Answers
The acceleration due to gravity always acts in the downward direction and its value remains constant.
During the motion of the soccer ball from position x to position y, the vertical acceleration is the acceleration due to gravity.
The magnitude of the soccer ball's vertical acceleration remains the same.
Thus, it remains the same.
Related Questions
11. Which type of cloud is shown in this image?
Answers
Cumulus, cirrus, and stratus clouds are the three types of clouds shown in this photograph.
How does a cloud behave in the sky?The importance of clouds cannot be overstated. One of the causes is precipitation, such as rain or snow.
Clouds make the surface warmer at night by reflecting heat back to it. Clouds may shield us from the sun and make Earth cooler throughout the day.
The type of cloud is shown in this image is;
1.Cumulous
2.Cirrus
3.Stratus
1. Cumulous
The fluffy, white, cotton-top clouds known as cumulus have such a gentle appearance that you may imagine angels relaxing and going about their business on them.
2. Cirrus
High clouds in the cirrus genus are comprised of ice crystals. The characteristic appearance of cirrus clouds is fragile and wispy with white filaments.
3. Stratus
Contrary to convective or cumuliform clouds, which are produced by rising thermals, stratus clouds are low-level clouds with horizontal stratification and a homogenous base.
Hence, the type of clouds shown in this image is cumulus, cirrus, and stratus.
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Answer: Cumulus
Explanation:the answer is Cumulus i just passes my test when i put this in so u try
Charge of uniform density (80 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical surfaces of radii 1.0 mm and 3.0 mm. Determine the magnitude of the electric field at a point which is 2.0 mm from the symmetry axis.
Answers
Answer: Magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.
Explanation:
Given: Density = 80 \(nC/m^{3}\) (1 n = \(10^{-9}\) m) = \(80 \times 10^{-9} C/m^{2}\)
\(r_{1}\) = 1.0 mm (1 mm = 0.001 m) = 0.001 m
\(r_{2}\) = 3.0 mm = 0.003 m
r = 2.0 mm = 0.002 m (from the symmetry axis)
The charge per unit length of the cylinder is calculated as follows.
\(\lambda = \rho \pi (r^{2}_{2} - r^{2}_{1})\)
Substitute the values into above formula as follows.
\(\lambda = \rho \pi (r^{2}_{2} - r^{2}_{1})\\= 80 \times 10^{-9} \times 3.14 \times [(0.003)^{2} - (0.001)^{2}]\\= 2.01 \times 10^{-12} C/m\)
Therefore, electric field at r = 0.002 m from the symmetry axis is calculated as follows.
\(E = \frac{\lambda}{2 \pi r \epsilon_{o}}\)
Substitute the values into above formula as follows.
\(E = \frac{\lambda}{2 \pi r \epsilon_{o}}\\= \frac{2.01 \times 10^{-12} C/m}{2 \times 3.14 \times 0.002 m \times 8.85 \times 10^{-12}}\\= 18.08 N/C\)
Thus, we can conclude that magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.
Which shows evidence of active transport?
A scientist places four identical cells into four different
liquids, each with different concentrations of magnesiuni.
Celll
w
Description of Liquid
Slightly more magnesium than the
cell
The least amount of magnesium
O
O
O
O
cells W and Z
cell W only
cell Y only
cells X and Y
Result
Took in
magnesium
Took in
magnesium
Took in
magnesium
Took in
magnesium
Slightly less magnesium than the
cell
The most amount of magnesium
Answers
Answer: D
X and Y
Explanation:
X The least amount of magnesium Took in magnesium
Y Slightly less magnesium than the cell Took in magnesium
Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.
Answer:
Cells X and Y
Explanation:
Active transport occurs when a substance moves across a membrane against its concentration gradient.
Cells W and Z were placed in a liquid containing more magnesium than the cells. Magnesium therefore, diffuses passively down it's concentration gradient into the cells.
However, cells X and Y were placed in a solution containing less magnesium than the cells, yet these cells took in magnesium against this concentration gradient. This, shows that active transport had taken place.
6.7.5. While you sleep, your body is using energy at a rate of 77 W. How many food calories are used during an eight hour period
Answers
Answer:
6.38×10¯⁴ Calorie.
Explanation:
The following data were obtained from the question:
Power (P) = 77 W
Time (t) = 8 h
Energy (E) =.?
Next, we shall convert 8 hours to seconds. This can be obtained as follow:
1 h = 3600 s
Therefore,
8 h = 8 h × 3600 s / 1h
8 h = 28800 s
Next, we shall determine the energy. This can be obtained as follow:
Power (P) = 77 W
Time (t) = 28800 s
Energy (E) =.?
Energy (E) = Power (P) / time (t)
E = P/t
E = 77 /28800
E = 2.67×10¯³ J
Finally, we shall convert 2.67×10¯³ J to calorie. This can be obtained as follow:
4.184 J = 1 calorie
Therefore,
2.67×10¯³ J = 2.67×10¯³ J × 1 Cal / 4.184 J
2.67×10¯³ J = 6.38×10¯⁴ Calorie.
Therefore, 6.38×10¯⁴ Calorie of food is used during the 8 hours period.
Suppose that there is a uniform electric field that points in the
+x
direction. If the electric potential is
3.46
volts at
x=3.79
and
5.67
volts at
x=9.72
. what is the magnitude of this electric field in
N/C
? The positions are given in meters. Remember that since this problem is asking you to find the magnitude of a vector (the electric field), your answer should be a positive number.
Answers
The response to the question states that the electric field has a strength of 0.37 N/C.
What precisely is a "electric field"?When charge was present in any kind, a point in space has an electric field that is related to it. The value of E, often referred as the electric field strength, electric field strength, or just the electric field, describes the size and orientation of the electrostatic potential.
Using the formula:
E = ΔV/Δx
where x represents the change in motion and V represents the difference in potential.
ΔV = 5.67 V - 3.46 V = 2.21 V
Δx = 9.72 m - 3.79 m = 5.93 m
Putting in the values, we get:
E = ΔV/Δx = 2.21 V / 5.93 m
= 0.37 V/m =
0.37 * (1 N/C) / (1 V)
= 0.37 N/C
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The size, shape, and color of an object would be an example of a
O physical change
O physical property
O chemical change
chemical property
Answers
Answer:
physical change
Explanation:
its only changing things you see.
3) A 10kg object rests on a frictionless surface when it is struck by a 300N force. At what rate will it accelerate?
3m/s/s
30m/s/s
0.3m/s/s
300m/s/s
Answers
Answer: 0.3m/s/s
(i'm really sorry if i'm wrong)
:(
A 130 g copper bowl contains 100 g of water, both at 20.0°C. A very hot 420 g copper cylinder is dropped into the water, causing the water to boil, with 8.63 g being converted to steam. The final temperature of the system is 100°C. Neglect energy transfers with the environment. (a) How much energy is transferred to the water as heat? (b) How much to the bowl? (c) What is the original temperature of the cylinder? The specific heat of water is 1 cal/g·K, and of copper is 0.0923 cal/g·K. The latent heat of vaporization of water is 539 Cal/kg.
Answers
Answer:
a) 4652 cal
b) 8000 cal
Explanation:
Amount of heat transferred
Q1 = mL(v)
Q1 = 8.63 * 539
Q1 = 4652 cal
Amount of heat transferred to the water
Q2 = mcΔT
Q2 = 100 * 1 * (100 - 20)
Q2 = 8000 cal
Q = Q1 + Q2
Q = 4652 + 8000
Q = 12652 cal
b)
Heat transferred to the copper bowl
Q(b) = m(b) * c(b) * ΔT
Q(b) = 0.13 * 0.0923 * (100 - 20)
Q(b) = 0.96 cal
c)
Original heat of the cylinder
Q(c) = Q + Q(b)
m(c) * c(c) * ΔT = Q + Q(b), making ΔT subject of the formula
ΔT = (Q + Q(b))/ (m(c) * c(c))
ΔT = (12652 + 0.96) / (0.42 * 1)
ΔT = 12652.96/0.42
ΔT = 30126.1
A 1kg cannon ball.is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a wall 20m above the ground, what is the total
change in KE?
Answers
Answer:
Ek = 196.2 [J]
Explanation:
The question concerns the KE kinetic energy.
That is, we must find the kinetic energy at the moment the cannon is fired and the kinetic energy of when the ball hits the ground after having fallen 20 meters.
At the moment when the ball is fired it is 20 meters above ground level. If the ground level is taken as the reference level of potential energy, where it is equal to zero, in this way when the ball is at the highest (20 meters) you have the maximum potential energy.
In this way, the energy in the initial state is equal to the sum of the kinetic energy plus the potential energy. As the energy is conserved this same energy will be present when the ball hits the ground, where the potential energy is zero and will have only kinetic energy.
