The work done by the weightlifter on the barbell is 166 J.
The work done on an object is given by the equation W = Fd, where W is the work done, F is the force applied, and d is the displacement of the object. In this case, the weightlifter is applying a force to lift the barbell against the force of gravity.
The weight of the barbell can be calculated as W = mg, where m is the mass of the barbell and g is the acceleration due to gravity (approximately 9.8 \(m/s^{2}\)).
Substituting the values given, we get: W = (13.0 kg)(9.8 \(m/s^{2}\)) = 127.4 N
To find the work done, we need to multiply the force by the distance moved, so: W = (127.4 N)(1.30 m) = 165.6 J
Therefore, the work done by the weightlifter on the barbell is 166 J (rounded to the nearest whole number).
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as magma travels up from the asthenosphere through the lithosphere and continental crust, how will fractional crystallization change the chemistry of an ultramafic magma
Fractional crystallization is a process that occurs as magma cools and solidifies, leading to the formation of different minerals. In the case of an ultramafic magma, which is rich in magnesium and iron, fractional crystallization can significantly change its chemistry.
During fractional crystallization, the minerals that crystallize first from the magma are typically richer in iron and magnesium than the remaining liquid portion. As these minerals separate from the liquid, the remaining magma becomes depleted in iron and magnesium and becomes more silica-rich. In the context of an ultramafic magma, which is composed primarily of minerals like olivine and pyroxene, the initial stages of fractional crystallization will result in the crystallization of these minerals. As the process continues, more silica-rich minerals like plagioclase feldspar and quartz can start to crystallize, further altering the magma's chemistry. Overall, fractional crystallization in an ultramafic magma leads to a gradual change in its composition, transforming it from a magnesium and iron-rich ultramafic composition to a more silica-rich composition. The specific minerals that crystallize and the extent of chemical changes depend on factors such as the cooling rate, pressure, and the composition of the original magma.
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When replacing an existing luminaire (fixture) with a ceiling-suspended paddle fan, make sure that the existing outlet box is listed and marked as ____________________.
Answer:
When replacing an existing luminaire (fixture) with a ceiling-suspended paddle fan, make sure that the existing outlet box is listed and marked as ________one that can support the fan__________
Explanation:
Because an outlet which is not listed an cannot support the fan will lead to its damage and short lifespan
in a helium-cadmium laser, find the energy difference between the two levels involved in the production of blue light of wavelength 441.6 nm by this system.
The energy difference between the two levels involved in the production of blue light of wavelength 441.6 nm in a helium-cadmium laser is approximately \(4.50 *10^{-19}\) Joules.
In a helium-cadmium laser, blue light with a wavelength of 441.6 nm is produced as a result of energy level transitions. To find the energy difference between the two levels involved, you can use the formula:
E = (hc)/λ
where E is the energy difference, h is Planck's constant (\(6.626 * 10^{-34} Js\)), c is the speed of light (\(3 * 10^8 m/s\)), and λ is the wavelength (441.6 nm or \(441.6 * 10^{-9} m\)).
E = \((6.626 * 10^{-34} Js)(3 * 10^8 m/s) / (441.6 * 10^{-9} m)\)
E ≈ \(4.50 * 10^{-19} J\)
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A vehicle travels for 20 minutes at a speed of 60 km/h. It then travels for 10 minutes at 90 km/h. At
the end of 30 minutes, it covers a distance of Select... v km.
Answer:
120km
Explanation:
it will covered 120km
alice is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. suppose you claim that you are feeling the effects of a gravitational field. how can you explain the fact that alice is weightless? alice is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. suppose you claim that you are feeling the effects of a gravitational field. how can you explain the fact that alice is weightless? she is weightless because she is in a not moving. she is weightless because she is in free-fall. she is weightless because she is moving at constant velocity. if you are in a gravitational field, then she cannot be weightless.
Alice is weightless because she is in free fall.
