an airplane travels down a Runway at 1500 m in 17s what is the average speed

Answer:

OLTO 3 Suppose the two glass plates in Figure are two microscope slides 10cm long. At one end they are in contact; at the other end they are separated by apiece of paper 0.02mm thick. What is the spacing of the interference fringes seen by reflection? Is the fringe at the line of contact bright or dark? Assume monochromatic light with a wavelength in air of lambda=lambdao=500nm. lo=500 nm = 0.0200 mm - 10.0 cm (15.05)) 4. Using the experimental apparatus shown in Figure, when ultraviolet light with a wavelength of 240 nm shines on a particular metal plate, electrons are emitted from plate 1, crossing the gap to plate 2 and causing a current to flow through the wire connecting the two plates. The battery voltage is gradually increased until the current in the ammeter drops to zero, at which point the battery voltage is 1.40 V. (a) What is the energy of the photons in the beam of light, in eV? (b) What is the maximum kinetic energy of the emitted electrons, in eV? (C) What is the work function of the metal, in eV? plate 2 AV incident electrons Tammeter light plate 1 (15.05) Powered by WPS Office

Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

Answer:

a) 0.47MW

b) 39.24%

Explanation:

In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:

P=Fv

where P is the power, F is the force and v is the velocity.

The force the elevator must carry can be calculated with the following formula:

F=mg

where m is the mass of the elevator and g is the acceleration of gravity, so:

\(F=(8000 kg)(9.81 m/s^{2})\)

F=78 480 N

so now we can make use of the power formula:

P=Fv

P=(78 480N)(6 m/s)

P=470 880W

P=0.47W

b)

In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:

\(efficiency = \frac{P_{in}}{P_{out}}*100\%\)

\(efficiency=\frac{0.470880}{1.2}*100\%\)

efficiency=39.24%

Answer:

Explanation:

Your body weighs more at the pole for two important reasons. Both have to do to the spin of the earth on its axis.

Because of its spin the earth is thicker around the equator than it is through the poles. This means that when you stand on the equator, you are farther away from the center of earth than you would be at the poles. As gravity decreases with the inverse of the square of distance, gravity will be weaker at the equator.

As you are also spinning with the earth, you will have a required centripetal acceleration and force to keep you attached to the ground, This force decreases the effect of gravity so again, you would weigh less at the equator.

Answer:

Explanation:

Galileo proved the superiority of the heliocentric theory over the geocentric theory . Heliocentric theory changed the centre of universe from the earth to the sun . According to this theory , the solar system or the universe revolves around the sun .

But the present knowledge of universe considers sun as one of billions of stars present in the universe , with each star behaving as sun with its  own solar system . The universe is made of cluster of stars with each cluster having their  own centre around with they revolve . These clusters are called galaxy . Sun is a part of cluster called milky way . Sun along with other star of this galaxy revolves around the centre of its galaxy which is a super massive star .

Hence the old heliocentric theory does not fit into the present framework of universe by the scientist.

A simplified version of Rutherford’s calculation of the size of the gold nucleus. A piece of gold foil that is 0.010 cm thick and whose area is 1 cm x 1 cm is used in the experiment. It is observed that 99.93% of all particles go through undeflected. The density of gold is 19,300 kg/m3.

Rutherford's experiment involved firing alpha particles (helium nuclei) at a thin sheet of gold foil to study the structure of atoms. Based on the results of this experiment, Rutherford was able to deduce that atoms have a small, dense nucleus at their center.

In this problem, we will go through a simplified version of Rutherford's calculation of the size of the gold nucleus.

First, we need to calculate the total number of gold atoms in the foil. We know that the foil is 0.010 cm thick and has an area of 1 cm x 1 cm, so its volume is

V = thickness x area = 0.010 cm x (1 cm x 1 cm) = 0.010 \(cm^{3}\)

The density of gold is 19,300 kg/\(m^{3}\), which is equivalent to 19.3 g/\(cm^{3}\)Therefore, the mass of the gold foil is

m = density x volume =  19.3 g/\(cm^{3}\) x 0.010 \(cm^{3}\) = 0.193 g.

The molar mass of gold is 197 g/mol, so the number of gold atoms in the foil is

N = (0.193 g) / (197 g/mol) x (6.022 x \(10^{23}\) atoms/mol) = 1.86 x \(10^{21}\) atoms

Next, we need to determine the fraction of alpha particles that are deflected by the gold nucleus. We are told that 99.93% of all alpha particles go through undeflected, which means that only 0.07% of the alpha particles are deflected. This is a very small fraction, which suggests that the size of the gold nucleus must be very small compared to the size of the atom.

