Answer:
6.3 rev/s
Explanation:
The new rotation rate of the satellite can be found by conservation of the angular momentum (L):
\( L_{i} = L_{f} \)
\( I_{i}*\omega_{i} = I_{f}*\omega_{f} \)
The initial moment of inertia of the satellite (a solid sphere) is given by:
\( I_{i} = \frac{2}{5}m_{s}r^{2} \)
Where \(m_{s}\): is the satellite mass and r: is the satellite's radium
\( I_{i} = \frac{2}{5}m_{s}r^{2} = \frac{2}{5}1900 kg*(4.6 m)^{2} = 1.61 \cdot 10^{4} kg*m^{2} \)
Now, the final moment of inertia is given by the satellite and the antennas (rod):
\( I_{f} = I_{i} + 2*I_{a} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}m_{a}l^{2} \)
Where \(m_{a}\): is the antenna's mass and l: is the lenght of the antenna
\( I_{f} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}150.0 kg*(6.6 m)^{2} = 2.05 \cdot 10^{4} kg*m^{2} \)
So, the new rotation rate of the satellite is:
\( I_{i}*\omega_{i} = I_{f}*\omega_{f} \)
\(\omega_{f} = \frac{I_{i}*\omega_{i}}{I_{f}} = \frac{1.61 \cdot 10^{4} kg*m^{2}*8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kg*m^{2}} = 6.3 rev/s\)
Therefore, the new rotation rate of the satellite is 6.3 rev/s.
I hope it helps you!
Which ray diagram demonstrates the phenomenon of absorption?
An illustration with a vector pointed right going through an opening in a boundary and splitting into 3 vectors. One up and to the right, one straight and one down to the right.
An illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side.
An illustration with a vector striking a boundary at an angle and a second vector coming off the boundary at the exact same angle.
Answer:
B
Explanation:
on edge
The illustration with a vector pointed right going through an opening in a boundary and turning into a transverse wave on the other side demonstrates the phenomenon of absorption, so, option B is correct.
What is absorption?Absorption, in wave motion, is the process by which a wave's energy is transferred to matter when the wave travels through it. The energy of an electromagnetic, acoustic, or other wave is related to the square of its amplitude, which is the maximum displacement or movement of a point on the wave.
The amplitude of a wave continuously diminishes as it travels through a substance. The medium is described as being transparent to a specific type of radiation if just a tiny portion of the energy is absorbed, whereas it is described as opaque if all the energy is lost.
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12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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Which of the following is NOT a correct statement?*
As the volume of a contained gas increases, the pressure in the container will
decrease.
As the temperature decreases, the kinetic energy of the particles decreases.
As pressure increases with a constant temperature, the volume decreases.
O As temperature increases, the kinetic energy of the particles decreases.
AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:
Explanation:
Determine the reduction in volume when the temperature of 0.5 litre ofethyl alcohol is reduced from 40 °C to -15 °C.
Answer:
It is reduced to 0.41L
Explanation:
The volume and temperature have a directly proportional relationship. So, we can write the following equation
\(\frac{V_2}{V_1}=\frac{T_2}{T_1}\)Now, we need to convert the temperatures 40 °C and -15 °C to kelvin, so
40°C + 273.15 = 313.15 K
-15 °C + 273.15 = 258.15 K
Then, we can replace the values as
\(\frac{V_2}{0.5\text{ L}}=\frac{258.15\text{ K}}{313.15\text{ K}}\)Solve for V2
\(\begin{gathered} V_2=\frac{258.15K}{313.15K}\cdot0.5L \\ V_2=0.41L_{}_{} \end{gathered}\)Therefore, the volume is reduced from 0.5 L to 0.41 L
Which choice is the best description of a well-defined, testable question for a science experiment?
The scientist has created questions for people to answer after they read about the science investigation.
The question is clearly stated, the question can be tested in an experiment, and the results can be measured.
The words are all defined in a glossary and a test can be given to see what students learned.
An experiment can be completed to help define the meaning of scientific words and phrases.
The best description of a well-designed testable question is "The question is clearly stated, the question can be tested in an experiment, and the results can be measured".
What is a scientific question?This type of question is the one that focuses on facts and aims at testing a hypothesis.
What are the features of a scientific question?Some features include:
The question is clear as it lets the reader know the phenomenon being studied.The question can be tested which means it is based on a phenomenon that can be studied through exact instruments.The results can be measured, which means the question leads to evidence.Learn more about science in: https://brainly.com/question/935949
Answer:
b
Explanation:
are recent changes in solar radiation strongly correlated with earth's temperature? group of answer choices
No, recent changes in solar radiation are not correlated with the earth's temperature.
Seasonal temperatures of sites at various latitudes are influenced by the angle of incoming solar radiation. The incoming solar energy is more direct (almost perpendicular or closer to a 90° angle) when the sun's rays hit the surface of the Earth close to the equator. Warmer temperatures result from solar radiation being concentrated over a smaller surface area.
Higher latitudes have narrower solar radiation angles, which spread energy across a broader region of the surface and result in cooler temperatures. Surface temperatures are typically warmer at lower latitudes and cooler at higher latitudes because the angle of radiation varies with latitude (even though higher latitudes have more hours of daylight during the summer months).
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1. What is the potential energy of a 5.0-kg
object located 2.0 m above the ground?
A. 2.5 J
C. 98 J
B. 10 J
D. 196 J
Answer:
C. 98 J
Explanation:
The appropriate formula is ...
PE = mgh . . . . . m is mass; below, m is meters
PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2
PE = 98 J
Work
Can be summarized as an equation.
W = Fd
W = work F = force d = distance
Measured in J Measured in N Measured in m
Example #1: You move a 75 kg refrigerator 35 m.
This requires a force of 90 N. How much work, in
joules, was done while moving the refrigerator?
Pls help !!
What must be the same for two resistors that are connected in parallel?
OA. The resistance of each
OB. The voltage drop across each
OC. The power used by each
OD. The current in each
Answer
its c
Explanation:
When resistors are connected in parallel combination the voltage drop across each resistor is same. However , the total current gets branched into different amount .
Question :
— What must be the same for two resistors that are connected in parallel ?
AnswEr :
When the two resistors are connected in parallel therefore , the Voltage drop across each resistors will be same .Option B seems to be correct answer .
An object moving with uniform acceleration has a velocity of 10.5 cm/s in the positive x-direction when its x-coordinate is 2.72 cm. If its x-coordinate 2.30 s later is ?5.00 cm, what is its acceleration? The object has moved to a particular coordinate in the positive x-direction with a certain velocity and constant acceleration; then it reverses its direction and moves in the negative x-direction to a particular x-coordinate in time t. We are given an initial velocity vi = 10.5 cm/s in the positive x-direction when the initial position is xi = 2.72 cm (t = 0). We are given that at t = 2.30 s, the final position is xf = ?5.00 cm. The acceleration is uniform so that we have the following equation in terms of the constant acceleration a. Xf-Xi=Vit-1/2at^2 Now we substitute the given values into this equation. (___cm)-(___cm)=(___cm/s)(__s)+1/2a(___s)
Answer:
Acceleration = 8.27 cm/s²
Explanation:
We are given;
initial velocity; v_i = 10.5 cm/s
Initial position; x_i = 2.72 cm
Time; t = 2.30 s
final position; x_f = 5.00 cm
To find the acceleration, we will make use of the formula;
x_f - x_i = (v_i * t) - (½at²)
Plugging in the relevant values, we have;
5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)
2.28 = 24.15 - 2.645a
24.15 - 2.28 = 2.645a
2.645a = 21.87
a = 21.87/2.645
a = 8.27 cm/s²
A car speeds up from 45 mph to 65mph to pass a truck.if this requires 6s. What is the average acceleration of the car
Answer: the average acceleration of the car is 3.33 mph/s.
