a. To create a data file with storm data, write the storm information (location, rainfall, duration) into a file, with each record on a separate line.
b. In the program, define a struct to store storm data and intensity, with fields for location, rainfall, duration, and intensity.
c. Read the data from the file, calculate the intensity for each storm record, and store the data in a suitable data structure (e.g., array, list, vector) of structs.
a. To create a data file with storm data, you can use a text editor or a programming language to write the storm information into a file. Here's an example of how the file can be created:
321 2.4 1.5
111 3.3 12.1
...
```
Each line represents a storm record with the location, rainfall amount (in inches), and duration (in hours) separated by spaces. Repeat this pattern for each storm record in the file.
b. In the program, we can design a data structure using a **struct** to store the storm data and intensity. Here's an example of how the struct can be defined in C++:
```cpp
struct Storm {
int location;
double rainfall;
double duration;
double intensity;
};
```
The `Storm` struct has four fields: `location` to store the location of the storm, `rainfall` to store the amount of rainfall in inches, `duration` to store the duration of the storm in hours, and `intensity` to store the calculated intensity of the storm (rainfall divided by duration).
c. Here's a function in C++ to read the data from the file, copy it into a vector of structs, and calculate the intensities:
```cpp
#include <iostream>
#include <fstream>
#include <vector>
void readStormData(std::vector<Storm>& storms, const std::string& filename) {
std::ifstream file(filename);
if (!file) {
std::cerr << "Failed to open file: " << filename << std::endl;
return;
}
Storm storm;
while (file >> storm.location >> storm.rainfall >> storm.duration) {
storm.intensity = storm.rainfall / storm.duration;
storms.push_back(storm);
}
file.close();
}
```
The `readStormData` function takes a vector of `Storm` objects and the filename as parameters. It opens the file, reads each line, and assigns the values to the corresponding fields of the `Storm` struct. The intensity is calculated by dividing the rainfall by the duration, and the storm is added to the vector. Once all the storms have been read, the file is closed.
You can call this function to read the data from the file and populate the vector of structs:
```cpp
std::vector<Storm> storms;
readStormData(storms, "storm_data.txt");
```
Make sure to replace `"storm_data.txt"` with the actual filename and path of your storm data file.
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1.2. Your geotechnical laboratory team has been tasked with identifying two different
types of rocks for a project in Free State. Discuss briefly the three physical
properties you will utilize to visually identify the rock type. (9)
There are several physical properties that can be used to visually identify rock types, but three key properties are color, texture, and mineral composition.
What are the physical properties used to identify rock types?Color is an easily observable property and can provide clues about the mineral content of a rock. For example, light-colored rocks typically contain minerals like quartz and feldspar, while dark-colored rocks may have minerals like biotite or hornblende.
Texture refers to the size and arrangement of mineral grains within a rock. Coarse-grained rocks are typically formed from slowly cooling magma or lava, while fine-grained rocks often result from rapid cooling or sedimentation.
Mineral composition can also be used to identify rocks. Certain minerals are characteristic of specific rock types, such as calcite in limestone or feldspar in granite. By examining the minerals present in a rock, geotechnical laboratory teams can identify its likely rock type.
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In electrical engineering, a group of devices wired in sequence is called a:.
In electrical engineering, a group of devices wired in sequence is called a series circuit.
A series circuit is a type of electrical circuit in which the components are connected end to end so that the current flows through each component in turn without any branching.
This means that the current passing through one device is the same as the current passing through the other devices in the circuit. However, the voltage across each device in a series circuit is different and the sum of the voltage across each device is equal to the voltage of the source. Series circuits are commonly used in electronic devices such as Christmas lights, flashlights, and remote controls. One of the advantages of a series circuit is that it is easy to control the amount of current flowing through the circuit by adding or removing devices. Additionally, series circuits are relatively easy to analyze mathematically, making them a popular choice in electrical engineering. Overall, a series circuit is a simple and effective way to connect multiple electrical devices in a single circuit.Know more about the series circuit
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5. The maximum scaffold height not requiring toeboards is 20 feet.
A. True
B. False
Where is the primary area for romanesque architectural sculpture?
Answer:
on the façade, entrance, and column capitals
. to provide some perspective on the dimensions of atomic defects, consider a metalspecimen that has a dislocation density of 104 mm-2. suppose that all the dislocationsin 1000 mm3 (1 cm3) were somehow removed and linked end to end. how far (in miles)would this chain extend? now suppose that the density is increased to 1010 mm-2 bycold working. what would be the chain length of dislocations in 1000 mm3 of material?
