A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is equal to 1000 NC/ at a point located a perpendicular distance of 0.1 m away from the center of the sheet, then the electric field at a point a perpendicular distance 0.2 m from the center of the sheet is:_______

a. 1000N/C
b. 500N/C
c. Impossible to say since we are not given Q and A
d. 250 N/C

When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.

When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.

When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.

From the given,

mass of the wood (m) = 2kg

the velocity of the wood (v) = 12 m/s

kinetic energy (K.E) = mv² / 2

                                = (2×12×12) / 2

                                = 144 J

Thus, the change in kinetic energy is 144 J.

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Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

\(F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}\)       (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

\(|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s\)

The interaction time to avoid that the water balloon breaks is 0.029s

Answer:

42.87

Explanation:

Google

OR

420/9.8 which equals 42.87.

Answer:

0

Explanation:

The speed of the ball when it reaches the floor is 0 because any object at rest or in uniform motion has no speed or velocity

Answer:

v = 4.0 m/s

Explanation:

       \(p_{f} = m_{w} * v_{w} + m_{g+w} *v_{g+w} = 0 (1)\)

       \(v_{g+w} =- \frac{m_{w} *v_{w}}{m_{g+w} } = - \frac{36.0kg *6.5m/s}{58.0kg } = -4.0m/s (2)\)

Answer:

The bulb which gives out heat like filament bulb. It helps to keep the egg warm (well eggs only hatch in warm condition).

Dont forget to give the brainliest

The type of light bulb used to incubate eggs are referred to as Heat filament bulbs.

Heat filament bulbs are different from other types of light bulbs in that it has

a very thin filament which makes it difficult to use up all the electric current

that passes through it. This then leads to the electrical energy being

converted to heat energy.

The heat energy generated is what is used by individuals to incubate the

eggs as they provide a very good heat and light source for the eggs.

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A kangaroo has to move vertically at least 8.34 m/s in order to leap over a 1.8 m-high object.

Determine the vertical circular motion's radius, measured in metres, and the approximate centripetal acceleration brought on by gravity, measured in metres per second squared. Step 2: Use the formula vmin=rg v min = r g to determine the object's minimum speed (the speed at the top of the circle).

(mass of kangaroo) x (acceleration due to gravity) x (height of the object) = 0.5 x (mass of kangaroo) x (minimum vertical speed)²

Canceling out the mass of the kangaroo on both sides, we get:

9.8 m/s² x 1.8 m = 0.5 x (minimum vertical speed)²

Solving for the minimum vertical speed, we get:

minimum vertical speed = sqrt((2 x 9.8 m/s² x 1.8 m)/0.5) = 8.34 m/s (rounded to two decimal places).

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Answer:

3117.914 m tall mountain

Explanation:

Chocolate bar gave him 2.2 Mega Joules energy

Gravitational Potential energy = mgh

now, if he store that energy entirely as gravitational potential energy then

mgh = 2.2×10^6

⇒ 72 × 9.8 × h = 2.2×10^6

⇒h = (2.2×10^6)/(72×9.8) = 3117.914 m

Answer:

h=4+85*time - 1/2 32*time^2

16time^2-85*time-106=0

use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).

time=(85+-sqrt(85^2+4*16*106) )/32

Explanation:

Recheck my work just in case I'm not good at this type of class but I wanted to help.

a. At maximum height h, the baseball has zero vertical velocity, so that with initial velocity v we have

\(0^2-v^2 = -2gh \implies h = \dfrac{v^2}{2g}\)

Given that \(v = 30 \frac{\rm m}{\rm s}\), the ball reaches a height of

\(h = \dfrac{\left(30\frac{\rm m}{\rm s}\right)^2}{2g} \approx \boxed{46\,\mathrm m}\)

b. At max height, the baseball's vertical velocity is such that

\(0=v-gt\)

For \(v = 30 \frac{\rm m}{\rm s}\), we find

\(gt=30\dfrac{\rm m}{\rm s} \implies t = \dfrac{30\frac{\rm m}{\rm s}}g \implies t \approx 3.1 s\)

which is half the time it spends in the air, making the total time about 6.1 s.

c. We saw in part (a) that

\(h = \dfrac{v^2}{2g}\)

If we halve the initial speed and replace \(v\) with \(\frac v2\), we get

\(h = \dfrac{\left(\frac v2\right)^2}{2g} = \dfrac14 \cdot \dfrac{v^2}{2g}\)

which means the max height is reduced by a factor of 1/4.

In part (b), we found the time to max height is

\(t = \dfrac{v}{g}\)

and halving the initial speed gives

\(t = \dfrac{\frac v2}g = \dfrac12 \cdot \dfrac{v}{g}\)

That is, the time to max height is reduced by a factor of 2 when the speed is halved, and so the overall time in the air is reduced by a factor of 2.

Answer:

magnitude is 1382.59 N/C

Explanation:

Given the data in the question;

The time taken is;

t = x / v

we substitute;

t = ( 2 × 10⁻²) / ( 5.69  × 10⁶ )

t = 3.5149 × 10⁻⁹ s

next, the acceleration is;

a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]

a =  2.42826 × 10¹⁴ m/s²

now, the electric field is;

E = ma / q

we know that;

mass of electron m = 9.11 × 10⁻³¹ kg,

charge of electron q = 1.60 × 10⁻¹⁹ coulomb

we substitute

E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹

E = 2.21214 × 10⁻¹⁶  / 1.60 × 10⁻¹⁹

E = 1.3826 × 10²¹

E = 1382.59 N/C

Therefore, magnitude is 1382.59 N/C  

Answer:

8.0s

Explanation:

45 km/h ÷ 3.6  = 12.5 m/s

t.v = d/t

vt/v = d/v

t = d/v = 100.0m /12.5 m/s = 8.0s

Hope this helps!!

The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer:

96,000joules!!!

Explanation:

Hope this helps u

No, the flood lamp does not accurately resemble the sun because it only emits 70 W/m2 of radiant energy, compared to the 1000 W/m2 that sunlight emits.

The majority of the energy that powers Earth's oceans, atmosphere, land, and biosphere comes from the Sun. Over the course of a year, the Earth receives an average of 342 watts of solar energy per square metre. There are 44 quadrillion (4.4 x 1016) watts of electricity in this, which is a huge amount of energy.

Solar energy is the term for the Sun's radiant light. Solar radiation can produce heat, trigger chemical reactions, or produce electricity.

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For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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Answer:

a = 7.749 ft/s²

Explanation:

First to all, we need to convert all units, so we can work better in the calculations.

The horizontal acceleration is asked in ft/s² so the units of speed will be the same. The Work is in BTU and we need to convert it in ft.lbf in order to get the acceleration and final speed in ft/s:

W = 10 BTU * 778.15 Lbf.ft / BTU = 7781.5 lbf.ft

Now, to get the acceleration we need to get the final speed of the object first. This can be done, by using the following expression:

W = ΔKe  (1)

And Ke = 1/2mV²

So Work would be:

W = 1/2 mV₂² - 1/2mV₁²

W = 1/2m(V₂² - V₁²)    (2)

Finally, we need to convert the mass in lbf too, because Work is in lbf, so:

m = 55 lb * 1 lbf.s²/ft / 32.174 lb = 1.7095 lbf.s²/ft

Now, we can calculate the final speed by solving V₂ from (2):

7781.5 = (1/2) * (1.7095) * (V₂² - 20²)

7781.5 = 0.85475 * (V₂² - 441)

7781.5/0.85475 = (V₂² - 400)

9103.83 + 400 = V₂²

V₂ = √9503.83

V₂ = 97.49 ft/s

Now that we have the speed we can calculate the acceleration:

a = V₂ - V₁ / t

Replacing we have:

a = 97.49 - 20 / 10

Hope this helps

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

Title) 50 (Bii) 45

Explanation:reflection, same angle as incidence

Answer:45

Explanation:

Answer:

C) 26.6

Explanation:

I don't know how to calculate vector

The angle between the two vectors is 117⁰

The given parameters;

vector A = 3.00i + 1.00j

vector B = -3.00i + 3.00j

The  angle between the two vectors is calculated as follows;

\(cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}\)

The dot product of vector A and B is calculated as;

\(A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6\)

The magnitude of vector A and B is calculated as;

\(|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}\)

The  angle between the two vectors is calculated as;

\(cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0\)

Thus, the angle between the two vectors is 117⁰

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Answer:

false.

Explanation:

Since temperature and kinetic energy of molecules are proportional, the more we increase the temperature of the solvent, the faster the solute will dissolve.

This increase of kinetic energy allows the solvent molecules to more effective break apart the solvent molecules that are held together by intermolecular forces.

We have that the balanced chemical equation   is mathematically given as.

2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2O

From the question we are told

Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation.

Generally the way to balance an equation is by making all elements present on the Left hand side(LHS) same with the right hand side RHS.

Therefore

The equation is mathematically given as.

We consider the Left hand side(LHS) first.

Then we consider the right hand side RHS.

Therefore the balanced chemical equation   is mathematically given as.

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If a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes, then it would have traveled 37.49 meters

The total distance covered by any object per unit of time is known as speed.

It depends only on the magnitude of the moving object.

As given in the problem a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes.

The distance traveled by the tumbleweed = speed ×time

                                                                       =  16.3 meters/minute×minutes

                                                                       =37.49 meters

Thus, the distance traveled would be 37.49 meters.

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Answer:C

Explanation:

Given:

The mass of the teenager is m = 45 kg

The potential energy is P.E. = 2205 J

To find the height of the diving board.

Explanation:

The height can be calculated using the formula

Here, g = 9.8 m/s^2 is the acceleration due to gravity.

On substituting the values, the height will be

Thus, the height of the diving board is 5 m

Answer:

The magnitude of the work done by the worker is 303 J.

Explanation:

The work done by the worker can be found as follows:

\( W = |F|\cdot |d| cos(\alpha) \)                              

Where:

F: is the force applied by the worker

d: is the displacement = 5.0 m

α: is the angle between the force applied and the displacement = 180°

We need to find the force applied by the worker:

\(\Sigma F = ma\)

Taking as positive the movement direction of the crate we have:

\( -F - F_{\mu} + P_{x} = 0 \)  

Where:              

m: is the crate's mass

a: is the acceleration = 0 (It is moving at constant speed)

F: is the force applied by the worker

Pₓ: is the weight in the horizontal direction    

\(F_{\mu}\): is the frictional force  

Hence, the force applied by the worker is:            

\(F = P_{x} - F_{\mu} = mgsin(\theta) - \mu mgcos(\theta)\)

\( F = 50 kg*9.81 m/s^{2}*(sin(25) - 0.33cos(25)) = 60.6 N \)  

Then, the work done by the worker is:                        

\( W = |F|\cdot |d| cos(\alpha) = 60.6 N*5.0 m*cos(180) = -303 J \)                              

Therefore, the magnitude of the work done by the worker is 303 J.

I hope it helps you!                                            

The work is done by the worker will be 303 J. Work done is described as the multiplication of applied force and the amount of displacement.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The given data in the problem is;

F is the force applied by the worker

d is the displacement = 5.0 m

α is the angle between the force applied and the displacement = 180°

m is the crate's mass=  50 kg

a is the acceleration = 0

Pₓ: is the weight in the horizontal direction    

The net force on the crate is found as;

\(\rm F_{net}= P_X - F_{\mu} \\\\ \rm F_{net}= mg sin \theta - \mu mg cos \theta \\\\ \rm F_{net}=50 \times \times 9.81 (sin 25^0 -0.33 cos(25) \\\\ \rm F_{net}= 60.6 N \\\\\)

The work done  by the worker will be;

\(\rm W= Fd cos \alpha \\\\ \rm W= 60.6 \times 5.0 cos 180^0 \\\\\rm W=-303 \ J\)

Hence the work is done by the worker will be 303 J.

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Answer:

true

Explanation:

my own opinion

Explanation:Beta Rays are not Electromagnetic Waves

Beta rays also known as beta radiation is obtained through the emission of an electron. Beta rays are not electromagnetic waves because they are charged particles and are capable of getting deflected by the magnetic field.

Microwaves are a form of "electromagnetic" radiation; that is, they are waves of electrical and magnetic energy moving together through space. Electromagnetic radiation spans a broad spectrum from very long radio waves to very short gamma rays. ... But the most common consumer use of microwave energy is in microwave ovens.

Visible light is carried by photons, and so are all the other kinds of electromagnetic radiation like X-rays, microwaves and radio waves. In other words, light is a particle.

So the answer is sound.

The sound wave is not an electromagnetic wave

In terms of science, electromagnetic radiation is made up of electromagnetic field waves that travel over space while carrying electromagnetic radiant energy and velocity. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves.

In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Given data ,

Let the electromagnetic wave be represented as A

Now , when A = microwaves

Microwaves are waves of electrical and magnetic energy traveling across  radio waves and infrared radiation on the electromagnetic spectrum combined. There is a wide range of electromagnetic radiation, from very lengthy radio waves to very brief gamma rays.

And , when A = x-rays

X-rays are high-frequency, and thus high-energy, electromagnetic radiation

They are found to reside between ultraviolet radiation and gamma rays on the electromagnetic spectrum.

X-rays are more energetic because they have shorter wavelengths. When discussing X-rays, we frequently refer to their energy rather than its wavelength.

Now , the sound waves are not electromagnetic waves as sound waves are examples of mechanical waves

Hence , sound waves are not electromagnetic waves

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Answer:

The net force on the desk is zero.

Answer:

1. The electric potential would stay the same.

2. The electric potential energy would double

Explanation:

1. Since the electric potential at the point is V and is not dependent on the charge q, the electric potential at the point still remains the same even if the charge q is doubled to 2q.

So, the electric potential remains the same when the charge is doubled to 2q.

2. Since potential energy U = qV where q = charge and V = electric potential. So when the charge is q and electric potential, V, the electric potential energy at the point is U = qV.

When the charge is doubled to 2q and the electic potential remains the same, the electric potential energy is now U' = 2qV = 2U (since U = qV).

So, the electric potential energy at the point is doubled when the charge is doubled.