An aluminium bar 600mm long1 with diameter 40mm, has a hole drilled in the centre of the bar. The hole is 30mm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/M^2 Calculate the total contraction on the bar due to a compressive load of 180KN

Answers

Answer 1

Answer:

Total contraction = 1.2277 mm

Explanation:

the solution is given in the picture below and it is more explanatory

An Aluminium Bar 600mm Long1 With Diameter 40mm, Has A Hole Drilled In The Centre Of The Bar. The Hole

Related Questions

11. A train car has the momentum of 50,000 kg*m/s and is moving at a velocity of 45 m/s what is
the mass of the train car?

Answers

20 hfzzigzgizugzgizgiziffuzufzufzufzifzifz

The Mass of the train car is 250,000

Because of you multiply the first digits it gives the first 3 numbers

Why echo sound cannot be heard in small room

Answers

They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the roomshould be 17.2 m. Obviously,in asmall room echoes cannot beheard.

The speed of sound is greater through a solid than through a gas because the molecules in a solid are

Answers

Answer

medium are much closer together

Explanation:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

How long would a simple pendulum need to be to have a period of 1. 0s.

Answers

Answer:

0.248 m

Explanation:

If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?

Answers

Answer:

speed

Explanation:

The distance traveled and time, the average speed of an object can be calculated. The correct answer would be option (A).

What is the average speed?

Average speed is defined as the total distance traveled by an object divided by the total time it took to travel that distance. This is a measure of the overall pace of an object's motion over a period of time.

Instantaneous speed is the limit of the average speed as the time interval approaches zero. In other words, it's the rate of change of an object's position with respect to time at a specific moment.

Average acceleration is defined as the change in velocity (speed in a certain direction) divided by the time interval over which that change occurred. This is a measure of the rate of change of an object's speed over a period of time.

Instantaneous acceleration is the limit of the average acceleration as the time interval approaches zero. In other words, it's the rate of change of an object's velocity at a specific moment.

In summary, with the given information of distance traveled and time, the average speed of an object can be calculated, but the instantaneous speed, average acceleration, and instantaneous acceleration cannot be calculated.

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The complete question would be as:

If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?

A. Average speed

B. Instantaneous speed

C. Average acceleration

D. Instantaneous acceleration

can force be expressed in units of pounds and newtons?

Answers

Yes, force can be expressed in units of pounds and newtons.

What are the units of force?

Force is an effect of the mass of object to accelerate in particular direction and can be expressed in the unit of pounds according to the FPS system of units. Newton is also a unit to express the force. SI unit of force is the newton and symbol is N.

Convert weight measured in pounds to equivalent in Newtons. In the formula for the determination of mass based on weight, mass is measured in Newtons. Weight is measured in Kilograms, and acceleration of gravity on Earth is measured as 9.8 meters per second squared and these are metric system unit measurements.

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what happens to the ballon when you squeeze the bottle?

Answers

Answer:

When you squeeze a bottle that has a balloon attached to its opening, the pressure inside the bottle increases. This increased pressure will cause the air molecules inside the bottle to move closer together, which in turn will cause the balloon to inflate.

If you continue to squeeze the bottle, the pressure inside the bottle will continue to increase, and the balloon will continue to inflate. However, if you squeeze the bottle too hard, the balloon may burst due to the excess pressure.

When you release the pressure on the bottle, the air molecules inside the bottle will spread out again, causing the pressure to decrease. As a result, the balloon will deflate back to its original size.

What state of matter has the highest energy? Lowest?

Answers

Answer:

The highest state of matter in energy is gas. The lowest is solid.

Explanation:

The reason why is because gas is the highest conductor of electricity (which is why we have lightning). However, solids don't conduct electricity very well.

What is the average speed of
a. an aircraft which travels 600 m in 10 seconds?
b. An athlete who runs 1000 m in 2 minutes?

Answers

Average Speed ( Velocity ) = [ Distance traveled ] ÷ [ time of the traveled distance in seconds ]

_______________________________

a .

AS = 600 ÷ 10

AS = 60 m/s

______________________________

b .

2 minutes = 2 × 60 = 120 seconds

AS = 1000 ÷ 120

AS = 100 ÷ 12

AS = 25 ÷ 3

AS = 25/3 = 8.33 m/s ( approximately )

The three-phase, 120 km long 50 Hz, and the nominal operating voltage of 380kVolt energy transmission line is the serial impedance z=0.05+j0.45Ω/km per unit length per phase and the shunt admittance is j3.4×10−6 S/km. At the end of the line, a load of 346MVA under a voltage between phases of 380kV and a power factor of cosϕ2​=0.8 is supplied. Using the π equivalent curciut model of the power transmission line, a.) Calculate the values of line A,B,C and D of the energy transmission line. b.) Calculate the voltage at the end of the line of the energy transmission line and the value of the voltage regulation.

Answers

The values of line A, B, C, and D in the π equivalent circuit model of the 120 km transmission line are: A = 6 Ω, B = 0 Ω, C = 0 S, and D = 0.816 × 10^(-3) S. The voltage at the end of the line is 153.883 kV, with a voltage regulation of 59.81%.

a) To calculate the values of line A, B, C, and D in the π equivalent circuit model of the power transmission line, we can use the given parameters and formulas.

Line impedance per unit length per phase, Z = 0.05 + j0.45 Ω/km

Shunt admittance per unit length, Y = j3.4 × 10^(-6) S/km

Length of the transmission line, L = 120 km

The impedance of the transmission line can be calculated as:

Z_line = Z * L = (0.05 + j0.45) * 120 = 6 + j54 Ω

The admittance of the transmission line can be calculated as:

Y_line = Y * L = j3.4 × 10^(-6) * 120 = j0.408 × 10^(-3) S

Using the π equivalent circuit model, we can equate the line impedance to A + B/2 and the line admittance to C + D/2.

Equating the real and imaginary parts, we get:

A + B/2 = 6 Ω

C + D/2 = 0.408 × 10^(-3) S

Solving these equations, we find:

A = 6 Ω

B = 0 Ω

C = 0 S

D = 0.816 × 10^(-3) S

Therefore, the values of line A, B, C, and D in the π equivalent circuit model are:

A = 6 Ω

B = 0 Ω

C = 0 S

D = 0.816 × 10^(-3) S

b) To calculate the voltage at the end of the transmission line and the voltage regulation, we can use the given load information and formulas.

Load apparent power, S_load = 346 MVA

Load power factor, cosϕ2 = 0.8

Nominal operating voltage, V_nominal = 380 kV

The load real power can be calculated as:

P_load = S_load * cosϕ2 = 346 MVA * 0.8 = 276.8 MW

The load reactive power can be calculated as:

Q_load = S_load * sinϕ2 = 346 MVA * sin(arccos(0.8)) = 207.6 MVAR

The voltage drop across the transmission line can be calculated using the π equivalent circuit model:

Voltage drop = (P_load * D) - (Q_load * B) = (276.8 MW * 0.816 × 10^(-3) S) - (207.6 MVAR * 0 Ω) = 226.117 kV

The voltage at the end of the line can be calculated as:

V_end = V_nominal - Voltage drop = 380 kV - 226.117 kV = 153.883 kV

The voltage regulation can be calculated as:

Voltage regulation = (V_nominal - V_end) / V_nominal * 100 = (380 kV - 153.883 kV) / 380 kV * 100 = 59.81%

Therefore, the voltage at the end of the transmission line is 153.883 kV, and the voltage regulation is 59.81%.

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a 32-kg child decides to make a raft out of empty 1.0-l water bottles and duct tape. neglecting the mass of the duct tape and plastic in the bottles, what minimum number of water bottles will the child need to be able to stay dry on the raft?

Answers

Ignoring the mass of duct tape and plastic in the bottles, a child will need at least 4 water bottles to stay dry on the raft. The child will need at least four water bottles to stay dry on the raft.

The buoyancy force exerted by the water on the raft must be greater than or equal to the weight of the child to keep the child afloat and dry on the raft. The buoyancy force is given by Archimedes' principle, which states that it is equal to the weight of the water displaced by the raft.

The volume of each 1.0 L water bottle is 0.001 m^3. The density of water is approximately 1000 kg/m^3. Therefore, each water bottle has a buoyant force of:

Buoyant force = Volume of water displaced x Density of water x Acceleration due to gravity

Buoyant force = 0.001 m^3 x 1000 kg/m^3 x 9.81 m/s^2

Buoyant force = 9.81 N

To find the minimum number of water bottles needed to keep the child afloat, we need to divide the weight of the child by the buoyant force of one water bottle:

Minimum number of water bottles = Weight of child / Buoyant force per bottle

Minimum number of water bottles = 32 kg / 9.81 N

Minimum number of water bottles = 3.26 (rounded up to 4)

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Assume you have 3 light bulbs connected in a series circuit to a battery.
What can you say about the current through each light bulb?
Current varies through all bulbs
There is no current through the bulbs
Current is the same through all bulbs

Answers

Answer:

Current is the same through all bulbs

Explanation:

Because it's a series circuit, the current traveling through the circuit doesn't change. In a parallel circuit, however, the current would not be the same due to the different 'paths' of the circuit.

