A steel cylindrical pressure vessel has an inside diameter of 2m and a wall thickness of 2cm. If the steel has a yield stress Y= 425 MPa, calculate the tank pressure that would just cause yielding of the tank material:

Answer:

Land capability is one aspect of land classification. For the determination of land capability, the usefulness of land for agriculture, forest and tourism is assessed solely on the basis of physical environmental factors.

Hence the capability denotes

The statement "The total power delivered to a pure inductor is dissipated in the form of heat" is false because the opposition to the flow of current in the coil is known as inductive reactance, which is measured in ohms.

When an electrical current flows through an inductor, it generates a magnetic field that produces a back EMF that opposes the current's direction. The power is not dissipated as heat but rather stored in a magnetic field when an ideal inductor is connected to a circuit. The inductor acts as a storehouse for magnetic energy in this scenario. When the circuit's magnetic field is developed, the inductor begins to release energy, which is then transformed into electrical energy, in an effort to preserve the magnetic field.

Power factor is the ratio of true power to apparent power in a circuit. True power is the power that is consumed by a load, while apparent power is the power that is drawn from the source. The power that is lost during the transmission of electrical energy from the source to the load is referred to as reactive power. Power factor can be calculated using the following formula:PF = True power (W) / Apparent power (VA)Hence, the total power delivered to a pure inductor is not dissipated in the form of heat, but instead, it is stored in the magnetic field.

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False.The total power delivered to a pure inductor is not dissipated in the form of heat. Instead, it is stored in the magnetic field surrounding the inductor.

This is because inductors store energy in the magnetic field that surrounds them when a current flows through them. Therefore, a pure inductor has zero resistance, which means that the power consumed by it is not dissipated in the form of heat but is instead stored as a magnetic field.As a result, in an AC circuit, the total power delivered to a pure inductor will fluctuate between positive and negative values because the stored energy is continually being alternated between the magnetic field and the electrical circuit. This can be represented by the formula: P = VIcosθ, where V is the voltage across the inductor, I is the current flowing through the inductor, and θ is the phase angle between the voltage and the current.So, the statement "The total power delivered to a pure inductor is dissipated in the form of heat" is false.

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Answer:

Water pressure is greatest at point B where the diameter is larger

Explanation:

This is due to Bernoulli's Equation: \(P_{A} +\frac{pv _{A}^{2} }{2} +pgh_{A}=P_{B} +\frac{pv _{B}^{2} }{2} +pgh_{B}\)

and Continuity Equation: \(p_{A} v_{A}A_{A}=p_{B} v_{B}A_{B}\)

where...

P = Pressure of Fluid at the Center of the Pipe

ρ = Density of Fluid

v = Velocity of Fluid

g = Gravitational Constant

h = Height of Fluid at the Center of the Pipe

A = Area of Pipe Cross Section

This is the same as saying the following:

Pressure Energy (\(P\)) + Kinetic Energy (\(\frac{pv _{}^{2} }{2}\)) + Potential Energy (\(pgh_{}\)) = Constant

The height of flow at the center of the pipe is the same, so we know that Potential Energy cancels out on both sides of the equation (Δ\(pgh_{}\) = 0)

\(P_{A} +\frac{pv _{A}^{2} }{2} =P_{B} +\frac{pv _{B}^{2} }{2}\)

Now that we've simplified Bernoulli's Equation, we need to determine which Pressure is greater using Continuity Equation.

\(p_{A} v_{A}A_{A}=p_{B} v_{B}A_{B}\)

Density is the same, so we can cancel this out on both sides of the equation (Δρ = 0)

\(v_{A}A_{A}=v_{B}A_{B}\)

From the problem statement, we know that \(A_{A} < A_{B}\)

Since \(A_{A} < A_{B}\), we know that \(v_{A} > v_{B}\) due to the Continuity Equation.

Answer: Jumping back to Bernoulli's Equation, we know that \(P_{A} < P_{B}\)

Answer:

I am thick but I dont know the anwser

The time that it will take for the outer surface of the wall to reach a temperature of 750 degree C will be 33800 seconds.