Free-fall occurs when an object is experiencing the force of gravity but is not experiencing any other forces, such as air resistance. Because Alice is in a spacecraft, air resistance is not a factor, so she is essentially in a vacuum.
When an object is in a vacuum, the only force acting upon it is gravity. Therefore, Alice is in free fall and is experiencing weightlessness. This is in contrast to you, who is experiencing 1g of acceleration due to the force of the engine of your spacecraft.
This force is greater than the force of gravity, so you are not in free fall, and thus you are feeling the effects of the gravitational field.
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what is sound??
ANSWER: A sound is a form of energy like heat energy, light energy, potential energy and
kinetic energy. It causes a sensation of hearing in our ears. Sound helps us
communicate with each other
Explanation:
A sound is a form of energy like heat energy, light energy, potential energy and
A sound is a form of energy like heat energy, light energy, potential energy andkinetic energy. It causes a sensation of hearing in our ears. Sound helps us
A sound is a form of energy like heat energy, light energy, potential energy andkinetic energy. It causes a sensation of hearing in our ears. Sound helps uscommunicate with each other
I just copied ur ans friend
A Blowhard Tests of lung capacity show that adults are able to exhale 1.5 liters of air through their mouths in as little as 1.0 second.Part AIf a person blows air at this rate through a drinking straw with a diameter of 0.61cm , what is the speed of air in the straw? Express your answer using two significant figures. V = m/s Part B If the air from the straw in part A is directed horizontally across the upper end of a second straw that is vertical, as shown in the figure(Figure 1) , to what height does water rise in the vertical straw? Express your answer using two significant figures. h = m
A). the speed of air in the straw is 35 m/s
B). height does water rise in the vertical straw is 0.078 m
Calculation :
d is the diameter, A is the area, v is the velocity,
Area*Velocity is the amount of air flowing per second.
A v = πd² v/4 = 1.5 liters per second = 0.0015 m^3/s
v = 0.0015*4/(π*0.0074²) =35 m/s
====== ===================
B).
Use Bernoulli's equation
ρ v₂²/2 = hdg where ρ is the density of air and d is water The density of
is
h = ρ v₂²/ (2dg) = 1.25*34.8769² /(2*1000*9.8) = 0.07758 = 0.078 m
The Bernoulli equation is the relationship between the pressure, kinetic energy, and gravitational potential energy of a liquid in a container. The formula for Bernoulli's principle is: p + 1 2 ρ v 2 + ρ g h = co n s t a n t.
Bernoulli's principle is based on the law of conservation of energy. Equalize the total energy (pressure energy, potential energy, and kinetic energy) of a flowing liquid at different points flowing under a constant pressure difference.
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a body starts from rest with a uniform acceleration of 2m s-2 find the distance covered by the body in 2s
The distances traveled by the boy will be 4 m. Newton's second equation of motion is applied.
What is the distance?Distance is a numerical representation of the distance between two objects or locations.
The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
Given data;
acceleration(a)=2m/s²
Time (t)=2 s
u(Initial velocity)=0
The distance traveled by the boy will be;
\(\rm S=ut+\frac{1}{2} at^2 \\\\ \rm S=0+\frac{1}{2} (2)(2)^2 \\\\ S=4 \ m\)
Hence, the distance traveled by the boy will be 4 m.
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Which type of graph would be best for showing the percentage of people in a
family with different jobs?
A. Bar graph
B. Circle graph
C. Scatterplot
D. Line graph
suppose the skater suddenly puts both skates on the ice (blades pointed directly forward) and coasts to a stop. neglecting air resistance (drag), how far will the skater travel before coming to a stop? assume the skater is moving at 4 m/s at the beginning of the coast
Since acceleration is negative, the skater will travel a positive distance before coming to a stop. Therefore, the skater will travel a distance of 16 / acceleration + 8 / acceleration.
The distance the skater will travel before coming to a stop can be determined using the equation of motion: distance = initial velocity × time + (1/2) × acceleration × time². In this case, the skater is coasting to a stop, so their acceleration is negative, opposing their initial velocity.
Given that the skater is moving at 4 m/s initially and neglecting air resistance, we know the initial velocity is 4 m/s. Since the skater is coasting to a stop, their final velocity will be 0 m/s.
To find the distance traveled, we need to determine the time it takes for the skater to stop. Since the acceleration is constant, we can use the equation final velocity = initial velocity + (acceleration × time). Solving for time, we get time = (final velocity - initial velocity) / acceleration.
Substituting the given values, we have time = (0 - 4) / acceleration. Since the skater is stopping, the acceleration is negative, so we have time = -4 / acceleration.
Now, substituting this value of time into the equation of motion, we have distance = 4 m/s × (-4 / acceleration) + (1/2) × acceleration × (-4 / acceleration)².
Simplifying the equation, we get distance = -16 / acceleration - 8 / acceleration.
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I need help please mark you answers with the question Ex: Question: 1 The answer is __
thank you
The velocity of an object includes direction of the motion of an object whereas speed does not include direction. Thus, the correct options for 1, 2, 3, 4, and 5 are B, B, A, A, and B, respectively.
What is Velocity?Velocity can be defined as the directional speed of an object in the motion as an indication of the rate of change in the position of an object as observed from a particular frame of reference by the observer and as measured by a particular standard of time.
The velocity is different from that of speed as it is a vector quantity, the velocity of an object includes direction of the motion of an object whereas speed does not include direction.
Track runners cover same distance however, the winner in the race is the one who covers the particular distance in less time than other competitors.
The slowest runner in the graph is the one represented with blue color. This is because, this runner took maximum time to cover the distance.
The distance covered by the train is 300 miles in time period of 6 hours. Therefore, the speed of the train will be the distance covered by the train divided by the total time taken.
Speed of the train = 300 miles/ 6 hours
Speed of the train = 50 miles per hour.
The example of velocity is the one with the unit of length per time. From the given options, 80 miler per hour is an example of velocity as miles is the unit of length and hour is the unit of time.
Therefore, the correct options for 1, 2, 3, 4, and 5 are B, B, A, A, and B, respectively.
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A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest possible efficiency it could have?
(NO UNIT)
Answer:
59.19%
Explanation:
Step 1:
Data obtained from the question. This include the following:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Step 2:
Determination of the efficiency of the engine.
Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:
Efficiency = output /input x 100
With the above formula, we can calculate the efficiency of the engine as follow:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Efficiency = output /input x 100
Efficiency = 293/495 x 100
Efficiency = 59.19%
Therefore, the efficiency of the engine is 59.19%
Answer:
0.41
Explanation:
Trust me bro
a spider is crawling at 630 ft/hr. the room is 15 ft wide. How long does it take the spider to travel
The time taken for the spider crawling at 630 ft/hr to travel through the 15 ft wide room is 42 hours
How do I determine the time taken for the spider to travel?From the formula of speed, we can obtain a formula for calculating time as illustrated below:
Speed = Distance / time
Cross multiply
Speed × time = Distance
Divide both sides by speed
Time = Distance / speed
Using the above formula, we can obtain the time taken from the spider to travel through the room. Details as follow:
Speed of spider = 630 ft/hrDistance travel = 15 ftTime taken to travel =?Time = Distance / speed
Time = 630 / 15
Time = 42 hours
From the calculation made above, we can conclude that the time taken is 42 hours
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The type of energy that depends on position is called
a.
potential energy.
b.
electrical energy.
c.
magnetic energy.
d.
solar energy.
Answer:
a. potential energy
Explanation:
ur welcome
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz, and the wavelength is 5.00 m, what is the spee
The speed of the sonar signal can be calculated by multiplying the frequency of the signal (288 Hz) by the wavelength (5.00 m). Thus, the speed of the sonar signal is 1,440 m/s.
