A straight razor is properly balanced when the weight distribution between the blade and the handle is even, allowing for comfortable and precise shaving.
Balanced straight razors enable users to achieve a smooth shave without applying excessive pressure, reducing the risk of nicks and irritation. The balance point is typically located near the pivot point, where the blade connects to the handle, ensuring a comfortable grip and efficient cutting motion. When selecting a straight razor, consider the blade length, width, and material, as well as the handle design and materials. High-quality steel blades provide a sharp, durable edge, while ergonomic handles made from materials like wood, metal, or resin ensure a secure grip. Proper maintenance, including regular stropping and honing, is crucial to maintaining the balance and performance of a straight razor. By keeping the blade sharp and clean, you can prolong its lifespan and ensure consistent, comfortable shaves. In conclusion, a balanced straight razor is crucial for a comfortable and precise shaving experience. By choosing a razor with a well-distributed weight between the blade and handle, and maintaining its sharpness and cleanliness, you can enjoy the benefits of a traditional straight razor shave.
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Gallium has an orthorhombic structure with a = 0.45258 nm, b = 0.45186 nm, and c = 0.76570 nm. The atomic radius is 0.1218 nm. The density is 5.904 g/cm3 , and the atomic weight is 69.72 g/mol. Determine the number of atoms in each unit cell and the packing factor in the unit cell.
Answer:
Number of atoms will be "8 atoms/cell". The further explanation is given below.
Explanation:
The given values are:
a = 0.45258 nm
b = 0.45186 nm
c = 0.76570 nm
Atomic radius = 0.1218 nm
Density = 5.904 g/cm³
Atomic weight = 69.72 g/mol
Now,
The volume of unit cells will be:
⇒ \(V=a_{0}b_{0}c_{0}\)
On putting the estimated values, we get
⇒ \(=0.45258\times 0.45186\times 0.76570\)
⇒ \(=0.1566 \ nm^3\)
⇒ \(=1.56\times 10^{-22} \ cm^3\)
(a)...
From equation of density we get,
⇒ \(Density=\frac{(x \ atoms/cell)(Atomic weight)}{(Volume)(6.02\times 10^{23} \ atoms/mol)}\)
⇒ \(5.904=\frac{x\times 69.72}{(1.566\times 10^{-22})(6.02\times 10^{23})}\)
⇒ \(x=8 \ atoms/cell\)
(b)...
From equation of PF we get,
⇒ \(PF=\frac{(3 \ atoms/cell)(\frac{411}{3} )(0.1218)}{0.1566}\)
⇒ \(= 0.387\)
The number of atoms in each unit cell and the packing factor in the unit cell are;
a) Number of atoms in each unit cell = 8 atoms
b) Atomic packing factor = 0.3876
We are given;
a = 0.45258 nm ≈ 0.45258 × 10^(-7) cm
b = 0.45186 nm = 0.45186 × 10^(-7) cm
c = 0.76570 nm = 0.7657 × 10^(-7) cm
Atomic radius; r = 0.1218 nm = 0.1218 × 10^(-7)
density; ρ = 5.904 g/cm³
Atomic weight = 69.72 g/mol
Avogadro's number = 6.02 × 10²³ atom/mol
a) The number of atoms per cell is calculated by clearing it from the equation;
Number of atoms/cell = (ρ × cell volume × Avogadro number)/atomic weight
Where;
cell volume = a × b × c
Cell volume = 0.45258 × 10^(-7) × 0.45186 × 10^(-7) × 0.7657 × 10^(-7)
Cell volume = 1.5659 × 10¯²² cm³
Thus;
Number of atoms per cell = (5.904 × 1.5659 × 10¯²² × 6.02 × 10²³)/69.72
Number of atoms per cell = 7.9 atoms
Number of atoms per cell = 8 atoms
b Formula for the packing factor is calculated from the formula:
FE = (number of atoms per cell x atom volume)/cell volume
Formula for atom volume is;
Atom volume = 4πr³/3
Atom volume = (4π × 0.1218 × 10^(-7))³/3
Atom volume = 7.5875 × 10¯²⁴ cm³
Thus;
FE = (8 x 7.5875 x 10¯²⁴)/(1.5659¯²²)
FE = 0.3876
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Transcribed image text: Which choice is a good reason to segment a network? Network segments that are more accessible to the Internet are known by what new term? Screened subnet Enhanced subnet None of these
The choice is a good reason to segment a network as the network segments that are more accessible to the Internet are known by new term is screened subnet.