\(E_{1}=E_{2}\\E_{k1}+E_{p1}=E_{k2}\\\frac{1}{2} *m*v^{2} +m*g*h=E_{k2}\\E_{k2}=0.5*1*(5)^{2} +1*9.81*20\\E_{k2}=208.7[J]\)
The kinetic energy in the initial state can be easily calculated by means of the following equation.
\(E_{k1}=\frac{1}{2} *m*v^{2}\\E_{k1}=0.5*1*(5)^{2}\\E_{k1}=12.5 [J]\)
Therefore the change in KE
\(E_{k} = 208.7 - 12.5\\E_{k} = 196.2 [J]\)
If the volume of an iron sphere is normally 100cm3 and the sphere is subjected to a uniform pressure of 100000000N/m2. What is its change in volume (m3)?
Answers
The change in volume of the iron ball under the given conditions is therefore approximately -0.00005882 m³.
To calculate the change in volume of an iron sphere subjected to uniform pressure, we can use the bulk modulus of iron and the formula relating the change in pressure and volume. Bulk modulus is a measure of a material's resistance to compression.
With regard to it regarding to it:
Initial volume (V₀) = 100 cm³ = 0.0001 m³
Uniform pressure (P) = 100,000,000 N/m²
Change in volume (ΔV) = ?
The formula for calculating the change in volume is:
ΔV = -V₀ * (P / B)
Where B is the bulk modulus of iron.
The bulk modulus of iron is approximately 170,000,000 N/m².
Enter the values:
ΔV = -0.0001 m³ * (100,000,000 N/m² / 170,000,000 N/m²)
Simplifying the equation:
ΔV = -0.0001 m³ * 0.5882
ΔV ≈ -0.00005882 m³
A negative sign means a decrease in volume.
Please note that this calculation assumes that the iron sphere behaves elastically under applied pressure and that no other factors such as thermal expansion affect the change in volume.
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Why do other stars look much dimmer than the sun?
Answers
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target? Neglect air friction.
Answers
The speed of the artillery shell when it hits its target is approximately 118.0 m/s.
The problem is asking for the velocity of the artillery shell when it hits the target. Since it has already been given that the speed of the shell at a height of 100 m is 100 m/s, we can make use of the conservation of energy to find the final velocity.
The total energy of the artillery shell at a height of 100 m above the ground can be given as:
K + U = E(1)where K is the kinetic energy, U is the potential energy, and E is the total energy of the artillery shell.
The kinetic energy of the artillery shell at a height of 100 m is given as:
K = (1/2)mv²
where m is the mass of the artillery shell and v is its velocity at a height of 100 m above the ground.
The potential energy of the artillery shell at a height of 100 m is given as:
U = mgh
where m is the mass of the artillery shell, g is the acceleration due to gravity (taken to be 9.81 m/s²), and h is the height of the artillery shell above the ground (in this case, h = 100 m).
Substituting the values of K and U into Equation (1), we have:
(1/2)mv² + mgh = E
where E is the total energy of the artillery shell.
The total energy of the artillery shell when it hits the target can be given as:
E = K' + U'
where K' is the kinetic energy of the artillery shell just before it hits the target, and U' is its potential energy just before it hits the target.
Since the problem states that there is no air friction, the total energy of the artillery shell is conserved (i.e., E = K + U = K' + U').
Therefore:
(1/2)mv² + mgh = K' + U'(1/2)mv² + mgh = (1/2)mv'² + mgh'(where v' is the velocity of the artillery shell just before it hits the target, and h' is its height just before it hits the target).
Solving for v', we have:
v' = sqrt(v² + 2gh)
Substituting the given values, we get:
v' = sqrt((100 m/s)² + 2(9.81 m/s²)(200 m)) = sqrt(10000 + 3924.4) m/s = sqrt(13924.4) m/s = 118.0 m/s
Therefore, the speed of the artillery shell when it hits its target is approximately 118.0 m/s.
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In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Describe a grand challenge in today's society?
Answers
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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a particle moves along the y-axis with the velocity given by the function f defined by ( ) 2 vt t t t
Answers
This means that the velocity of the particle is a function of time, and it is given by the equation f(t) = 2t^2 - t.
What is particle?A particle is a small piece or quantity of something. Particles are related to the field of particle physics, which is a branch of physics that studies the smallest known particles and the fundamental interactions between them. Particles come in many forms such as atoms, molecules, protons, electrons, photons, and neutrons. They can be found in both matter and energy. Particle physics is the study of these particles and how they interact with each other to form matter and energy.
