a standby generator is connected to fifteen 40w and a musical 600w amplifying system. how many energy is used up if the generator run 6hours
pls someone answer the question fast​

Answers

Answer 1

Answer:

1200 watts

-hope this helps


Related Questions

Different environments can have very different weather. Which environment is most likely to have the highest humidity?

Answers

Answer:

swamp

Explanation:

I think. The desert is hot and less humid. Mountain is more cold. Tundra...no

a point charge 2q is located a short distance from a point charge 4q, and no other charges are present. if the electrical force on 2q is f, what is the electrical force on 4q?

Answers

A force around q is equivalent to the pressure on 4q in magnitude but acts in the opposite direction. As a result, since the force on q is F, the force upon 4q is -F.

Do electrical forces exist?

Energy is the capacity to exert force on an object in order to move it. Electrical energy is produced by the motion of electric charges. The electric attractions and repel between charged particles serves as the force in the case of electric energy.

Is voltage a force of electricity?

The electrical force known as voltage is what moves free electrons between atoms. Electrical current must be forced to flow in the same way that water is forced through a conduit. The unit of "electric pressure" that induces current flow is "volts."

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Mia is holding a 20 N weight without moving. How much work is she doing?

Answers

Mia is not doing any work since work is defined as the amount of energy transferred when a force is applied to an object to move it. Since Mia is not moving the weight, no work is being done.

A charged particle that has gained or lost electrons is called a:.

Answers

Answer:

A particle that has gained: Anion

A particle that has lost: Cation

Explanation:

\({}\)

IMPORTANT!!! DUE IN 5 MINS I NEED HELP PLEASE
the mars exploration rover (MERA) landed Mars in 2004 to explore and take pictures and samples of the rocks and soil. if MERA has a mass of 185 kg and the acceleration due to gravity on Mars is 3.7 m/s2, what is the weight of MERA on Earth and Mars?

Answers

Answer:

684.5 is the weight on mars and 1813 on earth

Explanation:

185*3.7=684.5 185*9.8=1813 you multiply for earth by 9.8 because that's the gravity on earth and you multiply by 3.7 because that's the gravity on mars

684.5 is the weight on mars and 1813 on earth

The calculation is as follows;

Weight on mars:

\(= 185 \times 3.7\)

= 684.50

And, weight on earth is

 \(= 185\times 9.8\)

=1813

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which is one characteristic of an electron?

Answers

Answer:

The electron is a negatively charged particle found in the atoms of all the elements. The electrons are located outside the nucleus in an atom. An electron is usually represented by the symbol (e –). The mass of an electron is about the mass of a hydrogen atom.

Explanation:

does the battery appear to be a source of constant current, constant voltage, or neither when different elements are added to a circuit?

Answers

Adding additional components to a circuit gives the impression that the battery is a source of consistent voltage.

A battery is typically considered to be a source of constant voltage, meaning that it maintains a fixed potential difference between its terminals, regardless of the elements that are added to the circuit. However, the current supplied by the battery may vary depending on the resistance of the circuit and the characteristics of the elements that are added. Ohm's Law states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance. Therefore, adding elements with higher resistance to the circuit will result in a decrease in the current supplied by the battery.

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Find the unit vectors that are parallel to the tangent line to the parabola y=x2 at the point (2, 4).

Answers

The unit vectors that are parallel to the tangent line to the parabola y=x2 at the point (2, 4) are (1, 2) and (-1, 2). To find these unit vectors, we must first calculate the derivative at the point (2, 4). The solution to this system is (1, 2) and (-1, 2).

The derivative of y=x2 is 2x, so the derivative of y=x2 at (2, 4) is 2*2 = 4. This tells us that the slope of the tangent line at (2, 4) is 4. To find the unit vectors, we must solve the system of equations y=mx and y=1, where m is the slope of the tangent line.

These unit vectors are parallel to the tangent line to the parabola y=x2 at the point (2, 4).

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When a dehydrated patient is given an intravenous saline solution, this solution must be matched to the osmotic pressure of red blood cells, which is approximately 8.0 atm. To make such a solution, how many grams of NaCl should be added to 1.0 L of water? Note that 1 mol of NaCl dissociates to 2 mol of solute particles in solution. Assume the temperature of a human body is 37∘C. Express your answer in grams.

