about 97 percent of water is salty. People can't drink salt water. Using what you learned about the water cycle, explain which processes could be used to design a device for turning salt water into freshwater ​

Answer:

Earthquakes and Volcanos?

Explanation:

I'm a little unsure about my answer, however, I do have some insight backing my answer. Earthquakes happen when the plate tectonics shift into each other, causing them to collide. Then for volcanos, the plate tectonics shift from convection current and molten rock from the mantle come to the surface.

Answer:

HC₂H₃O₂ + 2O₂ —> 2CO₂ + 2H₂O

The coefficients are: 1, 2, 2, 2

Explanation:

From the question given above, the following data were obtained:

HC₂H₃O₂ + O₂ —> CO₂ + H₂O

We can balance the above equation as follow:

HC₂H₃O₂ + O₂ —> CO₂ + H₂O

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

HC₂H₃O₂ + O₂ —> CO₂ + 2H₂O

There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 2 before CO₂ as shown below:

HC₂H₃O₂ + O₂ —> 2CO₂ + 2H₂O

There are 4 atoms of O on the left side and a total of 6 atoms on the right side. It can be balance by writing 2 before O₂ as shown below:

HC₂H₃O₂ + 2O₂ —> 2CO₂ + 2H₂O

Now the equation is balanced.

The coefficients are: 1, 2, 2, 2

We study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry.

The study of the makeup, properties, and responses of organic compounds including organic materials, or matter in any of its many forms that contains carbon atoms, is the subject of the branch of science known as organic chemistry. Their structural formula is determined by study of structure.

We will study the reactions that chemists utilise to create bizarre carbon-based structures in organic chemistry, in addition to the analytical techniques used to characterise them. We'll also consider the molecular reaction mechanisms that are driving those reactions.

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The minimum concentration of fluoride ions needed is 2.726 x 10⁻⁴ M.

To find the minimum concentration of fluoride ions needed to precipitate CaF₂, we'll use the solubility product constant (Ksp) and the calcium ion concentration.

Ksp = [Ca²⁺][F⁻]²

Given: [Ca²⁺] = 5.25 x 10⁻³ M, Ksp = 3.9 x 10⁻¹¹

3.9 x 10⁻¹¹ = (5.25 x 10⁻³)[F⁻]²

Solve for [F⁻]:

[F⁻]² = (3.9 x 10⁻¹¹) / (5.25 x 10⁻³)

[F⁻]² = 7.4286 x 10⁻⁹

[F⁻] = 2.726 x 10⁻⁴ M

The minimum concentration of fluoride ions needed is 2.726 x 10⁻⁴ M.

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Answer:

Equation 2, because K being more reactive, exchanges position with Pb in PbNO3.

Explanation:

Hello there!

In this case, according to the given reactions, it is possible to realize that according to the reactivity series, since K is is group 1A of alkali metals, we infer it is by far more reactive than magnesium, for that reason last two choices can be easily discarded. Now, considering equation 2, it would be necessary to complete it to figure out the correct option:

\(Pb(NO_3)_2 + KI \rightarrow PbI_2+KNO_3\)

Whereas it can be seen that potassium exchanges position with Pb according to the double displacement reaction; therefore, the correct answer is "Equation 2, because K being more reactive, exchanges position with Pb in PbNO3".

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Answer:

Rubidium Cyanide and Water

Explanation:

First, we need to determine the mass of water in the pool:

mass = density x volume

density of water = 1000 kg/m³

volume = length x width x depth

volume = 10.0 m x 4.0 m x 3.0 m = 120 m³

mass = 1000 kg/m³ x 120 m³ = 120000 kg

Next, we need to calculate the heat required to raise the temperature of the water:

q = m x c x ΔT

where q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.

c = 4.18 J/g°C (specific heat of water)

ΔT = 27.3°C - 20.2°C = 7.1°C

m = 120000 kg

q = 120000 kg x 4.18 J/g°C x 7.1°C = 35792400 J

Next, we need to convert the energy required to burn methane to heat energy:

-891 kJ/mol x (1 mol CH4/160 g CH4) x (1000 g/1 kg) = -5.569 kJ/g

We can now calculate the amount of methane needed:

energy = -5.569 kJ/g x mass CH4

mass CH4 = energy / (-5.569 kJ/g)

mass CH4 = 35792400 J / (-5569 J/g) = -6431.6 g

At STP, 1 mole of any gas occupies 22.4 L of volume. We can use this to convert the mass of methane to volume at STP:

1 mol CH4 = 16 g CH4

-6431.6 g CH4 x (1 mol CH4/16 g CH4) x (22.4 L/1 mol CH4) = -9074.4 L

Since we cannot have a negative volume, we can take the absolute value of the result:

|9074.4 L| = 9074 L

Therefore, approximately 9074 liters of methane gas at STP must be burned to raise the temperature of the water in the pool from 20.2°C to 27.3°C.

