A satellite with a mass of 200 kg fires its engines to increase velocity, therebyincreasing the size of its orbit about Earth. As a result, it moves from acircular orbit of radius 7.5 × 106 m to an orbit of radius 7.7 x 106 m. What isthe approximate change in gravitational force from Earth as a result of thischange in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kgand G = 6.67 x 10-¹1 N-m²/kg².)A. -59 NB. -112 NC. -73 ND. -32 NSUBMIT
Answers
Given:
The mass of the satellite is m = 200 kg
The initial radius of the circular orbit is
\(r_i=7.5\times10^6\text{ m}\)The final radius of the circular orbit is
\(r_f=7.7\times10^6\text{ m}\)The mass of the earth is
\(M=5.97\times10^{24}\text{ kg}\)Also, the gravitational constant is
\(G=\text{ 6.67}\times10^{-11}\text{ N m}^2\text{ /kg}^2\)To find the approximate change in gravitational force.
Explanation:
In order to calculate the approximate change in the gravitational force, we have to find the difference between the initial and final gravitational forces.
The initial gravitational force can be calculated as
\(\begin{gathered} F_i=\frac{GmM}{(r_i)^2} \\ =\frac{6.67\times10^{-11}\times200\times5.97\times10^{24}}{(7.5\times10^6)^2} \\ =\text{ 1415.82 N} \end{gathered}\)The final gravitational force can be calculated as
\(\begin{gathered} F_f=\frac{GmM}{(r_f)^2} \\ =\frac{6.67\times10^{-11}\times200\times5.97\times10^{24}}{(7.7\times10^6)^2} \\ =1343.23\text{ N} \end{gathered}\)The approximate change can be calculated as
\(\begin{gathered} \Delta F=F_f-F_i \\ =1343.23-1415.82 \\ =-72.6\text{ N} \\ \approx-73\text{ N} \end{gathered}\)Final Answer: The approximate change in the gravitational force is -73 N
Related Questions
why is jupiter made of the same elements as the sun but is only considered a planet
Answers
Answer:
The ancient Greeks counted the Earth's Moon and Sun as planets along with Mercury, Venus, Mars, Jupiter, and Saturn. Earth was not considered a planet, but rather was thought to be the central object around which all the other celestial objects orbited. ...... Jupiter is composed of gases — hydrogen and helium, mostly — all ... the largest planet in the solar system, the gas giant just doesn't have ... But unlike the sun, it lacks the necessary amount to begin fusion, the process that fuels a star. ... to 80 times more massive than it is at present to be considered a star.
In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Help me out please. It’d be greatly appreciated
Answers
Answer:
Option D
2Na + Cl₂ —> 2NaCl
Explanation:
We'll begin by stating the law of conservation of matter.
The law of conservation of matter states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
For an equation to comply with the law of conservation of matter, the number of atoms of each element must be the same on both side of the equation. This simply means that the equation must be balanced!
NOTE: An unbalanced equation simply means matter has been created or destroyed.
Now, we shall determine which equation is balanced. This can be obtained as follow:
For Option A
Na + Cl₂ —> 2NaCl
Reactant:
Na = 1
Cl = 2
Product:
Na = 2
Cl = 2
Thus, the equation is not balanced!
For Option B
2Na + 2Cl₂ —> 2NaCl
Reactant:
Na = 2
Cl = 4
Product:
Na = 2
Cl = 2
Thus, the equation is not balanced!
For Option C
2Na + Cl₂ —> NaCl
Reactant:
Na = 2
Cl = 2
Product:
Na = 1
Cl = 1
Thus, the equation is not balanced!
For Option D
2Na + Cl₂ —> 2NaCl
Reactant:
Na = 2
Cl = 2
Product:
Na = 2
Cl = 2
Thus, the equation is balanced!
From the above illustrations, only option D has a balanced equation. Thus, option D illustrate the law of conservation of matter.
Mae puts on her new winter scarf. Signals are sent to her brain telling her that the scarf is soft. Which sense provides her brain with this information?
Answers
Answer:
Touch
Explanation:
Consider two identical objects of mass m = 0.250 kg and charge q = 4.00 μC. The first charge is held in place at the origin of a coordinate system, unable to move at all times. The second object is initially placed 3.00 cm along the positive x-axis and is free to move. The moment the second object is released at x = 3.00 cm, what is the acceleration of this second object? This experiment is done far away from other massive objects, in outer space.
