all the elements are found on earth, where were they formed?
1. in the sun
2. in ancient stars
3. in earths core
4. in the gas cloud that formed earth

Answer:

50km/h

Explanation:

Average velocity = change in distance (or distance travelled) divided by/ the change in time (or time taken.)

The change in distance has been given as 100km.

The change in time is 3pm-1pm = 2 hours.

Therefore the average velocity was 100/2 = 50km/h (to the east).

Hope this helped!

At the maximum height of an object thrown straight upward, the velocity of the object is zero and its potential energy is at a maximum.

The acceleration of the object is also zero, as it is no longer accelerating due to the force of gravity. The object is momentarily in a state of equilibrium, with no net force acting upon it.

As the object begins to fall, the force of gravity begins to act upon it, increasing its velocity and kinetic energy while decreasing its potential energy. The object will then accelerate downwards at a constant rate, due to the constant downward acceleration of gravity, until it reaches the ground. At this point, the object will have reached its terminal velocity and will no longer be accelerating.

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Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer:

It depends if they have the same lightbulb in them.

Explanation:

We have the next information

T=2.00 x 10^-1 s=0.2s

r=3.5 inch

For the angular speed

where omega is the angular speed, T is the period

We substitute

For the linear speed on the rim of the disc, we will use the next formula

in this case r= 3.5/2=1.75 inch

Then for the linear speed on the point at 0.750 inches from the center of the disk.

ANSWER

ω=31.41 rad/sec

v on the rim= 54.97 inches/sec

v on the point=23.56 inches/sec

Answer:

Explanation:

Need a diagram....

The minimum velocity for the meteorite before entrance into earth's atmosphere is 36.8 m/s.

To calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere, the equation for heat transfer is:

Q = mcΔT

Where Q = the heat transferred,

m = the mass of the meteorite,

c = the specific heat capacity of iron, and

ΔT = the change in temperature.

The specific heat capacity of iron is approximately = 0.45 J/g°C.

Temperature of the meteorite changes from -105°C to the melting point of iron, which is approximately = 1535°C.

So: Q = mc(1535 - (-105))

Mass of the meteorite unknown, but we know it is made of iron, so assume a value for the mass, such as 100 g.

Q = 100 x 0.45(1535 - (-105))

Solving for Q:

Q = 67875 J

To calculate the kinetic energy of the meteorite, which is given by the equation: Ek = 1/2mv²

where Ek is kinetic energy,

m = the mass of the meteorite and

v = the velocity of the meteorite.

Therefore, the velocity of the meteorite is given by the following equation: v = √(2Ek/m)

Substituting the values of Ek and m, we get

v = √(2 x 67875/100)

Solving for v:

v = √1357.5

The minimum velocity the meteorite must have had before it entered Earth's atmosphere is approximately 36.8 m/s.

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Answer:

B) meteoroids.  The key word here is "generally."  Not when it enters the atmosphere or hits the surface of the Earth.  

Explanation:

Answer:

Explanation:

Sample Response: Sound travels faster in a warm room because temperature affects the speed of a wave. In a warm room, the particles of air move faster and have higher chances of bumping into each other, which then increases the instances of energy transfer.

Answer: ill do deeper reaseach because thats hard

Explanation:

Answer:

take foot and kick balls

Explanation:

1) Nucleus is less than the sum of the masses of two protons and two neutrons. 2)  Nucleus is less than the sum of the masses of a nucleus. 3) The third option is greater than. 4) The fourth option is equal to.

1) The mass of a ₂⁴He nucleus is less than the sum of the masses of two protons and two neutrons, all separated from each other.

2) The mass of a ³₂He nucleus is less than the sum of the masses of a ¹₁H nucleus and a ²₁H nucleus, separated from each other.

3) The mass of a ²³⁵₉₂U nucleus is greater than the sum of the masses of a ¹⁴¹₅₆Ba nucleus and a ⁹²₃₆Kr nucleus, and two neutrons, all separated from each other.

4) The mass of a ⁵⁶₂₆Fe nucleus is equal to the sum of the masses of a ²⁶₁₂Mg nucleus and a ³⁰₁₄Si nucleus, separated from each other.

Therefore, 1) Nucleus is less than the sum of the masses of two protons and two neutrons. 2)  Nucleus is less than the sum of the masses of a nucleus. 3) The third option is greater than. 4) The fourth option is equal to.

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Answer:

Solids have definite shapes while liquid fill their containers.

Explanation:

Liquids have got further apart molecules than solids, so the liquid molecules have a higher degree of locomotion than solid molecules, hence able to fill the container though without a definite volume which is not the case for solid molecules.

The speed at aphelion is mathematically given as

v2 = 21.43 km/s

Question Parameter(s):

At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s.

At aphelion it is 250 x 106 km distant.

Generally, the equation for the angular momentum conservation is mathematically given as

I1*w1 = I2*w2

Therefore

(0.5*m*R1^2)*v1/R1 = (0.5*m*R2^2)*v2/R2

Where

v1*R1 = v2*R2

v2 = v1*(R1/R2) = (30*10^3)*(2.50*10^11)/(3.50*10^11)

v2 = 2.1428*10^4 m/s

v2 = 21.43 km/s

In conclusion, speed is

v2 = 21.43 km/s

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-- If A and B are pointing in exactly opposite directions, then their sum A+B is the minimum possible value.  A+B = 2 N in the same direction as B.

-- If A and B are pointing in exactly the same direction, then their sum A+B is the maximum possible value.  A+B = 6 N in that same direction.  

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Main Answer:

The distance of L is \(v^{2} /2g(sin\alpha +ucos\alpha )\)

Explanation:

if the block will slide a distance 'L' then syoped;

The initial velocity given to the block is V m/s

So, Total K.E given will goes to gain in potential energy and work done by friction .

K.E=1/2mv^2

P.E at hight (Lsin\(\alpha\)) will be = mgh

And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos\(\alpha\)L

so,

KE+WD by friction = gain in P.E

\(1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )\)

Hence by solving we get :

\(v^{2} /2g(sin\alpha +ucos\alpha )\)=L

So the distance = L

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Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

First, let's draw each vector:

Since the vectors are perpendicular (the angle between then is 90°), we can use the Pythagorean theorem to find the magnitude of the resulting vector:

Therefore the magnitude of the sum of vectors is 6.88.

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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We have that the  force between  the two charged objects is mathematically given as

F=2.349N

Question Parameters:

Two spheres carry a charge of 1x10^-7 C.

Their centers are separated by 0.7m.

Generally the equation for the Force  is mathematically given as

\(F=\frac{q1q2}{4*\pi e*r}\)

Therefore

\(F=\frac{(1e-7)^2}{9e9*0.7}\)

F=2.349N

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Answer:

Use of telemetry and radar astronomy

Explanation:

An astronomical Unit (AU) is a unit of measuring distances in outer space, which is based on the approximate distance between the earth and the Sun.

After several years of trying to approximate the distance between the Sun and the Earth using several methods based on geometry and some other calculations, advancements in technology made available the presence of special motoring equipment, which can be placed in outer space to remotely monitor and measure the position of the sun.

The use of direct radar measurements to the sun (radar astronomy) have also made the determination of the AU more accurate.

A standard radar pulse of known speed is sent to the Sun, and the time with which it takes to return is measured,  once this is recorded, the distance between the Earth and the Sun can be calculated using

distance = speed X time.

However, most of these means have to be corrected for parallax errors

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:

24km/h

Explanation:

go it right on ingenuity 2020

equal in magnitude but opposite in direction

For these question, it has two separate equations: 2f(a) and f(2a) .

For f(2a) equations its x=2a, so you must substitute 2a into the f(x) equation

For 2f(a), it means the two time of f(a) equation with x=a, so you substitute a inti f(x) equation first, then you multiply it by 2.

The acceleration of a 50 g object pushed with a force of 0.5 N is 10 m/s².

To find the acceleration of the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:

F = m * a

Given:

Force (F) = 0.5 N

Mass (m) = 50 g = 0.05 kg

Substituting the given values into the equation, we have:

0.5 N = 0.05 kg * a

To find the acceleration (a), we rearrange the equation:

a = F / m

a = 0.5 N / 0.05 kg

a = 10 N/kg

Since acceleration is measured in meters per second squared (m/s²), we convert the unit of N/kg to m/s²:

1 N/kg = 1 m/s²

Therefore, the acceleration of the 50 g object pushed with a force of 0.5 N is 10 m/s².

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(a) The swimmer needs 3000 seconds before take a bath across that whole river.

(b) D = 2730 meters, which represents how far downstream the swimmer will be when they cross the river.

Two miles downstream, in the course of or closer to the entrance of a stream drifting downstream. in or around the end of a typical industrial process and the stages after fabrication that increase earnings for downstream products.

Downstream It is referred to as downstream if somehow the boat is moving downwards of the stream. The downstream speed in this situation refers to the boat's net speed. In this situation, still water is seen as being immobile.

Time = ?

d / v = t

3000 m / 1.0 m/s

T = 3000 s

Distance = ?

t * v = d

3000 s * 0.91 m/s

D = 2730 m

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Answer:

\(F=3.61\times 10^{-47}\ N\)

Explanation:

Mass of a proton, \(m_p=1.67\times 10^{-27}\ kg\)

Mass of an electron, \(m_e=9.11\times 10^{-31}\ kg\)

The distance between the electron and the proton is, \(r=5.3\times 10^{-11}\ m\)

We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :

\(F=G\dfrac{m_em_p}{r^2}\)

Where G is the universal Gravitational constant

\(F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N\)

So, the force between the electron and proton is \(3.61\times 10^{-47}\ N\).