An ideal transformer has LaTeX: N_1 = 1000 N 1 = 1000 (number of windings on the primary side), and LaTeX: N_2 = 8000 N 2 = 8000 (number of windings on the secondary side). If the rms voltage on the primary side is LaTeX: V_{rms}=100V V r m s = 100 V , what is the rms voltage on the secondary side? Give your answer in terms of Volts (rms), without entering the units.

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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Collaboration is critical to successful product design, and with Solid Edge, OEMs and suppliers can improve and manage collaboration across design teams, regardless of location. By reducing design revisions and communication delays, our customers enjoy quicker time-to-market and increased profitability.

A 20-minute cycle ergometer exercise at 60% VO2max has been demonstrated to dramatically improve impact for the majority of persons.

the property of being strongly felt or having a powerful impact: The explosion was so loud that it could be heard from five kilometres distant. Measures of luminosity. [C or U] the strength of being something that may be measured, such as sunlight, sound, etc.

A measure that is produced from a randomised measure is known as an intensity measure in probability theory. Since the randomised measure of a set's expected value is the intensity measure, which is a non-random measure, it equates to the average volume that the random measure assigns.

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Answer:

16.5 m

Explanation:

The following data were obtained from the question:

Time (t) = 0.1 s

Speed of sound in air (v) = 330 m/s

Distance (X) =?

The Lenght (i.e distance) of the room can be obtained as follow:

v = 2X / t

330 = 2 × X / 0.1

Cross multiply

2 × X = 330 × 0.1

2 × X = 33

Divide both side by 2

X = 33/2

X = 16.5 m

Thus, the length of the room is 16.5 m.

These locations, where the potential difference between Vab and Vcb is 0 and 258v, respectively, have a uniform electric field with a magnitude of 3230 n/c.

The potential difference, also referred to as voltage, is equal to the amount of current multiplied by the resistance. One Joule of energy is consumed by a charge when it moves between two points in a circuit at a potential difference of one Volt. respectively, have a uniform electric field with a magnitude of 3230 n/c. An electric field is a type of physical field that exists around electrically charged particles and which influences the behaviour of all other charged particles nearby (or E-field).

whereas Vcb = E/d = 3230*0.08 = 258v, Vba = E/d = 0

Vba = E/d = 0

Vcb = E/d = 3230*0.08 = 258v

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The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

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Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer:

100 m

Explanation:

Answer: The force that pushes a plane upwards is the lift generated by the wings as the plane moves through the air. The lift force is created by the difference in air pressure above and below the wings, which creates an upward force that opposes the weight of the plane.

Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

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Answer:

9.81 or 10 m/s^2

Explanation:

Any object under free-fall experiences an acceleration of 9.81 m/s^2 (assuming downward is the positive direction), but for simplicity we will round it to 10 m/s^2.

Knowing this, we can also find the mass by dividing 25 by 10 (m = Fg/g) which is 2.5kg.

Answer:

g = 9.8 m/s²

Explanation:

All bodies fall to the ground with an acceleration g = 9.8 m/s²

Body weight is irrelevant...

Answer:

Density of liquid

Depth of liquid

Acceleration due to gravity

The velocity of the large cart after the collision is approximately 0.0486 m/s in the opposite direction of its initial motion.

We can use the principle of conservation of momentum to find the speed of the large cart after the collision. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum (p) of an object is calculated by multiplying its mass (m) by its velocity (v). Therefore, the momentum of the small cart before the collision is:

p_small_before = (mass_small) * (velocity_small) = (0.300 kg) * (1.80 m/s) = 0.540 kg·m/s.

Since the large cart is at rest before the collision, its initial momentum is zero:

p_large_before = 0 kg·m/s.

After the collision, the small cart bounces back at a speed of 0.810 m/s. According to the law of conservation of momentum, the total momentum after the collision should equal the total momentum before the collision. Therefore, the momentum of the small cart after the collision is:

p_small_after = (mass_small) * (velocity_small_after) = (0.300 kg) * (-0.810 m/s) = -0.243 kg·m/s.

The momentum of the large cart after the collision is labeled p_large_after. Since the initial momentum of the large cart is zero and the momentum after the collision is determined by the momentum of the small cart, we can write:

p_large_after = -0.243 kg·m/s.

To find the speed of the large cart after the collision, we divide the momentum by its mass:

velocity_large_after = p_large_after / (mass_large) = (-0.243 kg·m/s) / (5.00 kg) = -0.0486 m/s.

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Given that a solid disk and a hallow sphere roll down a frictionless ramp. Let's determine the object that will reach the bottom of the ramp first if they both start from rest.

Now, apply the formulas for the Inertia of the solid disk and hallow sphere:

For the solid disk, we have:

For the hallow sphere, we have:

Now, apply the conservation of energy

The solid disk will have a lesser rotational inertia while the rotational inertia of the hallow sphere will be greater. Since the solid disk will have a lower rotational inertia the angular momentum of the solid sphere will be greater than the angular momentum of the hallow sphere.

Since the angular momentum of the solid is greater, the solid disk will first reach the bottom of the ramp.

ANSWER:

The solid disk will first reach the bottom of the ramp.

Answer:

103.44g

Explanation:

R=f/u

=750/0.8

=937.5N

m = 937.5/10cos25

m = 103.44g

Work = (force) x (distance)

Your force was not enough to move the building, so the distance is zero.

Work = (your force) x (zero)

Work = zero

The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁  (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

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The horizontal distance traveled by the bales before it reaches the cattle is 95.1 m

The given parameters;

The time of flight of the bales before it reaches the cattle is calculated as;

\(h = v_o_yt + \frac{1}{2} gt^2\\\\160 = (75\times sin(55) )t \ + \ (0.5\times9.8)t^2\\\\160 = 61.425t + 4.9t^2\\\\4.9t^2 + 61.425t - 160 = 0\\\\solve \ the \ quadratic \ equation \ using \ formula \ method;\\\\a = 4.9, \ b = 61.425, \ c = -160\\\\t = \frac{-b \ + /- \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-61.425 \ + /- \ \sqrt{(61.425)^2 - 4(4.9\times -160)} }{2\times 4.9}\\\\t = 2.21 \ s\)

The horizontal distance traveled by the bales before it reaches the cattle is calculated as;

\(R = v_o_x t\\\\R = v\times cos(\theta) \times t\\\\R = 75 \times cos(55) \times 2.21\\\\R = 95.1 \ m\)

Thus, the horizontal distance traveled by the bales before it reaches the cattle is 95.1 m

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Answer:

a) the acceleration of the particle is (  v\(_f\)² - v\(_i\)² ) / 2as

b) the integral W = \(\frac{1}{2}\)m( \(_f\)² - v\(_i\)² )

Explanation:

Given the data in the question;

force on particle F = ma

displacement s = x\(_f\) - x\(_i\)

work done on the particle W = Fs = mas

we know that; change in energy = work done       { work energy theorem }

\(\frac{1}{2}\)m(  v\(_f\)² - v\(_i\)² ) = mas

\(\frac{1}{2}\)(  v\(_f\)² - v\(_i\)² ) = as

(  v\(_f\)² - v\(_i\)² ) = 2as

a = (  v\(_f\)² - v\(_i\)² ) / 2as

Therefore, the acceleration of the particle is (  v\(_f\)² - v\(_i\)² ) / 2as

b) Evaluate the integral W = \(\int\limits^{v_{f} }_{v_{i} } mvdv\)

\(W = \int\limits^{v_{f} }_{v_{i} } mvdv\)

\(W =m[\frac{v^{2} }{2} ]^{vf}_{vi}\)

W = \(\frac{1}{2}\)m( \(_f\)² - v\(_i\)² )

Therefore, the integral W = \(\frac{1}{2}\)m( \(_f\)² - v\(_i\)² )

Answer:

Meeee

Explanation:

Answer:

Answer:

\(P=217600Pa\)

Explanation:

From the question we are told that:

Density \(\rho=1000kg/m^3\)

Depth of Water \(d=12.0m\)

Generally the equation for Pressure is mathematically given by

 \(P=\rho gh\)

 \(P=1000*9.8*12\)

 \(P=117600N/m^2\)

Therefore

Absolute Pressure=P+P'

Where

P=Pressure under water

P'=Atmospheric Pressure

Therefore

 \(P_A=P+P'\)

 \(P_A=117,600+10^5\)

 \(P=217600Pa\)

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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Explanation:

To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK = 1/2 * m * (vf^2 - vi^2)

where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).

Substituting the given values, we get:

Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2

Net work = 46.4657 J - 22.6545 J

Net work = 23.8112 J

Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.

230.4 gm of ethanol is produced in the conversion of ethanol to acetaldehyde and the molar mass of sugar is 180,16 g/mol.

Fermentation is a metabolic process that converts sugar to acids, gases or alcohol. It occurs in yeast and bacteria, and also in oxygen-starved muscle cells, as in the case of lactic acid fermentation. Fermentation is also used more broadly to refer to the bulk growth of microorganisms on a growth medium, often with the goal of producing a specific chemical product like enzyme, vaccines, antibiotics, food product/additive etc.

Pyruvate is CH3COCOO−  is inorganic phosphate. Two ADP molecules and two Pi are converted to two ATP and two water molecules via substrate-level phosphorylation. Two molecules of NAD+ are also reduced to NADH.

In oxidative phosphorylation the energy for ATP formation is derived from an electrochemical proton gradient generated across the inner mitochondrial membrane (or, in the case of bacteria, the plasma membrane) via the electron transport chain. Glycolysis has substrate-level phosphorylation (ATP generated directly at the point of reaction).

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92.14 gm ethanol will be produced, if 180.16 grams of sugar was used in the alcohol fermentation reaction.

Alcohol fermentation is the breakdown reaction of sugar in the absence of oxygen, to produce wine(ethanol) and carbon dioxide. Following reaction takes place:

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

Chemical formula of the sugar is C₆H₁₂O₆,

Chemical formula of ethanol is C₂H₅OH

Atomic weight of sugar = (12×6 + 12×1 + 16×6) =  180 gm/mole

Atomic weight of ethanol = (12×2 + 5×1 +16+1) = 46 gm/mole

180 gm of sugar makes one mole, which produces 2 moles of ethanol.

So the weight of ethanol produced will be 2 × 46.07 = 96.14 gm

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