For a dislocation density of 10^4 mm^-2, the chain would extend 1.24 miles. For a density of 10^10 mm^-2, the chain would extend 124,274 miles.
1. Calculate total dislocations: Dislocation density x Volume = 10^4 mm^-2 x 1000 mm^3 = 10^7 dislocations
2. Estimate the length of one dislocation: Consider 1 mm as an average dislocation length
3. Calculate total length of dislocations: 10^7 dislocations x 1 mm/dislocation = 10^7 mm
4. Convert length to miles: 10^7 mm x (1 m/1000 mm) x (1 km/1000 m) x (1 mile/1.609 km) ≈ 1.24 miles
5. Repeat steps 1-4 for a density of 10^10 mm^-2: 10^10 mm^-2 x 1000 mm^3 = 10^13 dislocations, total length ≈ 124,274 miles.
Therefore the chain would extend 1.24 miles.
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A horizontal poly crystalline solar panel module has to be investigated by natural cooling. For crystal silicon, the thermal coefficient approximately 0.0045/K is used. Investigate the effect of air velocity on the cooling performance of PV panels at 0-5 m/s air velocities, 25-40 ºC ambient temperatures, and 400-1000 W/ m2 solar radiation
Solution :
It is given that :
Thermal coefficient = 0.0045/K
Ambient temperature, \($T_a = 25 - 40^\circ$\)
air velocity, v = 0-5 m/s
Solar radiation, \($G= 400-100 \ W/m^2$\)
\($P=50 \ W$\)
Model calculations :
Cell temperature (\($T_c$\))
\($T_c = T_a + \left(\frac{0.25}{5.7+3.8 \ v_w}\right) G$\)
where \($ v_w - v_a = $\) wind speed / air speed
∴ \($T_c = 2 \pi + \left(\frac{0.25}{5.7+3.8 \times 1}\right) \times 400$\)
\($T_c = 35.526 ^\circ$\)
\($\Delta T = T_c -25$\)
= 35.526 - 25
= 10.526 K
Thermal coefficient = 0.0045 x 10.526
= 0.04737
Pv power = \($(1 -C_T) \times P \times \frac{G}{1000}$\)
\($=(1 -0.04737) \times 50 \times \frac{400}{1000}$\)
= 17.0526 W
Calculate the B/CB/CB/C ratio for the following cash flow estimates at a discount rate of 777% per year.Item Cash FlowFW of benefi ts, $ 30,800,000AW of disbenefi ts, $ per year 105,000First cost, $ 1,200,000M&O costs, $ per year 400,000Life of project, years 20
Per year 400,000Life of project, years 20. The discount rate is the interest charge commercial banks and other financial institutions make to the Federal Reserve Bank in order to borrow short-term money. Thus, option D is correct.
What cash flow estimates at a discount rate?The formula for benefit-cost ratio is: Benefit-Cost Ratio = ∑ Present Value of Future Benefits / ∑ Present Value of Future Costs.
A project determined to have exactly equal benefits and costs B/C ratio equals precisely one). A systematic process for calculating and comparing benefits and costs of a project. Measure calculated by dividing the incremental monetized benefits related to a project by the incremental costs of that project.
Therefore, The present value of future cash flows is computed using a rate of return known as the discount rate in a discounted cash flow analysis. An examination of discounted cash flows shows. Per year 400,000Life of project, years 20
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Multiple Choice question. Selected the correct answer.
10. Which of the following is NOT a metal used for producing exhaust manifolds?
A. Cast iron.
B. Aluminium.
C. Heavy-gauge sheet metal.
D. Stainless steel.
Answer:
C. Heavy-gauge sheet metal.
Explanation:
Exhaust manifolds are typically made from cast iron, aluminum, or stainless steel, which are strong and durable materials that can withstand the high temperatures and pressures found in vehicle exhaust systems.
Heavy-gauge sheet metal is a type of metal, but it is not typically used for this application because it may not have the necessary strength and durability.
Isothermal Expansion of a vdW Gas Consider the expansion of a vdW gas from Vˉ1 to Vˉ2 at a Temperature T. Calculate the following properties for this COS.
To calculate the properties of the isothermal expansion of a van der Waals (vdW) gas, we need to consider the equation of state for the vdW gas and apply it to the given scenario. The vdW equation of state is given by:
[P + a/V^2] (V - b) = RT
Where P is the pressure, V is the volume, T is the temperature, R is the gas constant, and a and b are constants specific to the gas.
Given that the expansion is isothermal, the temperature T remains constant throughout the process. We are given the initial volume V1 and the final volume V2. Let's calculate the properties:
1. Pressure:
To calculate the pressure at the initial volume V1, we rearrange the vdW equation of state:
P1 = (RT)/(V1 - b) - (a/V1^2)
To calculate the pressure at the final volume V2:
P2 = (RT)/(V2 - b) - (a/V2^2)
2. Work Done:
The work done during the isothermal expansion can be calculated using the formula:
W = ∫(PdV) from V1 to V2
We can substitute the expression for pressure from the vdW equation and integrate to calculate the work done.
3. Change in Internal Energy:
Since the process is isothermal, the change in internal energy (ΔU) of the gas is zero. This is because the temperature remains constant, and internal energy depends only on temperature for an ideal gas.
4. Heat Transfer:
Since the process is isothermal, the heat transfer (Q) can be calculated using the equation:
Q = ΔU + W
Since ΔU is zero, the heat transfer is equal to the work done.
These calculations involve integration and substitution of the given values into the equations. The specific values of a and b for the vdW gas need to be provided to obtain accurate results.
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Cite another example of information technology companies pushing the boundaries of privacy issues; apologizing, and then pushing again once scandal dies down. As long as the controversy fades, is there anything unethical about such a strategy?
Answer:
Explanation:
Tech Social Media giant FB is one of those companies. Not long ago the ceo was brought to court to accusations that his company was selling user data. Turns out this is true and they are selling their users private data to companies all over the word. Once the news turned to something else, people focused on something new but the company still continues to sell it's users data the same as before. This is completely unethical as the information belongs to the user and they are not getting anything while the corporation is profiting.
The____is the issuer of certificates and certificate revocation lists and may also support a variety of administrative functions.
The certification authority is the issuer of certificates and certificate revocation lists and may also support a variety of administrative functions.
A certification authority (CA) is responsible for issuing digital certificates to entities such as individuals, organizations, or devices. These certificates validate the identity of the entity and are used for various purposes like secure communication, authentication, and digital signatures. The CA also maintains a certificate revocation list (CRL) which contains information about revoked certificates. This ensures that if a certificate is compromised or no longer valid, it can be identified and rejected. Additionally, a CA may perform administrative tasks such as managing certificate requests, verifying identities, and ensuring the security and integrity of the certificate infrastructure.
The certification authority (CA) plays a crucial role in the security infrastructure by issuing certificates, maintaining certificate revocation lists, and performing administrative functions to ensure the trustworthiness and validity of digital identities and communications.
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Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a direct link of R=2 Mbps. Suppose the propagation speed over the link is 2.5-108 meters/sec. a. Calculate the bandwidth-delay product, R.dprop.
The bandwidth-delay product represents the amount of data that can be transmitted over a network connection given the available bandwidth and the amount of delay experienced by packets traveling over the connection.
It is calculated by multiplying the bandwidth (R) by the round-trip propagation delay (dprop). The propagation delay is the time it takes for a packet to travel from one host to another and back and is influenced by the distance between the hosts and the speed at which signals travel over the network connection.
In the scenario described, with hosts A and B separated by 20,000 kilometers and connected by a direct link with a bandwidth of 2 Mbps and a propagation speed of 2.5 x 10^8 m/s, the propagation delay can be determined to be 8000 x 10^-5 seconds.
The resulting bandwidth-delay product can be obtained by multiplying R and drop, resulting in a value of 16000 bits. the most data that can be sent through an internet connection in a specific amount of time is called bandwidth.
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Searches related to Probability questions - A person frequents one of the two restaurants KARIM or NAZEER, choosing Chicken’s item 70% of the time and fish’s item 30% of the time. Regardless of where he goes , he orders Afghani Chicken 60% of his visits. (a) The next time he goes into a restaurants, what is the probability that he goes to KARIM and orders Afghani Chicken. (b) Are the two events in part a independent? Explain. (c) If he goes into a restaurants and orders Afghani Chicken, what is the probability that he is at NAZEER. (d) What is the probability that he goes to KARIM or orders Afghani Chicken or both?
