An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500 mm. The gas enters the heating section of the duct at 100 kPa and 27 deg C with a volume flow rate of 15 m3/s. If heat is lost from the gas in the duct to the surroundings at a rate of 80 kW, Calculate the exit temperature of the gas in deg C. (Assume constant pressure, ideal gas, negligible change in kinetic and potential energies and constant specific heat; Cp =1000 J/kg K; R = 500 J/kg K)

The average airspeed in the duct is calculated using an anemometer, a test device that detects air velocity.

The airflow passing through the duct is then calculated by multiplying the average feet per minute by the square feet of the duct's area. Three or four cups are joined to horizontal arms to form the most typical type of anemometer.

A vertical rod is where the arms are fastened. The cups turn when the wind blows, spinning the rod. The rod spins more quickly the stronger the wind blows. The anemometer measures the revolutions, or turns, from which wind speed is determined. The wind speed is often averaged over a brief period of time since wind speeds are not constant—there are gusts and lulls.

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Answer:

What are you talking about? pls explain and then maybe I can help.

It checks the type of the first element in `x` to determine if it's a single list or nested lists, and performs the calculations accordingly. The results are returned in a dictionary format.

Here's a version of the code that accomplishes the task in a single line:

import numpy as np

statistics = lambda x: {'mean': round(np.mean(x), 2) if isinstance(x[0], int) else [round(np.mean(i), 2) for i in x],

                      'std': round(np.std(x), 2) if isinstance(x[0], int) else [round(np.std(i), 2) for i in x],

                      'min': np.min(x).tolist() if isinstance(x[0], int) else [np.min(i).tolist() for i in x],

                      'median': round(np.median(x), 2) if isinstance(x[0], int) else [round(np.median(i), 2) for i in x],

                      'max': np.max(x).tolist() if isinstance(x[0], int) else [np.max(i).tolist() for i in x]}

This lambda function takes a list or nested lists as input (`x`) and calculates the mean, standard deviation, minimum, median, and maximum values.

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True. Industrial accidents are often caused by a combination of **unsafe equipment** and **poor safety regulations**.

Unsafe equipment can include malfunctioning machinery, lack of proper maintenance, inadequate safety features, or the absence of necessary safety precautions. When equipment is not designed, maintained, or operated in a safe manner, it increases the risk of accidents and injuries in industrial settings.

Similarly, poor safety regulations or the lack of effective safety protocols can contribute to industrial accidents. Insufficient training, inadequate safety procedures, failure to enforce safety regulations, and a lack of awareness regarding potential hazards can all contribute to an unsafe work environment.

To prevent industrial accidents, it is crucial to prioritize safety by implementing robust safety regulations, conducting regular equipment inspections, providing comprehensive training programs, and fostering a safety-conscious culture within the workplace. By addressing both unsafe equipment and poor safety regulations, the risk of industrial accidents can be significantly reduced.

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For gas piping other than black or galvanized steel installed in a concealed location, where a bored hole is located a maximum of 1/2 inch from the edge of the wood member.

What is galvanized steel?
Galvanized steel is a type of steel that has been treated with a layer of zinc oxide to protect it from corrosion. This layer is bonded to the steel so that it will not flake or peel off. Galvanized steel is often used in the construction industry because it is highly resistant to rust and other forms of corrosion. It is also used in the automotive and appliance industries as well as in the production of water pipes, fencing, and other metal items. Galvanized steel is cost-effective and easy to maintain, making it a popular choice for many applications. It is also environmentally friendly since it does not require the use of chemicals or paints. Galvanized steel is a durable and versatile material that is essential for many projects.

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Answer:

The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.

Explanation:

The air velocity is approximately 6.2 m/s. A Pitot-static probe is a device that is used to measure the velocity of fluid, in this case, air.

The probe consists of two tubes, a Pitot tube and a static tube. The Pitot tube is positioned in the airflow, and it measures the total pressure of the fluid, which includes the static pressure and the dynamic pressure. The static tube, on the other hand, is positioned perpendicular to the airflow and measures only the static pressure.

In this particular scenario, the Pitot tube is connected to a water manometer, which is a device that measures the difference in fluid levels between the two arms of a U-shaped tube. The difference in fluid levels is proportional to the difference in pressure between the two points being measured.

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The answer is analyze

The correct answer is B) bonded.

The National Electrical Code (NEC) requires that conductors 8 AWG and larger must be bonded when installed in a raceway.

Bonding is the process of connecting all metal parts of an electrical system to a common ground to prevent electrical shock and to protect against electrical fires. This requirement is in place to ensure the safety of the electrical system and the people using it. Bonding is especially important when installing conductors in metal raceways because the raceway can become energized if there is a fault in the system. By bonding the conductors to the raceway, any electrical current that flows to the raceway will be grounded, preventing the raceway from becoming energized and potentially causing harm.

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Answer:

I don't understand the question

Answer:

Food and drug admin

Explanation:

Answer:

La potencia disipada por el resistor es 200 watts.