Write the dimension of a / b in the x = at + bt2. Where x is the distance and t is the time?​

Answers

The dimension of a/b where x is the distance and t is the time is T

Given the expression

x = at + bt²

where

x is the distance

t is the time

Based on the homogeneity principle, the expression on the left-hand side must be equal to that on the right. Hence;

x = at

\(a = \frac{x}{t}\)

Since x is the distance and distance is measured in metres, the dimension equivalent will be the length 'L'

Since t is the time and time is measured in seconds, the dimension equivalent will be the seconds 'T'

\(a=\frac{L}{T}\)

Similarly;

x  = bt²

\(b=\frac{x}{t^2}\\b=\frac{L}{T^2}\)

Next is to get a/b;

\(\frac{a}{b} = \frac{L}{T} \div \frac{L}{T^2}\\\frac{a}{b} = \frac{L}{T}*\frac{T^2}{L} \\\frac{a}{b} =\frac{T^2}{T}\\\frac{a}{b} =T\)

Hence the dimension of a/b is T

the force of gravity between two objects decreases rapidly when

Answers

The force of gravity between two objects decreases rapidly when the distance between them increases.

The force of gravity is the force of attraction between two objects with mass. Gravity holds the planets in orbit around the sun. It holds moons in orbit around their planets. It is also what brings apples falling from trees and makes objects land on the ground. Gravity is what keeps all of the planets in orbit around the sun. The sun's gravity is what keeps the planets in orbit around it. The planets are constantly moving in an oval-shaped orbit. That is what keeps each planet in a path that doesn't run into the others.

Gravity is a force of attraction between two objects with mass. It is proportional to the product of the masses of two objects and inversely proportional to the square of the distance between them. According to the law of gravity, the force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Therefore, the force of gravity between two objects decreases rapidly when the distance between the objects increases.

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Reset all. Set the force back to 1 N. 14. Hit start, wait about 2 seconds, and set the brake force to 1 N. Hit enter and observe. 15. Describe the motion of the wheel: ______________________________________ 16. What happened to the acceleration vector

Answers

In the given scenario, if the force is reset back to 1 N, hit start and then set the brake force to 1 N, and then hit enter, the motion of the wheel will either be zero (if the brake force is applied) or it will be in a state of constant velocity (if no brake force is applied).

In this scenario, the acceleration vector will be zero since there is no force acting on the object.

When a force acts on a body, it can cause it to either change its velocity or change its direction, or both.

If no force acts on the body, the object will remain in a state of rest or constant motion.

In the given scenario, if there is no force acting on the wheel, it will remain in a state of constant motion.

Therefore, the acceleration vector will be zero.

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In general, sound
travels faster through

Answers

Answer:

solids

Explanation:

the particles of solid are closely packed , so it is much more easier to transfer sound wave from one particle to another compared to air and water which the particles are farther away from each other .

A 4000-kg car bumps into a stationary 6000kg truck. The Velocity of the car before the collision was +4m/s and -1m/s after the collision. What is the velocity of the truck?

Answers

Answer:

-4.33m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are their respective velocities

v is the final velocity

From the question;

m1 = 4000kg

m2 = 6000kg

u1 = 4m/s

u2 = ?

v =-1m/s

Substitute into the formula and get u2

4000(4)+6000u2 = (4000+6000)(-1)

16000 + 6000u2 = -10000

6000u2 = -10000-16000

6000u2 = -26000

6u2 = -26

u2 = -26/6

u2 = -13/3

u2 = -4.33m/s

Hence the velocity of the truck is -4.33m/s

Circular Motion A 650-kg car moving at 8.5 m/s takes a turn around a circle with a radius of 48.0 m. Determine the acceleration acting upon the car. Use a = v2/ r

Answers

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

\(a=\frac{v^2}{r}\) and filling in

\(a=\frac{(8.5)^2}{48.0}\) and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

The Earth rotates on its axis once every 24 hours. Due to this motion, roughly how many full hours would you expect to pass between two subsequent high tides at any given location on the Earth

Answers

The rotation of the Earth on its axis causes a periodic change in the position of the Moon and the Sun relative to any given location on the Earth's surface.

Earth is typically viewed as a massive, rotating, and gravitationally-bound celestial body that orbits around the sun. It has a radius of approximately 6,371 kilometers and a mass of approximately 5.97 x 10^24 kilograms. Earth's rotation on its axis produces day and night cycles, and its orbital motion around the sun produces the yearly cycle of seasons.

Earth's gravity plays a crucial role in many physical phenomena, such as tides, atmospheric pressure, and the motion of objects on its surface. Additionally, Earth's magnetic field helps to protect the planet from the charged particles of the solar wind. In terms of energy, Earth receives radiation from the sun and emits radiation in the form of heat.

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a block of mas 3 m can move without friction on a horizontal table. this blockis attached to another block of mass 33m by a cord to another block of mass 33m by a cord that passes over a frictionless pulley as shown. if the masses of the cord and the pulley are negligible, what is the magnitude of the acceleration of the descending block

Answers

The magnitude of the acceleration of the descending block is (5/33) times the acceleration due to gravity.

The force of gravity acts on both blocks, but since the pulley is frictionless and the cord has negligible mass, the tension in the cord must be the same on both sides of the pulley. Let's assume that the descending block of mass 33m has an acceleration of a and the ascending block of mass 3m has an acceleration of a'.

The net force acting on the descending block is the difference between the force of gravity and the tension in the cord. Therefore, we can write:

(33m)g - T = (33m)a

where g is the acceleration due to gravity and T is the tension in the cord. Similarly, the net force acting on the ascending block is:

T - (3m)g = (3m)a'

Since the tension in the cord is the same on both sides of the pulley, we can equate T in the two equations above to get:

(33m)g - (3m)g = (33m)a + (3m)a'

Simplifying, we get:

a' - a = (10/33)g

But we know that the blocks are connected by a cord that cannot stretch or compress, so the acceleration of the two blocks must be the same in magnitude. Therefore, a' = a, and we can solve for a:

2a = (10/33)g

a = (5/33)g

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What is a software program that contains DNA profiles of convicted offenders, missing persons, crime scene evidence, and other sources?
Group of answer choices

AFIS

ABLE

CODIS

GGNST

Answers

Answer:

CODIS should be the answer

A marksman holds a 3.00 kg rifle loosely, so that we can ignore any horizontal external forces acting on the rifle–bullet system. He fires a bullet of mass 5.00 g horizontally with a speed vbullet=300m/s.
The same rifle fires a bullet with mass 10.5 g at the same speed as before. For the same idealized model, find the ratio of the final kinetic energies of the bullet and rifle.

Answers

The final kinetic energy of the rifle is about 3.48 times greater when firing the heavier bullet.

We can use the conservation of momentum to find the velocity of the rifle after the bullet is fired. Since the rifle is initially at rest, the total momentum before the bullet is fired is zero. After the bullet is fired, the total momentum is:

\(p = mvbullet + MVrifle\)

where m is the mass of the bullet, vbullet is its velocity, M is the mass of the rifle, and Vrifle is the velocity of the rifle after the bullet is fired. Since there are no horizontal external forces acting on the rifle-bullet system, the total momentum is conserved, so we have:

0 = mvbullet + MVrifle

Solving for Vrifle, we get:

\(Vrifle = -mvbullet/M\)

Note that the negative sign indicates that the rifle moves in the opposite direction of the bullet.

The kinetic energy of an object is given by:

\(K = (1/2)mv^2\)

where m is the mass of the object and v is its velocity. The ratio of the final kinetic energies of the bullet and rifle is:

\(Kbullet/Krifle = (1/2)mvbullet^2 / (1/2)MVrifle^2\)

Substituting the expression for Vrifle that we found above, we get:

\(Kbullet/Krifle = (m/M)(vbullet/Vrifle)^2\)

For the first bullet, we have m = 5.00 g = 0.005 kg and vbullet = 300 m/s. Substituting these values, we get:

Kbullet/Krifle = (0.005 kg / 3.00 kg) (300 m/s / (-0.005 kg / 3.00 kg))^2

Simplifying, we get:

Kbullet/Krifle = 0.0025

For the second bullet, we have m = 10.5 g = 0.0105 kg and vbullet = 300 m/s. Substituting these values, we get:

Kbullet/Krifle = (0.0105 kg / 3.00 kg) (300 m/s / (-0.0105 kg / 3.00 kg))^2

Simplifying, we get:

Kbullet/Krifle = 0.0087

Therefore, the ratio of the final kinetic energies of the bullet and rifle for the two cases is:

0.0087 / 0.0025 = 3.48

So the final kinetic energy of the rifle is about 3.48 times greater when firing the heavier bullet.

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If a car moves 12 km north, 19 km east, and 12 km south, what is its displacement?

Answers

Answer:

19 km.

..............

Explanation:

.....

If a car moves 12 km north, 19 km east, and 12 km south, what is its displacement?

Answer:The Distance is 43 and displacement is 5km south

Explanation: To find the distance you add up all the numbers which was 43 and to fine the displacement subtract all the numbers and since all the other numbers were out expect for -5 which was south you would put 5 km south , if the number has a negative on it , it doesnt matter.

