A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a surface area of 9.50 m2. The total power it absorbs from the star is 4400 W. Assuming the surface is an ideal absorber and radiator, calculate the equilibrium temperature of the asteroid (in K).

Answers

Answer 1

Answer:

 T = 300.6K

Explanation:

In this problem, since the asteroid is an ideal absorber, we can approximate it to a black body, and use Stefan's law

      P = σ A e T⁴

where P is the absorbed power, A the area of ​​the asteroid, and the emissivity that for a black body is worth 1 and sigma the Stefan_boltzmann constant 5,670 10⁻⁸ W / m² K⁴

 they ask us for the temperature of the asteroid

      T = \(\sqrt[4]{(P / \sigma A e)}\)  

let's calculate

       T = (4400 / (5,670 10⁻⁸ 9.50 1)

       T =(81.6857 108)

       T = 3,006 102 K

        T = 300.6K


Related Questions

what is the function os isp??

Answers

ISPs play a vital role in providing internet access to individuals and businesses, which in turn helps them to stay connected, communicate, and access information, making them an essential part of the modern digital world.

An ISP, or Internet Service Provider, plays a crucial role in enabling individuals and businesses to access the internet. Its primary function is to provide internet connectivity to its customers, which can be done through various technologies such as DSL, cable, fiber, satellite, or wireless.
ISPs not only provide internet connectivity but also offer different types of internet plans that cater to different user needs, ranging from basic internet access to high-speed broadband connectivity with added features such as security, email, and web hosting services.
ISPs also allocate unique IP addresses to their customers, which enable them to access and communicate on the internet. They also manage and maintain the network infrastructure required to provide internet connectivity, such as servers, routers, switches, and cables.
In addition to providing connectivity, ISPs may also offer additional services such as virtual private network (VPN) services, cloud storage, and online backup solutions.
Overall, ISPs play a vital role in providing internet access to individuals and businesses, which in turn helps them to stay connected, communicate, and access information, making them an essential part of the modern digital world.

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I need help plissss..............

I need help plissss..............

Answers

Answer: A.
Have a good day!!!!

The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.

Answers

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

What is atom?

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

protons in the center of the nucleus.electrons closest to the nucleus.protons on the outer edge of the nucleus.

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determine energy of absorbed photon.

determine energy of absorbed photon.

Answers

The energy of an absorbed photon is \(2.998 * 10^8\) and  the resulting unit for energy is Joules (J).

To determine the energy of an absorbed photon in electronvolts (eV), we can use the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency of the photon. By substituting the values and units correctly, we can calculate the energy in electronvolts.

To determine the energy of an absorbed photon, one can use the following formula:

energy of absorbed photon = Planck's constant x frequency of radiation

Where Planck's constant is equal to \(6.626 * 10^{-34\) Joule seconds and frequency of radiation is measured in Hertz (Hz).

The energy of an absorbed photon can also be expressed using the wavelength of the radiation instead of its frequency.

The formula for this is:energy of absorbed photon = Planck's constant x speed of light / wavelength of radiation

Where the speed of light is equal to \(2.998 * 10^8\) m/s.In both cases,

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A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?

Answers

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

2.
In order to expand agriculture and urban areas to meet increased demand for growing
populations, water supples often have to be diverted. In three to five sentences, construct a
potential chain of consequences for what could happen when water is diverted from large bodies
like lakes and rivers. The chain does not have to be linear (i.e., five steps 1n a row), but can have
several branches, one for each different potential consequence.

Answers

Water bodies' quantity and flow both decrease.

What will happen if large water bodies are diverted?

When a river is redirected away from major water bodies, like rivers, lakes, etc. the volume of water flowing through the rivers and lakes decreases, and there is a reduction in the flow of water as well. This is because the water flows to the diverted sides of the river. We can say that this river's diversion has a detrimental impact on other communities because the areas it flows through may also suffer from a lack of water for either daily necessities or crop production.

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It is fun to exercise outside, but you have to be careful when it's hot. What are two things you should always do when you exercise in the heat?

Answers

Hydrate adequately and ensure you have sun protection.

Answer:

When exercising in the heat, it's important to take precautions to prevent heat-related illnesses. Two things you should always do when exercising in the heat are:

1.Stay hydrated: Drink plenty of water before, during, and after your workout to avoid dehydration. Sip water frequently, even if you don't feel thirsty.

2.Take breaks and rest in the shade: If you start feeling dizzy, lightheaded, or excessively fatigued, take a break in a cool, shaded area. Resting can help your body cool down and prevent heat exhaustion or heat stroke.







