The average velocity of the 150 kg cart on the 75-meter roller coaster track is approximately 0.42 meters per second.
To find the average velocity of the cart, we need to use the formula:
Average velocity = Total displacement / Total time
In this case, the total displacement is 75 meters (the length of the track) and the total time is 3 minutes, which we need to convert to seconds (1 minute = 60 seconds, so 3 minutes = 180 seconds).
Average velocity = 75 meters / 180 seconds
Average velocity ≈ 0.42 meters per second
So, the average velocity of the 150 kg cart on the 75-meter roller coaster track is approximately 0.42 meters per second.
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PLEASE HELP ILL GIVE CROWN!!!
the main difference between weather and climate is-
A ) Weather occurs daily, while climate is the average of weather over a long period of time.
B ) Climate occurs daily, while weather is the average of climate over a long period of time.
C ) Weather is not affected by ocean and wind currents but climate is.
D ) Climate is not affected by ocean and wind currents and wind currents but weather is.
Answer:
A :)
Explanation:
....................
Answer:
Shoukd be A
Explanation:
Weather reflects the short term conditions while climate is average for the certain location
Which two factors affect the amount of force seen in objects?
Answer:thanks
Explanation:xixo
gv
identify the correct pressure variation graph for the 1120 hz standing wave in the pipe. note that the closed end of the pipe is on the right. view available hint(s) an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?
The length of the air-filled pipe is \(v/560\) Hz, where v is speed of sound.
The correct pressure variation graph for the 1120 Hz standing wave in the pipe is the one with two antinodes and one node. The pressure is highest at the antinodes and lowest at the nodes.
To determine the length of the pipe, we can use the formula:
\(L = n * (v/2f)\)
where L is the length of the pipe, n is the harmonic number, v is the speed of sound, and f is the frequency of the harmonic.
For the fundamental frequency (the first harmonic), we have:
\(L = 1 * (v/2f) = v/2f\)
For the second harmonic, we have:
\(L = 2 * (v/2f) = v/f\)
For the third harmonic (1120 Hz), we have:
\(L = 3 * (v/2f) = 3v/2f\)
Since the pipe has harmonics at 480 Hz, 800 Hz, and 1120 Hz, we can write:
\(v/2L = 480 Hz,\) \(v/L = 800 Hz\), and\(3v/2L = 1120 Hz\)
Solving for L, we get:
\(L = v/(2 * 480 Hz) = v/960\)
\(L = v/800 Hz\)
\(L = 2v/3360 Hz\)
Since we do not know if there are harmonics below 480 Hz or above 1120 Hz, we cannot use these equations to solve for the length of the pipe. However, we can see that the length of the pipe is proportional to the wavelength of the sound waves in the pipe. The wavelength of the third harmonic is four times the wavelength of the first harmonic, so the length of the pipe must be four times the length of the pipe for the first harmonic. Therefore, the length of the pipe is:
\(L = 4 * (v/2 * 1120 Hz) = v/560 Hz\)
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Urgent need help 100 points
Suppose that scientists observe violent gas eruptions on a planet with an acceleration due to gravity of 3.6 m/s2.
The jets throw sand and dust about 75 m
above the surface.
What is the speed i
of the material just as it leaves the surface?
Scientists estimate that the jets originate as high‑pressure gas speeds through vents just below ground at about 150 km/h.
How much energy per kilogram of material does the jet lose to nonconservative forces as the high‑speed matter forces its way to the surface and into the air?
Answer: The velocity with which the sand throw is 24.2 m/s.
Explanation:
Explanation:
acceleration due to gravity, a = 3.9 m/s2
height, h = 75 m
final velocity, v = 0
Let the initial velocity at the time of throw is u.
Use third equation of motion
The velocity with which the sand throw is 24.2 m/s.
what is another common power source for an electric circuit besides a battery
Answer: solar power converters
Answer:
Outlets besides a battery
Select all that applySelect all the characteristics that the Renaissance motet and mass have in common.A. They have five parts, including the Kyrie.B. They are both sacred music.C. They use polyphony.D. They are performed by a chorus.
The characteristics that the Renaissance motet and mass have in common are:
B: They are both sacred music
C: They use polyphony
D: They are performed by a chorus
The Renaissance motet and mass are two important musical genres of the Renaissance period. Both are sacred music that use polyphony and are typically performed by a chorus. The motet is a polyphonic choral work that is usually short and sets a Latin text, often taken from the Bible or liturgy. The mass, on the other hand, is a longer work that sets the texts of the Catholic Mass Ordinary, including the Kyrie, Gloria, Credo, Sanctus, and Agnus Dei. Both genres demonstrate the elaborate contrapuntal writing, complex harmonies, and careful attention to text setting that are hallmarks of Renaissance music.
However, the statement "They have five parts, including the Kyrie" is not correct. The Renaissance motet and mass do not necessarily have five parts, and the Kyrie is not always included in motets.
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How is a Tan function represented on a unit circle?
The tangent function can be represented on a unit circle by mapping an angle in the circle to the ratio of the y-coordinate to the x-coordinate of the point on the circumference that corresponds to that angle. This ratio is the required tangent of the given angle.
What is Tangent?
The tangent is a mathematical function that describes the ratio of the length of the side opposite a given angle in a right triangle to the length of the adjacent side. It is represented by the symbol "tan" and is defined for angles in trigonometry. It is used to describe relationships in mathematics, science, and engineering.
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What is the internal energy of a substance?
Answer:
Internal energy is the microscopic energy contained in a substance, given by the random, disordered kinetic energy of the molecules. In addition it includes the potential energy between these molecules, and the nuclear energy contained in the atoms of these molecules
Answer:
Internal energy, in thermodynamics, the property or state function that defines the energy of a substance in the absence of effects due to capillarity and external electric, magnetic, and other fields.
Explanation:
What is the equation of the line of best fit for natalie's data?
enter the correct answer in the box by replacing mand b in the equation. round each number to the
nearest tenth.
Answer:
where the numbers at ?
Explanation
Erik Erikson’s theory of psychosocial development emphasizes that development occurs by overcoming an emotional crisis in each of the eight stages of one’s lifetime. Please select the best answer from the choices provided T F.
Answer:
True
Explanation:
Answer:
The answer is T (True)
Explanation:
For a group class project, students are building model roller coasters. Each roller coaster needs to begin at the top of the first hill, where a horizontal spring that is initially compressed 0.25 m will push a small car forward.
A hill with a compressed spring at the top. There is a car sitting against the compressed spring. The portion of the hill is vertically colored orange, the middle section is vertically colored yellow and the last section colored green.
Each group of students will choose a car and a spring to push the car and then build a track. The assignment is to make the car go 5.0 m/s when it reaches the bottom of the first hill. Four groups of students choose springs and build tracks as described in the table.
A 4 column table with 4 rows. The first column is labeled group with entries A, B, C, D. The second column is labeled car mass in kilograms with entries .75, .60, .55, .84. The third is labeled spring constant in newtons per meter with entries 65, 35, 40, 32. The last column is labeled hill height in meters with entries 1.2, .90, 1.1 , .95.
Which group’s roller coaster will most likely make the car travel closest to 5.0 m/s when it is at the bottom of the first hill?
A
B
C
D
The group that will make the car travel closest to 5 m/s when it is at the bottom of the first will is of:
Group C.
How to obtain the velocity for each car?The velocity that each car will assume at the bottom of the hill is given by the equation presented as follows:
v = square root (2gh + kx²/m).
The parameters are given as follows:
g = 9.8 m/s is the acceleration relative to the gravity.h is the height of the hill.k is the spring constant.x = 0.25 represents the initial compression of the spring.m is the mass of the car.The parameters are given by the table in this problem, hence the velocities of each car are given as follows:
Group A: v = square root(2 x 9.8 x 1.2 + (65 x 0.25²)/0.75) = 5.38 m/s.Group B: v = square root(2 x 9.8 x 0.9 + (35 x 0.25²)/0.6) = 4.61 m/s.Group C: v = square root(2 x 9.8 x 1.1 + (40 x 0.25²)/0.55) = 5.05 m/s. -> closest to 5 m/s.Group D: v = square root(2 x 9.8 x 0.95 + (32x 0.25²)/0.84) = 4.58 m/s.More can be learned about velocities and springs at https://brainly.com/question/13858183
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Answer: group C
Explanation:
describe what living in the southeast is like for many people in both cities and outside of cities.