Using the approximation methods, Fo will be;

= In(0.215/1.262)/(1.4289)²

= 0.867

Then, the time taken will be:

= 0.867(0.15)²/(1.5/2600 × 1000)

= 33800 seconds.

In conclusion, the time taken is 33800 seconds.

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(a) The hourly production rate of the machine:
Formula for hourly production rate is as follows: (Time available per day * Working days) / Cycle timeHourly production rate = (24* 300) / 50 = 1440
Main answer: The hourly production rate of the machine is 1440.

(b) The annual quantity of pieces (or products) molded:
Formula for Annual quantity of pieces is as follows: Production Rate * Annual hoursAnnual quantity of pieces = 1440 * 6000 = 8,640,000
Main answer: The annual quantity of pieces (or products) molded is 8,640,000.
(c) The cost per piece:
Explanation 1: The cost of the mold is AED 1,000,000 and it can produce 1,000,000 flip-flops. Therefore, the cost per piece is AED 1,000,000 / 1,000,000 = AED 1.
Explanation 2: The cost of the molding compound for each flip-flop is AED 5. Therefore, the total direct material cost is AED 5.

The total direct labor cost for each flip-flop is AED 20 / 2 (as the labor works for only 50% of his time on this machine) = AED 10.
The overhead cost per flip-flop can be calculated as follows: Equipment overhead cost per hour = 30% * AED 500,000 / 6000 = AED 25 per hour.Overhead cost per flip-flop = AED 25 / 1440 = AED 0.0174Total cost per piece = Direct Material cost + Direct labor cost + Overhead cost per piece = AED 5 + AED 10 + AED 0.0174 = AED 15.0174
Main answer: The cost per piece is AED 15.0174.

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Answer:

Bourdon Tube gauge

Explanation:

The most popular type of pressure gauge in several countries is the Bourdon pressure tube gauge, that is used to determine medium and high loads. Bourdon tube  will measure pressures ranging between 600 mbar - 4,000 bar. While the inner pressure is greater than the exterior pressure, the tube pushes forward, and vise versa.

Answer:

Every measuring quantity has a unit.

Explanation:

Ampere or A is the  measuring unit of current intensity.

Farad or F is the measuring unit of electrical capacitance.

Ohm or Ω is the  measuring unit of electrical resistance.

Henry  or H is the  measuring unit of inductance

Volts or V is the  measuring unit of voltage

Watts or W is the  measuring unit of power.

Answer:

25,000 mph or around 40,000 kph

Explanation:

all depends on the altitude and weather conditions but this is average

Answer:

subcontracting

Explanation:

I hope this is right

Answer:

I believe the answer is 0.138

Answer :

Im not really sure tbh

Explanation:  Water at 15°C is heated by passing it through 2-cm internal-diameter thin-walled copper tubes. Heat is supplied to the water by steam that condenses outside the copper tubes at 120°C. If water is to be heated to 65°C at a rate of 0.2 kg/s, determine (a) the length of the copper tube that needs to be used and (b) the pumping power requirement to overcome pressure losses. Assuming the entire copper tube to be at steam temperature of 120°C

Answer:

The goal of the software is to observe the software behavior to meet its requirement expectation. In software engineering, validating software might be harder since client's expectation may be vague or unclear.

Explanation:

✅C) Avoid having to use a net ✅

IamSugarBee

Answer:

Explanation:

The corresponding binary voltage levels in digital circuits have two states: a high-voltage state denoted VH corresponding to logical 1 and a low voltage state denoted VL corresponding to logical 0. In electronic digital systems, a transistor is used as a switch.

Image result for explain how Voltage levels are interpreted by a digital circuit

CMOS gate circuits have input and output signal specifications that are quite different from TTL. For a CMOS gate operating at a power supply voltage of 5 volts, the acceptable input signal voltages range from 0 volts to 1.5 volts for a “low” logic state, and 3.5 volts to 5 volts for a “high” logic state.