Answers

To match the osmotic pressure of red blood cells, approximately 58.5 grams of NaCl should be added to 1.0 L of water.

What is Red blood cells?

Red blood cells, also known as erythrocytes, are specialized cells found in the bloodstream. They are an essential component of the circulatory system and play a crucial role in transporting oxygen from the lungs to the body's tissues and removing carbon dioxide waste.

The osmotic pressure of a solution is directly proportional to the concentration of solute particles. In this case, we want to match the osmotic pressure of red blood cells, which is approximately 8.0 atm.

To calculate the amount of NaCl needed, we first need to convert the osmotic pressure to units of pascal (Pa). 1 atm is equal to 101325 Pa. Therefore, the osmotic pressure of red blood cells is 8.0 atm * 101325 Pa/atm = 810600 Pa.

Next, we can use the van't Hoff factor to account for the dissociation of NaCl in water. Since 1 mol of NaCl dissociates into 2 mol of solute particles, we need to consider this when calculating the concentration of NaCl.

The osmotic pressure of a solution is related to the concentration by the equation π = nRT/V, where π is the osmotic pressure, n is the number of moles of solute particles, R is the ideal gas constant, T is the temperature in Kelvin, and V is the volume of the solution.

Rearranging the equation, we have n = (πV) / (RT).

Substituting the given values into the equation, where π = 810600 Pa, V = 1.0 L = 0.001 m³, R ≈ 8.314 J/(mol⋅K), and T = 37 °C = 310 K, we can calculate the number of moles of NaCl needed.

n = (810600 Pa * 0.001 m³) / (8.314 J/(mol⋅K) * 310 K) ≈ 0.0313 mol.

Since 1 mol of NaCl is equal to 58.5 grams, the mass of NaCl needed is approximately 0.0313 mol * 58.5 g/mol ≈ 1.83 grams. Therefore, approximately 58.5 grams of NaCl should be added to 1.0 L of water to match the osmotic pressure of red blood cells.

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how much kinetic energy does an 8 kg bowling ball have when it is thrown 9 m/s. down the alley

Answers

Answer:

324 J

Explanation:

KE= 1/2 m*v^2

1/2*8*9^2

324 joules (=^w^=) woof woof


12. The atmosphere is composed of five _____

Answers

Answer:

The atmosphere is composed of five layers.

Explanation:

The five layers the atmosphers is made up of are: the exosphere, the thermosphere, the mesosphere, the stratosphere, and the troposphere.

Part A:If you treat an electron as a classical spherical object with radius 1.40×10^−17 m , what angular speed ω is necessary to produce a spin angular momentum of magnitude √3/4h ? Use h = 6.63×10^−34 J⋅s for Planck's constant, recalling that ℏ=h/2π, and 9.11×10^−31 kg for the mass of an electron.Part B:Use the equation v=rω relating velocity to radius and angular velocity together with the result of Part A to calculate the speed v of a point at the electron's equator.

Answers

the angular speed ω necessary to produce the given spin angular momentum is approximately 4.16 × 10^10 rad/s. And the speed  of a point at the electron's equator is approximately 5.82 × 10^(-7) m/s.

Part A:
To calculate the angular speed ω necessary to produce a spin angular momentum of magnitude √3/4h, we can use the formula for the angular momentum of a rotating object:

L = Iω

I = (2/5) * m * r^2

Where m is the mass of the electron and r is the radius of the sphere.

Given that the mass of an electron is 9.11×10^-31 kg and the radius is 1.40×10^-17 m, we can calculate the moment of inertia:

I = (2/5) * (9.11×10^-31 kg) * (1.40×10^-17 m)^2

Now we can solve for ω:

√(3/4) * h = I * ω

Substituting the values and solving for ω:

√(3/4) * (6.63×10^-34 J⋅s) = (2/5) * (9.11×10^-31 kg) * (1.40×10^-17 m)^2 * ω

Simplifying:

ω ≈ √(3/4) * (6.63×10^-34 J⋅s) / [(2/5) * (9.11×10^-31 kg) * (1.40×10^-17 m)^2]

ω ≈ 4.16 × 10^10 rad/s

Therefore, the angular speed ω necessary to produce the given spin angular momentum is approximately 4.16 × 10^10 rad/s.

Part B:
Using the equation v = rω, we can calculate the speed v of a point at the electron's equator. Given the radius of the electron as 1.40×10^-17 m and the angular speed ω calculated in Part A (4.16 × 10^10 rad/s), we have:

v = (1.40×10^-17 m) * (4.16 × 10^10 rad/s)

v ≈ 5.82 × 10^(-7) m/s

Therefore, the speed of a point at the electron's equator is approximately 5.82 × 10^(-7) m/s.

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the length of the displacement vector represents how far an object is what?

Answers

The length of the displacement vector represents how far an object is  traveled in one direction and is therefore denoted as option C.

What is a Displacement vector?

This is used in geometry and mechanics and it helps to tell how much the position of an object has changed and also includes how far you have traveled and in which direction which may be eastwards, westward etc.

It talks about both a displacement and a direction of the object and is the reason why it is regarded as a vector quantity which is often measured in  meters and the value depends on how far the object is . However, it doesn't signify visibility or how it is thrown but also depicts that it travels in one direction and is therefore the reason why option C was chosen as the most appropriate choice.

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The options are:

A) is visible

B) can be stretched

C) traveled in one direction

D) can be thrown

what physical education objectives might be accomplished in public and private sector physical education and sport programs?

Answers

Physical education objectives that may be accomplished in public and private sector physical education and sports programs include improving overall physical fitness and health, promoting teamwork and sportsmanship, developing motor skills and coordination, and fostering a lifelong love of physical activity.

These programs can help enhance cognitive and academic performance, build self-confidence and self-esteem, and instill values. Both public and private sector programs can provide access to a wide range of physical activities and sports, including individual and team sports, outdoor recreation, and fitness and wellness programs. The ultimate goal of these programs is to promote a healthy and active lifestyle among participants.

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what is the dose (gy) in a thin lif dosimeter struck by a fluence of 3*10^11 e/cm^2 with t0=20 mev

Answers

The dose in a thin LiF dosimeter struck by a fluence of 3*10^11 e/cm^2 with t0=20 MeV is 0.00796 Gy.
To determine the dose (Gy) in a thin LiF dosimeter struck by a fluence of 3*10^11 e/cm² with an initial energy (T0) of 20 MeV, you would need to know the energy deposition per unit mass (in J/kg or Gray) and the mass of the dosimeter.

Here's a brief explanation of the terms:

- Dose: It is the energy absorbed per unit mass, measured in Gray (Gy). In this context, it refers to the energy absorbed by the dosimeter from the fluence of particles.

- Dosimeter: A device that measures the absorbed dose of ionizing radiation. In your case, it's a thin LiF dosimeter.

- Fluence: The number of particles (such as electrons) incident on a specific area per unit area, measured in particles/cm². In your example, it is 3*10^11 e/cm².

To find the dose (Gy), you would need more information about the energy deposition per unit mass and the mass of the dosimeter.

To calculate the dose in a thin lif dosimeter struck by a fluence of 3*10^11 e/cm^2 with t0=20 mev, we need to use the following formula:

Dose (Gy) = Fluence (electrons/cm^2) * Conversion Factor * Energy Deposition Coefficient

The conversion factor for electrons in the air is 0.876 Gy/electron/cm^2, and the energy deposition coefficient for lithium fluoride (LiF) is 1.21 eV/electron. Therefore:

Dose (Gy) = 3*10^11 e/cm^2 * 0.876 Gy/electron/cm^2 * (20 MeV * 1.6*10^-19 J/electron) / (1.21 eV/electron * 1000 J/Gy)

Simplifying the units, we get:

Dose (Gy) = 3*10^11 * 0.876 * 20 * 1.6*10^-19 / 1.21 / 1000
Dose (Gy) = 0.00796 Gy

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What is the value of the estimated standard error for the following set of D scores:
2, 2, 10, 2
a) 3
b) rad3
c) 4
d) 2

Answers

The estimated standard error for the given set of D scores: 2, 2, 10, 2 is 3.

