The displacement current through the 1-cm^2 area perpendicular to the uniform electric field is 1.33 × 10^-19 A.
The displacement current is given by the equation:
I_d = ε_0 * dΦ_E/dt
Where ε_0 is the permittivity of free space, Φ_E is the electric flux through the area, and dΦ_E/dt is the rate of change of electric flux through the area.
In this case, we have a uniform electric field that is increasing at the rate of 1.5(V/M)/us. The electric flux through a 1-cm^2 area perpendicular to the field is simply the product of the field strength and the area:
Φ_E = E * A
Where E is the electric field strength and A is the area.
Substituting the given values, we have:
Φ_E = (1.5 V/m/us) * (1 cm^2)
Φ_E = 0.015 V/us
Now, we can calculate the displacement current:
I_d = ε_0 * dΦ_E/dt
I_d = (8.85 × 10^-12 F/m) * (0.015 V/us)/(1 × 10^-6 s)
I_d = 1.33 × 10^-19 A
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Two squares of wire like that in the previous question are placed side by side on a table with a distance of 3 cm between the closest sides of the two squares. A 15 mA current passes counterclockwise through both squares. What is the resulting force between the two squares? Is it attractive or repulsive?
The total magnetic field at the center point between the two squares is \(2 *10^{(-4)}\) Tesla.
Let's assume the current passing through each square of wire is I = 15 mA = \(15 *10^{(-3)} A\).
The magnetic field produced by a square wire at its center can be calculated using the formula for the magnetic field of a long straight wire:
B = (μ₀ * I) / (2 * π * r)
Where:
B is the magnetic field
μ₀ is the permeability of free space\((4\pi × 10^{(-7)} T.m/A)\)
I is the current
r is the distance from the wire
For each square wire, the distance from its center to the center point between the two squares is 1.5 cm = 0.015 m.
Calculating the magnetic field produced by each square wire:
B1 =\((4\pi * 10^{(-7)} T.m/A * 15 * 10^{(-3)} A) / (2 *\pi * 0.015 m)\)
B1 =\(10^{(-4)} T\)
Since the current passes through both squares in a counterclockwise direction, the magnetic fields produced by both squares will have the same magnitude and direction.
Therefore, the total magnetic field at the center point between the two squares is:
B_total = B1 + B1
B_total =\(2 * 10^{(-4)} T\)
B_total = \(2 *10^{(-4)} T\)
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--The complete Question is, Two squares of wire, each with a side length of 4 cm, are placed side by side on a table with a distance of 3 cm between the closest sides of the two squares. A 15 mA current passes counterclockwise through both squares. What is the total magnetic field at the center point between the two squares?--
An object starts from rest and has an acceleration of 2.0 ms−2. What is the speed (v = at) of the object after 7.00 seconds with the correct number of significant digits?
Answer:
14 m/s
Explanation:
Correct number of sig dig will be two since accel has only two SD ( you can only have as many SD as the factor with the LEAST SD)
v = at
= 2 m/s^2 * 7 s = 14 m/s
Watt-hours is a measure of energy, just like kilowatt-hours. how can you convert this to joules? (hint: break this down into basic units and determine the required conversion factors.)
Watt-hours and kilowatt-hours are both measures of energy. To convert watt-hours to joules, we need to break down the units and use the appropriate conversion factors.
1 watt-hour is equal to 3600 joules. This conversion factor comes from the fact that power is equal to energy divided by time, and 1 watt is equal to 1 joule per second. Since there are 3600 seconds in an hour, we multiply the power in watts by the number of seconds in an hour to get the energy in joules.
To convert kilowatt-hours to joules, we first convert kilowatts to watts. 1 kilowatt is equal to 1000 watts. Then, we multiply the power in watts by the number of seconds in an hour (3600 seconds) to get the energy in joules.
Here are the conversion steps:
1. For watt-hours to joules:
- Multiply the watt-hours by 3600 to get the energy in joules.
2. For kilowatt-hours to joules:
- Multiply the kilowatt-hours by 1000 to convert to watts.
- Multiply the result by 3600 to get the energy in joules.
Remember to always label your final answer with the correct units.
