a wall, a 55.6 kg painter is standing on a 3.15 m long homogeneous board that is resting on two saw horses. The board’s mass is 14.5 kg. The saw horse on the right is 1.00 m from the right. How far away can the painter walk from the saw horse on the right until the board begins to tip?

Answers

Answer 1

Answer:

0.15 m

Explanation:

First calculating the center of mass from the saw horse

\(\frac{3.15}{2} -1=0.575 m\)

from the free body diagram we can write

Taking moment about the saw horse

55.9×9.81×y=14.5×0.575×9.81

y= 0.15 m

So, the painter walk from the saw horse on the right until the board begins to tip is 0.15 m far.

A Wall, A 55.6 Kg Painter Is Standing On A 3.15 M Long Homogeneous Board That Is Resting On Two Saw Horses.

Related Questions

A polystyrene rod consisting of two cylindrical portions AB and BC is restrained at both ends and supports two 6-kip loads as shown. Knowing that E = 0.45 X 106 psi, determine (a) the reactions at A and C, (b) the normal stress in each portion of the rod.

Answers

The normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

We can start by drawing a free body diagram of the polystyrene rod and identifying the unknown reactions at A and C:

|-------- 6 kips --------|

          A                       C

          |-----------------------|

          |                       |

          |          BC           |

          |          σ₂           |

          |          L₂           |

          |                       |

          |-----------------------|

          |                       |

          |          AB           |

          |          σ₁           |

          |          L₁           |

          |                       |

          |-------- 6 kips --------|

Where σ₁ and σ₂ are the normal stresses in portions AB and BC of the rod, respectively.

Next, we can use the equations of static equilibrium to solve for the reactions at A and C. Taking moments about point A, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - Cz = 0

where z is the distance from A to the line of action of the force at C. Since the rod is symmetric about the midpoint of portion BC, we can take z = L₁ + L₂/2. Substituting the given values, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - C(L₁ + L₂/2) = 0

Solving for C, we get:

C = (12 kips * L₁ + 18 kips * L₂) / (3 L₁ + 2 L₂)

Taking vertical forces, we have:

A + C - 12 kips - 6 kips - 6 kips = 0

Substituting the value of C we just obtained, we get:

A = 12 kips - C - 6 kips - 6 kips = 0.4 kips

Therefore, the reactions at A and C are A = 0.4 kips and C = 11.6 kips.

Next, we can calculate the normal stresses in each portion of the rod. Using the formula for normal stress, we have:

σ₁ = P₁ / A₁ = A₂ / A₁ * σ₂

where P₁ and A₁ are the axial load and cross-sectional area of portion AB, and A₂ is the cross-sectional area of portion BC. Since the rod is of uniform diameter and the areas of the cylindrical portions are proportional to their lengths, we have:

A₂ / A₁ = L₂ / L₁

Substituting this into the equation for σ₁, we get:

σ₁ = (L₂ / L₁) * σ₂

Substituting the given values, we have:

σ₂ = P₂ / A₂ = 6 kips / (π/4 * (0.6 in)^2) = 47.69 psi

σ₁ = (2.5 ft / 1.5 ft) * 47.69 psi = 79.48 psi

Therefore, the normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

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it is natural for system in the universe to_____ spontaneously

Answers

We will have the following:

It is natural for a system in the universe to increase its entrophy spontaneously.

***Explanation***

We know from the laws of thermodynamics that any system will mantain its disorder or increase it expontaneously [Entrophy]. And since the universe is overall a "Giant system" then the entrophy will increase, and this happens naturally.

Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.

Answers

A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

What is the carbon cycle?

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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In an inertial system S, an event is observed to take place at point A on the x-axis and 10^-6 s later another event takes place at point B, 900 m further down. Find the magnitude and direction of the velocity of S' with respect to S in which these two events appear simultaneous.

Answers

The magnitude of the velocity of S' with respect to S is therefore approximately  \(9 * 10^(11)\)m/s. then the magnitude is approximately\(9 * 10^(11)\) m/s.

the velocity of the system S' with respect to S as v. Since the two events are simultaneous in the system S', they must have the same time coordinate in that system. Let's call this time coordinate t' and the position of the two events in the S' system as (x1', t') and (x2', t').

Using the Lorentz transformation equations, we can relate the coordinates (x1, t1) and (x2, t2) in the S system to the coordinates (x1', t') and (x2', t') in the S' system:

x1' = γ(x1 - vt1)

t' = γ(t1 - vx1/\(c^2\))

x2' = γ(x2 - vt2)

t' = γ(t2 - \(vx2/c^2\))

where γ = 1/√(1 - \(v^2/c^2\)) is the Lorentz factor.

Since the two events are separated by 900 m and a time interval of 10^-6 s, we have:

x2 - x1 = 900 m

t2 - t1 = \(10^-6\) s

Using the above equations, we can solve for v. First, we can eliminate t' by equating the two expressions for t':

γ(t1 - vx1/\(c^2\)) = γ(t2 - vx2/\(c^2\))

Simplifying this expression, we get:

v =\(c^2\)(x2 - x1)/(t2 - t1)(x1 + x2)

Plugging in the given values, we get:

v = c^2(900 m)/(\(10^-6\) s)(0 m + 900 m) = 9 × \(10^11\) m/s

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A stone is dropped from the roof of a high building. A second stone is dropped 1.04 s later.

How far apart are the stones when the second one has reached a speed of 14.7 m/s?
Express your answer to three significant figures and include the appropriate units.

A stone is dropped from the roof of a high building. A second stone is dropped 1.04 s later.How far apart

Answers

Explanation:

Let the initial speed of 2nd stone is u2 and final speed of it be v2.

Using the equation

v= u + at for the 2nd stone

We get

14.7=u2 + 10t (a=g, acceleration due to gravity)

14.7=0 +10t

Or, t= 1.47s

This is the time taken by 2nd stone to reach 14.7m/s

Now,

Total time for 1st stone=1.04 + 1.47= 2.51s

Using the equation

\(s = ut + \frac{1}{2} at {}^{2} \)

for distance travelled by 1st stone

s1=u2t + 1/2at²

u2=0 (initially it was also at rest)

\(s1 = \frac{1}{2} \times 10 \times 2.51 {}^{2} \)

therefore S = 31. 5005m

Distance travelled by 2nd stone

\(s2 = u2 + \frac{1}{2} at {}^{2} \)

\(s2 = \frac{1}{2} \times 10 \times 1.47 {}^{2} \)

therefore S2 = 10.8m

Therefore,

Distance between the stones is= s1 - s2 = 31.5005–10.8 = 20.7005

Ans:- 20.7m

So, RCF, or relative centrifugal force should be equal to RCF = \(11,18*r*(RPM/1000)^2\)

The radius is measured in centimeters and RPM is revolutions per minute.

What I don't know is, if I plug all the data in the formula, will the result equal to acceleration in meters per second squared, or it will be measured in g's so that if I multiply the g's by 9.8 meters per second square, it will give me the actual acceleration.

Answers

After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

What is relative centrifugal force?

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

ac is centripetal accelerationg is acceleration due to gravity

\(RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2\)

where;

r is radius in cm

For example,

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

\(RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g\)

Thus, after plugging all the data into the equation, the result is measured in terms of g.

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I attempted to answer and got 0m, please explain how to get to the answer.

A cannonball is fired straight up with an initial velocity of 150 m/s. How high will it get before it stops moving upward (it comes to a temporary stop before falling back down)?

Answers

The maximum height to which the ball attain before falling back down is 1147.96 m

Data obtained from the question

The following data were obtained from the question:

Initial velocity (u) = 150 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =?

How to determine the maximum height

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

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Explain how improving the EXERGY may be as good, if not better than discovering new/oil coal mines.

Answers

Answer:

It is necessary to search for new sources of energy because the sources we have now are non-renewable and exhaustible. The usage of these sources are increasing day by day and if this continues then one day we wlii be left with none so it is necessary to search for new sources of energy

PLEASE MARK ME BRAINLIEST

A crane is oriented so that the end of the 25-m boom AO lies in the yz plane. At the instant shown, the tension in cable AB is 5.9 kN Determine the moment about each of the coordinate axes of the force exerted on A by cable AB.
Previous question

Answers

0Nm, 147.5 Nm and  -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.

What is moment?

A moment is indeed a mathematical term used in physics that involves the combination of a physical quantity and a distance. Seconds relate to physical quantities that are dispersed from either the reference point and are often described with regard to something like a fixed reference point.

The instant therefore explains the position or arrangement of the amount. For instance, the moment of force, also known as torque, is the result of the force acting on an object and the item's distance first from reference point.

Moment = force ×distance

M = f × d

Moment about the x axis:

M = 5.9  ×0

M = 0Nm

Moment about the y axis:

M =5.9  ×25  = 147.5 Nm

Moment about the z axis:

M = 5.9  × (-25)

M = -147.5Nm

Therefore, 0Nm, 147.5 Nm and  -147.5Nm are the moment about each of the coordinate axes of the force exerted on A by cable AB.

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In a vernier caliper, the main scale reading is 9 cm and vernier coincidence is 5 and negative zero error is 0.02 cm, than the total reading is ____​

Answers

Answer:

It's 0.264cm in total reading

Given that the luminosity of a star is given as a function of its radius and temperature by the equation. I do not understand this last question in terms of what to put into the given equation.

Given that the luminosity of a star is given as a function of its radius and temperature by the equation.

Answers

The luminosity of this star in units of the solar luminosity would be: 483.7L.

How to calculate the luminosity

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?

The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat

Answers

Answer:

it is double the temperature change of iron

elophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the

Answers

Answer: The correct answer is formation of four haploid nuclei.

The event occurring during telophase II includes formation of four haploid daughter cells. Telophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the nuclear spindle. During this stage both the daughter cells get divided forming four haploid cells. The development of the nuclear envelope around each set of the chromosome and cytokinesis also takes place during telophase II.

Explanation:

???

In a football game, one team kicks off to the other. At the moment the receiver catches the ball, he is 40 meters from the nearest tackler. The receiver runs left to right at a speed of 10 meters per second (10 m/s). The tackler runs right to left at a speed of 6 meters per second.

How long does it take before they collide? ___________

How far does the receiver go? _____________________

Answers

Take left to be the negative direction, and right to be positive.

The receiver's position at time t, taking his starting position to be the origin, is

(10 m/s) t

while the tackler's position is

40 m + (-6 m/s) t

The two collide when their positions are equal:

(10 m/s) t = 40 m - (6 m/s) t

(16 m/s) t = 40 m

t = (40 m) / (16 m/s)

t = 2.5 s

In this time, the receiver covers a distance of

(10 m/s) (2.5 s) = 25 m

In 1994, a pumpkin with a mass of 449 kg was grown in Canada. Suppose you want to push a pumpkin with this mass along a smooth, horizontal ramp. You give the pumpkin a good push, only to find yourself sliding backwards at a speed of 4.0 m/s. How far will the pumpkin slide 3.0 s after the push? Assume your mass to be 60.0 kg.

Answers

After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.

We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:

p = (449 kg + 60 kg) * v

where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:

v = -4.0 m/s

Substituting this into the expression for momentum, we find:

p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s

The negative sign indicates that the momentum of the system is in the opposite direction of your motion.

During the sliding motion, the net force on the system is given by:

Fnet = (449 kg + 60 kg) * g * sin(θ)

where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.

Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:

x = x0 + v0t + (1/2)at²

Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:

x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m

The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.

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the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm​

Answers

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

What is the image and object distance?

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Which of the following is most likely the caption for the illustration that was scratched out of the textbook?

A. An electrically-charged object can attract an uncharged object with magnetic properties.

B. An electrically-charged object is stronger than a magnet.

C. A dry cell battery has magnetic properties.

D. An electric circuit can only have one dry cell battery.

IMAGE DOWN BELOW OR UP

Which of the following is most likely the caption for the illustration that was scratched out of the

Answers

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

\(90 \)

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically
(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically
(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically

Thallium-201 is a radioisotope used in brain scans. If the recommended dose is 3.0 mCi and a vial contains 60. mCi in 50. mL , how many milliliters should be injected?

Answers

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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The setup time of a clocked flip-flop is:
A) The minimum amount of time that an input must remain stable after an active clock
transition.
B) The maximum amount of time that an output must remain stable after an active clock
transition.
C) The minimum amount of time that an output must remain stable before an active clock
transition.
D) The minimum amount of time that an input must remain stable before an active clock
transition.

Answers

The setup time of a clocked flip-flop is:

The minimum amount of time that an output must remain stable before an active clock transition.

What is a Flip flop ?

A flip-flop is a device that can hold a single bit of data (a binary digit); one of its two states corresponds to a "one," and the other to a "zero." Such data storage can be used to store state, and in electronics, such a circuit is known as sequential logic.

The output state changes of a timed flip-flop can be synced to a clock pulse thanks to an additional input.

Data must be at a valid logic level at setup time (tS), which is defined as the time before the DAC clock shift.

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How does the ecotourism industry act as an ecosystem service that benefits tourists, the people that live in the area, and the people that work in the industry?

Answers

It promotes enjoyable experiences for both guests and hosts; It lessens the negative effects of tourism on the environment; It increases local residents' access to work and financial prospects; It promotes conservation by offering financial advantages in its direction.

What is ecotourism?

The World Tourism Organization defines ecotourism as all forms of nature-based travel in which visitors' primary interests are in observing and appreciating the environment as well as the local cultures that are still practiced in natural settings.

Here are a few instances of ecotourism:

Visit places where there is nature (think of the flora, animals, and resources)discovering the heritage of the local culture.Ecologically sound wilderness excursions.volunteering or watching nature.trips devoted to environmental preservation efforts, like beach clean-ups.

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two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle

Answers

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Definition of Coulomb's Law

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

Magnitude of the charge on each particle

In this case, you know that:

F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?

Answers

The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

What is displacement?

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!


Here is a function machine.



Input : multiply by 6. Subtract 80: output



The input is the same as the output. Find the input.


Also can you please show me an easy to work out these type of questions

Answers

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

A fish appears to be 2.00 m below the surface of a pond when viewed almost directly above by a fisherman. What is the actual depth of the fish

Answers

Answer:

2,66

Explanation:

The refractive index= real depth/ apparent depth

real depth = refractive index * apparent depth

Let's assume index for water is 1.33

real depth = 2*1,33 = 2,66

Which of the following is a possible food chain in the North Atlantic Ocean?

A. Zooplankton, phytoplankton, right whale

B. Right whale, Phytoplankton, zooplankton

C. Phytoplankton, right whale, zooplankton

D. Phytoplankton, zooplankton, right whale. Which one would he correct?

Answers

Answer: D

Explanation: if the order is right, zooplankton eat phytoplankton, and zooplankton would be eaten by the whale

Hope it helps! ^w^

Answer:

D

Explanation:

Phytoplankton is very small, zoo plankton is small, and right whales are BIG.

Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the speaker is amplified, the book can be torn apart into small pieces.

Answers

Answer:

yes with a lot of time it eventualy could be, but in short term no

Explanation:

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Answers

The letter that represents the various descriptions is as follows:

5.) Angle of incidence: B

6.) Object: D

7.) Plain mirror:A

8.) Reflection: E

9.) Angle of reflection: C

10.) Normal: F

How does the diagram explain the law of reflection?

The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.

The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.

Learn more about reflection here:

https://brainly.com/question/26494295

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1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20

Answers

Answer:

(D) x = 93.8 m

Explanation:

v^2 = v0^2 + 2ax

(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x

Solving for x,

x = 93.8 m

why an object weighs less on moon than earth?​

Answers

Answer :

Since the moon has considerably less mass than the Earth, it will not pull objects toward itself at the strength that Earth will
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