Answers
Given,
The spring constant, k=250 N/m
The compression of the spring, x=0.73 m
The mass of the weed, m=1.5 kg
The potential energy of the spring is given by,
\(U=\frac{1}{2}kx^2\)According to the law of the conservation of energy, the total energy of the spring and the weed should be conserved. That is when the spring is expanded, it loses its potential energy which is gained by the weed as kinetic energy.
Thus the potential energy of the spring is equal to the kinetic energy of the weed.
The kinetic energy of the weed is given by,
\(E_K=\frac{1}{2}mv^2\)Where v is the maximum speed of the weed.
From the law of conservation of energy,
\(\begin{gathered} \frac{1}{2}kx^2=\frac{1}{2}mv^2 \\ \Rightarrow v^2=\frac{kx^2}{m} \\ v=\sqrt[]{\frac{k}{m}}\times x \end{gathered}\)On substituting the known values,
\(\begin{gathered} v=\sqrt[]{\frac{250}{1.5}}\times0.73 \\ =9.42\text{ m/s} \end{gathered}\)Therefore the maximum speed of the block of weed is 9.42 m/s
Related Questions
Taigas, tundra and tropical rainforests share what common abiotic component?
Answers
Answer:
water
Explanation:
hope this helps
Find equivalent resistance of the following dig
Answers
The equivalent resistance between terminals a and b is 24 Ω
What is equivalent resistance?The equivalent resistance of a circuit is the total resistance of the circuit.
Given the figure, to find the equivalent resistance of between terminals a and b, we proceed as follows.
Now, we notice that the resistors between terminals a and b are the 60 Ω and 40 Ω resistors. These resistors are in parallel. So, their equivalent resistance in parallel is
1/R = 1/R₁ + 1/R₂ where R₁ = 60 Ω and R₂ = 40 Ω
So, R = R₁R₂/(R₁ + R₂)
So, substituting the values of the variables into the equation, we have that
R = R₁R₂/(R₁ + R₂)
R = 60 Ω × 40 Ω/(60 Ω + 40 Ω)
R = 2400 Ω²/(100 Ω)
R = 24 Ω
So, the equivalent resistance is 24 Ω
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You have to run 18,900 feet in track. How far is this in miles? Note: There are 5280 feet in 1 mile.
O A. 0.8 mi
O B. 2.4 mi
O C. 1.5 mi
D. 3.6 mi
Answers
The conversion factor of 5280 feet per mile is used to convert the distance, and rounding to the nearest tenth gives us approximately 3.6 miles. The correct answer is option D: 3.6 mi.
To convert 18,900 feet to miles, we can use the conversion factor of 5280 feet per mile. By dividing the distance in feet by this conversion factor, we will obtain the equivalent distance in miles.
Distance in miles = 18,900 feet ÷ 5280 feet/mile
Calculating this expression, we find:
Distance in miles = 3.57 miles
Rounding to the nearest tenth, the distance is approximately 3.6 miles.
Therefore, the correct answer is option D: 3.6 mi.
It is important to note that the conversion factor of 5280 feet per mile is derived from the definition of a mile as 5,280 feet. This conversion factor is widely used to convert measurements between feet and miles in various contexts, such as distance calculations, road signs, and sports events. Here option D is the correct answer.
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what did the biologist wear on his first date ?
Answers
Answer:
Calvin Cycles
Explanation:
This is a popular joke. Is this an answer choice for your question?
You have two flashlights that operate on 1.50-V D batteries. The first flashlight uses two batteries in a chain, and the second uses five batteries in a chain. Each flashlight has a current of 2.50 A flowing through its circuit. What power is being transferred to the bulb in each flashlight
Answers
Answer:
The first flashlight,
P = 7.5 W
The second flashlight,
P = 18.75 W
Explanation:
P = VI.................. Equation 1
Where P = Power, V = Voltage, I = current.
For the first flashlight,
Given: I = 2.5 A, and V = 1.5×2 (The first uses two battery in chain) = 3 V
Substitute into equation 1
P = 3(2.5)
P = 7.5 W.
For the second flash light,
P = VI
Given: I = 2.5 A, V = 1.5×5 ( The second uses five batteries in a chain) = 7.5 V
Substitute into equation 1
P = 2.5(7.5)
P = 18.75 W.
Ancient peoples both feared and revered Solar and Lunar Eclipses as they happened so rarely. Explain the following about eclipses:
1. Why are SOLAR eclipses more rare then lunar eclipses.
2. Explain what must occur for a SOLAR eclipse to occur.
3. Explain what must occur for a LUNAR eclipse to occur.
Answers
Answer:
Lunar and solar eclipses occur with about equal frequency. Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse. As a result, you are more likely to see a lunar eclipse than a solar eclipse.
For a total eclipse to take place, the sun, moon and Earth must be in a direct line. The second type of solar eclipse is a partial solar eclipse. This happens when the sun, moon and Earth are not exactly lined up. The sun appears to have a dark shadow on only a small part of its surface.
For a lunar eclipse to occur, the Sun, Earth, and Moon must be roughly aligned in a line
What force acts on a projectile in the horizontal direction?
Answers
The force that acts on a projectile in the horizontal direction is Gravitational force.
A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.
Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.
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A 250 kg beam is raised through 25 m at a constant velocity by a crane.
b) Determine the work done by the crane on the beam.
c) Determine the work done by gravity on the beam.
Answers
work = force × distance × cos(theta)
where force is the force exerted by the crane, distance is the distance the beam is raised, and theta is the angle between the force and the displacement.
Since the beam is raised at a constant velocity, the net force on the beam is zero, which means that the force exerted by the crane is equal in magnitude and opposite in direction to the force of gravity.
The force of gravity on the beam is given by:
force_gravity = mass × gravity
where mass is the mass of the beam and gravity is the acceleration due to gravity.
Substituting the given values, we get:
force_gravity = 250 kg × 9.81 m/s^2 = 2452.5 N
Since the net force on the beam is zero, the force exerted by the crane is also 2452.5 N, but in the opposite direction. Therefore, the work done by the crane on the beam is:
work = force × distance × cos(theta) = -2452.5 N × 25 m × cos(180°) = -61,312.5 J
The negative sign indicates that the work done by the crane is negative, which means that the crane is doing work against the force of gravity.
c) The work done by gravity on the beam is given by:
work_gravity = force_gravity × distance × cos(theta)
where force_gravity is the force of gravity on the beam, distance is the distance the beam is raised, and theta is the angle between the force and the displacement.
Substituting the given values, we get:
work_gravity = 2452.5 N × 25 m × cos(180°) = -61,312.5 J
The negative sign indicates that the work done by gravity is negative, which means that gravity is doing work against the motion of the beam. Note that the magnitude of the work done by gravity is the same as the magnitude of the work done by the crane, but with opposite sign, as expected due to the work-energy principle.
You have to run 2.2 miles in track. How far is that in feet? There are 5280 feet in 1 mile
Answers
Answer:
\(11616ft^{2}\) or 11616
Explanation:
Since there are 5280 feet in 1 mile
you do 2.2 × 5280
2.2 × 5280 = 11616
A 0.600-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 12.2 cm. (Assume the position of the object is at the origin at t = 0.)
a. Calculate the maximum value of its speed
b. Calculate the maximum value of its acceleration.
c. Calculate the value of its speed when the object is 8.60 cm from the equilibrium position.
d. Calculate the value of its acceleration when the object is 8.60 cm from the equilibrium position.
e. Calculate the time interval required for the object to move from x = 0 to x = 6.60 cm.