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How much work is done by an applied force to lift a 15 Newton block 3.0 meters vertically at a constant speed?5 J4500 J4 J45 J
The work done is 45 J.
Given data:
• The applied force is F=15 N.
,• The distance traveled is d=3.0 m.
The work done can be calculated as,
\(\begin{gathered} W=Fd \\ W=(15)(3) \\ W=45\text{ J} \end{gathered}\)Thus, the work done by the force is 45 J.
the mass of the box on a table is 20kg. a man applied force as below the picture. the static frictional coefficient is 0.6 and the dynamic frictional coefficient is 0.5. (gravitational acceleration =10ms^{-2}
1)what is the minimum force that should be applied to move the box?
2)What is the force that should apply to move in uniform velocity?
Calculate the pressure in pascals if a 400N force is applied to an area of 0.5m2.
Answer:
0.00789pa
Explanation:
since pressure=force/area
=400/0.5
=800N/m2
1.013*10^5N/m2=1pascal
800N/m2=xpascal
therefore it becomes,800/1.013*10^5
=0.00789pascal
An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle
Answer:
11 protons, 12 neutrons, 10 electrons
Explanation:
Sodium has an atomic number of 11, so it has 11 protons.
The atomic mass is 23, so there are 23 − 11 = 12 neutrons.
The charge is +1, so there is 1 more proton than electrons, so there are 10 electrons.
An object has an acceleration of 6 m/s/s. If the net force
was tripled and the mass were halved, then the new
acceleration would be m/s/s.
Answer:
\(F = ma \\ a = \frac{F}{m} = 6 \\ when \: force \: is \: trippled \: and \: mass \: is \: halved \\ a = \frac{3F}{ \frac{1}{2} m} = \frac{3}{2} \times 6 \\ a = \frac{(3 \times 6)}{2} \\ a = \frac{18}{2} \\ a = 9 \: m {s}^{ - 2} \)
it takes 79.4 s for a 1.57-a current to plate 0.1261 g of a metallic element from a solution containing m2 ions. what is the element (m)? answer with the chemical symbol for the element.
It takes 79.4 s for a 1.57-a current to plate 0.1261 g of a metallic element from a solution containing m2 ions. we need to determine the molar mass (M) and the number of moles of electrons transferred (n) for the metallic element (m). Since we don't have information about the specific element
To determine the metallic element (m) that is being plated from the solution, we need to use Faraday's law of electrolysis. According to Faraday's law, the amount of substance (m) that is deposited or plated on an electrode is directly proportional to the electric charge (Q) passed through the electrolyte. The equation is given by:
m = (Q * M) / (n * F)
where:
m is the mass of the substance plated,
Q is the electric charge,
M is the molar mass of the substance,
n is the number of moles of electrons transferred in the reaction,
F is Faraday's constant.
In this case, the electric charge Q is given by the product of the current (I) and time (t): Q = I * t.
From the information provided, the current is 1.57 A and the time is 79.4 s. Plugging these values into the equation, we have:
Q = (1.57 A) * (79.4 s) = 124.558 C
we cannot determine these values accurately. Therefore, we cannot determine the chemical symbol for the element without additional information about its molar mass and the number of moles of electrons transferred in the reaction.
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60-cm
c
m
-diameter wheel accelerates uniformly about its center from 130 rpm
r
p
m
to 320 rpm
r
p
m
in 4. 1 s
s
A 60-cm diameter wheel accelerates uniformly from 130 rpm to 320 rpm in 4.1 s.
The problem gives us two important pieces of information about the wheel's motion: its initial and final rpm, and the time it took for the acceleration to occur.
To solve for the wheel's acceleration, we can use the following equation:
a = (v_f - v_i) / t
where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time. In this case, substituting the given values gives:
a = (320 rpm - 130 rpm) / 4.1 s
a = 46.34 rpm/s
Next, we can use the wheel's diameter to convert its rpm into linear velocity, using the formula:
v = πdN / 60
where v is velocity, d is diameter, and N is rpm. Substituting the given values gives:
v_i = π(60 cm)(130 rpm) / 60 = 409.16 cm/s
v_f = π(60 cm)(320 rpm) / 60 = 1022.91 cm/s
Finally, we can use the time and acceleration to find the distance the wheel traveled during its acceleration, using the formula:
d = vi*t + (1/2)at^2
where d is distance, vi is initial velocity, t is time, and a is acceleration. Substituting the given values gives:
d = (409.16 cm/s)(4.1 s) + (1/2)(46.34 rpm/s)(4.1 s)^2
d = 782.34 cm
Therefore, the wheel traveled approximately 7.82 meters during its acceleration.
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is the pressure on the left side greater than, less than, or equal to the pressure on the right? explain.
The pressure on the left side is less than the pressure on the right side. This is because pressure is inversely proportional to volume, according to Boyle's law. When a gas is compressed in a container, the volume of the gas decreases, resulting in an increase in pressure.
When gas is released from a container, the volume increases, resulting in a decrease in pressure.In a closed container, the same number of gas molecules is present on both the left and right sides. However, the volumes of the two sides are not the same, hence the pressure on the left side is less than the pressure on the right side. This is because the right side is compressed to a smaller volume, causing the pressure to increase (main answer).
This can be further explained with the help of the formula for Boyle's law, which is P1V1 = P2V2. Here, P represents pressure, V represents volume, and the subscripts 1 and 2 represent the initial and final states, respectively. Suppose that the initial volume of the gas on the left side is V1 and the final volume of the gas on the right side is V2. As a result, P1V1 = P2V2, according to Boyle's law. As a result, P1/P2 = V2/V1, and since V2 < V1, P1 > P2. Therefore, the pressure on the left side is less than the pressure on the right side.
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WHAT IS COMPUTER ? EXPLAIN IT .
Answer: it's an electronic device
Explanation: it's where you store and process data, it acts according to the instructions given to it in a variable program.
Sorry if this wasn't the answer you were looking for.
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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A 1000 ml graduated cylinder contains an aqueous solution of soil. You notice three distinct layers after the solution was shaken and allowed to sit for 2 days; any organic material was removed. You observed layers within the column: sand, silt, and clay. Sand is on the bottom, silt in the middle, and clay on the top. After settling, the top layer goes from 920 ml down to 903 ml; the next layer from 903 down to 745, and the bottom layer from 745 to 0 ml.
a. Name the component of each layer.
b. What is the percentage of each layer?
c. What is this soil's textural callsification?
a stone is thrown vertically upwards with an initial velocity of 20m/s. find the maximum height it reaxhes and the time taken by it to reach the height.
for the decay n → p e−, which particle needs to be added on the right side for the interaction to be valid?
To balance the decay n → p e⁻, an antineutrino needs to be added on the right side of the interaction.
What is Antineutrino?
An antineutrino is a subatomic particle that is the antimatter counterpart of the neutrino. Like neutrinos, antineutrinos are elementary particles that belong to the lepton family. They have extremely low mass, no electric charge, and are affected only by the weak nuclear force and gravity.
Antineutrinos are typically produced in certain types of radioactive decays, such as beta-minus decay, where a neutron in an atomic nucleus transforms into a proton, an electron, and an antineutrino. In this process, the antineutrino carries away the excess energy and angular momentum.
The given decay, n → p e⁻, involves the neutron (n) transforming into a proton (p) and an electron (e⁻). In order for this interaction to be valid and conserve various properties, such as electric charge and lepton number, an additional particle is required.
During the decay process, an antineutrino is also produced. The antineutrino is the antiparticle counterpart of the neutrino (ν), which is a neutral, low-mass particle that interacts weakly with matter. The antineutrino carries away the necessary properties to conserve electric charge and lepton number in the decay process.
Therefore, to balance the decay n → p e⁻, an antineutrino must be added on the right side of the interaction. The complete balanced decay equation becomes: n → p e⁻
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what are two reasons communication is important in scientific research
Answer:
It allows them to write better and more comprehensible research papers. As well as being able to communicate the relevance and impact of their ideas and discoveries.
Explanation:
You and your friend grabbed some inner tubes to go sledding down a hill.
However, your friend needed a push to get him going. You gave your friend a
push of 5 meters on his inner tube with a force of 400 N to start him down the
snowy slope. How much work did you do?
Answer:2000jules
Explanation:
another friend With a force of 400 newtons and down the slope, and it applies this force Through a distance of five m. So they want to know what the work is. So the equation for work is force times distance, and usually we want to put with the cold sine of the angle between them if they are not aligned, but in this case they are aligned. So the call sign turns out to be one. So all we have to do is multiply force times distance 400 times five, and we get a value of And this is equal to 2000 jules. That's the answer to the problem.
What will happen to a straight fence that undergoes elastic strain during an earthquake?
A) The fence will bend in the direction of stress.
B) The fence will bend away from the direction of stress.
C) The fence will remain straight.
D) The fence will break.
During an earthquake, the ground experiences significant stress and movement, which can lead to elastic strain on structures, such as a straight fence.
Elastic strain is the temporary deformation of materials under stress, where the material returns to its original shape once the stress is removed.
In this case, if the straight fence undergoes elastic strain during the earthquake, the fence will respond according to the direction of stress. Therefore, the correct answer is:
A) The fence will bend in the direction of stress.
As the stress is applied to the fence, it will bend or deform in the same direction as the force. However, since the strain is elastic, the fence will return to its original straight shape once the earthquake has subsided and the stress is removed.
It is essential to note that the fence will not bend away from the stress, remains straight, or break due to the elastic nature of the strain. Elastic strain allows the fence to absorb the energy from the earthquake and then release it, preventing permanent deformation or damage.
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pls answer! 10 points bc i have a lil amount now!!
Answer: B probably because it is using UV rays which is a chemical energy to give you that sunburn.
Un prisma rectangular con un volumen de 80 m^3 se sumerge hasta la mitad en agua, calcular la fuerza de empuje que recibe.(rho_(del agua)=1000 kg/m^3)
Answer:
400 kN
Explanation:
El principio de Arquímedes establece que, cuando un cuerpo está total o parcialmente sumergido en un fluido, experimenta un empuje hacia arriba que es igual al peso del fluido desplazado.
Dado que;
Volumen del bloque = 80m ^ 3
Densidad del agua = 1000 kg / m ^ 3
Empuje hacia arriba = 1/2 * 80 * 1000 * 10
Empuje hacia arriba = 400 kN
why do the terrestrial planets have relatively meager atmospheres compared with those of the jovian planets?
The terrestrial planets receive more heat from the Sun and have a lower gravitational pull than the Jovian planets, which receive less heat from the Sun and have a much higher gravitational pull.
Because they are large and composed mostly of gas they are sometimes called gas giants. Small amounts of rocky material are found only deep within the core of Jupiter's planet. In the solar system, Jupiter planet is farther from the Sun than the terrestrial planets and is therefore cooler.
Terrestrial planets formed from rocky and metallic planetesimals but were ultimately too small to capture the large amounts of hydrogen and helium gases abundant in the solar nebula. But Jupiter's planet formed far from the Sun where ice and rock were abundant.
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Does potassium have a greater nuclear charge than Chlorine?
Answer:
This is important because in the case of the potassium atom, the outermost electrons will be attracted by the nucleus more. In other words, K+ has bigger effective nuclear charge than Cl− , which translates to a bigger net positive charge felt by the outermost electrons.
Explanation:
why did you have to draw circles around each station in order to pinpoint the epicenter? why couldn't you just use the distance from each station to go directly to the epicenter in a straight line? explain.
The ratio of the three circles they draw is equal to the distances from the stations to the epicenter.
Scientists use triangulation to find the epicenter of an earthquake. If seismic data are collected from at least three different locations, their intersection can be used to determine the epicenter. Each earthquake is recorded by numerous seismometers placed in different directions.
The epicenter is the point on the surface directly above the earthquake. A seismic station uses seismometer recordings to detect earthquakes. Determining the epicenter of an earthquake requires records from three separate seismic stations. Triangulation is a method of uniquely identifying earthquakes using distance information determined from three seismic stations.
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What direction would the north pole of a bar magnet point if you were to hang the bar magnet from a thin string?.
a car travels at a constant speed around a circular track whose radius is 3.50 km. the car goes once around the track in 200 s. what is the magnitude of the centripetal acceleration of the car?
