An airplane flying at 119 m/s is accelerated uniformly at the rate of 0.5 m/s2 for 10
seconds. What is its final speed?

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

The height difference that stabilizes between the surfaces of the mercury in the U-tube is approximately 0.142 m.

To solve this problem, we can use the principle of continuity and Bernoulli's equation. The principle of continuity states that the mass flow rate of a fluid is constant, so A1v1 = A2v2, where A is the cross-sectional area and v is the velocity of the fluid at two different points in the tube. Bernoulli's equation states that the total energy of a fluid (the sum of its kinetic energy, potential energy, and pressure energy) is conserved along a streamline.

Let h be the height difference between the surfaces of the mercury in the U-tube. Then, the pressure difference between the two points in the tube (at the wide and thin parts) is ΔP = ρgh, where ρ is the density of the mercury and g is the acceleration due to gravity.

From the principle of continuity, we have A1v1 = A2v2. Since the tube is horizontal, the potential energy of the fluid is the same at both points. Thus, Bernoulli's equation reduces to:

1/2 ρv1^2 + P1 = 1/2 ρv2^2 + P2,

where P is the pressure of the fluid at two different points in the tube. Since the air is the same at both points, P1 = P2. The air density is also given, ρair = 1.3 kg/m^3, and the air velocity is given, v1 = 15 m/s. We can find v2 by rearranging the equation A1v1 = A2v2 to v2 = (A1/A2)v1, where A1 = πr1^2 and A2 = πr2^2 are the cross-sectional areas of the wide and thin parts of the tube, respectively. Substituting the given values, we get v2 = 60 m/s.

Thus, Bernoulli's equation becomes:

1/2 ρairv1^2 = 1/2 ρairv2^2 + ρgh + P,

where P is the pressure of the air at the wide part of the tube. Since P1 = P2, we can cancel the pressure terms, and solve for h:

h = (v1^2 - v2^2)/(2g) * (ρair/ρmercury)

= (15^2 - 60^2)/(2*9.81) * (1.3/13600) ≈ 0.142 m

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Answer:B

Explanation: The book is thinner making magnets attraction stronger, making the paper clip harder to move

The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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Answer:

b

Explanation:

The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.

To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:

F = m × a

where:

F = force

m = mass

a = acceleration

Given:

m = 68 kg

F = 1650 N

Find the acceleration (a) first. Rearranging the equation:

a = F / m

Substituting the values:

a = 1650 N / 68 kg

a ≈ 24.26 m/s²

Now, use the equation of motion to find the time (t):

v = u + at

where:

v = final velocity (0 m/s as the person comes to a stop)

u = initial velocity (27 m/s)

a = acceleration (24.26 m/s²)

t = time

Rearranging the equation:

t = (v - u) / a

Substituting the values:

t = (0 m/s - 27 m/s) / 24.26 m/s²

t ≈ -27 m/s / 24.26 m/s²

t ≈ -1.11 s

The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.

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By flowing back across the membrane, protons (H+) seek to equalize their concentration of both sides of the membrane.

The third option is correct.

The  process by which Protons (H+) flowing back across a membrane seek to equalize their concentration on both sides of the membrane is known as proton gradient equilibration or proton motive force equilibration.

During cellular respiration, protons are pumped across a membrane to create a gradient. This gradient is then used to generate ATP, the energy currency of the cell. Protons flow back across the membrane through a channel called ATP synthase, which generates ATP as the protons flow through it.

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The points in order of increasing value of the velocity can be ranked as:

B < C < A ≡ F < E < D.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

According to the figure:

The points in order of increasing value of the velocity can be written as:

B < C < A ≡ F < E < D.

As the displacement becomes from positive to negative near point B, it has the lowest velocity and  as the displacement becomes from negative to positive near point D, it has the highest velocity

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Answer:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Explanation:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Answer:

The answer is ligaments!

Explanation:

Hope this helps!! :)

Answer:

You get Day and Night

It takes 24 hour

Answer:

Explanation:

The Earth's orbit makes a circle around the sun. At the same time the Earth orbits around the sun, it also spins.Since the Earth orbits the sun and rotates on its axis at the same time we experience seasons, day and night, and changing shadows throughout the day.It only takes 23 hours, 56 minutes and 4.0916 seconds for the Earth to turn once on its axis.

Answer: 708 N

Explanation:

Given

At rest, Elevator reads 588 N

When it starts moving upward at \(2\ m/s^2\), apparent weight changes

i.e. weight can be given by

\(\Rightarrow W'=m(g+a)\\\Rightarrow W'=mg+mg\cdot \dfrac{a}{g}\\\\\Rightarrow W'=W\left(1+\dfrac{a}{g}\right)\\\\\Rightarrow W'=588\left(1+\dfrac{2}{9.8}\right)\\\\\Rightarrow W'=707.99\approx 708\ N\)

The apparent weight is 708 N

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

3380 m

Explanation:

The rank of the forces in order of increasing magnitude is Fg < FB < FA.

option D is the correct answer.

The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.

That is, the two forces acting on a person when he is moving in an elevator are:

When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.

When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.

Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.

The box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.

FA = FB + Fg

Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.

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Answer: the answer is C- create and develop white blood cells

Explanation:

The acceleration of the body is 4.5 m/s^2.

First, let's convert the initial velocity and final velocity from m/s to km/h:

Initial velocity = 30 m/s = (30/1000) * 3600 = 108 km/h

Final velocity = 80 m/s = (80/1000) * 3600 = 288 km/h

Let the time taken to accelerate to 288 km/h be t1, and the time taken to decelerate from 288 km/h to rest be t2. Since the time spent at constant velocity is twice the time spent accelerating, it is 2t1.

