The energy changes that occur when the small aeroplane with a mass of 600kg is working and powered by fuel cells that use hydrogen gas are:
chemical --> electrical --> kinetic
This means that the fuel cells convert the chemical energy of the hydrogen gas into electrical energy, which is then used to power the electric motor of the aeroplane, resulting in the generation of kinetic energy that propels the aeroplane forward.
Therefore, the energy transformations that occur in this scenario are from chemical energy to electrical energy, and then from electrical energy to kinetic energy.
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Air is about 78.0% nitrogen molecules and 21.0% oxygen molecules. Several other gases make up the remaining 1% of air molecules. What is the partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm?
The atmospheric pressure of a gas is proportional to the number of gas molecules present in the system. The partial pressure is calculated from the total pressure of a mixture of gases by multiplying the mole fraction of a specific gas in the mixture by the total pressure.
The equation for calculating partial pressure is as follows: Partial pressure = Mole fraction x Total pressureHere, we are required to find the partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm. The nitrogen in air is approximately 78%, while the remaining 21% is oxygen.
The remaining 1% is made up of several other gases. It implies that the total mole fraction of nitrogen in the air is 0.78. Mole fraction is the ratio of the number of moles of one component to the total number of moles of all components in the mixture.
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The partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm is calculated by multiplying the total atmospheric pressure by the gas's percent content in the mixture. Using this formula results in a partial pressure of approximately 0.6552 atm for nitrogen.
Explanation:The partial pressure of a gas in a mixture can be determined using the formula P = (Patm) X (percent content in mixture). The total atmospheric pressure (Patm) is the sum of all the partial pressures of the gas components added together. In the case of nitrogen in the air, which makes up about 78.0% of the content, the partial pressure can be calculated as follows:
P = (0.84 atm) X (78.0%)
Converting the percentage to a decimal ratio gives, P = (0.84 atm) X (0.780)
Therefore, the partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm would be approximately 0.6552 atm.
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Select all the correct answers.
Andrew walks through his garden and observes that the shapes of dewdrops are not always the same. Suppose he wants to investigate using the scientific method. Which questions are testable questions that he can ask to look into the reasons for the different shapes?
Does the shape of the dewdrop depend on the temperature of the surface?
Which dewdrop seems to have the most unusual shape?
Is the material of the surface responsible for the shape of the dewdrop?
Which shape of dewdrop is the most pleasing to the observer?
Does the shape of the dewdrop depend on the moisture in the atmosphere?
The following questions are testable questions that Andrew can ask to investigate the reasons for the different shapes of dewdrops:
Does the shape of the dewdrop depend on the temperature of the surface?
Is the material of the surface responsible for the shape of the dewdrop?
Does the shape of the dewdrop depend on the moisture in the atmosphere?
The scientific method involves asking testable questions, formulating hypotheses, conducting experiments or observations, and drawing conclusions based on the evidence gathered. Testable questions are those that can be investigated through empirical evidence and experimentation.
Let's analyze each of the provided questions:
Does the shape of the dewdrop depend on the temperature of the surface?
This question is testable because Andrew can perform experiments by varying the temperature of different surfaces and observing the resulting shapes of dewdrops. He can control the temperature and measure the corresponding dewdrop shapes to determine if there is a relationship.
Is the material of the surface responsible for the shape of the dewdrop?
This question is also testable. Andrew can compare dewdrop shapes on different surfaces made of various materials. By observing and comparing the dewdrop shapes on these surfaces, he can determine if the material of the surface influences the shape.
Does the shape of the dewdrop depend on the moisture in the atmosphere?
This question is testable as well. Andrew can conduct experiments or observations in different atmospheric conditions with varying moisture levels. By analyzing the resulting dewdrop shapes, he can determine if there is a correlation between moisture in the atmosphere and the shape of dewdrops.
However, question 4, "Which shape of dewdrop is the most pleasing to the observer?" is not a testable question in the scientific sense. The "pleasing" aspect is subjective and based on personal preference, making it difficult to measure or evaluate objectively.
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A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the trolleys stick together after collision, find the velocity that they of with move
Answer:
Approximately \(0.29\; {\rm m \cdot s^{-1}}\).
Explanation:
Make use of the fact that total momentum is conserved in collisions.
The momentum of an object of mass \(m\) and velocity \(v\) is \(p = m\, v\).
The momentum of the two trolleys before the collision would be:
\(4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}\).\(3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}\).Thus, the total momentum of the two trolleys right before the collision would be \(2\; {\rm kg \cdot m \cdot s^{-1}}\).
Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass \(m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}\).
The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass \(m = 7\; {\rm kg}\) would continue to be \(v = 2\; {\rm kg \cdot m \cdot s^{-1}}\) shortly after the collision.
Rearrange the equation \(p = m\, v\) to find the velocity of the two trolleys combined:
\(\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}\).
Oxides of non-metals are ....... in nature.
A 90.0 kg man climbs hand over hand up a rope to a height of 15.2 m. How
much potential energy does he have at the top? (PE=mgh)
Need sum1 good at physics class
Answer:
13,680 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 90 × 10 × 15.2
We have the final answer as
13,680 JHope this helps you
what is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
A. 89,8666 m/s
B. 0.76 m
C. 1.11 x 10^ -5 m
D. 1.3 m
Heya!!
For calculate wavelength, lets applicate formula:
\(\boxed{\lambda = V/f}\)
Δ Being Δ
f = Frequency = 262 Hz
v = Velocity = 343 m/s
\(\lambda\) = Wavelenght = ?
⇒ Let's replace according the formula:
\(\boxed{\lambda = 343\ m/s / 262\ Hz }\)
⇒ Resolving
\(\boxed{\lambda = 1,3 \ m}\)
Result:
The wavelength is 1,3 meters.
Good Luck!!
Answer:
D) 1.3 m
Explanation:
Have a amazing day
why are different colors used to represent the floor of the ocean?
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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Aluminum oxide consists of two ions chemically bonded together. What are the charges of each ion? O A. Al3+ and 02- B. A12+ and 03- O C. A13- and 02+ O D. A12- and 03+
Answer:
a
Explanation:
just did it on a p e x
Aluminum oxide consists of one aluminum ion (Al3+) and two oxygen ions (O2-) chemically bonded together to form the compound Al2O3. The correct option is A.
What is a chemical bond?A chemical bond is a force of attraction that holds two or more atoms together in a molecule or compound. Atoms can bond together by sharing or exchanging electrons in their outermost energy levels, which is also known as the valence shell.
There are three main types of chemical bonds:
Covalent bond: This bond occurs when two or more atoms share electrons in their outermost energy level. Covalent bonds are strong and are commonly found in molecules of compounds like water (H2O) and methane (CH4).
Ionic bond: This bond occurs when one atom donates one or more electrons to another atom, forming oppositely charged ions that are then attracted to each other. Ionic bonds are strong and are commonly found in compounds like table salt (NaCl) and calcium chloride (CaCl2).
Metallic bond: This bond occurs between atoms of metallic elements, where their outer electrons are delocalized and shared among all the atoms in the metallic structure. Metallic bonds are strong and are responsible for the properties of metals like malleability and conductivity.
Chemical bonds are essential for the formation of molecules and compounds that make up all matter in the universe. Understanding chemical bonds is crucial for fields such as chemistry, biology, and materials science.
Here in the Question,
Option B, "A12+ and O3-", is not true because aluminum ions, in their stable state, lose three electrons to form a +3 ion, not a +2 ion.
Option C, "A13- and O2+", is not true because aluminum ions, in their stable state, lose three electrons to form a +3 ion, not a -3 ion.
Option D, "A12- and O3+", is not true because oxygen ions, in their stable state, gain two electrons to form a -2 ion, not a +3 ion.