Living in the Southeast for many people, both in cities and outside of cities, offers a distinct blend of cultural, geographical, and climatic characteristics.
In cities such as Atlanta, Charlotte, or Miami, residents experience the bustling energy of urban life with a range of amenities, diverse culinary scenes, and thriving cultural attractions. These cities often have vibrant downtown areas, modern infrastructure, and employment opportunities across various industries. Residents can enjoy a mix of entertainment options, including music festivals, sports events, and a vibrant nightlife. However, they may also encounter challenges such as traffic congestion and higher living costs in some areas. Outside of cities, the Southeast region boasts picturesque landscapes and a more relaxed pace of life. Residents can find charming small towns, close-knit communities, and a stronger connection to nature. The region offers stunning coastlines, scenic mountains, and lush forests, providing ample opportunities for outdoor activities like hiking, fishing, and beach outings. Residents often appreciate the Southern hospitality, a slower lifestyle, and a sense of community. Across the Southeast, the climate is generally characterized by hot summers and mild winters, with some areas prone to hurricanes and tropical storms. The region also showcases its rich history, diverse traditions, and a culinary heritage famous for dishes like barbecue, seafood, and soul food.
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the supernova that created the crab nebula and its pulsar was seen on earth in the year_____
The supernova that created the Crab Nebula and its pulsar was seen on Earth in the year 1054.
The supernova that created the Crab Nebula and its pulsar was seen on Earth in the year 1054 AD. This event was recorded by Chinese and Japanese astronomers as a new star in the sky that shone brightly for a few weeks before fading away. Today, the Crab Nebula is one of the most studied objects in the sky, as it provides a unique laboratory for studying the aftermath of a supernova explosion.
The pulsar at the center of the nebula is a rapidly spinning neutron star that emits beams of radio waves and gamma rays, making it one of the most energetic objects in the universe.
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Li and Raj are playing football. They take turns trying to run past each other with the football. Li weighs 125 pound and Raj weighs 175 pounds. Li discovers that if he changes direction quickly when running, he can always dodge out of the way before Raj can tackle him.
Complete question is;
Li and Raj are playing football. They take turns trying to run past each other with the football. Li weighs 125 pound and Raj weighs 175 pounds. Li discovers that if he changes direction quickly when running, he can always dodge out of the way before Raj can tackle him.
Why is Li able to avoid Raj’s tackle? Choose the best description.
A) Raj has more mass and therefore more inertia, so he can change his motion more easily than Li.
B) Raj has more mass and therefore less inertia, so he can change his motion more easily than Li.
C) Li has less mass and therefore more inertia, so he can change his motion more easily than Raj.
D) Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Answer:
Option D - Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Explanation:
From Newton's first law of motion which is known as law of inertia, an object will remain at rest or continue in constant motion unless an external force acts upon it. This means that Inertia is simply the resistance of an object to any change in its state of rest or motion.
This means that the larger the mass of the object, the more resistance the object will have from an external force. Similarly, the smaller the object, the less resistance it will have from an external force.
Therefore, we can see that larger mass means larger resistance and in turn larger inertia while smaller mass denotes smaller resistance and in turn smaller inertia.
Now, from the question,Li weighs 125 pound and Raj weighs 175 pounds. So, Li has lesser mass than Raj, and so he also has less inertia. Thus, he can change his motion more easily than Raj due to that.
Answer:
Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Explanation:
i did the test
A skier skies down a slope with an average speed of 50 km/s. How far does the skier travel in 5 minutes?
Answer:
15000000 m
Explanation:
From the question,
Speed (S) = Distance(d)/Time(t)
S = d/t....................... Equation 1
Make d the subject of the equation
d = St..................... Equation 2
Given: S = 50 km/s = 50000 m/s, t = 5 minutes = 5*60 seconds = 300 seconds
Substitute these values into equation 2
d = 50000(300)
d = 15000000 m
Hence the skier travels 15000000 m
A 11.5 cm tall object is placed 6.4 cm in front of a concave mirror that has a focal length of 9.9 cm. What is the magnification?
