A truck with the mass of 8 ton travels at a velocity of 60km/h and collides with a truck with mass of 5 ton travelling in the same direction at 40kh/h. After the collision the two trucks move together. Calculate the final common velocity if the TWO trucks in m/s after the collision?

Explanation:

Newton's second law of motion gives the relation between mass, force and acceleration.

We know that,

Force, F = mass (m) × acceleration (a)

or

\(m=\dfrac{F}{a}\)

or

\(a=\dfrac{F}{m}\)

Hence, this is the required solution.

A piece of iron absorbs 3589 Joules of heat energy and its temperature changes from 15°C to 105°C. If it has a heat capacity of 8. 34 J/g°C, 0.06 kg is the mass of the iron .

To find the mass of the iron, we can use the equation for heat capacity:

Q = m * C * ΔT. Given that the iron absorbs 3589 Joules of heat energy, has a heat capacity of 8.34 J/g°C, and undergoes a temperature change from 15°C to 105°C, we can calculate the mass of the iron.

The equation for heat capacity is Q = m * C * ΔT, where Q is the heat energy absorbed, m is the mass, C is the heat capacity, and ΔT is the change in temperature.

We are given:

Q = 3589 J

C = 8.34 J/g°C

ΔT = 105°C - 15°C = 90°C

We can rearrange the equation to solve for the mass:

m = Q / (C * ΔT)

Substituting the given values, we have:

m = 3589 J / (8.34 J/g°C * 90°C)

m=0.06kg

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Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

\(\Large \boxed{\displaystyle density \ (kgm^{-3})=\frac{mass\ (kg)}{volume \ (m^3)} }\)

Answer:

Answer is neutrons.

Explanation:

The nucleus contains two types of subatomic particles, protons and neutrons.the protons have a positive electrical charge and the neutrons have no electrical charge.

I hope it's helpful!

Answer:

\(A \to rad/s\)

\(B \to rad/s^3\)

Explanation:

\(\omega_z(t)=A + Bt^2\)

Required

The units of A and B

From the question, we understand that:

\(\omega_z(t) \to rad/s\)

This implies that each of \(A\) and \(Bt^2\) will have the same unit as \(\omega_z(t)\)

So, we have:

\(A \to rad/s\)

\(Bt^2 \to rad/s\)

The unit of t is (s); So, the expression becomes

\(B * s^2 \to rad/s\)

Divide both sides by \(s^2\)

\(B \to \frac{rad/s}{s^2}\)

\(B \to rad/s^3\)

The segment of copper wire with the highest resistance at room temperature is segment (2), which is 2.0 m in length and has a cross-sectional area of 1.0 x \(10^{-6}\) m².

What is the resistance?

The resistance of a conductor is given by the formula:

R = (ρL) / A

where R is the resistance, ρ is the resistivity of the material, L is the length of the conductor, and A is the cross-sectional area of the conductor.

Assuming that the resistivity of copper is constant, we can compare the resistance of the different segments of copper wire using the above formula.

We can calculate the resistance of each segment of copper wire as follows:

(1) R = (1.68 x \(10^{-8}\) Ωm x 1.0 m) / (1.0 x \(10^{-6}\) m²) = 0.017 Ω

(2) R = (1.68 x \(10^{-8}\) Ωm x 2.0 m) / (1.0 x \(10^{-6}\) m²) = 0.034 Ω

(3) R = (1.68 x \(10^{-8}\) Ωm x 1.0 m) / (3.0 x \(10^{-6}\) m²) = 0.0056 Ω

(4) R = (1.68 x \(10^{-8}\) Ωm x 2.0 m) / (3.0 x \(10^{-6}\) m²) = 0.0112 Ω

Therefore, the segment of copper wire with the highest resistance at room temperature is segment (2), which is 2.0 m in length and has a cross-sectional area of 1.0 x \(10^{-6}\) m².

