An ideal (non-viscous, incompressible) fluid flows through a horizontal pipe. The fluid density is 900 kg/m3. Initially, the pipe has a diameter of 0.7 cm and the fluid flows at a speed of 9 m/s at a pressure of 13,000 N/m2. Then, the pipe widens to a diameter of 2.1 cm. What is the speed of the fluid in the wider section of the pipe, in units of m/s

The function for the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time t = 0 is y = 6.45 cos(60π*t).

Moving an object back and forth along a line is known as simple harmonic motion.

See a pendulum, for instance. It follows the same path when we swing it back and forth. Oppositions are what these motions are. A simple harmonic motion example is the oscillations of a pendulum.

\(y=Acos(Bt)\)

has amplitude |A| and period 2π/B, and reaches its maximum at t=0.

So we choose A = 6.45

Period = 1/frequency

Period = 2π/B = 1/30

2π/B = 1/30

B = 60π

y = A.cos(Bt)

y = 6.45 cos(60π*t)

Therefore, The function for the simple harmonic motion is y = 6.45 cos(60π*t).

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The powder takes the shape of a magnetic field.

Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying or mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.

Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.

So we can conclude that Powders are a group of particles of different sizes.

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Answer:

1 is 3 -1

Explanation:

yan po ang tamang sagot thank you four gave thise answer thise if iam rong sorry i dont gate thinking

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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The right answer is C. Space plays a significant role in Florida culture. Space plays a significant role in Florida culture.

The natural environment, history, diversified population, and well-liked attractions like beaches and amusement parks are some of the influences on Florida's culture.

Although Florida has benefited economically and educationally from space-related activity, focusing on this industry as a significant part of the state's culture could have negative effects. Moreover, emphasizing space-related operations could put other crucial industries, like healthcare or environmental conservation.

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volume of balloon

= 4/3 T R3

= 4/3 x 3.14 x 6.953

= 1405.47 m3

uplift force

= volume of balloon x density of air x 9.8

= = 1405.47 x 1.29 x 9.8

= 1813.05 x 9.8 N

weight of helium gas

= volume of balloon x density of helium x

9.8

= 1405.47 x .179 x 9.8

= 251.58 x 9.8 N

Weight of other mass = 930 x 9.8 N Total weight acting downwards

= 251.58 x 9.8 +930 x 9.8

= 1181.58 x 9.8 N

If W be extra weight the uplift can balance

1181.58 × 9.8 + W × 9.8 = 1813.05 * 9.8

1181.58+W=1813.05

W= 631.47 kg

Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.

Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.

Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:

Option A:

Vi = 115 m/s

a = 2.88 m/s²

t = 25.0 s

Using the equation Vf = Vi + at, we can calculate:

Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s

Option B:

V₁ = 2.04 m/s

a = 2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s

Option C:

V₁ = 115 m/s

a = -2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s

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Answer:

B

speed.

Explanation:

hope it helps you

Answer:

\(\huge\underline\color{green}{Answer \: ☘}\)

In the case of a water wave in the ocean, the medium through which the wave travels is the ocean water. In the case of a sound wave moving from the church choir to the pews, the medium through which the sound wave travels is the air in the room.

hope helpful~

Answer: In the collision, the strength of the force exerted on the pod is greater than the strength of the force exerted on the space station, but those forces are exerted in opposite directions.

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Answer:You need to give more explanation sorry

Explanation:

Answer:

4.20 seconds

Explanation:

Supposing that silly goose weighs 69 pounds, we need to start on the math.

Simple maths, truly and really. 69/1=69, of course.

Therefore it will take 4.20 seconds for silly goose to hit the ground. if he is going to be a silly goose though, he can just go in the pond, instead of wasting his time.

Answer:

500km/h

Explanation:

I don't know what units you need the answer in, but if the units were to stay the same, then that's the answer^.

Answer:

I believe the answer is speed up.

Explanation:

this is because when water heats up the molecules move father apart from each other they speed up, eventually causing the water to boll

This question involves the concepts of kinetic energy, escape velocity, and rms speed.

a) The rms speed of hydrogen atom at 5800 K is "11991 m/s".

b) The escape velocity for the Sun is "6.18 x 10⁵ m/s".

a)

We will use the formula of the average kinetic energy of gas molecules to find out the rms speed of the hydrogen atom. rms speed is the root mean square speed of an atom:

\(K.E = \frac{3}{2}KT=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{3KT}{m}}\)

where,

v =rms speed = ?

K = Boltzman's Constant = 1.38 x 10⁻²³ J/k

T = absolute temperature = 5800 k

m = mass of hydrogen atom = 1.67 x 10⁻²⁷ kg

Therefore,

\(v=\sqrt{\frac{3(1.38\ x\ 10^{-23}\ J/k)(5800\ k)}{1.67\ x\ 10^{-27}\ kg}}\)

v = 11991 m/s

b)

The escape velocity of the Sun is given by the following formula:

\(v_e=\sqrt{\frac{2GM}{R}}\)

where,

ve = escape velocity = ?

G = Gravitational Constant = 6.673 x 10⁻¹¹ N.m²/kg²

M = Mass of Sun = 1.99 x 10³⁰ kg

R = radius of Sun = 6.96 x 10⁸ m

Therefore,

\(v_e=\sqrt{\frac{2(6.673\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{6.96\ x\ 10^8\ m}}\)

\(v_e = 6.18\ x\ 10^5\ m/s\)

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Answer:

1st one,.

It changes the direction,

And satellite falls in earth infinity,

Its total workdone is zero

Answer:

It continuously changes the direction of the satellite.

Explanation:

our Welcome (; (:

The components of the position vector of the rabbit's final location r₂, x and r₂, y is 36.77 m.

To find the final location of the rabbit, calculate the displacement of the rabbit, which is given by the product of average velocity and time.

r₂, x = 1, + vx x t = -18.7 - 2.17 x 10.7 = -43.77 m

r₂, y = 1, + vy x t = 21.5 + 1.71 x 10.7 = 36.77 m

Therefore, the components of the position vector of the rabbit's final location are r2x = -43.77 m and r2y = 36.77 m.

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Determine the planet's radius and mass. Use the formula g=GMR2 to get the acceleration 93.63×10¹⁶m/s brought on by gravity on that planet's surface.

The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is M represents mass, R is distance, and G is the gravitational constant of the universe.

g = G*M/R2,

g = 5.972×10²⁴/ 6.378×10⁶

g = 5.972×10¹⁸/6.378

g = 93.63×10¹⁶m/s

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Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

Answer:

B. They reproduce

Explanation:

Both arent made up of one cell, and both arent made up of mutliple cells. Only some unicellular and multicellular organisms are infectious.

Answer:

Your answer would be:
B.) They reproduce.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function. Multicellular organisms are composed of more than one cell, with groups of cells differentiating to take on specialized functions.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism. Multicellular organisms use many different cells to function.

Unicellular organisms are single-celled.

Multicellular organisms are multi-celled.
However, both reproduce.




Explanation:

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Yes, this equation is balanced.

You can check it using the law of conservation of mass, i.e., the total mass of the products formed must be equal to the total mass of the reactants.

Answer:

a) F=ma

F=13.2×10

F=132

b) I=P/V

I=75/15

I=5

Carl Rogers, along with Abraham Maslowsignificantly contributed to the humanistic psychology movement through his development of the person-centered approach and his emphasis on the individual's subjective experience and potential for personal growth.

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The unit of N is 238.8

What is unit ?

an individual thing or person regarded as single and complete but which can be a also form the an be  individual component of a larger or more complex the  whole.

Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.

It is given that the weight of the block is, mg=  242.N

The angle made with the inclined plane is 37.2°

\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9

o

=238.8N

Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.

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a) The speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

b) We cannot calculate the work done by the friction force.

c) The net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

(a) The work done on the 6.00 kg block by gravity can be calculated using the formula:

Work_gravity = force_gravity * displacement * cos(theta),

where force_gravity is the weight of the block, displacement is the downward displacement of the block, and theta is the angle between the force and displacement vectors (which is 0 degrees in this case).

The weight of the block is given by:

force_gravity = mass * acceleration_due_to_gravity = 6.00 kg * 9.8 m/s^2 = 58.8 N.

Plugging in the values, we get:

Work_gravity = 58.8 N * 0.800 m * cos(0) = 47.04 J.

The work done on the 6.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(180) = -29.6 J.

The negative sign indicates that the tension is in the opposite direction of the displacement.

Using the work-energy theorem, we can find the speed of the 6.00 kg block after descending 0.800 m:

Work_net = change_in_kinetic_energy.

Since the block starts from rest, its initial kinetic energy is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * mass * velocity^2.

Solving for velocity, we get:

velocity = sqrt(2 * Work_net / mass).

The net work done on the block is the sum of the work done by gravity and the tension:

Work_net = Work_gravity + Work_tension = 47.04 J - 29.6 J = 17.44 J.

Plugging in the values, we get:

velocity = sqrt(2 * 17.44 J / 6.00 kg) = 2.07 m/s.

Therefore, the speed of the 6.00 kg block after descending 0.800 m is 2.07 m/s.

(b) The total work done on the 8.00 kg block during the 0.800 m displacement can be calculated using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the 8.00 kg block is not moving vertically, its initial and final kinetic energies are zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 0.

The work done on the 8.00 kg block by the tension in the rope is given by:

Work_tension = tension * displacement * cos(theta).

Plugging in the values, we get:

Work_tension = 37.0 N * 0.800 m * cos(0) = 29.6 J.

The work done on the 8.00 kg block by the friction force can be calculated using the formula:

Work_friction = force_friction * displacement * cos(theta),

where force_friction is the frictional force on the block. However, the problem statement does not provide the value of the friction force. Therefore, we cannot calculate the work done by the friction force.

(c) The net work done on the system of two blocks during the 0.800 m displacement of the 6.00 kg block can be found using the work-energy theorem:

Work_net = change_in_kinetic_energy.

Since the system starts from rest, the initial kinetic energy of the system is zero. Therefore:

Work_net = Final_kinetic_energy - Initial_kinetic_energy = 1/2 * (6.00 kg + 8.00 kg) * velocity^2.

Simplifying, we get:

Work_net = 1/2 * 14.00 kg * velocity^2.

Using the value of velocity calculated in part (a), we get:

Work_net = 1/2 * 14.00 kg * (2.07 m/s)^2 = 29.13 J.

The work done on the system of two blocks by gravity is the sum of the work done on the individual blocks by gravity:

Work_gravity_system = Work_gravity_6kg + Work_gravity_8kg = 47.04 J + 0 J = 47.04 J.

The work done on the system of two blocks by the tension in the rope is the sum of the work done on the individual blocks by the tension:

Work_tension_system = Work_tension_6kg + Work_tension_8kg = -29.6 J + 29.6 J = 0 J.

Therefore, the net work done on the system of two blocks during the 0.800 m downward displacement of the 6.00 kg block is 29.13 J. The work done by gravity is 47.04 J, the work done by friction is unknown, and the work done by the tension in the rope is zero.

Note: The calculations for part (b) and (c) were based on the given information, but the value of the friction force was not provided in the problem statement.

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Answer:

A

Explanation:

the mass in the option a is conserved of two elements

Answer:

PHYSICAL CHANGE

Explanation:

PLEASE DON'T JUST IGNORE IT

I HOPE I WILL GET A GOOD RESPONSE

Lightning is a bright flash of electricity produced by a thunderstorm. All thunderstorms produce lightning and it is very dangerous. The light from a lightning bolt is equal to the amount of illumination from about 100 million light bulbs.