An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 10.0 m/s in 3.30 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.20 s has elapsed?

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Answer:

\(F=3.61\times 10^{-47}\ N\)

Explanation:

Mass of a proton, \(m_p=1.67\times 10^{-27}\ kg\)

Mass of an electron, \(m_e=9.11\times 10^{-31}\ kg\)

The distance between the electron and the proton is, \(r=5.3\times 10^{-11}\ m\)

We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :

\(F=G\dfrac{m_em_p}{r^2}\)

Where G is the universal Gravitational constant

\(F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N\)

So, the force between the electron and proton is \(3.61\times 10^{-47}\ N\).

===================================================

Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.

Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.

Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.

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Answer:

i got u its a

Explanation:

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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The forces acting on the skier is 602.1 N in perpendicular direction and 421.6 N in parallel direction.

The forces acting on the skier at the inclination of the slope is calculated by applying Newton's second law of motion as shown below.

There are two forces acting on the skier;

The perpendicular force is calculated as;

Fn = mg cosθ

where;

Fn = 75 kg x 9.8 m/s² x cos (35)

Fn = 602.1 N

The parallel force on the skier;

F = mg sinθ

F = 75 kg x 9.8 m/s² x sin (35)

F = 421.6 N

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The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun"  is not true about gravity.

Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.

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Answer:

\(T_2 = 0.592\)

Explanation:

Given

\(T_1 = 1.48s\)

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

The upper two connections are connected serially:

So, we have:

\(\frac{1}{C_{up}} = \frac{1}{C} + \frac{1}{C}\)

Take LCM

\(\frac{1}{C_{up}} = \frac{1+1}{C}\)

\(\frac{1}{C_{up}}= \frac{2}{C}\)

Cross Multiply

\(C_{up} * 2 = C * 1\)

\(C_{up} * 2 = C\)

Make \(C_{up}\) the subject

\(C_{up} = \frac{1}{2}C\)

The bottom two are also connected serially.

In other words, the upper and the bottom have the same capacitance.

So, the total (C) is:

\(C_1 = 2 * C_{up}\)

\(C_1 = 2 * \frac{1}{2}C\)

\(C_1 = C\)

The total capacitance in (b) is calculated as:

First, we calculate the parallel capacitance (Cp) is:

\(C_p = C+C\)

\(C_p = 2C\)

So, the total capacitance (C2) is:

\(\frac{1}{C_2} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C}\)

\(\frac{1}{C_2} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{C}\)

Take LCM

\(\frac{1}{C_2} = \frac{1 + 2 + 2}{2C}\)

\(\frac{1}{C_2} = \frac{5}{2C}\)

Inverse both sides

\(C_2 = \frac{2}{5}C\)

Both (a) and (b) have the same resistance.

So:

We have:

Time constant is directional proportional to capacitance:

So:

\(T\ \alpha\ C\)

Convert to equation

\(T\ =kC\)

Make k the subject

\(k = \frac{T}{C}\)

\(k = \frac{T_1}{C_1} = \frac{T_2}{C_2}\)

\(\frac{T_1}{C_1} = \frac{T_2}{C_2}\)

Make T2 the subject

\(T_2 = \frac{T_1 * C_2}{C_1}\)

Substitute values for T1, C1 and C2

\(T_2 = \frac{1.48 * \frac{2}{5}C}{C}\)

\(T_2 = \frac{1.48 * \frac{2}{5}}{1}\)

\(T_2 = \frac{0.592}{1}\)

\(T_2 = 0.592\)

Hence, the time constance of (b) is 0.592 s

Answer: I don't know my dude

Explanation:

Answer:

Humans can detect sounds in a frequency range from about 20 Hz.

The law of conservation of matter stated that during a chemical reaction, the amount of matter stays the same. Thus, option B is correct.

Matter can be changed into other forms either by physical or chemical changes. But through any of these changes matter remains constant. The amount of matter present before the chemical reaction will remain the same after the chemical reaction. Thus, the matter can neither be created nor destroyed.

The law of conservation of matter is defined as the law of conservation of mass. Hence, in a system, the mass or matter remains conserved, before and after the chemical reaction and it was given by Antonie Lavoisier.

The law of conservation of matter states that during a chemical reaction, the amount of matter remains the same. Thus, the ideal solution is option B.

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The moment of inertia of the flat square is MA²/6

The moment of inertia of a body is a property of the body which shows its ability to ritate about an axis.

To find the moment of inertia of the flat square through its center of mass, we know that the moment of  inertia of  a rectangular slab is given by

I = M(a² + b²)/12 where

Now, for a flat square a = b. so,its moment of inertia is I = M(a² + b²)/12

I = M(a² + a²)/12

= 2Ma²/12

= Ma²/6

Now for the given flat square, we have that

So, substituting these into the equation of moment of inertia for the flat square, we have that

The moment of inertia of the flat square is given by

I = Ma²/6

I = MA²/6

So, moment of inertia is MA²/6

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Explanation:

(a)

The initial kinetic energy is geven by 1/2 m v^2, all of which we are given in the problem.

KE = 1/2 (1500) (32)^2 = 768000 J

(b)

Use the work-kinetic energy theorem. The work-kinetic energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

ΔKE = KEf - KEi

Since, the car ends at rest (no velocity), the final kinetic energy is 0.

ΔKE = -KEi = -768000 J

Apply the work kinetic energy theorem.

ΔKE = W = -768000 J

(c)

W = F · d = F d cosα

We are given d, and we have W from part b. In this case, α is 180° since the force must be in the opposite direction of the motion to slow the car down. Rearrange the equation for F.

F = W / (d cosα) = -768000 / (21 cos180°) = 36571 N

(d)

The force causing the car to stop is the frictional force, caused by the car's tires rubbing against the pavement.

Answer:

A.REARRANGED AND FORM NEW SUBSTANCES WITH NEW PROPERTIES

Explanation:

Answer:25N/

Explanation:

Answer:

s = 0.337 m

Explanation:

First, we will find the angular displacement of the reel:

\(\theta = \omega t\)

where,

θ = angular displacement = ?

ω = angular speed = 1.9 rad/s

t = time taken = 7.1 s

Therefore,

θ = (1.9\ rad/s)(7.1 s)

θ = 13.5 rad

Now, we will find out the length of tape:

s = rθ

where,

s = length of tape = ?

r = radius of reel = 2.5 cm = 0.025 m

Therefore,

s = (0.025 m)(13.5 rad)

s = 0.337 m

Work is defined as the force times the distance, as in the following equation:

Where:

In the formula, the force "F" must be parallel to the movement of the object. Since the normal force and the perpendicular component of the weight are not parallel to the motion this means that these forces don't do work.

The parallel force and the force of the rope are parallel to the motion and therefore these forces do work on the crate.

The forces acting on an object are classified as internal and external. The external forces include the applied force on the object, the force of friction, the normal force, etc.,

The internal forces include the gravitational force.

The work done by the object is used to increase its potential gravitational energy, therefore, the energy in the system is conserved.

To calculate the work we will use the fact that the work is equivalent to the potential gravitational energy of the crate when it reaches the height of 3 meters. Therefore, we have:

Where:

The gravitational energy is determined using the following formula:

Where:

Substituting the values we get:

Solving the operations:

Therefore, the gravitational energy is 1470J, and since this is equivalent to the work, the work is also 1470 J.

Explanation:

There are 1024/2 = 512 SHEETS   (each is numbered on two sides)

  3 inches * 25.4 mm/inch / 512 sheet = .1488 mm per sheet

The work done on the box by the gravity is its weight that is equal to 1960 N. The work done on the box by the elevator to  move it  up a distance of 5 m is 9800 J.

When a force applied to an object make a displacement of  the body or stopes its motion, the force is said to be work done on the object. Thus, work done can be taken as the product of force and displacement.

Work done like force is a vector quantity thus characterized with magnitude and direction.  Work done is equivalent to the energy required to make the object displaced.

Given the mass of box = 200 kg

force by gravity = mg

F = 200 Kg × 9.8 m/s² = 1960 N

Displacement by the elevator = 5 m

Work done to displace 1960 N box is :

work done  = force × displacement

w =1960 N × 3m =  9800 J.

Therefore, the work done on the car is 581 KJ.

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The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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Answer: When a disrupted part of the ecosystem is left alone so that nature can help restore itself what people are counting on happening is secondary succession

Explanation:

Therefore, the speed of the trolley along the upper portion of the track is v = 0.84 m/s, which is closest to option D (0.75 m/s).

There are three fundamental quantities in mechanics that are conserved. These are power, forward motion, and angular momentum. It can come as a surprise to you that energy is a conserved quantity if you've read instances in prior pages, such the kinetic energy of charging elephants.

Let's first use the principle of conservation of energy to find the height of the inclined portion of the track. Since the trolley is initially moving with a constant speed, the initial kinetic energy of the trolley is given by:

\(K_i = (1/2) * m * u^2\)

where m is the mass of the trolley and u is the initial speed of the trolley.

At the top of the inclined portion of the track, the trolley comes to rest and all of its initial kinetic energy is converted to potential energy due to its height above the horizontal portion of the track. The potential energy of the trolley at the top of the inclined portion of the track is given by:

\(U_f = m * g * h\)

where g is the acceleration due to gravity and h is the height of the inclined portion of the track.

Since energy is conserved, we can equate the initial kinetic energy of the trolley to its potential energy at the top of the inclined portion of the track:

\(K_i = U_f\\(1/2) * m * u^2 = m * g * h\)

Simplifying this equation, we get:

\(h = u^2 / (2 * g)\)

Substituting the given values, we get:

\(h = (1.2 m/s)^2 / (2 * 9.81 m/s^2) = 0.072 m\)

Now, to find the speed v of the trolley along the upper portion of the track, we can use the principle of conservation of energy again. Since the trolley comes to rest at the top of the inclined portion of the track, all of its potential energy at the top of the inclined portion of the track is converted to kinetic energy as it moves along the upper portion of the track. Therefore, we can equate the potential energy of the trolley at the top of the inclined portion of the track to its kinetic energy along the upper portion of the track:

\(U_f = (1/2) * m * v^2\)

where v is the speed of the trolley along the upper portion of the track.

Substituting the given values, we get:

\(m * g * h = (1/2) * m * v^2\)

Simplifying this equation, we get:

\(v = \sqrt(2 * g * h)\)

Substituting the given values, we get:

\(v = \sqrt(2 * 9.81 m/s^2 * 0.072 m) = 0.84 m/s\)

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Answer:

The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.

Explanation:

Answer:

Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ

Explanation: