An astronaut on the surface of a large spherical asteroid fires a 5. 0 kg cannonball horizontally from a cannon. The asteroid has a diameter of 210 km , and has an acceleration due to gravity at its surface equal to one twelfth of the value on Earth

Answers

Answer 1

An astronaut on the surface of a large spherical asteroid fires a 5. 0 kg cannonball horizontally from a cannon, acceleration due to gravity at its surface equal to one twelfth of the value on Earth: the speed of the cannonball as it leaves the cannon, v ≈ 1410 m/s

Part A: To calculate the speed of the cannonball (v) for it to travel completely around the asteroid and return to its original location, we can use the formula for orbital velocity: v = sqrt(GM/R), where G is the gravitational constant, M is the mass of the asteroid, and R is the radius.

The asteroid's diameter is 210 km, so its radius is 105 km (or 105,000 meters). Since the acceleration due to gravity on the asteroid is 1/12th of Earth's, we can write GM/R = (1/12) * g, where g is Earth's acceleration due to gravity (9.81 m/s²). Solving for v, we get v ≈ 1410 m/s (to 3 significant figures).

Part B: To calculate the time it takes for the cannonball to travel around the asteroid, we can use the formula for orbital period: T = 2πR/v. Plugging in the values from Part A (R = 105,000 m, v = 1410 m/s), we get T ≈ 4700 seconds (to 3 significant figures).

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Complete question:

An astronaut on the surface of a large spherical asteroid fires a 5. 0 kg cannonball horizontally from a cannon. The asteroid has a diameter of 210 km , and has an acceleration due to gravity at its surface equal to one twelfth of the value on Earth

Part A

What must be the speed of the cannonball as it leaves the cannon, v, so that it travels completely around the asteroid and returns to its original location?

Give your answer in metres per second, to 3 significant figures.

Part B

How long does it take the cannonball to travel around the asteroid?

Give your answer in seconds, to 3 significant figures.


Related Questions

compared with the frequency of illuminating light on a sheet of transparent plastic, the frequency of light that is transmitted

Answers

The frequency of light that is transmitted through a sheet of transparent plastic is the same as the frequency of illuminating light. Transparent materials, like plastic, do not absorb light and therefore the frequency of light that passes through them remains unchanged.

What is transparent?

Transparency is a concept or value of being open and honest with others. It is the practice of being open, honest, and accountable with oneself and with others. Transparency involves communication between individuals and organizations in a way that is easily understood, accessible, and open to public scrutiny. Transparency is a key component of good governance, as it allows for public scrutiny and accountability, and encourages public participation in decision-making. Transparency also fosters trust in the government and promotes economic growth and development.

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A 1,725 kg car accelerates from 3.0 m/s for 4.4 s and reaches a velocity of 12.0 m/s. Ignoring friction, what is the applied force from the engine?

Answers

Given:

The mass of the car is m = 1725 kg

The initial velocity of the car is

\(v_i=\text{ 3 m/s}\)

The final velocity of the car is

\(v_f=\text{ 12 m/s}\)

The time is t = 4.4 s

To find the applied force.

Explanation:

The force can be calculated by the formula

\(F=\text{ ma}\)

Here, a is the acceleration.

The acceleration can be calculated as

\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ =\frac{12-3}{4.4} \\ =2.045\text{ m/s}^2 \end{gathered}\)

On substituting the values, the force applied will be

\(\begin{gathered} F=ma \\ =1725\times2.045 \\ =3527.625\text{ N} \end{gathered}\)

Thus, the applied force is 3527.625 N

What is the element notation of copper,lead, phosphuros,arsenic and barium.​

Answers

Answer:

Copper Cu

Lead Pb

Phosphorus P

Arsenic As

Barium Ba

Cu, Pb, P, As and Ba

Water flows in through a horizontal pipe of cross - sectional area 100cm^2. At the outlet section, the cross- sectional area is 5 cm^2. If the velocity of water at the larger cross-section is 1.25 m/s.

Answers

The velocity of water at the smaller cross-section is 25 m/s.

Area of larger cross section, A₁ = 100 cm²

Area of larger cross section, A₂ = 5 cm²

Velocity of water at larger section, v₁ = 1.25 m/s

According to equation of continuity,

A₁v₁ = A₂v₂

Therefore, the velocity of water at the smaller cross-section,

v₂ = A₁v₁/A₂

v₂ = 100 x 1.25/5

v₂ = 25 m/s

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PLEASE DO ASAP WILL GIVE BRAINLIEST!!!

An initially neutral and non-polarized conducting rod is moving to the right at a constant speed v through a large region that has a uniform magnetic field, as shown above. Which of the following statements correctly describes the motion of the particles within the rod and the resulting charge separation in the rod caused by this motion?

(A) Positively charged particles within the rod moved downward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.

(B) Negatively charged particles moved upward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.

(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.

(D) Negatively charged particles moved downward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.

PLEASE DO ASAP WILL GIVE BRAINLIEST!!!An initially neutral and non-polarized conducting rod is moving

Answers

Answer:

C

Explanation:

(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.

When a neutral and non-polarized conducting rod moves through a magnetic field, it will experience a force known as the Lorentz force. This force acts on the moving charges within the rod, and causes them to move perpendicular to both the direction of motion and the magnetic field. In this case, since the rod is moving to the right, and the magnetic field is pointing into the screen, the Lorentz force will act upward on the positively charged particles within the rod. This motion will cause a separation of charges in the rod, with the top having a positive charge and the bottom having a negative charge.

C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.

what two things does the strength of gravity depend on?

Answers

Answer:

i found this i hope it helps

Explanation:

The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.

Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what is its correct name? C1B4 (monocarbon tetrabromide) C1Br4 (monocarbon tetrabromide) CB4 (carbon tetrabromide) CBr4 (carbon tetrabromide)

Answers

Answer: \(CBr_4\) : carbon tetrabromide

Explanation:

\(CBr_4\) is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for \(CBr_4\) is carbon tetrabromide.

Answer:

Carbon tetrabromide ~ CBr4

Chlorine monofluoride~ ClF

Explanation:

EDGU 2021

Ice at 0 ∘
C and at a pressure 1 atm, has a density of 916.23 kg m −3
, while water under these conditions has a density 999.84 kg m −3
. How much work is done against the atmosphere when 10 kg of ice melt into water?

Answers

When 10 kg of ice melts into water, the work done against the atmosphere can be calculated using the difference in densities between ice and water. By considering the volume change during the phase transition, the work done against the atmospheric pressure can be determined.

When ice melts into water, it undergoes a phase transition from a solid to a liquid state. This transition involves a change in volume due to the difference in density between ice and water. The work done against the atmosphere can be calculated by considering the pressure exerted by the atmosphere and the change in volume.

The density of ice is 916.23 kg/m³, while the density of water is 999.84 kg/m³ at 0°C and 1 atm of pressure. The volume occupied by 10 kg of ice can be determined by dividing the mass by the density of ice. Similarly, the volume occupied by 10 kg of water can be calculated using the density of water.

By subtracting the initial volume of the ice from the final volume of the water, we can find the change in volume during the melting process. This change in volume multiplied by the atmospheric pressure gives us the work done against the atmosphere.

It is important to note that the work done against the atmosphere is positive because the system is doing work on the surroundings. Thus, the magnitude of the work done against the atmosphere can be calculated by taking the absolute value of the work.

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Now observe the graph of the vertical velocity against time (vy,vs.t).To do so click y label on the vertical axis and select "vy" velocity y-component from the pop-up menu What do you observe about the vertical velocity of the ball? what does this say about the mathematical relationship between y-velocity and time here

Answers

The vertical velocity of the ball will decrease with time.

The relation between the vertical velocity and time is given as,

\(v_y=u_{}-gt\)

Here, u is the initial velocity and g is acceleration due to gravity.

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Answers

What happened the thing is kinda glitched

What force is needed to give a 0.25 kg arrow an acceleration of 196 m/s² question 10 options: 0.25n 49n 196n 748n

Answers

The force that is needed to accelerate the arrow is 49 Newtons.

To determine magnitude of the force needed to give a 0.25 kg arrow an acceleration of 196 m/s², we can use the equation of force:

F = ma

where F is the force, m is the mass, and a is the acceleration.

Given that m = 0.25 kg and a = 196 m/s², we can substitute these values into the equation and solve for F:

F = (0.25 kg)(196 m/s²)

F = 49 N

So the force needed to give a 0.25 kg arrow an acceleration of 196 m/s² is 49 N. This is the correct answer out of the options given.

To arrive at this answer we used Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Thus, we were able to use the equation "F = ma" (where F is force, m is mass and a is acceleration) to solve for the force required to accelerate the arrow at 196 m/s².

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Who ever helps can you help me with some other ones?

Who ever helps can you help me with some other ones?

Answers

Answer:

2 seconds

Explanation:

It only went up by 2

Urgent!!!!
Please HELP

Urgent!!!!Please HELP

Answers

Noooooooooooooooooooooooooooooooooo

what does it mean if you hear thunder and then see lightning at almost the same time? (we are studying the nature of energy waves)

Answers

Answer:

If you hear thunder and then see lightning at almost the same time, this means that the lightning was likely close by. Thunder is the sound created by lightning, which is the discharge of energy between two clouds or between a cloud and the ground. Because sound travels much slower than light, it takes longer for the thunder to be heard, which is why we usually hear thunder after seeing a flash of lightning. This indicates that the lightning was very close in proximity and that you should be aware of the potential danger of an impending thunderstorm.

What does a line coming up and getting steeper represent on a distance/time graph?

Answers

Greater slope, Greater/faster change.

Suppose to a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how would the liquid raise at standard pressure?​

Answers

Answer:

           h = h₀/2,  the liquid column rises half the height

Explanation:

Pressure is defined as force per area,  

         P = F / A

in a barometer the force is the weights of the liquid column

         F = W = mg

         P = m g/A

if we use the definition of density

         ρ = \(\frac{m}{A h}\)

         \(\frac{m}{A}\) = ρ h

we substitute

         P = ρ g h

Let's use the index o for the mercury

         P₀ = ρ₀ g h₀

when we change the liquid for another with

          ρ = 2ρ₀

the pressure expression is

         P = 2ρ₀ g h

in the problem they indicate that the pressure is equal to the initial P = P₀

we substitute

           ρ₀ g h₀ = 2ρ₀ g h

           h₀ = 2h

           h = h₀/2

the liquid column rises half the height

A 3.2 kg ball that is moving straight upward has 17 J of kinetic energy and its total mechanical energy is 25 J.

Answers

Answer:

Height = 0.25 metres

Speed = 3.26 m/s

Explanation:

Kinetic energy = 17 joules

Mechanical energy = 25

Potential energy = 25-27 = 8

Potential energy PE = m*g*h

8 = 3.2x9.81xh

8 = 31.392h

We divide through by the value of h to get height

8/31.392 = h

h = 0.25 metres

We solve for speed = velocity

Kinetic Energy = 1/2mv²

17 = 0.5x3.2xV²

17 = 1.6v²

V² = 17/1.6

V² = 10.625

V = √10.625

Velocity = 3.26m/s

What is the numeric value of the prefix "micro"?
a. 0.00001
b. 0.000001
c. 0.0001
d. 0.001

Answers

What is the numeric value of the prefix "micro"?

a. 0.00001

b. 0.000001 ✓"Micro" is a prefix that is used to indicate a value of the factor 10^-6 and means very minute.

c. 0.0001

d. 0.001

Which acid is naturally found in foods and can be safe to eat?

Answers

Answer:

Citric

Explanation:

Citric and acetic acids are naturally found in foods and can be safe to eat.

Answer:

citrus

Explanation:

i think i am sure

Charge q1=1.00 nC is at x1 = 0 and charge q2 = 3.00 nC is at x2 = 2.00 m. At what point between the two charges is the electric field equal to zero?

Answers

Charge q1=1.00 nC is at x1 = 0 and charge q2 = 3.00 nC is at x2 = 2.00 m. At a point 1.00 m away from charge q1, the electric field will be equal to zero.

This can be determined by calculating the electric field at this point, which is given by:E = (1/4πεo) x (q1/x2 - q2/x2), where εo is the electric permittivity of free space and x is the distance from charge q1.
At x = 1.00 m, E = 0.

An electric field is defined as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, which is either attracting or repelling them. It is also refers as the physical field for a system of charged particles.

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Answer Questions below

Answer Questions below

Answers

Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

Students perform an experiment in which they drop two eggs with equal mass from a balcony. in the first trial, the egg hits the ground and breaks. in the second trial, the egg hits a foam cushion and does not break or bounce. what conclusions about impulse can the students make? the impulse was greater in the first experiment because the egg broke. the impulse was greater in the second experiment because the egg did not break. the impulse was the same in both experiments because the egg came to a stop. the impulse cannot be determined without the mass and velocity of the eggs.

Answers

The impulse was greater in the first experiment because the egg broke.

What is impulse?

The term impulse is defined a the product of the force and time. We know that the impulse is high when a large force acts for a short time.

From the experiment if the students, we can conclude that  the impulse was greater in the first experiment because the egg broke.

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Answer:

The impulse was the same in both experiments because the egg came to a stop.

Explanation:

test

A crane raises a crate with a mass of 180 kg to a height of 15 m. Given that
the acceleration due to gravity is 9.8 m/s2, what is the crate's potential energy
at this point?
O A. 276 J
B. 198,450 J
O c. 1,152J
O D. 26,460 J

Answers

Answer:

D

Explanation: Solve it in apex

The potential energy of crate with a mass of 180 kg at a height of 15 m will be 26460 joules.

What is Potential Energy?

The potential energy of a body at height 'h' above the earth surface having mass 'm' is -

E[P] = mgh

The amount of work done in moving the body to height 'h' is equal to E[P] and it is stored inside the body in the form of potential energy.

Given is a crane that raises a crate with a mass of 180 kg to a height of

15 m.

Crate's mass = [M] = 180 Kg

Height at which crate is taken = [h] = 15 m

Acceleration = [g] = + 9.8 m/s²          (by gravity)

The potential energy of the crate will be -

E[P] = mgh

Substituting values, we get -

E[P] = 180 x 9.8 x 15

E[P] = 2700 x 9.8

E[P] = 26460 joules

Therefore, the potential energy of crate with a mass of 180 kg at a height of 15 m will be 26460 joules.

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Write to your government officials convincing them to invest in global warming prevention. Discuss the 6th Mass extinction event and give examples of previous extinctions.

Answers

write abt gobal warmingExplanation:

An object that weighs 75 N is pulled on a horizontal surface by a horizontal pull of 50 N to
the right. The friction force on this object is 30 N to the left. What is the acceleration of the
object?

Answers

Using the Newton Laws, the acceleration of the object is 2.67m/s²

Based on the problem, we can draw the diagram as below to help our understanding.

From the information provided we know that:

F = 50 N (horizontal pull)

W = 75 N

f = 30 N (friction force)

From the picture, we could focus first on the X-axis, where the horizontal force and the friction force work on the object. We would apply the second law of Newton for this axis since there is movement happening within this axis.

∑Fx = m.a

F - f = m.a

50 - 30 = m.a

m.a = 20N ... (i)

Next, we will focus on the Y-axis. In this axis neutral force and weight are working but not resulting to any movement within the axis. ence, we will be applying the first law of Newton:

∑F = 0

N - W = 0

N = W

N = 75N ... (ii)

Since we know that weight is the result of multiply between mass and gravity, we could find the mass of the object by assuming the gravity is 10m/s²

W = m.g

75 = m (10)

m = 7.5kg ... (iii)

We could subtitute the equation (iii) into equation (i) to find the acceleration of the object:

m.a = 20N

(7.5) a = 20N

a = 2.67m/s²

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An object that weighs 75 N is pulled on a horizontal surface by a horizontal pull of 50 N tothe right.

Which aspect must be taken into consideration when creating a model of radioactive decay?

Answers

Answer:

The weak nuclear force perhaps?

Explanation:

the weak nuclear force is the fundamental force responsible for the radioactive decay of particles

GLOBAL PERSPECTIVES
I WILL GIVE A BRAIN


Make 5 global perspective questions that are debatable

Answers

Answer:    

   1. The death penalty should be abolished.

   2. Human cloning should be legalized.

   3. All drugs should be legalized.

   4. Animal testing should be banned.

   5. Juveniles should be tried and treated as adults.

   6. Climate change is the greatest threat facing humanity today.

   7.  Is There Life After Death?

   8. Is Evolution or Creationism the Truth?

Explanation:

which chemical equation obeys the law of conservation of mass

Answers

Answer:

C3H6OH + 5O3 = 5CO2 + 6H3O

Explanation:

A student places his hand in front of a plane mirror as shown in the diagram. Which terms correctly describe the image that the mirror forms?

A student places his hand in front of a plane mirror as shown in the diagram. Which terms correctly describe

Answers

Either A or D but maybe D

A boy of mass 40kg and a girl of mass 30kg play on a see-saw of negligible weight. If the boy sits 270 cm from the pivot of the see-saw, where must the girl sit to make it balance.
Please show the steps....I will follow you if you do.

Answers

Hi there!

To solve, we can use a summation of torques.

For the see-saw to balance, the sum of torques must equal 0, so:

∑τ = 0

Recall that:

τ = rFsinθ

r = distance from pivot (meters)

F = force (N)

In this case, the forces are the weight of the children. Also, we can leave the distance in centimeters for this type of problem, but others do require a conversion to meters.

Multiply each mass by 10 (g ≈ 10 m/s²) to get the weight:

Στ = 270(400) - x(300) = 0

270(400) = 300x

Solve for 'x', the distance in cm away from the fulcrum:

108000/300 = 360 cm

Other Questions
Which best describes the forces in the nucleus of a stable atom?O A. The weak nuclear force is greater than the electrostatic force.O B. The electrostatic force is greater than the strong nuclear force.O c. The weak nuclear force balances out the strong nuclear force.O D. The strong nuclar force balances out the electrostatic force. Un profesor realiza una prueba con 70 preguntas, cada una con igual valor. Unestudiante que responda 56 preguntas acertadamente que calificacion obtiene. Hey any oneill give brainleast please help me On a math test given to 20 students, the average was an 82 and the highest score was a 93. Five students scoredbelow a 70. Which of the following statements must be true?1. The median is greater than 702. The range is greater than 233. At least 10 students scored above an 82A. 1 onlyB. 2 onlyC. 1 and 2 onlyD. 1 and 3 onlyE. 1,2 and 3 NEED ANSWERS ASAP WILL GIVE BRAINLIEST 1. Based on the section "Third longest river," why is the Yangtze important to China? ______'s mobile group was disbanded by a former CEO who struggled to justify keeping talented engineers on underperforming projects. PLEASE HELP!!! THIS IS URGENT!!!!Imagine that you are the mayor of your town. In an upcoming election, you would like the citizens to vote yes for a gambling establishment to locate in your town. Prepare a short speech encouraging the people of the town to vote yes on your proposal. (8-10 sentences) Solve The Following Thx What is the mean what is the mean for 35, 40, 12, 16, 25, 10 At which event must special care be taken when preparing food Describe the transformation of the graph of the parent function y = x for the function y = x 7 5. How has your education thus far prepared you for theworkforce? What sort of things have your teachers done inregard to expectations, rules, roles, etc.) that will help to prepareyou for life outside of the school walls? What similarities does aschool and work environment have? What makes each of theseenvironments different? Which system functionality must your website have to be able to personalize or customize a product for a client? How many terminals does Chicago O Hare airport have? The shortest side of a triangle is a. The hypotenuse of the triangle is b. Which of the following equations could be used to express the value of the other leg in terms of a and b? HELP ASAP ! WHICH ONE A. B. C. OR D. Use graphs A-C to answer question 5GRAPH AGRAPHDGRAPH Cb 33 BB5. Which graph has a range of y> 0?O A. Graph A onlyO B. Graph B onlyO C. Graph ConlyO D. Graphs A and C :answer question number 5 Help me pleaseee with this question help me complete it all of it pls. PLEASE HELP!!!!Alexia, Benito, and Carmen won a team art competition at their local park. Aspart of their prize, they can paint the 5 km (5000 m) paved path through thepark any way they like.They decided Alexia will paint the first 70 m, then Benito will paint the next15 m, then Carmen will paint the next 35 m. They will keep repeating thispattern until they reach the end of the 5 km path.What percentage of the path will each person paint?