This means that the velocity of the particle is a function of time, and it is given by the equation f(t) = 2t^2 - t. This equation describes how the velocity changes over time, with the particle accelerating in the positive direction (increasing velocity) until t = 1, and then decelerating (decreasing velocity) afterwards.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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In thermodynamics energy can be transeferd to and from a system by
Answers
Three different types of energy can enter or leave a system: heat, work, and mass flow.Heat and work are the only 2 types that can exist in a closed system because no mass can cross its borders.
How does thermodynamics handle energy transfer?There are three methods that thermal energy can be transferred: conduction, convection, & radiation.Conduction is the transfer of heat energy between adjacent molecules which are in touch with one another.
What are the three ways that energy can be moved?We must become familiar with the three different ways that energy is transferred: conduction, convection, & radiation.
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Two window washers, Bob and Joe, are on a 3.00 m long, 395 N scaffold supported by two cables attached to its ends. Bob weighs 805 N and stands 1.00 m from the left end. Two meters from the left end is the 500 N washing equipment. Joe is 0.500 m from the right end and weighs 820 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable
Answers
Answer:
- the forces on the left hand side is 1.038 kN
- the forces on the right hand side is 1.483 kN
Explanation:
Given the data in the question, as illustrated in the image below;
Length of the scaffold = 3 m
weight of the scaffold = 395 N
Weight of Bob = 805 N and stands 1 m from the left end
weight of washing equipment = 500N and on sits 2 m from the left end
Weight of Joe = 820 N and stand 0.500 m from the right end
so the force on the left cable will be;
\(T_{left\) = \(\frac{1}{3m}\)[ (805 N)( (3-1) m) + ( 395 N )( \(\frac{3}{2} m\)) + ( 500 N )(1m ) + ( 820 N)( 0.500m ) ]
\(T_{left\) = \(\frac{1}{3m}\)[ 1610 + 592.5 + 500 + 410 ]
\(T_{left\) = \(\frac{1}{3m}\)[ 3112.5 ]
\(T_{left\) = 1037.5 N
\(T_{left\) = 1.038 kN
Therefore, the forces on the left hand side is 1.038 kN
On the right hand side;
\(T_{Right\) = ( 805 N + 395 N + 500 N + 820 N ) - 1037.5 N
\(T_{Right\) = 2520 N - 1037.5 N
\(T_{Right\) = 1482.5 N
\(T_{Right\) = 1.483 kN
Therefore, the forces on the right hand side is 1.483 kN
A person swims at a constant speed of 1 meter per second. What type of function can be used to model the distance the swimmer travels?
Hint: sketch a graph of what this would like and see which parent function it looks like
Answers
If a person swims at a constant speed of 1 meter per second, than the linear function will be used to model the distance travelled by the swimmer.
The parent function is "the principal's of ice"
A linear function is a function that forms a straight line on a graph. It is generally a polynomial function whose degree is at most 1 or 0. Although linear functions are also represented in terms of calculus and linear algebra.
Here Y-axis represents Distance and X-axis represents Time.
Also speed is the rate of change of distance with respect to time i.e. distance is changing linearly with time
Mathematically it is \(Speed = \frac{distance}{time}\).
Change in Distance = Change in time and hence speed is constant.
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A noise of -1 decibels is...a. audible.b. harmful.c. ultrasonic.d. subaudible
Answers
ANSWER
d. Subaudible
EXPLANATION
Sound intensity is usually measured in decibels.
The audible sound ranges from 0 dB to 120 dB while any sound that is beyond 120 dB is regarded as harmful and can cause hearing impairment.
Since the decibel is not an absolute measure of sound energy but a comparison with a value known as the reference value, it is possible to have negative decibels.
Therefore, a negative decibel means that the sound is quite lower or softer than this reference value or threshold.
Hence, the answer is subaudible noise.
Identify two kinds of data the student will likely collect during his experiment. Identify the type of data collected and how the student might present his data.
Answers
The two kinds of data that can be collected during an experiment are qualitative and quantitative data.
What are qualitative and quantitative data?
Numbers are used to convey quantitative data, which are measurements of values or counts. Numerical variables are the subject of quantitative data.
Qualitative data are represented by a name, symbol, or number code and are measurements of "types." Data concerning categorical variables make up qualitative data.