Therefore, option A, "Al3+ and O2-", is the correct answer as aluminum oxide consists of one aluminum ion with a charge of +3 and two oxygen ions, each with a charge of -2, that bond together to form the compound Al2O3.
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A stone is dropped from rest at a height of 2.0 m above the surface of a planet.
The planet has no atmosphere.
The speed of the stone just before reaching the surface of the planet is 3.8 m/s.
What is the acceleration of free fall on the planet?
A zero
B 1.9 m/s²
C 3.6 m/s²
D 7.2m/s²
The acceleration of free fall on the planet is 3.6 m/s^2. The correct answer is option C.
Let's assume that acceleration of free fall on the planet is a.
Potential energy of stone at height 2.0m is given be,
mah = 2ma
Kinetic energy of stone just before reaching the surface of the planet is,
Kinetic energy = mv^2/2
v= 3.8 m/s
Kinetic energy = 7.22m
By law of conservation of energy, Kinetic energy will be equal to Potential energy, and we get;
2ma = 7.22m
a = 3.6 m/s^2
Hence, the acceleration of free fall on the planet is is 3.6 m/s^2. Option C is the correct answer.
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at what time ABC or D is the writer accelerating upwardwhat is the magnitude of the maximum acceleration experienced by the rider
We will have the following:
From the graph we can see that the point at which it is accelerating upward is at point C. [We can see that where the slope of the function is positive the acceleration will be positive]
We determine the maximum magnitude of the acceleration of the rider by using the maximum force, that is:
\(F=m\cdot a\Rightarrow1.20N=a=\frac{1.20N}{m}\)So, the maixmum magnitude of the acceleration will depend on the mass of the rider. Now, since the mass cannot be 0 kg since that would undetermine the expression we know then that the best approximation is:
\(a=\frac{1.20N}{m}\)Where "m" is the mass of the rider in kg. Since we are not given a mass, then the acceleration can only be expressed as the force divided by the mass of the rider.
Label the layers of the Earth in order from youngest to oldest according to the law of superposition.
Answer:
With the increase in depth, age of layer increases.
Explanation:
According to the law of superposition, the layer of the Earth that is present in the deep is considered as the oldest layer while on the other hand, those layer which is present on the top of all layers is considered as youngest layer of earth. When we move from the top layer towards the bottom layer, the age of layer increases or in other words, when we move upward the age of the layer decreases so label the layers of earth on the basis of this phenomenon.
A man sees a bear and begins running away from it with an acceleration of 1.25 m/s2. Calculate the time it takes for the man to reach 30 meters away from the bear.
Answer:
20m/s2.isjsjsjjsjsisisiww
if a car has a negative acceleraction, what is the car doing?
Clara's grandfather is a captain of a cargo ship. He prefers to navigate his ship through the moderate neap tides. At these times, the line between Earth and the sun is at a right angle to the line between Earth and the moon. Which phase or phases of the moon describe this alignment?
Answer:
The phases are the first and third quarters.
Explanation:
During the first quarter of the moon phases, the line between Earth and the Sun is at a right angle to the line between Earth and the moon. At this time the moon has completed the first quarter of its orbit around the earth. At this point, half of the moon is fully reflecting light from the sun.
Also during the third quarter which is the last quarter, the line between the earth and the sun is at a right angle to the line between the earth and the moon. This is the time when the second half of the moon which was not illuminated during the first quarter becomes completely illuminated.
hai điện tích q1 =-2.10^(-8), q2=1,8.10^(-8) đặt tại A và B trong không khí,AB=8cm. Một điện tích q3 đặt tại C. 1, C ở đâu để q3 cân bằng
Answer:
Đáp án là vị trí để đặt q3 tại vị trí cân bằng là cách A một đoạn 0,0411 m
và nằm trong AB
Explanation:
Do q1 và q2 trái dấu nên q3 nằm trong
gọi r1 là vị trí từ A đến q3 suy ra r2=0.08-r1
Vị trí cân bằng nên \(\frac{q1}{r1^{2} }\) = \(\frac{q2}{(0.08-r1)^{2} }\)
in what tasks or jobs could refraction be dangerous. Please help its very urgent!!
