We can use the ideal gas law and the psychrometric chart to solve this problem. Specific Humidity of the water vapor is 0.0104. The relative humidity is 1.04%. The volume of tank is 0.823 m³.
1) Specific Humidity = mass of water vapor / (mass of dry air + mass of water vapor)
Therefore, the specific humidity is:
Specific Humidity = 0.2 kg / (19 kg + 0.2 kg) = 0.0104
2) Relative Humidity:
At 37°C and 91 kPa, the saturation pressure of water vapor is approximately 2.72 kPa. The partial pressure of water vapor is given by:
Partial pressure of water vapor = Total pressure x Specific humidity
Therefore, the relative humidity is:
Relative Humidity = (Partial pressure of water vapor / Saturation pressure of water vapor) x 100%
Relative Humidity = (0.2 kg / (19 kg + 0.2 kg)) x 100% = 1.04%
3) Volume of the tank:
We can use the ideal gas law to find the volume of the tank. The ideal gas law is:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in kelvins.
We can rearrange this equation to solve for the volume:
V = (nRT) / P
We can assume that the air and water vapor behave as ideal gases. The number of moles can be found using the mass and molar mass:
n = mass / molar mass
The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.02 g/mol.
Total mass = mass of dry air + mass of water vapor = 19 kg + 0.2 kg = 19.2 kg
Temperature = 37°C = 310 K
Pressure = 91 kPa
Therefore, the volume of the tank is:
V = [(19 kg / 28.97 g/mol) + (0.2 kg / 18.02 g/mol)] x (8.31 J/mol-K x 310 K) / (91 kPa x 1000 Pa/kPa)
V = 0.823 m³
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ayuda porfa es de actividades fisicas
Translate to English please
How is mass of the body measured ? Define one second ?
Answer:
It is based on weight and height. Weight (in kilograms) is divided by height (in meters squared)
GIVEN:
WEIGHT ARM MOMENT
(LB) (IN) (LB-IN)
Empty weight 1,495.0 101.4 151,593.0
Pilot and passengers 380.0 64.0 ----
Fuel (30 gal
usable no reserve) ----- 96.0 ----
The CG is located how far aft of datum?
The CG is located 99.76 inches aft of the datum.
To determine center of gravity (CG), we need to use formula:
CG = (Σ(weight x arm))/Σ(weight)
where Σ(weight x arm) is sum of weight times arm for each component, and Σ(weight) is sum of all weights.
Weight of pilot and passengers = 380.0 lb
Arm of pilot and passengers = 64.0 in
Weight of fuel = total weight - empty weight - weight of pilot and passengers = 1875.0 - 1495.0 - 380.0 = 0 lb
Arm of fuel = 96.0 in
Calculate the CG:
CG = (1495.0 x 101.4) + (380.0 x 64.0) + (0 x 96.0) / (1495.0 + 380.0 + 0) = 99.76 in aft of datum
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A sloth is climbing vertically on a vine. Its motion is shown on the following graph of vertical position y vs. time t.
What is the instantaneous velocity of the sloth at time t=8?
The instantaneous velocity of the sloth climbing vertically on a vine at t= 8 sec is 1.5 m/s.
Velocity is a vector quantity. There is both a magnitude and a direction to it. Speed is the measure of the magnitude of velocity. The meter per second is its S.I. unit. Other units like Km/h and Km/s are also included. [LT-1] is the dimensional formula for it.
Instantaneous velocity at any particular instant is given by the slope of the position-time graph at that particular instant. The slope of the curve is also equal to the tangent of the angle made by the slope.
In the given Graph, the instantaneous velocity at t= 8 sec will be given by the slope of the straight line from t=7 t0 t=9.
For t=7 sec, the value of y= 2 m
For t=9 sec, the value of y= 5 m
So instantaneous velocity at t= 8 sec is given by
V = (5 - 2) / (9 -7) m/s
V = 3/2 m/s
V = 1.5 m/s
Hence, the instantaneous velocity of the sloth climbing vertically on a vine at t= 8 sec is 1.5 m/s.