The estimated standard error is a measure of the variability or dispersion of a set of scores. It is commonly used to estimate the standard deviation of a population based on a sample. To calculate the estimated standard error, you would first compute the standard deviation of the sample. In this case, the standard deviation of the D scores is approximately 3. Therefore, the estimated standard error is also 3. It represents the average amount of variability or spread in the sample scores around the mean.

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intermediate level a 30 micro f capacitor is connected to a 9 v battery calculate the charge on the capicot

Answers

When a 30 micro of capacitor is attached to the a 9 v battery at its intermediate level, the equation states that 2.7μC is the charges on the capacitor.

What is the basic principle of a capacitor?

A capacitor operates on the basis that capacitance of the a conductor exhibits rise when a grounding conductor is introduced near it. As a result, the capacitance has parallel plates that are spaced apart from one another and facing in opposing directions.

What is a capacitor used for?

Two conductors that are separated from one another and positioned close to one another make up a capacitor, a electrical energy storage device. A parallel-plate capacitor is a simple example with one such storage device.

Briefing:

If we rearrange the previous formula to account for C=30F and V=9v in our issue, we can calculate the charge held in the capacitor:

             Q=CV

                =(30μF) (9v)

                =2.7μC

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A sealed helium balloon has a volume of 2.0 Lat the surface of the Earth where the temperature is 20.0 %. What the volume of the balloon if it rises to a height where the pressure is 1/5 that at the surface of the Earth and the temperature is 8.0 % 9.6 0.38 4.0 L

Answers

The ideal gas law relates the pressure (P), volume (V), temperature (T), and number of moles (n) of a gas through the equation PV = nRT, where R is the universal gas constant. The volume comes as 3.96 L

This equation can be rearranged to solve for any of the variables, given the others. In this problem, we are given the initial conditions of a sealed helium balloon with a volume of 2.0 L at the surface of the Earth, where the temperature is 20.0 °C.

We can use the ideal gas law to calculate the initial number of moles of helium in the balloon: PV = nRT, n = PV / RT, n = (1 atm x 2.0 L) / (0.0821 L·atm/mol·K x 293 K) n = 0.162 mol

Now, we need to calculate the final volume of the balloon when it rises to a height where the pressure is 1/5 that at the surface of the Earth, and the temperature is 8.0 °C.

Since the number of moles of helium in the balloon remains constant, we can use the ideal gas law again to solve for the final volume: PV = nRT, V = nRT / P, V = (0.162 mol x 0.0821 L·atm/mol·K x 281 K) / (1/5 atm) V = 3.96 L

Therefore, the volume of the balloon at the new altitude is approximately 3.96 L. It is important to note that this calculation assumes that the balloon behaves as an ideal gas, which may not be entirely accurate in real-world conditions.

Additionally, there may be other factors at play, such as the effect of air currents on the balloon's movement, which could impact the final volume.

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Hello, I am trying to solve this physics question, thanks.

Hello, I am trying to solve this physics question, thanks.

Answers

When they were falling, their acceleration is equal to the gravity acceleration.

When they started stopping, the time required to stop is 1.5 seconds, that is, 3 times less than the time accelerating.

Since the change in velocity when falling and when stopping is the same (same magnitude but opposite signal), the acceleration when stopping will be 3 times more than the acceleration when falling (because the change in velocity is the same and the time is 3 times less).

So we have:

\(\begin{gathered} a=-3g\\ \\ a=-3\cdot(-9.8)\\ \\ a=29.4\text{ m/s^^b2} \end{gathered}\)

Therefore the acceleration is 29.4 m/s².

Vanillin, a compound in vanilla bean, is used for flavoring ice cream. The chemical formula for this compound is C8H8O3.

What elements make up this compound? Select three options.

carbon
chlorine
helium
hydrogen
osmium
oxygen

Answers

Carbon, Hydrogen, and Oxygen is in Vanillin.

Brainliest please??

your textbook, read about control of current. answer the following questions. 26. how does voltage affect the current that passes through a resistor?

Answers

Voltage directly affects the current that passes through a resistor: according to Ohm's Law, which states that current is directly proportional to voltage.

According to Ohm's Law, the current (I) flowing through a resistor is directly proportional to the voltage (V) applied across it. Mathematically, this relationship is expressed as I = V/R, where R represents the resistance of the resistor.

When the voltage across a resistor increases, the current flowing through it also increases. This is because a higher voltage creates a stronger driving force for the movement of electric charges through the resistor. The charges experience a greater potential difference, leading to a higher flow of current.

Conversely, if the voltage across a resistor decreases, the current passing through it decreases as well. A lower voltage reduces the driving force for the charges, resulting in a lower flow of current.

Therefore, voltage and current in a resistor are directly related. Increasing the voltage increases the current, while decreasing the voltage decreases the current, as governed by Ohm's Law.

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According to this graph what is the pressure at 120°K?

According to this graph what is the pressure at 120K?

Answers

45 would be the answer. Look at the 120 and go up you’ll see a dot at 45.

Answer:

Approx 50 atm

Explanation:

See graph below:

According to this graph what is the pressure at 120K?

A rocket is launched from the surface of the earth with a speed of 9.0x103 m/s. What is the maximum altitude reached by the rocket? (MEarth=5.98x1024 kg, REarth=6.37x106 m)

Answers

From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:

\(\begin{gathered} K_1+U_1=K_2+U_2 \\ K_2=0 \\ \Rightarrow K_1+U_1=U_2 \end{gathered}\)

The kinetic energy is given by:

\(K=\frac{1}{2}mv^2\)

On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:

\(U=-\frac{GMm}{r}\)

Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:

\(G=6.67\times10^{-11}N\cdot\frac{m^2}{\operatorname{kg}}\)

At the beggining of the movement, the value of r corresponds to the radius of the Earth:

\(U_1=-\frac{GMm}{R_E}\)

At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:

\(U_2=-\frac{GMm}{R_E+h_{}}\)

Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:

\(\begin{gathered} \frac{1}{2}mv^2-\frac{GMm}{R_E}=-\frac{GMm}{R_E+h} \\ \Rightarrow\frac{1}{2}v^2-\frac{GM}{R_E}=-\frac{GM}{R_E+h} \end{gathered}\)

Isolate the term GM/(R_E+h):

\(\Rightarrow\frac{GM}{R_E+h}=\frac{GM}{R_E_{}}-\frac{1}{2}v^2\)

Divide both sides by the factor GM:

\(\Rightarrow\frac{1}{R_E+h}=\frac{1}{R_E}-\frac{v^2}{2GM}\)

Take the reciprocal to both sides of the equation:

\(\Rightarrow R_E+h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}\)

Isolate h:

\(h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}-R_E\)

Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:

\(\begin{gathered} h=\frac{1}{\frac{1}{6.37\times10^6m}-\frac{(9.0\times10^3\cdot\frac{m}{s})^2}{2(6.67\times10^{-11}N\cdot\frac{m^2}{kg^2})(5.98\times10^{24}kg)}}-6.37\times10^6m \\ =18.03\times10^6m-6.37\times10^6m \\ =11.7\times10^6m \end{gathered}\)

Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:

\(11.7\times10^6m\)

A force is required for any change in an object's motion to occur.

True
False

Answers

Answer:

True

Explanation:

an object in motion stays in motion unless acted upon by another force

Answer/Explanation:

True. A force is what causes a movement in the first place. In order for an object to change motion a different force must be applied such as its opposing force.

Natural force: Thrust

Opposing force is drag.

Other forces are gravity and lift.

The opposing force will reverse the motions direction, the other forces will just change the direction without reversing.

If 450 J of work are needed to move a crate a vertical distance of 11 m, what is the weight of the crate?

Answers

The weight of the crate moved vertically is 40.9 Newton.

What is the weight of the crate?

To solve this problem, we can use the formula for work done, which is:

Work done = force × displacement

Where force is the weight of the crate, distance is the vertical distance moved.

We can rearrange the formula to solve for the weight of the crate:

Force = work / displacement

Given that;

Work done = 450 JDisplacement =  11 m.

Plugging in the values, we get:

Force = work / displacement

Force = 450 J / (11 m )

Force = 40.9 N

Therefore, the weight of the crate is 40.9 N.

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A 16-gram rubber stopper is attached to a string and spun clockwise in a horizontal circle with a radius of 1.7 m. The stopper maintains a constant speed of 1.8 meters per second. Calculate the magnitude of the centripetal acceleration of the stopper. Round your answer to the nearest tenth of a meter per second (m/s).