The magnification of the object placed 6.4 cm in front of a concave mirror with a focal length of 9.9 cm is -0.62. To solve for the magnification, we can use the formula M = -di/do where M is the magnification, di is the image distance, and do is the object distance.
First, we need to find the image distance by using the mirror equation, which is 1/f = 1/do + 1/di where f is the focal length of the mirror. Rearranging the equation, we get di = 1/(1/f - 1/do). Plugging in the values, we get di = -4.14 cm. Next, we can use the magnification formula to solve for M. M = -di/do = -(-4.14 cm)/(6.4 cm) = -0.62. The negative sign indicates that the image is inverted compared to the object. Therefore, the magnification of the object placed 6.4 cm in front of a concave mirror with a focal length of 9.9 cm is -0.62.
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What is the magnitude of your displacement when you follow directions that tell you to walk 225 m in one direction, make a 90° turn to the left and walk 350 m, then make a 30° turn to the right and walk 125 m?
Start by facing East. Your first displacement is the vector
d₁ = (225 m) i
Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,
d₂ = (350 m) j
Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,
d₃ = (125 m) (cos(60º) i + sin(60º) j )
d₃ ≈ (62.5 m) i + (108.25 m) j
The net displacement is
d = d₁ + d₂ + d₃
d ≈ (287.5 m) i + (458.25 m) j
and its magnitude is
|| d || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m
The magnitude of the displacement is 291.08 m
From the given parameters;
initial displacement, x₁ = 225 msecond displacement, x₂ = 350 m at 90⁰ to the leftfinal displacement, x₃ = 125 m at 30⁰ to the rightDisplacement is the shortest distance between the initial position and the final position.
From the image added, the magnitude of the displacement is length PQ.
Apply Pythagoras theorem, t o determine the magnitude of the displacement.
"check the image uploaded"
\((125 + x)^2 = 350^ 2 + 225^2\\\\(125 + x)^2 = 173,125\\\\125 + x = \sqrt{173125} \\\\125 + x = 416.08 \\\\x = 416.08 - 125\\\\x = 291.08 \ m\)
Thus, the magnitude of the displacement is 291.08 m
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A sea turtle must crawl up a beach to lay eggs. Ignoring friction, what work must a 140-kg turtle do in lifting herself 2.5 m above the level of the sea?
Answer:
3500joules of work
Explanation:
Work done = Force×,distance
Given
Focrce= mass ,× acceleration = 140×10 = 1400N
Distance moved = 2.5m
Workdone = 1400×2.5
Work done = 140×25
Workdone = 3500Joules
If anyone answers this question, i will give you 100 points and give brainliest!
Answer:
Q1) C, D
Q2) A
Q3) E
Q4) C
Q5) B
Q6) C
Explanation:
I think these are correct, hopefully it helps!
The students tested each solution. They started each test with a bowl with one cup of water and 30 grams of oil on top. They recorded the mass of each bowl with water and oil before and after each test. They also described the results of each test. Solution Mass of Bowl Before Mass of Bowl After Description Scooping the oil with a spoon 212 g 196 g The spoon easily picked up a lot of the oil at first. As the amount of oil decreased, it got too hard to pick up the oil. Trying to remove more oil spread it around the bowl. Absorbing the oil with a paper towel 214 g 160 g The paper towel absorbed the oil really well at first. As the amount of oil decreased, the paper towel started to pick up a lot of water. The paper towel couldn't get all of the oil. Using soap to break up the oil 210 g 216 g Adding the soap rapidly cleared the oil from the top of the water. It went to the sides of the bowl. With mixing, the oil all broke up as the water got sudsy. Question After reading the results of each test, identify an advantage and a disadvantage of each solution. Drag each result to the correct location on the table. Each result can be used more than once, but not all results will be used. removes clean water with oildisperses oil on surfaceremoves all oil from the waterspreads oil around surfaceleaves all oil in the waterremoves some oil from water
Each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
The three solutions tested to remove oil from water are scooping the oil with a spoon, absorbing the oil with a paper towel, and using soap to break up the oil. Each solution has its advantages and disadvantages. Scooping the oil with a spoon is an effective solution to remove a significant amount of oil quickly. However, it is not a practical solution for removing a large amount of oil. The disadvantage is that it spreads the oil around the surface of the water and leaves some oil in the water. Absorbing the oil with a paper towel can effectively remove a lot of oil. The advantage is that it removes some oil from the water, leaving it relatively clean. However, it also picks up a lot of water and can't get all of the oil. Using soap to break up the oil is a good solution that removes all of the oil from the water. The advantage is that it removes all of the oil from the water, leaving it clean. However, the disadvantage is that it disperses the oil on the surface of the water, making it harder to remove from the sides of the bowl. In conclusion, each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
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1. what is the role of the baffles in a shell-and-tube heat exchanger? how does the presence of baffles affect the heat transfer and the pumping power requirements?