Assuming that the alpha particles are deflected only by the gold nucleus and not by the electrons, we can use the principle of conservation of momentum to estimate the size of the gold nucleus. When an alpha particle approaches the gold nucleus, it experiences a repulsive electrostatic force that causes it to change direction. The magnitude of this force is given by Coulomb's law

F = k\(q_{1}\)\(q_{2\) / \(r^{2}\)

Where k is Coulomb's constant, \(q_{1}\) and \(q_{2}\) are the charges of the alpha particle and gold nucleus, respectively, and r is the distance between them. Since the alpha particle has a positive charge and the gold nucleus has a positive charge, the force is repulsive.

If we assume that the alpha particle is initially moving directly toward the center of the gold nucleus, then at the point of closest approach, the alpha particle will have a velocity v that is perpendicular to the direction from the alpha particle to the gold nucleus. At this point, the force on the alpha particle will be perpendicular to its velocity, which means that it will change only the direction of the alpha particle's velocity, not its magnitude.

Using conservation of momentum, we can relate the angle of deflection θ to the distance of closest approach r.

m\(v^{2}\) / r = k\(q_{1}\)\(q_{2\) / \(r^{2}\)

Where m is the mass of the alpha particle. Solving for r, we get

r = k\(q_{1}\)\(q_{2\) / m\(v^{2}\)

To estimate the size of the gold nucleus, we assume that the alpha particles are deflected by a single, stationary gold nucleus at the center of the atom. In reality, the gold nucleus is not stationary, but this assumption gives us a rough estimate of its size.

Hence, the alpha particles are undeflected with a probability of 0.9993, we can assume that they do not interact with the gold nucleus and that their path is a straight line through the foil.

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Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Answer:

the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area.

Explanation:

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

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The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer:

Elastic potential energy is stored when materials stretch or compress. Examples of it include springs, rubber bands, and slingshots.

Explanation:

Answer:

hinata for sure

Explanation:

seems reasonable

The acceleration is 930 m/s^2 and the time taken is 0.07 s.

We know that the acceleration is the rate of change of velocity with time. We can find the acceleration in this case by the use of kinematic equations of motion as we shall demonstrate below.

Let use the formula;

v^2 = u^2 + 2as

Where

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

u = 0 m/s because the motion started from rest

v^2 =  2as

a = v^2/2s

a = (61)^2/2 * 2

a = 930 m/s^2

The time taken is;

v = u + at

u = 0 m/s

v = at

t = v/a

t = 61 m/s/930 m/s^2

t = 0.07 s

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C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\(\\ \tt\bull\leadsto PV\)

\(\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

RHS

\(\\ \tt\bull\leadsto nRT\)

\(\\ \tt\bull\leadsto [M^0L^{3}T^0][M^1 L^2 T^{-2}K^{-1}][M^0L^0T^0K^1]\)

\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)

LHS=RHS

hence verified

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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Answer:

Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Answer:

I Don't know

Explanation:

Because I'm 5 grade student

Sam and Sally are traveling aboard a spacecraft that approaches the asteroid Ceres within 14,000 kilometers. Sally will experience 1.989 × 10⁻¹¹  N of force.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Given data

Mass of asteroid ,m₁ = 8.7 1020 kg

Mass of sally,m₂ = 67 kg

Gravitational constant,G = 6.6 × 10⁻¹¹ kg⁻² m²

Distance of seperation,R =  14,000 km

\(\rm F = G\frac{m_1m_2}{R^ 2} \\\\ F = 6.6 \times 10^{-11 }\times \frac{8.71020 \times 67 }{(14,000)^2} \\\\F = 1.989 \times 10^{-11 } \ N\)

Hence, the force Sally experiences will be 1.989 × 10⁻¹¹  N.

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Acceleration is defined as the change in velocity per unit time. Its unit is m/s².

Distance is the amount of space, or the actual length of the path travelled.

Displacement is the difference between the initial and final positions of the object.

Speed is the rate at which an object covers a certain distance.

Velocity is defined as the speed with a direction.

An object is said to have a positive velocity, if it is moving in the positive direction. And an object moving in negative direction has a negative velocity.

Acceleration is the change in velocity per unit time.

For freely falling objects, gravity is the only thing acting on the object.

The acceleration due to gravity on the earth is 9.8 m/s².

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Answer:

50 N

Explanation:

To determine the force exerted on the particle, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). Mathematically, this can be expressed as:

F = m * a

Given that the mass of the particle is 5 kg and the acceleration is 10 m/s^2, we can substitute these values into the formula:

F = 5 kg * 10 m/s^2

F = 50 N

Answer:

Initial horizontal velocity should be approximately \(32.1\; {\rm m\cdot s^{-1}}\).