Explanation:

hope its help <:

Your car’s wheels are 65.0 cm in diameter, and the wheels are spinning at an angular velocity of 136 rad/s. How fast is your car moving (assume no slippage)?

Answers

The car is moving with the linear velocity of 44.2 m/s.

We have the diameter of car wheels as 65 cm which are spinning at an angular velocity of 136 rad/s.

We have to determine how fast is the car moving or its linear velocity.

What is Angular Velocity ?

Angular velocity is defined as the rate of change of angular position of a rotating body.

\(\omega = \frac{d\theta}{dt}\)

According to question, we have -

diameter of car wheels = 65 cm

Therefore, the radius will be = 32.5 cm

Angular velocity = 136 rad/s

We know that -

v = r\(\omega\)

v = 32.5 x 136

v = 4420 cm/s

v = 44.2 m/s

Hence, the car is moving with the linear velocity of 44.2 m/s.

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Can you answer this question?

Can you answer this question?

Answers

The equivalent resistance between the point A and B is 0.95 ohm.

Define resistance ?

Resistance means the degree to which a substance or device opposes the passage of an electric current, causing energy dissipation. It is measured in ohms, symbolized by the Greek letter omega (Ω). Resistance is also defined as the opposition offered by a body or substance to the passage through it of a steady electric current.

What is meant by ohms law?

Ohm's law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit. It states that the current through a conductor between two points is directly proportional to the voltage across the two points. The law is named after Georg Simon Ohm, a German physicist who discovered it,

Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be

                           1 / R = (1 /R3) + (1 / R4) + (1 / R6)

                                   = (1 / 4.4) + (1 / 3.5) + (1 / 6.6)

                           1 / R = 0.79

                                R = 1.43 ohm.

Next solving R6 and leg of this resistance which are in series connection,

                                 r = R + R6

                                   = 1.43 + 7.1)

                                 r = 8.53 ohm.

Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,

                             1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)

                                    = 1.04 ohm

Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.

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The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?

Answers

Answer:

(1.8 × 10^9) meters in one minute

Explanation:

To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.

The speed of light is 3 × 10^8 meters per second.

There are 60 seconds in a minute.

Therefore, the distance light can travel in one minute is:

Distance = Speed × Time

Distance = (3 × 10^8 meters per second) × (60 seconds)

Calculating this, we get:

Distance = 3 × 10^8 meters/second × 60 seconds

Distance = 18 × 10^8 meters

Distance = 1.8 × 10^9 meters

So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.

A laser source is replaced by a laser of the same color that is more powerful. How does the light of the second laser compare with the original laser?

Answers

The light of the second laser compare with the original laser in the following way: the light in the second laser absorbs more optical radiation.

What is a laser?

A laser is device that produces a monochromatic, coherent beam of light.

A laser is created when electrons in the atoms in optical materials like glass, crystal, or gas absorb the energy from an electrical current or a light.

Therefore, it can be said that light of the second laser compare with the original laser in the following way: the light in the second laser absorbs more optical radiation.

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when a stationary rugby ball is kicked, it is contact with a player's about for 0.05 s. during this short time, the ball accelerates at 600m/s/s.calculate the speed at which the ball leaves the player's boot​

Answers

Answer:

30 m/s

Explanation:

Applying,

v = u+at................ Equation 1

Where v = final speed of the ball, u = initial speed of the ball, a = acceleration, t = time.

From the question,

Given: u = 0 m/s (stationary), a = 600 m/s², t = 0.05 s

Substitute these values into equation 5

v = 0+(600×0.05)

v = 30 m/s

Hence the speed at which the ball leaves the player's boot is 30 m/s

study of bluefish locomotion found that their tail motion produces an average thrust of 0.65 N . Suppose a 1.7 kg bluefish that is coasting horizontally at 0.45 m/s suddenly begins tail motion.

Answers

Answer:

he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion

Explanation:

The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:

F = ma

0.65 N = 1.7 kg * a

a = 0.38 m/s^2

This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:

d = vit + 1/2 at^2

where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:

d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2

d = 1.78 meters

Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.

An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?

Answers

The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

Hor to convert 175 centimeters to meters

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

How to determine the number of people needed

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.

Answers

The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.

To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.

At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.

As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.

Therefore, we can equate the initial potential energy to the final kinetic energy:

mgh = 1/2 m\(v^{2}\),

where v is the horizontal velocity of the boy when he leaves the track.

Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:

d = vt.

Solving these equations, we can express the initial height H in terms of h and d:

H = h + d.