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The component of the normal force on the object parallel to the plane balances the friction force on the object.True/False
True. The component of the normal force on the object parallel to the plane balances the friction force on the object at rest.
What is component of normal force parallel to the plane?
An object placed on an inclined plane is subject to three forces, namely;
Normal force acting downwardsComponent of the normal force acting parallel to the planeFrictional force, parallel to the planeNet force acting on the object at rest∑F = 0
mg sinθ - μFₙ cosθ = 0
mg sinθ = μFₙ cosθ
where;
mg sinθ is component of the normal force acting parallel to the planeμFₙ cosθ is frictional force, parallel to the planeThus, the component of the normal force on the object parallel to the plane balances the friction force on the object at rest.
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The number of degrees of arc that Polaris is above the horizon depends on
O Your latitude
O Mass
O The core
O spiral
The correct answer is "Your latitude." The number of degrees of arc that Polaris (the North Star) is above the horizon depends on your latitude.
Polaris is located very close to the North Celestial Pole, which is the point in the sky directly above Earth's North Pole. If you are at the North Pole (latitude 90 degrees North), Polaris would appear directly overhead at an angle of 90 degrees above the horizon. As you move south from the North Pole, the angle decreases. At the equator (latitude 0 degrees), Polaris would appear on the horizon, or at an angle of 0 degrees above the horizon.
Therefore, the correct answer is "Your latitude." The other options you mentioned, such as mass, the core, and spiral, are not directly related to the angle at which Polaris appears above the horizon.
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Help pls sand quickly plssssss
Answer:
The magnet produces an electric current in the wire
Explanation:
Answer: the first one is right
Explanation:
A ball is thrown up into the air. When it falls half-way back, what kind of energy does it have?
Answer:
it's gravitational potential energy would have converted to kinetic energy half way back when it's falls
Please help answer the following questions ASAP
Answer:
renewable are fuels that can be reused while non renewable are fuels that can not be used again
How does friction affect object acceleration down an incline?
Friction is the force that acts on the opposite side of direction of force, thus it manages to decelerate an object, so it acts upward along the plane
The froghopper holds the title of the best jumper of the animal world. A 0. 0198-gram froghopper can accelerate at 4,000 m/s2 over 2. 0 mm as it jumps. What is the impulse delivered to the froghopper as it makes this jump?.
The impulse delivered to the froghopper is 7.92 x 10^-5 Ns. Impulse is defined as the change in momentum of an object.
Impulse can be calculated by multiplying the force applied to an object by the time during which it is applied.
Impulse is denoted by the symbol J and is measured in units of Newton-seconds (Ns).
The formula for impulse is given as: J = FΔt Where J is the impulse, F is the force applied, and Δt is the time during which the force is applied.
We know the mass of the froghopper, its acceleration, and the distance it jumps.
We can use these values to calculate the force applied on the froghopper during the jump.
The mass of the froghopper is 0.0198 g or 0.0000198 kg. Its acceleration is 4000 m/s2.
The distance it jumps is 2.0 mm or 0.002 m. Force = mass x acceleration = 0.0000198 x 4000 = 0.0792 N.
Time = distance/velocity = 0.002/4000 = 5 x 10^-7 s. Impulse = force x time = 0.0792 x 5 x 10^-7 = 7.92 x 10^-5 Ns.
An impulse is defined as the change in momentum of an object. When an object is subjected to a force, its momentum changes.
The change in momentum of the object is called impulse.
Impulse is equal to the force applied to the object multiplied by the time during which the force is applied.
The formula for impulse is given as J = FΔt, where J is the impulse, F is the force applied,
and Δt is the time during which the force is applied.In this problem, we are given the mass of the froghopper, its acceleration, and the distance it jumps.
We can use these values to calculate the force applied on the froghopper during the jump.
The mass of the froghopper is 0.0198 g or 0.0000198 kg. Its acceleration is 4000 m/s2.
The distance it jumps is 2.0 mm or 0.002 m.
Using the formula force = mass x acceleration, we can find the force applied on the froghopper during the jump. Force = 0.0000198 x 4000 = 0.0792 N.
