A soccer ball is released from rest at the top of a grassy incline. After 2.2 seconds, the ball travels 22 meters. One second later, the ball reaches the bottom of the incline. (Assume that the acceleration was constant.) How long was the incline

Answer: Friction  :)        

Answer:

B) 1500m/s

Explanation:

Ans is 1500m/s

In conclusion, the experiment on the oscillation of a simple pendulum provided valuable insights into the behavior and characteristics of pendulum motion.

The results obtained during the experiment confirmed the expected relationship between the period of a pendulum and its length. It was observed that as the length of the pendulum increased, the period also increased, indicating a direct proportionality between these two variables.

This relationship aligns with the theoretical predictions of a simple pendulum, as stated by the formula T = 2π√(L/g), where T is the period, L is the length, and g is the acceleration due to gravity.

The experiment also demonstrated the effect of changing the angle of displacement on the period of the pendulum. It was observed that for small angles of displacement, the period remained constant, confirming the approximation of small angle oscillations as simple harmonic motion.

However, as the angle of displacement increased, the period deviated from the expected value, highlighting the non-linear nature of the pendulum's motion at larger angles.

Furthermore, the experiment emphasized the importance of minimizing external influences, such as air resistance and friction, to obtain accurate and reliable results. By ensuring a controlled environment and employing proper techniques, the impact of these external factors was minimized.

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Answer:  the density of ivory in SI units is 1800 kg/m^3.

Explanation: To calculate the density of ivory in SI units, we use the formula density = mass/volume. We are given the mass of 25 cm^3 of ivory as 0.045 kg. Since volume is in cm^3, we need to convert it to SI units of m^3. 1 cm^3 is equal to 1 milliliter (ml), so 25 cm^3 is equal to 25 ml. To convert ml to m^3, we use the conversion factor 1 ml = 10^-6 m^3. We then substitute the values of mass and volume into the density formula and simplify. The resulting density is expressed in units of kg/m^3, which are the SI units for density. Therefore, the density of ivory in SI units is 1800 kg/m^3.

The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).

When an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.

To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.

The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.

For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:

F ≥ mg sin(θ)

Substituting F = μN, we get:

μN ≥ mg sin(θ)

Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):

μmg cos(θ) ≥ mg sin(θ)

μ cos(θ) ≥ sin(θ)

Now, divide both sides of the equation by cos(θ):

μ ≥ tan(θ)

Taking the inverse tangent (arctan) of both sides, we get:

θ ≤ arctan(μ)

Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).

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From the darkest part of the object's shadow, you would be able to see a small amount of the light source. There would be a small amount of light that is visible, but it would be faint. On the other hand, from the lightest part of the shadow, you would be able to see much more of the light source. The light source would be far brighter and more visible, and you would be able to identify the source of the light.

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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The net electric potential at the origin due to the circular arc of charge Q1, and the two particles of charges Q2 and Q3 can be calculated by using the formula for electric potential due to a point charge:

V = (kQ)/r

Where V is the electric potential, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the point of charge to the point where we want to calculate the electric potential.

For the circular arc of charge Q1, the electric potential at the origin is:

V1 = (kQ1)/R = (8.99 x 10^9 Nm^2/C^2)(7.21 x 10^-12 C)/(2.00 m) = 1.62 x 10^-2 V

For the particle of charge Q2, the electric potential at the origin is:

V2 = (kQ2)/R = (8.99 x 10^9 Nm^2/C^2)(4.00Q1)/(2.00 m) = 4.00V1 = 6.48 x 10^-2 V

For the particle of charge Q3, the electric potential at the origin is:

V3 = (kQ3)/R = (8.99 x 10^9 Nm^2/C^2)(-2.00Q1)/(2.00 m) = -2.00V1 = -3.24 x 10^-2 V

The net electric potential at the origin is the sum of the electric potentials due to each charge:

Vnet = V1 + V2 + V3 = 1.62 x 10^-2  V  + 6.48 x 10^-2  V  - 3.24 x 10^-2  V

Vnet = 4.86 x 10^-2 V

Therefore, the net electric potential at the origin due to the circular arc of charge Q1 and the two particles of charges Q2 and Q3 is 4.86 x 10^-2 V.

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Answer:

Explanation:

Let the x axis lie along the 66 lb force with the force vector tail at the origin.

The 68 lb force would lie along a radial 77° CCW from the x axis

The resultant would have an x and y values of

Fx = 66cos0 + 68cos77 = 81.3 lb

Fy = 66sin0 + 68sin77 = 66.3 lb

F = √(81.3² + 66.3²) = 104.87 = 105 lb

θ = arctan (66.3/81.3) = 39°

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The acceleration of children will be 0.136m/s²

We are given that,

The first child exert force= F₁ =  75.0 N  

The second child exerts force = F₂ = 90.0N

The friction force = Fₓ = 12.0 N

The mass of the third child = m = 22.0 kg

The first child & second child exert force 75 N and 90 N which are acting in opposite direction.