What do subnet masks mean?A subnet mask is a 32-bit numeral formed by setting keeper bits to all 0s and developing network times to all 1s. In this way, the subnet mask divides the IP speech into the network and host addresses.
A subnet mask is used to separate an IP address into two pieces. One element defines the host (computer), and the different part identifies the network to which it belongs.
Therefore, The choice is a good reason to segment a network as the network segments that are more accessible to the Internet are known by new term is screened subnet.
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Determine the required diameter of a steel transmission shaft 10 meters in length and material yield strength 350 MPa in order to resist a torque of up to 500 N.m. The shaft is supported by frictionless bearings at its ends. Design the shaft using the maximum shear stress theory, and selecting a factor of safety of 1.5. Neglect shaft weight.
Answer:
0.02795 m
Explanation:
Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter
factor of safety = 1.5
length of shaft = 10 meters
material yield strength = 350 MPa
Torque = 500 N.m
The required shaft diameter = 0.02795 m
attached below is a detailed solution of the problem
Calculate the steady state flux of atomic hydrogen at 25°C through a steel vessel of wall thickness 4 mm given that the inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, the outside surface is exposed to the atmosphere. (The diffusivity of hydrogen in steel D0 = 0.1 mm2 s-1, Q = 13.5 kJ mol-1) A steady-state flux allows the application of Fick’s first law: J = -D(dC/dx)
If the vessel contains 20 moles of hydrogen, calculate the time taken to dissipate all of the hydrogen of that the vessel has a surface area of 3 m2.
Answer:
To calculate the steady state flux of atomic hydrogen through a steel vessel, we need to use Fick's first law, which states that the flux (J) is equal to the diffusivity (D) multiplied by the concentration gradient (dC/dx).
First, we need to calculate the concentration gradient by dividing the difference in hydrogen concentration between the inside and outside surfaces by the wall thickness of the vessel. The inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, and the outside surface is exposed to the atmosphere, which has a hydrogen concentration of 0 moles/m3. Therefore, the concentration gradient is (4.5 - 0) moles/m3 / (4 mm) = 1.125 moles/m3 mm.
Next, we need to substitute this value into Fick's first law along with the diffusivity of hydrogen in steel, which is given as 0.1 mm2/s. This gives us the steady state flux as J = (-0.1 mm2/s) * (1.125 moles/m3 mm) = -0.01125 moles/s mm2.
Finally, we need to convert the units of the flux from moles/s mm2 to moles/s m2. To do this, we can multiply the flux by 1,000 to convert the units of millimeters to meters, giving us a final steady state flux of -0.01125 moles/s mm2 * 1,000 = -1.125 moles/s m2.
IF THE VESSEL CONTAINS 20 MOLES OF HYDROGEN, CALCULATE THE TIME TAKEN TO DISSIPATE ALL OF THE HYDROGEN OF THAT THE VESSEL HAS A SURFACE AREA OF 3 M2.
To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm2/s, the inside concentration is 4.5 moles/m3, and the outside concentration is 0, the concentration gradient is 4.5 moles/m3.
Plugging these values into the equation above, we get:
J = -0.1 mm2/s * 4.5 moles/m3 = -0.45 moles/s-m2
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
Explanation:
SELF EXPLANATORY
The time taken is 44.44 seconds to dissipate all of the hydrogens from the vessel.
How to calculate the time?To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm²/s, the inside concentration is 4.5 moles/m³ and the outside concentration is 0, the concentration gradient is 4.5 moles/m³.
Plugging these values into the equation above, we get:
J = -0.1 mm²/s * 4.5 moles/m³ = -0.45 moles/s-m²
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
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The figure below appeared three heat treatments processes of steel (A, B and C),
select only One and answer the following:
1- Named the heat treatment process.