Answers
Answer:
a. vmax = 0.445 m/s
b. amx = 1.65 m/s^2
c. v = 0.32 m/s
d. 1.12 m/s^2
e. t = 0.21 s
Explanation:
a. The maximum speed of the object is given by the following formula:
\(v_{max}=\omega A\) (1)
w: angular frequency of the object
A: amplitude of the motion = 12.2cm = 0.122m
The angular frequency is calculated by using:
\(\omega=\sqrt{\frac{k}{m}}\) (2)
k: spring constant = 8.00 N/m
m: mass of the object = 0.600kg
you replace the equation (2) into the equation (1) and replace the values of the other parameters:
\(v_{max}=\sqrt{\frac{k}{m}}A=(\sqrt{\frac{8.00N/m}{0.600kg}})(0.122m)=0.445\frac{m}{s}\)
The maximum speed is 0.445m/s
b. The maximum acceleration is:
\(a_{max}=\omega^2 A\\\omega=\sqrt{\frac{8.00N/m}{0.600kg}}=3.65\frac{rad}{s}\\\\a_{max}=(3.65rad/s)^2(0.122m)=1.625\frac{m}{s^2}\)
The maximum acceleration is 1.65m/s^2
c. To calculate the value of the speed for x = 8.60cm you first find the time t by using the following equation of motion for a simple harmonic motion:
\(x=Asin(\omega t)\\\\t=\frac{1}{\omega}sin^{-1}(\frac{x}{A})\\\\t=\frac{1}{3.65rad/s}sin^{-1}(\frac{8.60cm}{12.2cm})=0.21s\)
You use this value of t in the following equation for v:
\(v=\omega Acos(\omega t)\\\\v=(3.65rad/s)(0.122m)cos((3.65rad/s)(0.21s))=0.32\frac{m}{s}\)
The speed of the object when it is at x = 8.60cm is 0.32m/s
d. The acceleration is:
\(a=-\omega^2 A sin(\omega t)\\\\a=-(3.65rad/s)^2(0.122m)sin((3.65rad/s)(0.21))=1.12\frac{m}{s^2}\)
The acceleration is 1.12 m/s^2
e. The time is 0.21s
The fuel is ignited in a model rocket sitting on a launch pad, which blasts the rocket upward. The rocket goes up because: Group of answer choices air friction pushes on the escaping fuel. the downward force of gravity is less than the downward momentum of the fuel. None of the above. the fuel pushes on the launch pad. the downward force of gravity is greater than the downward momentum of the fuel.
Answers
Answer: The fuel pushes on the launch pad.
Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.
Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.
28. An electron with a speed of 4.0 x 10° m/s enters a uniform magnetic field of magnitude 0.040 T at an angle of 35 degrees to the magnetic field lines. The electron will follow a helical path. a) Determine the radius of the helical path. b) How far forward will the electron have moved after completing one circle?
Answers
The radius of the helical path and the period of the electron are 3. 26* 10^-10m and 8.94*10^-10m respectively.
How to determine the radiusUsing the formula:
r = \(\frac{mvsin \alpha }{Bq}\)
m = 9.109 × 10-31 kg
α = 35°
B = 0. 040 T
q = 1.6 × 10-19 C
Substitute values into the formula
\(r = \frac{9. 109 * 10^-31 * 4.0 * 10^0 * sin 35}{0. 040 * 1.6 * 10^-19 }\)
\(r = \frac{2. 089 * 10^-30}{6. 4* 10^-21}\)
\(r = 3. 26 * 10^-10\) m
b. \(T = \frac{2\pi m}{qB}\)
\(T = \frac{2 * 3.142 * 9.109 *10^-31}{1.6* 10^-19* 0.040}\)
\(T = \frac{5. 72* 10^-30}{6. 4* 10^-21}\)
\(T = 8. 94* 10^-10\)
Therefore, the radius of the helical path and the period of the electron are 3. 26* 10^-10m and 8.94*10^-10m respectively.
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find the change in momentum of a car weighting 1900kg when its speed increases from 36km/h to 72km/h
Answers
m=1900kg
v=72_36=36km/hr=129.6m/s
p=mv
=1900kg×129.6m/s
=246240kg.m/s
Describe: On the CORAL REEF tab, click on the stoplight parrotfish, queen angelfish, yellowtail snapper, and Nassau grouper. Describe what each of these fishes eat.
Stoplight parrotfish:
Yellowtail snapper:
Queen angelfish:
Nassau grouper:
Answers
These fish have food. Yellowtail snapper, algae, stoplight parrotfish, shrimp, crabs, and worms Sponges, the queen angelfish Grouper from Nassau: Various fish.