A software engineer might engage in any of the following activities that could be deemed illegal, immoral, and unethical:
Software piracy, security breaches, data theft, software spying or snooping, creating viruses or other harmful code, intentionally producing defective code, and knowingly releasing software with bugs or security flaws.


Creating software that serves a beneficial social or moral purpose, such as software that promotes environmental sustainability, public safety, and public health. Software that serves the public good is legal, but some software might have unintended or unforeseen ethical implications.

According to the IEEE code of ethics, engineers should support and participate in pro bono and charitable work that promotes the public good. Therefore, as a software engineering company owner, you should allow your employees to do pro bono work on company time as long as it does not interfere with their assigned tasks or affect the company's productivity.

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Align the OTA antenna to the broadcast tower by pointing it towards the strongest signal and adjusting the angle for optimal reception.

The height of an OTA (over-the-air) antenna is determined by several factors, including the frequency of the signal being received, the surrounding terrain and buildings, and any nearby sources of interference. In general, the higher the antenna is positioned, the better the signal reception. The antenna should be placed on the roof or on a tall mast above the roofline for optimal signal reception in most homes. In some cases, an amplifier or signal booster may be required to compensate for signal losses caused by long cable runs or other factors. For optimal performance, professional installation and tuning may be required.

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Answer:

See explanation below

Explanation:

Hypo-eutectoid steel has less than 0,8% of C in its composition.

It is composed by pearlite and α-ferrite, whereas Hyper-eutectoid steel has between 0.8% and 2% of C, composed by pearlite and cementite.

Ferrite has a higher tensile strength than cementite but cementite is harder.

Considering that hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains whereas hypereutectoid steel contains a higher amount of cementite, the following properties are obtainable:

Hypo-eutectoid steel has higher yield strength than Hyper-eutectoid steel

Hypo-eutectoid steel is more ductile than Hyper-eutectoid steel

Hyper-eutectoid steel is harder than Hyper-eutectoid steel

Hypo-eutectoid steel has more tensile strength than Hyper-eutectoid steel.

When making a knife or axe blade, I would choose Hyper-eutectoid steel alloy because

1. It is harder

2. It has low cost

3. It is lighter

When making a die to press powders or stamp a softer metals, I will choose hypo-eutectoid steel alloy because

1. It is ductile

2. It has high tensile strength

3. It is durable

Answer:

(a)

Steels having carbon within 0.02% – 0.8% which consist of ferrite and pearlite are known as hypoeutectoid steel.

Steels having greater than 0.8% carbon but less than 2.0% are known as hypereutectoid steel.

(b)

The proeutectoid ferrite formed at a range of temperatures from austenite in the austenite+ferrite region above 726°C. The eutectoid ferrite formed during the eutectoid transformation as it cools below 726°C. It is a part of the pearlite microconstiutents . Note that both hypereutectoid and hypoeutectoid steels have proeutectoid phases, while in eutectoid steel, no proeutectoid phase is present.

Proeutectoid signifies is a phase that forms (on cooling) before the eutectoid austenite decomposes. It has a parallel with primary solids in that it is the first phase to crystallize out of the austenite phase. If the steel is hypoeutectoid it will produce proeutectoid ferrite and if it is hypereutectoid it will produce proeutectoid cementite.  The carbon concentration for both ferrites is 0.022 wt% C.

(c)

(i) Yield strength: The hypoeutectoid steel have good yield strength and hypereutectoid steels have little higher yield strengh.

(ii) Ductility: The hypoeutectoid steel is more ductile and the ductility has decreased by a factor of three for the eutectoid alloy. In hypereutectoid alloys the additional, brittle cementite on the pearlite grain boundaries further decreases the ductility of the alloy. The proeutectoid cementite restricts plastic deformation to the ferrite lamellae in the pearlite.