To find the speed of the sonar signal, we can use the formula v = f * λ, where v represents the speed, f is the frequency, and λ is the wavelength.
Given that the frequency of the sonar signal is 288 Hz and the wavelength is 5.00 m, we can substitute these values into the formula.
v = 288 Hz * 5.00 m
By multiplying the frequency and the wavelength, we can calculate the speed of the sonar signal.
v = 1440 m/s
Therefore, the speed of the sonar signal is 1440 meters per second.
Sonar devices use the speed of sound in water to measure underwater depths. By transmitting sound waves and measuring the time it takes for them to bounce back, sonar systems can determine the distance between the device and an object underwater. The speed of the sonar signal is crucial for accurate depth calculations, as it affects the time it takes for the signal to travel and return.
The question was incomplete. find the full content below:
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz, and the wavelength is 5.00 m, what is the speed of the sonar signal in water?
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what is the acceleration if a 5 kg cart is pushed with 30 N of force?
Answer:
6 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
f is the force
m is the mass
From the question we have
\(a = \frac{30}{5} \\ \)
We have the final answer as
6 m/s²Hope this helps you
a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite direction. what is the work done on it?
Answer:-50 J
Explanation:
Answer: -50 N
Explanation:
taking the potential energy to be zero at infinite separation, find the potential energy of a 47 kg object at the surface of the earth.
The potential energy of a 47 kg object at the surface of the Earth is approximately 2.94 x 10^9 J.
The equation U = mgh, where m is the object's mass, g is the acceleration brought on by gravity, and h is the height above the surface of the Earth, may be used to determine an object's potential energy at a particular height h above the Earth's surface. At the Earth's surface, h is equal to the radius of the planet, which is around 6.37 x 106 metres. About 9.81 m/s2 is the value of g at the Earth's surface. As a result, it is possible to compute the potential energy of a 47 kilogramme item at the Earth's surface using the formula U = (47 kg) x (9.81 m/s2) x (6.37 x 106 m) = 2.94 x 109 J. in 30 words.
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USE THE FOLLOWING INFORMATION TO ANSWER THE NEXT TWO QUESTIONS. Some Characteristics of Electrical Energy Generation Systems i. non-renewable fuel i
ii. contribute to acid rain iii. heats up water iv. converts chemical potential energy v. converts gravitational potential energy vi. not available during all seasons 23. When comparing a CANDU nuclear reactor with a coal- fired electrical generating system, which characteristics are common to both? a. i and iii only b. ii and iv only C. i, iv, and v only d. ii, iii, and v only
When comparing a CANDU nuclear reactor with a coal-fired electrical generating system, the characteristics that are common to both are i, iv, and v. Both a CANDU nuclear reactor and a coal-fired electrical generating system share the use of non-renewable fuel, conversion of chemical potential energy, and the absence of direct gravitational potential energy conversion.
i. Both systems utilize non-renewable fuel. The CANDU reactor uses uranium as fuel, which is a finite resource, while coal-fired systems rely on the combustion of coal, which is also a non-renewable fossil fuel.
iv. Both systems convert chemical potential energy into electrical energy. In the CANDU reactor, nuclear fission of uranium atoms releases energy that is converted into electricity, whereas in a coal-fired system, the combustion of coal produces heat that is converted into electrical energy.
v. Both systems do not directly convert gravitational potential energy. The CANDU reactor and coal-fired systems do not rely on the gravitational potential energy of water or any other substance as a primary source of energy conversion.
Therefore, the correct answer is option c. i, iv, and v only. Both systems share the use of non-renewable fuel, conversion of chemical potential energy, and absence of direct gravitational potential energy conversion.
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a 50 kg box is pushed to the left using 500 N, the frictional force on the box is 100 N what is the acceleration on the box?
First thing's first, we need to find the Net Force of the system in order to solve for acceleration. Gravity and Normal Force cancel out, so we don't really have to worry about anything on the y-axis. However, looking at the x-axis, we see two forces: the Force of the push and Frictional Force.
This means that:
\(F_{net}\) = 500 - 100
\(F_{net}\) = 400 (N)
Recall that Force = Mass * Acceleration. Since we have the Force and Mass, we can easily solve for Accel:
F = ma
a = \(\frac{F}{m}\)
Plug the net force and mass into the equation:
a = \(\frac{F}{m}\)
a = \(\frac{400}{50}\)
a = 8 (m/\(s^{2}\))
The box's acceleration is 8 m/\(s^{2}\)
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3.5 x 10^-3 as a regular number (convert from scientific notation to a real number)
Answer: 0.0035
============================================
Explanation:
The exponent is -3, so we move the decimal point 3 spots to the left to go from 3.5 to 0.0035
If the exponent was positive, then we would move the decimal point to the right that amount of spaces.
Deanna's niece loves to swing at the local playground, so Deanna takes her and pushes her on the swing. Deanna must use (motion / transfer / force / energy) to exert a (transfer / motion / force / energy) that causes the swing to change (force / energy / motion / transfer/position).
AnswerShe uses force and air
Explanation:
n bhvygvg gv
2. Stars normally convert hydrogen into helium through nuclear fusion. That requires incredibly hot temperatures and high pressure. At the moment, the temperature of empty space is nowhere near warm enough to fuse any elements together. What type of temperature and pressure conditions needed to be present in the early universe in order to create the first hydrogen atoms
Answer:
About 4,000 K and 10⁻¹⁷ atm
Explanation:
The Big Bang theory states that the Big Bang which is the origin of the universe was about 13.75 billion years ago, and the temperature a few seconds later was 10³²K
The first element began forming at about 3 minutes after the Big Bang with a temperature of 10⁹ K, the nuclei of simple elements
The nuclei of hydrogen and helium began combine with electrons at a temperature of 3,000 K to 4,000 K to form the first neutral atoms. The pressure of the universe at that stage was 10⁻¹⁷ atmospheres
The gravitational force exerted on an astronaut on the Earth's surface is 650 N directed downward. When she is in the space station in orbit around the Earth, the gravitational force on her is
larger. exactly the same. smaller. nearly but not exactly zero. exactly zero.
The gravitational force exerted on an astronaut on the Earth's surface is 650 N directed downward. When she is in the space station in orbit around the Earth, the gravitational force on her is nearly but not exactly zero.
Gravity is the force that draws objects to the center of the earth. Gravity is determined by the mass and density of the earth. The closer you are to the earth, the stronger the gravitational force on you. The gravitational force on an astronaut on the surface of the earth is 650N, directed downwards. The gravitational force on her in the space station in orbit around the earth is nearly but not exactly zero. In other words, the force of gravity on an object or person is directly proportional to the object or person's mass and the distance between them and the earth. The gravitational force exerted by the earth on an object decreases as the object's distance from the earth increases. The farther an object is from the earth, the less it weighs.
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What magnitude of impulse (in n-s) will give a -kg object a momentum change of magnitude kg-m/s? round your answer to the nearest whole number.
The magnitude of the impulse will be equal to the magnitude of the momentum change.
The magnitude of impulse can be calculated using the formula:
Impulse = change in momentum
Given that the momentum change has a magnitude of kg-m/s, we can use this value to calculate the magnitude of the impulse.
Impulse = kg-m/s
To find the magnitude of the impulse in n-s (newton-seconds), we can use the fact that 1 N-s is equal to 1 kg-m/s.
So, the magnitude of the impulse will be equal to the magnitude of the momentum change.
Therefore, the magnitude of the impulse is kg-m/s.
To round this answer to the nearest whole number, we can round kg-m/s to the nearest whole number.
In this case, the magnitude of the impulse is 150 n-s.
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what is the work done on a 10.0-kilogram object at rest to give it a speed of 5.00 meters per second?
The work done on a 10.0-kilogram object at rest to give it a speed of 5.00 meters per second is 125J.
Calculation:
Ek = kinetic energy (Ek)
Mass = kilograms (kg)
Speed = meters per second (m/s)
Therefore, the answer to this question is:
Ek = 1/2 x 10 x 5^2
Ek = 5 x 25
Ek = 125J
And since Ek is the same as work done.
Work done = 125 J.
The product is the kinetic energy of the object. Kinetic energy depends on the square of the object's velocity. That is, if the velocity of an object doubles, its kinetic energy quadruples. Find the square of the object's velocity. Multiply this square by the mass of the object.
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What is 44 °C in °F?
44 degrees celsius when converted into fahrenheit will be equal to 111.2 degrees Fahrenheit.
you can use the below given formula in order to convert degree Celsius from degree Fahrenheit .
°F = (°C × 9/5) + 32
in order to get the temperature in terms of degree Fahrenheit you should initially substitute the given temperature in degree Celsius.
After substituting the degree Celsius as 44 the equation is as given below.
F = (44 × 9/5) + 32
upon solving the equation we get
°F = 79.2 + 32
°F = 111.2
Hence 44 degrees Celsius when converted to Fahrenheit will be 111.2 degree Fahrenheit.
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Explain in terms of internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising.
The internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising are mentioned below.
What is evaporation ?
The water cycle's crucial step is evaporation. When a liquid transforms into a gas, evaporation takes place. As rain puddles "disappear" on a hot day or when wet clothing dries in the sun, it is simple to envision. The liquid water in these instances is evaporating into a gas known as water vapor rather than actually dissipating.
What is energy?
Examples and Definitions of Energy (Science) The capacity to work comes from energy. Energy types include chemical, nuclear, and electrical energy. Science and engineering both depend on the idea of energy. Here is a look at the classification of energy as well as its description and examples.
Therefore, The internal energy of the system how the evaporation of sweet cools down the body of the athlete after exercising are mentioned above.
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calculate the frequency of a wave that is traveling at a speed of 3.0 m/s and has a wavelength of 1.2m
Answer:
2.5 Hz
Explanation:
3.0m/s / 1.2 m=2.5 1/s=2/5 Hz
The frequency of a wave with speed of 3.0 m/s and has a wavelength of 1.2m is 2.5 Hz.
What is frequency?The frequency of a wave is the number of cycles per second.
Given the wavelength is 1.2 m and speed v =3.0m/s, then the frequency of the wave is
v =fλ
f = 3 / 1.2
f = 2.5 Hz
Thus, the frequency of the wave is 2.5 Hz.
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A student performs an activity using a sheet of paper, a magnet, and a steel ball. The image shows the setup. The student observes that the steel ball sticks to the magnet even though, the paper is between them. Which factor leads to the attraction of the ball to the magnet.
A. The magnet exerts a force on the ball.
B. The magnet attracts paper, which pulls the ball. C. The paper exerts a force on the ball, Which pulls the ball towards the magnet.
D. The size of the ball attracts to the ball towards the magnet.
Answer:b
Explanation:
A steel ball, a magnet, and a piece of paper are used in an activity by a pupil. The ball is under the influence of the magnet. Therefore, choice A is right.
What is a magnet?When electric charges move, a phenomenon known as magnetism is produced. These tiny movements can occasionally be found inside a material known as magnets. Magnets and the magnetic fields created by moving electric charges can attract or repel other magnets, which can also change how other charged particles move.
Because they can support a magnetic field that lasts forever, some materials, like iron, are categorized as permanent magnets. These are the magnets that are typically encountered in day-to-day life. Other materials like iron, cobalt, and nickel can be briefly given a magnetic field when placed inside a stronger, bigger magnetic field, but they will eventually lose their magnetic qualities.
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