An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N/C. What is the kinetic energy of the electron at the end of the motion

Answers

Answer 1

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

K.E = 15.57 x 10⁻¹⁷ J


Related Questions

Chloe puts 2 equal-sized marbles in a graduated cylinder containing 50 cm3 of water. The water level rises up to 70 cm3. What is the volume of each marble?

Chloe puts 2 equal-sized marbles in a graduated cylinder containing 50 cm3 of water. The water level

Answers

A glass marble has an average volume of about 2 cm3. When discussing the volume of a marble, you want to know how much space the object occupies.

What is the volume of each marble?

Because the volume of each marble must be 0.05 because the amount of water decreases by 0.05 times the number of marbles.

Essentially, the volume is equal to the product of the shape's area and height. Volume equals base area multiplied by height.

Finding the volume of an object can help us determine how much water is needed to fill that object, such as how much water is needed to fill a bottle, aquarium, or water tank.

Volume is a measurement of an object's capacity. For example, the volume of a cup is 100 ml if it can hold 100 ml of water up to the brim. Volume is also the amount of space occupied by a three-dimensional object.

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equation for distance

Answers

Answer:

d=√[(x₂ - x₁)² + (y₂ - y₁)²]

Please help!! i need the answers to both!!!


1: Shine the flashlight on the liquid crystal sheet. Did you observe evidence that light carries energy?


2: shine the flashlight on the solar panel of the solar powered toy. Did you observe evidence that light carries energy?

Answers

Answer and Explanation:

1. Evidence can be observed that light is energy-consuming because the liquid crystal sheet sets the temperature and gets warmer. With this, we can affirm that the light energy, moved the liquid crystal sheet molecules, making them when they move generate heat.

2. The evidence that light loads energy can be seen through the movement of the toy. This is because the light states that there was energy received, which will make all the gear of the toy work and move it.

(1) The evidence is the increase in the temperature of the liquid crystal sheet.

(2) The evidence that light carries energy can be seen through the movement of the toy.

The evidence that light carries energy can be observed through the increase in temperature of the liquid crystal sheet. The energy from the incident light increases the temperature of the liquid crystals.

The evidence that light carries energy can be seen through the movement of the toy. The photo-voltaic cell of the solar panel helps to convert solar energy into electricity that will power the toy, thereby creating movement of the toy.

Thus, light carries energy and it can be seen through the increase in the temperature of liquid crystals when light incidents on it and the movement of toy powered by solar energy.

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It turns out that the depth in the ocean to which airborne electromagnetic signals can be detected grows with the wavelength. Therefore, the military got the idea of using very long wavelengths corresponding to about 30 Hz to communicate with submarines throughout the world. If we want to have an antenna that is about one-half wavelength long, how long would that be

Answers

Wavelength = speed / frequency.

Wavelength = 3x10^8 m/s / 30 hz

Wavelength = 10 million meters

1/2 wavelength = 5 million meters

(that's about 3,100 miles)

I'm pretty sure the frequency is wrong in the question.

I think it's actually 30 kHz, not 30 Hz.

That makes the antenna about 3.1 miles long.

A bicycle has a momentum of 36 kg•m/s and a velocity of 4 m/s. What is the mass of the bicycle?

Answers

Answer:

45kw45_32+675&453try to get it done

Answer:

A: 9 kg

Explanation:

on edge! hope this helps!!~ ∩(︶▽︶)∩

The electric field at the center of a ring of charge is zero. At very large distances from the center of the ring along the ring's axis the electric field goes to zero. Find the distance from the center of the ring along the axis (perpendicular to the plane containing the ring) at which the magnitude of the electric field is a maximum. The radius of the ring is 7.55 cm and the total charge on the ring is 7.06E-6 C.

