A graph would be a straight line with a positive slope.
When the block of mass m is released, it falls downward due to gravity, causing the pulley to rotate in the clockwise direction (positive). Since frictional effects from the axle are negligible and the string wrapped around the disk never fully unwinds, the system experiences a constant torque. This constant torque results in a constant angular acceleration (α) for the pulley.
The rotational inertia of the pulley is given by 1/2 MR^2, where M is the mass of the pulley and R is its radius. According to Newton's second law of rotation, the torque (τ) acting on the pulley is related to its angular acceleration (α) as follows:
τ = Iα
where I is the rotational inertia.
Since the torque and rotational inertia remain constant, the angular acceleration (α) also remains constant. The angular velocity (ω) of the pulley is related to the angular acceleration as:
ω = ω0 + αt
where ω0 is the initial angular velocity (0 in this case, as the pulley starts from rest) and t is the time elapsed.
Given that α is constant, the graph of angular velocity (ω) as a function of time (t) would be a straight line with a positive slope.
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A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.
The arrow leaves the bow at a speed of 40.47 m/s.
When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma
m = mass of the arrow (kg) = 0.0850 kga = acceleration of the arrow (m/s²)F = force (N) = 89.0 N\(a \:=\: \frac{F}{m}\)
\(a \:=\: \frac{89.0}{0.0850}\)
a = 1,047.059 m/s²
When the object has acceleration, the object will move in a non-uniform motion. The formula
v = u+atv² = u² + 2ad\(d \:=\: v_0 \times t \:+\: \frac{1}{2} \times a \times t^2\)u = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)v = final speed (m/s) a = acceleration (m/s²) = 1,047.059 m/s²t = interval (s)d = distance (m) = 0.782 mv² = u² + 2ad
v² = 0² + (2×1,047.059×0.782)
v² = 1,637.6
\(v_t \:=\: \sqrt{1,637.6}\)
\(v_t\) = 40.47 m/s
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4. A bowling ball and a baseball are dropped in a vacuum. Which would hit
the ground first?
please answer as fast as possible
a monometer containing mercury of density p = 13.6 x 10^3 connected to a gas supply. caluclate the perssure of the gas supply
also sorry for the blury image
Explanation:
the pressure is given by P=hpg
where h is height,p is density, g is 10m/s²
thus P= 0.05m•13.6x10³•10
P=6.8x10³ Hgmm
The electromagnetic waves with the longest wavelength are: *
-microwaves
-gamma rays
-radio waves
-visible light
Answer:
Radio waves
Explanation:
I hope it helps u dear^_^
\( \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }\)
electromagnetic waves :- electromagnetic radiation▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂
\(\large\underline{ \boxed{ \sf{✰\:Radio\:waves }}}\)
▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂
The electromagnetic waves with the longest wavelength are radio waves .
Example:- television, mobile phones and radios.========================
Hope it helps!
a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall. the ball bounces back at nearly the same speed with which it hit the wall. which object experiences the greater momentum change? a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall. the ball bounces back at nearly the same speed with which it hit the wall. which object experiences the greater momentum change? the putty experiences the greater momentum change. not enough information is given to determine the answer. the ball experiences the greater momentum change. they both experience the same momentum change
The putty experiences the greater momentum change.
Momentum is a vector quantity that represents the motion of an object. It is given by the product of an object's mass and velocity. The momentum change of an object is equal to the force applied to it, multiplied by the time it takes to apply that force. In other words, the greater the force applied or the longer the force is applied, the greater the momentum change.
This is because momentum change is equal to the final momentum minus the initial momentum, and the final momentum of the putty is zero since it sticks to the wall. Therefore, the momentum change of the putty is equal to its initial momentum, which is the same as the initial momentum of the ball. However, the final momentum of the ball is in the opposite direction to its initial momentum, so its momentum change is less than that of the putty.
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Give me some of the best anime movies !!!!
Answer:
yarchij b club, kakegurui, devilman, Mr.love, yuri on ice, sk8, joker game, young black jack
which of the following is not evidence for an fp discussion? select one: a. we can not observe exoplanets around most stars. no, we can overcome this by understanding our observational limitations and account for non-detections. b. we have detected planets in the habitable zone. c. the kepler mission discovered 1000s of exoplanets, but it's success rate was very low. d. we observe disks around young stars. e. exoplanets are detected in binary systems.
We have detected planets in the habitable zone s not evidence against the discussion of the Fermi Paradox. Option B is correct.
The fp discussion refers to the Fermi Paradox, which is the apparent contradiction between the high probability of the existence of extraterrestrial civilizations and the lack of evidence for, or contact with, such civilizations. The presence of exoplanets in the habitable zone is actually evidence supporting the discussion of the Fermi Paradox, which asks why we haven't detected any signs of intelligent extraterrestrial life despite the high probability of its existence.
As the inability to observe exoplanets around most stars does not necessarily imply a contradiction with the Fermi Paradox. In fact, this limitation can be accounted for by understanding our observational capabilities and taking into account non-detections in our analysis. Option B is correct.
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A student passed a current of 0.6 A through copper sulfate solution for 300 s
Calculate the charge flow through the solution.
Two long straight parallel lines, #1 and #2, carry uniform positive linear charge densities. The charge density on line #2 is twice as great as the charge density on line #1. The locus of points where the electric field due to these lines is zero is
along a line between the lines closer to line #2 than line #1.
at a point midway between the lines.
along a line between the lines closer to line #1 than line #2.
along a line perpendicular to lines #1 and #2.
Answer:
The locus of points where the electric field due to these lines is zero is;
Along the line between the lines closer to line#1 than line #2
Explanation:
The charges on the parallel lines #1 and #2 = Positive linear charge
The charge density on line #2, λ₂ = 2 × The charge density on line #1, λ₁
Therefore, we have;
λ₂ = 2 × λ₁
Electric field strength, E, is given as follows;
\(E = \dfrac{\lambda}{2\cdot \pi\cdot \epsilon_0\cdot d}\)
Therefore;
\(E_1 = \dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)
\(E_2 = \dfrac{\lambda_2}{2\cdot \pi\cdot \epsilon_0\cdot d} = 2 \times\dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)
E₂ = 2·E₁
E₂/2 = E₁
E₂/(2·d) = E₁/d
The strength of the electric field at a given distance from line #2 is 2 times the strength of the electric field from line #1 at the same distance
Therefore the strength of the electric field will be the same at a point twice the distance from line #2 than from line #1 which is a point closer to line #1 than line #2.
what's electron affinity? and what is the formula of electric current?
Answer:
Electron affinity is the energy change that results from adding an electron to a gaseous atom. For example, when a fluorine atom in the gaseous state gains an electron to form F⁻(g), the associated energy change is -328 kJ/mol.
Give brainliest please.
Answer:
Electron affinity is the energy change that results from adding an electron to a gaseous atom.
Sorry I don't know about the second one.
Heat waves are defined by the difference in temperature compared to the normal _________ typical of a region.
Heat waves are defined by the difference in temperature compared to the normal temperature typical of a region.
Describe a heat wave:A heatwave happens when a location has extremely high maximum and minimum temperatures over the course of three days. This is taken into account in light of the area's climate and previous weather patterns.
What transpires throughout heat waves?An protracted period of unusually warm weather that frequently lasts longer than two days is known as a heat wave. Heat waves can occur both with and without a lot of humidity. They can spread out across a large region, placing many people in danger of extreme heat.
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Among discovered meteorites, we have found some with all the following origins EXCEPT... A. Being a fragment of a shattered asteroid. B. Being a fragment from the surface of the Moon. C. Being a fragment from Cornet Halley. D. Being a fragment from the surface of Mars.
We have discovered meteorites with ALL of the following sources, EXCEPT one being a piece of the comet Halley, among the identified meteorites.
Where do most meteors come from? Most meteors come from what place?Our solar system is where all meteorites originate. Most of them are pieces of ancient asteroids that shattered into smaller pieces in the asteroid belt, which is situated between Mars and Jupiter.
How did asteroids get their start?Asteroids are remains of the solar system's creation, which occurred around 4.6 billion years ago. Early on, the formation of Jupiter stopped any planetary bodies from forming in the space between Mars and Jupiter, causing the small particles that were already present to smash and shatter into the asteroids we know today.
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when poked by a spear, an operatic soprano lets out a 1,100-hz shriek. what is its wavelength if the speed of sound is 344 m/s?
The wavelength of the wave produced by the sound is found as 0.312 m.
Explain the relation of wavelength and velocity?As a result, an increase in just about any one quantity while maintaining a constant value for the other will increase the wave speed, which is mathematically equal to that product of the wave's wavelength and linear frequency.Mathematically: v = fλ;
In which;
v = speed of the waveλ = wavelength of the wavef = frequency of the waveThe given data for the question-
f = 1100 Hz ; frequency of sound
v = 344 m/s; speed of the sound
λ = wavelength of the wave
Put the value in the formula;
344 = 1100 x λ
λ = 344/1100
λ = 0.312
Thus, the wavelength of the wave produced by the sound is found as 0.312 m.
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Why do most scientists prefer quantitative data over qualitative
data?
Quantitative data are preferred by scientists above qualitative data. because quantitative data is expressed in numbers and is more trustworthy.
What is qualitative data?Descriptive interpretation-based qualities define qualitative data. By using qualitative data, we can better understand the particular behaviors
Quantitative information is based on numbers and may be counted or measured. Quantitative information provides us with how many, how much, or how frequently something occurs.
Hence, due the the reliability of the data scientists prefer quantitative data over qualitative data.
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Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.
Please help :)
\(\star\sf \overrightarrow{A}=4N\)
\(\star\sf\overrightarrow{B}=6N\)
Angle=160
\(\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}\)
\(\\ \sf\longmapsto R=\sqrt{4^2+6^2+2(4)(6)cos160}\)
\(\\ \sf\longmapsto R=\sqrt{16+36+48(-0.93)}\)
\(\\ \sf\longmapsto R=\sqrt{52-44.6}\)
\(\\ \sf\longmapsto R=\sqrt{7.4}\)
\(\\ \sf\longmapsto R=2.7N\)
the properties of a sound wave are measured as the wave moves from water to air. what two properties would you expect to change
When sound waves travel from water to air, their velocity and wavelength change. The source determines the frequency. It remains unchanged.
The medium through which the sound wave is travelling determines the velocity of the sound wave.
The density of the medium has an indirect relationship with the velocity of sound waves. When a sound wave moves from water into air, its velocity increases. Wavelength also changes.
As a result, the frequency does not change as sound waves travel from water to air.
The range of distance that a sound wave can travel in water depends on its temperature and pressure. In comparison to air, sound travels through water at a far faster rate.
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A certain ideal gas has a molar specific heat at constant pressure of 7R/2. What is its molar specific heat at A constant volume? 9R/2 6R 8R
5R/2 3R/2
The answer is 3R.The molar specific heat at constant pressure (Cp) and the molar specific heat at constant volume (Cv) are related through the gas constant R and the number of degrees of freedom of the gas molecule (f):
Cp - Cv = R
For an ideal gas, the number of degrees of freedom is f = 3, since there are three translational degrees of freedom.
Given that the molar specific heat at constant pressure for this gas is 7R/2, we can calculate its molar specific heat at constant volume as:
Cv = Cp - R/2 = 7R/2 - R/2 = 3R
Therefore, the answer is 3R, which is one of the options given.
It's worth noting that the molar specific heat at constant pressure is generally larger than the molar specific heat at constant volume, since at constant pressure, the gas can expand and do work, which requires energy. This means that more heat is needed to raise the temperature of the gas at constant pressure compared to constant volume.
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What is the recommended range from which a temperature should be selected and maintained constantly to achieve targeted temperature manage?
The recommended range from which a temperature should be selected and maintained constantly to achieve targeted temperature manage is 32ºC-36ºC.
In most centers, the patient is actively cooled by using an induced hypothermia protocol for 24 hours to a goal temperature of 32ºC-36ºC. The goal is to achieve the target temperature as quickly as possible. In most cases, this can be achieved within 3-4 hours of initiating cooling.
Targeted temperature management (TTM), previously known as mild therapeutic hypothermia, in selected patients surviving out-of-hospital sudden cardiac arrest (OHCA) can significantly improve rates of long-term neurologically intact survival, [1] and it may prove to be one of the most important clinical advancements in the science of resuscitation.
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What is the cause for fluctuation of carbon concentrations in short term and long term carbon cycles?
Answer: Much of this variation happens because of the role of plants in the carbon cycle
Explanation:
The amount of CO2 found in the atmosphere varies over the course of a year. Much of this variation happens because of the role of plants in the carbon cycle. ... Respiration occurs all the time, but dominates during the colder months of the year, resulting in higher CO2 levels in the atmosphere during those months.
Answer:
If the amount of C14 in a given amount of carbon (C12) has changed in a particular time period has changed then the results of carbon dating would change, One would have to examine the reasons for changes in the amount of C14 present in a given amount of C12.
In a double‑slit interference experiment, the wavelength is =552 nm , the slit separation is =0. 100 mm , and the screen is =49. 0 cm away from the slits. What is the linear distance Δ between the ninth order maximum and the fourth order maximum on the screen?
I got 11. 6mm but that seems to be incorrect, does anyone else know what it could be?
The linear distance Δ between the ninth order maximum and the fourth order maximum on the screen is 729.6 mm.
Use formula Δ = L * (y9 - y4).
where L is the distance between the double gashes and the screen, and y9 and y4 are the distances between the centre outside and the ninth and fourth order maxes.
To get y9 and y4, we may use the maximum position formula in a double- slit hindrance pattern
y = m * λ * L/ d
where m is the loftiest order, is the light wavelength, L is the distance between the double gashes and the screen, and d is the slit distance. With the handed values, we get
d = 0.100 mm = 0.0001 m
λ = 552 nm = 0.000552 m
L = 49.0 cm = 0.49 m
m = 9
y9 = m * λ * L / d = 9 * 0.000552 * 0.49 / 0.0001 = 2.6876 m
Δ = L * (y9 - y4) = 0.49 * (2.6876 - 1.2056) = 0.7296 m
Δ = 729.6 mm
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On Earth, what is the main force that resists all motion?
Answer:
gravity
Explanation:
What is the impedance of a series RLC circuit at resonance?
(a) XL
(b) XC
(c) R
(d) XL − XC
(e) 0
At resonance, the reactance of the inductor (XL) and the capacitor (XC) in the RLC circuit are equal in magnitude and opposite in sign. Therefore, the total impedance of the circuit is equal to the resistance (R) only. Mathematically, this can be represented as:
Z = R + j(XL - XC)
At resonance, XL = -XC, so the imaginary part of the impedance cancels out, leaving only the real part (resistance) as the impedance of the circuit. Therefore, the correct answer is (c) R. At resonance, the circuit behaves purely resistive and the impedance is at its minimum value, making it easier to transfer power to the circuit.
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what is the probable origin of the dark colored features in this image of the surface of mars? it is about 20 km across.
The probable origin of the dark colored features in the surface of mars for about 20 kilometers across are dunes shaped by the wind.
Explanation:
Dunes are familiar features on Earth and they also occur on Mars, Venus, and Saturn's moon, Titan. What all these bodies have in common is an atmosphere, plus substantial amounts of loose sand-size particles. Of all the extraterrestrial dunes scientists know about, those on Mars are the most closely studied.
A dune is a heap of sand piled up and shaped by the wind. (Underwater dunes exist on Earth, but we can ignore these in regard to today's Mars.) The word "dune" implies a substantial size — at least several meters (yards) high. But small ripples of sand only a few centimeters (inches) high are made in the same way from the same materials. The difference lies mainly in the supply of particles and how much time the wind has had to work on them.
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Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .
Answer: Medial rotation
Lateral rotation
Supination
Pronation
Opposition
Explanation:
Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.
Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.
Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.
Pronation is the downward motion of hand to put things down.
Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.
Un prisma rectangular con un volumen de 80 m^3 se sumerge hasta la mitad en agua, calcular la fuerza de empuje que recibe.(rho_(del agua)=1000 kg/m^3)
Answer:
400 kN
Explanation:
El principio de Arquímedes establece que, cuando un cuerpo está total o parcialmente sumergido en un fluido, experimenta un empuje hacia arriba que es igual al peso del fluido desplazado.
Dado que;
Volumen del bloque = 80m ^ 3
Densidad del agua = 1000 kg / m ^ 3
Empuje hacia arriba = 1/2 * 80 * 1000 * 10
Empuje hacia arriba = 400 kN
I need help with nine and 10 I will really appreciate it
Answer:
9] V = \(\frac{D}{T} \)
Take any distance value from the graph and its relevant time.
V = \(\frac{8}{4} \)
V = 2 m/s
[You will notice that any distance values with its time will give you 2 m/s as its speed. This means that speed is constant throughout.]
10] Take the distance value and its time for the highest peak of B.
V = \(\frac{20}{2} \)
V = 10 m/s
the main bonding jumper is located at the . a. last outlet in the branch circuit b. service disconnect c. ground rod or other grounding system d. meter enclosure
Bonding jumper is located at the service disconnect. This is the point in the electrical system where the main breaker or fuses are located, and where the power from the utility company enters the building.
The main bonding jumper is an important component that connects the grounded conductor (neutral) and the equipment grounding conductor to ensure a low-impedance path for fault currents. This helps to prevent electrical shock and fire hazards.
the main bonding jumper plays a crucial role in ensuring the safety and proper functioning of the electrical system, and it is located at the service disconnect.
To ensure safety and proper functioning of an electrical system, it is important to know the location of the main bonding jumper, which is at the service disconnect.
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The main bonding jumper is situated at the b) service disconnect. It plays a key role in ensuring safety by causing the circuit breaker to trip in case of a fault condition, which then forces the repair of the appliance. Besides, circuit breakers and GFCIs are also vital protective devices for preventing electrical accidents.
Explanation:The main bonding jumper is typically located at the service disconnect (b), which is designed to interrupt the electric service for maintenance or emergency.
When the insulation of a live or hot wire is worn and it comes into direct contact with the metal casing of an appliance, it can cause a severe shock. However, if there's a proper earth or ground, the circuit breaker will trip and force the repair of the appliance.Circuit breakers are important protective devices that prevent over-current situations by interrupting the electrical flow upon the detection of a fault condition. They are rated for a maximum current and can be reset after tripping. Another prominent protective device found particularly in kitchens and bathrooms is a Ground Fault Circuit Interrupter (GFCI), which responds quickly to changes in current and open if a change in the magnetic field produced by current-carrying conductors is detected.Learn more about Circuit Protection here:https://brainly.com/question/31840675
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Carolina is running at a rate of 5 m/s. Mr. Smith comes out and tells her to get fired
up. She is scared. Over a period of 5 seconds, she increases her speed to a rate of
17.2 m/s. What is her rate of acceleration?
Answer:
Correct answer 2.44 m/s2
Treating the cases where t is less than and greater than 0 differently when evaluating the integral by residues, solved for the inverse Fourier transformation f(t)=(2π)^(-1/2) - F(w)e^(-iwt)dw of the
The inverse Fourier transformation is given by: f(t) = {2γ e^γt, if t < 0} {-2γ e^{-γt}, if t > 0}.
The inverse Fourier transformation of the given Lorentz distribution can be obtained using the following steps:
f(t) = (2π)^{1/2} ∫_{-∞}^{∞} F(ω)e^{-iωt} dω
Here, F(ω) = [γ/π(ω² + γ²)] and t is greater than and less than 0.
Therefore, we have to evaluate the integral using the residue theorem with two contours:
one closed in the upper half-plane for t < 0 andone in the lower half-plane for t > 0.We will evaluate the integral for t < 0 and t > 0 separately.
1) Calculation for t < 0:
For t < 0, we have to evaluate the integral using a closed contour in the upper half-plane.
Let's consider a closed semicircle contour C_R in the upper half-plane. This contour encloses only one pole of F(ω) at z = -iγ.
Hence, the residue of F(ω) at z = -iγ is given by:
Residue of F(ω) at z = -iγ
= lim_{ω → -iγ} (ω + iγ)F(ω)
= lim_{ω → -iγ} [(ω + iγ)γ/π(ω² + γ²)]
= (-iγ)(-2iγ/π(2iγ))
= γ/π
So, we can write the integral as:
f(t) = (2π)^{1/2} [2πi Res(F(ω), -iγ)] = 2π^{3/2} Res(F(ω), -iγ)
According to the residue theorem, we can write:
f(t) = 2π^{3/2} Res(F(ω), -iγ)
= 2π^{3/2} [γ/π e^{-i(-iγ)t}]
= 2γ e^γt
2) Calculation for t > 0:
For t > 0, we have to evaluate the integral using a closed contour in the lower half-plane.
Let's consider a closed semicircle contour C_R in the lower half-plane. This contour encloses only one pole of F(ω) at z = iγ.
Hence, the residue of F(ω) at z = iγ is given by:
Residue of F(ω) at z = iγ
= lim_{ω → iγ} (ω - iγ)F(ω)
= lim_{ω → iγ} [(ω - iγ)γ/π(ω² + γ²)]
= (iγ)(-2iγ/π(-2iγ))
= -γ/π
So, we can write the integral as:
f(t) = (2π)^{1/2} [2πi Res(F(ω), iγ)] = 2π^{3/2} Res(F(ω), iγ)
According to the residue theorem, we can write:
f(t) = 2π^{3/2} Res(F(ω), iγ)
= 2π^{3/2} [-γ/π e^{iγt}]
= -2γ e^{-γt}
Therefore, the inverse Fourier transformation of the Lorentz distribution F(ω) = [γ/π(ω² + γ²)] is:
f(t) = {2γ e^γt, if t < 0} {-2γ e^{-γt}, if t > 0}
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Complete question:
Treating the cases where t is less than and greater than 0 differently when evaluating the integral by residues, solved for the inverse Fourier transformation \(f(t) = (2 \pi)^{\frac{1}{2} } \int\limits^\infty_\infty^{-} {F(\omega)e^{-i\omegat} } \, d\omega\) of Lorentz distribution
\(F (\omega)= (\frac{\gamma}{\pi}) (\frac{1}{(\omega^{2} + \gamma^{2} )} )\)
First To Answer With Correct Answer and Full Reasoning Will Be Marked Brainliest! A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
x=x0+v0t+12at^2
v=v0+at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?
Use 3–5 sentences to explain your reasoning.
Answer:
x = x0 + v0 t + 1/2 a t^2
The question asks for distance traveled in 1 sec
x0 = 0
v0 = 0
This leaves
x = 1/2 a t^2
x = 1/2 * 9.8 /s^2 * 1 s^2 = 4.9 m
The balloon will fall 4.9 m in the first second.