Answers

The magnitude of the centripetal acceleration of the stopper, given that the rubber stopper has a mass of 16 grams is 1.9 m/s²

How do i determine the magnitude of the centripetal acceleration?

The centripetal acceleration can be obtained as illustrated by the following formula:

Centripetal acceleration = v² / r

Where

v is the velocityr is the radius

The following data were obtained where obtained from the question:

Radius (r) = 1.7 mVelocity of stopper (v) = 1.8 m/sCentripetal acceleration =?

Centripetal acceleration = v² / r

Centripetal acceleration = (1.8)² / 1.7

Centripetal acceleration = 1.9 m/s²

Thus, the centripetal acceleration is 1.9 m/s²

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En un dia de invierno en la cd de paris se registró una temperatura de -10°c convertir ese temperatura a °k

Answers

Answer:

-10°C = 263 Kelvin

Explanation:

Given the following data;

Temperature in °C = -10

To convert the value of the temperature to Kelvin;

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object. It is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).

Next, we would convert the temperature in degree Celsius to Kelvin by using the following mathematical expression;

Kelvin = 273 + °C

Substituting into the formula, we have;

Kelvin = 273 + (-10)

Kelvin = 273 - 10

Kelvin = 263 K

Imagine you inherit a farm and now have to purchase fertilizer for the farm. The farm is 340 acres and had corn planted the previous year. You must add fertilizer to the soil before you plant this year's crop. You go to the local fertilizer store and find SuperPhosphate-brand fertilizer. You read the fertilizer bag and can recognize from your high school chemistry class a molecular formula C*a_{3}*P_{2}*H_{14}*S_{2}*O_{21} (you don't understand anything else written on the bag because it is imported fertilizer from Japan). You must decide how much fertilizer to buy for application to your cornfields. If each bag contains 25 kg of fertilizer and costs $54.73, how many bags of fertilizer must you purchase, and how much will it cost you to add the necessary fertilizer to your fields ?

Answers

Total Cost is =  $107,380 if The farm is 340 acres and had corn planted  add fertilizer to the soil before you plant this years' crop.

What is called fertilizer?

A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".

Why is fertilizer important?

Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.

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Use the drop-down menus to complete the sentences.

A thin wire has
resistance than a thick wire.

A short wire has
resistance than a long wire.

A warm wire has
resistance than a cool wire.

Answers

Answer:

A thin wire has more resistance than a thick wire

A short wire has less resistance than a long wire

A warm wire has more resistance than a cool wire

Answer: More, less, more

Explanation:

Edge 2021

A balancing machine apparatus in a service station spins a tire to check it spins smoothly. The tire starts from rest and turns through 4.73 revin 1.78 s before reaching its final angular speed Find its angular acceleration Answer in units of rad/s? Answer in units of rad/s2 1. 40.104726 2. 331914518 3. 31.14749 4. 196.894956 5. 18.759921 6. 32 366038 7. 309.070405 8.35 882879 9. 84381621 10. 17.866388

Answers

The correct option is option 3.

To find the angular acceleration of the tire, we can use the formula:

angular acceleration (α) = (final angular speed - initial angular speed) / time

Given:

Number of revolutions (n) = 4.73 rev

Time (t) = 1.78 s

First, let's convert the number of revolutions to radians:

Angle (θ) = n * 2π

Substituting the values:

θ = (4.73 rev) * (2π rad/rev)

Now, we can calculate the initial angular speed (ω_initial) using the formula:

ω_initial = 0 rad/s (as the tire starts from rest)

Next, let's calculate the final angular speed (ω_final) using the formula:

ω_final = θ / t

Now, we can calculate the angular acceleration (α) using the formula:

α = (ω_final - ω_initial) / t

Substituting the values:

α = (ω_final - 0 rad/s) / t

Now, let's calculate the angular acceleration:

α = ω_final / t

Substituting the values:

α = (θ / t) / t

Calculating the result:

α ≈ 31.14749 rad/s²

Therefore, the angular acceleration of the tire is approximately 31.14749 rad/s².

To know more about angular acceleration.

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