Answers

Answer:b\(4.29\times 10^6\ N/C\)

Explanation:

Given

The radius of the ring is \(a=7.55\ cm\)

The charge on the ring is \(Q=7.06\times 10^{-6}\ C\)

Electric field along the axis at a distance \(x\) is given by

\(E=\dfrac{kxQ}{(x^2+a^2)^{\frac{3}{2}}}\)

To get the maximum value, differentiate \(E\) w.r.t \(x\) we get

\(E_{max}=\dfrac{2kQ}{3\sqrt{3}a^2}\quad [\text{at}\ x=\dfrac{a}{\sqrt{2}}]\\\\E_{max}=\dfrac{2\times 9\times 10^9\times 7.06\times 10^{-6}}{3\sqrt{3}(7.55\times 10^{-2})^2}\\\\E_{max}=\dfrac{24.456\times 10^3}{57\times 10^{-4}}=4.29\times 10^6\ N/C\)

an animal which is known as an ascendant of man

Answers

Answer:

spirit animal?

Explanation:

12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.

Answers

The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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2. What is the mass of an object that was accelerated at a rate of 1 m/s with a force of 2 N

2. What is the mass of an object that was accelerated at a rate of 1 m/s with a force of 2 N

Answers

Answer:

2 kilograms

Explanation:

F = ma

2 = 1m = 2

Angela has been exercising regularly for two years. Right now at her house everyone is feeling sick, but she is able to help the others to feel better. Which long-term benefit of exercise is Angela noticing?

Answers

Answer:

it make your immune system build up from the strain your puting on you body

Explanation:

excercise is good for you  and builds muscle and blood cells

examples of electromagnetic interactions in everyday life

Answers

Answer:

Maybe when you bump into the refrigerator and the magnet falls?

Explanation:

This is an example of you interacting with electromagnetics because you must have bumped into something and made a magnet fall.

I hope it helps?

If it does help can I have a brainliest?

A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car’s initial velocity calculated to the nearest tenth? Record your answer in the boxes below. Be sure to use the correct place value.

Answers

Answer:

2.1 m/s

Explanation:

According to law of conservation of momentum;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the common velocity

Given

m1 = 2150kg

m2 = 3250kg

u1 = 10.0m/s

u2 = ?

v = 5.22m/s

Substitute and get u2

2150(10) + 3250u2 = (2150+3250)5.22

21,500 + 3250u2 = 5400(5.22)

3250u2 = 28,188 - 21500

3250u2 = 6688

u2 = 6688/3250

u2 = 2.1 m/s

Hence the 3250 kg car’s initial velocity has an initial velocity of  2.1 m/s

What is the difference between classical mechanics and quantum mechanics?

Answers

Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

the main difference between classical mechanics and quantum mechanics lies in how they describe the behavior of objects.

classical mechanics is the branch of physics that deals with the motion of everyday objects like balls, cars, and planets.

quantum mechanics is a branch of physics that focuses on the behavior of very small particles, such as atoms and subatomic particles like electrons.

A body is projected upward at an angle of 30 degree to the horizontal at an initial speed of 200ms-.In how many seconds will it reach the ground? How far from the point of projection would it strike?

Answers

Answer:

20.41 s

3534.80 m

Explanation:

In how many seconds will it reach the ground?

We are given the initial velocity of the body, which is 200 m/s at a 30° angle.

We know the acceleration in the vertical direction is -9.8 m/s², assuming that the upwards/right direction is positive and the downwards/left direction is negative.

Since we are using acceleration in the y-direction, let's use the vertical component of the initial velocity.

200 · sin(30) m/s

Let's use the fact that at the top of its trajectory, the body will have a final velocity of 0 m/s.

Now we have one missing variable that we are trying to solve for: time t.

Find the constant acceleration equation that contains v₀, v, a, and t.

v = v₀ + at

Substitute known values into the equation.

0 = 200 · sin(30) + (-9.8)t -200 · sin(30) = -9.8t t = 10.20408163

Recall that this is only half of the body's trajectory, so we need to double the time value we found to find the total time the body is in the air.

2t = 20.40816327

The body will reach the ground in 20.41 seconds.

How far from the point of projection would it strike?

We want to find the displacement in the x-direction for the body.

Let's find the constant acceleration equation that contains time t, that we just found, and displacement (Δx).

