An angry soccer player uses dynamite to blow the rival teams stadium apart after a close loss. Debris from the explosion flies off in all directions and is later found at distances as far as 50 m from the explosion. Estimate the maximum speed at which debris was blown outward by the explosion.

Answers

Answer 1

Answer:

The maximum speed is  \(u = 22 \ m/s\)

Explanation:

From the question we are told that

   The distance covered by the debris is \(R = 50 \ m\)

   

The maximum range of the debris projectile is mathematically represented as

      \(R = \frac{ u^2 sin^2 \theta }{g}\)

At maximum  \(\theta = 90 ^o\)

Now making u which is the maximum speed at which debris was blown outward by the explosion.

  we  have

      \(u = \sqrt{\frac{R * g }{ sin ^2 \theta } }\)

substituting values

          \(u = \sqrt{\frac{50 * 9.8 }{ [sin 90] ^2} }\)

        \(u = 22 \ m/s\)


Related Questions

Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!


Here is a function machine.



Input : multiply by 6. Subtract 80: output



The input is the same as the output. Find the input.


Also can you please show me an easy to work out these type of questions

Answers

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?

Answers

Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

A rock is shot straight upward with sling-shot. The intial velocity is 24.5 m/s where the downward
acceleration due to gravity is 9.81 m/s2. What is the rock'sdisplacement after 1.00 s?

Answers

Answer:

Explanation:

If launch spot is origin and UP the positive direction.

s = s₀ + v₀t + ½at²

s = 0 + 24.5(1.00) + ½(-9.81)(1.00²)

s = 19.595

rounding to the 3 significant digits of the question numerals

s = 19.6 m  upward

Which of these actions will increase friction? Select three options. scratching a surface to make it rougher polishing a surface to make it smoother increasing the size of a flying object adding extra weight to an object placing oil between two surfaces

Answers

Answer:

A, c, d

Explanation:

edge 2022

The actions which will increase friction such as scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object. Thus, the correct options are A, C, and D.

What is Friction?

Friction is the force which is resisting the relative motion of two solid surfaces, fluid layers, and the material elements which are sliding against each other. There are several types of friction including dry friction, which is a force that opposes the relative lateral motion of two solid surfaces in contact.

The actions which will increase the friction include scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object.

Therefore, the correct options are A, C, and D.

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Six identical elements are connected in a battery whose internal resistance is 6Ω. Resistors R₁=14Ω and R₂ are connected to the battery, the total resistance of the external circuit is R=7Ω and the current flowing in it is 4 A. Determine the resistance of the second resistor and the internal EDS of the elements .

Six identical elements are connected in a battery whose internal resistance is 6. Resistors R=14 and

Answers

Answer:

Using Ohm's Law, we can calculate the voltage of the battery as V = IR = (4 A)(7 Ω) = 28 V.

The total resistance of the circuit is R = R₁ + R₂ + r, where r is the internal resistance of each element.

We know that R₁ = 14 Ω and R = 7 Ω, so we can solve for R₂:

R₂ = R - R₁ = 7 Ω - 14 Ω = -7 Ω

This is a negative resistance, which doesn't make sense physically. However, it indicates that there is an error in the problem or the calculations.

To find the internal EDS of the elements, we can use the equation:

V = ε - Ir

where V is the voltage of the battery, ε is the internal EDS of each element, I is the current flowing in the circuit, and r is the internal resistance of each element.

We know that V = 28 V, I = 4 A, and r = 6 Ω, so we can solve for ε:

ε = V + Ir = 28 V + (4 A)(6 Ω) = 52 V

Therefore, the internal EDS of each element is 52 V.

Question 16 of 17
Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance of 4.00 mOhm. Its interior is split into three equal areas, with magnetic fields B₁, B₂, and B. The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B, of the three fields with time t; the vertical axis scale is set by B, = 3.00 μT
and B-2.50B, What are the
(a) the magnitude and
(b) direction of the current induced in the wire?

Question 16 of 17Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance

Answers

For the magnetic fields:

(a) 53.8 A(b) The induced current will flow counterclockwise.

How to determine magnitude and direction?

From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:

emf = -dΦ/dt

where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.

The magnetic flux through each of the three regions can be calculated as follows:

Φ₁ = B₁WH/3

Φ₂ = B₂WH/3

Φ₃ = BWH/3

The total magnetic flux through the wire is:

Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3

Taking the time derivative of the magnetic flux:

dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)

Substituting the given values:

dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V

The induced emf is equal to the product of the current and the resistance of the wire:

emf = IR

Solving for I:

I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A

The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.

As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.

Therefore, the direction of the induced current will be counterclockwise.

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An astronaut weighing 190 lbs on Earth is on a mission to the Moon and Mars.

Required:
a. What would he weigh in newtons when he is on the Moon?
b. How much would he weigh in newtons when he is on Mars, where the acceleration due to gravity is 0.38 times that on Earth?

Answers

Answer:

The weight is defined as:

W = m*g

where:

m = mass

g = gravitational acceleration.

We know that in Earth the astronaut weights 190 lb-f (this is force, not mass, the correct unit here is 190 lb*m/s^2)

then:

190 lb*m/s^2 = m*9.8m/s^2

(190 lb*m/s^2)/(9.8m/s^2) = 19.39 lb

Now we know the mass of the astronaut.

a) wieght on the moon in Newtons.

Newtons uses kilograms as the units of mass, then we need to rewrite the mass of the astronaut in kg.

we know that 1lb = 0.454 kg

Then 19.39 lb is equal to: 19.39*0.454 kg = 8.8 kg

We know that the acceleration due to gravity on the Moon is one-sixth that on Earth.

then: g = (9.8m/s^2)/6

And the weight of the astronaut in the moon will be:

W = 8.8 kg*(9.8m/s^2)/6 = 14.37 N

b) The weight on mars, where the acceleration due to gravity is 0.38 times that on Earth, we have:

g = (9.8m/s^2)*0.38

then the weight will be:

W = 8.8kg*(9.8m/s^2)*0.38 = 32.77 N

Rotation axis. Big disk on the bottom M2 and small disk on the top M1 or mass1. Angular frequency of M₁ is zero.  M₂ initial angular frequency is Wi = 6π rad/s. Two objets both can spine freely in the axis someone is holding M1  and M2 is fixed on the axis. So M1 can slide down the axis and M₂ is fixed its rotating. Surface of M₂ is rough like sand paper but bottom of M1 surface is soft and it can rub on M₂ rough surface. then M1 disk is dropped on M2. then both disks are rotating and M1 cant slipe because of M2 rough surface. find wf final anular frequency of the system​

Rotation axis. Big disk on the bottom M2 and small disk on the top M1 or mass1. Angular frequency of

Answers

The final angular frequency of the system is 3π/2 rad/s. Moment of inertia increased, frictional torque decreased angular momentum, conservation of energy equation used.

At the point when M1 is dropped onto M2, the two circles will be coupled together and pivot as a solitary framework. The complete precise force of the framework should be saved. At first, just M2 was turning with a precise recurrence of Wi = 6π rad/s, while M1 was very still, so the underlying rakish force was L = I2 * Wi, where I2 is the snapshot of dormancy of M2.

At the point when M1 is dropped onto M2, the snapshot of latency of the framework expands, so to preserve rakish energy, the precise recurrence of the framework should diminish. The last rakish recurrence can be tracked down utilizing the preservation of precise force condition: L = I1 * wf + I2 * wf, where I1 is the snapshot of dormancy of M1 and wf is the last rakish recurrence of the framework.

Since M1 is sliding on the unpleasant surface of M2, there is frictional power that goes against its movement. This frictional power creates a force on the framework, which makes the precise energy decline. The last precise recurrence can be determined utilizing the preservation of energy condition, which compares the underlying active energy of the framework to the last dynamic energy of the framework:

0.5 * I1 * 0^2 + 0.5 * I2 * (6π)^2 = 0.5 * (I1 + I2) * wf^2

Improving on the situation and tackling for wf, we get:

wf = 3π/2 rad/s

Thusly, the last rakish recurrence of the framework is 3π/2 rad/s.

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Summarize the article in a paragraph .

Summarize the article in a paragraph .

Answers

Words are too small for me -_-

Which bWhich piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?

a 50kg couch
a 5kg dining chair
a 75kg dining table
an 10kg end tableest describes friction?

Answers

Answer:

The answer is C:  a 75kg dining table

Explanation:

Took it on the Unit Test: 2020

A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?

Answers

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.

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Your friend's Frisbee has become stuck 19 m above the ground in a tree. You want to dislodge the Frisbee by throwing a rock at it. The Frisbee is stuck pretty tight, so you figure the rock needs to be traveling at least 4.1 m/s when it hits the Frisbee.

If you release the rock 1.8 m above the ground, with what minimum speed must you throw it?

Answers

Answer:

18.36 m/s

Explanation:

We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:

1/2mv^2=mgh

m=mass

g=gravity

h=height

v=velocity

We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.

19m-1.8m=17.2m

Now we can plug in our variables to solve for velocity.

First we negate mass since its on both sides and cancels out leaving us with.

1/2v^2=gh

Plug in.

1/2v^2=(9.8)(17.2)

1/2v^2=168.56

v^2=337.12

v=18.36m/s

Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF

Answers

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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PLEASE ANSWER FAST
Select the statement(s) that accurately illustrate examples of energy transfer by radiation.
Heat emitted from a candle
Ocean waves on the surface of the sea Microwaves from a microwave oven
Radio waves transmitted between towers Sound waves from a car radio​

Answers

Heat emitted from a candle, Microwaves from a microwave oven, Radio waves transmitted between towers, Sound waves from a car radio.

Illustrate examples of energy transfer by radiation?The examples of energy transfer by radiation mentioned above are heat, microwaves, radio waves, and sound waves. Heat is the transfer of thermal energy from one object to another, usually through the process of convection, conduction, or radiation. Heat emitted from a candle is an example of energy transfer by radiation.Microwaves are electromagnetic waves that are used to heat food in a microwave oven. The microwaves are generated by an oscillating electric current and then radiated into the oven, where they are absorbed by the food. This energy is then converted into heat, which cooks the food. Radio waves are used to transmit information between towers, such as those used for cellular phone communication. The towers emit radio waves, which travel through the air, and the information they contain is then picked up by the towers on the other end. Sound waves are also a form of energy transfer by radiation. When a car radio is playing, sound waves are emitted from the radio, which then travel through the air to your ears. The process of energy transfer by radiation is called electromagnetic radiation. This is the process by which energy is transferred from one place to another in the form of electromagnetic waves. Examples of electromagnetic radiation include visible light, infrared radiation, ultraviolet radiation, x-rays, and gamma rays.

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In Edgar Allan pies the raven how does the speaker describe the bird by the end of the poem

Answers

In Edgar Allan Poe's poem "The Raven," the speaker's description of the bird evolves throughout the poem, reflecting the changing emotions and perceptions of the speaker. By the end of the poem, the speaker's description of the bird is one of eerie and unsettling admiration.

Initially, the speaker describes the raven as a "stately" and "ebony" bird, highlighting its majestic and imposing presence. As the poem progresses, the speaker's description becomes more vivid and eerie. The bird is referred to as a "prophet" and a "devil," emphasizing its ominous and supernatural qualities. Its eyes are described as "burning" and "demon's," intensifying the sense of unease.

Towards the end of the poem, the speaker's attitude towards the bird shifts. The raven becomes a symbol of despair and sorrow, representing the speaker's torment. The speaker's repeated questioning of the raven about the possibility of being reunited with his lost love, Lenore, showcases his desperation and longing for answers.

In the final stanza of the poem, the speaker describes the bird as a "thing of evil" and a "demon." This description emphasizes the bird's malevolent nature and its power to haunt the speaker's thoughts and torment his soul. Despite its dark and foreboding presence, the speaker cannot help but be captivated and entranced by the raven's presence.

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The most effective way to reduce waste is to not create it in the first place.

True
False

Answers

Answer:

True

Explanation:

If there isnt any waste it would reduce the quantity however the waste that is present needs to be dealt with so......

A body of mass 50 kg explodes and splits into three pieces. The first piece has a mass of 10 kg and a velocity of [-3,2] m/s, the second piece has a mass of 18 kg and a velocity of [5, -4] m/s. What is the velocity of the third piece?
. ​

Answers

The velocity of the third piece 2/11. (13 j - 15i)

What is velocity?Velocity is the directional velocity of a moving object  as an indicator of the rate of change of position  observed from a particular frame of reference and  measured by a particular time standard.Velocity is a vector representation of the displacement  an object or particle experiences with respect to time. The standard unit for velocity magnitude (also called velocity) is meters per second (m/s). Alternatively, centimeters per second (cm/s) can be used to express velocity magnitude.Simply put, velocity is the speed at which something moves in a particular direction. For example, the speed of a car traveling north on a highway, or the speed of a rocket  after launch.

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When is vertical velocity zero? Select all the apply

1. when an object changes direction.

2.the moment you kick a football in the air.

3. vertical velocity is zero initially when an object is dropped from a window.

4. the moment a ball rolls off a table.

5. the moment you throw a ball in the air.

Answers

Answer:

3

Explanation:

When the projectile reaches a vertical velocity of zero, this is the maximum height of the projectile and then gravity will take over and accelerate the object downward. The horizontal displacement of the projectile is called the range of the projectile, and depends on the initial velocity of the object.

Answer is 3

The velocity in the vertical direction begins to decrease as the object rises. At its highest point, the vertical velocity is zero. As the object falls toward Earth again, the vertical velocity increases again in magnitude but points in the opposite direction to the initial vertical velocity


Gold-198 is a radioactive isotope, and it has a half-life of about 2.5 days.
You have 100 grams of Gold-198. How many grams remain after 20 days?

3.125 grams
1.5625 grams
0.78125 grams
0.390625 grams

Answers

Answer: 0.390625 grams

Explanation:

A half-life of an element is the amount of time that it takes for half the mass of the element to decay.

Gold-198 having a half-life of 2.5 days therefore means that every 2.5 days, the mass is cut in half.

If there are 20 days, find out how many half-life periods there are:

= 20 / 2.5

= 8 periods

The half life is:

= Original mass * 0.5^number of half-life periods

= 100 * 0.5⁸

= 0.390625 grams

what is a shargaff rule

Answers

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Who is Chargaff ?

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is
pitched to the right with a velocity of 41.26 m/s.

Answers

The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

What is the momentum of the baseball?

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

m is the mass of the baseballv is the speed of the baseball

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

A 90.0 kg person is being pulled away from a burning building as shown in the figure below.
(a)
Calculate the tension (in N) in the first rope, T1, if the person is momentarily motionless. (Enter the magnitude only.)
_______N

(b)
Calculate the tension (in N) in the second rope, T2, if the person is momentarily motionless. (Enter the magnitude only.)
_______N

Answers

Answer:

Try doing 90.0/2xT1 and that soud get u the answer of T2

Explanation:

I hope that helps!

4. What force must be exerted on a 1500-kg car to make it move with
an acceleration
of 3.8 m/s²

Answers

The force must be exerted on a 1500-kg car to make it move with

an acceleration of 3.8 m/s² is 5700 N.

According to Newton's Second Law Of Motion,

The Force is directly proportional to the Change in Momentum,

Thus, F ∝ dp/dt

Now, Momentum p = mv

F = m*dv/dt

F = ma

Thus, Force is the product of mass and acceleration,

Mass of the car = 1500 kg

Acceleration of the car = 3.8 m/\(s^{2}\)

So, The force required will be = m*a = 1500 * 3.8 = 5700 N

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The transfer of energy from one organism to the next in an ecosystem begins with a producer. A producer is an organism that produces its own food. A consumer is an organism in a food chain that obtains energy from producers or other consumers; consumers may be herbivores or carnivores.
Which food chain correctly describes the flow of energy in an ecosystem?

A) grass → grasshopper → fish → human
B) grasshopper → fish → human
C) human → fish → grasshopper
D) human → grasshopper → fish → grass

Answers

Answer:

A.)

Explanation:

The answer is food chain A, as plants produce their own food using photosynthesis, therefore making them producers.  

A grasshopper then eats this grass, making it a consumer as it is obtaining its energy from the producer.  It is then eaten by a fish and a human.  This chain accurately describe the flow of energy in an ecosystem, as it goes, producer, consumer, consumer, consumer

Hope this helps a little

Answer:

sorry

Explanation:

patulong

write one example of base unit ​

Answers

Answer: Meter, kilogram, second are a few of the base units.

Which segment shows the substance changing from a gas to a liquid? X-Y Y-X W-X X-W

Answers

The segment that shows the substance changing from a gas to a liquid is Y-X. This is because during this segment, the temperature of the substance decreases, causing it to undergo condensation and change from a gas to a liquid state.

4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)​

Answers

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

How to find reaction?

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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A wire passes 45 C of charge every 0.58 s. How many amperes of current is passing through the wire during this time?

Answers

We will have the following:

\(A=\frac{45C}{0.58s}\Rightarrow Amp=\frac{2250}{29}Amp\Rightarrow A\approx77.59Amp\)

So there will be approximately 77.29 amperes passing through.

A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?

Answers

Answer:

The time taken for the package to reach the ground is 20.6s

Explanation:

Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :

\(distance = speed \times time\)

\(let \: distance = 105 \\ let \: speed = 5.10\)

\(105 = 5.1 \times t\)

\(5.1t = 105\)

\(t = 105 \div 5.1\)

\(t = 20.6 \: second \: (3s.f)\)

1) Which of the following is not true about vectors.a) Must have magnitude and direction.b) When doing math with vectors, we can usually treat the x and y components independently.c) If several vectors are added together, their order does not matter.d) The magnitude of a vector is the sum of the magnitude of its x and y components.2) Explain briefly your argument or reasoning.

Answers

a) A vector must have a magnitude and direction. A physical quantity with only the magnitude is called a scalar.

b) When doing the math we can treat the x and y components independently. We can use only x-component or only y-component for the necessary calculations. For example, the projectile motion. In projectile motion, we use the components of velocities independently.

c) We can add or subtract more than two vectors in any order. For example, If there are 3 vectors, A, B, and C then, from the associative law of vector addition,

\(\vec{A}+(\vec{B}+\vec{C})=(\vec{A}+\vec{B})+\vec{C}\)

d) The magnitude of the vectors is not the sum of their x and y components. Let vector A be represented as

\(\vec{A}=x\hat{i}+y\hat{j}\)

Where x and y are the x and y components of vector A respectively. And î and j cap are the unit vectors along the x and y direction respectively.

Then, the magnitude of vector A is given by,

\(A=\sqrt[]{x^2+y^2}\)

Thus the correct answer is option d. That is the statement in option d is not true.

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