λ2 = 405.81 nm

Answer:

C

Explanation:

Answer:

c

Explanation:

e2020

Answer:

The speed of sound is greater in hot air than it is in cold air. This is because the molecules of air are moving faster and the vibrations of the sound wave can therefore be transmitted faster. This means that when sound travels from hot air to cold air or from cold air to hot air it will refract.

Explanation:

Hope this will be help!

There are certainly times when someone's actions can cause others to dislike them. For example, if someone consistently behaves rudely or disrespectfully towards others, this can quickly turn people off.  we can build positive physical relationships and avoid causing unnecessary conflicts or hurt feelings.

The Similarly, if someone is frequently dishonest or unreliable, this can also cause others to lose trust and respect for them. It's also worth noting that some actions may be more egregious than others and may cause stronger negative reactions. For example, if someone engages in bullying behavior or is openly discriminatory towards certain groups, this is likely to be viewed very negatively by most people. Ultimately, the key to avoiding negative reactions from others is to be mindful of how our actions impact those around us, and to strive to treat others with kindness, respect, and honesty. By doing so, we can build positive physical relationships and avoid causing unnecessary conflicts or hurt feelings.

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Answer:

I think it's dio to atmospheric pressure.

Answer: Distance: 27m Displacement: 7m

Explanation: Distance is total, Displacement is from the start.

Hope this helped!

Mark Brainliest if you feel like it!

Answer:

its black

Explanation:

because thats the color it is

Answer:

Constants: 1 atm = 760 mm Hg = 760 torr = 1.01325 bar = 101.325 kPa R = 8.314 J·mol-1K-1= 0.08206 L·atm·mol-1K-11 Calorie = 1 kcal = 4.184 kJ Data:Properties of liquid water: b.p. (at 1 atm) = 100.00°CCH2O(l)= 4.184 J·g-1·K-1ΔHovap= 40.7 kJ·mol-1dH2O(l)(at 25°C) = 1.00 g·mL-1 KfH2O= 1.86 °C·kg·mol-1KbH2O= 0.52 °C·kg·mol-1Po(298 K)= 23.8 mm Hg Properties of ice: m.p. (at 1 atm) = 0.00°CCH2O(s) = 2.06 J·g-1·K-1 dH2O(s)= 0.917 g·mL-1 ΔHofus= 6.02 kJ·mol-1Formulae: ΔGo= ΔHo-TΔSo ΔG = ΔGo+ RT lnQΔGo= -RT lnKeqC = k P (or, S = k P) P = χPoΔT = KmπV = nRT [A]t= -k t + [A]oln[A]t= -k t + ln[A]o1/[A]t= k t + 1/[A]o

I am not sure If that helps im sorry I'm only in middle school :P.

10 kHz is the frequency does a stationary listener hear the sound as the plane approaches.

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Answer:the rock is heaver and gravity pulls it down while the feather floats for a while and then reaches the ground

Explanation:i dont know if this is the right answer or not

We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

From the question we are told

For Cart A

Generally the equation for the Velocity  is mathematically given as

\(v=\frac{d}{t}\\\\t=\frac{d}{v}\\\\t=\frac{1000}{20}\\\\t=50sec\)

For Cart B

Generally the Newtons equation for the Motion  is mathematically given as

\(S=ut+1/2at^2\\\\Therefore\\\\S=ut+1/2at^2\\\\1000=0+1/2*(0.33)t^2\\\\t=\frac{1000}{1/2*(0.33}}\\\\t=77.5secs\)

Since

Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

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Answer:

I can not see the image, so i will answer in a general way.

As you know, the sound behaves like a wave, this means that the sound needs some time to cover a given distance. An example of this motion can be seen when you drop a little stone in water, and you can see how the waves expand.

This means that the one who will hear the sound first, will be always the one that is closer to the source of the sound, in this case, the sound comes from the ball hitting the backboard, then the one who is closer to the backboard will hear the sound first.

The power output of the man pulling the bar can be calculated as follows:

Power = Work / Time

The work done by the man is equal to the force he exerts multiplied by the distance he moves the weights:

Work = Force x Distance

The force he exerts is equal to the weight of the weights he is lifting:

Force = Weight x g

where g is the acceleration due to gravity, which is approximately 10 m/s^2.