(iii) Hardness:  hypoeutectoid steels are softer and hypereutectoid steel contains low strength cementite at grain boundary region which makes it harder than hypoeutectoids.

(iv) Tensile strength: Grain boundary regions of hypereutectoid steel are high energy regions prone to cracking because of cementite in the grain boundaries, its tensile strength decreases drastically even though pearlite is present. Hypoeutectoid steel contains ferrite at grain boundaries and pearlite inside grains, so grain boundaries being the high energy state region, it has a higher tensile strength.

(d)

I would recommend hypereutectoid steel alloy to make a knife or ax blade

1- Hardness is required at the surface of the blades.

2- Ductility is not needed for such application.

3- Due to constant impact, the material will not easily yield to stress.

(e)

I would choose a hypoeutectoid steel alloy to make a steel that was easy to machine.

1- hypoeutectoid steel alloys have high machinability, hence better productivity

2- It will be used on softer metals, hence its fitness for the application

3- Certain amount of ductility is required which hypoeutectoid steel alloys possess.

Explanation:

See all together above

I. Systematic review of the thesis topicIn recent times, the consumption of energy has been on the rise, with the world’s energy demands expected to rise by at least 30% by 2040, and renewable energy providing at least 50% of all energy needs. This growth rate has called for the need for better storage capacity and the optimization of renewable energy. Storage and optimization of renewable energy have emerged as the critical drivers of the global energy transition. Energy storage and optimization have the potential to enhance the efficiency of renewable energy systems and promote the integration of renewable energy into existing grids. Hierarchical control is the ideal control method to achieve optimization. This paper presents a systematic review of the literature and the most recent findings on the optimization of renewable energy and energy storage by reducing costs using hierarchical control.

II. Possible objectives of the thesisThe main objective of this thesis is to optimize renewable energy and energy storage capacity while reducing costs by applying hierarchical control. This objective is achieved by exploring the following objectives:To review the most recent literature on the optimization of renewable energy and energy storage capacity.To review the most recent literature on hierarchical control in renewable energy systems.To develop a hierarchical control algorithm for renewable energy systems using renewable energy data.To design and optimize energy storage systems in renewable energy systems.To examine the possibility of integrating renewable energy into the existing grid network.To optimize energy management systems in renewable energy systems.To minimize energy costs by optimizing renewable energy and energy storage capacity.

III. Framework of the thesisThe framework of this thesis is based on the research objectives. The paper starts with an introduction, which includes background information, research aims and objectives, research questions, and hypothesis. Chapter two covers a systematic literature review of the most recent studies on the optimization of renewable energy and energy storage capacity. Chapter three discusses hierarchical control, including the fundamental principles of hierarchical control, the advantages of hierarchical control, and the application of hierarchical control in renewable energy systems. Chapter four discusses the hierarchical control algorithm and energy management systems, including the development of hierarchical control algorithms and energy management systems in renewable energy systems. Chapter five covers energy storage optimization, which includes the optimization of energy storage capacity and the design of energy storage systems in renewable energy systems. Chapter six discusses the integration of renewable energy into existing grid networks, including the feasibility and challenges of integrating renewable energy into the grid network. Finally, chapter seven summarizes the research findings, highlights the contributions, limitations, and recommendations for future research, and concludes the research.

IV. Hypothesis of the thesisThe hypothesis of this thesis is that optimizing renewable energy and energy storage capacity using hierarchical control will significantly reduce the cost of renewable energy and energy storage, increase the efficiency and reliability of renewable energy systems, and promote the integration of renewable energy into the existing grid network.

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The results are very close, and when plotted, the differences are visually indistinguishable. This shows that the hand and MatLab results agree very closely.

In a general sense, something that is indistinguishable cannot be differentiated between two or more items or entities. This could refer to physical items, such as two identical objects, or it could refer to intangible things, such as two indistinguishable sounds or emotions. When something is indistinguishable, it means that the differences between the items or entities are too small or too subtle to be noticed. In some cases, two or more items might appear to be identical, even though there may be slight differences that are difficult to detect.

