An archer shoots an arrow with vertical velocity of 10 m/s and horizontal velocity of
30m/s. What is the maximum height the arrow reaches?

Answer:

1

Explanation:

it go up than down than up

Answer:

533.33 nm

Explanation:

Since dsinθ = mλ  for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.

Since the fringes coincide,

m'λ = m"λ'

λ' = m'λ/m"

= 10 × 640 nm/12

= 6400 nm/12

= 533.33 nm

The work done by the wind on Mikaela as she rounds the curve is zero.

The given parameters;

The work done by the wind on Mikaela as she rounds the curve is determined by applying work-energy theorem.

The change in kinetic energy of Mikaela = Work done by wind on Mikaela

\(\Delta K.E = W\\\\\Delta K.E = \frac{1}{2} m(v_f^2 - v_0^2)\)

The speed of Mikaela was constant; \(v_f = v_0\)

\(\Delta K.E = W = 0\)

Thus, the work done by the wind on Mikaela as she rounds the curve is zero.

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In order to find his weight, let's analyze the formula for the gravitational force between two bodies:

We can see that the gravitational force is inversely proportional to the square of the distance.

So, if the distance doubles, that means the gravitational force will decrease by a factor of 4.

Joe's weight on Earth is 720 N, so his weight on the aircraft would be:

Joe's weight would be 180 N.

Answer: Trail Braking!

Explanation: Trail braking is used to smoothly and gradually reduce brake pedal pressure at the end of a braking maneuver.

Option A. trail braking.

In four-wheel vehicles, trail braking is using the brakes past the corner entrance, as opposed to the normally taught practice of releasing the brakes before starting the turn. It creates weight transfer to the front tires, increasing their traction and reducing understeer.

Trail-braking allows a driver to brake later by extending the braking zone into the corner. It also improves the car's turn-in response by increasing the load on the front tires to maximize grip. Together, these result in higher corner entry speed and reduced time through the corner.

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The top surface moves relative to the bottom surface by 1.167 x 10⁻⁶ m.

The distance the top surface move relative to the bottom surface is calculated as follows;

shear strain = F/(αx)

where;

shear strain = (14 )/(1.2 x 10⁷ x 0.00117 m)

shear strain = 0.000997

The movement of the top surface;

top surface movement = shear strain x thickness

= 0.000997  x 0.00117 m

= 1.167 x 10⁻⁶ m

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Answer:

dimond and 21

Explanation:

Answer:

Explanation:

Out of the given options, A would not describe a physical property of a substance. How a substance reacts with another substance is a chemical property, whereas physical properties are intrinsic characteristics that can be observed or measured without changing the substance's identity. B, C, and D are examples of physical properties - shininess, color, and mass respectively.

Answer:

The mass formula is also given as m = F / a If acceleration itself is the gravity, then M = F / g

please mark me as brainleist

Answer:

1.8 m/s

An

Explanation:

We will use the given equation:

m1u1 + m2u2 = m1v1 + m2v2

Where m1 is the mass of the large marble, m2 is the mass of the smaller marble, u1 is the velocity of the large marble before the collision, u2 is the velocity of the smaller marble before the collision, v1 is the velocity of the large marble after the collision and v2 is the velocity of the large marble after the collision.

So, replacing the values, we get:

m1 = 0.06 kg

m2 = 0.03 kg

u1 = 0.7 m/s

u2 = 0 m/s

v1 = -0.2 m/s

Therefore:

So, solving for v2, we get:

Then, the velocity of marble B is 1.8 m/s

Granite will heat up the quickest among dry soil, granite, water, and wet soil due to its lower specific heat capacity.

To determine which substance will heat up the quickest among dry soil, granite, water, and wet soil, we need to consider their specific heat capacities. The substance with the lowest specific heat capacity will heat up the quickest.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a certain amount. Different substances have different specific heat capacities due to variations in their molecular structure and composition.

Water has a relatively high specific heat capacity of about 4.18 J/g°C, meaning it requires a significant amount of heat energy to raise its temperature. Dry soil and granite, on the other hand, have lower specific heat capacities compared to water.

Wet soil is a mixture of dry soil and water, and its specific heat capacity will lie between the values of dry soil and water. Since water has a higher specific heat capacity than dry soil, wet soil is expected to have a higher specific heat capacity than dry soil as well.

Therefore, based on the comparison of specific heat capacities, the substance that will heat up the quickest is granite. Granite has a lower specific heat capacity than water and wet soil, making it more susceptible to temperature changes. Dry soil and wet soil, including water, will heat up at a slower rate compared to granite.

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After thoroughly calculating we have come to find that, the tension in the string is 2.752 N

In physics, tension is defined as the pulling force transmitted axially by a string, cable, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object.

Tension can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements. Compression's opposite, tension, is possible.

We know that

Tension = (Mass × gravity) / cos∅

Here given that

Mass = 0.280kg

Gravity = 9.8 m/s²

∅ = 4.2°  

Lets substitute the values and we get

Tension = (280g × 9.8 m/s²) / cos4.2°  

Tension = 2.752 N

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Full question

A tetherball leans against the smooth, frictionless

post to which it is attached (Figure 1). The string is

attached to the surface of the ball such that a line

along the string passes through the center of the

ball. The string is 1.40 m long, and the ball has a

radius of 0.110 m with mass 0.280 kg. What is the

tension in the string?

Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m

Answer:

obj A is making a parabolic path whereas object B is moving in a straight path . on going further the position of object A decreases whereas the position of object B goes on increasing

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Speed = distance / time

Part 1: 40 km at 80 km per goir = 0.50 hours

Part 2: 40 km at 40 km per hour = 1 hour

The time of the trip was 1.5 hours

Total distance was 40 + 40 = 80 ins.

Speed = distance / time = 80/1.5 = 53.33 km/he ( round answer as needed)

The frictional force of the wind on water produces surface currents that travel in a pattern analogous to "wind currents".

Wind, temperature, water density, and the moon's gravitational pull may all affect ocean currents.

Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface. When wind constantly disturbs the surface of an ocean or lake, a wave crest is created.

Friction slows the wind, which also changes its direction. This phenomenon might lead to surface roughness variations along regional boundaries or turbulence in winds near the surface. Turbulence stirs the lower atmosphere.

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Answer:45 m/s north

Explanation:

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

The stiffer the spring is and the harder it is to stretch, the larger the spring constant.

Springs are pliable mechanical devices that regain their previous shape after deforming, i.e. after being stretched or compressed. They are an essential part of many different mechanical devices.

The well-known metal coil has evolved into an essential element in the modern world, appearing in everything from engines to appliances to tools to automobiles to medical equipment and even basic ball-point pens. The spring's ability to store mechanical energy accounts for its widespread use and applications.

Therefore, The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

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Answer:

yeah

Explanation:

Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it.

Answer:

Found this answer off of google, "Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it."

Hope this helps, have a great day and stay safe!

Also Happy Halloween! :) :D :3

Answer:

ratio variables

Ratio scale of measurement

Weight, height and distance are all examples of ratio variables. Data in the ratio scale can be added, subtracted, divided and multiplied. Ratio scales also differ from interval scales in that the scale has a 'true zero'. The number zero means that the data has no value point

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

4.8min

Explanation:

The police car is traveling at 100/km and is 1.6km away from red car that is traveling at 80/km

George burnt his fingertips so badly that he can't feel anything with them anymore, then the papillary layer part of his skin must have been damaged, therefore the correct answer is option A.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

As given in the problem George burnt his fingertips so badly that he can't feel anything with them anymore.

Option A is the appropriate response since George must have injured the papillary layer of his skin if his fingertips were burned so badly that he can no longer feel anything with them.

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Hi there!

a)
We can use the equation for the magnetic dipole moment to solve for the number of turns:
\(\mu_m = NIA\vec{n}\)

\(\mu_m\) = Magnetic dipole moment (0.194 Am²)

N = Number of loops (?)

A = Area of loop (4.0 cm²)

\(\vec{n}\) denotes the area vector, or the normal line perpendicular to the area.

We first need to convert cm² to m² using dimensional analysis.

\(4.0 cm^2 * \frac{0.01m}{1 cm} * \frac{0.01 m}{1cm} = 0.0004 m^2\)

Rearranging the equation to solve for 'N':

\(N = \frac{\mu_m}{IA}\\\\N = \frac{0.194}{(8.8)(0.0004)} = \boxed{55.11 \text{ turns}}\)

**Since we cannot have part of a turn, the coil has about 55 turns.

b)

For this, we can use the Right-Hand-Rule for current. Looking at the coil from the left with your curled fingers going around the coil with the fingertips pointing through and to the left in the direction of the magnetic moment, your thumb points in the COUNTERCLOCKWISE direction.

c)
Now, let's use the equation for the torque produced by a magnetic field:
\(\tau = \mu_m \times B\)

This is a cross-product, but since our magnetic field is perpendicular to the magnetic moment, we can disregard it.

Plugging in the values for the magnetic moment and the magnetic field:

\(\tau = 0.194 * 45 = \boxed{8.73 Nm}\)

d)

Using the other RHR (current, field, force), the coil will spin about its vertical axis in the field. In more detail, if you look at the coil from the left-hand side with its opening towards you, from this perspective, the left of the coil will come towards you, and the right side of the coil will move away.

Answer:

If the particle was projected at an angle of zero with the horizontal, that is the highest point of the trajectory, and (D) is correct.

To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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Projectile motion is the curved path motion of a body launched into the air near the Earth's surface and having a horizontal velocity.

Reason:

Given parameter are;

Initial velocity of the skateboarder, v₁ = 5.4 m/s

Inclination of the track, above the horizontal, θ = 48°

Height of the end of the elevated track, h ≈ 0.40 m

Path of the skateboarder when she leaves the track = Path of a projectile

Required:

Maximum height H to which she rises above the end of the track.

Solution;

From v² = u² - 2·g·h, at the end of the track where;

h = 0.40 m

u = Initial velocity = 5.4

g = 9.81 m/s²

We have;

v₂² ≈ 5.4² - 2 × 9.81 × 0.40 = 21.312

At the maximum height, H, we have;

\(\displaystyle v__y\) = 0

Therefore, from \(\displaystyle v__y\)² = \(\displaystyle u__y\)² - 2·g·H, where;

\(\displaystyle u__y\)² = 2·g·H

Which gives;

Therefore;

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