So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G

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A rock is thrown with an initial vertical velocity 50 m/s at an angle of 40 degrees.
a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. What is the hang timel?
d. What is the peak height?
e. What is the range?

Answers

Answer:

\(38.3\ \text{m/s}\)

\(32.14\ \text{m/s}\)

6.55 seconds

\(52.65\ \text{m}\)

\(254.84\ \text{m}\)

Explanation:

u = Initial velocity of rock = 50 m/s

\(\theta\) = Angle of throw = \(40^{\circ}\)

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

Horizontal component is given by

\(u_x=u\cos\theta\\\Rightarrow u_x=50\times \cos40^{\circ}\\\Rightarrow u_x=38.3\ \text{m/s}\)

The horizontal component of the velocity is \(38.3\ \text{m/s}\)

Vertical component is given by

\(u_y=u\sin\theta\\\Rightarrow u_y=50\times \sin40^{\circ}\\\Rightarrow u_y=32.14\ \text{m/s}\)

The horizontal component of the velocity is \(32.14\ \text{m/s}\)

Time of flight is given by

\(t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 50\sin40^{\circ}}{9.81}\\\Rightarrow t=6.55\ \text{s}\)

The hang time of the rock is 6.55 seconds

Maximum height is given by

\(h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{50^2\sin^240^{\circ}}{2\times 9.81}\\\Rightarrow h=52.65\ \text{m}\)

Maximum height is \(52.65\ \text{m}\)

Range is given by

\(d=\dfrac{u^2\sin2\theta}{g}\\\Rightarrow d=\dfrac{50^2\sin(2\times40)^{\circ}}{9.81}\\\Rightarrow d=254.84\ \text{m}\)

The range is \(254.84\ \text{m}\)

A resistor has a power output of 15 W. If it is powered by 3 AA batteries, what is the current through the circuit?

A torch takes two 1.5 V AA batteries and provides a current of 0.3 A to the bulb. What is the power output of the bulb?

Answers

Answer:

well i am sure you need this to so look really hard at this then delete it

Explanation:

1. The speed with which electrons move through a copper wire is typically 10-4 m s-1

.

a. Explain why is it that the electrons cannot travel faster in the conductor?

b. Explain why the electron drift produces heat?

1. a) collisons with the crystal lattice atoms b) collisions with lattice atoms transfers energy.

2. Explain in terms of atomic and electron movement, why resistance increases with temperature.

2. Electrons drift through the lattice, as temperature increases the lattice atoms vibrate more and this increases the probability of

collision and hence resistance to electrons has increased.

3. Calculate the resistance of an aluminum (ρ = 2.8x10-8 Ωm) wire that is 2.0 m long and of circular cross section

with a diameter of 1.5 mm.

3. 32 mΩ

4. Determine the length of tungsten (ρ = 5.6x10-8 Ωm) wire with a diameter of 1.0 mm that is used to make a 20.0 Ω resistor.

4. 280 m

5. A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. Calculate the length of this wire needed to carry a current

of 30 mA when there is a potential difference of 12 V across it.

5. 50 m

6. A thin copper (ρ = 1.68x10-8 Ωm, but you don’t need it) wire 200 cm in length has a 9 V dry cell connected between its ends.

Determine the voltage drop that occurs along 30 cm of this wire.

6. 1.35 V

7. If the potential difference across the bulb in a camping lantern is 9.0 V, what is the potential difference across the battery used to

power it?

battery gives the voltage of 9.0 V to the lantern to use it.

8. How much current, in amperes, is in a lightning stroke that lasts 0.05 second and transfers 100 coulombs?

I = q/t = (100 C)/(0.05 s) =2000 A

9. Calculate the resistance of the filament in a light bulb that carries 0.4 A when 3.0 V is impressed across it.

V = IR R = V/I = 7.5 Ω

10. Electric socks, popular in cold weather, have a 90-ohm heating element that is powered by a 9-volt battery.

How much current warms your feet?

V = I/R = 0.1 A

11. Calculate the current of a lightning bolt that delivers a charge of 35 coulombs to the ground in a time of 1/1000 second.

11. I = q/t = 35 000 A.

12. Calculate the current where 10 coulombs of charge pass a point in 5 seconds.

12. I = V/R = 2 A

13. Two light bulbs designed for 120-V use are rated at 40W and 60W. Which light bulb has the greater filament resistance? Why?

