. Air entrainment is a process of entrapping tiny air bubbles in concrete mix in order to increase the durability of the hardened concrete in freeze-thaw climates. After 35 days, the breaking stress [in psi] was measured for concrete samples with and without air entrainment. Based on the data, does the air entrainment process increase the breaking stress of the concrete

The lowest-cost form of transporting goods very long distances by: B: Train

There are different modes of transportation such as:

Road Transportation

Maritime Transportation

Air transportation

Rail Transportation

Pipeline transportation

Now, among the listed modes of transportation above, the slowest is usually rail when transporting goods over long distances.

This is because In modern practice, rail is used more exclusively for the largest and heaviest payloads (bulk cargo) traveling across land. The vast majority of railway infrastructure connects highly populated areas with large unpopulated strips of land between them making rail ideal for long-distance and cross country hauls.

Read more about Mode of Transportation at: https://brainly.com/question/25935364

#SPJ1

Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

Learn more about Efficiency here:

https://brainly.com/question/13764250

#SPJ4

A project team may choose to prepare a low-fidelity version of a website design using sticky notes for several reasons:

Sticky notes allow for quick and easy changes. Since they are easy to move around and modify, the team can iterate on the design quickly, making adjustments and improvements without investing significant time or resources. This promotes an iterative design process, enabling the team to refine and enhance the design rapidly.Collaboration and Communication: Sticky notes facilitate collaboration and communication among team members. They can be easily placed on a whiteboard or a wall, allowing everyone to visualize and discuss the design together. Team members can share their ideas, suggestions, and feedback by directly manipulating the sticky notes, fostering effective communication and collaboration within the team.Low Cost and Accessibility: Sticky notes are affordable and readily available, making them a cost-effective option for creating prototypes. Compared to digital design tools or high-fidelity prototypes, sticky notes are inexpensive and accessible to all team members, regardless of their technical expertise. This inclusivity encourages participation from different stakeholders and promotes a diverse range of perspectives during the design process.Focus on Conceptual Design: Low-fidelity designs with sticky notes primarily focus on the conceptual aspects of the website, such as layout, content organization, and user flow. By avoiding intricate details or visual aesthetics, the team can concentrate on the fundamental structure and functionality of the design. This allows for early validation and testing of design concepts before investing significant time and resources in higher-fidelity prototypes.Emphasis on User Experience: Sticky notes enable the team to simulate user interactions and test the usability of the design. By physically moving and rearranging the sticky notes, the team can simulate user flows and assess the user experience. This hands-on approach allows for early identification of potential usability issues, leading to design improvements and a better user experience.

To learn more about fidelity click on the link below:

brainly.com/question/26959627

#SPJ11

Answer:

None of the above cause thats what i put

Answer:

u do the same thing as part B but only add 100 k, I think, cuz I'm still in middle school but I mean if u see it asks u to do the same thing as B but C says that instead, u do it at half pressure and 100 k is higher temp so what its asking is to repeat b but the twist is u do it at half pressure and 100 k is the higher temp

hope this helps :)  

To determine the normal and shearing stresses after the element has been rotated, we need additional information about the state of stress and the orientation of the element before the rotation.

Without this information, it is not possible to provide specific calculations for the normal and shearing stresses.
However, I can explain the general concept behind the transformation of stresses due to rotation. When an element is rotated, the stresses acting on the element will change according to the rotation angle and the original stress state. The transformation of stresses can be achieved using transformation equations such as Mohr's circle or transformation matrices.
Mohr's circle is a graphical method that can be used to determine the transformed stresses. By plotting the original stress state on a Mohr's circle and then rotating the circle by the given angle (clockwise or counterclockwise), the new stresses can be obtained by reading the coordinates on the transformed circle.
Alternatively, transformation matrices can be used for mathematical calculations. The transformation matrix relates the stresses before and after rotation. By multiplying the original stress matrix with the appropriate transformation matrix, the transformed stress matrix can be obtained.
In summary, to determine the normal and shearing stresses after rotation, we need the initial stress state and the angle of rotation. With this information, the transformation equations, such as Mohr's circle or transformation matrices, can be used to calculate the new stresses.

To learn more about shearing stresses
https://brainly.com/question/20630976
#SPJ11

The specific gravity of the oil in the closed tank with Bourdon-tube gages tapped into it depends on the type of oil being used. Generally speaking, the specific gravity of a petroleum-based oil is between 0.85 and 0.95.

The pressure reading on Gage C will also depend on the type of oil being used and the pressure inside the tank.

For example, if the tank is filled with water, then the pressure reading on Gage C will be the same as the atmospheric pressure.

