A weather balloon is designed to expand to a maximum radius of 24 m at its working altitude, where the air pressure is 0.030 atm and the temperature is 200 K. If the balloon is filled at atmospheric pressure and 349 K, what is its radius at liftoff

Answer:

c

Explanation:

amembers of the group protocista

The coefficient of kinetic friction is determined as 0.75.

The coefficient of kinetic friction is calculated by applying the newton's second law of motion.

Fsinθ - Ff = ma

where;

W = mg

where;

m = W/g

m = 325/9.8

m = 33.2 kg

425 sin(35.2)   -  Ff = 33.2a

425 sin(35.2)   -  μW = 33.2a

at constant velocity, a = 0

425 sin(35.2)   -  μW= 0

μW = 244.98

μ = 244.98/W

μ = 244.98/325

μ = 0.75

Thus, the coefficient of kinetic friction is 0.75.

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Answer:

a) h(g) = 358,53 m

b) t = 8,16 s

c) t(t) = 16,71 s

Explanation:

Equations for vertical shooting are:

Vf = V₀ -  g * t   ;     h  =  V₀*t -  (1/2)*g*t²  ;    Vf² = V₀² - 2*g*h

And at maximum heigt Vf = 0 then

0 = V₀ - g * t

t = V₀/g                     V₀  = 80 m/s      and   g = 9,8 m/s²

t  =  80 / 9,8   (s)

t = 8,16 s

Then 8,16 s is the time to get maximum height

If we plug t = 8,16 (s) in equation  h  =  V₀*t -  (1/2)*g*t²

we get:     h (max)  =  (80)*8,16 - 0,5*9,8*(8,16)² (m)

h (max) = 652,8  -  326,27 m

h (max) = 326,53 m

Then relative to ground that height becomes

h(g) = 326,53 + 32

h(g) = 358,53 m

In order to get the time the arrow is in the air we proceed as follows:

a) for the arrow to be at the launched point will take the same time that from the launched point to the maximum height, and after that we have to find out the time the arrow takes from 32 m down to the ground level

Then  

t(t) = 8,16 + 8,16 + tₓ     (2)

Where tₓ  is the time from 32 m height to ground

h  =  V₀*tₓ -  (1/2)*g*tₓ²  but since the arrow now is going down then we change the sign of the second term on the right side of the equation

32 = (80)*tₓ  +  0,5 * 9,8 * tₓ²     Note that when the arrow is at 32 m height the speed is again V₀ = 80 m/s

32 = 80*tₓ  + 4,9*tₓ²

A second-degree equation for tₓ, solving it

4,9*tₓ² + 80*tₓ - 32 = 0

t₁,₂ = -80 ± √ 6400 + 627,2 / 9,8

t₁,₂ =( - 80 ± 83,8 ) / 9,8

there is not a negative time therefore we dismiss such solution and

t₁ = 3,8 / 9,8

t₁ = 0,39 s

And

t(t) = 8,16 + 8,16 + 0,39  s

t(t) = 16,71 s

A particle with the potential energy diagram shown is located at point A and is moving to the right with a kinetic energy of 10.0 Joules. When the particle reaches point F, the speed of the particle has decrease

As the sum of potential and kinetic energy remains constant

Kinetic energy decreases when potential energy increases and vice versa.

When kinetic energy decreases speed will also decrease.

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Ans-The density of states function describes the number of states that are available in a system and is essential for determining the carrier concentrations and energy distributions of carriers within a semiconductor.

Answer:

density equal to mass upon volume

simple definition

The electrostatic force of attraction between the proton and electron is 4.2 x 10⁻⁸N.

The gravitational force between the proton and electron is 1.9 x 10⁻⁴⁷N.

a) Charge on proton = charge on electron = q = 1.6 x 10⁻¹⁹C

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The electrostatic force of attraction between the proton and electron is given by,

F = 1/4πε₀(q²/r²)

F = 9 x 10⁹ x (1.6 x 10⁻¹⁹)²/(7.4 x 10⁻¹¹)²

F = 9 x 10⁹ x 2.56 x 10⁻³⁸/54.76 x 10⁻²²

F = 4.2 x 10⁻⁸N

b) Mass of the electron, m₁ = 9.1 x 10⁻³¹kg

Mass of the proton, m₂ = 1.67 x 10⁻²⁷kg

Distance between the proton and electron, r = 7.4 x 10⁻¹¹m

The gravitational force between the proton and electron is given by,

F = Gm₁m₂/r²

F = 6.67 x 10⁻¹¹x 9.1 x 10⁻³¹x 1.67 x 10⁻²⁷/(7.4 x 10⁻¹¹)²

F = 1.9 x 10⁻⁴⁷N

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Given

12 km south

4 km west

1 km north

Procedure

Let's do a diagram

The distance they covered is just the sum of all the distance they went

Total distance = 12 + 4 + 1 = 17 km

The displacement, however, is the vector sum. It answer's the question of how far are you from your starting point.

Answer:

A decrease in the radius and an increase in the tangential speed.

The greatest increase in the acceleration of a satellite is caused due to a decrease in the radius and an increase in the tangential speed. The correct option is third.

Acceleration is given by the ratio of resultant or total force acting on any object and the its mass.

It can also be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

There are two types of acceleration: centripetal and tangential acceleration.

Tangential acceleration in a circular motion is given by

at = mv²/r

Acceleration is inversely proportional to the radius of the orbit of satellite.

Tangential acceleration and centripetal acceleration collectively gives the resultant acceleration. Both are perpendicular to each other.

The greatest increase in the acceleration of a satellite is caused due to a decrease in the radius and an increase in the tangential speed.

Thus, the correct option is third.

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We can use the formula for angular deceleration to find the time interval needed for the wheel to come to a complete stop:

α = (ωf - ωo) / Δt

where ωf is the final angular velocity, ωo is the initial angular velocity, and Δt is the time interval. Rearranging the formula, we get:

Δt = (ωf - ωo) / α

Since the wheel comes to a complete stop, the final angular velocity is zero:

ωf = 0

Substituting the given values, we get:

Δt = (0 - 34.28) / (-1.77) ≈ 19.37 s

The formula for angular displacement is:

θ = ωo t + (1/2) α t^2

where θ is the angular displacement, ωo is the initial angular velocity, α is the angular acceleration, and t is the time interval. When the wheel comes to a complete stop, the final angular velocity is zero, so the formula simplifies to:

θ = ωo t + (1/2) α t^2

Substituting the given values, we get:

θ = (34.28 rad/s)(19.37 s) + (1/2)(-1.77 rad/s^2)(19.37 s)^2 ≈ -2003.9 rad

The negative sign indicates that the wheel has rotated in the opposite direction of its initial motion.

To get the total angular distance traveled by the wheel during this time interval, we take the absolute value of θ:

|θ| = |-2003.9 rad| = 2003.9 rad

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Answer:

The correct option is B.

away from each other (they repel)

Explanation:

This because when current flows in opposite direction in wire, the electrons in them are at high density or electrons in the wires will be at high density which is as a result of contraction of the length due to relativistic of the length, this make the wires to move away from each other or repel.

Answer:

1.2 x \(10^4\) N

Explanation:

The centripetal force of a body moving in a circle is given by:

Centripetal force = \(\frac{Mv^2}{r}\)

where M = mass of the object, v = velocity with which the object is moving, and r = radius of the circle.

In this case, M = 25,000 kg, v = 2.0 m/s, and r = 8.2 m. Hence;

Centripetal force generated by the whale = 25,000 x 2^2/8.2

                                            = 12,195.12 N = 1.2 x \(10^4\) N to two significant digits.

If the applied force is 20 N and the displacement is from X=0m to X=5.0m, the work done is 100 Joules.

To determine the work done by a force, you need to know the displacement and the component of the force parallel to the displacement.

In this case, if the force applied is 20 N and the displacement is from X=0m to X=5.0m, you need to determine if the force is parallel to the displacement.

If the force is parallel to the displacement, then the work done is simply the product of the force and the displacement, which is:

Work = Force x Displacement

Work = 20 N x (5.0 m - 0 m)

Work = 100 Joules

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The complete question is below:

What is the work done from X =0m to 5.0m? if the applied force is 20 N

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

RBA = -1100 m, 26 m. a radio detecting device that can detect objects and provide their range, azimuth, and/or elevation. Military and Related Terms Dictionary.

Many people believe the WSR-88D to be the most potent radar in the world because it transmits at a whopping 750,000 watts (a typical light bulb only uses 75 watts)! With this strength, a radar's energy beam may cover large areas and pick up a variety of weather occurrences.

AOPA Numerous features, including articles and planning tools, are included in this all-in-one software from the largest pilot organization in aviation. But for pilots, the Pilot Passport feature is of great significance.

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Answer:

8.87

Explanation:

Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

Answer:

Following are the responses to the given question:

Explanation:

In point a:

Nucleus denoting, he refers to those same nuclei of the helium ( that is alpha particle)

\({z}^{N^{A}}\to z-2^{N^{A-4}} + 2^{He^{4}}\)

In point b:

Let the kinetic energy of \(\alpha\) particle = \(K_1\)

\(\to K_1 = \frac{mass \times (velocity)^2}{2}\)

The velocity of \(\alpha\) particle \((v_1)= (2 \times \frac{k_1}{m_1})^\frac{1}{2}\)

Let daughter core velocity be =\(v_2\)

Preserving linear acceleration since there was no external factor we can write

\(\to m_2 \times v_2 = m_1 \times v_1\\\\\to v_2 = \frac{m_1\times v_1}{m_2}\\\\\to v_2 = \frac{m_1\times (2 \times \frac{k_1}{m_1})^{\frac{1}{2}}}{m_2}\)

Daughter nuclei energy can be written as:

\(\to \frac{mass \times (velocity)^2}{2}\\\\\to \frac{m_2 \times (m_1)^2 \times 2 \times k_1}{(2\times m_1 \times (m_2)^2)}\\\\ \to (\frac{m_1}{m_2}) \times k_1\)

In point c:

Initial weight = M

Total product weight \(= m_1 + m_2\)

You can use the total release energy (Q-factor) as =\((M - (m_1+m_2)) c^2\)

Answer:

B. IV only

Explanation:

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Explanation:

Both because water can fall in holes and then freeze. However, water can also be chemically react with other elements and substances to wear something away.

Here is a synthesis method for using the Grignard reagent to change cyclopropane into cyclopropanecarboxylic acid: Make cyclopropane into cyclopropanone using ozonolysis or another appropriate process.

Dichlorocarbene is one illustration. The formation of cyclopropanes from these halogenated carbenes is similar to that of methylene, with the intriguing addition of two halogen atoms in lieu of the hydrogen atoms. Although they do not strictly qualify as carbenes, carbeneoids are substances that combine to form cyclopropanes.

Since the addition of carbene and carbenoids to alkenes is a type of cheletropic reaction and occurs in a syn way, cyclopropanation also exhibits stereospecificity.

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The experimental verifications about the existence of the gravity can be done with different contexts.

For instance, the force in between two isolated spheres, demostrates that there is a kind of interaction in between the spheres. The scientist defined such interaction as gravity.

When artificial satellites are sent to the outer space, they orbit the Earth becasue of the gravity of the Earth, otherwise, they would travel away in a straight line trought the outer space.

Explanation:

180 million km = 10 min

? = 1 min

180 million x 10 = 1,800,000,000 km

180 million km = 600s

? = l s

108,000,000,000km

Answer:

I think false I don't know if I right but I hoped this help

Answer:

North and South poles

Explanation:

Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.