Answers
Answer:
a = 640 m/s²
Explanation:
From work-kinetic energy principles,
The net force acting on the second object is the gravitational force and the electric force due to the first object.
So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²
Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²
The net Force F = ma
So, -F₁ + F₂ = F (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)
-Gm²/r² + kq²/r² = ma
ma = -Gm²/r² + kq²/r²
a = (-Gm²/r² + kq²/r²)/m
a = (-G + kq²/m²)m/r²
Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.
Substituting the variables into the equation, we have
a = (m/r²)(-G + k(q/m)²)]
a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)
a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]
a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]
a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg² ]
a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)
a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²
a = 0.064 × 10⁴N/kg
a = 64 × 10 N/kg)
a = 640 m/s²
1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.
2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?
3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?
4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.
Answers
1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.
3. The cost of electricity from the automobile battery is 38.6 cents per kWh.
4. The current that would be carried through the body is 0.8 mA if dry.
1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.
Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.
3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.
Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.
4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.
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If you drop a rock from 700 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)
Answers
Answer:
it would be 11.95 seconds
Explanation:
sorry for saying i did not know
When is a field study more appropriate that a laboratory experiment? Give a specific example.
Answers
A field study is more appropriate that a laboratory experiment when we need to know the real mining of unknown variables in a given outcome such as for example dark matter in space.
What are unknown variables in science?Unknown variables in science can be defined as variables that have yet to be identified or studied, either due to a lack of data or unknown factors.
Therefore, with this data, we can see that unknown variables in science such as the amount of Dark matter in the Universe are able to be shown by field (observational) studies.
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What are 5 examples of steong forces and what are 5 examples of weak forces. Thx!
Answers
Answer: The Strong Nuclear Force is an attractive force between protons and neutrons that keep the nucleus together and the Weak Nuclear Force is responsible for the radioactive decay of certain nuclei.
Explanation:
A person is dragging a crate over a shag carpet with a push force of 10N. The shag rug creates a friction force of 5N. The mass of the crate is 5 k
g. Calculate the acceleration of the crate?
(Just enter the numbers, no
Answers
The acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
What is acceleration?Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.
The acceleration of the crate is calculated from the net force acting on the crate as shown below;
F(net) = applied force - frictional force
F(net) = 10 N - 5N
F(net) = 5 N
Apply Newton's second law of motion to calculate the acceleration of the crate.
F(net) = ma
where;
m is mass of the cratea is acceleration of the cratea = F(net) / m
a = 5/5
a = 1 m/s²
Thus, the acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
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A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A that splits at point B and attaches to the ship at points C and D. The two rope segments BC and BD angle away from the center of the ship at angles of ϕ = 26.0 ∘ and θ = 21.0 ∘, respectively. The tugboat pulls with a force of 1200 lb . What are the tensions TBC and TBD in the rope segments BC and BD?
Answers
Answer:
The tensions in \(T_{BC}\) is approximately 4,934.2 lb and the tension in \(T_{BD}\) is approximately 6,035.7 lb
Explanation:
The given information are;
The angle formed by the two rope segments are;
The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°
The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°
Therefore, we have;
The tension in rope segment BC = \(T_{BC}\)
The tension in rope segment BD = \(T_{BD}\)
The tension in rope segment AB = \(T_{AB}\) = Pulling force of tugboat = 1200 lb
By resolution of forces acting along the line A_F gives;
\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = \(T_{AB}\) = 1200 lb
\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb............(1)
Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;
\(T_{BC}\) × sin(26.0°) + \(T_{BD}\) × sin(21.0°) = 0...........................(2)
Which gives;
\(T_{BC}\) × sin(26.0°) = - \(T_{BD}\) × sin(21.0°)
\(T_{BC}\) = - \(T_{BD}\) × sin(21.0°)/(sin(26.0°)) ≈ - \(T_{BD}\) × 0.8175
Substituting the value of, \(T_{BC}\), in equation (1), gives;
- \(T_{BD}\) × 0.8175 × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb
- \(T_{BD}\) × 0.7348 + \(T_{BD}\) ×0.9336 = 1200 lb
\(T_{BD}\) ×0.1988 = 1200 lb
\(T_{BD}\) ≈ 1200 lb/0.1988 = 6,035.6938 lb
\(T_{BD}\) ≈ 6,035.6938 lb
\(T_{BC}\) ≈ - \(T_{BD}\) × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb
\(T_{BC}\) ≈ -4934.1733 lb
From which we have;
The tensions in \(T_{BC}\) ≈ -4934.2 lb and \(T_{BD}\) ≈ 6,035.7 lb.
What is the function of the slip rings in an electric generator?
Answers
Answer:
Explanation:
Slip rings function to pass an electric current across an interface where one side is rotating while the other side is fixed.
C. producing a path for current to flow
EDG
You decide to make one of the world’s largest musical instruments, using long cylindrical steel rods that are clamped tightly at both ends. The speed of longitudinal waves in rods of the type of steel you use is 5068 m/s and the steel has a Young’s modulus of 199 GPa.
Required:
a. What is the density of the steel, in kilograms per cubic meter?
b. When a longitudinal wave is excited in one of the steel rods in your instrument to produce resonance, will the rod’s ends be nodes or antinodes?
c. A standard frequency for tuning musical instruments is 440 Hz for the pitch of A above middle C, denoted A4. What is the length, in meters, of the steel rod that produces the pitch A4 as its fundamental longitudinal resonance?
d. Assume, instead, that you want to create a smaller version of this, using the same kind of construction, with one rod of length 9.5 cm. What would the fundamental longitudinal resonance frequency of that rod be, in hertz, with the same longitudinal wave speed as above, 5149 m/s?
Answers
Answer:
Explanation:
speed of longitudinal wave in a rod = \(\sqrt{\frac{Y}{D} }\)
Where Y is young's modulus of elasticity and D is density .
Putting given data
5068 = \(\sqrt{\frac{199\times 10^{9}}{D} }\)
D = 199 x 10⁹ / .2568 x 10⁸
= 7749 kg / m³
b )
Rod's ends are not to vibrate as they are clamped . So node is produced there .
c )
Frequency = 440 Hz
Note = fundamental
l = λ / 2 , l is length of rod and λ is wavelength
wavelength of 440 Hz note
= velocity of sound / frequency
= 5068 / 440
= 11.518 m
l = 11.518 / 2
= 5.76 m .
Length of rod = 5.76 m
d )
l = .095 m
velocity = 5149 m /s
wavelength = 2l
= 2 x .095 m
= .19 m
frequency = velocity / wavelength
= 5149 / .19
= 27100 Hz .
In this exercise we have to use the density knowledge to calculate the wave speed, like this:
A)\(D=7749 kg/m^3\)
B) Have node.
C) \(L = 5.76 m\)
D) \(f= 27100 Hz\)
So knowing that from the data informed by the statement we find that:
A) First we have to calculate the density as:
\(D = 199 * 10^9 / 0.2568 * 10^8\\D= 7749 kg / m^3\)
B) Rod's ends are not to vibrate as they are clamped.
C) Second we have to calculate the length as:
\(Length= velocity \ of \ sound / frequency\\= 5068 / 440\\= 11.518 m\\L= 11.518 / 2\\L= 5.76 m\)
D) Third we have to calculate the frequency as:
\(wavelength = 2L\\= 2 * 0.095 m\\=0 .19 m\\frequency = velocity / wavelength\\= 5149 / 0.19\\f= 27100 Hz .\)
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Which force is a noncontact force?
(15 points)
A.
magnetic force
B.
frictional force
C.
normal force
D.
impact force
Answers
Answer:
Magnetism is an example of a non-contact or action-at-a-distance force. These are forces which can act on an object without being in physical contact with it. The force of gravity is another example. Thus, gravity will pull a raindrop down to Earth without any tangible physical link between the Earth and the drop.
Explanation:
hope this helps u, sorry if it doesn't.
Answer:
Magnetic force
Explanation:
It would be this because all of th other forces are touching the object to make it move or somhting like that, the only one that makes it move by not touching it would be the magnetic force,
Hope this helps
The mass of an empty cylindrical tin is
proportional to its surface area.
Two empty cylindrical tins, G and H, are
shown below.
The mass of tin G is 72 g, and the surface
area of tin H is 792π cm².
2
a) Work out the total surface area of tin G in
terms of π.
b) Work out the mass of tin H.
Tin G
12 cm
5 cm
Tin H
Not drawn accurately
Answers
a) The total surface area of tin G in terms of π is 170π cm².
b) The mass of tin H is 336 g.
To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.
a) Total surface area of tin G in terms of π:
The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:
Lateral surface area = 2πrh
where r is the radius of the base and h is the height of the cylinder.
In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:
Lateral surface area = 2π(5 cm)(12 cm)
Lateral surface area = 120π cm²
Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:
Area of a circle = πr²
The radius of the circular base of tin G is 5 cm, so the area of each circular base is:
Area of each circular base = π(5 cm)²
Area of each circular base = 25π cm²
To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:
Total surface area of tin G = Lateral surface area + 2 × Area of each circular base
Total surface area of tin G = 120π cm² + 2 × 25π cm²
Total surface area of tin G = 120π cm² + 50π cm²
Total surface area of tin G = 170π cm²
Therefore, the total surface area of tin G in terms of π is 170π cm².
b) Mass of tin H:
We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:
(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)
Using the given values, we have:
(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)
Cross-multiplying and solving for the mass of tin H, we get:
(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)
mass of tin H = (72 g) × (792π cm²) / (170π cm²)
mass of tin H = 336 g
Therefore, the mass of tin H is 336 g.
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200 g of water is heated and its temperature goes from 280 K to 300 K. What was the change in temperature for this process?
A. 280 K
B. 20 F
C. 20 K
D. 300 K
Answers
The change in temperature is 20 kelvin
What is Temperature?
Temperature can simply be described as how hot or how cold an object is at a particular period in time. The unit of temperature is Kelvin.
The formula for calculating change in temperature is
Final temperature - Initial temperature
Final temperature = 300 kelvin
Initial temperature= 280 kelvin
Change in temperature= 300-280
= 20 kelvin
Thus the change in temperature for this process is 20 kelvin
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Can a naturalized citizen serve as President/Vice President?
Answers
Answer:
No
Explanation:
I read a lesson about this yesterday, the president has to be naturally born in the US and has to live there for some years (30 I think?)
Answer:
The U.S. Constitution requires that a candidate for president or vice president must have been born in the United States or otherwise a “natural born citizen.” Controversies have arisen in U.S. history from time to time as to who is “natural born” and therefore eligible to be president. Furthermore, with so many foreign-born citizens living in the United States, many people believe this constitutional requirement itself should be changed.
Explanation:
What does gravitational potential energy depend on?; What three things does gravitational potential depend on?; Does the gravitational potential energy of an object depends on the path?
Answers
The Gravitational potential energy depends on mass , acceleration and path and potential also as G=V/m.
a). As you can imagine, gravitational energy is the energy associated with gravity. This is the potential energy stored due to an object being in a higher position compared to a lower position. (e.g. far from the ground or close to the ground).
Gravitational energy is the energy associated with gravity.
b). Systems can increase their gravitational energy as their mass moves away from the center of the Earth and away from other bodies (such as the sun, planets, and stars) large enough to generate a large amount of gravity. there is.
Potential energy can be defined as the amount of work expended to lift an object from the ground to its current height. In another sense, this is the amount of work the body does before returning to ground level (the position of maximum stability) when translated from its current level. Therefore, potential energy can be related to work.
c). A negative sign indicates that gravity is doing positive work as the mass approaches. A negative potential indicates a bonding state. That is, when mass is placed under its influence, it becomes trapped in its potential, and if something can provide the energy to escape the clutches of gravity, it must not escape.
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Calculate the average acceleration when a vehicle is moving with a velocity from 3 m / s to 5 m / s in a time interval from 4 s to 6 s .
Answers
ANSWER
\(1m/s^2\)EXPLANATION
The average acceleration of a body is the change in velocity divided by the change in time. That is:
\(a=\frac{v_2-v_1}{t_2-t_1}\)Therefore, the average acceleration of the vehicle is:
\(\begin{gathered} a=\frac{5-3}{6-4}=\frac{2}{2} \\ a=1m/s^2 \end{gathered}\)Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?
(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.
Answers
Hi there!
We can begin by identifying key characteristics of both graphs.
Graph A.
Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).
We also know that:
\(T = 2\pi \sqrt{\frac{m}{k}}\)
We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.
Graph B.
The amplitude is 20 cm (0.2 m), and each period is 4 seconds.
We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.
For the other choices, we must look at forces and work.
Recall that:
Spring potential energy = \(\frac{1}{2}kx^2\)
Kinetic energy = \(\frac{1}{2}mv^2\)
Using the work-energy theorem:
\(\frac{1}{2}kx^2 = \frac{1}{2}mv^2\)
Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.
Using Hooke's Law:
\(\Sigma F = -kx\\\\ma = -kx\\\)
\(a = \frac{-kx}{m}\)
If the mass is greater, the acceleration will be smaller. Choice D is correct.
How many significant figures are in the number 17.95?
Answers
Answer:
4
Explanation:
All of them are significant figures
Heather and Jerry are standing on a bridge 46 m
above a river. Heather throws a rock straight down with a speed of 14 m/s
. Jerry, at exactly the same instant of time, throws a rock straight up with the same speed. Ignore air resistance. How much time elapses between the first splash and the second splash?
Answers
The time elapsed between the first splash and the second splash is approximately 0.69 seconds.
To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.
We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.
For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).
Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.
Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.
For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.
Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.
To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.
Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.
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1800 kg object was moving to the east at 13 m/s, collided with a 200 KG object that was moving to the north at 32 m/s. What was the magnitude of the velocity after the collision assuming it was inelastic
Answers
1. How much work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the
lungs?
Answers
W=Fd
2- state the given
F=180N d=0.3 m
3- plug in and solve
W=Fd
W=(180)(0.3)
W=39 j
Work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the lungs 39 joule.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
Work = force x distance. In units, Joules = Newtons x meters.
W = F.d
F = 180 N d=0.3 m
W = F.d
W = (180)(0.3)
W = 39 j
Work does the human heart do if it uses 180 N of force to pump blood 0.3 meters to the lungs 39 joule.
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What is the relationship between the type of energy sublevels present and the
principal energy level?
Answers
What is my acceleration when I travel at a constant speed of 10 m/s for 50 seconds on a straight street?
Answers
Answer:
there is no acceleration
Explanation:
acceleration only occurs when the speed changes for example if you were to start at 10m/s and after ten seconds be at 50m/s then there would be acceleration but because speed is constant there is no acceleration
6.1 62 6.3 64 quency of sound waves emitted by a stationary source. the relationship between the observed frequency and the The learner moves towards the source at a constant velocity and records the observed frequency (f) for a given source frequency (fs). This process is repeated for different frequencies of the source, with the learner moving at the same constant velocity each time The graph below shows how the observed frequency changes as the frequency of sound waves emitted by the source changes. fL (Hz) fs (Hz) Name the phenomenon illustrated by the graph Name ONE application in the medical field of the phenomenon in QUESTION 6.1. O Write down the type of proportionality that exists between f and fs, as illustrated by the graph. The gradient of the graph obtained is found to be 1,06. (1) of the
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The highlighted phenomenon in the graph is called the Doppler effect, which involves a modification of frequency for sound waves (or any kind of wave) due to the difference in motion between the observed and the source.
How to explain the effectAn example of this effect present in the medical field is through ultrasound imaging; doctors use it to measure the velocity and route of blood circulating throughout the patient's body by sending out high-frequency sound waves and analyzing the reflected waves.
What appears in the graphed illustration specifically is linear proportionality, meaning that there is a direct correlation between f and fs, the former being the observed frequency and the latter the source frequency.
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Scott drives a jeep 12 km east, then 4 km north, then finally 3 km west. He traveled a total distance of:
Answers
Answer:
Using the pythagoras theorem
S²=9²+4²
S²=81+16
S²=97
S=9.85km.
In finding the direction
tan□=opposite/Adjacent
=4/9
□=23.96
¤=90-23.96
=66.03 degrees
9.85, N 66.03 E
Can a conductor be given limitless charge
Answers
Answer:
No
Explanation:
You could try to give it enough to fill all valence electrons in all of the atoms in the conductor, but practically this could not be achieved.
If a car is traveling at an average speed of 20 m/s, how long will it take to travel 500 meters?
A. 0.04 seconds
B. 25 seconds
C. 520 seconds
D. 10,000 seconds
Answers
Answer:
B. 25 seconds
Explanation:
500÷20=25
B.25 seconds