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Complete question is: The segment of copper wire with the highest resistance at room temperature is segment (2), which is 2.0 m in length and has a cross-sectional area of 1.0 x \(10^{-6}\) m².

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

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Answer:

Then our fires would become massive.

Explanation:

Hope this helps

Answer: When you change lanes, follow these steps:

Turn on your signal.

Check your mirrors.

Check your blind spot by looking over your shoulder.

If it is safe, change lanes.

Turn off your signal after completing the lane change.

Explanation: urwellcome

Answer:

Turn on your turn signal, and check for cars behind and in front of you.

Explanation:

It is important to check for cars because you may crash and injure/die. So stay safe!

ANSWER:

NEPTUNE & JUPITER

Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:

E=m×c²

This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.  

In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.

In this case, you know:

Replacing:

E= 1.05 kg× (3×10⁸ m/s)²

Solving:

E= 9.45×10¹⁶ J

Finally, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

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Answer:

because heat evaporates water

Explanation:

Answer:

The correct option is;

d) All of the above

Explanation:

a) In an electric circuit through which electric current flows, it is due to the electric charges which can be the negatively charged electrons or the positively charged protons

b) Voltage is the potential difference that results in current flowing through the circuit, therefore, the voltage is applied across the circuit through which current flows

c) The voltage which is the electric potential difference is the change in potential energy in joules of a given system due to the movement of a test charge (in Coulombs) between points in the electric field, ΔE, divided by the value of the test charge, 'q'

V = ΔE/q

Therefore, all of the above are correct.

360N is the normal force exerted on the crate by the elevator.

To find the normal force exerted on the crate by the elevator, we need to consider the forces acting on the crate.

The weight of the crate is given by W = mg, where m is the mass of the crate (60 kg) and g is the acceleration due to gravity (10 m/s^2). Thus, W = 600 N.

As the elevator is slowing down at 6 m/s^2, there is a net force acting on the crate in the upward direction (since the elevator is moving upward). This net force is given by Fnet = ma, where a is the acceleration of the elevator (in this case, -6 m/s^2, since the elevator is slowing down) and m is the mass of the crate.

Thus, Fnet = (-6 m/s^2)(60 kg) = -360 N. The negative sign indicates that the net force is acting in the opposite direction to the motion of the crate.

The normal force exerted on the crate by the elevator is equal in magnitude and opposite in direction to the net force acting on the crate.

Thus, the normal force is given by Fnorm = -Fnet = 360 N.

Therefore, the normal force exerted on the crate by the elevator is 360 N.

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There are some traits of successful entrepreneurs, these are as follows:

1. He should be a highly motivated towards the work.

2. He sholud be creative in nature. He should think out of box and develop some ideas for the problem.

3. He should have clear vision for the future.

4. He should be very versatile and ready to adapt any changes.

5. He should be ready to take some risk.

6. He should have the ability of decision making and leadership quality.

The rate of change of the distance between the two particles is 10 units per second.

Let's call the distance between particle A and particle B "d". To find the rate of change of "d", we need to take the derivative of "d" with respect to time. By using the Pythagorean theorem to relate the distance between the two particles to their x and y coordinates:

d^2 = x^2 + y^2

Taking the derivative of both sides with respect to time, we get:

2dd/dt = 2x(dx/dt) + 2y(dy/dt)

where dx/dt is the rate of change of particle A's x-coordinate (which is equal to 2), and dy/dt is the rate of change of particle B's y-coordinate (which is equal to 3).

We need to find x and y in terms of time. Particle A is moving at a constant rate of 2 per second along the positive x-axis, so its x-coordinate is given by:

x = 2t

where t is time in seconds.

Similarly, particle B is moving at a constant rate of 3 per second along the positive y-axis, so its y-coordinate is given by:

y = 3t

Substituting these expressions for x and y into our equation for the rate of change of "d", we get:

2dd/dt = 2(2)(1) + 2(3)(1) = 10

So the rate of change of the distance between the two particles is 10 units per second.