Additionally, any changes in the atmospheric pressure can also affect the pressure reading on Gage C. To ensure accurate readings, it is important to monitor the pressure in the tank and adjust the pressure reading on Gage C accordingly.

Learn more about pressure reading on pressure gauge c:

https://brainly.com/question/12990106

#SPJ4

Fermat's theorem can be used to find a number x between 0 and 28 that satisfies the congruence x^85 ≡ 6 (mod 29). By applying the theorem, we can simplify the calculation and determine the value of x without resorting to brute-force searching.

Fermat's theorem states that if p is a prime number and a is an integer not divisible by p, then a^(p-1) ≡ 1 (mod p). In this case, the prime number is 29. We can rewrite the congruence x^85 ≡ 6 (mod 29) as x^(283+1) ≡ 6 (mod 29), which implies that x^(283) * x ≡ 6 (mod 29).

Using Fermat's theorem, we know that x^(28*3) ≡ 1 (mod 29), since 29 is a prime number. Therefore, the congruence simplifies to 1 * x ≡ 6 (mod 29), which gives us x ≡ 6 (mod 29).

To find the value of x within the range of 0 to 28, we can observe that 6 + 29 = 35 is a multiple of 29. Thus, x = 35 satisfies the congruence. However, since we are looking for a value between 0 and 28, we subtract multiples of 29 from 35 until we find a value within the desired range. In this case, 35 - 29 = 6, so x = 6 is the solution that satisfies x^85 ≡ 6 (mod 29) within the given constraints.

Learn more about  brute-force searching here :

https://brainly.com/question/32382588

#SPJ11

The process comprises breaking the truss into individual pieces and analyzing each piece as a separate rigid body.

To learn more about the truss's sectional analysis refer to:

https://brainly.com/question/20556049

#SPJ4

Answer:

Area of the piston = 1.143 * 10^-3 m^2

Explanation:

Here, we are tasked with calculating the area of the piston.

Mathematically, the area of the piston =

Piston force/ cylinder pressure

From the question,

Piston force = mg where m is the mass of the piston = 35 kg and g is the acceleration due to gravity = 9.8 m/s^2

Thus, piston force = 35 * 9.8 = 343 N

Now the pressure gauge reads 300 KPa and 1KPa = 300 * 10^3 Pa = 300000 Pa

Thus, the area of the piston = 343/300000 =

0.001143333333 m^2 which is simply 1.143 * 10^-3 m^2

Analyze non -structured data, manage large datasets across platforms, and construct queries from web app data are all included.

NoSQL databases, also known as "not only SQL" databases, store data in a different way than relational tables. The data model of a NoSQL database determines the types of these databases. Document, key-value, wide-column, and graph are the most common types. They have flexible schemas and are easy to scale with a lot of data and a lot of users.

Any non-relational database is typically referred to as a "NoSQL database" by those who use the term. Some people interpret the term "NoSQL" to mean "non SQL," while others interpret it to mean "not only SQL." NoSQL databases, in any case, are databases that store data in a format other than relational tables, as most agree.

To learn more about NoSQL visit :

https://brainly.com/question/29891022

#SPJ4

According to Stanford psychologist Carol Dweck, people with a growth mindset develop their abilities through dedication, effort, and hard work.

Dweck's research on mindset theory distinguishes between two mindsets: a fixed mindset and a growth mindset. A fixed mindset is the belief that intelligence, talents, and abilities are fixed traits that cannot be changed significantly. In contrast, a growth mindset is the belief that abilities can be developed and improved through effort, perseverance, and learning.Individuals with a growth mindset embrace challenges, persist in the face of setbacks, and see failures as opportunities for learning and growth. They believe that intelligence and abilities can be nurtured and developed through hard work and dedication.

learn more about psychologist here :

https://brainly.com/question/27579365

#SPJ11

Answer:

uehgeg7djw7heidiisosowiuisiejei2k

There are a lot of ways employees uses in controlling exposure routes.  But when risk assessment is not be performed is not a part of the control methods.

The ways to control workplace hazards are known to be means taken to ensure safety in the workplace.

The examples are:

Learn more about exposure routes from

https://brainly.com/question/25799066

Answer:

The first one.

Explanation:

The first one without a doubt

this is perfect.........

Pressure in compressed air tank reads 43.2 pounds per square inch (lb/in)

Now, convert pressure to atmosphere (atm)

Recall that 1 atm = 14.695964 lb/in

so, let Z = 43.2 lb/in

To get the value of Z, cross multiply

43.2 lb/in x 1 atm = 14.695964 lb/in x Z

43.2 lb/in atm = 14.695964 lb/in x Z

Z = 43.2 lb/in atm / 14.695964 lb/in

Z = 2.94 atm

The pressure of the compressed air tank reads 2.94 atmosphere.The relation between the volume, the pressure, and the temperature is PV = mRT. Then the amount of air added to the tank is 1.2062 kg.

