Thus, the inductive reactance of the L-R-C circuit with an inductor of 1.53×10−3h, a capacitance of 1.67×10−2f, and a resistance of 0.329 ω operating at 60 Hz is 0.0579 Ω.
To calculate the inductive reactance of this L-R-C circuit, we need to use the formula X_L = 2πfL, where X_L is the inductive reactance, f is the frequency of the circuit, and L is the inductance of the inductor.
Substituting the given values in the formula, we get:
X_L = 2π x 60 x 1.53×10−3
X_L = 0.0579 Ω
Therefore, the inductive reactance of this L-R-C circuit is 0.0579 Ω.
In this circuit, the inductor and capacitor are connected in parallel, and the resistance is in series with them. The capacitor and inductor in a parallel circuit have opposite reactances, and their combination produces a resonant frequency.
At the resonant frequency, the inductive and capacitive reactances cancel out, leaving only the resistance in the circuit. However, at a frequency of 60 Hz, the inductor and capacitor do not cancel out completely, and their combination produces a non-resonant circuit.
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Describe, in order, what changes in substance to change from a liquid to a gas and then back into a liquid. energy would have to occur for a
A substance's atoms split from one another when it transforms from a liquid to a gas. The distance between atoms widens in a gaseous state as opposed to a liquid state. In a gaseous condition, the atoms are randomly moving. Entropy is growing.
A substance's physical state transitions from its gas phase to its liquid phase through the process of condensation. When water vapor comes into touch with a solid surface, it can also be said to transform into water droplets. The solute and solvent can be removed from their solution with the help of this procedure. The solvent evaporates from the solution when it is heated, and is then separated when it condenses.
Despite the fact that a liquid and a gas are both at the same temperature, a gas has greater thermal energy than a liquid. Consider the fact that the thermal energy of the same substance's liquid molecules is lower than that of its gaseous molecules. As a result of their greater kinetic energy, the gas molecules are "freer" to move more.
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You don't learn any movement concepts until high school.
Answer:
true
Explanation:
Answer:
yes
Explanation:
you don't learn it until high school
( TRUE false )
1.)manuals are the organic matter.
2.)combine is used for sowing the seeds.
3.) the first agricultural task is sowing of seeds.
4.) many plants are first grown in Kinder Gardens and then sown in fields.
5.) earthworm are farmer friendly.
6.)substance that kills
pests are called weedicides.
7.) animals which provide us both egg and flesh are called milch animals.
8.) Grains should be dried in Sun before storage.
9.)wheat,gram,barley,potato, are kharif crops.
10.) the crops on in June /July and harvested in September/ October are called rabi crops.
plz answerzz fast
Answer:
number 6 is wrong
the answer is pesticides
2.combines are used for harvesting or threshing.so number 2 is wrong
at least you tried
Explanation:
there is no such thing as weedicides
Answer:
1. True
2.True
3.False
4. True
5. True
6.False
7.False
8.True
9.False
10.False
Please help me with this (20 points)
Answer:
1. troposphere
2. troposphere (still)
3. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere.
4.The stratosphere is where you'll find the very important ozone layer. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection.
5. It contains the ozone, which protects Earth from the sun's radiation. Why aren't there many meteors in the troposphere? They burn up before they reach the troposphere.
Explanation:
1.The troposphere is the atmospheric layer closest to the planet and contains the largest percentage (around 80%) of the mass of the total atmosphere. Temperature and water vapor content in the troposphere decrease rapidly with altitude.
2.The layer closest to Earth's surface is the troposphere, reaching from about seven and 15 kilometers (five to 10 miles) from the surface. The troposphere is thickest at the equator, and much thinner at the North and South Poles.
3. Explained in the answer.
4. Explained in the answer.
5. Explained in the answer.
What is the magnitude and direction of the momentum of a 1200 kg truck traveling at 20m/s towards the east
Given :
A 1200 kg truck traveling at 20 m/s towards the east.
To Find :
The magnitude and direction of the momentum.
Solution :
We know, momentum is given by :
Momentum, P = mv
P = 1200 × 20 kg m/s
P = 24000 kg m/s
Now, we know, direction of momentum is same as the direction of velocity.
Therefore, momentum of truck is 24000 kg m/s and direction is towards the east.
Always swim with a _____, no matter where you are
A.Partner
B.bikini
C.floatation device
D.hair cap
Help ASAP!
Answer:
A.
Explanation:
Never swim alone just in case something happens
Answer:
the answer is partner
Explanation:
this is common sense. if you are drowning or need help your partner will either be able to help you, or get help this is why u should NEVER swim alone no matter where or who you are. May i be marked brainliest?
The distance from one crest to the next is the ________.
Answer:
Wavelength.
Explanation:
1 period, or wavelength, is measured from one crest to another or from one trough to another.
Two 3.0-cm-diameter aluminum electrodes are spaced 0.50 mm apart. The electrodes are connected to a 100 V battery.
A) What is the capacitance?
B) What is the magnitude of the charge on each electrode?
(a)The capacitance of the electrodes is 2.23 × 10⁻¹¹ F and the magnitude of charge on each electrode would be 2.23×10⁻⁹coulomb.
We are given that,
Area of the = A = 1.26 ×10⁻³m²
Distance = d = .50mm = 5 ×10⁻⁴m
Voltage = v = 100volt
(a) The capacitance of electrode can be calculated as, can be calculated as,
C = A∈₀/d
Where, C is the capacitance of the electrode, ∈₀ is the permittivity constant in free space.
C = [(1.26 ×10⁻³m²)(8.85× 10⁻¹²Fm⁻¹ )]/ 5 ×10⁻⁴m
C = 2.23 × 10⁻¹¹ F
(b) The magnitude of the charge on each electrode can be calculated by the formula,
C= Q/v
Q = CV
Putting the values from the above we get,
Q =(2.23 × 10⁻¹¹ F)×( 100volt)
Q = 2.23 × 10⁻⁹coulomb
Therefore, the capacitance of the electrode would be 2.23 × 10⁻¹¹ F and the magnitude of charge on each electrode would be 2.23×10⁻⁹coulomb.
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hume suggests that the assumption that objects are permanent can be argued for on the basis of
Hume suggests that the assumption of objects being permanent can be argued for based on our repeated and consistent experiences.
In other words, through our constant observations of objects remaining unchanged over time, we develop a belief in their permanence.
This assumption is a result of the principle of induction, which states that the future will resemble the past based on our past experiences.
Hume argues that our belief in the permanence of objects is not derived from reason or logic but rather from habit and custom. We have observed objects behaving consistently in the past, and therefore we expect them to behave similarly in the future.
However, according to Hume, this belief is not grounded in any necessary connection between past and future events. It is simply a product of our psychological inclination to infer causality and continuity based on our repeated observations.
Thus, while we may assume objects to be permanent based on our experiences, Hume suggests that this assumption lacks a solid rational foundation.
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A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg•m2. if the arms are pulled in so the moment of inertia decreases to 1.80 kg•m2, what is the final angular speed?
A) 2.25 rad/s
B) 6.25 rad /s
C) 0.81 rad/s
D) 4.60 rad/s
An orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground. How far is the ground from orange's starting position?
The orange was at a height of 3.26 m above the ground.
State third equation of motion.The third equation of motion is
v² - u² = 2aS
Given is an orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground.
We can write -
[v] = 8 m/s
[a] = 9.8 m/s²
[u] = 0 m/s
Using third equation of motion, we get -
v² - u² = 2aS
64 - 0 = 2 x 9.8 x S
64 = 19.6 x S
S = 3.26 m
Therefore, the orange was at a height of 3.26 m above the ground.
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The astronomer who first worked out the mathematical description of black hole event horizons was?
Karl Schwarzschild devised the first general relativity model that would adequately describe a black hole in 1916.
What is Black Hole?
A black hole is an area of spacetime with such intense gravitational pull that nothing can escape from it, not even light or other electromagnetic waves. According to general relativity theory, a compact enough mass can bend spacetime into a black hole. The event horizon is the line beyond which there is no escape.
Black holes were once thought to be a mathematical curiosity, but theoretical research in the 1960s revealed that they were actually a general prediction of general relativity.
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What point in the video would make sense to set the time to zero? Answer based on the green rubber ball.
Incomplete question.
Options:
At the start of the video (frame 0) When the green rubber ball leaves the person's hand (frame 120) When the green rubber ball reaches the top (frame 664)Answer:
When the green rubber ball leaves the person's hand (frame 120)
Explanation:
Remember, we are told to answer based on the green rubber ball, which means we are to take note of the moment when the green rubber ball leaves the person's hand (frame 120).
However, if we decide to set the time at the start of the video or when the green rubber ball reaches the top, we would get inaccurate results.
A ball is thrown upwards at an angle to the horizontal. Air resistance is negligible. Which statement about the motion of the ball is correct?
a. The acceleration of the ball changes during its flight.
b.The velocity of the ball changes during its flight.
c. The acceleration of the ball is zero at the highest point.
d. The velocity of the ball is zero at the highest point.
When a ball is thrown upwards at an angle to the horizontal b. the velocity of the ball changes during the flight but acceleration remains constant.
When a ball is thrown upwards at an angle to the horizontal, it experiences two forces: gravity and the force of the throw. Gravity pulls the ball downwards, while the force of the throw pushes the ball upwards and forwards. The net result of these two forces is that the ball follows a curved path, called a parabola.
The velocity of the ball is the rate of change of its position. In other words, it is the speed and direction of the ball. The velocity of the ball changes throughout its flight. When the ball is first thrown, it has a high velocity in the upwards and forwards direction. As the ball rises, its upwards velocity decreases, until it reaches zero at the highest point of its flight. After this, the ball starts to fall, and its downwards velocity increases.
The acceleration of the ball is the rate of change of its velocity. In other words, it is the rate at which the ball's speed and direction change. The acceleration of the ball is constant throughout its flight. This is because the only force acting on the ball is gravity, and gravity always accelerates objects downwards at the same rate.
Thus the correct answer is b. The velocity of the ball changes during its flight.
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Lionel explores electromagnetic induction using the procedure shown. 1. Move the magnet quickly into the right end of a solenoid. 2. Hold the magnet in the solenoid for 3 s. 3. Move the solenoid slowly to the left away from the magnet. What should Lionel observe during his investigation?
Answer:
B. A large current forms, drops to zero, then a smaller current forms in the opposite direction
Explanation:
The results of Lionel observation about electromagnetic induction is as follows:
In the first step, a large current will form because of the fast or quick movement of the magnet into the right end of a solenoid that generates a induces emf.
In the second step, the magnet was in rest position for 3 s so the current drops to zero because according to Faraday's law, no voltage will be generated if the magnet held stationary and no voltage means no current.
In the third step, smaller current forms in the opposite direction as the magnet is slowly moving away from the solenoid generating a smaller voltage.
Hence, the correct answer is "B."
Answer:
B
Explanation:
There is a bell on top of a tower that is 45 meters high. The bell has a mass of 20 kg. Calculate its potential energy.
Answer:
9000 Joules
Explanation:
Potential energy = mass x acceleration due to gravity x height
mass = 20kg
acceleration due to gravity = 10m/s2
height = 45 meters
20 x 10 x 45 = 9000 Joules
Which surface has the most friction? a An ice rink b A grassy field c A paved road
Answer:
An Ice Rink
Explanation:
Answer:
b
Explanation:
i remember this from a test
You are on an interstellar mission from the Earth to the 8.7 light-years distant star Sirius. Your spaceship can travel with 70% the speed of light and has a cylindrical shape with a diameter of 6 m at the front surface and a length of 25 m. You have to cross the interstellar medium with an approximated density of 1 hydrogen atom/m3 . (a) Calculate the time it takes your spaceship to reach Sirius. (b) Determine the mass of interstellar gas that collides with your spaceship during the mission. Note: Use 1.673 × 10−27 kg as proton mass.
Answer:
a) Time taken for the spaceship to reach Sirius, t' = 8.86 years = 9 years(approx)
b) The mass of the interstellar gas that collides with the spaceship, m' = 1.195 * 10^(-27) kg
Explanations:
The calculations are handwritten and attached as files below. However, the following steps were taken to arrive at the solutions
a) to calculate the time taken for the spaceship to reach Sirius
Step 1: calculate the time taken to reach Sirius from the perspective of the earth using time = distance/speed
Step 2: Use lorentz time dilation formula to calculate the equivalent time to reach Sirius from the perspective of the person in the spaceship
b) to calculate the mass of the interstellar gas
Step1: Calculate the new length of the spaceship using special relativity
Step 2 Get the new volume also by using the new length gotten
Step2: Get two equations for the original mass and the new mass using mass = density * volume
Step 3: Write the original mass in terms of the new mass and make necessary substitution.
Note: Check complete solution in the file attached.
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Carbohydrates contain that your body absolutely must have to stay alive.
Ο Α. hormones
ОВ. chemicals
O C. fats
O D. minerals
Answer:
C
Explanation:
10. A ream of copy paper (500 sheets) is 28.5 mm thick, what is the thickness of one sheet of copy paper?
5.5 x 10-6 m
E
5.8 x 10³ m
5.6 x 104 m
5.7 x 105 m
Answer: The volume of the ream is length times width times height
V = LWH
L = 11
W = 8.5
H = ??
(11)(8.5)H = 187
H = 187/[(11)(8.5)]
H = 2 inches
Why does a green leaf look green in our eyes
Answer:
because the leaf absorbs all the other colors except for green. So the leaf reflects the green color which is what we see. that is why a leaf spears to be green.
Explanation:
floor gang aooh sub to pewdiepie
How does air pressure help to inflate a football?
Answer:
When air is flushed into the ball, the elastic lining inside is expanded. This happens because when too much air enters, there is a lacking of space inside. Therefore the air with pressure pushes the walls of the ball and results in inflation.(same like after you have excess food your stomach inflates)
The acceleration due to gravity of Mars is 3.71 m/s2. What is the weight of the Curiosity rover on Mars?
A rectangle has an area measuring 1350 square centimeters. Its length and width are whole numbers of centimeters. What are the possible combinations of length and width? which possibility gives the smallest perimeter?.
The smallest perimeter of the rectangle is of value 150 cm.
Given:
The area of the rectangle, A = 1350 cm²
Calculation:
Let the length of the rectangle be 'x'
the breadth of the rectangle be 'y'
We know that the area of a rectangle is given as:
A = (x) × (y)
Applying values in the above equation we get:
xy = 1350 cm²
Factorizing the value of 1350, the possible values of length and breadth of the rectangle is as listed below:
x (cm) y (cm)
1350 × 1
675 × 2
450 × 3
270 × 5
225 × 6
150 × 9
135 × 10
90 × 15
75 × 18
54 × 25
50 × 27
45 × 30 (least possible value)
Thus, the smallest perimeter of the rectangle can be calculated as:
P = 2 (x + y)
= 2 (45 + 30)
= 150 cm
Therefore, the smallest perimeter that the rectangle will have is 150 cm.
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Are mass and weight the same thing?
Yes
No
Answer:
Explanation:
Definitely NOT! Mass is unchanging, wherever you go. On the moon you will have the same mass as you will on the earth. Mass is just a measure of the matter that makes up a body. Weight, however, is dependent upon the pull of gravity which is different on earth than it is on the the moon, for example.
Mass doesn't change with proximity whereas weight can.
Answer: No
Explanation: The terms'mass' and 'weight' are frequently used interchangeably, yet they have distinct meanings. Your mass remains constant regardless of where you are in the universe; nevertheless, your weight varies. The mass of anything is a measure of how much power is required to change its course.
A Resistance Temperature Detector has the following transfer function 273.15% + T)" RT = R25( 298.15°K Where T is the current temperature and 25 is the reference temperature in °C. A) Compute the Temperature Coefficient of Resistance (TCR) ofthe above sensor element. B) Compute the sensitivity of the sensor at 25 °C? Assume R25=1000 .Q. C) Plot the transfer function of the above sensor for the range [-60,150] °C. Comment on the relationship between the change in temperature and the change in resistance. D) [f the temperature changed from 25 to 26 °C, determine the absolute change in resistance to be observed?
A) The Temperature Coefficient of Resistance (TCR) of the sensor element is 0.00385 °C⁻¹.
B) The sensitivity of the sensor at 25 °C is 3.85 Ω/°C.
C) The transfer function of the sensor, RT = R25(1 + T/100), shows a linear relationship between the change in temperature and the change in resistance. As the temperature increases, the resistance of the sensor increases proportionally. Similarly, as the temperature decreases, the resistance decreases proportionally. The plot of the transfer function for the range [-60, 150] °C would be a straight line with a positive slope, indicating a direct relationship between temperature and resistance.
D) If the temperature changed from 25 to 26 °C, the absolute change in resistance observed can be calculated using the transfer function. RT1 = R25(1 + T1/100) and RT2 = R25(1 + T2/100), where T1 and T2 are the initial and final temperatures, respectively. Plugging in the values, RT1 = 1000 Ω(1 + 25/100) = 1250 Ω and RT2 = 1000 Ω(1 + 26/100) = 1260 Ω. The absolute change in resistance would be RT2 - RT1 = 1260 Ω - 1250 Ω = 10 Ω.
A) The Temperature Coefficient of Resistance (TCR) represents the change in resistance per degree Celsius change in temperature. It is calculated by dividing the change in resistance by the change in temperature. In this case, since the transfer function is given as RT = R25(1 + T/100), we can see that the TCR is 0.00385 °C⁻¹, indicating that for every degree Celsius increase in temperature, the resistance increases by 0.00385 times the reference resistance.
B) The sensitivity of the sensor at 25 °C refers to the change in resistance per degree Celsius change in temperature at the reference temperature. Since R25 is given as 1000 Ω, the sensitivity is equal to the TCR, which is 0.00385 Ω/°C.
C) The transfer function RT = R25(1 + T/100) describes the relationship between the temperature and resistance of the sensor. The plot of this function for the temperature range [-60, 150] °C would be a straight line with a positive slope. This indicates that as the temperature increases, the resistance also increases, and as the temperature decreases, the resistance decreases. The slope of the line represents the TCR or sensitivity of the sensor, which is constant throughout the range.
D) To determine the absolute change in resistance when the temperature changes from 25 to 26 °C, we can use the transfer function. By substituting the values into the function, we find that the resistance changes from 1250 Ω to 1260 Ω, resulting in an absolute change of 10 Ω.
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**100 POINTS**
Suppose you have a balenced stick with 3 weights on one side and only 1 weight on the other side.What needs to happen on the side with less weight for the objects to be balanced?
A.Nothing.The objects cannot be balanced
B.Move the 1 weight closer to the center
C.Set the 1 weight 3 times the distance from the center as the weights on the other side
D.Set the 1 weight 6 times the distance from the center as the weights on the other side
Answer:
B
Explanation:
Calculate the new gravitational force between two heavenly bodies if one of the masses is doubled and the other mass is tripled keeping the distance between them constant.
The new gravitational force between the two heavenly bodies is six times the original gravitational force.
The gravitational force between two heavenly bodies can be calculated using Newton's law of universal gravitation;
F1 = G × (m1 × m2) / r²...eq (1)
gravitational constant = G
mass 1 = m1
mass 2 = m2
radius = r
distance between them constant,
we can calculate the new gravitational force F2 using the formula:
F2 = G × (m1 × m2) / r²; where
gravitational constant = G
mass 1 = 2m1 (doubled)
mass 2 = 3m2 (tripled)
radius = r
on substitution,
F2 = G × (2m1 × 3m2) / r²
= G × (6m1m2) / r²
= 6 × G × (m1m2) / r²
⇒ (G × (m1 × m2) / r² = F1 )...from eq. (1)
= 6 × F1
⇒ F2 = 6F1
Therefore, the new gravitational force will be six times the original gravitational force when one mass is doubled and the other mass is tripled.
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If one of the masses in a gravitational system is doubled and the other mass is tripled while keeping the distance between the bodies constant, then the new gravitational force will increase by a multiple of:
6 (2 x 3 = 6)
We know from Newton's Law of Gravitation that the gravitational force between two objects is:
F = G * (m1 * m2) / r^2
Where:
F = Gravitational force
G = Universal gravitational constant
m1 = Mass of first object
m2 = Mass of second object
r = Distance between the objects
Since the distance (r) between the two bodies remains constant in the given scenario, it drops out when calculating the change in force.
We are only concerned with how the change in masses affects the force.
Based on the equation, we can see that the gravitational force is directly proportional to the product of the two masses (m1 * m2).
If one mass doubles and the other mass triples, their product will increase by a multiple of 2 x 3 = 6.
Therefore, the new gravitational force between the two heavenly bodies will increase by a factor of 6, compared to the original gravitational force when only one mass was doubled and the other mass tripled, while keeping the distance constant between them.
can someone help me :(
Answer:
Where is the question?
Explanation:
how is it possible to get out of a psychiatric ward?
The steps to get out of a psychiatric ward might include speaking with healthcare professionals, following treatment plans, attending meetings, expressing your desire to leave, appealing the decision if necessary, and following discharge instructions.
Getting out of a psychiatric ward typically depends on a few different factors, including the reason for admission, the policies of the facility, and the judgment of the treating healthcare professionals. Here are a few general steps that might help someone get out of a psychiatric ward:
Speak with the healthcare professionals: The first step is to communicate with the healthcare professionals who are treating you.
Follow treatment plans: If you are admitted to a psychiatric ward, you will likely be given a treatment plan to help manage your symptoms.
Attend all meetings: Attend all meetings with healthcare professionals and participate in therapy sessions.
Express your desire to leave: If you believe you are ready to leave the psychiatric ward, it is important to express this to your healthcare team.
Appeal the decision: If you disagree with the decision to keep you in the psychiatric ward, you can appeal the decision.
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