Δx = v₀t + 1/2at²

Substitute known values into the equation. Remember that we want to use the horizontal component of the initial velocity and that the acceleration in the x-direction is 0 m/s².

Δx = (200 · cos(30) · 20.40816327) + 1/2(0)(20.40816327)² Δx = 3534.797567

The body will strike 3534.80 m from the point of projection.

An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off

Answers

The airplane change in velocity be 120 m/sec

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
____________________________________________________________________
A. 2 times stronger
B. 1000 times stronger
C. 100 times stronger
D. 20 times stronger

Answers

the 7.5 is a 100 times stronger than the 5.5 . The 100 comes from the increase in scale from 5.5 to 7.5 which is an increase of two so you multiply the strength of the weaker earthquake 10^7-5=10^2=100 and that gives you the strength of the stronger earthquake!

Answer:

100 stronger

Explanation:

HELP ASAP-WILL GIVE BRAINLIEST-NO FILES
When a person is moving a desk, which one of the following has the greater amount of force?

A. the desk itself
B. the push from the person moving the desk
C. the drawers as they slide in and out​

Answers

Answer:C

Explanation:

Valence electron of the first 20 elements​

Answers

Answer:

Hydrogen

1 valence electron

Helium

2 valence electrons

lithium

1 valence electrons

beryllium

2 valence electrons

boron

3 valence electrons

carbon

4 valence electrons

nitrogen

5 valence electrons

oxygen

6 valence electrons

flourine

7 valence electrons

neon

8 valence electrons

sodium

1 valence electron

magnesium

2 valence electrons

aluminum

3 valence electrons

silicon

4 valence electrons

phosphorus

5 valence electrons

Answer:  17 Chlorine -1, +1, (+2), +3, (+4), +5, +7

18 Argon 0

19 Potassium +1

20 Calcium +2

Explanation:

1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination

Answers

Answer:

1.) 30 m is the total distance covered 10m is the displacement you

2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance

Explanation:

24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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which type of energy is the energy of a moving tennis ball

Answers

Answer:

Kinetic energy.

The explanation never existed

Answer: Kinetic Energy

1. An automatic focus camera is able to focus on objects by use of an ultrasonic sound
wave. The camera sends out sound waves that reflect off distant objects and return to
the camera. A sensor detects the time it takes for the waves to return and then
determines the distance an object is from the camera. If a sound wave (speed = 345
m/s) returns to the camera 0.115 seconds after leaving he camera, how far away is the
object?

Answers

Answer:

19.84 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 345 m/s

Time (t) = 0.115 s

Distance (x) =?

The distance of the object away can be obtained as follow:

v = 2x / t

345 = 2x / 0.115

Cross multiply

345 × 0.115 = 2x

39.675 = 2x

Divide both side by 2

x = 39.675 / 2

x = 19.84 m

Thus, the object is 19.84 m away from the camera.

PLEASEEEEE HELP TIMED TEST!!!! Which of following correctly shows the part of the wave that represents the wavelength

PLEASEEEEE HELP TIMED TEST!!!! Which of following correctly shows the part of the wave that represents

Answers

Answer:

the 2nd one is the right one

Explanation:

wave length is on top

The figure 2 correctly shows the part of the wave that represents the wavelength.

What is wave?

A wave is a dynamic disturbance that propagates and causes a change in equilibrium of one or more parameters in physics, mathematics, and related subjects. Quantities may oscillate regularly around an equilibrium (resting) value at certain frequency if a wave is periodic.

A travelling wave is one in which the entire waveform moves in one direction; in contrast, a standing wave is one in which two periodic waves are overlaid and move in the opposing directions.

In a standing wave, there are some points where the wave amplitude seems reduced or even zero, and these positions have null vibration amplitudes. A wave equation (standing wave field comprising two opposing waves) or a one-way wave equation (for single wave propagation in a certain direction) is frequently used to describe waves.