2- The temperature range of heating process.
3- The cooling process method.
4- The aims of process.
Answer:
b
Explanation:
The air conditioner in a house or a car has a cooler that brings atmospheric air from 30C to 10C, with both states at 101KPa. If the flow rate is 0.75kg/s, find the rate of heat transfer using constant specific heat of 1.004kj/kg.K
The rate of heat transfer by the air conditioner using constant specific heat of 1.004kj/kg.K is 15.06 kW.
What is the rate of heat transfer?Rate of heat transfer is the power rating of the machine.
Work done and changes in potential and kinetic energy are neglected since it is a steady state process.
The specific heat in terms of specific heat capacity and temperature change is given as:
\(q_{out} = Cp(Ti - Te)\)
\(q_{out} = 1.004(30 - 10) = 20.08 kJ/kg \\ \)
The rate of heat transfer, is then determined as follows:
Qout = flow rate × specific heatQout = 0.75 × 20.08 = 15.06 kW
Therefore, the rate of heat transfer by the air conditioner is 15.06 kW.
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Draw the logic circuit for each of the following. For each gate, determine if it generates either EVEN or ODD parity bit and finds the output for the given input data: (Remember: A XOR generates EVEN parity bit. A XNOR generates Odd Parity bit, whatever how many inputs they have.)
Data Inputs Which kind parity bit can it generate?
4-input XOR, input data-1001 Even Parity Bit ODD Parity Bit
5-input XOR, input data-10010
6-input XOR, input data-101001
7-input XOR, input data 1011011
Answer:
a) 4-input XOR, input data-1001 = 0 Even parity Bit
b) 5-input XOR, input data-10010 = 0 Even parity Bit
c) 6-input XOR, input data-101001 = 1 Even parity Bit
d) 7-input XOR, input data 1011011 = 1 Even parity Bit
Explanation:
a) 4-input XOR, input data-1001 ; generates 0 Even parity Bit
b) 5-input XOR, input data-10010 ; generates 0 Even parity Bit
c) 6-input XOR, input data-101001 ; generates 1 Even parity Bit
d) 7-input XOR, input data 1011011 ; generates 1 Even parity Bit
Attached below is the Logic circuits of the data inputs
Suppose the vapor pressures of two components of a binary solution are given by:
P1 = x, Pi*e* and P2 = x,Pema1 +fx} Find kh.1 and kH.2.
kh.1 = Pie, kH.2 = Pema1 + fx. kh.1 is the Henry's law constant for component 1, kH.2 is the Henry's law constant for component 2.
The expression P1 = x, Pie implies that the vapor pressure of component 1, P1, is directly proportional to its mole fraction, x, and the pure component vapor pressure, Pie. Thus, dividing P1 by x gives us Pie, which is the Henry's law constant for component 1 (kh.1). Similarly, the expression P2 = x, Pema1 +fx represents the vapor pressure of component 2, P2, as a function of its mole fraction, x, and a combination of the pure component vapor pressure, Pema1, and the mole fraction of component 2, f, multiplied by x. Dividing P2 by x yields Pema1 +fx, which is the Henry's law constant for component 2 (kH.2).
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Calculate the discrete settling velocity of a grit particle with a radius of 0.05mm and specific gravity of 2.65 at water temperature 20degrees(v=1.004×10^-6m2/s)
The correct answer is To calculate the discrete settling velocity of a grit particle, we can use the following formula:
\(V_s = (2/9) * (ρ_p - ρ_f) * g * r^2 / η\)
V_s = discrete settling velocity
ρ_p = density of particle
ρ_f = density of fluid
g = acceleration due to gravity
r = radius of particle
η = dynamic viscosity of fluid Given that the radius of the grit particle is 0.05mm and its specific gravity is 2.65, we can calculate its density as:
ρ_p = specific gravity * ρ_water
\(= 2.65 * 1000 kg/m^3= 2650 kg/m^3\)
At a water temperature of 20°C, the dynamic viscosity of water is\(1.004 × 10^-6 m^2/s,\)which we are given.