Therefore, the net force = F₂ - F₁ = 90 - 75 = 15 N

Friction force Fₓ would be act in the direction opposite to the direction of net force. So that the friction force will act in the direction in which the first child F₁  (75 N) is acting .

Total force acting in the direction of the second child= F₁+ Fₓ=75+12= 87 N

Net force acing on the third child F = 90 - 87 = 3 N  

Therefore, the acceleration of the child can be calculated by the Newton's second law of motion i.e.

F = ma

a = F /m

a = 3N /22kg

a = 0.136 m/s²

Thus, the acceleration of the child will be  0.136 m/s²

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The acceleration of the car in three significant figures is 0.181 m/s².

The acceleration of the car is calculated by applying the following kinematic equation as shown below.

v² = u² + 2as

where;

The given parameters include the following;

the final velocity of the car = 2 m/s

the distance travelled by the car = 11 m

The acceleration of the car is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

a = v² / 2s

a = ( 2² ) / ( 2 x 11 )

a = 0.181 m/s²

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The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

plz mark me as brainliest.

Based on the information, we can infer that A. represents a Mitochondria.

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

Note: This question is incomplete. Here is the complete information:

Attached image

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Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

The main reason is that very young calves are more noticeable to predators when mixed with older calves from the previous year

Explanation:

They are forced to migrate by carnivores that hunt them.

Answer:

  1.234567 kA

Explanation:

The prefix k stands for kilo-, or 10³. The prefix m stands for milli-, or 10⁻³. The sum shown is ...

  1.234 kA + 0.000567 kA = 1.234567 kA

inside a moving elevator, in free fall

Do you weigh the same inside an elevator?

We shall weight ourselves when the elevator is travelling at our normal weight. Because we are currently moving up or down the elevator at the same speed, nothing is changing our weight. However, once the elevator begins to move or stops, our bodies resist it.

What is the apparent weight when the elevator is running?

If the elevator accelerates downward, an is negative and the apparent weight is less than the real weight. There is no weight discernible if the elevator descends naturally. The apparent weight is zero because when a human and a scale are falling freely, they cannot clash.

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Answer:

There are 75 people in the class. The number of boys is 48 and the number of girls is 27. The percentage of girls is 36% of 75.

Explanation:

Given data

*The amount of gold-198 is N = 100 g

*The amount of gold decays is n = 6.25 g

*The given number of days is T = 10.8 days

The expression for the radioactivity decay is given as

*Here t is the half-life period

Substitute the values in the above expression as

Given data

*The given mass of the apple is m = 0.75 kg

*The given height is h = 3 m

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The formula for the potential energy is given as

Substitute the known values in the above expression as

Hence, the potential energy of a 0.75 kg apple sitting 3 m off the ground is U_p = 22.05 J

Answer:

Explanation:

1. Place a cup of hot tea on a flat surface.

2. Place a thermometer in the tea and record the temperature.

3. Place a fan in front of the cup of tea and turn it on.

4. Place the thermometer in the tea again and record the temperature.

5. Compare the two temperatures and observe the difference.

6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

First we convert miles to meters and Hours minutes to seconds.

221 miles = ( 221 × 1609.344 )m = 355665.024 meters

3 hours and 40 minutes = ( 3×60×60)s + ( 40×60)s

= 10800s + 2400s

= 13200s

Now, determine the average speed.

Speed = Distance ÷ time

Speed = 355665.024m / 13200s

Speed = 26.944m/s

Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.

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Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω

According to the given data in the question, the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.

Kinetic energy is the energy that a moving physical object has due to its movement. It is defined as the energy an object possesses by virtue of its motion, and is dependent on its mass and velocity.

The kinetic energy gained by the drum is equal to the work done by the falling mass. On earth, the work done is given by:

W = mgh = (15.0 kg)(9.81 m/s²)(5.00 m) = 735.75 J

Since the drum gains 350.0 J of kinetic energy, the efficiency of the system is:

efficiency = 350.0 J / 735.75 J = 0.475

On Mars, the work done by the falling mass must also be equal to 350.0 J, but with a different value of h:

350.0 J = (15.0 kg)(3.71 m/s²)h

h = 26.0 m

Therefore, the 15.0 kg mass must fall through 26.0 m on Mars to give the same amount of kinetic energy to the drum.

The final speed of the mass just as the drum gains 350.0 J of kinetic energy can be found using the formula:

K = (1/2)mv²

where K is the kinetic energy of the mass and v is its final speed. Solving for v:

v = \(\sqrt{(2K/m)}\)

On Mars, with the same efficiency as on earth, the kinetic energy of the mass is also 350.0 J. Therefore:

v = \(\sqrt{(2(350.0 J) / 15.0 kg) }\)= 6.66 m/s

So the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.

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Answer:

It's A. White light is made up of many different wavelengths of light.