Baffles are flat plates or bars that are placed inside a shell-and-tube heat exchanger to promote turbulence and enhance heat transfer. The baffles create a series of parallel flow paths, forcing the fluid to change direction several times as it flows through the heat exchanger.
This results in an increase in the heat transfer coefficient by promoting better mixing and reducing the thickness of the thermal boundary layer.
The presence of baffles increases the pressure drop across the heat exchanger, which in turn increases the pumping power requirements. However, the increase in heat transfer coefficient outweighs the increase in pressure drop, resulting in an overall improvement in the heat transfer efficiency of the heat exchanger. The baffles also serve to support the tubes and prevent damage from tube vibration, which can occur in the absence of baffles.
The selection and design of baffles are critical to the performance of a shell-and-tube heat exchanger. The spacing, angle, and number of baffles must be carefully considered to optimize the heat transfer rate and minimize the pumping power requirements.
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a 16.0 kg cart is moving with a speed of 14.0 m/s. to what height up a frictionless hill will the cart roll before starting to roll back down?
The maximum height up to which the cart can roll where its potential energy equals to the kinetic energy is 10 m.
What is potential energy?Potential energy of an object is the energy stored on it by virtue of its position. Kinetic energy is the energy generated on a body by virtue of its motion.
The maximum height that an object can roll up can be determined using the fact that, at the maximum height, the kinetic energy of the body equals to its potential energy.
mgh = 1/2 mv²
Thus, h = 1/2 v² /g
= 1/2 (14 m/s )² / 9.8 m/s²
= 10 m
Therefore, the height upto which the cart can move up is 10 m.
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An object traveling at velocity (100 10) pixels per frame is bounced off a wall with normal (-1/2 V3/2). What is the velocity of the object after the bounce?
The velocity of the object after bouncing off the wall is approximately (150 - 5√3, -(5√3 - 40)) pixels per frame.
To calculate the velocity of the object after the bounce, we need to use the concept of vector reflection. The velocity after the bounce can be obtained by reflecting the initial velocity vector across the given wall's normal vector.
To reflect the velocity vector across the wall's normal vector, we can use the formula:
V_final = V_initial - 2 * (V_initial dot N) * N
where V_final is the final velocity vector, V_initial is the initial velocity vector, N is the normalized wall's normal vector, and dot represents the dot product between vectors.
First, let's normalize the wall's normal vector:
N = (-1/2, √3/2) / √((-1/2)^2 + (√3/2)^2)
N = (-1/2, √3/2)
Next, we can calculate the dot product between the initial velocity and the normalized normal vector:
(V_initial dot N) = (100, 10) dot (-1/2, √3/2)
(V_initial dot N) = -50 + 5√3
Finally, we can substitute the values into the reflection formula:
V_final = (100, 10) - 2 * (-50 + 5√3) * (-1/2, √3/2)
V_final = (150 - 5√3, -(5√3 - 40))
Therefore, the velocity of the object after the bounce is approximately (150 - 5√3, -(5√3 - 40)) pixels per frame.
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A sample of oxygen gas occupies a volume of 200 mL at a pressure of 720 torr. What volume will the gas occupy at a pressure of 800 torr if temperature is held constant
We have that the gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of
\(V_2=0.18L\)
From the Question we are told that
Initial Pressure \(P_1=720\)
final Volume \(V_1=200mL\)
Initial Pressure \(P_2=800\)
final Volume \(V_2=?\)
Generally the equation for Boyle's law is mathematically given as
\(P_1V_1= P_2V_2\)
Therefore
\(V_2=\frac{ P_1V_1}{P_2}\\\\V_2=\frac{ 720*200}{800}\\\\V_2=180mL\)
\(V_2=0.18L\)
The gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of
\(V_2=0.18L\)
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Aluminum is often melted down for recycling purposes. Assuming 1 kg of aluminum is at room temperature, what is the minimum amount of heat needed to melt it to a liquid? The specific heat capacity of aluminum is 899 J/kg°C, the melting point is 660°C, and the latent heat of fusion is 3.97 x 105 J/kg.
60 points
The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
What is enthalpy of fusion?The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.
The formula for the enthalpy of the fusion is;
\(\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ\)
Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
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Class: Date: ame: 20. (113) A simple pendulum clock with an arm length of 150.3 cm swings through 100.0 cycles in 246.7 s on the surface of the Earth. (10 PTS.) (a) Compute the period of the pendulum
A simple pendulum clock with an arm length of 150.3 cm swings through 100.0 cycles in 246.7 s on the surface of the Earth. The period of the pendulum is approximately 2.467 s.
The period of a simple pendulum is the time it takes for one complete oscillation, which can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum arm, and g is the acceleration due to gravity. In this case, the length of the pendulum arm is given as 150.3 cm.
To use the formula, we need to convert it to meters by dividing by 100, resulting in 1.503 m. The acceleration due to gravity on the surface of the Earth is approximately 9.8 m/s². Substituting these values into the formula, we find T = 2π√(1.503/9.8) ≈ 2.467 s. Therefore, the period of the pendulum is approximately 2.467 seconds.
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A simple pendulum clock with an arm length of 150.3 cm swings through 100.0 cycles in 246.7 s on the surface of the Earth. The period of the pendulum is approximately 2.467 s.
The period of a simple pendulum is the time it takes for one complete oscillation, which can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum arm, and g is the acceleration due to gravity. In this case, the length of the pendulum arm is given as 150.3 cm.
To use the formula, we need to convert it to meters by dividing by 100, resulting in 1.503 m. The acceleration due to gravity on the surface of the Earth is approximately 9.8 m/s². Substituting these values into the formula, we find T = 2π√(1.503/9.8) ≈ 2.467 s. Therefore, the period of the pendulum is approximately 2.467 seconds.
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Can anyone tell me what concept of physics acts on snowboarders during the olympics big air jump
Answer:
gravity,lift and dragExplanation:
hope it helpsA hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) What was the photon's energy (in eV)? _________eV (b) Later, the atom returns to the ground state, emitting one or more photons in the process. Which of the following energies describes photons that might be emitted thus? (Select all that apply.) O 1.89 ev O 12.1 eV O 10.2 ev O 13.6 ev
A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.
To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:
E = -13.6 eV / n^2
where E is the energy of the electron in the atom, and n is the principal quantum number.
(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:
ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)
Calculating the value of ΔE:
ΔE = -13.6 eV / 9 + 13.6 eV
= -1.51 eV
Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).
(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.
ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV
ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV
ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV
ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV
ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV
ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV
ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV
Comparing the calculated energy differences with the given options:
(A) 1.89 eV: This energy difference does not match any of the calculated values.
(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.
(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.
(D) 13.6 eV: This energy difference does not match any of the calculated values.
Therefore option B and C are correct.
To learn more about principal quantum number visit: https://brainly.com/question/2292596
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A squirrel travels from one tree top to another. the distance between tree tops is 30 m and takes the squirrel 8 s to travel. What is the speed of the squirrel?
Answer:
3.75
Explanation:
Because when we use the formula S=D/T to find speed it will end up being
S= 30/8 because 30m is the distance and 8 s is the time.
Hoped I helped-
Sleepy~
btw we should talk sometime-
:>
Question 1
1 points)
Will any two objects dropped from the same height hit the ground at the same time if air resistance is not a
factor?
A) scientific
B) non-scientific