The distance covered during acceleration and deceleration can be calculated using the formula:

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

For acceleration:

distance1 = (108 * t1) + (0.5 * a * t1^2)

For deceleration:

distance2 = (288 * t2) + (0.5 * (-a) * t2^2)

Since the total time taken for the journey is 40, we have:

t1 + 2t1 + t2 = 40

3t1 + t2 = 40

Also, the total distance traveled is given as 2550 km:

distance1 + distance2 = 2550

Substituting the expressions for distance1 and distance2, we get:

(108 * t1) + (0.5 * a * t1^2) + (288 * t2) - (0.5 * a * t2^2) = 2550

Simplifying the above equation:

108t1 + 144t1^2/a + 288t2 - 0.5t2^2a = 2550

Now, we have three equations with three variables (a, t1, t2). We can solve these equations to obtain the value of acceleration (a).

From the first equation, we have:

t2 = 40 - 3t1

Substituting this value of t2 in the equation for distance2, we get:

distance2 = 288(40 - 3t1) - 0.5*a(40 - 3t1)^2

Substituting the values of distance1 and distance2 in the equation for total distance, we get:

(108 * t1) + (0.5 * a * t1^2) + 288(40 - 3t1) - 0.5*a(40 - 3t1)^2 = 2550

Simplifying the above equation and solving for a, we get:

a = 4.5 m/s^2
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A controlled procedure that tests the effect of one variable on another is known as experiment.

An experiment is a set of actions and observations, performed in the context of solving a particular problem or question, to support or falsify a hypothesis or research concerning phenomena.

An experiment generally tests how one variable is affected by another.

Thus, a controlled procedure that tests the effect of one variable on another is known as experiment.

The correct answer is option B. "experiment"

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Answer:

The experiment.

The change in angular momentum of the pulley-block system is given as \(\omega = Rm_ogt_o\)

Data;

This is the force that makes object rotate about an axis. The formula is given as the product between the radius about the axis and the force acting upon it.

The torque about point o is given as

\(\tau = R * m_og\)

The change in angular momentum about point 'o' is the product between the torque and time.

\(\omega = \tau * t_o\\\omega = Rm_ogt_o\)

The change in angular momentum of the pulley-block system is given as

\(\omega = Rm_ogt_o\)

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For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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The box slides down the wall unless an external force of magnitude 23 N is applied on it. The object is directed upward with an angle of 27° above the horizontal surface. Therefore, the mass of block is 1.90 kg

A friction is a kind of force which resists the sliding or rolling of objects over the surface of each other.

Applied force, F = 23 N

Coefficient of static friction, μs = 0.40

Coefficient of kinetic friction, μs = 0.30

θ = 27°

Let 'N' be the normal reaction of the wall acting on the block and 'm' be the mass of block.

Resolve the components of force 'F'

As the block is in horizontal equilibrium with the wall.

So,

F Cos27° = N

N = 23 Cos27° = 20.495 N

As the block does not slide so it means that the static friction force acting on the block balances the downwards forces (gravity) acting on the block.

The force of static friction is:

μs x N = 0.4 x 20.495 = 8.19 N   .... (1)

The vertically downward force acting on the block is (mg - F Sin27°)

mg - 23 Sin 27° = mg - 10.441    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 10.441 = 8.19

mg = 18.631

m x 9.8 = 18.631

m = 1.90 kg

Thus, the mass of block is 1.90 kg.  

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Your question is incomplete, most probably the complete question is:

A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above the horizontal. The coefficients of static and kinetic friction between the box and wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has magnitude 23 N. What is the mass of the box in kilograms?

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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The velocity of the teddy bear as it strikes the ground is 7.67 m/s.

The velocity of the teddy when it strikes the ground is calculated from principle of conservation of energy as shown below.

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 3)

v = 7.67 m/s

Thus, the velocity of the teddy bear as it strikes the ground is 7.67 m/s.

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Answer:

Explanation:

The rms speed:

Vrms = (500 + 600 + 700 + 800 + 900) / 5 = 700 m/s

K = 8.93 ⋅ 10 9 N m 2 C 2 hope this helps.

The displacement of the train after 2.23 seconds is 25.4 m.

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

The displacement of the train is the change in position of the train after a given period of time.

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

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The standard form equation for the circle with center (3, 10) and radius 2 is: \(\rm 2.x^{2} + y^{2} - 6x - 20y + 105 = 0.\)

The radius, diameter, circumference, arc, chord, secant, tangent, sector, and segment are all parts of a circle.

A circle is a round figure with no corners or edges. A circle is a closed shape, a two-dimensional shape, and a curved shape in geometry.

A circle with center (h, k) and radius r has the following standard form equation:

\(\rm (x-h)^{2} + (y-k)^{2} = r^{2}\)

Substituting the values of center and radius:

\(\rm (x-3)^{2} + (y-10)^{2} = 2^{2}\)

Simplifying the equation:

\(\rm x^{2} - 6x + 9 + y^{2} - 20y + 100 = 4\)

\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)

\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)

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Acceleration of the skydiver during the free fall is 4.13 m/s².

1) Mass of the skydiver, m = 83 kg

Weight, W = mg = 83 x 9.8

W = 813.4 N

Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.

Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.

Freebody diagram is given in Fig.1.

2) Mass of the skydiver, m = 78 kg

Air resistance acting on him, F' = 470 N

mg - 470 = ma

813.4 - 470 = ma

a = 343.4/83

a = 4.13 m/s²

Freebody diagram is given in fig.2.

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