The tasks that refraction can be dangerous is when a person is always on a swimming pool that does looks shallower than it was due to the light that is being emitted from the bottom of the pool and thus bends at the surface as a result of refraction of light and also when a person is Working in the light-production crew.
Does refractive error pose a threat?Two papers from very different parts of the world, Australia and India, published in the late 1990s, emphasized the fact that uncorrected refractive error was a significant contributor to blindness and the primary cause of vision impairment.
Therefore, When the retina is not properly illuminated by the eye, refractive error occurs. It might result in vision blur. If your child exhibits any symptoms of eye issues, you should take them to an eye doctor for a thorough eye examination.
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two point charges -5 uc and 4 uc charge are 21 cm apart. what is the magnitude of the electric field at a point half-way between the two charges?
The electric field at a point halfway is 18.37 x 10⁵ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 = -5μC = -5 x 10¯⁶ C
Q2 = 4μC = 4 x 10¯⁶ C
x = 21 cm = 0.21 m
from midpoint (r = 0.105 m)
The electric field directly outward from Q2 to Q1 so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.Q1/r² + k.Q2/r²
Etotal = k/r² x (Q1 + Q2)
Etotal = 9 x 10⁹/(0.21)² x (5 x 10¯⁶ + 4 x 10¯⁶)
Etotal = 18.37 x 10⁵ N/C
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if the temperature of a star doubles and all other properties remain constant, how does its spectrum and flux change?
If the temperature of a star doubles while all other properties remain constant, its spectrum shifts towards shorter wavelengths (bluer) and its flux increases by a factor of 16.
When the temperature of a star doubles while other properties remain constant, its spectrum undergoes a shift towards shorter wavelengths, meaning it becomes bluer. This shift is due to the relationship between temperature and the peak wavelength of radiation emitted by a black body, known as Wien's displacement law. Additionally, the star's flux, which is the amount of energy emitted per unit area, increases by a factor of 16. This increase is a result of the Stefan-Boltzmann law, which states that the total energy radiated by a black body is proportional to the fourth power of its temperature. Thus, doubling the temperature leads to a 16-fold increase in the star's flux.
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An airplane flies 1400 miles in 2 1/2 hours.
4 What is its average speed in miles per hour?
Answer:
the average speed of the airplane is 560 miles per hour.
Explanation:
To calculate the average speed of an airplane, you need to divide the total distance it travels by the total time it takes to travel that distance.
In this case, the total distance is 1400 miles and the total time is 2 and a half hours, so we can calculate the average speed as follows:
Average Speed = Total Distance / Total Time
Average Speed = 1400 miles / 2.5 hours
Average Speed = 560 miles per hour
which forces are capable of affecting particles or objects from large distance
Answer:
only long-range force that affects all particles is the gravitational force.
Explanation:
In nature there are four fundamental forces: nuclear, weak, gravitational and electrical.
The last two are long-range, that is, the forces are zero for infinite distances, the current gravitational on all the particles and the electric one acts on the charged particles, without the chosen charge it is zero, the forces is also zero.
Consequently the only long-range force that affects all particles is the gravitational force.
An unknown galaxy has a large flattened core. Which of the following classifications would best fit this galaxy's description? Irregular Spiral Lens Elliptical
Answer:
Lens
Explanation:
A lens galaxy has a large flattened core.
Spiral has arms.
Elliptical is a perfect sphere.
Answer:lens
Explanation:
What is the kinetic energy of a 200kg boat moving at 2.7m/s?
Answer:
729 JoulesExplanation:
Kinetic energy is 1/2mv²
where m is the mass of the object
v is the velocity
From the question
m = 200kg
v = 2.7m/s
Kinetic energy is
1/2 × 200 × 2.7²
= 729 Joules
Hope this helps you
A 15 kg child slides down a 5 m tall (vertical) slide that is inclined to the horizontal 34°. Her velocity is 5 m/s at the bottom of the sled. How much mechanical energy was lost to friction?
ANSWER
547.5 J
EXPLANATION
Given:
• The child's mass, m = 15 kg
,• The height of the slide, h = 5 m
,• The velocity of the child at the bottom of the slide, v = 5 m/s
Find:
• The loss of mechanical energy due to friction
The loss of mechanical energy due to friction is the difference between the child's gravitational potential energy at the top of the slide, and the child's kinetic energy at the bottom of the slide,
\(PE-KE=mgh-\frac{1}{2}mv^2\)Replace the known values and solve,
\(PE-KE=15kg\cdot9.8m/s^2\cdot5m-\frac{1}{2}\cdot15kg\cdot5^2m^2/s^2=735J-187.5J=547.5J\)Hence, 547.5 Joules of energy were lost due to friction.
The star Betelgeuse is about 600 light-years away. If it explodes tonight, approximately when can it be observed?
The star Betelgeuse is about 600 light-years away. If it explodes tonight, approximately: we won't know about it until 600 years from now.
What is light-years?Rather than measuring time, a light-year measures distance (as the name might imply). The distance a light beam travels in a single Earth year is measured in "light-years," which is roughly equivalent to 6 trillion miles (9.7 trillion kilometers).
Because the cosmos is expanding, the light that goes the farthest is stretched the most, resulting in the object that emitted that light being farther away. The expanding cosmos is the reason we can see things up to 46.1 billion light-years away. According to a common model of the Universe, some of the most recently discovered objects may be more than 13 billion light years away.
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suppose an object is accelerated by a force of 100 n . suddenly a second force of 100 n in the opposite direction is exerted on the object, so that the forces cancel. the object is?
If an object is accelerated by a force of 100 N and then a second force of 100 N in the opposite direction is applied to the object, the object will continue to move at a constant velocity in the direction of the original force.
When the two forces are equal and opposite, they cancel each other out, resulting in a net force of zero on the object. This means that the object is no longer accelerating, and is instead moving at a constant velocity in the direction of the original force. This constant velocity is known as the terminal velocity of the object, and is determined by the balance of forces acting on the object.
In summary, if two forces of equal magnitude but opposite direction act on an object, the object will continue to move at a constant velocity in the direction of the original force, with a net force of zero.
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7. Let's assume that a voice signal with a frequency band of 300 to 3.4 kHz is sampled at a frequency of 8 kHz. 7-1. Let's say it's made into a multi-level PAM signal with 64 levels and transmitted. If the symbol waveform of the square pulse is used, what is the minimum value of the transmission signal bandwidth? Also, what is the symbol rate? 7-2. When transmitting the PAM signal in the previous problem into binary data by PCM encoding, what is the bandwidth of the transmission signal if a square wave pulse is used? Also, what is the bit rate?
The minimum value of the transmission signal bandwidth in the case of a multi-level PAM signal with 64 levels, using a symbol waveform of a square pulse, is 8 kHz. The symbol rate is also 8 kHz.
In a multi-level PAM (Pulse Amplitude Modulation) signal, the number of levels determines the number of distinct amplitudes that can be transmitted. In this case, there are 64 levels.
To determine the minimum value of the transmission signal bandwidth, we need to consider the Nyquist criterion. According to the Nyquist theorem, the minimum bandwidth required for a signal is twice the highest frequency component of the signal. Here, the highest frequency component of the voice signal is 3.4 kHz.
Since the voice signal is sampled at a frequency of 8 kHz, the Nyquist criterion tells us that the minimum bandwidth required for transmission is 2 * 3.4 kHz = 6.8 kHz. However, in practice, it is common to choose a slightly higher value to account for the practical implementation considerations. Therefore, the minimum value of the transmission signal bandwidth is rounded up to 8 kHz.
The symbol rate is the number of symbols transmitted per second. In this case, since the voice signal is sampled at 8 kHz, the symbol rate is also 8 kHz.