To provide a complete picture of a population, quantitative and qualitative data are frequently combined since they produce distinct results. For instance, if yearly income statistics are acquired (quantitative), occupation data might also be gathered (qualitative) to learn additional specifics about the average annual income for each type of profession.
Depending on whether the variable of interest is numerical or categorical, it is possible to acquire both quantitative and qualitative data from the same data unit.
Therefore, the two kinds of data that can be collected during an experiment are qualitative and quantitative data.
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which phenomenon supports the particular model of light?
Answers
Answer:
photoelectric effect
Explanation:
The photoelectric effect supports a particle theory of light in that it behaves like an elastic collision (one that conserves mechanical energy) between two particles, the photon of light and the electron of the metal.
Construct a ray diagram to determine the image.
A thin lens is located centered over a 14 cm ruler at the 7 cm mark. A black dot is located at 5.5 cm on the left side of the lens and at 8.5 cm on the right side of the lens. An arrow is located at the 3.0 cm mark.
Where is the image located?
At 8.3 cm on the ruler
At 9.4 cm on the ruler
At 10.7 cm on the ruler
At 11.5 cm on the ruler
Answers
The distance of the image formed by the lens is at 10.7 cm on the ruler.
option C.
What is the location of the image?The distance of the image is calculated by applying lens formula as shown below;
1/f = -1/u + 1/v'
where;
f is the focal length of the lens v is the image distance u is the object distanceFrom the diagram, the focal length of the lens = 8.5 cm
the object distance = 3 cm
The image distance is calculated as follows;
1/v' = 1/f + 1/u
1/v' = 1/8.5 + 1/3
1/v' = 0.45
v' = 1/0.45
v' = 2.21 cm
The position of the image on the rule is calculated as follows;
v = v' + 8.5 cm
v = 2.21 cm + 8.5 cm
v = 10.71 cm
Thus, the ray - diagram shows the position or distance of the image formed.
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ayuden ha resolver este ejercicio porfa
Answers
Answer:
un café y a seguir pensando porque no se la respuesta xd
2. Circle the best answer:
1000 Newtons
1000 Newtons
A. The forces shown above are PUSHING / PULLING forces.
B. The forces shown above are WORKING TOGETHER/OPPOSITE FORCES.
C. The forces are EQUAL/NOT EQUAL.
D. The forces DO / DO NOT balance each other.
E. The resultant force is 1000 N TO THE RIGHT / 1000 N TO THE LEFT/ZERO.
F. There IS/IS NO motion.
Answers
According to the information we can infer that the forces are PULLING forces, OPPOSITE FORCES, EQUAL, forces DO balance each other, the resultant force is ZERO, and there IS NO motion.
How to explain each element in the image?According to the information of the image, we can conclude that the forces shown above are PULLING forces because they involve pulling a rope on each side. Also, the forces shown above are OPPOSITE FORCES because they act in opposite directions, pulling the rope towards different sides.
On the other hand, the forces are EQUAL in magnitude because each side exerts a force of 1000 Newtons. Additionally, the forces DO balance each other because they have the same magnitude and act in opposite directions. The individuals on each side are exerting equal forces, resulting in a balanced system.
Finally, the resultant force is ZERO because the forces are equal in magnitude and act in opposite directions. The combined effect of the forces is no net force or resultant force and there IS NO motion because the forces are balanced, resulting in a net force of zero. In a balanced system, the objects will remain at rest or in a state of uniform motion.
Note: This question is incomplete. Here is the complete information:
Attached image
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PLEASE HELP!!!!
Do you think we will ever be able to get rid of our dependency on fossil fuels? Why or why not?
Answers
Answer:Probably because we've been so dependent on them,and we took to long to find new reusable resources.
Explanation:
TRUE OR FALSE
Scientists understand the effects of gravity, but they don't know what causes it.
Answers
Answer: false
Explanation:
Which of the following processes is not regarded as contributing to the creation of greenhouse gases?
A. deforestation
B. creating electricity from coal
C. creating electricity from wind
D. use of fertilizers
Answers
Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)
Answers
Answer:
Potential difference \(V=1.6\times 10^{-10}\ V\)
Explanation:
Capacitance of capacitor, C = 0.9 MF
Charge, \(Q=1.4\times 10^{-4}\ C\)
We need to find the amount of potential difference. We know that,
\(Q=CV\)
V is potential difference
So,
\(V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V\)
So, the required potential difference is \(1.6\times 10^{-10}\ V\).