The magnitude of the centripetal acceleration of the car is 0.0314 m/s².
centripetal acceleration
Centripetal acceleration is described because the assets of the motion of an item, traversing a circular path. Any object that is shifting in a circle and has an acceleration vector pointed in the direction of the center of that circle is referred to as Centripetal acceleration.
a = v²/ r
r = 3500 m (SI unit)
t = 200 s
circumference = C
C = 2 * π * r
C = 2 * 3.141 * (3500 m)
C = 21987 m
v = D / t
v = (21987 m) / (200 s)
v = 109.935 m/s
a = (109.935 m/s)² / (3500 m)
a = (109.935 m/s²) / (3500 m)
a = 0.0314 m/s²
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A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
1) The time taken to get to the maximum height
ii) the time of flight
Explanation:
It is given that,
The angle of projection is 60 degrees
Initial velocity of the ball is 120 m/s
We need to find the time taken to get to the maximum height and the time of flight.
Time taken to reach the maximum height is given by :
\(T=\dfrac{u^2\sin^2\theta}{2g}\)
g is acceleration due to gravity
\(T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s\)
(ii) Time of flight,
\(t=\dfrac{2u\sin\theta}{g}\)
So,
\(t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s\)
Hence, this is the required solution.
Help fast
Who is often referred to as the "father of modern physics?"
Rutherford
Edison
Newton
Dalton
Answer:
C. Newton
Explanation:
hope this helped:)
The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines called the Lyman series. Calculate the wavelengths of the first four members of the series.
the wavelengths in the hydrogen spectrum of the first four members of the series where m=1, the first four members have the wavelength of \(1.464 * 10^7 m,\) \(1.231 * 10^7 m,\) \(1.164 * 10^7 m,\) and \(1.097 * 10^7 m.\)
The wavelengths of the spectral lines in the Lyman series of the hydrogen spectrum can be calculated using the Rydberg formula:
1/λ = \(R * (1/n1^2 - 1/n2^2)\)
Where λ is the wavelength of the spectral line, R is the Rydberg constant (approximately \(1.097 * 10^7 m^-^1)\), and n1 and n2 are positive integers representing the energy levels of the electron in the hydrogen atom.
For the Lyman series, we have m = 1, which means the electron transitions from higher energy levels (n2) to the first energy level (n1 = 1).
Let's calculate the wavelengths for the first four members of the Lyman series:
For n2 = 2:
1/λ = \(R * (1/1^2 - 1/2^2)\)
1/λ = \(R * (1 - 1/4)\)
1/λ = \(R * (3/4)\)
λ = \(4/3R\)
Substituting the value of the Rydberg constant:
λ = \((4/3) * (1.097 × 10^7 m^-^1)\)
λ ≈ \(1.464 * 10^7 m\)
For n2 = 3:
1/λ = \(R * (1/1^2 - 1/3^2)\)
1/λ = \(R * (1 - 1/9)\)
1/λ = \(R * (8/9)\)
λ = \(9/8R\)
Substituting the value of the Rydberg constant:
λ = \((9/8) * (1.097 * 10^7 m^-1)\)
λ ≈ \(1.231 * 10^7 m\)
For n2 = 4:
1/λ = \(R * (1/1^2 - 1/4^2)\)
1/λ = \(R * (1 - 1/16)\)
1/λ = \(R * (15/16)\)
λ = \(16/15R\)
Substituting the value of the Rydberg constant:
λ = \((16/15) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.164 * 10^7 m\)
For n2 = 5:
1/λ = \(R * (1/1^2 - 1/5^2)\)
1/λ = \(R * (1 - 1/25)\)
1/λ = \(R * (24/25)\)
λ = \(25/24R\)
Substituting the value of the Rydberg constant:
λ = \((25/24) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.097 * 10^7 m\)
Therefore, the wavelengths of the first four members of the Lyman series are approximately:
\(1.464 * 10^7 m,\)
\(1.231 * 10^7 m,\)
\(1.164 * 10^7 m,\)
and \(1.097 * 10^7 m.\)
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What is the difference between zone coverage and man coverage, and how can the offense team read those coverages?
Answer:
zone coverage is about sensing what the offense is attempting to accomplish against the defense. Each defensive player reacts when the ball is in the air, whereas in man-to-man coverage, he simply plays the receiver.
Explanation: