Answers
Motion of the basket is 3.2667 m/s^2.
Given that force exerted T=100N
Weight of the basket W=mg=75N
Mass of the basket m= W/g=7.653kg
If a is the acceleration then
T-W=ma
a=T-W/m
=100-75/7.653
=3.2667 m/s^2
In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
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Related Questions
pls help need it last question on my test
Answers
The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.
Friction is a force that opposes motion between two surfaces in contact.
In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.
As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.
Friction is a resistance force that opposes motion.
It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.
When the car is moving, there is friction between the two surfaces.
The direction of the friction force is opposite to the direction of motion of the car.
This means that the friction force slows the car down.
In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.
The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.
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An 74,769kg airplane is flying at 217m/s to the East. What is the magnitude of the momentum of the airplane
Answers
Given,
The mass of the airplane, m=74,769 kg
The speed of the airplane, v=217 m/s
The momentum can be defined as the product of the mass of an object and its velocity.
Thus, the magnitude of the momentum of the airplane is given by,
\(p=mv\)On substituting the known values,
\(\begin{gathered} p=74769\times217 \\ =16.22\times10^6\text{ kg}\cdot\text{m/s} \end{gathered}\)Thus the magnitude of the airplane is 16.22×10⁶ kg·m/s.
an object is thrown into the air and follows the path shown in the diagram above. Neglecting air resistance, which vector best represents the acceleration of the object at point A?
Answers
Answer: 3 (c)
Explanation: The only force acting on the object is the force of gravity, mg, which acts straight downward. Even though the object has horizontal velocity, there is no horizontal force after the object is done being thrown.
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
Answers
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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True or False. A person who is nearsighted cannot see objects that are close to them clearly.
Answers
Answer:
false
Explanation:
hope it works
A driver loses control of a car, drives off an embankment, and lands in a canyon 6.0 m below. if it was traveling on the level surface at 12 m/s and traveled 20 meters before crashing off the crash with a kinetic friction between the car and road of .1. What was the speed at the time it hits the ground?
Answers
The initial mechanical energy of the car is equal to its final energy from this, we can find the speed of the car. The final velocity of the car at the time it hits the ground is 16.17 m/s.
What is mechanical energy ?Mechanical energy of an object is the sum of its kinetic and potential energy. According to law of conservation of energy initial mechanical energy of a moving object is equal to the final mechanical energy.
Given initial speed of the car u = 12 m/s
height from the surface = 6 m
g = 9.8 m/s²
According to conservation of energy,
1/2 mu² + mgh = 1/2 mv²
u²/2 + gh = v²/2
12²/2 + (9.8 m/s² × 6 m) = v²/2
v = 16.17 m/s.
Therefore, the final speed of the car at the time it hits the ground is 16.17 m/s.
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There exist two parallel 1 m x 1 m x ~0 m (infinitesimally thin) conducting plates sitting
parallel to each other and the xz-plane. The positively charged plate is at y = 0, and the negatively
charged plate is at y = 0.01 m. An electron is released from rest in between the charged plates. Explain
why the electron moves in the proper direction in terms of the forces acting on the electron.
Answers
An electric field is a region in which electric charges sustain electrical conduction. An electric field describes the electrical environment around an electron.
What is meant by electric force?The electric force is the force between two charged bodies due to electric charges. The electric field at a point indicates the force experienced by a positive unit test charge at that point.
In this case, electrons move to higher potentials. Since the electric field is directed from the positive plate to the negative plate, electron acceleration occurs towards the negative plate and the negative plate is deflected towards the positive plate.
In this case, the electrostatic force is F = E q,
Here the electric field E = V/d is constant and the charge on the electron is constant, so the force on the electron is constant. Hence, the electron moves in the proper direction in terms of the forces acting on the electron.
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WILL GIVE BRAINLIEST PLS HELP!!
A student taking an Earth Science class tries to move a rock with a weight of 10,000 N. He strains and huffs and puffs but fails to budge the rock. How much work did your friend do?
Answers
Answer:
zero
Explanation:
zero, because no displacement
How might writing an online journal be different than writing in a paper one?
A. It's ok to talk badly about people in an
online journal.
O B. It's easier to communicate online.
O C. You should expect less privacy.
O D. You should expect more privacy.
Answers
Writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online (option B).
What is a journal?A journal is a newspaper or magazine dealing with a particular subject.
A journal is an efficient medium to communicate the findings or results of an investigation to the public.
However, a journal can be virtual (online) or paper (hard copy). In this 21st century, it is easier to communicate to the masses online because more audience will be captured.
Therefore, writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online.
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The addition of 9.5×10^5 of thermal energy is required to convert a block of ice at −15° to water at 15°. What was the mass of the block of ice?
Answers
Answer:
2.2241 Kg
Explanation:
Given that it takes \(9.5 \times 10^5 \ J\) of energy to convert a block of ice at −15° to water at 15°. Find the mass of the block of ice. We'll call \(9.5 \times 10^5 \ J\) "\(Q_{melt}\)" which is the total energy taken to melt the block of ice.
\(\boxed{\left\begin{array}{ccc}\text{\underline{Heat energy formulas:}}\\Q=mc\Delta T\\Q=mL_f\\\end{array}\right}\)
The energy it takes to raise the temperature of the ice from −15° to 0°:
\(Q_1=m_b(2090)(-15\°-0\°)\\\\||Q_1||=\boxed{31350m_b}\)
The energy it takes to convert the ice to water:
\(Q_2=\boxed{3.33\times 10^5 m_b}\)
The energy it takes to raise the temperature of the water from 0° to 15°:
\(Q_3=m_b(4186)(0\°-15\°)\\\\||Q_3||=\boxed{62790m_b}\)
\(Q_{melt}=Q_1+Q_2+Q_3; \ Q_{melt}=9.5 \times 10^5 \\\\\Longrightarrow 9.5 \times 10^5=31350m_b+3.33\times 10^5 m_b+62790m_b\\\\\Longrightarrow 9.5 \times 10^5=(31350+3.33\times 10^5 +62790)m_b\\\\\Longrightarrow 9.5 \times 10^5=427140m_b\\\\\Longrightarrow \boxed{\boxed{m_b \approx 2.2241 \ kg}}\)
Thus, the mass is found.
When putting the ball on the tee you want half of the golf ball to be above the club be below the club be in front of the club be behind the club
will put brainlest
Answers
A golf ball is a unique ball made specifically for the game of golf.
What is Gulf ball?A golf ball must adhere to specific velocity, distance, and symmetry requirements as well as have a mass of no more than 1.620 oz (45.9 g), a diameter of no less than 1.680 inches (42.7 mm), and no more than 1.620 oz (45.9 g) in total.
Similar to golf clubs, golf balls must pass testing and approval by The R&A and the United States Golf Association before they can be used in competitions.
Early in the 20th century, it was discovered that dotting the ball gave the player even more control over the trajectory, flight, and spin of the ball.
Therefore, A golf ball is a unique ball made specifically for the game of golf.
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A 5 cm spring is suspended with a mass of 1.408 g attached to it which extends the spring by 2.078 cm. The same spring is placed on a frictionless flat surface and charged beads are attached to each end of the spring. With the charged beads attached to the spring, the spring's extension is 0.332 cm. What are the charges of the beads? Express your answer in microCoulombs.
Answers
First, use the mass of the object attached to the spring and the distance that the spring extends to find the constant of the spring.
Once the spring's constant is known, use it to find the force between the charges of the beads. Finally, use Coulomb's Law to find the charges of the beads.
The force exerted by a spring extended a distance Δx is given by Hooke's Law:
\(F=k\Delta x\)The weight of a mass m is:
\(W=mg\)Where g=9.81m/s^2.
Isolate k from the Hooke's Law expression and replace F=W:
\(k=\frac{F}{\Delta x}=\frac{W}{\Delta x}=\frac{mg}{\Delta x}\)Since the spring extends by 2.078cm when a mass of 1.408g is attached, then:
\(\begin{gathered} k=\frac{(1.408g)(9.81\frac{m}{s^2})}{(2.078cm)} \\ \\ =\frac{(1.408\times10^{-3}kg)(9.81\frac{m}{s^2})}{(2.078\times10^{-2}m)} \\ \\ =0.6647\frac{N}{m} \end{gathered}\)When the charged beads are attached to the ends of the spring, it extends 0.332cm. Then, the force between the charges is:
\(F=k\Delta x=(0.6647\frac{N}{m})(0.332\times10^{-2}m)=2.2068\times10^{-3}N\)Since the resting length of the spring is 5cm, when the beads are attached, the distance between the beads is 5.332cm.