Plugging in the given values, we get:

Force = 30 kg x 10 m/s^2 = 300 N

Work = Force x Distance = 300 N x 0.5 m = 150 J

Power = Work / Time = 150 J / 0.5 s = 300 W

Now we can check which of the other options exerts the same power output:

Option A:

Force = 25 kg x 10 m/s^2 = 250 N

Work = Force x Distance = 250 N x 2.4 m = 600 J

Power = Work / Time = 600 J / 2.0 s = 300 W

Option B:

Force = 45 kg x 10 m/s^2 = 450 N

Work = Force x Distance = 450 N x 2.4 m = 1080 J

Power = Work / Time = 1080 J / 3.0 s = 360 W

Option C:

Force = 45 kg x 10 m/s^2 = 450 N

Work = Force x Distance = 450 N x 0.5 m = 225 J

Power = Work / Time = 225 J / 0.5 s = 450 W

Option D:

Force = 30 kg x 10 m/s^2 = 300 N

Work = Force x Distance = 300 N x 0.5 m = 150 J

Power = Work / Time = 150 J / 1.5 s = 100 W

Therefore, options A and B exert the same power output as the man pulling the bar, while options C and D do not.

Answer:

Matter, Force

Explanation:

In scientific contexts, mass is the amount of "matter" in an object (though "matter" may be difficult to define) whereas weight is the force exerted on an object by gravity. Objects on the surface of the Earth have weight, although sometimes the weight is difficult to measure.

Answer: because he loves her:)

Explanation:

A 2 kg cue ball is moving at a velocity of 2 m/s when it collides with another 3 kg billiard ball at rest. The total momentum is 4 kg m/ s.

Elaborating the problem:

Before the collision, the momentum of the 2 kg cue ball is:

p₁ = m₁ × v₁

p₁ = 4 kg m/s

The 3 kg billiard ball is at rest, so its momentum is: p₂ = 0 kg m/s

The total momentum of the system before the collision is:

p_total = p₁ + p₂

p_total = 4 kg m/s

The total momentum of the system after the collision is:

p_total = M × \(V_{f}\)

p_total = p₁ + p₂

M × \(V_{f}\) = p₁ + p₂

5 kg × \(V_{f}\) = 4 kg m/s + 0 kg m/s

5 kg * \(V_{f}\) = 4 kg m/s

Therefore, \(V_{f}\) = 0.8 m/s

So, the total momentum of the system is:

p_total = M × \(V_{f}\)

p_total = 5 kg  × 0.8 m/s

p_total = 4 kg m/s

A system's total momentum is the sum of the momentum of all its components. To put it another way, it is the total amount of motion experienced by the system's objects. The total momentum of an isolated system remains constant when there are no external forces acting on it, as stated by the law of conservation of momentum.

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Answer:

Patterson isolated lead from fragments of a meteorite that had struck Earth thousands of years ago, and determined the age of the fragments by analyzing proportions of the lead isotopes. The meteorite is assumed to have been formed at the same time as the rest of the solar system, including Earth

Explanation:

Answer:

9 s.

Explanation:

The following data were obtained from the question:

Time (t) taken to reach the maximum height = 4.5 s

Time of flight (T) =?

The time of flight (T) is simply defined as the total time spent by the ball in the air. Mathematically, it defined as twice the time taken (t) to reach the maximum height i.e

T = 2t

With the above formula, we can obtain the time of flight as follow:

Time (t) taken to reach the maximum height = 4.5 s

Time of flight (T) =?

T = 2t

T = 2 × 4.5

T = 9 s

Thus, the time of flight of the ball is 9 s.

cause there's no gravity therefore they appear weightless

Answer:

it would take approximately 1.7 seconds for Fluffy the Cat to fall from a 15 meter tall tree.

Explanation:

To calculate the time it takes for an object to fall, you can use the following formula:

t = sqrt(2d / g)

where:

t is the time in seconds

d is the distance fallen in meters

g is the acceleration due to gravity (approximately 9.8 m/s^2 on the surface of the Earth)

So, substituting in the values for d (15 meters) and g (9.8 m/s^2), we get:

t = sqrt(2 * 15 / 9.8)

t = sqrt(30 / 9.8)

t = sqrt(3.06122448979591836734693877551)

t ≈ 1.744823934831724823036837018032 seconds

Answer:

they will repel, moving in opposite,

Explanation

The mass of the given will be 20kg.

By using formula,

force = mass x acceleration

mass = force / acceleration

mass = 400 N / 20m/s²

mass = 20 Kg

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because the velocity is both a speed and a direction.

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Answer:

f/2

Explanation:

In this case the force that is necessary to keep the object moving in a curved path and that is directed inward toward the center of rotation, centripetal force = f

f= m × centripetal acceleration

centripetal acceleration = V^2/r

Therefore f = m (2v)^2 /r --------1

If frictional force required to keep the large car on the road = F

F= 2m (v)^2/ r----------2

Now Divide 1st equation by 2nd one

f/F = m (2v)^2/2m(v)^2

f/F = 2

F= f/2

a) The force diagram of the block and all the forces are in the image attached.

(b) The weight of the block and its parallel component is  98.1 N and 33.55 N respectively.

(c) The applied force on the block is 52.75 N

(a) The force diagram of the block include, the parallel and pedicular component, as well as friction force.

(b) The weight of the block and its parallel component is calculated as;

Fg = mg

where;

Fg = 10 kg x 9.81 m/s²

Fg = 98.1 N

Fgₓ = mgsinθ

Fgₓ = 98.1 N x sin(20)

Fgₓ = 33.55 N

(c) The applied force on the block is calculated as follows;

F - Fgₓ - μFgcosθ = ma

where;

μ = a/g

μ = 1 / 9.81 = 0.1

F - 33.55 - 0.1(98.1 x cos20) = 10 x 1

F - 33.55 - 9.2 = 10

F = 10 + 33.55 + 9.2

F = 52.75 N

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Given: Distance (x) covered by the ball = 180 m, maximum height (y) reached by the ball = 21.3 m The trajectory followed by the ball can be modelled using the equations of motion. The initial velocity of the ball is 31.63 m/s.

The equations of motion relate the displacement, velocity, time and acceleration of the moving body. The general equation of motion for vertical motion under gravity is: y = u sinθt - 1/2 gt²where y is the vertical displacement, u is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity and t is the time taken to reach the maximum height.

The maximum height is given by: (u y = 0)t = u sinθ/g Solving for t, we have: t = (u sinθ)/g Therefore, the equation of motion becomes: y = (u²sin²θ)/ 2 g Putting the given values in the above equation:21.3 = (u² sin² 45)/ (2 x 9.8) => u = 31.63 m/s Therefore, the initial velocity of the ball is 31.63 m/s.

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The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.

The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:

F = (G * m₁ * m₂) / r²

where G is the gravitational constant.

m₁ = 6 x 10²⁴ kg (mass of Earth)

m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)

r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)

Plugging in the values into the formula, we have:

F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²

Calculating the expression, we find:

F ≈ 1.32 x 10²⁸ N

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THE COMPLETE QUESTION IS:

Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹

Rewrite the equation as

\(y = (x-1) (x-2) x^{-1/2}\)

Then by the product rule, the derivative is

\(\dfrac{dy}{dx} = (x-2) x^{-1/2} + (x-1) x^{-1/2} - \dfrac12 (x-1) (x-2) x^{-3/2}\)

and we can factorize this as

\(\dfrac{dy}{dx} = \dfrac12 x^{-3/2} \left(2 (x-2) x^{3/2-1/2} + 2 (x-1) x^{3/2-1/2} - (x-1) (x-2)\right)\)

\(\dfrac{dy}{dx} = \dfrac12 x^{-3/2} \left(2 (x-2) x + 2 (x-1) x - (x-1) (x-2)\right)\)

\(\dfrac{dy}{dx} = \dfrac12 x^{-3/2} (3x^2 - 3x - 2)\)

\(\dfrac{dy}{dx} = \dfrac{3x^2 - 3x - 2}{2x^{3/2}}\)

and optionally expanded once more (if only to match the provided "Ans") to

\(\dfrac{dy}{dx} = \dfrac32 x^{2-3/2} - \dfrac32 x^{1-3/2} - x^{-3/2}\)

\(\dfrac{dy}{dx} = \dfrac32 x^{1/2} - \dfrac32 x^{-1/2} - x^{-3/2}\)

\(\dfrac{dy}{dx} = \dfrac32 \sqrt x - \dfrac3{2\sqrt x} - \dfrac1{\sqrt{x^3}}\)

Answer:

get some

get some ⛽⛽⛽⛽⛽

pour the ⛽ on the module,

get that on itttttt and booooooommmm

Explanation:

Answer:

23.6

Explanation:

The net force applied on the truck is 267.8 N.

The acceleration of the truck is 3.15 m/s².

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

Given parameters:

Force applied on the truck: F = 295 N.

Mass of the trick: m = 85 kg.

Weight of the truck: W = mg = 85 kg × 10 m/s² = 850 N.

The coefficient of friction between the rock and the ground is μ = 0.32.

Frictional resistance force applied on the truck: f = μ N =  μW

= 0.32×85 N

= 27.2 N.

Hence, net force applied on the truck = F - f = 295 N - 27.2 N = 267.8 N.

Hence, acceleration of the truck is = 267.8 N/85 kg = 3.15 m/s².

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