A traffic fanatic wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. She assumes that each car is 18 feet long, travels at speed s, and follows the car in front of it at a safe distance for that speed. She finds that the number N of cars that can pass a given spot per minute is modeled by the function N(s)

Answers

Answer 1

To estimate the maximum number of cars that can safely travel on a road at a given speed, the traffic fanatic should consider the free-flow speed, headway between cars at different speeds, and other factors affecting traffic flow.

The traffic fanatic's assumption is based on the concept of traffic flow theory, which aims to understand and predict the behavior of traffic on a road network. The safe distance between cars is known as the "headway" and it is dependent on the speed of the cars.

The traffic flow theory proposes that the maximum traffic flow occurs at a certain speed called the "optimal speed" or "free-flow speed". At this speed, the headway between cars is minimized, and the maximum number of cars can safely travel on the road.

The function N(s) represents the number of cars that can pass a given spot per minute at a given speed s. In this case, the function is modeled as N(s) = 150, which means that the maximum number of cars that can pass the given spot per minute is 150, regardless of the speed.

However, in reality, the number of cars that can pass a given spot per minute varies with speed. At speeds lower than the free-flow speed, the headway between cars increases, and the number of cars that can pass the given spot decreases. At speeds higher than the free-flow speed, the headway between cars decreases, and the number of cars that can pass the given spot also decreases due to increased congestion and potential accidents.

Therefore, to estimate the maximum number of cars that can safely travel on a particular road at a given speed, the traffic fanatic should consider the free-flow speed and the headway between cars at different speeds. She can use traffic flow models such as the Greenshields model or the Underwood model to estimate the traffic flow at different speeds and densities.

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Related Questions

PLEASE HELP

A pendulum is in a spacecraft to measure
acceleration during lift off. Before the launch, its period
is 6.5 X 10-3 s. At a point during lift off, its period is 3.1
X 10-3 s. What is the acceleration at this point?

Answers

Answer:

im just 15 yearsold hehhez i dont know that either

Which model correctly represents the product or products of the chemical reaction?

Which model correctly represents the product or products of the chemical reaction?

Answers

The model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.

What is a Chemical reaction?

A chemical reaction may be defined as a type of reaction in which one or more substances that are known as the reactants are considerably converted to one or more different substances that are known as the products.

In a chemical reaction, the molecules or atoms of the substance may always remain the same in the reactant or product. That is the mass of the chemical substance may always remain the same. While model 2 and 4 increases the mass of compound A in the given reaction. So, they are eliminated.

Option 3 is incorrect because when you get a product of any chemical reaction, it may never be separated automatically as described in option C.

Therefore, the model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.

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a positively charged test particle is placed midway between two fixed, identical positively charged source particles. part a is the test particle in a stable or unstable equilibrium at that location?
a) The test particle is in a stable equilibrium regardless of dimensionality.
b) The test particle is in stable equilibrium if these particles are constrained to one dimension and in unstable equilibrium if the particles can move in at least two dimensions.
c) The test particle is in stable equilibrium if these particles are constrained to one or two dimensions and in unstable equilibrium if the particles can move in three dimensions.
d) The test particle is in an unstable equilibrium regardless of dimensionality.

Answers

b) The test particle is in stable equilibrium if the moving particles can only travel in one dimension, and in unstable equilibrium if they can move in at least two dimensions.

In this case, the dimensionality of the system affects the test particle's stability. The test particle will be in a stable equilibrium if the system is limited to one dimension. The test particle is in this case equally far from the two source particles, and as a result, each of them exerts electrostatic forces on it that are equal and opposing and cancel one another out. As a result, the test particle doesn't move from its place.

The test particle, on the other hand, is in an unstable equilibrium if the system exists in two or more dimensions.

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You swing a 3.00 kg stone in a circle, using the full length of a thin 75.0cm rope. At what speed should you swing it so its acceleration will be 9.8 m/s^2? m/s

Answers

To achieve an acceleration of 9.8 m/s², you should swing the 3.00 kg stone at a speed of approximately 2.71 m/s.

The centripetal acceleration formula, a = (v² / r), relates the acceleration (a) to the velocity (v) and the radius (r) of the circular path. Rearranging the formula to solve for v gives v = sqrt(a * r). In this case, the acceleration is given as 9.8 m/s² and the radius is half the length of the rope, which is 0.75 m. Substituting these values into the formula, we get v = sqrt(9.8 m/s² * 0.75 m) ≈ 2.71 m/s. Therefore, to achieve an acceleration of 9.8 m/s², you should swing the stone at a speed of approximately 2.71 m/s.

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To warm up for a match, a tennis player hits the 58.0 g ball vertically with her racket. If the ball is stationary just before it is hit and goes 5.50 m high, what impulse did she impart to it?

Answers

The impulse imparted by the tennis player to the ball is 29.7 Ns. The impulse-momentum theorem states that the impulse imparted on an object is equal to the change in momentum of the object.


In this case, the momentum of the ball just before it is hit is zero since it is stationary. The momentum of the ball just after it is hit and reaches a height of 5.50 m can be calculated using the equation p = mv, where p is momentum, m is mass, and v is velocity. Since the ball only moves vertically, its final velocity is zero. Therefore, its initial momentum is equal to its final momentum. The mass of the ball is 58.0 g, which is 0.0580 kg.

The change in momentum is therefore: Δp = p_final - p_initial = 0 - (0.0580 kg * 9.81 m/s^2 * 5.50 m) = -3.2061 Ns. The impulse imparted on the ball is the opposite of the change in momentum, so it is 3.2061 Ns. However, since impulse is a vector quantity, we must also include the direction, which is upward. Therefore, the impulse imparted by the tennis player to the ball is 29.7 Ns upward.

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two objects are “r” distance apart and experience an afghan equal to 15 N. What must we modify their distance by to experience an Fg of 135 N

Answers

The new distance between the two objects should be r/3 units to have the attractional force of 135 N

What is Gravitational force?

The gravitational force, which is what pushes mass-containing objects toward one another. We frequently consider the pull of gravity from the Earth. Your body is kept on the ground by this force. However, all mass-bearing objects are pulled toward one another by gravity.

The gravitational pull between two masses Ocean tides rise and fall due to the moon's gravitational pull. of or pertaining to a strong inclination or movement in the direction of something or someone: There has been a lot of research on why they gravitate toward harmful conduct.

Gravity is a basic interaction that causes all objects with mass or energy to attract one another.

Let the masses be M and m kg

The distance is given as'r'

So when the distance is 'r'

GMm/r² = 15

Now when the distance is modified to z

GMm/z² = 135

The ratio of the two

(GMm/z²)/(GMm/r²) = 135/15

⇒r²/z² = 9

⇒z = r/3

The new distance between the two objects should be r/3 units to have the attractional force of 135 N

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A race car sets out on a 100.0 km race. At the halfway marker, the pit crew notes that the driver has averaged only 80.0 km/h. What speed must the driver maintain for the second half of the race in order to average 100.0 km/h overall?​

Answers

The driver has to maintain the speed of 133.3 km/h for second half of the race in order to average 100km/h.

What does "average velocity" and "speed" mean?

In order to calculate average velocity, divide the change in position or displacement (x) by the time intervals (t) during which the displacement takes place. Depending on the displacement's sign, the average velocity can either be positive or negative. Meters per second (m/s or ms-1) is the SI measure for average velocity. By dividing the entire distance the body has traveled by the amount of time it took to cross that distance, the average speed formula can be calculated.

To complete the race in 1 hr => 100 km/hr in a 100 km

Driver is going 80 km/hr at half way marker (50m).

Time taken to cover 50m = 50 km * (1 hr/80 km) = 5/8 hour.

Total time to complete the race on average 100 km/hr is 1 hr.  

Hence, time required to cover second half of the race => 1 hr - 5/8 hr          

                                                                                              => 3/8 hr

v= 50km/(3/8 hr) = 50*(8/3) = 133.3 km/h

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A cylinder at rest is released from the top of a ramp, as shown above. The ramp is 1.0 m high, and the cylinder rolls down the ramp without slipping. At the bottom of the ramp, the cylinder makes a smooth transition to a small section of a horizontal table and then travels over the edge at a height of 1.0 m above the floor, eventually landing on the floor at a horizontal distance of 1.5 m from the table. 3. As the cylinder rolls down the ramp, how do the potential energy of the cylinder-Earth system and the kinetic energy of the cylinder change, if at all? Potential Energy of Kinetic Energy Cylinder-Earth System of Cylinder (A) Stays the same Increases (B) Stays the same Decreases (C) Decreases Increases (D) Decreases Decreases

Answers

Cylinder loses height as it moves down the ramp, causing a decrease in gravitational potential energy. Simultaneously, the cylinder gains speed, resulting in an increase in its kinetic energy. Therefore, the correct answer is (C) Decreases Increases.