Answer:
a) 0.42
b) Independent
c) 30%
d) 0.88
Explanation:
Person chooses Chicken's item : 70% = 0.7
Person chooses fish's item : 30% = 0.3
Visits in which he orders Afghani Chicken = 60% = 0.6
a)
Probability that he goes to KARIM and orders Afghani Chicken:
P = 0.7 * 0.6 = 0.42
b)
Two events are said to be independent when occurrence of one event does not affect the probability of the other event's occurrence. Here the person orders Afghani Chicken regardless of where he visits so the events are independent.
c)
P = 0.30 because he orders Afghani Chicken regardless of where he visits.
d)
Let A be the probability that he goes to KARIM:
P(A) = 0.7 * ( 1 - 0.6 ) = 0.28
Let A be the probability that he orders Afghani Chicken:
P(B) = 0.3 * 0.6 = 0.18
Let C be the probability that he goes to KARIM and orders Afghani chicken:
= 0.7 * 0.6 = 0.42
So probability that he goes to KARIM or orders Afghani Chicken or both:
P(A) + P(B) + P(C) = 0.28 + 0.18 + 0.42 = 0.88
f the amounts of bases in a DNA molecule are measured, what would you find?A) A = C and G = T
B) A = G and C = T
C) T = Aand C = G
D) A = U and C = G
E) U = C and A = G
What is the attenuation in db for a 4th order low pass filter at a frequency of 10fc, where fc is the filter's corner frequency?
Fourth-order Low Pass Filter If the gain of both filters is set at 1.586, the voltage gain will be down 6 dB at the cutoff frequency. We can get a more flat response by choosing different values of voltage gain for both stages.
What is a fourth order low pass filter ?It is possible to create a 4th order low-pass filter with just one Op Amp. Due to the interconnected nature of all filter parameters, component tolerance sensitivity needs to be confirmed. The 4th order Sallen-Key topology is too sensitive to component tolerances, making it unsuitable for application.
Formula fc= 1/(2πRC).
How to calculate the attenuation of a low pass filter?The attenuation rate for a low-pass or high-pass filter will be -20 times the filter order, expressed in decibels per decade. A first-order filter, for instance, will attenuate at a rate of -20 dB/decade, but a fourth-order filter will attenuate at a rate of about -80 dB/decade.
Attenuation (dB)= 10 X log(PI/PO)
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AJ-K flip-flop has a condition of J=1, K=0, and both PRESET and CLEAR are active (for IC 7476, it is logic 0). If a 100-Hz clock pulse is applied to the CLK, the output Q is (a) o (b) 1 (c) 100 HZ (d) 50 Hz (e) unpredictable
The conditions of J=1, K=0, PRESET and CLEAR being active, and a 100-Hz clock pulse applied to the CLK, the output Q of the JK flip-flop will be 1. The correct option is (b) 1.
In an JK flip-flop, when J=1 and K=0, the output Q changes to a logic high or 1 on the rising edge of the clock pulse. Since both PRESET and CLEAR are active (logic 0 for IC 7476), the flip-flop will be in its normal mode of operation, and the 100-Hz clock pulse applied to CLK will cause Q to become 1 on every rising edge of the clock pulse.
Given the conditions of J=1, K=0, PRESET and CLEAR being active, and a 100-Hz clock pulse applied to the CLK, the output Q of the JK flip-flop will be 1. The correct option is (b) 1.
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characteristics of 3 types of soil
fertile, infertile and corroded soil
In a countersinking operation, once the tool reaches the proper depth, what should the operator do to ensure hole concentricity and a good surface finish?
1. Back the tool in and out of the bottom of the hole several times.
2. Increase the spindle speed one and a half times the normal rate.
3. Turn off the spindle to let the hole walls cool before continuing.
4. Let the tool run a few seconds before backing out of the hole.
There are different aspect of drilling operations. What the operator have to do to ensure hole concentricity and a good surface finish is to Increase the spindle speed one and a half times the normal rate.
Countersinking is often used to produce a conical hole linking the angled shape on the bottom side of a flat-head screw.
Research has shown that surface roughness is often affected by the spindle speed and feed rate. Note that surface roughness often increases with increased in feed rate and is known also to be higher at lower speeds and vice versa..There is a required spindle speed used for countersinking operation . The lead out rule is of 1/3 the speed of a drill of the same size often work for almost all countersinking and counterboring operations.
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will mark brainliest if correct
When a tractor is driving on a road, it must have a SMV sign prominently displayed.
True
False
Answer: true
Explanation:
name as much parts in a car that you know
Answer:
engine suspension brake and more
Explanation:
The three suspender bars are made of A992 steel and have equal cross-sectional areas of 360mm2 . The rigid beam is subjected to the loading shown.
Determine the average normal stress in the bar BE,AD,CFBE,AD,CF
The given problem states that three suspender bars, made of A992 steel and with equal cross-sectional areas of 360mm², are attached to a rigid beam. The problem requires us to find the average normal stress in the bars BE, AD, and CF.
The formula for average normal stress is Total Normal force divided by Total area of cross-section. To find the normal force and area of cross-section for each bar, we need to calculate the force acting on each bar. As the cross-sectional areas are equal i.e. 360mm², we only need to find the force acting on each bar.
The normal force in each bar can be found as follows:
- For Bar AD: Normal force in AD = (1000 + 1200) N = 2200 N
- For Bar CF: Normal force in CF = (1500 + 1800) N = 3300 N
- For Bar BE: Normal force in BE = 3000 N
Using the above-normal force values, we can now find the average normal stress by using the formula:
Average normal stress = Total Normal force / Total area of cross-section
Therefore, the average normal stress in the bars BE, AD, CF are 8.33 N/mm², 6.11 N/mm², and 9.17 N/mm²,
respectively.
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Which step in the reverse-engineering process involves the identification of subsystems and their relationship to one another?
The answer is analyze
Determine the minimum radius of a horizontal curve required for a highway if the design speed is 70 mph and the superelevation rate is 0.08.
Answer:
1819.4 ft
Explanation:
Let us assume the coefficient of side friction is 0.10
The radius of curve is given by the formula:
\(R=\frac{V^2}{g(f_s+\frac{e}{100} )}\)
Where R is the minimum radius of a horizontal curve, V is the speed, f is coefficient of side friction and e/100 = super elevation rate, g =acceleration due to gravity
Given that:
V = 70 mph = (70 * 1.467) ft/s = 102.69 ft/s, g =32.2 ft/s², e/100 = 0.08, f= 0.1
\(R=\frac{V^2}{g(f_s+\frac{e}{100} )}=\frac{102.69^2}{32.2(0.1+0.08)}=1819.4\ ft\)
the minimum radius of a horizontal curve is 1819.4 ft
Identify several areas in which a risk manager should be knowledgeable?
At least five fundamental components must be considered when creating a framework for risk management. They are risk governance, risk reporting and monitoring, risk reporting and assessment, risk mitigation, and risk identification.
What are the risk manager should be knowledgeable?They are aware of the potential effects those risks could have on the company and what preventative measures or backup plans should be put in place.
In order to set objectives or budgets, it is essential to analyze your growth and performance, which analytics help you do.
Risk managers find it challenging to reflect on the past or plan for the future without analytics. They make it straightforward to raise any company's productivity and effectiveness.
Therefore, risk managers are aware of all potential risks in their domain and, if feasible, beyond.
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Water at 27oC is being pumped through a water supply system illustrated in the figure from a sump at
atmospheric pressure to a tank under a pressure of 60kPa. Galvanised steel pipe of 100mm diameter is
used throughout, 2.5m length on the suction side and 80m length on the discharge side. The following
fittings are used:
Suction side: 2 unions k=0.05 (screwed), 1 lift foot valve-k=10.0 (with strainer), 1 standard elbow k=0.9.
Delivery side: 1 transition (65-100mm) k=0.4, 1 glove valve k=12.5(half open), 16 unions k=0.05
(screwed), 2 standard elbows k=0.9, 1 gate valve k=0.2(fully open), 1 sudden enlargement k=1 (exit to
tank).
Determine the total system head for flow rates from 0 to 20l/s in steps of 5 l/s. Hence, plot the system
head curve. Assume a constant friction factor based upon a mean flow rate of 10l/s. The dynamic viscosity
of water at 27oC may be taken as 0.9x10-3Pa.s). The relative roughness is 0.0015.
To determine the total system head for flow rates from 0 to 20l/s in steps of 5 l/s, we need to calculate the head loss due to friction and fittings on both the suction and delivery sides.
First, we need to calculate the Reynolds number to determine the flow regime in the pipe. The Reynolds number is given by:
Re = (ρVD)/μ
Where:
ρ = density of water = 1000 kg/m3
V = flow velocity
D = diameter of pipe = 100 mm = 0.1 m
μ = dynamic viscosity of water at 27°C = 0.9x10-3 Pa.s
At a flow rate of 10 l/s, the flow velocity is given by:
V = Q/A = (10x10-3 m3/s)/(π(0.1/2)2) = 2.54 m/s
Therefore, the Reynolds number is given by:
Re = (1000x2.54x0.1)/0.9x10-3 = 282222
Since the Reynolds number is greater than 4000, the flow regime is turbulent.
Next, we need to calculate the friction factor using the Colebrook equation:
1/sqrt(f) = -2.0log((ε/D)/3.7 + 2.51/(Re*sqrt(f)))
Where:
ε/D = relative roughness = 0.0015/0.1 = 0.015
Solving this equation iteratively using a spreadsheet or calculator, we get a friction factor of 0.018.
Using this friction factor, we can now calculate the head loss due to friction on both the suction and delivery sides using the Darcy-Weisbach equation:
hf = f(L/D)(V^2/2g)
Where:
L = length of pipe
D = diameter of pipe
V = flow velocity
g = acceleration due to gravity = 9.81 m/s2
For the suction side, the length of the pipe is 2.5 m and the fittings have a total equivalent length (TEL) of:
TEL = 2(0.05) + 10.0 + 0.9 = 11.95
Therefore, the total length of the suction side is 2.5 + 11.95 = 14.45 m.
The head loss due to friction on the suction side is given by:
hfs = 0.018(14.45/0.1)(2.54^2/2x9.81) = 1.14 m
For the delivery side, the length of the pipe is 80 m and the fittings have a TEL of:
TEL = 0.4 + 12.5 + 16(0.05) + 2(0.9) + 0.2 + 1 = 15.15
Therefore, the total length of the delivery side is 80 + 15.15 = 95.15 m.
The head loss due to friction on the delivery side is given by:
hfd = 0.018(95.15/0.1)(2.54^2/2x9.81) = 5.96 m
The total system head is given by the sum of the head losses due to friction and fittings on both the suction and delivery sides, plus the static head difference between the sump and tank:
hsystem = hfs + hfd + (60 - 1) = 64.1 m
To plot the system head curve, we repeat these calculations for flow rates of 5, 10, 15, and 20 l/s, and plot the results on a graph. The x-axis represents the flow rate and the y-axis represents the system head. The resulting curve shows the relationship between the flow rate and system head for this water supply system.
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What is the inductive reactance of a 20 mH inductor at a frequency of 100Hz?
Answer:
The correct approach is "12.56 Ω".
Explanation:
The given values are:
Frequency,
f = 100 Hz
Inductor length,
L = 20 mH
Now,
The inductive reactance will be:
⇒ \(X_L=2 \pi fL\)
On putting the estimated values, we get
⇒ \(=2 (3.14)\times 100\times 20\times 10^{-3}\)
⇒ \(=12.56 \ \Omega\)
Convert 5m/h to yds/week
918.63517 is the answer.
As an engineer you are responsible for selecting and procuring pump for your water distribution system. After some background study you selected and purchased an 1160 rpm Taco 4013 FI and CI series pumps with a 12.75 impeller diameter (for details see the ppt slides for the pump chapter). After procuring the pump you realize that you should have purchased a similar pump but with a 2000 rpm.
Required:
a. What will be your approach to handle this situation?
b. How would you prepare a performance curve at 2000 rpm?
Which statement best describes how power and work are related?
O A. Power is the ability to do more work with less force.
O B. Power is a measure of how quickly work is done.
O C. Power and work have the same unit of measurement
O D. Power is the amount of work needed to overcome friction.
Pls answer quick
B
a jsdnjwevhfgruewbkuwygru
Electrotechnology is important to aerospace engineering for what key reason? A. Spacecrafts must be lightweight. B. Spacecrafts need advanced electrical systems. C. Spacecrafts must have structural integrity. D. Spacecrafts must be resistant to extreme temperatures.
Electrotechnology is important to aerospace engineering for what key reason is option B. Spacecrafts need advanced electrical systems.
What is Electrotechnology?Electrotechnology plays a critical role in aerospace engineering because spacecrafts need advanced electrical systems to function.
These systems are responsible for powering and controlling various subsystems on the spacecraft, such as the propulsion system, the communication system, and the environmental control system.
Therefore, Electrotechnology is used to design and build these systems, as well as to troubleshoot and maintain them. It involves the use of electricity, electronics, and electromechanical systems to control and manipulate the flow of electrical energy.
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