13. More current flows in the 60-W bulb, which means the resistance of the filament is less.

P = IV = V2/R, R = V2/P = (120 V)2/(60 W) = 240 Ω; for the 40-W lamp, R = (120 V)2/(40 W) = 360 Ω

14. A battery does 18 joules of work on 3 coulombs of charge. What voltage does it supply?

14. V= E/q= (18 J)/(3 C) = 6V

15. A power line with a resistance of 2 ohms has a current of 80 A in it. The power dissipated in the line is

15. 12800 W.

2

16. A toaster oven is plugged into an outlet that provides a voltage difference of 120 V.

What power does the oven use if the current is 10A?

16. P = IV = 1200 W

17. A VCR that is not playing still uses 10.0 W of power. What is the current if the VCR is plugged into a 120 V electric outlet? 17.

17. P = IV I = P/V = 0.083 A

18. A flashlight bulb uses 2.4 W of power when the current in the bulb is 0.8 A. What is the voltage difference?

18. P = IV V = P/I = 3V

19. A refrigerator operates on average for 10.0 h a day. If the power rating of the refrigerator is 700 W, how much electrical energy

does the refrigerator use in 1 day? (make sure to convert to kW)

19. E = Pt = (0.7 kW)(10.0 h) = 7 kWhours

20. A TV with a power rating of 200 W uses 0.8 kWh in one day. For how many hours was the TV on during this day?

20. E = Pt t = E/P= 0.8 kWh/0.2 kW = 4 h

21. Calculate the voltage difference in a circuit with a resistance of 25 Ω if the current in the circuit is 0.5 A.

21. V = IR = 12.5 V

22. A current of 0.5 A flows in a 60 W light bulb when the voltage difference between the ends of the filament is 120 V.

What is the resistance of the filament?

22. R = V/I = 240 Ω

23. A toy car with a resistance of 20 Ω is connected to a 3 V battery. How much current flows in the car?

23. I = V/R = 0.15 A

24. The current flowing in an appliance connected to a 120 V source is 2 A. How many kilowatt-hours of electrical energy does the

appliance use in 4 h? (2 equations used & convert watts to kW)

24. E = Pt P = IV = 0.24 kW E = 0.96 kWh

25. A calculator uses 9 V battery & draws 0.1 A of current. How much power does it use?

25. P = IV = 0.9 W

26. A battery causes 250 mA to flow when it is applied to a light bulb with a resistance of 50 ohms. How much current would flow if

the same source were applied to a 12 ohm resistor?

26. voltage of the source: V = IR = 12.5 V I = V/R = 1.04 A

You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogram-meter^3 and the density of silicon in other units: 2.33 gram-centimeter^3. You decide to convert the density of silicon into units of kilogram-meter^3 to perform the comparison.
By which combination of conversion factors will you multiply 2.33 gram-centimeter^3 to perform the unit conversion?

Answers

Answer:

Explanation:

To convert gram / centimeter³ to kg / m³

gram / centimeter³

= 10⁻³ kg / centimeter³

= 10⁻³  / (10⁻²)³ kg / m³

= 10⁻³ / 10⁻⁶ kg / m³

= 10⁻³⁺⁶ kg / m³

= 10³ kg / m³

So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³

2.33 gram / cm³

= 2.33 x 10³ kg / m³ .

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 450 m with a radial acceleration of 17 m/s^2.

Required:
What is the plane's speed?

Answers

Answer:

v = 87.46 m/s

Explanation:

The radial acceleration is the centripetal acceleration, whose formula is given as:

\(a_c = \frac{v^2}{r}\)

where,

\(a_c\) = centripetal acceleration = 17 m/s²

v = planes's speed = ?

r = radius of path = 450 m

Therefore,

\(17\ m/s^2 = \frac{v^2}{450\ m}\\\\v^2 = (17\ m/s^2)(450\ m)\\\\v = \sqrt{7650\ m^2/s^2}\)

v = 87.46 m/s

A 4260-kg roller coaster train full of riders approaches the level loading dock at a speed of 19.0 m/s. It is abruptly decelerated to a speed of 3.2 m/s. Determine the work done on the roller
coaster.
KE+PE+Wext=KE+ PE

Answers

Answer:

below

Explanation:

The change in Kinetic Energy is equal to the work done

  KE = 1/2 mv^2

      Change in KE =   1/2 m (19^2 - 3.2^2) = 747.1 kjoules

Trace the decay of U-238 to Ra-226 as shown in Figure 39.15 in the textFigure out what particles must be emitted in each step, and write the reaction for that step in terms of symbols

Answers

The reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

What is the radioactive equation for the decay of U-238?

The radioactive equation for the decay of U-238 to Ra-226 is calculated as follows;

First the uranium atom (U-238) will decay thorium by emitting alpha particle as shown in the equation below;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

The second stage is, the thorium will decay to radium by emitting alpha particles again as shown below;

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

The third, and final stage, the radium will decay to an isotope of radium again, by emitting alpha particle as shown below;

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

Thus, the reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

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Trace the decay of U-238 to Ra-226 as shown in Figure 39.15 in the textFigure out what particles must

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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A key challenge with renewable energy is that the energy must be transported to the place where it's needed _ or devices that store the energy needed improvement.



A. batteries


B. refineries


C. solar panels


D. wind turbines

Answers

A. batteries

Renewable energy sources like solar and wind power are often located in remote areas, far from where the energy is needed. This means that the energy must be transported over long distances to reach the end user, which can result in energy losses due to resistance in transmission lines. To address this issue, energy storage devices like batteries are needed to store excess energy generated by renewable sources during periods of low demand, and then release it when demand is high. However, current battery technology still needs improvement in terms of capacity, efficiency, and cost to make it more widely accessible and practical for large-scale renewable energy storage.

In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate the greatest?

Answers

Answer:

Volume flow rate is the same in both sections of the pipe

Explanation:

A household refrigerator consumes electrical energy at the rate of 200 W. lf electricity costs 5 k per kWh, calculate the cost of operating the appliance for 30 days

Answers

Answer:

= 720000 [k]

Explanation:

The cost is equal to 5 [$/kW-h], kilowatt per hour, this value should be multiplied by the power, and then by the time.

\(5[\frac{k}{kw*h}]*200[w]*30[day]*24[\frac{h}{day} ]\)

= 720000 [k]

If Light is travels from air into pure water with an incident angle of 30°. What is the angle of refraction?

Answers

Explanation:

For air, n1 = 1.00003; for water, n2 = 1.3330

Given: θ2 = 30 degrees, then

θ1 = arcsin [(n2/n1) sin θ2]

= arcsin [(1.3330/1.0003) sin (40)]

= 58.93 degrees

Note that since, in this example, light is traveling from a medium of higher density (water; n2 = 1.3330) to a medium of lower density (air; n1 = 1.0003), then n2 > n1, and the angle of refraction (θ1) is larger than the angle of incidence (θ2), thus the light bends away from the normal (in this example, the vertical) as it leaves the water and enters the air.

what is the acceleration of a ball traveling horizontally wit an initial velocity of 20 meters/seconds and, 2.0 seconds later, a velocity of 30 meters/seconds

Answers

Answer:

\(a=5\ m/s^2\)

Explanation:

Given that,

Initial velocity of the ball, u = 20 m/s

Final velocity, v = 30 m/s

Time, t = 2 seconds

Let us assume to find the acceleration of the ball. The rate at which the velocity of the ball is changing is called the acceleration of the ball. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{30-20}{2}\\\\a=5\ m/s^2\)

So, the acceleration of the ball is \(5\ m/s^2\)

A car decelerates from 36 meters per second to 12 meters per second. The constant rate of deceleration is 12 meters per second per second. How long did it take for the car to decelerate?

Answers

Answer:
2s
Explanation:
It takes the car 1 second to decelerate 12m and it decelerated 24m (as 36 - 12 = 24)

Why is sound not an electromagnetic wave

Answers

Answer:

There is no sound in space because there are no molecules there to transmit the sound waves. Electromagnetic waves are not like sound waves because they do not need molecules to travel. This means that electromagnetic waves can travel through air, solid objects and even space.

There is no sound in space because there are no molecules there to transmit the sound waves. Electromagnetic waves are not like sound waves because they do not need molecules to travel. This means that electromagnetic waves can travel through air, solid objects and even space.

Purpose: Determine the kinetic energy of a constant velocity car when it is switched on.

A. Design an experimental procedure to find the kinetic energy of a constant velocity car. Make a list of the equipment you would use.

B. Describe the overall procedure you would follow. Provide enough detail so another student could replicate the experiment, including any steps necessary to reduce experimental uncertainty.

C. Clearly list what data you need to collect.

D. List what equations you need to use with the data you collected to find the kinetic energy of the car.

E. Describe the energy conversion that occurs while the constant velocity car is running. What other types of energy does the car have, aside from kinetic energy?

F. If you were to actually complete this lab, what are some potential sources of error that could cause your answer to be incorrect?

Answers

Answer:

The kinetic energy is proportional to the square of the speed, so doubling the speed increases the kinetic energy by a factor of 4.

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