Using the formula time = distance/velocity, we can find the time during which the force is applied. Time = 0.002/4000 = 5 x 10^-7 s.
Now, we can use the formula J = FΔt to find the impulse delivered to the froghopper during the jump. Impulse = 0.0792 x 5 x 10^-7 = 7.92 x 10^-5 Ns.
The impulse delivered to the froghopper during the jump is 7.92 x 10^-5 Ns.
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A balloon is rubbed with a wool glove. The two items attract one another with a force of strength 1.2 N when they are 1 cm apart. If they have equal but opposite charges, what is the magnitude of the charge?
The magnitude of the charge on the balloon and the wool glove is approximately 1.2 x 10^-8 coulombs.
According to Coulomb's law, the force between two charged objects is given by:
F = k * (|q1| * |q2|) / r^2
where F is the force, k is the Coulomb's constant, q1 and q2 are the magnitudes of the charges on the objects, and r is the distance between them.
Force (F) = 1.2 N
Distance (r) = 1 cm
= 0.01 m
The Coulomb's constant, k, is approximately 9 x 10^9 N·m²/C².
Rearranging the equation, we can solve for the magnitude of the charge (|q1| = |q2|):
|q1| * |q2| = (F * r^2) / k
Substituting the given values:
|q1| * |q2| = (1.2 N * (0.01 m)^2) / (9 x 10^9 N·m²/C²)
|q1| * |q2| ≈ 1.33333333333 x 10^-12 C
Since the charges on the balloon and the wool glove are equal but opposite in sign, we can consider them as |q1| = |q2|. Thus:
|q1| ≈ |q2|
≈ 1.33333333333 x 10^-12 C / 2
|q1| ≈ |q2|
≈ 6.66666666667 x 10^-13 C
Therefore, the magnitude of the charge on the balloon and the wool glove is approximately 6.66666666667 x 10^-13 coulombs or, in a more concise form, 1.2 x 10^-8 coulombs.
The magnitude of the charge on the balloon and the wool glove is approximately 1.2 x 10^-8 coulombs.
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what is the minimum uncertainty in an electron's velocity, δmin,e, if the position is known within 1.4 nm?
The minimum uncertainty in an electron's velocity is δmin,e ≈ 2.24×10⁶ m/s.
What is the minimum uncertainty in the electron's velocity?The Heisenberg uncertainty principle states that there is a fundamental limit to the precision with which certain pairs of physical properties, such as position and velocity, can be known simultaneously.
The uncertainty in an electron's velocity can be calculated using the formula Δv ≥ h/(4πmΔx), where Δv is the minimum uncertainty in velocity, h is the Planck's constant, m is the mass of the electron, and Δx is the uncertainty in position.
Given that Δx is known within 1.4 nm (or 1.4×10⁻⁹ m) for the electron, we can substitute these values into the formula:
Δv ≥ (6.63 × 10⁻³⁴ J·s) / (4π × 9.11 × 10⁻³¹ kg × 1.4 × 10⁻⁹ m)
Δv ≥ 2.24 × 10⁶ m/s
Therefore, the minimum uncertainty in an electron's velocity is approximately 2.24×10⁶ m/s.
The Heisenberg uncertainty principle is a fundamental concept in quantum mechanics that describes the limitations in simultaneously measuring certain pairs of physical properties with precision. In this context, the uncertainty in an electron's velocity is determined by the uncertainty in its position.
The uncertainty principle quantifies this relationship and provides a lower bound on the minimum uncertainty in velocity. The uncertainty in position and velocity arises due to the wave-particle duality of matter, where particles such as electrons can exhibit both wave-like and particle-like behaviors.
Understanding the uncertainty principle is crucial in quantum mechanics, as it underlies the probabilistic nature of quantum phenomena and has implications for the behavior and properties of subatomic particles.
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How deep is the floor of the ocean if a sonar sound takes 7 seconds to return back to the ship?
What are health problems that are directly related to nutritional habits?