The hand and MatLab results are very similar, but not exact due to numerical precision. However, when plotted, they are nearly indistinguishable. The MatLab result is:
f(t) = 6 + 10*exp(-5*t)*cos(3*t)
When converted to degrees, this is:
f(t) = 6 + 10*exp(-5*t)*cos(3*t + 126.891°).
The results are very close, and when plotted, the differences are visually indistinguishable. This shows that the hand and MatLab results agree very closely.

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The correct option that represents source reduction in the 'Pollution Prevention Hierarchy' for air pollution control is:

a. Turning off appliances and lighting when not in use.

Source reduction focuses on minimizing or eliminating the generation of pollutants at their source, thereby reducing the need for pollution control measures. By turning off appliances and lighting when not in use, energy consumption is reduced, resulting in lower emissions from power generation sources. This action helps prevent air pollution by reducing the release of pollutants associated with electricity production.

Desulfurizing fuel before power generation (option b) is an example of pollution control rather than source reduction. It aims to reduce the emissions of sulfur dioxide (SO2) during the combustion of fossil fuels, but it does not eliminate the generation of pollutants at the source.

Installing electrostatic precipitators (option c) is also a pollution control measure rather than source reduction. It aims to capture and remove particulate matter emitted from coal-fired power stations but does not address the root cause of pollution.

Switching from coal-fired power generation to renewable energy (option d) is an example of a more sustainable and environmentally friendly approach. It represents a shift away from a pollutant-intensive energy source to one that generates cleaner energy. However, it is not specifically classified as source reduction within the given options.

Therefore, the correct option representing source reduction in the context of the 'Pollution Prevention Hierarchy' for air pollution control is a. Turning off appliances and lighting when not in use.

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Polarity is the state of charge that decides the flow of electric current. Technician A is correct in stating this fact, and technician B is also correct because polarity does not produce current flow.

Polarity is a characteristic that shows the presence of an electrical charge at the ends of a conductor. Electrical current flows from an area of higher polarity to an area of lower polarity. In other words, it flows from positive to negative terminals. The polarity of a conductor is an essential consideration when designing or repairing electrical circuits. Hence, technician A is correct in stating that polarity is merely the state of charge in the circuit.Technician B is also correct in saying that polarity does not produce current flow.

Polarity is responsible for establishing the flow of electrical current. Current flows through a circuit because of the difference in polarity at the two ends of the conductor. As a result, technician B's statement is true because polarity only establishes the flow of current, and it is not responsible for producing current flow. Therefore, both technician A and technician B are correct in their statements.In conclusion, the right answer is that both technician A and technician B are correct.

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Answer:

Explanation:

Here is an example of a binary search tree (BST) implementation in Python using a list:

class BST:

   def __init__(self, data):

       self.root = [data, [], []]

   def insert_left(self, data):

       if self.root[1] == []:

           self.root[1] = [data, [], []]

       else:

           t = BST(data)

           t.root[1] = self.root[1]

           self.root[1] = t.root

   def insert_right(self, data):

       if self.root[2] == []:

           self.root[2] = [data, [], []]

       else:

           t = BST(data)

           t.root[2] = self.root[2]

           self.root[2] = t.root

   def get_left_child(self):

       return self.root[1]

   def get_right_child(self):

       return self.root[2]

   def set_root_val(self, data):

       self.root[0] = data

   def get_root_val(self):

       return self.root[0]

This implementation uses a list to represent the nodes of the tree. Each node contains the data value, and the indices of the left and right child nodes (which are also lists).

To create a BST object, we can use the following code:

python

Copy code

my_bst = BST(5)

my_bst.insert_left(3)

my_bst.insert_right(8)

This creates a BST with a root node of 5, a left child node of 3, and a right child node of 8.

We can access and modify the values of the nodes using the methods get_root_val, set_root_val, get_left_child, and get_right_child. For example:

print(my_bst.get_root_val())  # output: 5

my_bst.set_root_val(7)

print(my_bst.get_root_val())  # output: 7

print(my_bst.get_left_child().get_root_val())  # output: 3

This code sets the root value to 7, and then prints the root value and the value of the left child node. The output should be:

7

3

The maximum capillary rise and tube diameter for this maximum-rise case will be d=0.414× 10⁻⁴ m.

What do you mean by tube?

A tube, also known as tubing, is a long hollow cylinder that is used to transport fluids (liquids or gases) or to protect electrical and optical cables and wires.

Given that, P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water = 1000kg/m³

So the capillarity rise h

h=ΔP/ρg

h= (100×1000-4×1000)/(1000×10)

h= 9.61 m

We know that for capillarity rise h

h=2σcosθ/rρg

r = 2σcosθ/hρg

r = (2×1cos4°)/(9.61×1000×10)

r = 0.207×10⁻⁴m

d=0.414× 10⁻⁴ m

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Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

Answer:

Hello your question is incomplete attached below is the complete question

answer :

I) P = t/R * 492.85

II) The final equation : PR / t  + 4M/πR3 =  б e

Explanation:

attached below is a detailed solution to the given problem

i) P = t/R * 492.85

ii) Final equation : PR / t  + 4M/πR3 = б e

To help you simplify the given rational expression using the provided terms. The expression is:

\(\frac{n^2+5n-24}{n^2-11n+24}\)

Step 1: Factor the numerator and the denominator.
To do this, we look for two numbers that multiply to the constant term and add to the coefficient of the linear term.

Numerator: \(n^2+5n-24\)
Factors: (n - 3)(n + 8), because (-3) * 8 = -24 and (-3) + 8 = 5.

Denominator: \(n^2-11n+24\)
Factors: (n - 3)(n - 8), because (-3) * (-8) = 24 and (-3) - 8 = -11.

Step 2: Rewrite the expression with the factored terms.
\(\frac{(n - 3)(n + 8)}{(n - 3)(n - 8)}\)

Step 3: Cancel out the common factors.
Since (n - 3) is in both the numerator and the denominator, we can cancel it out.

\(\frac{\cancel{(n - 3)}(n + 8)}{\cancel{(n - 3)}(n - 8)}\)

Step 4: Write the simplified expression.
\(\frac{n + 8}{n - 8}\)

So, the simplified rational expression is \(\frac{n + 8}{n - 8}\).

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The name of the German company Siemens' trade name for computer numerical controls is Sinumerik.

Computer Numerical Controls (CNC) is a technological system for automating a wide range of machining operations. CNC systems usually consist of a computer processor and a series of servo motors that move the machine's axes along set directions. The name of the German company Siemens' trade name for computer numerical controls is Sinumerik.
Sinumerik, one of Siemens' most well-known trade names for its CNC systems, is now one of the world's most popular CNC systems.
Sinumerik CNC systems are known for their accuracy, dependability, and ease of use.

The systems provide a variety of advanced features that enable users to streamline machining operations and achieve greater precision, speed, and efficiency.

These features include advanced machine monitoring and analysis capabilities, real-time error detection and correction, automatic tool changing, and more.
Siemens' CNC systems are used in a wide range of industries, including aerospace, automotive, energy, medical, and more.

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Answer:

The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.

The wind turbine makes a daily revenue of 1736.75 US dollars.

Explanation:

First, we have to determine the stored energy of wind (\(E_{wind}\)), measured in Joules, by means of definition of Kinetic Energy:

\(E_{wind} = \frac{1}{2}\cdot \dot m_{wind}\cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1)

Where:

\(\dot m_{wind}\) - Mass flow of wind, measured in kilograms per second.

\(\Delta t\) - Time in which wind acts in a day, measured in seconds.

\(v_{wind}\) - Steady wind speed, measured in meters per second.

By assuming constant mass flow and volume flows and using definitions of mass and volume flows, we expand the expression above:

\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot \dot V_{air} \cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1b)

Where:

\(\rho_{air}\) - Density of air, measured in kilograms per cubic meter.

\(\dot V_{air}\) - Volume flow of air through wind turbine, measured in cubic meters per second.

\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot A_{c}\cdot \Delta t\cdot v_{wind}^{3}\) (Eq. 2)

Where \(A_{c}\) is the area of the wind flow crossing the turbine, measured in square meters. This area is determined by the following equation:

\(A_{c} = \frac{\pi}{4}\cdot D^{2}\) (Eq. 3)

Where \(D\) is the diameter of the wind turbine blade, measured in meters.

If we know that \(\rho_{air} = 1.25\,\frac{kg}{m^{3}}\), \(D = 100\,m\), \(\Delta t = 86400\,s\) and \(v_{wind} = 8\,\frac{m}{s}\), the stored energy of the wind in a day is:

\(A_{c} = \frac{\pi}{4}\cdot (100\,m)^{2}\)

\(A_{c} \approx 7853.982\,m^{2}\)

\(E_{wind} = \frac{1}{2}\cdot \left(1.25\,\frac{kg}{m^{3}} \right) \cdot (7853.982\,m^{2})\cdot (86400\,s)\cdot \left(8\,\frac{m}{s} \right)^{3}\)

\(E_{wind} = 2.171\times 10^{11}\,J\)

Now, we proceed to determine the quantity of energy from wind being used by the wind turbine in a day (\(E_{turbine}\)), measured in joules, with the help of the definition of efficiency:

\(E_{turbine} = \eta\cdot E_{wind}\) (Eq. 4)

Where \(\eta\) is the overall efficiency of the wind turbine, dimensionless.

If we get that \(E_{wind} = 2.171\times 10^{11}\,J\) and \(\eta = 0.32\), then the energy is:

\(E_{turbine} = 0.32\cdot (2.171\times 10^{11}\,J)\)

\(E_{turbine} = 6.947\times 10^{10}\,J\)

The wind turbine generates \(6.947\times 10^{10}\) joules of electricity daily.

A kilowatt-hours equals 3.6 million joules. We calculate the equivalent amount of energy generated by wind turbine in kilowatt-hours:

\(E_{turbine} = 6.947\times 10^{10}\,J\times\frac{1\,kWh}{3.6\times 10^{6}\,J}\)

\(E_{turbine} = 19297.222\,kWh\)

The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.

Lastly, the revenue generated per day can be found by employing the following:

\(C_{rev} = c\cdot E_{turbine}\) (Eq. 5)

Where:

\(c\) - Unit price, measured in US dollars per kilowatt-hour.

\(C_{rev}\) - Revenue generated by the wind turbine in a day, measured in US dollars.

If we know that \(c = 0.09\,\frac{USD}{kWh}\) and \(E_{turbine} = 19297.222\,kWh\), then the revenue is:

\(C_{rev} = \left(0.09\,\frac{USD}{kWh} \right)\cdot (19297.222\,kWh)\)

\(C_{rev} = 1736.75\,USD\)

The wind turbine makes a daily revenue of 1736.75 US dollars.

The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

The thickness of the aluminum can be determined using from distance of closest approach of the particle.

\(K.E = \frac{2KZe^2}{r}\)

where;

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.

Charge of alpah particle = 2e

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

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Armature is the component of a DC motor receives the electric current, Thus, the correct option is option B.

Any rotary electric motor in the class of DC motors that transforms direct current (DC) electrical energy into mechanical energy is referred to as a DC motor. The most popular kinds rely on the forces created by induced magnetic fields as a result of current flowing through the coil. To periodically change the direction of current in a specific area of the motor, nearly all types of DC motors have some internal mechanism, either electromechanical or electronic.

Since direct-current lighting systems already in place could be used to supply power, DC motors were the first type of motors that were widely used. By adjusting the supply voltage or the amount of current flowing through a DC motor's field windings, the speed of the motor can be varied over a wide range.

Learn more about DC motor

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