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Part 3: Energy Conversions 7. Record your data in the chart and include at least 5 potential-kinetic energy conversions shown in your device's construction. Example Item Description of potential-kinetic energy conversion Example Book The book had gravitational potential energy when it was on the table. Then as the book fell off the table, it was in motion and had kinetic energy. 1 2 3 4 5

Answers

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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laser light (λ = 568.7 nm) is incident on a single slit. what is the maximum width of the slit (in nm) for which no diffraction minima are observed? round to the closest integer.

Answers

The maximum width of the slit (in nm) for which no diffraction minima are observed is 569 nm.

What is the maximum width of the slit?

The maximum width of the slit (in nm) for which no diffraction minima are observed is calculated by applying the following equation.

sinθ = mλ/a

where;

m is = 1 order integerthe maximum angle for diffraction to occur = 90⁰λ is the wavelength = 568.7 nma is the maximum width of the slit

Substitute the given parameters and solve for the maximum width of the slit (in nm) for which no diffraction minima are observed.

sin(90) = (1 x 568.7 nm) / a

1 = (568.7 nm) / a

a = (568.7 nm) /1

a = 568.7 nm

to the closest integer = 569 nm

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An infrared (IR) and ultraviolet (UV) wave propagating through a vacuum must have the same____
a. speed
b. amplitude
c. frequency
d. wavelength

Answers

Answer:

D. Wavelength

Explanation:

An infrared (IR) and ultraviolet (UV) wave propagating through a vacuum must have the same wavelength.

What will happen to the wavelength of light uf the frequency is doubled?What will happen to the wavelength of light uf the frequency is doubled?​

Answers

Answer:

if the frequency is double, the wavelength is only half as long

Explanation:

Considering the definition of wavelength, frequency and propagation speed, if the wavelength is doubled, the frequency is reduced by half.

In a periodic wave the wavelength (λ) is the physical distance between two points from which the wave repeats itself. That is, the wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

The frequency (f) is a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).

The wavelength and its frequency are related from the speed at which the wave travels. The propagation speed (v) is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement. So, the speed expression is:

v=λ×f

This indicates that the higher the frequency, the shorter the wavelength and the lower the frequency, the longer the wavelength.

All electromagnetic waves propagate in a vacuum at a constant speed of 300,000,000 m/s, the speed of light. Then, since an inversely proportional relationship is established between the frequency and the wavelength, if the wavelength is doubled, the frequency is reduced by half.

In summary, if the wavelength is doubled, the frequency is reduced by half.

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At the 2009 Berlin World Championships, Usain Bolt set the world record in the 200m race. During the race he reached a maximum speed of 12.27 meters per second. If Usain weighs 96.54 kg and he ran the entire race at this speed, how much kinetic energy would he have generated in units of -

Answers

Answer:

7267.19 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 96.54 kg

Velocity (v) = 12.27 m/s

Kinetic energy (KE) =?

Kinetic energy is simply defined as the the energy possess by a body in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

KE => is the kinetic energy

m => is the mass of the object

V => is the velocity of the object.

With the above formula, we can obtain the kinetic energy Usain Bolt as follow:

Mass (m) = 96.54 kg

Velocity (v) = 12.27 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 96.54 × 12.27²

KE = 48.27 × 150.5529

KE = 7267.19 J

Thus, the kinetic energy of Usain Bolt is 7267.19 J

The amount of kinetic energy generated by Usain Bolt is equal to 7,267.189 Joules.

Given the following data:

Distance = 200 m.Speed = 12.27 meters per second.Mass = 96.54 kg.

To calculate the amount of kinetic energy generated by Usain Bolt:

How to calculate kinetic energy.

Mathematically, kinetic energy is given by this formula:

\(K.E = \frac{1}{2} MV^2\)

Where:

K.E is the kinetic energy.M is the mass.V is the speed.

Substituting the given parameters into the formula, we have;

\(K.E = \frac{1}{2} \times 96.54 \times 12.27^2\\\\K.E = 48.27 \times 150.5529\)

K.E = 7,267.189 Joules.

Read more on kinetic energy here: https://brainly.com/question/1242059

Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.​

Answers

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

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