The force between two charged particles separated a distance r is given by the equation:
\(F=k_e\frac{q_1q_2}{r^2}\)Where k_e is Coulomb's constant:
\(k_e=8.98755\times10^9N\frac{m^2}{C^2}\)Assuming that both beads have the same charge, isolate q from the equation:
\(\begin{gathered} F=k_e\frac{q^2}{r^2} \\ \\ \Rightarrow q=r\sqrt{\frac{F}{k_e}} \end{gathered}\)Replace r=5.332cm, F=2.2068*10^-3N and the value of k to find the charge of the beads:
\(\begin{gathered} q=(5.332\times10^{-2}m)\sqrt{\frac{2.2068\times10^{-3}N}{8.98755\times10^9N\frac{m^2}{C^2}}} \\ \\ =26.4211...\times10^{-9}C \\ \\ =0.02642\mu C \end{gathered}\)Therefore, the charges of the beads are approximately 0.02642μC if both charges are equal.
if a wave has to travel 600 m and its wavelength is 0.4 m, with a frequency of 500 Hz. How much time will it take for the wave to travel 600 m?
Answers
Answer: 3 s
Explanation:
i took the test in physics :)
The time taken by the wave to travel the distance is 3 seconds.
What is meant by frequency of a wave ?
Frequency of a wave is defined as the number of oscillations or cycles completed by the wave within one second.
Here,
Distance travelled by the wave, d = 600 m
Wavelength of the wave, λ = 0.4 m
Frequency of the wave, f = 500 Hz
The expression for the velocity of the wave is given by,
v = fλ
v = 500 x 0.4
v = 200 m/s
Therefore, the time taken by the wave to travel the distance of 600 m can be given as,
Time taken = displacement/velocity
So,
t = d/v
t = 600/200
t = 3 s
Hence,
The time taken by the wave to travel the distance is 3 seconds.
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A 175,000 kg space probe is landing on an alien planet with a gravitational acceleration of 8.25. If its fuel is ejected from the rocket motor at 35,000 m/s what must the mass rate of change of the space ship (delta m)/(delta t) be to achieve at upward acceleration of 2.00 m/s^2? Remember to use the generalized form of Newton's Second Law.
answer with correct units
Answers
The mass rate of change of the space probe is approximately 28.49 kg/s .
What is the mass rate of the space probe?To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:
F = ma
In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:
F = (Δ m /Δt) * v
where;
Δ m /Δt t is the mass rate of change of the space ship, and v is the velocity of the ejected fuel, which is given as 35,000 m/s.Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:
F_net = m * g - (Δ m /Δt) * v
Plugging in the values and solving for delta m / delta t, we get:
2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s
Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s
Δm / Δt ≈ 28.49 kg/s
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a uniform electric field has magnitude 240 n/c and is directly to the right. A particle with charge +7.90 nC moves in this field along a straight line from a to b
Answers
The electric force that acts on the particle is 1.90 × 10^-6 N.
What is the electric force that acts on the particle?
The electric force F on a charged particle in a uniform electric field E is given by the formula:
F = qE
where;
q is the charge of the particle.E is the electric fieldIn this case, the charge of the particle is +7.90 nC, which is equivalent to +7.90 × 10^-9 C. The electric field has a magnitude of 240 N/C and is directed to the right.
So, the electric force acting on the particle is:
F = qE
= (+7.90 × 10^-9 C)(240 N/C)
= +1.90 × 10^-6 N
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The complete question is below:
a uniform electric field has magnitude 240 n/c and is directly to the right. A particle with charge +7.90 nC moves in this field along a straight line from a to b. Find the electric force that acts on the particle.
All the questions are in the photos above. Thanks guys!
Answers
Answer:
right
Explanation:
A solenoid 25.0 cmcm long and with a cross-sectional area of 0.550 cm^2 contains 460 turns of wire and carries a current of 90.0 A. Calculate:
a. the magnetic field in the solenoid.
b. the energy density in the magnetic field if the solenoid is filled with air.
c. the total energy contained in the coil’s magnetic field (assume the field is uniform).
d. the inductance of the solenoid.