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It takes the ball 1.02 seconds to reach the highest point.

The ball goes as high as 5.10 meters.

Since the ball is thrown straight up into the air, there is no horizontal motion involved. Therefore, ignore the horizontal position and velocity equations.

Use the vertical position and velocity equations:

At the highest point, the ball will have zero vertical velocity (Vy = 0). We can use this fact to find the time it takes to reach the highest point:

Vy = v₀y + ayΔt

0 = 10 - 9.8Δt

Δt = 10/9.8

Δt = 1.02 seconds

Therefore, it takes 1.02 seconds to reach the highest point.

To find the height the ball goes, we can use the vertical position equation at the highest point:

y = y₀ + v₀yΔt + 1/2ayΔt²

y = 0 + 10(1.02) + 1/2(-9.8)(1.02)²

y = 5.10 meters

Therefore, the ball goes up to a height of 5.10 meters before falling back down.

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The text transcription is:

QI: You throw a ball straight up into the air. The initial speed is v_y= 10 m/s. How long does it take to reach the highest point? How high does it go?

Horizontal position: x(t) = x₀ + v₀x Δt

Horizontal velocity: vx(t) = v₀x    constant

Vertical position: y(t) = y₀ + v₀yΔt + 1/2ayΔt²

Vertical velocity: vy(t) = v₀y + ayΔt, ay = -9.8 m/s²

Answer:

a) twice the mass and was moving at the same speed?

c) one-half the mass and was moving with twice the speed?

Explanation:

New KE = 248 Joules. Thus, in case of the same speed and twice the mass, the new kinetic energy will be 248 Joules.

Answer: i think A and C

Explanation:

Answer:

A, B, C, D

Explanation:

Yes, i know it is abcd, but it is correct

Answer:

average speed - b

speed - d

acceleration- c

Instantaneous speed- a

Explanation:

I think I dont really remember

Answer:

10.4 m/s²

Explanation:

use the formula:  V² = Vo² - 2aΔx

Plug in the known values then solve for a.  Vo = 0 because the car starts from rest.

(25 m/s)² = 0 + 2a(30m)

a = (625 m²/s²)/(2)(30m) = 10.4 m/s²

Answer:

48cm by the minus of difference of 32 CM length 20 CM because of the length of the building

After the collision of the two balls of clay, the velocity of the combined unit is 0.7965 m/s south.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.In this case, the total momentum before the collision is:535 g × 12.4 m/s (north) + 725 g × (-6.4 m/s) (south)= 6634.5 g.m/s (north - south)After the collision, the two balls of clay form a single unit, so the total mass of the combined unit is:535 g + 725 g = 1260 gTo find the velocity of the combined unit, we can use the formula: m1v1 + m2v2 = (m1 + m2)v, where m1 and v1 are the mass and velocity of the first ball, m2 and v2 are the mass and velocity of the second ball, and v is the velocity of the combined unit. Substituting the values we know, we get:535 g × 12.4 m/s + 725 g × (-6.4 m/s) = (535 g + 725 g) × v6634.5 g.m/s = 1260 g × vSimplifying, we get:v = 6634.5 g.m/s ÷ 1260 g = 5.2655 m/s southTherefore, the velocity of the combined unit is 5.2655 m/s south.

The velocity of the combined unit is 0.7965 m/s south.

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Identification of compounds can benefit from density. It is also a useful feature since it connects (or acts as a conversion factor between) a substance's mass and volume. Volume and mass are extended (or extrinsic) qualities of matter that are quantity dependent.

The force of an air mass acting on the earth's surface is known as atmospheric pressure. Remember that wind currents are created when the densities of two separate air masses differ.

Our wind currents are driven by the atmospheric pressure density, and denser air exerts a higher pressure than less dense air. Compared to the cold and dry air, the warm and humid air is less dense. The less dense air will then float on top of the thicker air in certain regions.

Therefore, Warm air masses rise while cold air masses descend because they are less dense.

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