Answer:
Good nutritional habits are important to live a long and healthy life. Unhealthy eating habits like having too much sugar, salt, or fat in your diet can raise your risk for certain diseases. Not eating enough or eating too much both have different effects. Healthy eating can lower your risk for heart disease, stroke, diabetes, and other health conditions. A well balanced diet that satisfies your needs is sure to improve your way of life.
Explanation:
kinda just re-worded the stuff I saw on google
a 3.50 kg object is attached by a thread of negligible mass, which passes over a frictionless pulley of negligible mass, to a 4.50 kg object. the objects are positioned so that they are the same height from the floor, and then released from rest. what is the speed of the objects when they are separated vertically by 1.00 m?
2.56 m/s is the speed of the objects when they are separated vertically by 1.00 m. When a 3.50 kg object is attached by a thread of negligible mass, which passes over a frictionless pulley of negligible mass, to a 4.50 kg object.
What is mass ?The amount of matter in a particle or object is represented by the dimensionless quantity mass (symbolized m). The kilogram is the International System's (SI) preferred unit of mass (kg).Given:
Mass of 1st object, m1=3.50 kg Mass of 2nd object, m2=4.50 kgthey are at the same height from the floor.Solution:F=mg
putting value
F=3.50*9.8
Fd=34.3N
and
Fu=4.50*9.8
Fu=44.55
Hence the difference of the forces is
Fn=44.55-34.3N
Fn=10.25N
Generally
F=(m1+m2)a
10.25 = (3.50+4.50)a
a = 10.25/8
a= 1.28 m/s²
the equation for the Speed known as
v^2 = u^2+ 2as
So
v^2 = 0^2 + 2* 1.28 * 1
v = 2.56 m/s
Hence, 2.56 m/s is the speed of the objects when they are separated vertically by 1.00 m.
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A massless spring with spring constant 19.5N / m hangs vertically. A body of mass 0.400 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. How far below the initial position does the body Hlescend?
Using this equilibrium condition, we can solve for x: 3.924 N = 19.5 N/m * x, which gives x = 3.924 N / 19.5 N/m ≈ 0.201 m. Therefore, the body descends approximately 0.201 meters below the initial position.
We need to use the equation for the potential energy stored in a spring: U = (1/2)kx^2
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
The body is released from rest, so all of its initial energy is potential energy stored in the spring. At the top of its motion, this potential energy is entirely converted to kinetic energy. At the bottom of its motion, all of its energy is again potential energy stored in the spring.
We can use the conservation of energy to relate the initial potential energy to the final potential energy: U_i = U_f
(1/2)kx_i^2 = (1/2)kx_f^2
where x_i is the initial displacement (zero) and x_f is the final displacement, which we want to find.
Solving for x_f, we get: x_f = sqrt((U_i/k))
We're given the spring constant, k = 19.5 N/m, and the mass of the body, m = 0.400 kg. We can use these to find the initial potential energy: U_i = (1/2)kx_i^2 = 0
We can also use the mass and gravitational acceleration (g = 9.81 m/s^2) to find the weight of the body:
F = mg = (0.400 kg)(9.81 m/s^2) = 3.924 N
Since the spring is hanging vertically, the weight of the body is balanced by the force of the spring:
F_s = 3.924 N
We can use this force and the spring constant to find the final displacement: x_f = sqrt((U_i/k)) = sqrt((F_s^2)/(2k)) = sqrt((3.924 N)^2/(2(19.5 N/m)))
x_f = 0.402 m
Therefore, the body ascends 0.402 m from its initial position.
The answer to the question is: The body ascends three paragraphs, which is a distance of 0.402 m from its initial position. In the initial position, the mass (0.400 kg) is subjected to gravitational force, which can be calculated using the formula F_gravity = m * g, where m is the mass and g is the gravitational acceleration (approximately 9.81 m/s²). Therefore, F_gravity = 0.400 kg * 9.81 m/s² = 3.924 N.
When the mass descends, the spring stretches and exerts a force on the mass, F_spring = k * x, where k is the spring constant (19.5 N/m) and x is the extension of the spring. At the equilibrium position, these two forces balance each other: F_gravity = F_spring.
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Thalia is designing a compound machine for her physics class. She wants to set up a system so that she can press down on a lever with 10N, over a distance of 0.1m, and the output of the machine will be a 1N force exerted over 3m. Is this possible to develop? Justify your answer.
The work done on the lever by the input force is 1 J. Similarly the work done by the output force is 3 J. Here the output is greater than the input work which is not possible since all the energy given to the system cannot be converted as work done.
What is work done ?Work done is the product of force and displacement. When a force applied on a body is resulted in a displacement, the force is said to be done work on the body.
Work done is a vector quantity and is characterized by a magnitude and direction. The force applied on the lever have to be 10 N over a distance of 0.1 m.
then work done = F. ds
w = 10 N × 0.1 m = 1 J
The output force = 1 N
distance = 3 m
work done by the body = 1 N × 3 m = 3 J
It is generally impossible to generate a machine with an efficiency of 100%. Thus output work done cannot be greater than the input work.
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What is the acceleration of gravity on Mercury?
The acceleration of gravity on Mercury is approximately 3.7 meters per second squared (m/s^2). This value is determined by the mass of Mercury and the distance between its center of mass and the surface of the planet. Because Mercury is smaller and less massive than Earth, the force of gravity on its surface is weaker, leading to a lower acceleration of gravity.
PLS HELPPPP ILL GIVE YOU 30 POINTS
Spinning is ________. A. Biking in the mountains or hills B. Biking on rough terrain C. Cycling on a stationary bike D. Cycling on a road bike
Answer:
C
Explanation:
Ever heard of a 'spin' class at your local gym? ===> spinning on a stationary bike with others doing the same
Answer: D
Explanation:
Rank the following configurations according to the magnitude of the force felt at point P
— strongest force = top
— weakest force = bottom
**20 points!!**
Spam/unrelated content= reporting
Answer:
3, 4, 1, 2
Explanation:
When they collide, or combining into clusters
When particles collide, they can either bounce off each other or stick together to form larger clusters.
The outcome of a collision depends on the properties of the particles involved, including their size, shape, and composition, as well as the conditions under which the collision occurs, such as temperature, pressure, and velocity. In elastic collisions, particles bounce off each other without losing any energy or undergoing any permanent deformation. In inelastic collisions, particles stick together to form larger clusters, which can range in size from small molecules to large aggregates. In some cases, collisions can also result in chemical reactions, where the particles involved undergo a chemical transformation to form new compounds. The way in which particles collide and interact with each other is important in many areas of science and engineering, including materials science, chemical reactions, and the behavior of gases and fluids. By understanding the dynamics of particle collisions, scientists and engineers can develop new materials and processes, and gain insights into the fundamental nature of matter and energy.
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If 1000 droplets of water of surface tension 0. 07N/m,having same radius 1mm each,combine to form a single drop. In the process the released surface energy is
Surface energy released when 1000 droplets of water of surface tension 0.07 N/m, each with a radius of 1 mm, combine to form a single drop is approximately \(8.82 * 10^-7 J.\)
When the 1000 droplets of water combine to form a single drop, the surface area of the resulting drop decreases. As a result, the surface energy of the drop decreases because the surface tension of water is a measure of the energy required to increase the surface area of the water.
The surface area of the combined droplets can be calculated using the formula for the surface area of a sphere:
A = \(4pi*r^2\)
where A is the surface area, and r is the radius of the individual droplets.
Substituting the known value of the radius, we get:
A =\(4pi*(0.001 m)^2\)
A ≈ \(1.26 * 10^-5 m^2\)
The surface energy of the combined droplets can be calculated using the formula:
E = σA
where E is the surface energy, and σ is the surface tension of water.
Substituting the known values, we get:
E = \((0.07 N/m) * (1.26 * 10^-5 m^2)\)
E ≈\(8.82 * 10^-7 J\)
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help pls pls pls pls
Is it B? Not too sure about this one.
Michael Jordan's vertical leap is reported to be 48 inches (1.22m). What is his take off speed?
Jordan's take-off speed is 4.9 ms.
Key Accomplishments Too many to list. See the link below. Bottom line Jordan's incredible 4-foot vertical jump puts the top of his head 6 inches above the edge and the soles of his feet higher than any of his other NBA cleats. rice field. I also ran 4.3 Forty. Don't let anyone tell you that someone was a better athlete than you are. MJ was not only a great goalscorer back then, but he was also a high-flying dunker.
He has only one player in NBA history called his Airness and that is Michael He Jordan. He currently owns his NBA vertical jump of 48 inches, the highest in the entire tournament. That number comes with a hang time on the edge of 0.92 seconds. The 30th-40th percentile is 15-16 inches. Above-average vertical jump, values are in the 60th and 70th percentiles and range from 18 to 19 inches. A good rating is 20-21 inches, which corresponds to the 80-90th percentile.
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A ship leaves port and travels 50 miles at a standard position of 45⁰. The ship
then travels for 90 miles in a standard position angle of 80⁰. At that point the ship
drops anchor. A speedboat travelling 30 miles per hour moves towards the ship in a
straight line. At what time will it get there?
Answer:
t = 4.468 h
Explanation:
For this exercise let's start by calculating the distance where the boat is
the first trip is 50 miles at 45 °, then 90 miles at 80 °,
to find the total distance let's find the distance of each displacement
cos 45 = x₁ / 50
sin 45 = y₁ / 50
x₁ = 50 cos 45 = 35.35 miles
y₁ = 50 cos 45 = 35.35 miles
cos 80 = x₂ / 90
sin 80 = y₂ / 90
x₂ = 90 cos 80 = 15.63 miles
y₂ = 90 sin 80 = 88.63 miles
let's find the total displacement in each axis
x_total = x₁ + x₂
x_total = 35.35 + 15.63
x_total = 50.98 miles
y_total = y₁ + y₂
y_total = 35.35 + 88.63
y_total = 123.98 miles
Let's use the Pythagorean theorem to find the modulus of the displacement
R = √ (x_total² + y_total²)
R = √ (50.98² + 123.98²)
R = 134.05 miles
The boat goes at a constant speed,
v = R / t
t = R / v
let's calculate
t = 134.05 / 30
t = 4.468 h
What is a scientific law?
Answer:
In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.
Explanation:
hope you get it right
:)
Answer: Found this in google. Statement based on repeated experiments or observations, that describe or predict a range of natural phenomena. Hope this helps!
Explanation:
6- A boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground, what is the horizontal displacement of the ball?
A. 5.6 m
B. 4.0m
C. 3.1 m
D. 2.5 m
Answer:
Explanation:
Given:
V₀ = 3.0 m/s
H = 5.2 m
__________
L - ?
Time for the ball to fall vertically:
H = g·t²/2; ⇒ t = √ (2·H / g) = √ (2·5.2 / 9.8) ≈ 1.0 c
Move the ball horizontally:
L = V₀·t = 3.0·1.0 = 3.0 m
If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground , then the horizontal displacement of the ball is 3.09 meters.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground
S = ut + 1/2 × a × t²
5.2 = 0 + 0.5 × 9.8 × t²
t² = 5.2 / 4.9
t = 1.03 seconds
The horizontal displacement of the ball = 1.03 × 3
= 3.09 meters
Thus, the horizontal displacement of the ball is 3.09 meters.
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among the ellipticals, e0 types look the most like huge globular star clusters. group of answer choices true false
True; The ellipticals, e0 types look the most like huge globular star clusters.
Star clusters are massive collections of stars. Globular clusters, which are tightly grouped groups of thousands to millions of old stars that are gravitational bonded, can be distinguished from open clusters, which are more loosely clustered groups of stars that typically have fewer than a few hundred members and are frequently quite young. Open clusters are gradually disrupted as they move through the galaxy due to the gravitational pull of giant molecular clouds, but cluster members will still move roughly in the same direction through space even though they are no longer gravitationally bound; at this point, they are known as a stellar association, also known as a moving group.
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