An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500 mm. The gas enters the heating section of the duct at 100 kPa and 27 deg C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 80 kW, Calculate the exit temperature of the gas in deg C. (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat; Cp =1000 J/kg K; R = 500 J/kg K)​

Answer:

The correct option is D

D) At minimum 10-20 minutes

Explanation:

After the car is jump started, the car should be allowed to run atleast for 10-20 minutes, this will help charge the battery of the car. If you don't do it and shut down the car immediately, the battery won't get charged and you will need another jump start. Apart from, parts of the car which are running from the battery e.g headlights, music player etc, should be turned off so it doesn't drain away the battery which is being charged.

Answer:

D. at minimum 10-20 minutes

Explanation: I got it right on FLVS

Explanation:

Most ceilings are coverd with plaster or board.

Answer: The two statements that apply to gas welding as compared to arc welding are:

1.Slower than arc welding

2.Easier to control than arc welding

Explanation: Gas welding is a slower process than arc welding because it requires heating the metal to be welded to a high temperature before the welding process can begin.

However, it is easier to control than arc welding because the welder can adjust the heat and flame of the gas torch to achieve the desired results. In contrast, arc welding requires more skill and practice to control the electric arc and produce a good weld.

(a) To calculate the complex power (S), we can use the formula S = P + jQ, where P is the real power (in watts), and Q is the reactive power (in VARs). Since we are given the apparent power (120 VA) and the power factor (0.707 lagging), we can find the real and reactive power using the following equations:

P = S * power factor = 120 VA * 0.707 = 84.84 W
Q = √(S^2 - P^2) = √(120^2 - 84.84^2) = 84.84 VAR (lagging)

Now we can write the complex power as S = 84.84 + j84.84.

(b) To find the rms current (I) supplied to the load, we can use the formula I = S / V, where V is the rms voltage. Rearranging the formula and plugging in the given values, we get:

I = 120 VA / 110 V = 1.0909 A rms

(c) To determine the impedance (Z), we can use the formula Z = V / I, where V is the rms voltage, and I is the rms current. Plugging in the values, we get:

Z = 110 V / 1.0909 A = 100.8 + j100.8 ohms (approx)

(d) Assuming that Z = R + jωL, we can find the values of R and L by equating the real and imaginary parts:

R = 100.8 ohms
ωL = 100.8 ohms

To find L, we can use the formula ω = 2πf, where f is the frequency. Given the 60-Hz source, we can calculate ω as follows:

ω = 2π * 60 Hz = 377 rad/s

Now we can solve for L:

L = ωL / ω = 100.8 ohms / 377 rad/s ≈ 0.268 H

So, the values of R and L are 100.8 ohms and 0.268 H, respectively.

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Both technicians are correct in their respective statements about the causes of low and high line pressures in a transmission system. It is essential to regularly maintain the transmission, including checking and cleaning the vent and filter, to ensure optimal performance and avoid potential problems.

Technician A and Technician B both present plausible causes for transmission issues, but they address different aspects. Technician A is correct in stating that low line pressure can be caused by a plugged transmission vent. A blocked vent can lead to the buildup of pressure inside the transmission, resulting in low line pressure as the transmission cannot maintain the necessary fluid flow for proper functioning. This can cause problems such as erratic shifting, slipping, or overheating.

On the other hand, Technician B is correct in asserting that high line pressure can be caused by a restricted filter. A clogged or restricted transmission filter can obstruct the flow of transmission fluid, leading to increased pressure within the transmission system. This high line pressure can cause harsh shifts, delayed engagement, or even transmission damage over time.

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Explanation:

A student as given in the context is persuing his study in science and one days he or she aspires to become a research scientist in some chemical company.

From the above information, we can say that the student is a bright student and has a experimentalist mind set and wants to explore and also research  more on science and the principles of scientific laws.

Answer: this student has strong analytical and reasoning skills.

Explanation:

The specific volume at 240°C and 1.25MPa will be 0.1879m³/kg.

Volume is a measure of three-dimensional space. It is often quantified numerically using SI derived units or by various imperial or US customary units. Volume is the amount of space taken up by an object, while capacity is the measure of an object's ability to hold a substance, like a solid, a liquid or a gas.

The specific volume at 240°C and 1.25MPa will be calculated thus:

V2 =V1 + (V3 - V1) (P2 - P1)/(P3 - P1)

V2 = 0.2275 + (0.1483 - 0.2275) (1.25 - 1.0)/(1.5 - 1.0)

= 0.2275 + (-0.0792 × 1/2)

= 0.1879m³/kg.

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The Geiger-Muller counter and Scintillation detector are two different types of radiation detectors that are used to detect ionizing radiation.