A truck with a mass of 2.00 × 103 kilograms is traveling at +19.0 meters/second along a road. It hits a stationary sedan with a mass 9.90 × 102 kilograms. If the truck and the sedan stick together after the collision, what is the final velocity of the two together?

Answers

Answer:

This one's easy

The final velocity of the truck and the sedan together is +7.19 m/s. This can be calculated using the law of conservation of momentum: m1v1 + m2v2 = (m1+m2)vf, where m1 and m2 are the masses of the truck and the sedan respectively, v1 is the velocity of the truck, v2 is the velocity of the sedan (which is 0 in this case) and vf is the final velocity of the truck and the sedan together.

If an object moves 21m north 16m east and 26m south what is the displacement of the object?

Answers

Explanation:

the net displacement of an object is

X-coordinate is

16.

Y-coordinate is

21-26=-5.

The magnitude of displacement is

d=√(〖16〗^2+(-5)^2 )=17 blocks.

The direction is

θ=tan^(-1)⁡〖5/16〗=17° east of south.

therefore, I think it helps you.

Complete the program to calculate and print the volume and surface area of a rectangular box, each rounded to the nearest tenth (1 decimal place).
The starter code already prompts the user and takes in the dimensions of the box (length, width, and height) as three double-value inputs. You need to do the calculations and print the results. Use the printf() command (described in chapter 3 of the book) to print the results with the correct rounding.
Sample output:
Enter the dimensions of a box, in centimeters:
Length?
8.5
Width?
5
Height?
3.4
Volume = 144.5 cm^3
Surface Area = 176.8 cm^2

Answers



Here's the completed program to calculate and print the volume and surface area of a rectangular box, each rounded to the nearest tenth (1 decimal place):

The program uses a Scanner object to get the user input for the dimensions of the box. It then uses the input values to calculate the volume and surface area of the box using the appropriate formulas. The printf() method is used to format the output and round the values to one decimal place.
To calculate the volume of the box, we simply multiply the length, width, and height values together. To calculate the surface area, we use the formula: Surface Area = 2 * (length * width + length * height + width * height) This formula accounts for the six faces of the rectangular box.


Here's the code snippet that demonstrates the calculations and print statements:
```java
// Assume that length, width, and height are already provided by the user
double volume = length * width * height;
double surfaceArea = 2 * (length * width + length * height + width * height);
// Print the volume and surface area with 1 decimal place rounding
System.out.printf("Volume = %.1f cm^3%n", volume);
System.out.printf("Surface Area = %.1f cm^2%n", surfaceArea).

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A body of mass 5 kg moving with velocity 10m/s attains a velocity of 30m/s in 20 seconds, after applying the force. The amount of force applied will be:


a 10N

b 20N

c 5N

d 15N​

Answers

Answer↷

c) 5N

➦I hope it seemed helpful to you!

Show that liquid pressure is directly
proportional to height of liquid in a vessel.​

Answers

Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

So

P=dhg

So we have shown that liquid pressure is directly  proportional to height of liquid in a vessel.​

1. A 500.0 g metal block absorbs 5.875 × 103 J of heat to raise its temperature by 50.0 K. What is the substance? Show your work.
Specific Heats of Selected Substances
Substance
C [J/(kg·K)]
Water (ice)
2,060
Iron
450
Aluminum
897
Gold
130
Copper
385
Silver
235
Ammonia (liquid)
4,700
Water (liquid)
4,180
Water (steam)
2,020
Lead
128

Answers

The name of the substance is silver based on the specific heat capacity value.

What is the specific heat capacity of the substance?

The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.

Q = mcΔθ

where;

m is the mass of the substancec is the specific heat capacity of the substanceΔθ is the change in temperature

c = Q / mΔθ

The specific heat capacity of the substance is calculated as;

c = (5875 J ) / ( 500 g x 50 )

c = 0.235 J/kgK

The substance that has the same specific heat capacity calculated above is silver.

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A student following on her treasure map, starts at the origin and walks the following routes

- 18 meter North (0=90)
- 17 meter West (0=0)
How far away are they from their starting positions

Answers

Answer:

= 24.76m

= 2476 cm

Explanation:

18 meters from point of origin = 18m north 90 degrees?

17 meters from point of origin = 17m west 0 degrees?

                                                                                                        _

If these routes are one after the other then we get a triangle  |

18 side and 17 side

This means we need to do Pythagoras Theorem.

18^2 + 17^2 = c^2

sqrt 324 + sqrt 289 =  c^2

c^2 = sqrt 613 = 24.7588368

= 24.76m

Other Questions
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