Moving on to the second part of the question, when transmitting the PAM signal into binary data using PCM (Pulse Code Modulation) encoding, we need to consider the bandwidth and bit rate.
To determine the bandwidth of the transmission signal when using PCM encoding with a square wave pulse, we need to apply the Nyquist criterion again. The Nyquist criterion states that the bandwidth is equal to the highest frequency component of the signal. In PCM encoding, the highest frequency component is half the sampling rate, which is 4 kHz (8 kHz / 2).
Therefore, the bandwidth of the transmission signal when using PCM encoding with a square wave pulse is 4 kHz.
The bit rate is the number of bits transmitted per second. In PCM encoding, each sample of the PAM signal is quantized and represented using a fixed number of bits. Since the symbol rate is 8 kHz and each symbol is represented by 6 bits (64 levels), the bit rate is calculated as 8 kHz * 6 bits = 48 kbps.
In summary, the bandwidth of the transmission signal when using a multi-level PAM signal with 64 levels and a square wave pulse is 8 kHz, with a symbol rate of 8 kHz. When using PCM encoding with a square wave pulse, the bandwidth of the transmission signal is 4 kHz, with a bit rate of 48 kbps.
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how deep would be the eclipse caused by jupiter transiting in front of the solar disk, as observed from a distant star? to calculate it, compute the ratio of the cross-section of the jupiter disk to the cross-section of the solar disk (find the diameters online), and remove that number from 1 (it is a small number).
The depth of the eclipse caused by Jupiter transiting in front of the solar disk, as observed from a distant star, would be approximately 0.9899 or 98.99% of the total solar disk area remaining visible.
To determine the depth of the eclipse caused by Jupiter transiting in front of the solar disk, we'll compute the ratio of the cross-sections of Jupiter's disk and the solar disk.
Jupiter's diameter: approximately 139,822 km
Solar diameter: approximately 1,391,000 km
To find the cross-sections, we'll use the formula for the area of a circle: A = π * \(r^{2}\), where r is the radius of the circle (half the diameter).
Jupiter's cross-section: π * (69,911 km\()^{2}\) ≈ 15,342,634,686 k\(m^{2}\)
Solar cross-section: π * (695,500 km\()^{2}\) ≈ 1,518,429,780,450 k\(m^{2}\)
Now, we'll compute the ratio of Jupiter's cross-section to the solar cross-section:
Ratio = (15,342,634,686 k\(m^{2}\)) / (1,518,429,780,450 k\(m^{2}\)) ≈ 0.0101
Finally, we'll subtract this ratio from 1:
1 - 0.0101 = 0.9899
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Which describes the sum of potential energy and kinetic energy of objects or systems? *
a. nuclear energy and electric energy
b. nuclear and mechanical energy
c. thermal energy and electric energy
d. thermal energy and mechanical energy
Answer:
The Total Mechanical Energy
The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy (abbreviated TME).
Thermal energy and mechanical energy describes the sum of potential energy and kinetic energy of objects or systems. Correct option is D.
Potential Energy: This is the energy that an object possesses due to its position or condition. For example, a book placed on a shelf has potential energy because it can potentially fall down. The higher the object is positioned, the more potential energy it has.
Kinetic Energy: This is the energy of motion. An object that is moving has kinetic energy. The kinetic energy of an object depends on its mass and its velocity (speed).
Thermal Energy: This is the energy associated with the random motion of particles within a substance. It's related to temperature and is a form of kinetic energy at the microscopic level.
Mechanical Energy: This is the sum of potential energy and kinetic energy in a mechanical system. In other words, it accounts for both the energy an object has due to its position and the energy it has due to its motion.
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2. A hit used on a ball below the shoulders
1. Bump
2. Set
3. Serve
4. Spike
Answer:
Bump
Explanation:
Also called the forearm pass; An underhand pass hit with your forearms when the ball is below your shoulders; used to receive the serve.