What functions do parrotfish provide on the coral reef?All parrotfish species on coral reefs have the critical duty of preventing algae from outpacing reef-building corals. Wake Atoll's reef environment is kept healthy and diverse by bumphead parrotfish (Photo by Andrew E. Gray/NOAA Fisheries).
What is parrotfish, a fish that has the potential to restore coral reefs?Up to 90% of the time, parrotfish graze on the corals' overgrowth of algae, which helps to keep the ecological balance between the two groups of species in good shape.
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A/An breaks down a complicated goal into daily action to make it more manageable?
Answers
A routine breaks down a complicated goal into daily action to make it more manageable.
What is a routine?A routine can be described as the sequence of actions regularly followed which do help individuals as well as the organization so they can acheive their goals.
It should be noted that a routine is neccessary in an organization because it will help help them to breakdown the task as well as the activities and this will help to achive the goals as well as the neccessary things on time because allcomplicated goals woud have been included as well as how it will be carried out.
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a concave mirror has a radius of curvature of 60cm. How close to the mirror should an object be placed so that the rays travel parallel to each other after reflection
Answers
Answer:
Answer:30 cm
Answer:30 cmExplanation:
Answer:30 cmExplanation:Given=ROC= 60cm
Answer:30 cmExplanation:Given=ROC= 60cmObject be placed so that the rays that came from the object to them mirror are reflected from the mirror, and, then travel parallel to each other= 30cm at focus.
The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answers
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
A long, thin metal tube of cross-sectional area 1.60 cm2 is sealed into the top of a hollow cube of edge length 0.150 m. Water fills the cube and extends upward a distance h into the tube. Find h if the water exerts a force of 1.00 103 N on the base of the cube. What is the weight of the water?
Answers
Answer:
Explanation:
Given that:
The area of the metal tube = 1.60 cm² = 1.60 × 10⁻⁴ m²
Length of cube L = 0.150 m
The exerted force by water = 1.00 × 10³ N
At the top of the cube;
The force on water is F = pgL
F = 9.8 m/s² × (1000 kg/m³) (0.150 m)(0.150 m)²
F = 33.075 N
∴
\(pgh = \dfrac{F}{A}\)
\(h = \dfrac{F}{Apg}\)
\(h = \dfrac{33.075}{(1.60 \times 10^{-4} \ m^2) \times (1000 \ kg/m^3)(9.8)}\)
h = 21.09 m
The volume of the water V = L³
V = (0.150 m)³
V = 0.003375 m³
weight of the water w = p(V + Ah)
w = 1000 (0.003375 + (1.60 × 10⁻⁴ × 21.09))
w = 6.75 kg
3) Vector A is 2.8 cm at 60° above the positive x-axis. Vector B is 1.90 cm at 60 below the
positive x-axis. Use components to find the following
a) A+ B
b) A-B
c) B-A
Answers
The following vector components are:
a) A+ B - 84.21°
b) A-B - 18.74°
c) B-A - -84.21°
How to find vector components?To use components to find the given vectors, break each vector into its x and y components using trigonometry.
Assume the positive x-axis points to the right and the positive y-axis points up.
For vector A, the magnitude of the x-component is given by Acos(60°) and the magnitude of the y-component is given by Asin(60°),
Ax = Acos(60°) = 2.8 cm × 0.5 = 1.4 cm
Ay = Asin(60°) = 2.8 cm × 0.866 = 2.425 cm
For vector B, the negative sign since the vector is below the x-axis,
Bx = Bcos(60°) = 1.9 cm × 0.5 = 0.95 cm
By = -Bsin(60°) = -1.9 cm × 0.866 = -1.6494 cm
a) To find A + B, add the x and y components separately:
(A + B)x = Ax + Bx = 1.4 cm + 0.95 cm = 2.35 cm
(A + B)y = Ay + By = 2.425 cm - 1.6494 cm = 0.7756 cm
Then, the vector A + B has a magnitude of √[(2.35 cm)² + (0.7756 cm)²] = 2.466 cm and an angle of tan⁻¹(0.7756 cm / 2.35 cm) = 18.74° above the positive x-axis.
b) To find A - B, subtract the x and y components separately:
(A - B)x = Ax - Bx = 1.4 cm - 0.95 cm = 0.45 cm
(A - B)y = Ay - By = 2.425 cm + 1.6494 cm = 4.0744 cm
Then, the vector A - B has a magnitude of √[(0.45 cm)² + (4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(4.0744 cm / 0.45 cm) = 84.21° above the positive x-axis.
c) To find B - A, subtract the x and y components separately:
(B - A)x = Bx - Ax = 0.95 cm - 1.4 cm = -0.45 cm
(B - A)y = By - Ay = -1.6494 cm - 2.425 cm = -4.0744 cm
Then, the vector B - A has a magnitude of √[(-0.45 cm)² + (-4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(-4.0744 cm / -0.45 cm) = -84.21° below the positive x-axis.
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During the vietnam war, journalists _____. Select two choices. Called the military's press briefings "five o'clock follies" accepted the u. S. Government's justification for the war could not interview american soldiers while serving did not witness any combat on a firsthand basis.
Answers
During the Vietnam War, journalists often referred to the military's press briefings as "five o'clock follies" because they felt that the information provided was often incomplete or misleading.
The two choices that are correct are:
•Called the military's press briefings "five o'clock follies"
•Did not witness any combat on a firsthand basis.
. Additionally, due to the dangers of the conflict, many journalists did not have the opportunity to witness combat on a firsthand basis.
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An ore cart of mass 1200 kg is rolling at a speed of 12.8 m/s across a flat surface. A crane dumps 338 kg of ore into the cart from directly above it. How fast does the cart move after being loaded with ore?
Answers
ANSWER
10.0 m/s
EXPLANATION
The ore cart has a mass m1 of 1200kg, and rolls at a speed v1 of 12.8 m/s. Then a crane dumps 338 kg of extra ore into the cart, so now the mass is m2 = m1 + 338 kg = 1538 kg. We want to find the new speed v2 of the ore cart.
By law of conservation of momentum we have:
\(m_2v_2=m_1v_1_{}\)Solving for v2:
\(v_2=\frac{m_1v_1}{m_2}\)And replacing with the values:
\(v_2=\frac{1200\operatorname{kg}\cdot12.8m/s}{1538\operatorname{kg}}=10.0m/s\)The speed of the ore cart is now 10.0 m/s, rounded to the nearest tenth
A uniform brick of length 18 m is placed
over the edge of a horizontal surface with a
maximum overhang of 9 m attained without
tipping.
Now two identical uniform bricks of length
18 m are stacked over the edge of a horizontal
surface.
What maximum overhang is possible for
the two bricks (without tipping)?
Answer in units of m.
Answers
We have that the overhang possible for the two bricks are is mathematically given as
x=13.5m
Length of Overhang
Question Parameters:
A uniform brick of length 18 m
a maximum overhang of 9 m attained
Length 18 m are stacked over the edge of a horizontal
surface.
Generally the equation that balances the moment is mathematically given as
\(mg*(x-l/2)=mg(L-x)\\\\2x=3l/l\\\\x=3l/4\\\\x=3/4*18\\\\\)
x=13.5m
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Select one of the agents of socialization as the one that you think has had the
greatest impact on defining who you are and write a well-developed paragraph
explaining how it has impact on your life and helped define who you are.
Answers
Among the many agents of socialization, the one that has had the most significant impact on defining a person's identity is the family. Growing up in a family shapes a person's values, beliefs, attitudes, and behavior patterns.
The family provides the foundation for a child's socialization process, and the experiences a child has in the family can determine their outlook on life.
For example, if a child is raised in a family that values education, they are more likely to value education and strive for academic success. Likewise, if a child is raised in a family that values honesty and integrity, they are more likely to uphold these values in their interactions with others. The family is also responsible for providing emotional support, which can impact a child's mental health and self-esteem. Overall, the family is the most critical agent of socialization as it shapes a person's identity from a very young age and sets the foundation for their future relationships and interactions with society.
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A car moving at a velocity of 25m/s, so how much distance it will travel in 5 seconds?
Answers
Answer:
125 meters
Explanation:
5s= s*5 so 25*5=125 m
why don't scale models show the real distance between planets
Answers
The average speed of molecules of a 0.1 mole nitrogen gas in a container is 5103
m/s.
a/ Determine the total translational kinetic energy of the gas.
b/ Compute the energy as heat providing to the gas so that the average speed of its molecules increases to
double.
Answers
Answer: (a) The total translational kinetic energy of the gas is \(35 \times 10^{7} J\).
(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is \(8.7 \times 10^{7} J\).
Explanation:
Given: Average speed of molecules = \(5 \times 10^{3}\) m/s
Moles = 0.1 mol
(a) As the give gas is nitrogen so its mass is 28 g/mol.
Formula to calculate translational kinetic energy is as follows.
Total translational K.E = \(\frac{1}{2}mv^{2}\)
where,
m = mass
v = velocity
Substitute the values into above formula as follows.
\(Translational K.E = \frac{1}{2}mv^{2}\\= \frac{1}{2} \times 28 \times (5 \times 10^{3})^{2}\\= 35 \times 10^{7} J\)
(b) As the energy is directly proportional to the square of velocity. So, when average speed of molecules increases to double then relation between energy and velocity will be as follows.
\(E \propto (2v)^{2}\\or, E \propto 4v^{2}\\v^{2} \propto \frac{E}{4}\)
This means that velocity gets one-fourth times the energy of its molecules.
Therefore, energy will be calculated as follows.
\(Energy = \frac{35 \times 10^{7}}{4}\\= 8.7 \times 10^{7} J\)
Therefore, we can conclude that
(a) The total translational kinetic energy of the gas is \(35 \times 10^{7} J\).
(b) The energy as heat providing to the gas so that the average speed of its molecules increases to double is \(8.7 \times 10^{7} J\).
problem 1
A train starts at rest, accelerates with constant acceleration a for 5minutes,then travels at constant speed for another 5minutes,and the decelerates with a.suppose it travels a distance of 10km in all find a
problem 2
A ball is dropped from a height of 10m.At the same time, another ball is thrown vertically upwards at an initial speed of 10m/sec.How high above the ground will the two balls collide
problem 3
find the resultant of the two velocity vectors and also, find the angle that the resultant makes with the vector
Answers
The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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to determine how the electric field between the plates of the capacitor changes as the potential difference across the plates changes, the students set up an electron emitter as shown to send a beam of electrons between the plates of the capacitor. when the voltage is turned on, it is observed that the beam is deflected upward. as the voltage is increased, the electrons are deflected more. which of the following statements is supported by this observation?
Answers
the statements is supported by this observation is: The electric field between the plates is direct downwards and its strength increases with increasing voltage.
What is charged particle?Every object that has an electric charge is said to be charged. It might be an ion, such as a molecule or atom having excess or shortage of electrons in comparison to protons. However, as all elementary particles are thought to have the same charge, it may possibly be an electron, a proton, or another elementary particle.
Atoms having a positive or negative charge are known as charged particles, often known as ions. Every time an "ionic link" forms, this occurs. Electrons are the tiniest, negatively charged particles in atoms, and when two particles have differing quantities of them, they begin to interact.
Since, electron is a negatively charged particle, therefore it would always deflect towards positive plate.
So, upper plate is positive and hence electric field is direct downwards.
more defection means that electric field is getting stronger.
Thus, the statements is supported by this observation is: The electric field between the plates is direct downwards and its strength increases with increasing voltage.
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The complete question is as follows:
how can you rewrite the force formula (f=ma) to solve the acceleration?
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The force formula can be rewritten to solve the acceleration as:
acceleration = force/mass.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
From Newton's 2nd law of motion, we can write that:
Force = mass × acceleration
⇒ acceleration = force/mass.
Hence, the force formula can be rewritten to solve the acceleration as:
acceleration = force/mass.
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In the study of personality, what model includes different traits that underlie one’s basic tendencies
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In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.
What is the Five-factor model?The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.
In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.
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