Explanation:

Supóngase que el resistor trabaja en corriente continua (CC). La potencia disipada por el resistor (\(\dot W\)), medida en watts, es definida por la siguiente ecuación matemática:

\(\dot W = i^{2}\cdot R\) (1)

Donde:

\(i\) - Corriente eléctrica, medida en amperios.

\(R\) - Resistencia eléctrica, medida en ohms.

Si sabemos que \(R = 10000\,\Omega\) y \(i = 20\times 10^{-3}\,A\), la potencia disipada por el resistor es:

\(\dot W = (20\times 10^{-3}\,A)\cdot (10000\,\Omega)\)

\(\dot W = 200\,W\)

La potencia disipada por el resistor es 200 watts.

Answer:

(a) The ball's initial speed is 8.4 m/s

(b) The height of the ball  is 3.28 m

Explanation:

Given;

maximum height of the ball, H = 3.6 m

Apply conservation of energy;

¹/₂mu² + mgh = ¹/₂mv² + mgH

Where;

m is the mass of the ball

u is the initial velocity of the ball

v is the final velocity of the ball

h is the initial height of the ball

H is the maximum height of the ball

(a) The ball's initial speed, u;

¹/₂mu² + mgh = ¹/₂mv² + mgH

¹/₂u² + gh = ¹/₂v² + gH

make u the subject of the formula

\(u = \sqrt{v^2 +2gH -2gh} \\\\\)

at maximum height, the final velocity  = 0

maximum height H = 3.6 m

initial height, h = 0

g is acceleration due to gravity = 9.8 m/s²

\(u = \sqrt{0^2 +2*9.8*3.6 -2*9.8*0} \\\\u = \sqrt{2*9.8*3.6} \\\\u = 8.4 \ m/s\)

(b) The height of the ball when it has a speed of 2.5 m/s

v = 2.5 m/s

\(u = \sqrt{v^2 +2gH -2gh} \\\\u^2 = v^2 +2gH -2gh \ (h = 0)\\\\u^2 = v^2 +2gH\\\\2gH = u^2 - v_2\\\\H = \frac{u^2 - v^2}{2g} \\\\H = \frac{8.4^2 - 2.5^2}{2*9.8}\\\\H = 3.28 \ m\)

A) The ball's initial speed is : 8.4 m/s

B) The height of the ball when it has a speed of 2.5 m/s is : 3.28 m

Given data :

Maximum height reached by ball = 3.60 m

applying conservation of energy relation

¹/₂mu² + mgh = ¹/₂mv² + mgH -------- ( 1 )

where : u = initial velocity , v = final velocity , H = max height , h = initial height

Given that the value of m is not given equation ( 1 ) becomes

¹/₂u² + gh = ¹/₂v² + gH  --- ( 2 )

solve for u ( initial velocity )

u = \(\sqrt{v^2 +2gH -2gh}\)   ----- ( 3 )

where : g = 9.8 m/s², v = 0 , H = 3.60 m , h = 0

insert values into equation ( 3 )

u ( initial speed of ball ) = 8.4 m/s

applying equation ( 3 )

u = \(\sqrt{v^2 +2gH -2gh}\)

where : u = 8.4 m/s , v = 2.5 m/s ,  H = ? , h = 0

solve for H

H = u² - v² / 2g

   = ( 8.4² - 2.5² ) / ( 2 * 9.8 )

   = 3.28 m

Hence we can conclude that The ball's initial speed is : 8.4 m/s and The height of the ball when it has a speed of 2.5 m/s is : 3.28 m.

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Technician b is correct. The bleed screw should be closed before the brake pedal is released during manual bleeding of the system.

Unwanted air can be let out of a house radiator unit by turning the bleed screw, which is often done with a key. Bleed screws are also present on some pump types, serving a related function.

They are often found on the side of the inflow pipe near the top of the radiator. Inside a little circular protrusion is the actual screw, which is frequently shaped like a hexagonal or square knob.

The key resembles the winding key for a clock. It is turned after being placed into the protrusion and mated with the bleed screw.

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Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

Answer:

  both are

Explanation:

It depends on what the symptoms of the "basic circuit problem" are. Both overvoltage and shorts are the kinds of things that can cause circuit damage, and either can be the cause of the other.