Answer:

transfer

Explanation:

An ionic bond forms when atoms transfer electrons.

The enthalpy or heat content of a system can be defined as the sum of the internal energy and the pressure volume energy of the system. It is denoted by H. The energy change of mixture is  47 kJ.

The transference of energy may take place in the form of work if the system and surroundings have different pressures. According to international conventions, work done on the system is positive and work done by the system is negative.

The enthalpy change is:

ΔH = ΔU + PΔV

190 = ΔU + 143

ΔU = 47 kJ

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With 3 covalent connections to h and 1 lone pair, nitrogen has formed its whole octet, as seen by the Lewis dot picture.

How is nitrate used? Ammonia generated by industries is used as fertilizer in agriculture to the tune of 80%. Ammonia is also used to create polymers, explosives, textiles, pesticides, dyes, and other compounds in addition to its various applications. Additionally, it is utilized to clean water sources.

It is also known as ammonia, aqueous ammonia, or ammonia solution when it is in this form. The majority of ammonia in water converts to ammonium ions, or nH4+. For plant, animal, and human life to exist, ammonia is a necessary component. It is a source that can be found in the air, soil, and water.

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Answer:

14.9 mol

Explanation:

To find the number of moles in a given mass of a sample of sodium chloride (NaCl), we can multiply the number of grams in the sample by the molar mass of sodium chloride, which is 58.44 g/mol.

871 g × (1 mol / 58.44 g)

= 871/58.44 mol

≈ 14.9 mol

Note that we rounded to 3 significant figures in the final answer because that is how many significant figures were given in the mass measurement of the sodium chloride sample.

Answer:

arthropod

Explanation:

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Answer:

acidic

Explanation:

Answer:

Not sure sorry :(

Explanation:

Barium chloride turned from sparkly white into dull white during the heating process.

An inorganic substance with the formula BaCl2 is barium chloride. It is among the most popular barium salts that dissolve in water. Like the majority of some of the other water-soluble barium salts, is also white, extremely hazardous, and gives flames a yellow-green tint.

Among the most common barium salts is barium chloride. Bacl2 is hygroscopic and soluble in water. Deep hypokalemia, generalized muscle weakness, and eventually paralysis of the limbs and breathing muscles can occur within 1 to 4 hours of consumption.

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Answer:

C because they are the same

Answer:

\( \small \sf \: 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O \\ \small \sf \: 2 KNO_3 \rightarrow 2 KNO_2 + O_2 \\ \small \sf \: Ca + 2 H_2O \rightarrow \: Ca(OH)_2 + H_2 \\ \small \sf \: 2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2 \\ \small \sf \: 2 CO + O_2 \rightarrow \: 2 CO_2\)

Explanation:

A) When four moles of ammonia reacts with five moles of O2 gas, four moles of Nitrogen mono oxide liberates along with six moles of water.

\( \sf \: 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O\)

B) When two moles pottasium nitrate (KNO3) is heated it dissociates into two moles of potassium nitrite liberates along with one mole of O2 gas.

\( \sf \: 2 KNO_3 \rightarrow 2 KNO_2 + O_2\)

C) When one mole of calcium reacts with two moles water, one mole of calcium hydroxide obtained & one of hydrogen gas released.

\( \sf \: Ca + 2 H_2O \rightarrow \: Ca(OH)_2 + H_2\)

D) When two mole of Sodium bicarbonate (NaHCO3) is heated it gradually decomposes to one mole of Sodium carbonate (Na2CO3) obtained along with one mole of each Water & Carbon dioxide.

\( \sf \: 2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2\)

E) The question needs to corrected,

When two moles of carbon monoxide reacts with one mole oxygen two moles of carbon dioxide is released.

\( \sf \: 2 CO + O_2 \rightarrow \: 2 CO_2\)

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Answer:

x=51.66

Explanation:

1 ml = 1 gram

(mass) (Δt) (Cp) = (mass) (Δt) (Cp)

Substituting values into the above, we then have:

(25)(25-x)(4.184)=(50)(x-65)(4.18)

Solve for x

x= 51.6667

The final temperature is "51.67°C".

According to the question,

At 65°C,

= \(\frac{50}{50+25}\)

= \(\frac{50}{75}\)

= \(0.66667\)

At 25°C,

= \(\frac{25}{50+25}\)

= \(\frac{25}{75}\)

= \(0.33333\)

By multiplying the volume fractions, we get

→ \(65^{\circ} C\times 0.66667\) = \(43.3334^{\circ}C\)

→ \(25^{\circ} C\times 0.33333\) = \(8.3333325^{\circ} C\)

hence,

The final temperature will be:

= \(43.33334+8.333325\)

= \(51.6666^{\circ}C\)

or,

= \(51.67^{\circ} C\)

Thus the above answer is right.

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Fe(OH)2 doesn't react with water. Fe(OH)2 is said to have a solubility constant that ranges from 8x10-16 to 2x10-15.

Fe(OH)2 is significantly more soluble than Fe(OH)3, which has a solubility constant in the range of 10-38.

Fe(OH)2 is incredibly insoluble when compared to NaCl (Ksp of roughly 4x101!!! ).

Consequently, perspective is key.

The aqueous solution numbers are in the morning. In the early history of the earth (the "oxygen catastrophe"), the numbers for Fe(II) and Fe(III) were extremely important.

They shouldn't be directly compared because the three solubility products have different dimensions (officially, Fe(OH)3 splits into four ions, Fe(OH)2 splits into three, and NaCl splits into two). However, because of how far apart they are, the morning conclusions remain valid.

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Explanation:

We have to find the temperature change of a 198.0 g sample of hot water that released 3072 J to a pipe. So we know that:

Q = -3072 J (negative because the water is releasing the heat)

m = 198.0 g

Cp = 4.184 J/(g°C)

The temperature change is our unknown, so we can apply this formula and solve it for ΔT:

Q = m * Cp * ΔT

ΔT = Q/(m * Cp)

ΔT = -3072 J/(198.0 g * 4.184 J/(g°C))

ΔT = - 3.708 °C

Answer: The temperature change of the water will be -3.708 °C

ANSWER:

CATION

is ur answer

Explanation:

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Explanation:

H=mc×∆©

9.86=m×0.902×(30.5-23.2)

m=1.5

Explanation:

The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. The formula for calculating the heat absorbed or released by a substance is `q = mcΔT`, where `q` is the heat absorbed or released, `m` is the mass of the substance, `c` is the specific heat of the substance, and `ΔT` is the change in temperature.

In this case, we can use this formula to solve for the mass of the aluminum sample. We know that `q = 9.86 J`, `c = 0.902 J/g°C`, and `ΔT = 30.5°C - 23.2°C = 7.3°C`. Plugging these values into the formula, we get:

`9.86 J = m * 0.902 J/g°C * 7.3°C`

Solving for `m`, we find that the mass of the aluminum sample is approximately `1.5 g`, rounded to 2 significant figures.

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Answer:

i don't think you can, but if you do know let me know

Based on the given data, the relationship between rate and concentration is exponential.

A proposed rate law for the reaction based on the given data is:

Collision theory suggests that the rate of a chemical reaction is proportional to the frequency and energy of collisions between the reactant molecules.

As the concentration of iodate ions decreases, the frequency of collisions between reactant molecules decreases, which leads to a decrease in the rate of the reaction.

At higher temperatures, the kinetic energy of the reactant molecules increases, which increases the frequency and energy of collisions between reactant molecules.

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The relationship between tissues and organs is one of interdependence. Tissues work together to form organs, and organs rely on the different types of tissues to function properly.

The relationship between tissues and organs is an important one, and it is particularly exemplified in the case of the heart. The heart is an organ, and like all organs, it is made up of various types of tissues that work together to allow it to function properly. In the case of the heart, these tissues include muscle tissue, connective tissue, epithelial tissue, and nervous tissue.
Muscle tissue is particularly important in the heart, as it contracts to pump blood to the body. Without muscle tissue, the heart would not be able to perform its vital function. Connective and epithelial tissues are also important in the heart, as they hold the muscle cells together and in place in the chest. Without these tissues, the muscle cells would not be able to work together efficiently, and the heart would not be able to function properly.
Finally, nervous tissue plays a crucial role in the heart, as it coordinates how fast and hard the muscle cells contract. This coordination is essential for the heart to function properly and maintain the circulation of blood throughout the body.  In the case of the heart, the different types of tissues work together seamlessly to allow the heart to perform its vital function of pumping blood throughout the body.

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Answer: A

Explanation:

I got C wrong

Answer:

2, 19, 12 and 14 are the coefficients.

Answer: Since k2 corresponds to 64 hours, the time for the milk to sour at 40 C is 64 h / 9.38 = 6.8 hours.

Explanation:

At temperature T1, the Arrhenius Equation is:

k1 = Ae^(-Ea/RT1).

An equivalent equation can be written at T2:

k2 = Ae^(-Ea/RT2).

If these equations are divided, then A cancels:

k1/k2 = e^(-Ea/RT1)/e^(-Ea/RT2)

Taking the natural log:

ln(k1/k2) = (Ea/RT2)-(Ea/RT1);

or:

ln(k1/k2) = (Ea/R)(1/T2 - 1/T1)

We can infer from the question that the milk sours 3 times as fast at the higher temperature (let's call it T1), so we can arbitrarily call k2 = 1 and k1 = 3.

a) Substitute:

ln(3) =  (Ea/R)(1/276.15 K - 1/293.15 K).

We get Ea/R = 5231.6. Multiply this by whatever value of R you choose to get Ea in your favorite energy unit. Remember the sig figs.

b) Again, let's let the lower temperature = T2, since we have defined k2 = 1:

ln(k1) = (5231.6)(1/276.15 K - 1/313.15);

ln(k1) = 2.24, so k1 = 9.38.

Since k2 corresponds to 64 hours, the time for the milk to sour at 40 C is 64 h / 9.38 = 6.8 hours.

Answer:

18.066 x 10^23 atoms of Au

Explanation:

ONE mole = 6.022 x 10^23  particles

3   x   6.022 x 10^23

0.49 M is the molarity of the 4.9% \(H_{2}SO_{4}\) solution.

To find the molarity of a solution, we need to calculate the number of moles of the solute (\(H_{2}SO_{4}\)) present in a given volume of the solution. Here's how to determine the molarity of a 4.9% \(H_{2}SO_{4}\)solution with a density of 0.98 g/ml:

Determine the mass of the solute: The 4.9% concentration implies that 4.9 g of \(H_{2}SO_{4}\) is present in 100 g of the solution.

Calculate the volume of the solution: Divide the mass of the solution by its density. In this case, 100 g / 0.98 g/ml = 102.04 ml.

Convert the volume of the solution to liters: Divide the volume by 1000 to convert from milliliters to liters. 102.04 ml / 1000 = 0.10204 L.

Calculate the number of moles: Multiply the mass of the solute by its molar mass. The molar mass of \(H_{2}SO_{4}\) is 98.09 g/mol. Therefore, 4.9 g / 98.09 g/mol = 0.0499 mol.

Calculate the molarity: Divide the number of moles by the volume of the solution in liters. 0.0499 mol / 0.10204 L ≈ 0.49 M.

Thus, the molarity of the 4.9% \(H_{2}SO_{4}\) solution is approximately 0.49 M.

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This technique has been used to identify the presence of gases such as oxygen, methane, and carbon dioxide in the atmospheres of exoplanets.  

i) To estimate the frequency of the violet (leftmost) emission, we can use the equation v = c/λ, where v is frequency, c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the emission in meters. The wavelength of the violet emission is 400 nm or 400 x 10^-9 m, so the frequency can be calculated as v = (3.00 x 10^8 m/s) / (400 x 10^-9 m) = 7.50 x 10^14 Hz.

ii) To estimate the energy of the violet emission, we can use the equation E = hv, where E is energy, h is Planck's constant (6.63 x 10^-34 Js), and v is frequency in Hz. Substituting the frequency calculated in part (i), we get E = (6.63 x 10^-34 Js) x (7.50 x 10^14 Hz) = 4.97 x 10^-19 J.

b. The spectral lines are produced by the electrons within the atoms of this element, which can absorb or emit specific amounts of energy to move between different energy levels. These energy transitions result in the emission or absorption of photons with specific wavelengths and frequencies, giving rise to the observed emission spectrum.

c. The violet emission line represents the photon with the most energy since it has the shortest wavelength (400 nm) and highest frequency (7.50 x 10^14 Hz) among the lines shown. This highest energy does not necessarily represent the energy of the valence electrons, but rather corresponds to the specific energy transitions occurring within the atoms of the element.

d. Emission spectra can be used to determine the gases present in the atmosphere of a far-away planet by analyzing the specific wavelengths of the emitted or absorbed light from the planet. Each gas has a unique emission or absorption spectrum, allowing scientists to identify the gases present in the planet's atmosphere.

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