It is a branch of science that deals with heat and work transfer. A rigid tank contains 20 lbm of air at 20 psi and 70°F. More air is added to the tank until the pressure and temperature rise to 23.5 psi and 90°F, respectively.

Therefore, Pressure in compressed air tank reads 43.2 pounds per square inch (lb/in)

Now, convert pressure to atmosphere (atm)

Recall that 1 atm = 14.695964 lb/in

so, let Z = 43.2 lb/in

To get the value of Z, cross multiply

43.2 lb/in x 1 atm = 14.695964 lb/in x Z

43.2 lb/in atm = 14.695964 lb/in x Z

Z = 43.2 lb/in atm / 14.695964 lb/in

Z = 2.94 atm

Learn more about atmosphere on:

brainly.com/question/26767532

#SPJ1

Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

The acceleration at points A, B and C are respectively; 960 mm²/s, 1600 mm²/s and 600 mm²/s

The drum rolls without sliding and as such its' instantaneous center will lie at B. Thus;

V_d = V_c = 160 mm/s

Also, a_d = a_c = 600 mm²/s

Now, formula for velocity at A is;

V_a = r_ab * ω

where ω = 160/(100 - 60)

ω = 4 rad/s

V_a = 60 * 4

V_a = 240 mm/s

Acceleration at A = V_a²/r_ab

Acceleration at A = 240²/60 = 960 mm²/s

Now, V_b = 100 * 4 = 400 mm/s

Acceleration at B = 400²/100 = 1600 mm²/s

Read more about Acceleration at; https://brainly.com/question/14344386

Answer:

Trim heel and transducer separations are two potential errors that can affect the accuracy of a ship's draft and trim readings.

Trim heel refers to the angle of inclination of a ship in the water, which can affect the readings taken by the ship's sensors. If the ship is not perfectly level in the water, the sensors may not provide accurate measurements of the draft or the amount of cargo on board. This can result in incorrect calculations of the ship's stability, which can lead to dangerous situations.

Transducer separation is another potential source of error that can affect the accuracy of a ship's draft readings. Transducers are sensors that are mounted on the hull of a ship to measure the water level and provide information on the ship's draft. If these sensors are not properly calibrated or if they are separated from the hull, they may provide inaccurate readings, which can lead to errors in the ship's stability calculations.

In summary, trim heel and transducer separations can result in inaccurate readings of a ship's draft and cargo load, which can affect the ship's stability and safety. It is important for ship operators to regularly calibrate and maintain their sensors to minimize the risk of errors due to trim heel and transducer separations.

Hope this helps!

The question is missing some important details but I will guide you on how to solve for normal stress

The point in the beam has got a normal stress (σ) which can be calculated by taking the ratio of the bending moment (M) and section modulus (S):

σ = M/S

To ascertain the section modulus of a rectangular cross-section, the following equation is employed:

S = (b * h^2) / 6

In answer to the supplicated inquiry, within this example, b stands for the width of the beam (6 in), and h represents the height of the beam (8 in). Hence, by accounting for these dimensions, S can be calculated.

The effect of a uniformly distributed load (q) on an elicited bending moment (M) can be determined through utilization of the pertinent beam equations, that can be derived once the location of point C, as well as the length of the demonstrated beam is known.

Having notably acknowledged M and S, it is possible to estimate the normal stress (σ) at point C.

Read more on normal stress here https://brainly.com/question/30576259

#SPJ4

los trabajadores no pueden trabajar directamente debajo de cargas suspendidas sin ninguna medida de precaución. El trabajo debajo de las cargas suspendidas es un trabajo peligroso y puede ser mortal si no se toman medidas de seguridad.

El peso de una carga suspendida puede ser demasiado grande para ser sostenido por el equipo de izaje y puede caerse y causar lesiones graves o incluso la muerte. Por lo tanto, es importante que los trabajadores estén capacitados y se les enseñe cómo trabajar de manera segura en estas situaciones.Los empleados deben estar informados y ser conscientes de los riesgos asociados con el trabajo debajo de las cargas suspendidas.

Si hay alguna duda acerca de la seguridad del equipo o la capacidad del equipo de izaje, el trabajo debe ser detenido hasta que se realice una inspección y se asegure la seguridad. Además, se deben seguir los procedimientos adecuados para levantar y mover las cargas, y se deben usar los equipos de protección personal necesarios.

To know more about directamente visit:

https://brainly.com/question/22409014

#SPJ11

The force acting at the point (x, y) can be determined by finding the gradient of the potential energy function U = 3x^5y - 4x. The force vector that acts at the point (x, y) is given by F = (15x^4y - 4) * i + (3x^5) * j.

To find the force vector at the point (x, y) based on the given potential energy function U = 3x^5y - 4x, we need to calculate the gradient of the potential energy function. The gradient is a vector that points in the direction of the steepest increase of a scalar function and has components equal to the partial derivatives of the function with respect to each variable. In this case, the potential energy function U has two variables, x and y. Therefore, the force vector F can be obtained by taking the partial derivatives of U with respect to x and y and combining them into a vector. Let's calculate the force vector F:

First, find the partial derivative of U with respect to x:

∂U/∂x = 15x^4y - 4

Next, find the partial derivative of U with respect to y:

∂U/∂y = 3x^5

Now, construct the force vector F using these partial derivatives:

F = (∂U/∂x) * i + (∂U/∂y) * j

where i and j are the unit vectors along the x and y directions, respectively.

Substituting the partial derivatives, the force vector F is:

F = (15x^4y - 4) * i + (3x^5) * j

Learn more about derivatives here:

https://brainly.com/question/25324584

#SPJ11

Answer:1. Driving under the influence of any drug that makes you drive unsafely is:

a. Permitted if it is prescribed by a doctor

b. Against the law

c. Permitted if it is a diet pill or cold medicine

2. Which fires can you put out with water:

a. Tire fires

b. Gasoline fires

c. Electrical fires

3. How far should a driver look ahead of the vehicle while driving:

a. 9-12 seconds

b. 12-15 seconds

c. 18-21 seconds

4. To prevent shifting, there should be at least one tie-down for ever ____feet of cargo: a. 10

b. 15 c. 18

5. Which of these statements about downshifting is true:

a. When you downshift for a curve, you should do so before you enter the curve

b. When you downshift for a hill, you should do so after you start down the hill

c. When you downshift for a curve, you should do so after you enter the curve

6. How do you test hydraulic brakes for a leak:

a. Move the vehicle slowly and see if it stops when the brake is applied

b. With the vehicle stopped, pump the pedal three time, apply pressure then hold

For five seconds and see it the pedal moves.

c. Step on the brake pedal and accelerator at the same time and see if the vehicle moves

7. For an average driver, driving 55 MPH on dry pavement, it will take about _____ to bring The vehicle to a stop:

a. Twice the length of the vehicle

b. Half the length of a football field

c. The length of a football field

8. You are driving a vehicle with a light load, traffic is moving at 35 MPH in a 55 MPH zone. The safest speed for your vehicle in this situation is most likely:

a. 30 MPH

b. 35 MPH

c. 40 MPH

9. Which of these is a good rule to follow when driving at night:

a. Keep your speed slow enough to stop within the range of your headlights

b. Look directly at oncoming headlights

c. Keep your instrument lights bright

10. A moving vehicle ahead of you has a red triangle with an orange center on the rear. What does this mean?

a. The vehicle is hauling hazardous materials

b. It may be a slow-moving vehicle

c. It may be oversized

11. You wish to turn right form a two lane two way street to make the turn. Which of these Drawings show how the turn should be made.

12. You are driving a heavy vehicle and must exit a highway using an offramp that curves downhill:

a. Use the posted speed limit for the offramp

b. Slow down to a safe speed before the turn

c. Wait until you are in the turn before downshifting

13. Which of these statements about using mirrors is true:

a. You should look at a mirror for several seconds at a time

b. There are “blind spots” that your mirror cannot show you

c. A lane change requires you to look at the mirrors twice

14. You must park on the side of a level, straight, two-lane road. Where should you place the three reflective triangles?

a. one within 10 feet of the rear of the vehicle, one about 100 feet to the rear and one about 200 feet to the rear.

b. One with 10 feet of the rear of the vehicle, one about 100 feet to the rear and one about 100 feet from the front of the vehicle

c. One about 50 feet from the rear of the vehicle, one about 100 feet to the rear and one about 100 feet from the front of the vehicle

15. Your vehicle is in a traffic emergency and may collide with another vehicle if you do not take action. Which of these is a good rule to remember at such a time?

a. Stopping is always the safest action in a traffic emergency

b. Heavy vehicles can almost always turn more quickly than they can stop

c. Leaving the road is always more risky than hitting another vehicle

16. The most important reason for being alert to hazards is:

a. Law enforcement personnel can be called

b. You will have time to plan your escape if the hazard becomes an emergency

c. You can help impaired drivers

17. You are traveling down a long, steep hill. Your brakes begin to fade and then fail. What should you do?

a. Downshift

b. Pump the brake pedal

c. Look for an escape ramp or escape route

18. The most common cause of serious vehicle skids is:

a. Driving too fast for road conditions

b. Poorly adjusted brakes

c. Bad tires

19. To avoid a crash, you had to drive onto the right shoulder. You are now driving at 40 MPH on the shoulder. How should you move back onto the pavement?

a. If clear, come to a complete stop before steering back onto the pavement

b. Brake had to slow the vehicle, then steer sharply onto the pavement

c. Keep moving at the present speed and steer very gently back onto the pavement

20. If

a. Slide sideways and spin out

b. Go straight ahead but will turn if you turn the steering wheel

c. Go straight ahead even if the steering wheel is turned

Here's the program to achieve the given requirements:
#include
using namespace std;

float average(float a[], int n) {
   float sum = 0;
   for(int i = 0; i < n; i++) {
       sum += a[i];
   }
   float avg = sum / n;
   return avg;
}

int main() {
   float scores[20];
   for(int i = 0; i < 20; i++) {
       cout << "Enter score " << i+1 << ": ";
       cin >> scores[i];
   }
   float avgScore = average(scores, 20);
   cout << "The average score is " << avgScore << endl;
   return 0;
}

In this program, the `average` function takes an array of floating-point numbers (`a[]`) and the size of the array (`n`) as input arguments, and returns the average of the numbers in the array as a float value. The `main` function declares an array `scores` of size 20 and reads in 20 scores from the user using a loop. It then calls the `average` function to get the average of the scores and outputs the result in the `main` function.

To know more about program visit:-

https://brainly.com/question/14588541

#SPJ11

6.8÷1.5 = 4.53...

So, it's 4 pipe with some left over.

Hope this helps!

The amount of settlement that would occur at the end of 1.5 year and 5 year are 7.3 cm and 13.14 cm respectively.

For a layer of 3.8 m thickness, we were given the following parameters:

For Sf, we have:

Sf = Sc/U

Sf = 7.3/0.5

Sf = 14.6

Therefore, Sf for a layer of 38 m thickness is given by:

Sf = 14.6 × 38/3.8

Sf = 146 cm.

At 50%, the time for a layer of 3.8 m thickness is:

\(t_{50}\) = 1.5 year.

At 50%, the time for a layer of 38 m thickness is:

\(t_{50}\) = 1.5 × (38/3.8)²

\(t_{50}\) = 150 years.

For a thickness of 38 m, U₂ is given by:

\(\frac{U_1^2}{U_2^2} =\frac{(T_v)_1}{(T_v)_2} = \frac{t_1}{t_2} \\\\U_2^2 = U_1^2 \times [\frac{t_2}{t_1} ]\\\\U_2^2 = 0.5^2 \times [\frac{1.5}{150} ]\\\\U_2^2 = 0.25 \times 0.01\\\\U_2=\sqrt{0.0025} \\\\U_2=0.05\)

The new settlement after 1.5 year is:

Sc = U₂Sf

Sc = 0.05 × 146

Sc = 7.3 cm.

For time, t₂ = 5 year:

\(U_2^2 = U_1^2 \times [\frac{t_2}{t_1} ]\\\\U_2^2 = 0.5^2 \times [\frac{5}{150} ]\\\\U_2^2 = 0.25 \times 0.03\\\\U_2=\sqrt{0.0075} \\\\U_2=0.09\)

The new settlement after 5 year is:

Sc = U₂Sf

Sc = 0.09 × 146

Sc = 13.14 cm.

Read more on clay layer here: https://brainly.com/question/22238205

#SPJ1

Answer:

105°touch sensce what I could wathskb

Answer:

the cost of heating a 2000 sq ft house with natural gas can vary depending on factors such as the efficiency of the furnace, the average heat setting, and the location. However, I have found some estimates on the average heating costs for a 2000 sq ft house with natural gas.

According to a heating cost calculator on Columbia Gas of Pennsylvania's website, the average heating cost for a 2000 sq ft house with natural gas is around $860 per heating season, assuming an average heat setting of 70°F.

Another estimate from Inspire Energy suggests that natural gas costs for a 2000 sq ft house could be around $72.10 per month.

However, it's important to note that these are just estimates and actual costs may vary depending on many factors such as insulation quality, thermostat settings, and weather conditions. It's always a good idea to consult with a local heating professional for a more accurate estimate.

Explanation: