An 800 kg white horse has the power output of 1 hp. The maximum force it can exert at speed of 3 meters second is
0.25 kilo-Newton's
2.20 kilo-Newton's
2.60 kilo-Newton 's
3.60 kilo-Newton s

To find the instantaneous velocity of the ball at time t₀ > 4 seconds when it is at a height of 30 meters above the ground, we need to find the derivative of the height function with respect to time and then evaluate it at t₀. The instantaneous velocity of the ball at t₀ > 4 seconds when it is at a height of 30 meters above the ground is approximately -53.42992 m/s.

Given:

Height function: h(t) = 1 + 30t - 4.9t^2

Height above the ground: h(t₀) = 30 meters

Time: t₀ > 4 seconds

First, let's find the derivative of the height function with respect to time:

h'(t) = d(h(t))/dt = d(1 + 30t - 4.9t^2)/dt

Differentiating each term separately:

h'(t) = d(1)/dt + d(30t)/dt - d(4.9t^2)/dt

h'(t) = 0 + 30 - 9.8t

Now we have the velocity function, which gives the instantaneous velocity of the ball at any time t.

To find the value of t when the ball is at a height of 30 meters, we can set h(t) equal to 30 and solve for t:

30 = 1 + 30t - 4.9t^2

Rearranging the equation to quadratic form:

4.9t^2 - 30t + 29 = 0

Solving this quadratic equation, we find two possible values of t. Let's denote them as t₁ and t₂.

Using the quadratic formula:

t₁, t₂ = (-(-30) ± √((-30)^2 - 4 * 4.9 * 29)) / (2 * 4.9)

t₁ ≈ 0.6708 seconds

t₂ ≈ 8.5104 seconds

Since we're interested in the ball's velocity at t₀ > 4 seconds, we focus on t₂ ≈ 8.5104 seconds.

Now we can find the instantaneous velocity at t = t₂ by substituting it into the velocity function:

v(t) = h'(t) = 30 - 9.8t

v(t₂) = 30 - 9.8 * t₂

v(t₂) ≈ 30 - 9.8 * 8.5104

Calculating the value:

v(t₂) ≈ 30 - 83.42992

v(t₂) ≈ -53.42992 m/s

Therefore, the instantaneous velocity of the ball at t₀ > 4 seconds when it is at a height of 30 meters above the ground is approximately -53.42992 m/s.

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The charge on each capacitor

Q1=118.0uC u

CQ2= 118.0uC uC

The potential difference across each capacitor

V1=35.8V

VV2=22.7V

To solve this problem, we will first calculate the equivalent capacitance of the series connection, then find the charge on each capacitor, and finally calculate the potential difference across each capacitor.

1. Equivalent capacitance (Ceq) of capacitors in series:

1/Ceq = 1/C1 + 1/C2

1/Ceq = 1/3.30uF + 1/5.20uF

Ceq = 2.00uF

2. Charge on each capacitor (Q1 and Q2):

Since capacitors in series have the same charge,

Q1 = Q2 = Q

Q = Ceq * Vab

Q = 2.00uF * 59.0V

Q = 118.0uC

So, Q1 = 118.0uC and Q2 = 118.0uC

3. Potential difference across each capacitor (V1 and V2):

V1 = Q1 / C1

V1 = 118.0uC / 3.30uF

V1 = 35.8V V2 = Q2 / C2

V2 = 118.0uC / 5.20uF

V2 = 22.7V

In conclusion:

Q1 = 118.0uC

Q2 = 118.0uC

V1 = 35.8V

V2 = 22.7V

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Answer:

the correct answer is D

Explanation:

Answer:

Explanation:

bv

Answer:

5.05 sec

Explanation:

h = 1/2gt²

solve for t:

t² = (2h)/g

t = √(2h)/g = √((2)(125 m)) / (9.8 m/s²) = 5.05 s

Given data:

* The mass of the student is m = 65 kg.

* The distance covered by the student is d = 100 m.

* The time taken by the student to cover the distance is t = 12 seconds.

Solution:

(a). The velocity of the student is,

Thus, the velocity of the student is 8.33 meters per second.

(b). The kinetic energy of the student is,

Thus, the kinetic energy of the student is 2255.14 J.

(c). The mechanical energy of the student is the energy acquired by the student during its motion.

Thus, the mechanical energy of the student is 2255.14 J.

A force of 0.8 N would be required to accelerate the object from rest to a velocity of 8 m/s on the same surface.

If the object is to be accelerated from rest to a velocity of 8 m/s on the same surface, the force required can be calculated using Newton's second law, which states that force is equal to mass times acceleration (F=ma).

In this case, the mass of the object is 1 kg, and the initial velocity is 0 m/s. The final velocity is 8 m/s, and the time taken is 10 s. Therefore, the acceleration can be calculated as,

a = (v-u)/t = (8-0)/10 = 0.8 m/s^2

Using F=ma, the force required can be calculated,

F = ma = 1 x 0.8 = 0.8 N

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The labelled table data hat the experimenter can record observations for the sand and water temperatures at various points is given below.

Here is a labeled data table for recording sand and water temperatures at various points:

Point            Sand Temperature (°C)                 Water Temperature (°C)

1  

2  

3  

4  

5  

The table is 5 columns wide and 3 rows long, with the first column labeled "Point" to indicate the location being observed, and the second and third columns labeled "Sand Temperature (°C)" and "Water Temperature (°C)" respectively to indicate the type of temperature being measured.

The cells under the "Sand Temperature (°C)" and "Water Temperature (°C)" columns are left blank to allow the experimenter to record the corresponding temperature readings for each point.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Label a data table so that the experimenter can record observations for the sand and water temperatures at various points.

the column table 5 length x 3 width

Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

Explanation:

1 meter per second squared is equivalent to 0.001 kilometer per second squared.

To convert 1 meter per second squared (m/s²) into kilometer per second squared (km/s²), we need to consider the conversion factor between meters and kilometers.

1 kilometer is equal to 1000 meters, so we can use this conversion factor to convert the units.

First, let's convert the acceleration from meters per second squared to kilometers per second squared:

1 m/s² = (1/1000) km/s²

Therefore, 1 meter per second squared is equal to 0.001 kilometer per second squared.

So, 1 m/s² = 0.001 km/s².

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Answer:

The phenomenon of the irregular movement of pollen grains suspended in water was observed by Robert Brown in 1827. Brownian motion, the name given to this process, was not given a rigorous mathematical treatment until almost one hundred years later by N.

Answer:

this is the answer

The instantaneous velocity of the object at t = 5 is approx. 16.

To find the instantaneous velocity of the object at t = 5, we need to take the derivative of the position function with respect to time.

Given that the position function is s(t) =\(t^2\) + 6t + 2, we differentiate it to obtain the velocity function:

v(t) = d/dt \((t^2\) + 6t + 2)

Using the power rule of differentiation, we have:

v(t) = 2t + 6

Now, we can find the instantaneous velocity at t = 5 by substituting t = 5 into the velocity function:

v(5) = 2(5) + 6

v(5) = 10 + 6

v(5) = 16

Therefore, the instantaneous velocity of the object at t = 5 is 16.

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--The complete Question is, An object is moving in a straight line, and its position is given by the equation s(t) = t^2 + 6t + 2. What is the instantaneous velocity of the object at t = 5?--

When a patient sees an out-of-network physician, the payment rules depend on the type of insurance plan the patient has.

In general, out-of-network care is not covered or is only partially covered by insurance plans, and the patient may be responsible for paying the difference between the amount charged by the out-of-network physician and the amount that the insurance plan covers.

For example, in a preferred provider organization (PPO) plan, patients may have some coverage for out-of-network care, but they will generally have to pay higher copays, coinsurance, and deductibles.

In a health maintenance organization (HMO) plan, out-of-network care may not be covered at all, except in emergency situations.

In some cases, out-of-network physicians may be willing to accept the insurance plan's payment as payment in full, but this is not guaranteed, and patients should check with their insurance plan and the physician's office to understand their financial responsibility.

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the answer is 0.284 lb/in3

When you stand a meterstick on its end and let it rotate to the floor, the time it takes to fall is dependent on the moment of inertia.

If you attach a heavy glob of clay to its upper end and repeat the experiment, the time it takes to fall will be longer. The moment of inertia is defined as the resistance of an object to rotational motion. It is dependent on the shape and mass distribution of an object. The clay's addition to the meterstick's upper end changes the mass distribution of the object and increases its moment of inertia. As a result, the object will take longer to fall because it has more resistance to rotational motion.

In summary, the time it takes for a meterstick to fall is dependent on its moment of inertia. Adding a heavy glob of clay to its upper end increases the moment of inertia, resulting in a longer time for it to fall.

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Parallax is the most commonly used technique to measure distances to nearby stars, followed by radar, which is used for objects in our solar system. Spectroscopic parallax is used to determine the distances to stars that are too far away for parallax measurements. Cepheids and Type la supernovae are used to measure distances to galaxies and are typically used together as cross-checks on each other's measurements. Therefore, the ranking from closest to most distant is parallax, radar, spectroscopic parallax, Cepheids, and Type la supernovae.
To correctly rank the distance ladder in terms of techniques used to measure distances from the closest to the most distant objects, the order is as follows:

a. radar, parallax, spectroscopic parallax, Cepheids, Type Ia supernovae.

1. Radar: Used for measuring distances within our solar system, such as the distance between planets.
2. Parallax: Effective for measuring distances to nearby stars within our galaxy, up to around 1,000 parsecs.
3. Spectroscopic parallax: Used for determining distances to stars further away in our galaxy, based on their spectral characteristics and brightness.
4. Cepheids: Useful for measuring distances to objects within our galaxy and nearby galaxies, utilizing their unique pulsation properties and period-luminosity relationship.
5. Type Ia supernovae: Employed for measuring distances to very distant galaxies, as they have a consistent peak luminosity and serve as "standard candles" in astronomy.

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Answer:

if an object is in free fall for a longer time its position will increase at an exponential rate because the object is accelerating

Answer:

13328 Newtons

Explanation:

Definition of Weight

\(W=mg\)

We are given

\(m=1360\)

\(g=9.8\)

So the weight is equal to

\(W=1360*9.8\)

\(W=13328\)

If you are standing on a dock and are planning to kill a fish using a laser beam,  aim of your laser beam depends on various factors such as the type of fish, size, distance from the dock, and the strength of your laser beam. The aim would change from fish to fish as the eyes of the fish, like most animals, are different.

If your target fish is one that lives in the surface waters, its eyes may be positioned to look upwards. In this case, you would have to aim at the fish's head so that the laser beam can reach the eyes and cause damage or death. Similarly, fish with eyes positioned on the side of their heads need a different aim, depending on whether the fish is facing you or swimming parallel to you.

In most cases, the best aim is to target the fish's eyes. In any case, the exact aim will depend on the strength of the laser beam and the distance between you and the fish. A stronger laser beam is more likely to cause damage or death, while a weak beam may not be effective at all. Therefore, before you use your laser beam to kill a fish, you should make sure you understand its power and the safety guidelines for handling it to avoid causing harm to yourself and others around you.

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gravitaional pull

not sure

Answer:

hi

Explanation:

bye

Answer: San diego

Because it is closer to the ocean

Answer:

electric current refers to electrons and protons flow in the opposite direction. current is flow electrons ,but current and electron flow in the opposite direction. current flows from positive to negative and electron flows from negative to positive.

The term "psychophysics" was coined by German psychologist and philosopher Gustav Fechner in the mid-19th century.

He introduced the concept in the mid-19th century as a way to quantify and study the relationship between physical stimuli and their psychological effects. Fechner is considered to be the founder of psychophysics, and his work laid the foundation for the development of this field of study. Psychophysics aims to understand the perception of stimuli and how it is related to the physical properties of the stimuli, such as their intensity, duration, and frequency. Psychophysics is a subfield of psychology that deals with the relationship between physical stimuli and their psychological effects. It aims to quantify the relationship between the physical properties of stimuli, such as intensity, duration, and frequency, and the subjective experiences of those stimuli, such as sensation, perception, and response.

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A hallmark of courage is being ready and willing to face challenging or uncomfortable circumstances. The word "bravery" is similar. It can also include doing so, even though confronting these situations fearlessly is generally thought of as showing courage.

In reality, courage is the capacity to move forward in the face of fear. The ability to behave bravely in the face of any anxiety or tension is what is meant by having courage. One of the finest ways to be courageous is to recognize your fears and then decide not to let them stop you. having the guts to handle risk in a responsible manner as opposed to acting cowardly or irrationally confident.

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The direction of this current's magnetic force on an electron that is moving perpendicular to the page and outward from it on the left side of the wire is downward.

What is Magnetic force?

The force exerted by a magnetic field on a moving charged particle is known as a magnetic force. It is described by the formula F = q(v x B), where F is the magnetic force, q is the particle's charge, v is the particle's velocity, and B is the magnetic field.

The right-hand rule states that when a wire-carrying current is held in the right hand with the thumb pointing in the direction of the current, the fingers will curl in the direction of the magnetic field lines created by the current.

The magnetic field lines will create clockwise circles around the wire because, in this instance, the current flows from the top of the page downward.

Now imagine an electron on the left side of the wire traveling perpendicular to the page. The electron will experience a magnetic force since it travels in a direction perpendicular to both the magnetic field and the current.

We can use the left-hand rule for a negative charge to determine the direction of this force. If the left hand is held with the fingers pointing toward the magnetic field and the thumb pointing toward the electron's velocity, the palm will face the order of the force on the electron.

The thumb points to the left because the electron leaves to the left. The fingers curl because the magnetic field lines go clockwise around the wire. Therefore, the magnetic force acting on the electron is directed downward because the palm is facing downward.

Therefore, the magnetic pull exerted by this current on an electron traveling outward and perpendicular to the page on the wire's left side is directed downward.

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Answer:

21.2 km

Explanation:

You're basically solving for the hypotenuse of a right triangle with legs of 15 and 15.  Use the pythagorean theorem:

d =  displacement vector

d² = 15² + 15² = 450

d = √450 = 21.2 km

The rotational kinetic energy about the center of mass of the rolling cylinder is 250.0 joules.

When a cylinder rolls without slipping on a horizontal surface, the relationship between its linear speed (v) and its angular speed (ω) is given by:

v = R * ω

where:

v = linear speed of the center of mass (given as 10.0 m/s)

R = radius of the cylinder (unknown)

ω = angular speed

Since the cylinder rolls without slipping, the angular speed (ω) can also be expressed as:

ω = v / R

Now, let's use this relationship to calculate the rotational kinetic energy (\(K_{rot\)) about the center of mass.

First, we need to find the angular speed (ω):

ω = v / R

ω = 10.0 m/s / R

Next, we can calculate the moment of inertia (I) using the formula:

I = (1/2) * m * \(R^2\)

I = (1/2) * 10.0 kg * \(R^2\)

Finally, we can calculate the rotational kinetic energy (\(K_{rot\)) using the formula:

\(K_{rot\) = (1/2) * I * \(\omega^2\)

Substituting the expressions for I and ω:

\(K_{rot\) = (1/2) * (1/2) * 10.0 kg * \(R^2\) * (10.0 m/s / \(R)^2\)

\(K_{rot\) = (1/4) * 10.0 kg * \(R^2\) * (100.0 \(m^2/s^2 / R^2\))

\(K_{rot\) = (1/4) * 10.0 kg * 100.0 \(m^2/s^2\)

\(K_{rot\) = 250.0 joules

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The complete question is:

A cylinder of mass 10.0 kg rolls without slipping on a horizontal surface. At a certain instant, its center of mass has a speed of 10.0 m/s. Determine the rotational kinetic energy about its center of mass