Answers
Answer:
a. B = 0.20T
b. u = 17230.6 J/m³
c. E = 0.236J
d. L = 5.84*10^-5 H
Explanation:
a. In order to calculate the magnetic field in the solenoid you use the following formula:
\(B=\frac{\mu_o n i}{L}\) (1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
n: turns of the solenoid = 460
L: length of the solenoid = 25.0cm = 0.25m
i: current = 90.0A
You replace the values of the parameters in the equation (1):
\(B=\frac{(4\pi*10^{-7}T/A)(460)(90.0A)}{0.25m}=0.20T\)
The magnetic field in the solenoid is 0.20T
b. The magnetic permeability of air is approximately equal to the magnetic permeability of vacuum. To calculate the energy density in the solenoid you use:
\(u=\frac{B^2}{2\mu_o}=\frac{(0.20T)^2}{2(4\pi*10^{-7}T/A)}=17230.6\frac{J}{m^3}\)
The energy density is 17230.6 J/m³
c. The total energy contained in the solenoid is:
\(E=uV\) (2)
V is the volume of the solenoid and is calculated by assuming the solenoid as a perfect cylinder:
\(V=AL\)
A: cross-sectional area of the solenoid = 0.550 cm^2 = 5.5*10^-5m^2
\(V=(5.5*10^{-5}m^2)(0.25m)=1.375*10^{-5}m^3\)
Then, the energy contained in the solenoid is:
\(E=(17230.6J/m^3)(1.375*10^{-5}m^3)=0.236J\)
The energy contained is 0.236J
d. The inductance of the solenoid is calculated as follow:
\(L=\frac{\mu_o N^2 A}{L}=\frac{(4\pi*10^{-7}T/A)(460)^2(5.5*10^{-5}m^2)}{0.25m}\\\\L=5.84*10^{-5}H\)
The inductance of the solenoid is 5.84*10^-5 H
can someone help me pleaseenkwnsn
Answers
If a third resistor is added in SERIES, what changes happens to the....
a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decreaseWhat happens in a circuit?When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.
The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.
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5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
Answers
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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I am desperate to get to Denver, Colorado to catch the Denver Broncos
football game. It is a 1,778 mile trip from the Hamilton Street Campus. The
GPS tells me that it will take 26 hours to get there. What will my average
speed be during my trip there? INCLUDE THE UNITS IN YOUR ANSWER. plsss help meee
Answers
Answer:
The average speed needed is 68.4 mi/h
Explanation:
Average Speed
If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:
\(\displaystyle V=\frac{d}{t}\)
The distance to get to Denver from the Hamilton Street Campus is d=1,778 miles. An estimated time of t=26 hours should be needed to cover that distance, thus you will need to travel at an average speed of:
\(\displaystyle V=\frac{1,778\ mi}{26\ h}\)
V = 68.4 mi/h
The average speed needed is 68.4 mi/h
What is the mechanical advantage of a lever that has an input arm of 6 meters and an output arm of 2 meters
Answers
Answer:A
Explanation:I TOOK THE Test
There is a bottleneck in producing masses higher than4He, because there are no mass-5or mass-8 stable nuclides. For older stars with high densities and high temperatures (T>100 million K), three alpha particles can form12C. This occurs by two alpha particles firstforming8Be, and then8Be reacting with another alpha particle to form12C before8Be candecay back to two alpha particles.a) Explain why this can only happen in very hot stars and high density.b) Calculate how much energy is given up when three alpha particles form12C.
Answers
Answer:
Explanation:
a)
To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.
b)
The amount of energy given up can be calculated as follows:
\(_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)\)
where;
\(M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u\)
Therefore, from the reaction (1);
\(Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}\)
From the second reaction:
\(Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}\)
A 7.30 kg sign hangs from two wires. The first wire is attached to the left end, and pulls 28.0 N directly left. What is the y-component of the force of the second wire?
Answers
Answer:
Approximately \(71.6\; {\rm N}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)
Explanation:
Refer to the diagram attached. Forces on this object are:
Tension on the left, from the wire on the left end.Tension on the right, from the wire on the other end.Weight, from the planet.Assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\), the magnitude of the weight of the sign would be:
\(\begin{aligned}(\text{weight}) &= m\, g \\ &= (7.30\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) \\ &\approx 71.6\; {\rm N}\end{aligned}\).
Note that weight points downwards (negative) and is entirely in the vertical direction. As a result, the \(y\)-component of weight would be equal to \((-71.6)\; {\rm N}\).
Hence, the \(y\)-component of these forces would be:
\(0\; {\rm N}\) for the wire on the left end, since this tension is entirely horizontal (entirely in the \(x\)-direction,)\((-71.6)\; {\rm N}\) for the weight, which points downwards, andNot yet found for the tension from the other wire.Since forces on the object to be balanced, forces need to be balanced in each component. For forces in the \(y\)-component to be balanced, forces in the vertical direction need to add up to \(0\; {\rm N}\):
\(0\; {\rm N} + (-71.6)\; {\rm N} + (\text{$y$-component of tension on the right}) = 0\; {\rm N}\).
Hence, the \(y\)-component of the tension from the wire on the right end would be \(71.6\; {\rm N}\).
i need this ASAP please!!!
What is the significance of the discovery of exoplanets?
a. they may possibly be inhabited or harbor life.
b. they can provide natural resources for the future.
c. they help our understanding of the formation of planetary bodies.
d. they help calibrate gps satellites.
e. they help understand the nature of the expansion of the universe.
Answers
Answer:
C. the help our understanding of the formation of planetary bodies.
Explanation:
this is the answer of PLATO
Difference between Weightlessness in space and weightlessness during free fall.
Answers
Weightlessness in space and weightlessness during free fall may appear similar in terms of the sensation experienced, but they occur under different circumstances and have distinct underlying causes. Here are the key differences between the two:
1.Environment:
Space: Weightlessness in space refers to the state experienced by astronauts in orbit around the Earth or in deep space. They are in a microgravity environment, far away from any significant gravitational forces.
Free fall: Weightlessness during free fall occurs when an object is falling under the influence of gravity, experiencing zero-gravity conditions momentarily. This typically happens when an object is in a state of free fall, such as during skydiving or in an airplane during a parabolic flight.
2.Gravitational Forces:
Space: In space, weightlessness is the result of being in constant free fall around the Earth. Although gravity is still present, the gravitational forces are counterbalanced by the centrifugal force created by the orbiting motion. This results in a continuous state of free fall, giving the sensation of weightlessness.
Free fall: Weightlessness during free fall occurs due to the absence of support forces countering the force of gravity. When an object is in free fall, there are no contact forces pushing against it, leading to a sense of weightlessness.
3.Duration:
Space: Weightlessness in space can last for an extended period, as long as the object or person remains in orbit or deep space. Astronauts aboard the International Space Station (ISS), for example, experience weightlessness for months at a time.
Free fall: Weightlessness during free fall is relatively brief and temporary. It occurs during the duration of the free fall, which can last for a few seconds to a couple of minutes, depending on the specific circumstances.
4.Context:
Space: Weightlessness in space is a constant state for astronauts. They adapt to this environment and conduct various experiments, work on scientific research, and live aboard the spacecraft for extended periods.
Free fall: Weightlessness during free fall is typically experienced as part of a recreational activity or a specific scientific experiment. It is a brief moment of weightlessness within the context of a larger activity, such as skydiving, parabolic flights, or drop towers.
While both weightlessness in space and weightlessness during free fall share the absence of apparent gravity and the sensation of floating, they occur in different environments, are caused by different factors, and have varying durations and contexts.
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In a mass spectrometer chlorine ions of mass 35u and charge +5e are emitted from a source and accelerated through a potential difference of 250 kV. They then enter a region with a magnetic field that is perpendicular to their original direction of motion. The chlorine ions exit the spectrometer after being bent along a path with radius of curvature 3.5 m. What is the speed of the chlorine ions as they enter the magnetic field region?
(u = 1.66 × 10^(–27) kg, e = 1.6 × 10^(–19) C)
2.6 × 106 m/s
1.2 × 106 m/s
1.5 × 107 m/s
Answers
Answer:
v=26.23*105 m/s
or 2.6 × 106 m/s
Explanation:
Force generated by magnetic field will only provide centripetal acceleration thus the entering speed will be same as the exit speed
so,
.5mv2=eV potential differnce*charge= kinetic energy
.5*35*1.66*10-27*v2= 1.6*10-19*5*250000
v2=68.84*1011
v=26.23*105 m/s
or 2.6 × 106 m/s
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.
Answers
Answer:
Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.
Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.
Example of conductor is copper
Example of insulator is plastic
Researchers studying the possible effects of “heading” a soccer ball--hitting it with the head--use a force plate to measure the interaction force between a ball and a hard surface. (Figure 1) shows smoothed data of the force when a 430 g
soccer ball is fired horizontally at the force plate with a speed of 15 m/s
With what speed does the ball rebound from the plate?
Answers
The speed of the ball rebounding from the plate is approximately 13.2 m/s.
According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.
The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.
The speed of the ball rebounding can be calculated using the formula:
(1/2)mv²= (1/2)mv_0²
where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).
Solving for v, we get:
v = sqrt(v_0² - (2F/m))
where F is the maximum force exerted on the force plate (1900 N).
Plugging in the values, we get:
v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s
Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.
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The work-energy theorem states that the change in the kinetic energy of an object is equal to what?
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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.
Mathematically, it can be expressed as;
ΔKE = W
Where; ΔKE represents the change in kinetic energy of the object,
W represents the net work done on the object.
This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.
This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.
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