The density of water at 20°C is approximately \(1000 kg/m^3,\) and the acceleration due to gravity is\(9.81 m/s^2.\)
Substituting these values into the formula, we get:
\(V_s = (2/9) * (2650 - 1000) * 9.81 * (0.05 × 10^-3)^2 / (1.004 × 10^-6)= 0.086 m/s\)(rounded to three decimal places)
Therefore, the discrete settling velocity of the grit particle is approximately 0.086 m/s.
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The automatic antenna tuner on the ft-dx10 is designed to ensure what ohm antenna impedence is presented?.
At amateur operating frequencies, the FTDX10 is designed for 50 Ohm resistive impedance.
What is meant by Impedance?Impedance is the sum of resistance and reactance. It was defined as anything that can obstructs the flow of electrons within the electrical circuit. As a result, it influences current generation in the electrical circuit. It could be found in all the possible circuit components and across all possible electrical circuits. Impedance is represented mathematically by the letter Z and has the unit ohm. It's a mix of resistance and reactance.
Z stands for impedance, which is an expression of the resistance to alternating and/or direct electric current that an electronic component, circuit, or system offers. Resistance and reactance are two independent scalar (one-dimensional) phenomena that make up the vector (two-dimensional) quantity known as impedance.
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Find the perpendicular distance from the point P(9,11,−8) ft to a plane defined by three points A(1,9,−4) ft, B(−4,−8,6) ft, and C(−1,−2,2) ft
Distance = ______ ft
Answer:
0 ft
Explanation:
The equation of the plane can be found from the cross product AC×BC. That vector is ...
N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)
Then the equation of the plane is ...
8x +10y +21z = 14 . . . . . 14 = N·A
Point P satisfies this equation, so is on the plane. The distance is 0 feet.
8(9) +10(11) -8(21) = 72 +110 -168 = 14
You are the curator of a museum. The museum is running short of funds, so you decide to increase revenue. Should you increase or decrease the price of admission? Explain
Answer:
Explanation:
If the museum is running short of funds, and you decide to increase revenue. An increase or decrease in the price of admission into the museum depends on the following:
1. If demand for admission into the museum is elastic there are two possible outcomes
a. An increase in the price of admission leads to a decrease in the quantity demand of admission into the museum
b. A decrease in price of admission into the museum leads to an increase in the quantity demand of admission into the museum.
This follows the law of demand which states that "the higher the price, the lower the quantity demanded and the lower the price, the higher the quantity demanded".
2. If the demand for admission into the museum is inelastic, then an increase in price will lead to an increase in revenue of the museum.
Therefore, before the curator increase the price of admission into the museum, he should first determine the price elasticity of demand of the museum.
Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
I'd say number 4, number 3 looks like an exhaust valve
three condition necessary for the formation of stationary
wave
Answer:
Two waves must be having same wavelength, frequency, amplitude and travelling in the opposite direction.
Write an if-else statement for the following: If user_tickets is equal to 7, execute award_points = 1. Else, execute award_points = user_tickets.
Answer:
if user_tickets == 7:
award_points = 1
else:
award_points = user_tickets
Explanation:
Not sure what language you are using. But this can be used for python. Also don't know if you are required to ask the user for any input
Assume quicksort always chooses a pivot that divides the elements into two equal parts.
1. How many partitioning levels are required for a list of 8 elements?
2. How many partitioning "levels" are required for a list of 1024 elements?
3. How many total comparisons are required to sort a list of 1024 elements?
Assuming quicksort always chooses a pivot that divides the elements into two equal parts, the answers are:
1. The number of partitioning levels required for a list of 8 elements is 3.
2. The number of partitioning levels required for a list of 1024 elements is 10.
3. The total number of comparisons required to sort a list of 1024 elements is 9217.
Step-by-step explanation:
1. For a list of 8 elements with an ideal pivot that divides the elements into two equal parts, the number of partitioning levels required is 3. Here's a step-by-step explanation:
- Level 1: 8 elements are divided into 2 groups of 4 elements each.
- Level 2: Each group of 4 is divided into 2 groups of 2 elements each.
- Level 3: Each group of 2 is divided into 2 groups of 1 element each (sorted).
2. For a list of 1024 elements with an ideal pivot that divides the elements into two equal parts, the number of partitioning levels required is 10. This is because 2^10 = 1024. In each level, the number of elements in each group is halved, so after 10 levels, there will be groups of 1 element each (sorted).
3. To calculate the total number of comparisons required to sort a list of 1024 elements using quicksort with an ideal pivot, we can use the formula n * log2(n) - n + 1.
In this case, n = 1024:
- 1024 * log2(1024) - 1024 + 1 = 1024 * 10 - 1024 + 1 = 10240 - 1024 + 1 = 9217.
So, a total of 9217 comparisons are required to sort a list of 1024 elements with an ideal pivot.
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If quicksort always chooses a pivot that divides the elements into two equal parts, then we can assume that the algorithm will use the median element as the pivot.
1. For a list of 8 elements, quicksort with this assumption will require 3 partitioning levels. The first partitioning will divide the list into two equal parts, each with 4 elements. The second partitioning will divide each of these parts into two equal parts, each with 2 elements. Finally, the third partitioning will divide each of these parts into two equal parts, each with 1 element. 2. For a list of 1024 elements, quicksort with this assumption will require 10 partitioning levels. Each level will divide the list into two equal parts, and since 2^10 = 1024, we need 10 levels to reduce the list to single elements. 3. The total number of comparisons required to sort a list of 1024 elements using quicksort with this assumption can be calculated using the formula 1024 * log2(1024), which is approximately 10,240 comparisons. This is because each level of partitioning requires comparisons between each element and the pivot, and there are a total of 10 levels of partitioning.
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The maximum capacity of a 2-lane carriageway of a four lane dual carriageway is 2000 veh/hour. due to pipe laying operations the width of two lane carriageway is reduced, restricting the maximum capacity to 1100 veh/hour. when the flow upstream beyond the influence of the bottleneck is reasonably steady and freeflowing at 1500 veh/hour. find i) the mean speed of traffic in the bottleneck ii) the rate at which the queue of the congested conditions outside bottleneck grows. the mean space headway when the vehicles are stationary is 8 m. the relation between speed and concentration is linear
Based on the maximum capacity as a result of the pipe-laying operations, and the maximum capacity without obstruction to the four-lane dual carriageway, the mean speed of traffic in the bottleneck is -2.73km.
What is the mean speed of traffic?This can be found as:
= (Maximum restricted capacity - freeflowing rate) / (Kb - Ka)
= (1,100 - 1,500) / (209 - 62.5)
= -2.73 km/h
The rate that the queue outside the bottleneck grows is:
= Free flowing rate - (mean speed of traffic x ka)
= 1,500 - (-2.73 x 62.5)
= 1,670 veh/hour
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Which of the following workers are not likely to be paid during an election?
campaign press secretary
volunteer coordinator
poll worker
director of communications
Answer:
volunteer coordinator
Explanation:
because they are volunteering for that and in most of the cases they do not expect to be paid
The elbow of the pipe has an outer radius of 0.75 in. and an inner radius of 0.63 in. if the assembly is subjected to the moments of M 25 Ib-in, determine the maximum stress developed at section a-a 2. 30° 1 in. M 25 lb in. 0.63 in 0.75 in. M 25 lb-in.
The elbow of the pipe has an outer radius of 0.75 in. and an inner radius of 0.63 in. if the assembly is subjected to the moments of M 25 Ib-in. The maximum stress developed at section a-a 2 is 7327.47 psi.
1:Calculate the moment of Inertia. The moment of inertia of a circular section is calculated as I = π/4 (r2 - R2), where r is the inner radius and R is the outer radius. I = π/4(0.752 - 0.632) = 0.0138 in4
2: Calculate the section modulus. The section modulus can be calculated as Z = I / c, where c is the distance from the neutral axis to the outermost fiber.
Z = 0.0138 / 0.06 = 0.23 in3
3: Calculate the maximum bending stress. The maximum bending stress can be calculated as
σmax = M / Z,
where M is the applied bending moment.
σmax = 25 / 0.23 = 108.7 psi
4: Calculate the maximum stress using the formula
σ = ± σmax x (r / c)σ = ± 108.7 x (0.75 / 0.06) = ± 1363.63 psi
The maximum tensile stress occurs at the outer fiber, so we take the positive value.
σmax = 1363.63 psi
The maximum stress developed at section a-a 2 is 7327.47 psi.
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The maximum stress developed at section a-a is 4310 psi.
Given the following diagram as follows:The elbow of the pipe has an outer radius of 0.75 in. and an inner radius of 0.63 in. if the assembly is subjected to the moments of M 25 lb-in, determine the maximum stress developed at section a-a. We are required to determine the maximum stress developed at section a-a.Let us assume the thickness of the pipe is t. Then, the length of the section a-a can be written as;Length of section a-a = π/6 [d1 + d2 - √(d1d2)]Length of section a-a = π/6 [0.75 + 0.63 - √(0.75 × 0.63)]Length of section a-a = 0.57 in.The area moment of inertia of section a-a can be written as;I = π/64 [(d1⁴-d2⁴)]I = π/64 [(0.75⁴ - 0.63⁴)]I = 0.0058 in4Using the flexural formula;σ = Mc/Iσ = (25 × 1)/0.0058σ = 4310 psi.
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lease write a calculator program in java using the javafx libraries as we discussed in class. at a minimum, your calculator should handle addition, subtraction, multiplication and division of integer numbers. so basically you should be able to input a number, click an operation ( - * /) button, then enter another number and hit
The calculator program will be:
import java.util.HashMap;
import java.util.Map;
public class JavafxCalculator extends Application {
private static final String[][] template = { { "7", "8", "9", "/" }, { "4", "5", "6", "*" }, { "1", "2", "3", "-" },
{ "0", "c", "=", "+" } };
private final Map<String, Button> buttons = new HashMap<>();
private DoubleProperty stackValue = new SimpleDoubleProperty();
private DoubleProperty value = new SimpleDoubleProperty();
private enum Operation {
NOOPERATION, ADDITION, SUBTRACTION, MULTIPLICATION, DIVISON
What is a program?A computer program is the sequence or set of instructions in a programming language for a computer to execute.
It should be noted that computer programs are one component of software. In this case, the program is illustrated above.
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For a cylindrical annulus whose inner and outer surfaces are maintained at 30 ºC and 40 ºC, respectively, a heat flux sensor measures the magnitude of the heat flux at 3cmr= as 40 W/m2. Assume that the temperature distribution is steady and depends only on the radial coordinate. Under the hypothesis that the thermal conductivity is independent of temperature, what is k if a) the inner and outer radii
Answer:
\(k=0.12\ln(r_2/r_1)\)\(\frac {W}{ m^{\circ} C}\)
where \(r_1\) and \(r_2\) be the inner radius, outer radius of the annalus.
Explanation:
Let \(r_1\), \(r_2\) and \(L\) be the inner radius, outer radius and length of the given annulus.
Temperatures at the inner surface, \(T_1=30^{\circ}C\\\) and at the outer surface, \(T_2=40^{\circ}C\).
Let q be the rate of heat transfer at the steady-state.
Given that, the heat flux at r=3cm=0.03m is
\(40 W/m^2\).
\(\Rightarrow \frac{q}{(2\pi\times0.03\times L)}=40\)
\(\Rightarrow q=2.4\pi L \;W\)
This heat transfer is same for any radial position in the annalus.
Here, heat transfer is taking placfenly in radial direction, so this is case of one dimentional conduction, hence Fourier's law of conduction is applicable.
Now, according to Fourier's law:
\(q=-kA\frac{dT}{dr}\;\cdots(i)\)
where,
K=Thermal conductivity of the material.
T= temperature at any radial distance r.
A=Area through which heat transfer is taking place.
Here, \(A=2\pi rL\;\cdots(ii)\)
Variation of temperature w.r.t the radius of the annalus is
\(\frac {T-T_1}{T_2-T_1}=\frac{\ln(r/r_1)}{\ln(r_2/r_1)}\)
\(\Rightarrow \frac{dT}{dr}=\frac{T_2-T_1}{\ln(r_2/r_1)}\times \frac{1}{r}\;\cdots(iii)\)
Putting the values from the equations (ii) and (iii) in the equation (i), we have
\(q=\frac{2\pi kL(T_1-T_2)}{\LN(R_2/2_1)}\)
\(\Rightarrow k= \frac{q\ln(r_2/r_1)}{2\pi L(T_2-T_1)}\)
\(\Rightarrow k=\frac{(2.4\pi L)\ln(r_2/r_1)}{2\pi L(10)}\) [as \(q=2.4\pi L\), and \(T_2-T_1=10 ^{\circ}C\)]
\(\Rightarrow k=0.12\ln(r_2/r_1)\)\(\frac {W}{ m^{\circ} C}\)
This is the required expression of k. By putting the value of inner and outer radii, the thermal conductivity of the material can be determined.
Which characteristics describe customers who are more likely to have low assets and medium-low debt?
Answer:
Here are some characteristics that describe customers who are more likely to have low assets and medium-low debt:
* **Age:** Younger customers are more likely to have lower assets and debt than older customers. This is because they have had less time to accumulate assets and may be carrying more student loan debt.
* **Income:** Customers with lower incomes are more likely to have lower assets and debt than customers with higher incomes. This is because they have less money to save and invest, and may be spending more of their income on necessities.
* **Education:** Customers with less education are more likely to have lower assets and debt than customers with more education. This is because they may have lower-paying jobs and may be less likely to save and invest.
* **Marital status:** Single customers are more likely to have lower assets and debt than married customers. This is because they may have less income and may be spending more of their income on housing and other expenses.
* **Employment status:** Unemployed customers are more likely to have lower assets and debt than employed customers. This is because they may have less income and may be spending more of their income on necessities.
* **Credit score:** Customers with lower credit scores are more likely to have lower assets and debt than customers with higher credit scores. This is because they may have difficulty qualifying for loans and may be paying higher interest rates on debt.
It is important to note that these are just general trends, and there are always exceptions. There are many factors that can affect a customer's assets and debt, including their personal circumstances, financial decisions, and economic conditions.
Explanation:
Many farms and ranches use electric fences to keep animals from getting into or out of specific pastures. When switched on, an electric current is produced in the fence. When an animal touches the electrified fence, it receives a small shock. What material would be the best choice for making an effective electric fence, and why?
Answer:
Aluminum
Explanation:
The best material to use when creating an electric fence would be Aluminum. Aluminum wiring is incredibly durable and can be easily obtained. Since aluminum is a non-magnetic metal its conducting capabilities far exceed other metallic options in the market and is also why companies choose aluminum for their high tension cable wiring. Aside from being more expensive than other feasible options its durability and conducting capabilities make it easily the best option.
Answer:
Steel Wires
Explanation:
International house of pancakes
A circular tube AB is fixed at one end and free at the other end. The tube is subjected to concentrated torques as shown in the figure. If the outer radius of the tube is 1.5in. and the thickness is 3/4in. , calculate the strain energy stored in the tube. Let G = 11800ksi.
n-Hexane is burned with excess air. An analysis of the product gas yields the following dry-basis molar composition: 10.65% CO2, 1.29% CO, 0.098% C6H14 (with the remainder O2 and N2). The stack gas emerges at 760 mm Hg. Calculate the percentage conversion of hexane, the percentage excess air fed to the burner, and the dew point of the stack gas, taking water to be the only condensable species.
What is the percent conversion of n-hexane?
____________ %
What is the percentage by which air is fed in excess?
___________ %
What is the dew point of the stack gas (assuming that water is the only condensable species)?
To calculate the percentage conversion of n-hexane, the percentage excess air fed to the burner, and the dew point of the stack gas, more information is required. Specifically, the initial molar composition of n-hexane, the stoichiometric reaction equation, and the equilibrium relationship between water vapor pressure and temperature are needed.
Determining the percentage conversion of n-hexane involves comparing the molar amount of n-hexane in the product gas to the initial amount of n-hexane supplied.
The percentage excess air is calculated by comparing the actual amount of air fed to the burner to the stoichiometrically required amount of air for complete combustion. The dew point of the stack gas, assuming water is the only condensable species, depends on the equilibrium relationship between water vapor pressure and temperature.
To perform these calculations accurately, the initial molar composition of n-hexane, the stoichiometric reaction equation, and the equilibrium relationship between water vapor pressure and temperature need to be provided.
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Which term describes how the Mac operating system handles files created, deleted, or modified since the last backup when the backup drive is temporarily missing?A) Disk dumpB) SnapshotC) System restore pointD) Tarball
The term that describes how the Mac operating system handles files created, deleted, or modified since the last backup when the backup drive is temporarily missing is B) Snapshot.
A snapshot is a point-in-time copy of the contents of a volume. When Time Machine creates a backup of your Mac, it takes a snapshot of your files and folders at that moment. If the backup drive is temporarily missing, Time Machine will continue to take snapshots of your files and folders. When the backup drive is reconnected, Time Machine will copy over the differences between the latest snapshot and the previous backup to ensure that your backup is up to date. This allows you to restore your files to a point in time even if the backup drive was not available for a period.
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what should you consider when choosing the type of head protection
Answer: hope this helps u
Explanation:
Material,Flexibility,Comfort,Workplace Hazards
Which of the following accurately describes how switches and hubs work? (Select two) A. A switch uses the logical addresses in a packet to send it through the correct port to all VLANS defined on that port B. A hub repeats frames to all ports, regardless of the destination address C. Switches use the hardware address in the frame to send it only to the port where the device is located D. A hub uses the hardware address in the frame to forward it to the hosts on the VLAN that corresponds to that address
The following accurately describes how switches and hubs work
C. Switches use the hardware address in the frame to send it only to the port where the device is located.
B. A hub repeats frames to all ports, regardless of the destination address.
The option A is partially correct but not completely. A switch uses the logical addresses in a packet to send it through the correct port to a specific device, not to all VLANs defined on that port. Therefore, options C and B are the most accurate descriptions of how switches and hubs work, respectively.
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n order to test whether camshafts are being manufactured to specification a sample of n = 35 camshafts are selected at random. The average value of the sample is calculated to be 4.44 mm and the depths of the camshafts in the sample vary by a standard deviation of s = 0.34 mm. Test the hypotheses selected previously, by filling in the blanks in the following: An estimate of the population mean is 4.44 . The standard error is 0.06 . The distribution is normal (examples: normal / t12 / chisquare4 / F5,6). The test statistic has value TS= . Testing at significance level α = 0.01, the rejection region is: less than and greater than (2 dec places). Since the test statistic (is in/is not in) the rejection region, there (is evidence/is no evidence) to reject the null hypothesis, H0. There (is sufficient/is insufficient) evidence to suggest that the average hardness depth, μ, is different to 4.5 mm. Were any assumptions required in order for this inference to be valid? a: No - the Central Limit Theorem applies, which states the sampling distribution is normal for any population distribution. b: Yes - the population distribution must be normally distributed.
Why is it important to keep portable welders properly tuned
It is important to keep welders properly tuned because it "Reduces air pollution" (Option A).
What are the types of welding?Welding machinery, welding guns, and welders are among the most important items for a welding expert to have. Welding machines provide heat that melts steel pieces, allowing them to be bonded.
Gas Steel Arc Welding (GMAW/MIG), Gas Tungsten Arc Welding (GTAW/TIG), Shielded Steel Arc Welding (SMAW), andFlux Cored Arc Welding are the four primary methods of welding.Most welders also use an angle grinder to smooth out joints, wire brushes to clean or abrade steel surfaces before welding etc.
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Full Question:
Why is it important to keep portable welders properly tuned?
a-Reduce air pollution
b-So they run quieter
c-To produce smoother welding current
d-All of the above