Velocity right before landing would be approximately \(37.3\; {\rm m\cdot s^{-1}}\).

(Assumptions: the vehicle from on a flat surface with an initial vertical velocity of \(0\); air resistance is negligible; \(g = 9.81\; {\rm m\cdot s^{-2}}\).)

Explanation:

Under the assumptions, acceleration of the vehicle in the vertical direction would be \(a_{y} = g = 9.81\; {\rm m\cdot s^{-2}}\). It is given that the vertical displacement of the vehicle would be \(x_{y} = (18.9 - 2.3)\; {\rm m} = 16.6\; {\rm m}\).

Rearrange the SUVAT equation \(x_{y} = (1/2)\, a_{y}\, t^{2}\) to find the time \(t\) the vehicle was in the air:

\(\begin{aligned}t &= \sqrt{\frac{2\, x_{y}}{a_{y}}} \\ &= \sqrt{\frac{2\, (18.9 - 2.3)}{9.81}}\; {\rm s} \approx 1.8397\; {\rm s}\end{aligned}\).

For the vehicle to exactly reach the opposite side, its horizontal displacement would be \(x_{x} = 60.0\; {\rm m}\), same as the width of the river.

Also under the assumption, horizontal velocity of the vehicle would be constant while in the air. To find the horizontal velocity \(v_{x}\) of the vehicle, divide the horizontal displacement by time the vehicle in the air:

\(\begin{aligned}v_{x} &= \frac{x_{x}}{t} \\ &\approx \frac{60.0}{1.8397}\; {\rm m\cdot s^{-1}} \\ &\approx 32.62\; {\rm m\cdot s^{-1}}\\ &\approx 32.6\; {\rm m\cdot s^{-1}} \end{aligned}\).

Right before landing, vertical velocity of the vehicle would be increase at a rate of \(a_{y} = 9.81\; {\rm m\cdot s^{-2}}\).

After \(t \approx 1.8397\; {\rm s}\) in the air (right before landing) the vertical velocity of the vehicle would be:

\(\begin{aligned}v_{y} &= u_{y} + a_{y}\, t \\ &\approx 0\; {\rm m\cdot s^{-1}} + (9.81)\, (1.8397)\; {\rm m\cdot s} \\ &\approx 18.05 \; {\rm m\cdot s^{-1}} \\ &\approx 18.0\; {\rm m\cdot s^{-1}}\end{aligned}\).

Apply the Pythagorean Theorem to find the velocity \(v\) of the vehicle right before landing:

\(\begin{aligned}v &= \sqrt{{v_{x}}^{2} + {v_{y}}^{2}} \\ &\approx \sqrt{(32.62)^{2} + (18.05)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 37.3\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer: A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car.

Explanation: NO EXPLANTION

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

Answer:

ac = ω²R = 3.5²(1.5) = 18.375 ≈ 18 m/s²

1. (a) Peixotto Media's charter authorizes the sale of 35,000,000 shares of stock, but it will begin by offering 20,000 of them at a par value of $4 per share. John William currently has $500 that he would like to invest in this company's stocks. John William will be able to purchase 125 shares of Peixotto Media stock.

(b) Privileges John William will have as a shareholder in Peixotto Media are Voting Rights, Dividend Payments, Capital Appreciation etc.

(a) In order to calculate how much stock John William will be able to purchase, we need to determine how many shares he can buy with his available funds. The par value per share is $4, so to find the number of shares he can buy, we divide his investment amount ($500) by the par value per share ($4):

Number of shares = Investment amount / Par value per share

Number of shares = $500 / $4 = 125 shares

Therefore, John William will be able to purchase 125 shares of Peixotto Media stock.

(b) As a shareholder in Peixotto Media, John William will have certain privileges. These privileges typically include:

Voting Rights: Shareholders are generally entitled to vote on matters that affect the company, such as electing the board of directors or approving major corporate decisions.

Dividend Payments: If the company declares dividends, shareholders may receive a portion of the company's profits in the form of dividend payments.

Capital Appreciation: If the value of the company's stock increases, shareholders can benefit from capital appreciation by selling their shares at a higher price than what they initially paid.

Information Rights: Shareholders have the right to access certain company information, such as financial reports or annual statements, to stay informed about the company's performance.

Liquidation Preference: In the event of the company's liquidation or bankruptcy, shareholders may have a claim on the company's assets after other obligations are fulfilled.

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The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.

The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.

The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km

The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km

The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.

Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km

The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km

The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east

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