Answer:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

Explanation:

Given

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,\)

\(0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,\)

\(0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,\)

\(0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.\)

Required

Plot a steam and leaf display for the given data

Start by categorizing the data by their tenth values:

\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.\)

\(0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\)

\(0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.\)

\(0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.\)

\(0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.\)

\(0.78.\)

The 0.3's is will be plotted as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}\)

The 0.4's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}\)

The 0.5's is as follows:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}\)

The 0.6's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}\)

Lastly, the 0.7's is as thus:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

The combined steam and leaf plot is:

\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)

Answer:

E = 132.69 sin(ωt -11.56)

i(t) = 6.64 sin (ωt +48.44) A

Explanation:

given data

e1 = 80 sin ωt volts                       80 < 0

e2 = 60 sin (ωt + π/2) volts          60 < 90

e3 = 100 sin (ωt – π/3) volts        100 < -60

solution

resultant will be  = e2 + e2 + e3

E =  80 < 0 + 60 < 90 + 100 < -60

\(\bar E\) = 80 + j60 + 50 - j50\(\sqrt{3}\)

\(\bar E\) = 130 + (-j26.60)

\(\bar E\) = 132.69  that is less than -11.56

so

E = 132.69 sin(ωt -11.56)

and

as we have given the impedance

z = (10-j17.3)Ω

z = 19.982 < -60

and

i(t) = \(\frac{132.69}{19.982}\) sin(ωt -11.56 + 60)  

i(t) = 6.64 sin (ωt +48.44) A

The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.

Statistical file: {2, -6, 5}

Quartile Q1: -6

Quartile Q2: 2

Quartile Q3: 5.

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Answer:

A) Batch shop production

B) Batch shop production

C) Job shop production

D) production line

Explanation:

A)The preferred production system here will be  Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs

B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches

C) Job shop production

D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production

The flap is used to lift the aircraft in the air as it provides them with balance.

The flaps' main function is to produce additional pull during decreased airspeed, therefore allowing the aircraft to fly at much low rpm with a reduced chance of crashing.

The flap is used to lift the aircraft in the air as it provides them with balance.

They are used for dragging the aircraft as it provides them with a certain amount of height with increases and lowers it.

The takeoff speed is slowed so relatedly to the flap as the change in the structure for the dynamic effect of the airspeed.

Flap reduces the takeoff distance as a smaller speed is being created, which reduces the feed with the coefficient of lift.

The class have a chamber it provides some hollow stairs through which they can store the good and services also it is sometimes used for oil storage.

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a. The average value of the waveform VAVG is VAVG = (1/T) * ∫(waveform function) dt from 0 to T

b. The effective (RMS) value of the repeating waveform VRMS is VRMS = sqrt((1/T) * ∫(waveform function^2) dt from 0 to T)

To find the average value (VAVG) and the effective (RMS) value (VRMS) of the repeating waveform, we'll follow these steps:
a. To find the average value (VAVG) of the waveform:

1. Determine the waveform's period (T). In this case, it repeats every 12 ms, so T = 12 ms.
2. Determine the mathematical function that represents the waveform. You'll need to provide this information to calculate the average value.
3. Integrate the waveform function over one period (0 to T) and divide by the period (T).

VAVG = (1/T) * ∫(waveform function) dt from 0 to T

b. To find the effective (RMS) value (VRMS) of the repeating waveform:

1. Determine the waveform's period (T), which is already given as 12 ms.
2. Determine the mathematical function that represents the waveform (same as step 2 in VAVG).
3. Square the waveform function.
4. Integrate the squared waveform function over one period (0 to T) and divide by the period (T).
5. Take the square root of the result from step 4.

VRMS = sqrt((1/T) * ∫(waveform function^2) dt from 0 to T)

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An example of LEED Green Associate will be D. The director of the museum has a strong general knowledge of the major periods and styles of art represented in the museum.

The LEED Green Associate simply affirms a professional's comprehension of the green building practices and principles.

It should be noted that the LEED Green Associate shows the general knowledge of the green building practices.

In conclusion, the correct option is the director of the museum has a strong general knowledge of the major periods and styles of art represented in the museum.

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Answer:

14.12 w /m^2

Explanation:

Determine the heat transfer rate per unit surface area

First step : determine the thermal resistance of the composite wall considering all present forms of heat transfer

Rth = 1 / h₀ + Lp / Kp + Li / Ki  + Lp / Kp  + 1 / hi  --------- ( 1 )

where : h₀ and hi = 5 W/m^2  ,  Li = 50 mm , Ki = 0.046 W/m.k,  Lp = 3 mm,

            Kp = 60 W/m.k  

Insert values into equation 1 above

Rth = 1.487 m^2. K/W

Next : determine the heat gain per unit surface area ( heat transfer rate )

Q = ( To - Ti ) / Rth

   = 21° C / 1.487

   = 14.12 W/m^2

The objective is to calculate the average power supplied or absorbed by each element in the circuit.

In the given circuit shown in Figure 11.35, to determine the average power supplied or absorbed by each element, we need to analyze the circuit and calculate the power for each element.

To calculate the power, we can use the formula P = VI, where P represents power, V represents voltage, and I represents current.

For each element in the circuit (such as resistors, capacitors, or inductors), we need to determine the voltage across the element and the current flowing through it. Once we have these values, we can calculate the power using the P = VI formula.

To find the average power, we need to consider the time-varying components, such as AC signals or time-varying currents or voltages. In this case, we might need to use techniques like calculus or complex analysis to calculate the average power over a complete cycle or a specified time period.

By applying the appropriate calculations and analysis techniques, we can determine the average power supplied or absorbed by each element in the given circuit shown in Figure 11.35.

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