The Geiger-Muller counter is made up of a cathode tube, gas inside the tube, a tungsten wire anode, resistance, a capacitor, and a counter. When ionizing radiation enters the tube, primary ionization occurs, which leads to the ionization of gas atoms.

The electrons that result from this ionization move to the positive electrode.The movement of the electrons from the cathode to the anode generates more ionizations, known as secondary ionizations

. The positively charged ions from the secondary ionizations move to the negative electrode, while the electrons generated from these ionizations move towards the positive electrode. This results in an electrical current that is discharged through pulses that are read through a counter. The number of pulses per second corresponds to the amount of radiation that is detected.

The scintillation detector is made up of a scintillator material, a photomultiplier tube, a photocathode, a dynode, and an anode. When ionizing radiation falls on the scintillator material, it emits low energy light photons. These light photons then fall on the photocathode, which leads to the emission of primary photoelectrons.

These photoelectrons are doubled by increasing voltage electrodes known as dynodes. Finally, the photoelectrons fall on the anode connected to an electronic counter, from which the type of pulse current of the associated signal can be observed. The number of pulses generated per second corresponds to the amount of radiation that is detected.

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Time required to melt paraffin is \(t_{m} =4660s = 1.29 hours\)

The time taken to liquify the paraffin,

\(T= 27.4^{o}\)

so, \(\frac{T-T_{0} }{T-T_{1} } = exp(\frac{-PidLb}{mxcp} )\)

Here, the Reynolds number is donated by \(R_{eD}\).

So, \(R_{eD}\) = \(\frac{4m}{pi*D*m}\)= \(\frac{4*0.1}{pi*0.025*467*10^{-6} }\)

Therefore, \(R_{eD}\) = 10,906

h = ?

Given, water flow rate = 0.1 kg/s

so, \(h = \frac{NneudK}{D} =\frac{k}{D} *00.023*R_{eD}^{4/5}* P^{0.3} _{o}\)

=\(\frac{0.653}{0.025} *0.023*10906^{4/3} *2.99^{0.3}\)

therefore, 'h' = \(1418\frac{w}{m^{2}* k}\)

so, \(T_{0} =T-(T-T_{i})exp(\frac{piDlh}{mcp} )\)

by substituting, we get

\(T_{0}=27.4-(27.4-60)exp(\frac{-pi*0.25*3*1418}{0.1*4185})\)

Therefore, \(T_{0}=42.17^{o}\)

As per the balance energy equation, we get

\(q=h_{i} C_{p} (T_{i} -T_{0} )=0.1*4185*(60-42.17) = 7500 watts\)

with the help of balance energy, we can calculate the time required to melt paraffin

so, \(q*T_{m} = P_{v}h_{s} f\)

\(=PL(wH-\frac{pid^{2} }{4})h_{s} f\)

so, \(T_{m} =(770*3)* \frac{(0.25*\frac{0.25^{2} -pi}{4} *0.025)^{2}}{750} h_{s} f\)

Therefore, time required to melt paraffin is \(T_{m} =4660 seconds= 1.29 hours\)

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Answer: See explanation

Explanation:

69.48 / 7.2 = 965 as written in the question isn't correct. The correct answer should have been:

69.48 / 7.2 = 9.65

It should be noted that when we divide, the answer that one gets cannot be more than the two numbers that were used for the division. Hence, there's no way that 965 would be more than 69.48 and 7.2.

This question is incomplete, the complete question is;

Given the complex numbers A₁ = 6∠30 and A₂ = 4 + j5;

(a) convert A₁ to rectangular form

(b) convert A₂ to polar and exponential form

(c) calculate A₃ = (A₁ + A₂), giving your answer in polar form

(d) calculate A₄ = A₁A₂, giving your answer in rectangular form

(e) calculate A₅ = A₁/(\(A^{*}\)₂), giving your answer in exponential form.

Answer:

a) A₁ in rectangular form is 5.196 + j3

b) value of A₃  in polar form is 12.19∠41.02°

The polar form of A₂ is 6.403 ∠51.34°, exponential form of A₂ = 6.403\(e^{j51.34 }\)

c) value of A₃  in polar form is 12.19∠41.02°

d) A₄ in rectangular form is 5.784 + j37.98

e) A₅ in exponential form is 0.937\(e^{j81.34 }\)

Explanation:

Given data in the question;

a) A₁ = 6∠30

we convert A₁ to rectangular form

so

A₁ = 6(cos30° + jsin30°)

= 6cos30° + j6cos30°

= (6 × 0.866) + ( j × 6 × 0.5)

A₁  =  5.196 + j3

Therefore, A₁ in rectangular form is 5.196 + j3

b) A₂ = 4 + j5

we convert to polar and exponential form;

first we convert to polar form

A₂ = √((4)² + (5)²) ∠tan⁻¹( \(\frac{5}{4}\) )