As the cylinder rolls down the ramp, the potential energy of the cylinder-Earth system decreases due to the cylinder's decreasing height. At the same time, the kinetic energy of the cylinder increases due to its increasing velocity as it gains speed while rolling down the ramp. Once the cylinder reaches the bottom of the ramp, its potential energy has been fully converted into kinetic energy. As the cylinder travels on the horizontal section of the table, it maintains its constant velocity, so its kinetic energy remains the same. When the cylinder rolls off the table and falls to the ground, its kinetic energy is converted into potential energy as it gains height, but then it is converted back into kinetic energy as it falls to the ground again. Overall, there is no change in the total energy of the system, which remains constant throughout the process.

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Hey can anyone pls pls pls answer dis i rlly need it i only need the conclusion!!

Hey can anyone pls pls pls answer dis i rlly need it i only need the conclusion!!
Hey can anyone pls pls pls answer dis i rlly need it i only need the conclusion!!

Answers

Explanation:

since oil needs more boiling time and a higher boiling temperature the oil would have to be in the pot longer than the water if it needs to be boiled longer that is why the blue line for oil temp. is significantly higher than that of the water temp.

Engineers are using computer models to study train collisions to design safer
train cars. They start by modeling an elastic collision between two train cars
traveling toware each other. Car 1 is traveling east at 6 m/s and has a mass
of 3,154 kg. Car 2 is traveling west at 23 m/s and has a mass of 8,296 kg.
After the collision, car 1 has a final velocity of 7 m/s west. What is the final
velocity of car 2?
A. 23 m/s west
B. 18 m/s west
O C. 23 m/s east
D. 18 m/s east

Answers

Answer:

B. 18 m/s west

Explanan

I took the test

Engineers are using computer models to study train collisions to design safer train cars. They start by modeling an elastic collision between two train cars traveling tower each other. Car 1 is traveling east at 6 m/s and has a mass of 3,154 kg. Car 2 is traveling west at 23 m/s and has a mass of 8,296 kg. After the collision, car 1 has a final velocity of 7 m/s west. The final velocity of car 2 is 23 m/s east. Hence, Option C is the correct answer.

What is  law of conservation of momentum ?

Conservation of momentum states that for two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

Using conservation of momentum,

m1v1 + m2v2 = m1 v1' + m2 v2'

Given,

m1 = 3154 kg

v1= 6m/s

m2 = 8296 kg

v2 = 23 m/s

v1' = 7m/s

v2' = ?

Substituting the values,

3154 * 6 + 8296 * 23 = 3154 * 7 + 8296 v2'

209732 - 22078 = 8296 v2'

187654 = 8296 v2'

v2' = 22.62 ≈ 23 m/s east

Car 1 is traveling east at 6 m/s and has a mass of 3,154 kg. Car 2 is traveling west at 23 m/s and has a mass of 8,296 kg. After the collision, car 1 has a final velocity of 7 m/s west. The final velocity of car 2 is        23 m/s east.

Hence, Option C is the correct answer.

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Rutherford's scattering experiments gave the first indications that an atom consists of a small, dense, positively charged nucleus surrounded by negatively charged electrons. His experiments also allowed for a rough determination of the size of the nucleus. In this problem, you will use the uncertainty principle to get a rough idea of the kinetic energy of a particle inside the nucleus.
Consider a nucleus with a diameter of roughly 5.0×10−15 meters.
Part A
Consider a particle inside the nucleus. The uncertainty Δx in its position is equal to the diameter of the nucleus. What is the uncertainty Δp of its momentum? To find this, use ΔxΔp≥ℏ.
Express your answer in kilogram-meters per second to two significant figures.
Part B
The uncertainty Δp sets a lower bound on the average momentum of a particle in the nucleus. If a particle's average momentum were to fall below that point, then the uncertainty principle would be violated. Since the uncertainty principle is a fundamental law of physics, this cannot happen. Using Δp=2.1×10−20 kilogram-meters per second as the minimum momentum of a particle in the nucleus, find the minimum kinetic energy Kmin of the particle. Use m=1.7×10−27 kilograms as the mass of the particle. Note that since our calculations are so rough, this serves as the mass of a neutron or a proton.
Express your answer in millions of electron volts to two significant figures.

Answers

Rutherford's scattering experiments gave the first indications that an atom consists of a small, dense, positively charged nucleus surrounded by negatively charged electrons. Consider a nucleus with a diameter of roughly 5.0×\(10^{-15}\) meters. The uncertainty in momentum is 2.1×\(10^{-20}\) kg m/s. The minimum kinetic energy is 1.1×\(10^{6}\) eV, or 1.1 million electron volts.

Part A

The uncertainty principle states that ΔxΔp≥ℏ, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and ℏ is the reduced Planck constant.

For a particle inside the nucleus, Δx is equal to the diameter of the nucleus, which is 5.0×\(10^{-15}\) meters. Therefore

ΔxΔp≥ℏ

(5.0×\(10^{-15}\) )(Δp)≥(1.054×\(10^{-34}\))

Δp≥(1.054×\(10^{-34}\))/(5.0×\(10^{-15}\) )

Δp≥2.11×\(10^{-20}\) kgm/s

Rounded to two significant figures, the uncertainty in momentum is 2.1×\(10^{-20}\) kgm/s.

Part B

The minimum kinetic energy Kmin of a particle in the nucleus can be found using the formula

Kmin = \(p^{2}\) / 2m

Where p is the minimum momentum of the particle, and m is the mass of the particle.

Substituting the given values

Kmin = (2.1×\(10^{-20}\) )^2 / (2×1.7×\(10^{-27}\))

Kmin = 1.7×\(10^{-10}\) J

To convert this to electron volts, we can use the conversion factor 1 eV = 1.602×\(10^{-19}\) J

Kmin = ( 1.7×\(10^{-10}\) J) / (1.602×\(10^{-19}\) J)

Kmin = 1.06×\(10^{9}\)eV

Rounded to two significant figures, the minimum kinetic energy is 1.1×\(10^{6}\) eV, or 1.1 million electron volts.

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The uncertainty principle states that ΔxΔp≥ℏ, where ℏ is Planck's constant divided by 2π (ℏ = h/2π). We are given Δx = 5.0×\(10^{-15}\) meters. Therefore, ΔxΔp≥ℏ gives us: Δp ≥ ℏ/Δx, Δp ≥ (h/2π)/Δx

Δp ≥ (6.63×\(10^{-34}\) J s)/(2π × 5.0×\(10^{-15}\) m), Δp ≥ 2.1×\(10^{-20}\) kg m/s. Therefore, the uncertainty in momentum is Δp = 2.1×\(10^{-20}\) kg m/s. The minimum kinetic energy \(K_{min}\)of a particle is given by \(K_{min}\)= \(p^{2}\)/(2m), where p is the momentum of the particle and m is its mass. We are given Δp = 2.1×\(10^{-20}\) kg m/s and m = 1.7×\(10^{-27}\) kg. Therefore, \(K_{min}\) = \(p^{2}\)/(2m), \(K_{min}\) = (2.1×\(10^{-20}\) kg m/s)^2/(2 × 1.7×\(10^{-27}\) kg), \(K_{min}\) = 1.5×\(10^{-10}\) J. To convert to electron volts, we divide by the charge of an electron (1.602×\(10^{-19}\) C) and multiply by \(10^{-6}\) to get:\(K_{min}\) = (1.5×\(10^{-10}\) J)/(1.602×\(10^{-19}\) C) × \(10^{-6}\), \(K_{min}\) = 0.93 MeV (million electron volts). Therefore, the minimum kinetic energy of a particle inside the nucleus is approximately 0.93 MeV.

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If a glider on an air track collides with another glider with twice the mass and then they stick together, their resultant velocity will be___ that of the original glider?

Answers

Answer:

twice

just know it

Vaughn Manufacturing manufactures and sells solar chargers for $90 each. Variable costs are $50 per unit, and fixed costs total $120000. What amount of sales revenue is needed by Vaughn to break even

Answers

$270,000 amount of sales revenue is needed by Vaughn to break even.

How much sales revenue is needed to break even?

To calculate the sales revenue needed to break even, we need to consider the fixed costs and the variable costs per unit.

Fixed costs: $120,000

Variable costs per unit: $50

To break even, the total sales revenue should cover both the fixed costs and the variable costs. The formula to calculate the break-even sales revenue is:

Break-even sales revenue = Fixed costs / (1 - (Variable costs / Sales price per unit))

In this case, the sales price per unit is $90.

Break-even sales revenue = $120,000 / (1 - ($50 / $90))

                     = $120,000 / (1 - 5/9)

                     = $120,000 / (4/9)

                     = $120,000 * (9/4)

                     = $270,000

Therefore, Vaughn Manufacturing needs $270,000 in sales revenue to break even.

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Barbera argues that simple machines like levers and pulleys reduce the amount of work needed
to get things done. Clarice argues that machines don’t decrease work - they decrease force.
Who is right and why?

Answers

Answer:

Machines can reduce force but not work.

Work = force * distance

If a machine reduces the force input by a factor of two, say, then the distance traveled by the applied force must be doubled

One cannot get more work out of a machine than the work input to the machine.

17.Shenna is observing two mineral samples in science class. He records his observations of the

samples in

the table below,

Minerals

Pyrite

Description

cubic crystals

Mica

breaks into thin sheets

Which property of the samples has Shenna recorded?

A. cleavage

B. hardness4

C. luster

D. streak

Answers

Shenna has recorded the property of cleavage. Cleavage refers to the tendency of a mineral to break along flat, smooth planes due to its internal structure.structure.So,The correct option would be (A) Cleavage.

Cleavage is a property that describes how a mineral breaks along planes of weakness, resulting in smooth, flat surfaces. It is one of the key characteristics used to identify and classify minerals.

In the given observations, Shenna noted that the mineral sample called "Mica" breaks into thin sheets. This characteristic indicates that Mica exhibits cleavage. When Mica is subjected to stress or force, it breaks along flat planes, resulting in thin, sheet-like fragments.

On the other hand, Shenna described the mineral sample called "Pyrite" as having cubic crystals. While this information is valuable for identifying Pyrite, it does not pertain directly to the property of cleavage.

Shenna has recorded the property of cleavage based on his observation that the mineral sample called "Mica" breaks into thin sheets.sheets.Hence the correct answer is Cleavage. Cleavage refers to the tendency of a mineral to break along flat, smooth planes due to its internal structure.

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A discordant igneous intrusion
Select one:
a.
cuts across bedding planes.
b.
will consist dominantly of pyroclasts.
c.
parallels sedimentary rock layering.
d.
produces deadly explosions.

Answers

A discordant igneous intrusion cuts across bedding planes. Here is the detailed explanation of the given question:Explanation:The Discordant igneous intrusion is the formation of an igneous rock mass when magma is injected into a host rock and cools there.

This form of igneous intrusion does not conform to the stratification or layering of the existing rock mass because it cuts across it.Therefore, a discordant igneous intrusion cuts across bedding planes.Option (a) is correct. It is the only option that describes the features of discordant igneous intrusion. Hence, the correct answer is option (a).

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a relaxed spring of length 0.12 m stands vertically on the floor; its stiffness is 1370 n/m. you release a block of mass 0.5 kg from rest, with the bottom of the block 0.5 m above the floor and straight above the spring. how long is the spring when the block comes momentarily to rest on the compressed spring?

Answers

The length of the spring when the block comes momentarily to rest on it is 0.076 m.

We can use the conservation of energy to solve this problem. The initial potential energy of the block is given by its mass (m) times the gravitational acceleration (g) times the height (h) above the floor

U_i = mgh

At the moment when the block comes to rest on the compressed spring, all of its initial potential energy will be converted into elastic potential energy stored in the spring, given by

U_s = (1/2)kx^2

where k is the stiffness of the spring and x is the amount by which the spring is compressed from its original length.

Since energy is conserved, we can equate these two expressions

mgh = (1/2)kx^2

Solving for x, we get

x = sqrt((2mgh)/k)

Plugging in the values given in the problem, we get

x = sqrt((2 × 0.5 kg × 9.81 m/s^2 × 0.5 m) / 1370 N/m)

x = 0.044 m

Therefore, the spring is compressed by 0.044 m from its original length of 0.12 m. The length of the spring when the block comes momentarily to rest on it is

length of spring = original length - amount of compression

length of spring = 0.12 m - 0.044 m

length of spring = 0.076 m

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True or False? Index Fossils are used to help constrain the relative age of the rocks in an area?

Answers

The answer to this question is True

Describe the development of our current model of the atom from the ancient Greeks till the 20 th century. For the toolbar, press \( \mathrm{ALT}+\mathrm{F} 10 \) (PC) or \( \mathrm{ALT}+\mathrm{FN}+\m

Answers

The development of our current model of the atom evolved over centuries, starting with the ancient Greeks' conceptualization of the atom as an indivisible particle.

Around the fifth century BCE, the Greeks became the first people to put forth the idea of the atom. Democritus and other philosophers proposed the idea that matter is made up of tiny, indivisible pieces called atoms, but there was no experimental support for this theory at the time. Although it survived for centuries, this idea did not significantly change until the 19th century.

Scientific developments in the 19th century led to a deeper comprehension of atoms. With notable contributions from Michael Faraday's work on electromagnetic induction and Benjamin Franklin's electricity tests, scientists discovered the presence of electrical charges.

Groundbreaking investigations that transformed our understanding of the atom took place in the early 20th century. The electron, a negatively charged particle inside the atom, was discovered in 1897 as a result of J.J. Thomson's cathode ray tube studies. Atoms are shown to have a small, dense, positively charged nucleus that is around by negatively charged electrons in a large empty region by Ernest Rutherford's gold foil experiment in 1911.

The Rutherford model, sometimes known as the planetary model, was created in response to the discovery of the nucleus. This model, however, encountered problems since it was unable to explain the stability of atoms and the behavior of electrons. Researchers like Werner Heisenberg and Erwin Schrödinger made significant contributions to the development of quantum mechanics in the 1920s and 1930s.

The wave-particle duality and quantum mechanical concepts are both included in the current model of the atom, also referred to as the quantum mechanical model. In orbitals, which are areas of probability where electrons are most likely to be located, it says that electrons exist. Around the nucleus, these orbitals are arranged into energy levels or shells. The behavior of subatomic particles like protons and neutrons, which make up the nucleus, is also taken into consideration by the model.

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A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.

Answers

The electric potential at point b experienced by the charge cab be determined using the formulas given.

Electric potential

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

V is the electric potentialF is electric forceE is the electric fieldq is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

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Of the following, which is a renewable energy resource?

a.

coal

c.

geothermal energy

b.

kerosene

d.

natural gas



Please select the best answer from the choices provided


A

B

C

D

Answers

natural gas djdjdjjdjdjdjd

coal or natural gas i think


b. Which station broadcasts waves with a shorter wavelength

Answers

Answer:

blue and purple light

Explanation:

Light waves have very, very short wavelengths. Red light waves have wavelengths around 700 nanometers (nm), while blue and purple light have even shorter waves with wavelengths around 400 or 500 nm.

A rocket is travelling vertically upwards. Three vertical forces act on it.
The thrust acts upwards and is equal to 100 000N.
The weight acts downwards and is equal to 80 000N.
What is the air resistance force acting on the rocket when it is travelling upwards at constant
speed?
A 20 000N downwards
B 20 000N upwards
C 180 000N downwards
D 180 000N upwards

Answers

The answer is b if you see that 100,000 over powers the 80,000 and the biggest number defeats the small number so I’m this case the big number is going up so it with even out 20,000 up
The answer is B

If we subtract the upward force from the downward force we will get 20,000

100,000 - 80,000 = 20,000

What is the velocity of a plane that traveled 3,000 miles from new york to California?

Answers

The velocity of a plane that traveled 3,000 miles from new york to California is 666.6 miles per hour.

we use formula

v=d/t= 3000/4.5= 666.66 miles per hour.

Definition of velocity

Based on the Viewpoint of Physics In physics, speed is a quantity that indicates the speed of an object plus the direction of its motion. Like displacement, velocity is direction. Velocity is the speed in a given direction, and is usually measured in meters per second (m/s or ms 1 ).

In addition, the meaning of velocity can be related to the definition as the rate of change of an object's position with respect to the frame of reference and time. The International standard unit of velocity is meters per second (ms -1 ). If there is a change in magnitude or direction of the velocity of an object, the object is said to be accelerating.

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A tank is full of water. Find the work required to pump the water out of the spout. (use 9. 8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 6 m and h = 2 m. ).

Answers

70.934648 MJ of work is needed to pump the water out of the spout.

The tank is shaped like a globe. the distance to the mass's center = h+r =6+2=8

Weight of water in tank = 9.8×π×6³×1000×4/3

= 8.866831×10⁶ N

to empty the tank Work done  = 8 × 8.866831×10⁶

=70.934648×10⁶ J

= 70.934648 MJ.

A pump is a mechanical device used to transport fluids (liquids, gases, or occasionally slurries). It commonly converts electrical energy into hydraulic energy. Pumps can be divided into three main categories based on how they move the fluid: direct lift, displacement, and gravity pumps.

Pumps use a mechanism to move the fluid (usually a rotary or reciprocating one) and require energy to operate. Pumps exist in a variety of sizes, from microscopic for use in medical applications to enormous industrial pumps, and they can be powered by a variety of energy sources, including electricity, manual operation, engines, or wind power.

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A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)

Answers

Answer:

T= 0.6 sec

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

what is fire proof plastic​

Answers

Explanation:

.Flame retar,dant plastic additi,ves are compounds added to plastics and other materials to inhibit, suppress or de,lay combustion. These compounds are useful in impending burning in the ign,ition phase of fire. They do not prevent char,ring or melting nor do they increase the heat resistance of a material

does putting batteries in the freezer recharge them?

Answers

Simply put, no. Try not to be hard on you if this is the first time you've heard it; in some cases, a belief was once accurate. A bulk of energy storage units kept in fridge are basic AA, AAA, C, & D batteries.

What three types of batteries are there?

There are three main battery kinds that may be used by consumers. They are lithium ion, nickel metal hydride, and alkaline. Each kind has benefits and drawbacks. Each of them has a unique position in the history of technology.

What kind of battery is ideal?

With the greatest energy density of just about any battery cell, lithium batteries are made of this very light metal. As a result, they have a higher energy capacity than battery systems or any other separate bat of a similar size. Additionally, they work admirably in the both cold and warm environments.

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FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) thank you very much!!! (22pts)

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions

Answers

b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .

Item 1
The figure presents a block on a horizontal surface attached to a horizontal spring. The other end of the spring is attached to a wall. The spring is labeled 50 newtons per meter, and the box is labeled 0.5 kilogram. The horizontal position of the center of spring is x equals negative 0.3 meter. The horizontal position of the center of the box is x equals 0 meters. When the spring is stretched the box will be at a horizontal position of x equals 0.3 meter.
A block of mass 0.5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50N/m. The other end of the spring is attached to a wall, and there is negligible friction between the block and the horizontal surface. When the spring is unstretched, the block is located at x=0m. The block is then pulled to x=0.3m and released from rest so that the block-spring system oscillates between x=−0.3m and x=0.3m. What is the magnitude of the acceleration of the block and the direction of the net force exerted on the block when it is located at x=0.3m?


Magnitude of Acceleration Direction of Net Force
30m/s2 Positive
, Magnitude of Acceleration Direction of Net Force 30 meters per second squared Positive

Magnitude of Acceleration Direction of Net Force
30m/s2 Negative
, Magnitude of Acceleration Direction of Net Force 30 meters per second squared Negative

Magnitude of Acceleration Direction of Net Force
0 m/s2 Positive
, Magnitude of Acceleration Direction of Net Force 0 meters per second squared Positive

Magnitude of Acceleration Direction of Net Force
0 m/s2 Negative

Answers

Explanation:

No need to calculate the force you can just find by Hookes law

Hookes law states that

F=-kx

Where

F is force ,k is spring constant x is distance

So

force remains negative as per it

Acceleration=50/0.5÷1/3=100/3=33≈-30m/s²

Option B

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