Explanation:
To find the average acceleration of the car, we can use the formula:
average acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity of the car is 45 mph, the final velocity is 65 mph, and the time taken to reach the final velocity is 6 seconds.
Substituting these values in the formula, we get:
average acceleration = (65 mph - 45 mph) / 6 s
average acceleration = 20 mph / 6 s
average acceleration = 3.33 mph/s (rounded to two decimal places)
Therefore, the average acceleration of the car is 3.33 mph/s.
Answer:
110
Explanation:
45+65=110
HELP PLEASE THIS IS URGENT!!!
The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.
Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.
Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.
From the given,
X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two. ₐ₋₂Xᵇ⁻⁴ -----> ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.
When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay, ₐ₋₅Xᵇ⁻⁸ -----> ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.
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A neutron star has about one and a half times the mass of our Sun but has collapsed to a radius of 10 kmkm . Part A What is the acceleration due to gravity on the surface of this star in terms of the free-fall acceleration at Earth's surface?
Answer:
gₓ = 1.36 x 10¹³ g
Explanation:
The value of acceleration due to gravity at a certain place is given by the following formula:
gₓ = GM/R²
where,
gₓ = acceleration due to gravity on the surface of neutron star
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of the star = 10 * Mass of sun = (10)(2 x 10³⁰ kg) = 2 x 10³¹ kg
R = 10 km = 10⁴ m
Therefore,
gₓ = (6.67 x 10⁻¹¹ N.m²/kg²)(2 x 10³¹)/(10⁴)²
gₓ = 1.334 x 10¹⁴ m/s²
Hence, comparing it with the free-fall acceleration at Earth's Surface:
gₓ/g = (1.334 x 10¹⁴)/9.8
gₓ = 1.36 x 10¹³ g
The acceleration due to gravity on the surface of this star in terms of the free-fall acceleration at Earth's surface is \(1.35 \times 10^5 \ g_E\).
The given parameters:
Mass of the neutron star, m = 1.5 MRadius of the neutron star, R = 10 kmkmThe acceleration due to gravity on the surface of this star in terms of the free-fall acceleration at Earth's surface is calculated as follows;
\(F = mg = \frac{GM_sm}{R^2} \\\\(1.5 M_s)g = \frac{GM_s(1.5 M_s)}{R^2} \\\\g = \frac{GM_s}{R^2} \\\\\)
where;
\(M_s\) is the mass of the Sun = 1.989 x 10³⁰ kg.
\(g = \frac{6.67 \times 10^{-11} \times 1.989 \times 10^{30} }{(10,000,000)^2} \\\\g = 1.326 \times 10^{6} \ m/s^2\)
In terms of gravity of Earth \((g_E)\);
\(= \frac{1.326 \times 10^6}{9.81} = 1.35 \times 10^5 \\\\= 1.35 \times 10^5 \ g_E\)
Thus, the acceleration due to gravity on the surface of this star in terms of the free-fall acceleration at Earth's surface is \(1.35 \times 10^5 \ g_E\).
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Which of the following muscles acts synergistically to the rectus femoris during the upward movement phase of the low-bar back squat?
a) anterior tibialis
b) iliopsoas
c) biceps femoris
d) rectus abdominis
Biceps femoris muscles acts synergistically to the rectus femoris during the upward movement phase of the low-bar back squat.
What is biceps femoris?The posterolateral area of the thigh contains the biceps femoris muscle, which is located in the posterior compartment. Because it has both long and short heads of origin, the leg muscle known as the biceps femoris gets its name. In connection with the semitendinosus tendon of origin, the long head emerges from the medial facet of the ischial tuberosity. Movement at the hip and knee joints is controlled by the biceps femoris muscles.External rotation and thigh extension are made possible by the long head of the biceps femoris at the hip. Knee flexion and external rotation of the lower leg are made possible at the knee by the biceps femoris. So, Option c is correct.To learn more about muscles, refer:
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Describe Health and Exercise
Answer:
plenty of exercise
Explanation:
If you are unhealthy or not happy with yourself. try this. Do a 30 minute walk everyday and eat normal amounts of food portions a human should have an in a day. Make sure you drink plenty of water. If that doesn't work maybe taking to someone about it and see what information they have for you. These things do work because i was over weight and lost 73 pound just by doing those few things.
A point charge q1 has a magnitude of 3.5x10-6 C. A second charge q2 has a magnitude of -1.8x10-6 C and is located 0.15 m from the first charge. Determine the electrostatic force exerts on each other.
The electrostatic force exerts on each other is 1.134 N
Electrostatic force calculation.
The electrostatic force between the two charges is given by Coulomb's Law:
F = k * |q1| * |q2| / r^2
where k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2), |q1| and |q2| are the magnitudes of the two charges, and r is the distance between them.
Substituting the given values, we have:
F = (9.0 x 10^9 N*m^2/C^2) * (3.5 x 10^-6 C) * (1.8 x 10^-6 C) / (0.15 m)^2
F = 1.134 N
The electrostatic force exerted on each charge is equal in magnitude but opposite in direction, according to Newton's Third Law. Therefore, the magnitude of the force on each charge is 1.134 N, but they point in opposite directions. The force on q1 is attractive (toward q2), while the force on q2 is repulsive (away from q1).
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a constant force of magnitude F=45 N and making an angle of 30 to the horizontal is applied on a stationary block placed on the floor over a distance of 8 m. the work done by the force
The work done by the force on the block is approximately 311.2 Joules.
To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.
The horizontal component of the force can be calculated using trigonometry:
F_horizontal = F * cos(angle)
= 45 N * cos(30 degrees)
= 45 N * (√3 / 2)
≈ 38.9 N
Now, we can calculate the work done by the force using the equation:
Work = Force * Distance * cos(theta)
where theta is the angle between the force and the displacement.
Work = F_horizontal * Distance * cos(0)
= 38.9 N * 8 m * cos(0)
= 38.9 N * 8 m
= 311.2 Joules
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TRUE OR FALSE The sun has more gravity than the earth because it is more massive.
Energy of a wave is measured in terms of the wave's Choose... .
The energy of a wave is measured in terms of the wave's amplitude.
What is the energy of a wave?The energy of a wave depends on the amplitude and the frequency of of the wave.
The energy of a wave is directly proportional to the square of the wave's amplitude.
Mathematically, the formula for energy of a wave is given as;
E = ¹/₂μω²A²
where;
μ is the mass per unit length of the stringω is the angular velocity of the waveA is the amplitude of the waveE is the energy of the waveSo based on the formula given above, energy of a wave is proportional to the square of wave's amplitude and square of angular frequency of the wave.
Thus, we can conclude that the energy of a wave is measured in terms of the wave's amplitude because the energy of the wave is function of maximum displacement of the wave (wave amplitude).
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HELP ASAP!
Everything on screenshot.
Answer:
I believe the answer is sea floor spreading
How long did it take me to make this?
Answer:
Its according from what it is made with if wax it takes longer but if with a craft paper it takes lesser time if paper approximately 20 to 25 minutes
4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
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A toy car's movements is measured using photogates.
Answer:
a) the velocity increases then decreases.
Which statement about an atom is correct
The efficiency of a machine is 80%? What does it mean?
Answer:
It means how much input work you put into the machine, which then becomes output from the machine. So you're putting 80% of work into the machinie. To find the efficency of a machine, it's output divided by input work.
Explanation:
Answer:
efficiency is the ratio of the power ouput to the power input
Explanation:
It compares how much energy is used to do work versus how much is lost or wasted to the environment, the more efficient the machine, the less energy wasted.
If all pairs of adjacent sides of a quadrilateral are congruent then it is called _________.
(A) rectangle (B) parallelogram (C) trapezium, (D) rhombus
Answer:
D
Explanation:
If you need an explanation feel free to ask.
Consider a block sliding down a ramp whose motion is opposed by frictional forces. The total energy of this system is modeled by the equation:
Etotal = 1/2mv^2 + mgh + Ff(f is underscore)d
Which part of the equation represents the amount of energy converted to thermal energy?
A. mg
B. Ffd
C. mgh
D. 1/2 mv^2
Answer:
Energy Flows Quick check answers:
1. Ffd.
2. The kinetic energy decreases, and gravitational potential energy increases.
3. The internal energy of the system increases.
4. KEbox= Etotal-mgh
5. Etotal = 1/2m1(v1)^2+1/2m^2(v2)^2+U
The part of the equation that represents the amount of energy converted to thermal energy is \(F_f d\).
The given equation for the total energy of a system;
\(E_{total} = \frac{1}{2} mv^2 \ +\ mgh\ + \ \ F_fd\)
The definition of the various terms in the energy equation is given as;
\(E_{total}\): this is the total mechanical energy of the system\(\frac{1}{2} mv^2\): this is the kinetic energy of the system\(mgh\): this is the potential energy of the system\(F_f d\): this is the energy lost due to friction.The energy lost due to friction is equal to the energy converted to thermal energy.
Thus, the part of the equation that represents the amount of energy converted to thermal energy is \(F_f d\).
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based on this, which of the following materials would your state need in large quantities to expand future biopower production?
In order to expand future biopower production, states would need to acquire large quantities of biomass materials such as wood and agricultural crops like corn, switchgrass, and other grasses.
These materials are used in the production of biofuels, which is a type of renewable energy generated from organic matter. Biomass materials are typically converted into liquid fuels such as ethanol or biodiesel for use in vehicles, or burned for electricity generation. Additionally, states may need to acquire large quantities of organic waste materials like animal manure and food scraps for use in anaerobic digestion systems that generate biogas. Biogas is a type of renewable energy that can be used to produce electricity or heat.
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In the blanks below write what the independent variable and the dependent variable would be for each experiment. (what are you testing?) (how are you measuring it?) Independent variable Dependent variables
1. Problem: Does the amount you study a subject affect the scores you get on a test? Independent variable ____did you study_ Dependent variable ___higher test scores_
2. Problem: Does misbehaving in school affect a student’s grades? Independent variable _____________________ Dependent variable _______________________
3. Problem: What gives people more gas; eating beans or cabbage? Independent variable _____________________ Dependent variable _______________________
4. Problem: Can you catch more fish with worms or with shrimp? Independent variable _____________________ Dependent variable _______________________
5. Problem: Does talking to plants help increase their growth? Independent variable _____________________ Dependent variable _______________________ 6. Problem: Does eating breakfast help students perform better in school? Independent variable _____________________ Dependent variable _______________________ 7. Do gerbils or hamsters run faster? Independent variable _____________________ Dependent variable _______________________ 8. Problem: Does eating more candy cause cavities? Independent variable _____________________ Dependent variable _______________________
9. Problem: What diet will allow you to lose the most weight, no sugar or no carbs? Independent variable _____________________ Dependent variable _______________________
10. Problem: What, on average, is larger, a chicken egg or a duck egg? Independent variable _____________________ Dependent variable _______________________
Answer:
1. independent- if you studied. dependent- test scores
2. independent- behavior of students. dependent-student grades
3. independent- what you eat. dependent- amount of gas
4. independent- which bait you use. dependent- how much fish you catch
5. independent-if you talk to the plants or not. dependent- growth
6. independent- whether you eat breakfast or not. dependent-student performance
7. independent- which animal you test. dependent- speed of the animals
8. independent- how much candy you eat. dependent- cavities or not
9. independent- if you eat no sugar or no carbs. dependent- how much weight you lose
10. independent- which thing you measure. dependent- the measurements