= √(16 + 25) ∠tan⁻¹( 1.25 )

= √41 ∠ 51.34°

A₂ = 6.403 ∠51.34°

The polar form of A₂ is 6.403 ∠51.34°

next we convert to exponential form;

A∠β can be written as A\(e^{j\beta }\)

so, A₂  in exponential form will be;

A₂ = 6.403\(e^{j51.34 }\)

exponential form of A₂ = 6.403\(e^{j51.34 }\)

c) A₃ = (A₁ + A₂)

giving your answer in polar form

so, A₁ = 6∠30 = 5.196 + j3 and A₂ = 4 + j5

we substitute

A₃ = (5.196 + j3) + ( 4 + j5)

= 9.196 + J8

next we convert to polar

A₃ = √((9.196)² + (8)²) ∠tan⁻¹( \(\frac{8 }{9.196}\) )

A₃ = √(84.566416 + 64) ∠tan⁻¹( 0.8699)

A₃ = √148.566416 ∠41.02°    

A₃ = 12.19∠41.02°

Therefore, value of A₃  in polar form is 12.19∠41.02°

d) A₄ = A₁A₂

giving your answer in rectangular form

we substitute

A₄ = (5.196 + j3) ( 4 + j5)

= 5.196( 4 + j5) + j3( 4 + j5)

= 20.784 + j25.98 + j12 - 15

A₄ = 5.784 + j37.98

Therefore, A₄ in rectangular form is 5.784 + j37.98

e) A₅ = A₁/(\(A^{*}\)₂)

giving your answer in exponential form

we know that \(A^{*}\)₂ is the complex  conjugate of A₂

so

\(A^{*}\)₂ = (6.403 ∠51.34° )*

= 6.403 ∠-51.34°

we convert to exponential form

A∠β can be written as A\(e^{j\beta }\)

\(A^{*}\)₂  = 6.403\(e^{-j51.34 }\)

also

A₁ = 6∠30

we convert to polar form

A₁ = 6\(e^{j30 }\)

so A₅ = A₁/(\(A^{*}\)₂)

A₅ = 6\(e^{j30 }\) / 6.403\(e^{-j51.34 }\)

A₅  = (6/6.403) \(e^{j(30+51.34) }\)

A₅  = 0.937\(e^{j81.34 }\)

Therefore A₅ in exponential form is 0.937\(e^{j81.34 }\)

A brick hammer has a textured striking surface to create patterns in masonry.It typically has a chisel-shaped head with a flat striking surface on one end and a pointed tip on the other end.

The textured surface, also called a "boss", is located on the opposite end of the hammer head from the chisel edge.

This feature allows bricklayers and masons to create decorative patterns in bricks and other types of masonry by striking the surface with the textured end of the hammer.

The chisel edge is used for cutting and shaping bricks and other masonry materials.

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Answer:

I think the answer is d: underground tunnel

Explanation:

Hope this helps

Answer:

The correct option is;

c.  the exergy of the tank can be anything between zero to P₀·V

Explanation:

The given parameters are;

The volume of the tank = V

The pressure in the tank = 0 Pascal

The pressure of the surrounding = P₀

The temperature of the surrounding = T₀

Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change

The exergy balance equation  is given as follows;

\(X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}\)

Where;

X₂ - X₁ is the difference between the two exergies

Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system

Therefore, the exergy of the tank can be anything between zero to P₀·V.

Answer:

dddddddddddddddddddddddddddddddddddddd

Explanation:

Answer:

What force is requiere to move the cylinder along

Explanation:

The kinematic viscosity of the ol is 0.006 fr2

Answer: hello your question lacks the required diagram attached below is the diagram

answer :  29528.1  N/m^2

Explanation:

Given data :

dimensions of tank :

Length = 5-m

Width = 4-m

Depth = 2.5-m

acceleration of tank = 2m/s^2

Determine the maximum gage pressure in the tank

Pa ( pressure at point A )  = s*g*h1

    = 10^3 * 9.81 * 3.01

    = 29528.1  N/m^2

attached below is the remaining part of the solution

Answer:

234567891234567891234567891 what is this?????

Explanation:

234567891234567891234567891

IS THIS IS A QUESTION

OH DON'T MIND JUST ASKING

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PLS MARK ME AS BRAINLIEST

The possibility that at least three queries will be observed in a 4-microsecond interval is 0.3233. The chance that at least one query will be found in a 1-microsecond interval is 0.3297.

It states the number that reflects a chance of a particular event occurring, it can be expressed in the proportion from 0 to 1 or expressed in percentages ranging from 0% to 100%.

At least three queries will be processed in a 4-microsecond interval having the probability that is

So, 1 - 0.6767 = 0.3233.

For in a 1-microsecond interval is:

So, 1 - 0.6703 = 0.3297.

Therefore, for a 4-microsecond it is 0.3233, and for a 1-microsecond interval, it is 0.3297.

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A Ukrainian man was executed by his own military unit for refusing to fight and retreating from the front lines. The man, identified as Oleksandr Matsiyevsky, was a sniper with the 163rd Battalion of the 119th Separate Tank Brigade of the Chernihiv Region.

The incident occurred on December 30, 2022, near the village of Krasna Hora in the Donetsk region. Matsiyevsky was reportedly part of a group of soldiers who were ordered to retake a strategic hill from Russian forces.

However, Matsiyevsky and several other soldiers refused to obey the order, citing the high number of casualties that had already been suffered in the battle.

The commanding officer reportedly became enraged and ordered Matsiyevsky and the other soldiers to be executed. Matsiyevsky was shot and killed, while the other soldiers were reportedly beaten. The incident has been condemned by human rights groups, who have called for an investigation.

The execution of Matsiyevsky is a reminder of the dangers faced by Ukrainian soldiers who refuse to fight. It is also a sign of the increasing desperation of the Ukrainian military, as they are forced to defend their country against a much larger and better-equipped Russian force.

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Steel undergoes different heat treatment processes to obtain desired microstructures. These processes include heating the steel to a specific temperature and cooling it in a specific way. The four main processes are full annealing, normalizing, quenching, and tempering.

Heat treatment is a crucial process in altering the mechanical properties of steel. The four main heat treatment processes for steel are full annealing, normalizing, quenching, and tempering. Full annealing involves heating the steel to a temperature above its critical range, holding it at that temperature for a specific time, and then cooling it down slowly. The purpose of full annealing is to obtain a uniform and refined grain structure, increase ductility, and reduce internal stress.

Normalizing is similar to full annealing, but the steel is cooled in air instead of being cooled slowly. The purpose of normalizing is to refine the grain structure, increase the strength and hardness of the steel, and improve machinability.

Quenching involves heating the steel to a high temperature and then rapidly cooling it down by immersing it in a quenching medium such as oil or water. The purpose of quenching is to achieve a hard and brittle microstructure that is suitable for cutting tools, gears, and other applications that require high wear resistance.

Tempering is a process that involves reheating the quenched steel to a specific temperature and holding it there for a certain time before cooling it down. The purpose of tempering is to reduce the brittleness of the steel and increase its toughness and ductility. The final microstructure of tempered steel is dependent on the temperature and time of the tempering process.

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It is to be noted that the welding process is most widely used in the repair of process equipment is SMAW (Shielded Metal Arc Welding)  (option C)

Note that SMAW or Shielded Metal Arc Welding is used widely for different positions and environment of welding. This is why is is very popluar.

SMAW utilizes a consumable electrode and a metal filer material along with a shielding gas which  is used to generate a very strong bond between the two metals being welded.

Hence, it is correct to state that the welding process is most widely used in the repair of process equipment is SMAW (Shielded Metal Arc Welding)

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Answer:

True

Explanation:

The driver is the one who applies the force,so the driver is the effort

To establish the order of transformations used in the transformation given by the notation "s5a2," we must carefully examine the notation. The symbol "s5a2" denotes a pair of transformations.

The first transformation, indicated by the letter "s," is shear. The subscript 5 denotes that this shear is applied in a certain direction along a line 5 units distant from the origin. The second change, indicated by the letter "a," is an expansion or dilatation. The subscript 2 denotes that this enlargement's scale factor is 2. As a result, according to the notation "s5a2," shear is used first, followed by expansion. As a result, the right transformation order is: Shear along a 5 unit line away from the origin. To establish the order of transformations used in the transformation given by the notation "s5a2," we must carefully examine the notation. The symbol "s5a2" denotes a pair of transformations.

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precision. Double-clicking on the Pencil tool allows the user to adjust the fidelity of the tool, which affects how precisely the tool can create shapes and lines when in use.

A tool is an object used to perform a specific task. Tools are generally used to increase efficiency and accuracy, and to reduce labor. Common tools include items such as hammers, screwdrivers, wrenches, saws, pliers, spades, shovels, and axes. Many tools can be used for multiple purposes, and can be adapted for a variety of uses. Tools can be manual or powered, and can range from simple to complex. They can be used for construction, repair, and maintenance, and can be used in a variety of industries. Tools are essential for any job, and can make a task easier or faster to complete.

Higher fidelity settings can create more precise lines, while lower fidelity settings are more suited to creating rougher shapes and lines.

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